McGraw Hill Math

McGraw Hill Math Grade 4 Chapter 13 Lesson 6 Answer Key Problem Solving: Choosing a Method

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 13 Lesson 6 Problem Solving: Choosing a Method to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 13 Lesson 6 Problem Solving: Choosing a Method

Solve.

Tell which method you chose for each problem. Explain why.

Question 1.
Kameko and Bill have the same size water bottle. Kameko’s bottle is \(\frac{3}{10}\) full of water. Bill’s bottle is \(\frac{5}{10}\) full of water. How much more water does Bill’s bottle have?
Answer:
\(\frac{2}{10}\) more or \(\frac{1}{5}\) more; I used mental math. It’s easy to subtract \(\frac{3}{10}\) from \(\frac{5}{10}\) in your head.

Question 2.
A mechanic turns a bolt 89°. Then he turns it another 67°. How many degrees did he turn the bolt altogether?
Answer:
McGraw Hill Math Grade 4 Chapter 13 Lesson 6 Answer Key img 1

Explanation:
A mechanic turns a bolt 89°
Then he turns it another 67°
I used pencil and paper to find the sum
89 + 67 = 156
So, the mechanic turned the bolt 156° altogether.

Question 3.
A small office building has a rectangular parking lot. It measures 58 m long and 52 m wide. What is the perimeter of the parking lot?
Answer:
McGraw Hill Math Grade 4 Chapter 13 Lesson 6 Answer Key img 2

Explanation:
A small office building has a rectangular parking lot
It measures 58 m long and 52 m wide
I used pencil and paper to find the sum
perimeter of a rectangle = 2(l + w)
Length of the parking lot = 58 m
Width of the parking lot = 52 m
Perimeter = 2(58 + 52)
= 2 x 110 = 220
So, perimeter of the parking lot is 220 meters.

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McGraw Hill Math Grade 4 Chapter 13 Test Answer Key

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 13 Test to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Chapter 13 Test Answer Key

Write each missing number.

Question 1.
2 right angles = _____________
Answer:
180

Explanation:
1 right angle = 90
2 right angles = 2 x 90 = 180
So, 2 right angles = 180.

Question 2.
3 right angles = _____________
Answer:
270

Explanation:
1 right angle = 90
3 right angles = 3 x 90 = 270
So, 3 right angles = 270.

Use a protractor to measure each angle.

Question 3.
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key 1
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 1

Explanation:
The measure of the angle is 120-degrees.

Question 4.
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key 2
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 2

Explanation:
The measure of the angle is 175-degrees.

Question 5.
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key 3
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 3

Explanation:
The measure of the angle is 35-degrees.

Question 6.
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key 4
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 4

Explanation:
The measure of the angle is 80-degrees.

Solve. Write an equation for each.

Question 7.
∠ABC measures 34°.
∠CBD measures 113°.
What is the measure of ∠ABD?
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key 5
Answer:
147°

Explanation:
∠ABC measures 34°
∠CBD measures 113°
34 + 113 = x
Add to find
34 + 113 = 147
So, ∠ABD measures 147°

Question 8.
A wheel is turned 141° one way and then 49° the other way. At what degree measure does the wheel stop?
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key 6
Answer:
92°

Explanation:
A wheel is turned 141° one way and then 49° the other way
141 – 49 = x
Subtract to find
141 – 49 = 92°
The wheel stops at 92° .

Draw an angle with each measure. Use a protractor.

Question 9.
50°
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 5

Explanation:
The measure of the angle is 50-degrees.

Question 10.
145°
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 6

Explanation:
The measure of the angle is 145-degrees.

Question 11.
97°
Answer:
McGraw Hill Math Grade 4 Chapter 13 Test Answer Key img 7

Explanation:
The measure of the angle is 97-degrees.

Solve. Tell whether you used mental math, paper and pencil, or a calculator. Explain why.

Question 12.
Connor has a roll of tape. He uses 2\(\frac{1}{7}\) ft to tape one present. He uses 4\(\frac{2}{7}\) ft to tape another present. Then he uses 3\(\frac{2}{7}\) feet to tape a third present. He has 14\(\frac{1}{7}\) ft of tape left over. How many feet of tape did he begin with?
Answer:
23\(\frac{6}{7}\) ft

Explanation:
Connor has a roll of tape
He uses 2\(\frac{1}{7}\) ft to tape one present
He uses 4\(\frac{2}{7}\) ft to tape another present
Then he uses 3\(\frac{2}{7}\) feet to tape a third present
He has 14\(\frac{1}{7}\) ft of tape left over
Add to find
2\(\frac{1}{7}\) + 4\(\frac{2}{7}\) + 3\(\frac{2}{7}\) + 14\(\frac{1}{7}\) = 23\(\frac{6}{7}\)
So, Connor begin with 23\(\frac{6}{7}\) ft of tape.

Question 13.
A school group goes on a field trip to the Grand Canyon. 140 people ride 7 buses. If each bus holds the same number of people, how many people are on each bus?
Answer:
20

Explanation:
A school group goes on a field trip to the Grand Canyon
140 people ride 7 buses
Each bus holds the same number of people
I use mental math to solve
I divide 140 by 7
140 / 7 = 20
So, 20 people are on each bus.

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McGraw Hill Math Grade 5 Chapter 6 Test Answer Key

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 6 Test are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Chapter 6 Test Answer Key

Identify the least common multiple, LCM, for each pair of numbers.

Question 1.
5, 6 __________
Answer:
LCM of 5, 6 is 30.

Explanation:
Here, multiplies of 5 are 5, 10, 15, 20, 25, and 30.
Multiples of 6 are 6, 12, 18, 24, and 30.
So LCM of 5, 6 is 30.

Question 2.
7, 8 _____
Answer:
LCM of 7, 8 is 56.

Explanation:
Here, multiplies of 7 are 7, 14, 21, 28, 35, 42, 49, and 56.
Multiples of 8 are 8, 16, 24, 32, 40, 48 and 56.
So LCM of 7, 8 is 56.

Question 3.
3, 4 ________
Answer:
LCM of 3, 4 is 12.

Explanation:
Here, multiplies of 3 are 3, 6, 9, and 12.
Multiples of 4 are 4, 8, 12.
So LCM of 3, 4 is 12.

Question 4.
7, 6 _________
Answer:
LCM of 7, 6 is 42.

Explanation:
Here, multiplies of 7, 14, 21, 28, 35, and 42,
Multiples of 6 are 6, 12, 18, 24, 30, 36, and 42.
So LCM of 7, 6 is 42.

Question 5.
10, 12 ____
Answer:
LCM of 10, 12 is 120.

Explanation:
Here, multiplies of 10 are 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, and120.
Multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96, 108, and 120.
So LCM of 10, 12 is 120.

Question 6.
6, 9 _________
Answer:
LCM of 6, 9 is 54.

Explanation:
Here, multiplies of 6 are 6, 12, 18, 24, 30, 36, 42, 48, and 54.
Multiples of 9 are 9, 18, 27, 36, 45, 54.
So LCM of 6, 9 is 54.

Question 7.
2, 5 _________
Answer:
LCM of 2, 5 is 10.

Explanation:
Here, multiplies of 2 are 2, 4, 6, 8 and 10 .
Multiples of 5 are 5, and 10.
So LCM of 2, 5 is 10.

Question 8.
5, 3 ________
Answer:
LCM of 3, 4 is 12.

Explanation:
Here, multiplies of 5 are 5, 10, and 15.
Multiples of 3 are 3, 6, 9, 12 and 15.
So LCM of 3, 4 is 12.

Find the equivalent fractions.

Question 9.
equivalent to \(\frac{1}{2}\), denominator 22 ___________
Answer:
The equivalent fraction is \(\frac{11}{22}\).

Explanation:
The equivalent fraction to \(\frac{1}{2}\) with denominator 22 is \(\frac{1}{2}\) × \(\frac{11}{11}\) = \(\frac{11}{22}\).

Question 10.
equivalent to \(\frac{2}{5}\), denominator 20 _________
Answer:
The equivalent fraction is \(\frac{8}{20}\).

Explanation:
The equivalent fraction to \(\frac{2}{5}\) with denominator 20 is \(\frac{2}{5}\) × \(\frac{4}{4}\) = \(\frac{8}{20}\).

Question 11.
equivalent to \(\frac{3}{7}\), denominator 35 _________
Answer:
The equivalent fraction is \(\frac{15}{35}\).

Explanation:
The equivalent fraction to \(\frac{3}{7}\) with denominator 35 is \(\frac{3}{7}\) × \(\frac{5}{5}\) = \(\frac{15}{35}\).

Question 12.
equivalent to \(\frac{2}{3}\), denominator 12 _________
Answer:

The equivalent fraction is \(\frac{8}{12}\).

Explanation:
The equivalent fraction to \(\frac{2}{3}\) with denominator 12 is \(\frac{2}{3}\) × \(\frac{4}{4}\) = \(\frac{8}{12}\).

Question 13.
equivalent to \(\frac{3}{5}\), denominator 15 _________
Answer:
The equivalent fraction is \(\frac{9}{15}\).

Explanation:
The equivalent fraction to \(\frac{3}{5}\) with denominator 15 is \(\frac{3}{5}\) × \(\frac{3}{3}\) = \(\frac{9}{15}\).

Question 14.
equivalent to \(\frac{1}{3}\), denominator 21 _________
Answer:
The equivalent fraction is \(\frac{7}{21}\).

Explanation:
The equivalent fraction to \(\frac{1}{3}\) with denominator 21 is \(\frac{1}{3}\) × \(\frac{7}{7}\) = \(\frac{7}{21}\).

Add or subtract. Give answers in simplest terms.

Question 15.
\(\frac{1}{4}\) + \(\frac{1}{4}\) ___________
Answer:
\(\frac{1}{4}\) + \(\frac{1}{4}\) = \(\frac{1}{2}\).

Explanation:
The simplest form of \(\frac{1}{4}\) + \(\frac{1}{4}\) which is \(\frac{1+1}{4}\)
= \(\frac{2}{4}\)
= \(\frac{1}{2}\).

Question 16.
\(\frac{2}{9}\) + \(\frac{5}{9}\) ___________
Answer:
\(\frac{2}{9}\) + \(\frac{5}{9}\) = \(\frac{7}{9}\).

Explanation:
The simplest form of \(\frac{2}{9}\) + \(\frac{5}{9}\) which is \(\frac{5+2}{9}\)
= \(\frac{7}{9}\).

Question 17.
\(\frac{3}{7}\) – \(\frac{2}{7}\) ___________
Answer:
\(\frac{3}{7}\) – \(\frac{2}{7}\) = \(\frac{1}{7}\).

Explanation:
The simplest form of \(\frac{3}{7}\) – \(\frac{2}{7}\) which is \(\frac{3 – 2}{7}\)
= \(\frac{1}{7}\).

Question 18.
\(\frac{3}{3}\) + \(\frac{2}{5}\) ___________
Answer:
\(\frac{3}{3}\) + \(\frac{2}{5}\) = 1\(\frac{2}{5}\).

Explanation:
The simplest form of \(\frac{3}{3}\) + \(\frac{2}{5}\) which is \(\frac{15+6}{15}\)
= \(\frac{21}{15}\)
= \(\frac{7}{5}\)
= 1\(\frac{2}{5}\).

Question 19.
\(\frac{9}{17}\) – \(\frac{5}{17}\) ___________
Answer:
\(\frac{9}{17}\) – \(\frac{5}{17}\) = \(\frac{4}{17}\).

Explanation:
The simplest form of \(\frac{9}{17}\) – \(\frac{5}{17}\) which is \(\frac{9-5}{17}\)
= \(\frac{4}{17}\).

Question 20.
\(\frac{5}{8}\) – \(\frac{3}{8}\) ___________
Answer:
\(\frac{5}{8}\) – \(\frac{3}{8}\) = \(\frac{1}{4}\).

Explanation:
The simplest form of \(\frac{5}{8}\) – \(\frac{3}{8}\) which is \(\frac{5-3}{8}\)
= \(\frac{2}{8}\)
= \(\frac{1}{4}\).

Add or subtract. Give answers in simplest terms.

Question 21.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 1
Answer:
\(\frac{1}{7}\) – \(\frac{1}{8}\) = \(\frac{1}{56}\).

Explanation:
The simplest form of \(\frac{1}{7}\) – \(\frac{1}{8}\) which is \(\frac{8-7}{56}\)
= \(\frac{1}{56}\).

Question 22.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 2
Answer:
1\(\frac{1}{2}\) + 1\(\frac{3}{7}\) = 2\(\frac{13}{14}\).

Explanation:
The simplest form of 1\(\frac{1}{2}\) + 1\(\frac{3}{7}\) which is \(\frac{3}{2}\) + \(\frac{10}{7}\)
= \(\frac{21+20}{14}\)
= \(\frac{41}{14}\)
= 2\(\frac{13}{14}\).

Question 23.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 3
Answer:
3\(\frac{2}{3}\) + 2\(\frac{3}{5}\) = 6\(\frac{4}{15}\).

Explanation:
The simplest form of 3\(\frac{2}{3}\) + 2\(\frac{3}{5}\) which is \(\frac{11}{3}\) + \(\frac{13}{5}\)
= \(\frac{55+39}{15}\)
= \(\frac{94}{15}\)
= 6\(\frac{4}{15}\).

Question 24.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 4
Answer:
5\(\frac{1}{6}\) – 4\(\frac{1}{7}\) =

Explanation:
The simplest form of 5\(\frac{1}{6}\) – 4\(\frac{1}{7}\) which is \(\frac{31}{6}\) – \(\frac{29}{7}\)
= \(\frac{217-174}{42}\)
= \(\frac{43}{42}\)
= 1\(\frac{1}{42}\).

Question 25.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 5
Answer:
1\(\frac{1}{2}\) + 1\(\frac{2}{3}\) = 3\(\frac{1}{6}\).

Explanation:
The simplest form of 1\(\frac{1}{2}\) + 1\(\frac{2}{3}\) which is \(\frac{3}{2}\) + \(\frac{5}{3}\)
= \(\frac{9+10}{6}\)
= \(\frac{19}{6}\)
= 3\(\frac{1}{6}\).

Question 26.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 6
Answer:
3\(\frac{2}{5}\) – 2\(\frac{1}{4}\) = 1\(\frac{3}{20}\).

Explanation:
The simplest form of 3\(\frac{2}{5}\) – 2\(\frac{1}{4}\) which is \(\frac{17}{5}\) – \(\frac{9}{4}\)
= \(\frac{68-45}{20}\)
= \(\frac{23}{20}\)
= 1\(\frac{3}{20}\).

Question 27.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 7
Answer:
8\(\frac{1}{7}\) – 7\(\frac{1}{8}\) = 1\(\frac{1}{56}\).

Explanation:
The simplest form of 8\(\frac{1}{7}\) – 7\(\frac{1}{8}\) which is \(\frac{57}{7}\) – \(\frac{57}{8}\)
= \(\frac{456-399}{56}\)
= \(\frac{57}{56}\)
= 1\(\frac{1}{56}\).

Question 28.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 8
Answer:
5\(\frac{1}{6}\) + 4\(\frac{1}{7}\) = 9\(\frac{13}{42}\).

Explanation:
The simplest form of 5\(\frac{1}{6}\) + 4\(\frac{1}{7}\) which is \(\frac{31}{6}\) + \(\frac{29}{7}\)
= \(\frac{217+174}{42}\)
= \(\frac{391}{42}\)
= 9\(\frac{13}{42}\).

Solve.

Question 29.
Randy built a pool that is 30 feet x 20 feet. Then he built a wooden deck that is 6 feet wide around all four sides of the pool. What is the area of the deck? Draw a diagram to help you find the answer.
Answer:

Question 30.
Phillip walks 4\(\frac{1}{2}\) blocks to school. Joyce walks 3\(\frac{3}{4}\) blocks to the same school. How much farther does Phillip walk than Joyce?
Answer:

Question 31.
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 9
What subtraction problem is represented on this number line?
Answer:

Question 32.
George recorded the height of his bean plant every week for Week Plant Height (cm) four weeks. If the same pattern continues, how tall will his plant be in the seventh week?
_____________________________________________________
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 10
Answer:
For the seventh week, it will be 14.75 cm.

Explanation:
Given that George recorded the height of his bean plant every week for Week Plant Height (cm) for four weeks. Here, the pattern follows adding 1.75 to the next digit. So for the 5th week, it will be 9.5+1.75 = 11.25
6th week it will be 11.25+1.75 = 13 and for the seventh week, it will be 13+1.75 = 14.75.

Question 33.
Cammie works a total of 25 hours on Friday, Saturday, and Sunday. She works 7 hours on Saturday. She works twice as many hours on Sunday as she does on Friday. How many hours does Cammie work on Sunday?
Answer:

Question 34.
The Romero, Hill. and Johnson families each went on a weekend outing. The Romero’s parking was not the most expensive. The Hill’s parking cost less than the Romero’s. Which location did each family visit?
McGraw Hill Math Grade 5 Chapter 6 Test Answer Key 11
Answer:
Romero’s parking is near the swimming pool,
Hill’s parking is near a forest preserve, and Johnson families parking is near the zoo.

Explanation:
Given that the Romero, Hill. and Johnson families each went on a weekend outing and the Romero’s parking was not the most expensive and Hill’s parking cost less than Romero’s. So Romero’s parking is near the swimming pool which costs $15.50 and Hill’s parking is near a forest preserve which is $12.00 and Johnson families parking is near the zoo which costs $16.00.

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McGraw Hill Math Grade 5 Posttest Answer Key

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 11 Posttest are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Chapter 11 Posttest Answer Key

Write each number in standard form.

Question 1.
39 thousandths
Answer:
The standard form of 39 thousandths is 0.039.

Question 2.
17 and 871 thousandths
Answer:
The standard form of 17 and 871 thousandths is 17.871.

Question 3.
84 billion, 652 million, 34
Answer:
The standard form of 84 billion, 652 million, 34 is 84,652,000,034.

Write each number in word form.

Question 4.
7,111,658,314
Answer:
The word form of the given number 7,111,658,314 is seven billion, one hundred eleven million, six hundred fifty eight thousand, three hundred fourteen.

Question 5.
12,500,500,500
Answer:
The word form of the given number 12,500,500,500 is twelve billion, five hundred million, five hundred thousand, five hundred.

Write >, <, or = to compare each pair of numbers.

Question 6.
1.1 _______ 0.99
Answer:
1.1 > 0.99
Explanation:
The decimal number 1.1 is greater than the decimal number 0.99.

Question 7.
0.012 ________ 0.121
Answer:
0.012 < 0.121
Explanation:
The decimal number 0.012 is less than the decimal number 0.121.

Question 8.
5.687 ________ 5.687
Answer:
5.687 = 5.687
Explanation:
The decimal number 5.687 is equal to the decimal number 5.687.

Round each number to the place of the underlined digit.

Question 9.
7.123
Answer:
7.12
Explanation:
Here the number next to the underlined digit is less than five and so the underlined digit will not have any change. So, the rounded number is 7.12.

Question 10.
4.741
Answer:
5
Explanation:
Here the number next to the underlined digit is greater than five and so 1 is added to the underlined digit. So, the rounded number is 5.

Question 11.
6.148
Answer:
6.1
Explanation:
Here the number next to the underlined digit is less than five and so the underlined digit will not have any change. So, the rounded number is 6.1.

Add. Write the sum.

Question 12.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 1
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-1
Explanation:
Perform addition operation on above two given decimal numbers. Add 3.87 with 2.66 the sum is equal to 6.53.

Question 13.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 2
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-2
Explanation:
Perform addition operation on above two given numbers. Add 791 with 109 the sum is equal to 900.

Question 14.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 3
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-3
Explanation:
Perform addition operation on above two given numbers. Add 680 with 64 the sum is equal to 744.

Question 15.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 4
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-4
Explanation:
Perform addition operation on above two given decimal numbers. Add 4.72 with 0.16 the sum is equal to 4.88.

Question 16.
61,115 + 17,956 __________
Answer:
61,115 + 17,956 = 79,071
Explanation:
Perform addition operation on above two given numbers. Add 61,115 with17,956 the sum is equal to 79,071.

Question 17.
8.46 + 0.54 _____________
Answer:
8.46 + 0.54 = 9.00
Explanation:
Perform addition operation on above two given decimal numbers. Add 8.46 with 0.54 the sum is equal to 9.00.

Question 18.
67.36 + 1.51 _______________
Answer:
67.36 + 1.51 = 68.87 
Explanation:
Perform addition operation on above two given decimal numbers. Add 67.36 with 1.51 the sum is equal to 68.87.

Subtract. Write the difference.

Question 19.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 5
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-5
Explanation:
Perform subtraction operation on above two given numbers. Subtract 24 from 411 the difference is equal to 387.

Question 20.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 6
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-6
Explanation:
Perform subtraction operation on above two given decimal numbers. Subtract 6.21 from 7.01 the difference is equal to 0.80.

Question 21.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 7
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-7
Explanation:
Perform subtraction operation on above two given numbers. Subtract 656 from 815 the difference is equal to 159.

Question 22.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 8
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-8
Explanation:
Perform subtraction operation on above two given decimal numbers. Subtract 37.09 from 214.14 the difference is equal to 177.05.

Question 23.
77,777 – 3,028 = ___________
Answer:
77,777 – 3,028 = 74,749
Explanation:
Perform subtraction operation on above two given numbers. Subtract 3,028 from 77,777 the difference is equal to 74,749.

Question 24.
12,499 – 11,645 = ____________
Answer:
12,499 – 11,645 = 854
Explanation:
Perform subtraction operation on above two given numbers. Subtract 11,645 from 12,499 the difference is equal to 854.

Question 25.
17.66 – 14.76 = _____________
Answer:
17.66 – 14.76 = 2.90
Explanation:
Perform subtraction operation on above two given decimal numbers. Subtract 14.76 from 17.66 the difference is equal to 2.90.

Question 26.
An alligator’s brain weighs about 0.49 ounces. A peach can weigh about 5.5 ounces. How many ounces heavier is a peach than an alligator’s brain?
Answer:
An alligator’s brain weighs about 0.49 ounces.
A peach weigh about 5.5 ounces.
Subtract alligator’s brain weight from peach weight.
5.5 ounces – 0.49 ounces = 5.01 ounces
A peach is 5.01 ounces heavier than an alligator’s brain.

Simplify and complete. Tell what property is represented.

Question 27.
15 × 12 = (________ × 12) + (10 × __________) = 60 + __________ = ___________
_____________ Property
Answer:
15 × 12 = (5 × 12) + (10 × 12) = 60 + 120 = 180
The above property is named as distributive property.
Explanation:
For example take the equation A(B + C). If we want to apply distributive property on the equation A(B + C) we have to multiply A with both B and C and then add.
Distributive property is A (B + C) = A x B + A x C = AB + AC
Here 15 × 12 can be written as (5 + 10)12.
(5 + 10)12 = (5 × 12) + (10 × 12) = 60 + 120 = 180

Question 28.
(8 × 2) × 30 = __________ × (2 × _________) = 8 × ___________ = ___________
______________ Property
Answer:
(8 × 2) × 30 = 8 × (2 × 30) = 8 × 60 = 480
The above property is named as associative property.

Multiply. Write the product.

Question 29.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 9
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-9
Explanation:
Perform multiplication operation on above two given numbers. Multiply 256 with 3 the product is equal to 768.

Question 30.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 10
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-10
Explanation:
Perform multiplication operation on above two given numbers. Multiply 14 with 9 the product is equal to 126.

Question 31.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 11
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-11
Explanation:
Perform multiplication operation on above two given numbers. Multiply 57 with 57 the product is equal to 3,249.

Question 32.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 12
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-12
Explanation:
Perform multiplication operation on above two given numbers. Multiply 764 with 12 the product is equal to 9,168.

Question 33.
A gym has 2-dozen treadmills. Each treadmill weighs 145 pounds. How many pounds do the treadmills weigh in all?
Answer:
A gym has 2-dozen treadmills.
We know that 1 dozen is equal to 12.
2 x 12 = 24 treadmills
Each treadmill weighs 145 pounds.
24 x 145 = 3,480 pounds
All treadmills weighs 3,480 pounds.

Question 34.
1,685 × 102 = ______________
Answer:
1,685 × 102
= 1,685 × 100
= 168,500
Explanation:
Perform multiplication operation on above two given numbers. Multiply 1,685 with 100 the product is equal to 168,500.

Question 35.
59 × 104 = ______________
Answer:
59 × 104
= 59 x 1,0000
= 590,000
Explanation:
Perform multiplication operation on above two given numbers. Multiply 59 with 1,0000 the product is equal to 590,000.

Question 36.
987 × 101 = ______________
Answer:
987 × 101
= 987 x 10
= 9,870
Explanation:
Perform multiplication operation on above two given numbers. Multiply 987 with 10 the product is equal to 9,870.

Divide. Write the quotient.

Question 37.
28 ÷ 5 = _____________
Answer:
28 ÷ 5 = 5.6
Explanation:
Perform division operation on above two given numbers. Here the dividend is 28 and divisor is 5. Divide 28 by 5 the quotient is equal to 5.6.

Question 38.
90 ÷ 2 = _____________
Answer:
90 ÷ 2 = 45
Explanation:
Perform division operation on above two given numbers. Here the dividend is 90 and divisor is 2. Divide 90 by 2 the quotient is equal to 45.

Question 39.
77 ÷ 8 = ______________
Answer:
77 ÷ 8 = 9.625
Explanation:
Perform division operation on above two given numbers. Here the dividend is 77 and divisor is 8. Divide 77 by 8 the quotient is equal to 9.625.

Estimate. Then multiply or divide.

Question 40.
Estimate: 3.02 × 4 = ______________
Multiply: 3.02 × 4 = ______________
Answer:
Estimate:
The estimated product for the expression 3.02 × 4 is 12.
The product for the expression 3.02 × 4 is 12.08.

Question 41.
Estimate: 4.95 × 6 = ______________
Multiply: 4.95 × 6 = ______________
Answer:
The estimated product for the expression 4.95 × 6 is 27.
The product for the expression 4.95 × 6 is 29.7.

Question 42.
Estimate: 6.14 × 3 = ______________
Multiply: 6.14 × 3 = ______________
Answer:
The estimated product for the expression 6.14 × 3 is 18.
The product for the expression 6.14 × 3 is 18.42.

Question 43.
15.88 ÷ 102
Estimate: _____________
Quotient: _____________
Answer:
Here 102 = 100
The estimated quotient for the expression 15.88 ÷ 102 is less than 1.
The quotient for the expression 15.88 ÷ 102 is 0.1588.

Question 44.
872.3 ÷ 104 =
Estimate: _____________
Quotient: _____________
Answer:
Here 104 = 10,000
The estimated quotient for the expression 872.3 ÷ 104  is greater than 0.08.
The quotient for the expression 872.3 ÷ 104 is 0.08723.

Question 45.
298.4 ÷ 101 =
Estimate: _____________
Quotient: _____________
Answer:
Here 101 = 10
The estimated quotient for the expression 298.4 ÷ 101  is greater than 29.
The quotient for the expression 298.4 ÷ 101  is 29.84.

Question 46.
1.37 × 102 =
Estimate: _____________
Product: _____________
Answer:
Here 102 = 100
The estimated product for the expression 1.37 × 102 is 137.
The product for the expression 1.37 × 102 is 137.

Question 47.
7.743 × 104 =
Estimate: _____________
Product: _____________
Answer:
Here 104 = 10,000
The estimated product for the expression 7.743 × 104 is 77,400.
The product for the expression 7.743 × 104 is 77,430.

Question 48.
15.85 × 103 =
Estimate: _____________
Product: _____________
Answer:
Here 103 = 1,000
The estimated product for the expression 15.85 × 103  is 15,800.
The product for the expression 15.85 × 103  is 15,850.

Work backward to solve.

Question 49.
Mr. Pedersen is making a pot of marinara sauce. He pours the sauce into 8 jars. Each jar holds 1.5 quarts of sauce. There are 0.75 quarts of sauce left in the pot. How many quarts of sauce were in the pot before Mr. Pedersen began pouring??
Answer:
He pours the sauce into 8 jars.
One jar holds 1.5 quarts of sauce.
Multiply 1.5 with 8 the product is equal to 12.0 quarts of sauce.
1.5 x 8 = 12.0 quarts
So, 8 jars holds total 12.0 quarts of sauce.
There are 0.75 quarts of sauce left in the pot.
0.75 + 12.0 = 12.75 quarts
12.75 quarts of sauce were in the pot before Mr. Pedersen began pouring.

Simplify and solve. Show your work.

Question 50.
(18 – 8)3 – (12 × 5) × (9 – 4) + 104
Simplify inside the parentheses: _____________
Simplify exponents: _____________
Multiply: _____________
Add and subtract from left to right: _____________
Final answer: _____________
Answer:
Given equation is (18 – 8)3 – (12 × 5) × (9 – 4) + 104
First simplify inside the parentheses:
(10)3 – (60) × (5) + 104
Second simplifying exponents:
1,000 – 60 × 5 + 10,000
Third performing Multiplication:
1,000 – 300 + 10,000
Fourth performing addition and subtraction from left to right:
700 + 10,000 = 10,700
Final answer is equal to 10,700.

Question 51.
6{[4(1 + 7) + 3] – 15}
Simplify inside the parentheses: _____________
Simplify inside the brackets: _____________
Simplify inside the braces: _____________
6{[4(1 + 7) + 3] – 15} = _____________.
Answer:
Given 6{[4(1 + 7) + 3] – 15}
First simplifying inside the parentheses:
6{[4(8) + 3] – 15}
Second simplifying inside the brackets:
6{[32 + 3] – 15}
Third simplifying inside the braces:
= 6{[35] – 15}
= 6{20}
= 120
6{[4(1 + 7) + 3] – 15} = 120

Question 52.
(72 ÷ 8) + (13 – 3)2
Answer:
Given expression is (72 ÷ 8) + (13 – 3)2
First simplifying inside the parenthesis:
(9) + (10)2
Second simplifying exponents:
(9) + 100
Third Perform addition operation:
9 + 100 = 109
(72 ÷ 8) + (13 – 3)2 = 109
Question 53.
14 + 42 × (2 × 4) ÷ 2
Answer:
Given expression is 14 + 42 × (2 × 4) ÷ 2
First simplifying inside the parenthesis:
14 + 42 × (8) ÷ 2
Second simplifying exponents:
14 + 16 × 8 ÷ 2
Third Perform division operation:
14 + 16 x 4
Fourth perform multiplication operation:
14 + 64
Fifth perform addition operation:
14 + 64 = 78

Add or subtract. Give the answers in simplest terms. Change any improper fractions to mixed numbers.

Question 54.
\(\frac{1}{6}\) + \(\frac{2}{6}\) _____________
Answer:
\(\frac{1}{6}\) + \(\frac{2}{6}\) = \(\frac{3}{6}\) or \(\frac{1}{2}\)
Explanation:
Perform addition operation on above two given fraction numbers. Add \(\frac{1}{6}\) with \(\frac{2}{6}\) the sum is equal to \(\frac{3}{6}\). The simplest form of \(\frac{3}{6}\) is \(\frac{1}{2}\).

Question 55.
\(\frac{3}{9}\) + \(\frac{1}{9}\) _____________
Answer:
\(\frac{3}{9}\) + \(\frac{1}{9}\) = \(\frac{4}{9}\)
Explanation:
Perform addition operation on above two given fraction numbers. Add \(\frac{3}{9}\) with \(\frac{1}{9}\) the sum is equal to \(\frac{4}{9}\).

Question 56.
\(\frac{7}{8}\) – \(\frac{1}{8}\) _____________
Answer:
\(\frac{7}{8}\) – \(\frac{1}{8}\) = \(\frac{6}{8}\) or \(\frac{3}{4}\)
Explanation:
Perform subtraction operation on above two given fraction numbers. Subtract \(\frac{1}{8}\) from \(\frac{7}{8}\) the difference is equal to \(\frac{6}{8}\). The simplest form of \(\frac{6}{8}\) is \(\frac{3}{4}\).

Question 57.
\(\frac{4}{9}\) + \(\frac{5}{6}\) _____________
Answer:
\(\frac{4}{9}\) + \(\frac{5}{6}\) = \(\frac{23}{18}\)
Explanation:
Perform addition operation on above two given fraction numbers. Add \(\frac{4}{9}\) with \(\frac{5}{6}\) the sum is equal to \(\frac{23}{18}\). The improper fraction \(\frac{23}{18}\) is converted to mixed number 1\(\frac{5}{18}\)

Question 58.
\(\frac{1}{4}\) – \(\frac{1}{8}\) _____________
Answer:
\(\frac{1}{4}\) – \(\frac{1}{8}\) = \(\frac{1}{8}\)
Explanation:
Perform subtraction operation on above two given fraction numbers. Subtract \(\frac{1}{8}\) from \(\frac{1}{4}\) the difference is equal to \(\frac{1}{8}\).

Question 59.
\(\frac{5}{7}\) – \(\frac{2}{9}\) _____________
Answer:
\(\frac{5}{7}\) – \(\frac{2}{9}\) = \(\frac{31}{63}\)
Explanation:
Perform subtraction operation on above two given fraction numbers. Subtract \(\frac{2}{9}\) from \(\frac{5}{7}\) the difference is equal to \(\frac{31}{63}\).

Question 60.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 13
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-13
Explanation:
The mixed fraction 9\(\frac{3}{8}\) is converted into fraction form as \(\frac{75}{8}\).
The mixed fraction 2\(\frac{1}{5}\) is converted into fraction form as \(\frac{11}{5}\).
Subtract the fraction \(\frac{11}{5}\) from \(\frac{75}{8}\) the difference is equal to \(\frac{287}{40}\).
The fraction \(\frac{287}{40}\) is converted into mixed fraction form 7\(\frac{7}{40}\).

Question 61.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 14
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-14

Explanation:
The mixed fraction 7\(\frac{2}{3}\) is converted into fraction form as \(\frac{23}{3}\).
The mixed fraction 4\(\frac{3}{8}\) is converted into fraction form as \(\frac{35}{8}\).
Add the fraction \(\frac{23}{3}\) with \(\frac{35}{8}\) the sum is equal to \(\frac{289}{24}\).
The fraction \(\frac{289}{24}\) is converted into mixed fraction form 12\(\frac{1}{24}\).

Question 62.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 15
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-15

Explanation:
The mixed fraction 2\(\frac{5}{6}\) is converted into fraction form as \(\frac{17}{6}\).
The mixed fraction 4\(\frac{1}{2}\) is converted into fraction form as \(\frac{9}{2}\).
Add the fraction \(\frac{17}{6}\) with \(\frac{9}{2}\) the sum is equal to \(\frac{44}{6}\) or \(\frac{22}{3}\).
The fraction \(\frac{22}{3}\) is converted into mixed fraction form 7\(\frac{1}{3}\).

Question 63.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 16
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-16

Explanation:
The mixed fraction 5\(\frac{2}{7}\) is converted into fraction form as \(\frac{37}{7}\).
The mixed fraction 3\(\frac{3}{4}\) is converted into fraction form as \(\frac{15}{4}\).
Subtract the fraction \(\frac{15}{4}\) from \(\frac{37}{7}\) the difference is equal to \(\frac{43}{28}\).
The fraction \(\frac{43}{28}\) is converted into mixed fraction form 1\(\frac{15}{28}\).

Find the equivalent fraction.

Question 64.
equivalent to \(\frac{2}{3}\), denominator 9 _____________
Answer:
Multiply numerator and denominator with 3.
The fraction equivalent to \(\frac{2}{3}\) with denominator 9  is \(\frac{6}{9}\).

Question 65.
equivalent to \(\frac{1}{2}\), denominator 20 _____________
Answer:
Multiply numerator and denominator with 10.
The fraction equivalent to \(\frac{1}{2}\) with denominator 20  is \(\frac{10}{20}\).

Question 66.
equivalent to \(\frac{1}{4}\), denominator 28 _____________
Answer:
Multiply numerator and denominator with 7.
The fraction equivalent to \(\frac{1}{4}\) with denominator 28  is \(\frac{7}{28}\).

Question 67.
equivalent to \(\frac{7}{8}\), denominator 16 _____________
Answer:
Multiply numerator and denominator with 2.
The fraction equivalent to \(\frac{7}{8}\) with denominator 16  is \(\frac{14}{16}\).

Multiply.

Question 68.
24 × \(\frac{1}{6}\) ______________
Answer:
24 × \(\frac{1}{6}\) = 4 x 1 = 4
Explanation:
Perform multiplication operation on above numbers. Multiply 24 with \(\frac{1}{6}\) the product is equal to 4.

Question 69.
\(\frac{5}{8}\) × 21 _______________
Answer:
\(\frac{5}{8}\) × 21 = \(\frac{105}{8}\) or 13\(\frac{1}{8}\)
Explanation:
Perform multiplication operation on above numbers. Multiply \(\frac{1}{6}\) with 21 the product is equal to 13\(\frac{1}{8}\).

Question 70.
7 × \(\frac{1}{7}\) _______________
Answer:
7 × \(\frac{1}{7}\) = \(\frac{7}{7}\) = 1
Explanation:
Perform multiplication operation on above numbers. Multiply 7 with \(\frac{1}{7}\) the product is equal to 1.

Solve.

Question 71.
A florist is making an arrangement of 45 roses. The customer has asked that \(\frac{2}{3}\) of the roses be pink. How many pink roses does the florist need?
Answer:
A florist is making an arrangement of 45 roses.
The customer asked that \(\frac{2}{3}\) of the roses should be pink.
Multiply 45 roses with \(\frac{2}{3}\) the product is equal to 30 pink roses.
45 x \(\frac{2}{3}\) = 15 x 2 = 30 pink roses
The florist need 30 pink roses.

Question 72.
\(\frac{3}{4}\) of Diego’s grocery cart is filled with fresh produce, \(\frac{6}{7}\) of the produce is leafy greens. What fraction of the produce is leafy greens?
Answer:

Question 73.
Chase’s journal has 200 pages. So far, he has written 32 pages of journal entries. If he writes \(\frac{1}{2}\) a page every day, how many days will it take him to fill the remaining pages?
Answer:
Chase’s journal has 200 pages.
So far, he wrote 32 pages of journal entries.
He writes \(\frac{1}{2}\) a page every day.
Subtract 32 pages from 200 pages the difference is equal to 168 pages.
200 – 32 = 168 pages
\(\frac{1}{2}\) page = 1 day
168 pages = ? days
(168 x 1)/\(\frac{1}{2}\) = 168 x 2 = 336 days
He will take 336 days to fill the remaining pages.

Multiply to find the area of each rectangle.

Question 74.
9 ft long × \(\frac{3}{8}\) ft wide
area = ________________
Answer:
To calculate area of a rectangle we need to perform multiplication operation.
Area of a rectangle = 9 ft × \(\frac{3}{8}\) ft
= \(\frac{27}{8}\) square feet
= 3\(\frac{3}{8}\) square feet
Area of a rectangle is equal to 3\(\frac{3}{8}\) square feet.

Question 75.
5 m long × \(\frac{1}{3}\) m wide
area = _______________
Answer:
To calculate area of a rectangle we need to perform multiplication operation.
Area of a rectangle = 5 m× \(\frac{1}{3}\) m
= \(\frac{5}{3}\) square meter
= 1\(\frac{2}{3}\) square meter
Area of a rectangle is equal to 1\(\frac{2}{3}\) square meter.

Find each quotient. Draw models to help. Use multiplication to check your answers.

Question 76.
\(\frac{1}{6}\) ÷ 9 = _______________
Answer:
\(\frac{1}{6}\) ÷ 9 = \(\frac{1}{54}\)
To check the answer we need to perform multiplication. Multiply \(\frac{1}{54}\) with 9 the product is equal to \(\frac{1}{6}\). So, the answer is correct.

Question 77.
\(\frac{1}{2}\) ÷ 7 = _______________
Answer:
\(\frac{1}{2}\) ÷ 7 = \(\frac{1}{14}\)
To check the answer we need to perform multiplication. Multiply \(\frac{1}{14}\) with 7 the product is equal to \(\frac{1}{2}\). So, the answer is correct.

Question 78.
9 ÷ \(\frac{1}{8}\) = _______________
Answer:
9 ÷ \(\frac{1}{8}\) = 72
To check the answer we need to perform multiplication. Multiply 72 with \(\frac{1}{8}\) the product is equal to 9. So, the answer is correct.

Solve.

Question 79.
The reptile exhibit at a zoo has a python that is 5 meters long. There is also a coral snake that is 0.6 meters long. How much longer in centimeters is the python than the coral snake?
Answer:
A python is 5 meters long.
A coral snake is 0.6 meters long.
We know that 1 meter is equal to 100 cm.
So, 5 meters is equal to 500 cm.
5 x 100 = 500 cm
So, 0.6 meters is equal to 60 cm.
0.6 x 100 = 60 cm
Subtract 60 cm from 500 cm the difference is equal to 440 cm.
500 – 60 = 440 cm
The python snake is 440 cm longer than the coral snake.

Question 80.
People must be at least 54 inches tall to ride a roller coaster at an amusement park. Gabrielle is 4 feet 3 inches tall. Is she tall enough to ride the coaster? How do you know?
Answer:
To ride a roller coaster at an amusement park people must be at least 54 inches.
Gabrielle is 4 feet 3 inches tall.
We know that 1 feet is equal to 12 inches.
4 feet = 4 x 12 = 48 inches
48 inches + 3 inches = 51 inches
Gabrielle is 51 inches tall.
No, she is 3 inches shorter than the height she need to ride the coaster.

Question 81.
Yolanda is 1 year, 5 days old. Her brother Benjamin is 4 years, 1 week old. How many days older is Benjamin than Yolanda?
Answer:
We know that 1 year is equal to 365 days.
Yolanda is 1 year, 5 days old.
1 year, 5 days = 365 + 5 = 370 days
Yolanda is 370 days old.
Her brother Benjamin is 4 years, 1 week old.
4 years = 4 x 365 = 1,460 days
We know that 1 week is equal to 7 days.
4 years, 1 week = 1,460 + 7 = 1,467 days
Her brother Benjamin is 1,467 days old.
1467 – 370 = 1097 days
Benjamin is 1097 days older than Yolanda.

Question 82.
What temperature does the thermometer show?
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 17
The average temperature in Paris in July is 75?F Is the temperature shown by the thermometer higher or lower than average? How many degrees higher or lower?
Answer:
The thermometer shows the temperature 87℉.
The average temperature in Paris in July is 75℉.
The temperature shown by the thermometer is higher than average.
87℉ – 75℉ = 12℉
12℉ higher.

Use the diagram for Exercises 83 to 85.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 18

Question 83.
Identify 3 points. ________________________
Answer:
The three points are Point A, Point C, Point F.

Question 84.
Identify 2 intersecting lines that are not perpendicular. __________________________
Answer:
The two intersecting lines that are not perpendicular are AB and EF.

Question 85.
Identify 3 line segments. _________________
Answer:
A line segment is part of a line and it has two end points.
One line segment is AE.
Second line segment is CF.
Third line segment is EB.

Classify each angle as straight, right, obtuse, or acute. If you have a protractor, measure each angle. You may need to extend the angle to measure it. Write each measure.

Question 86.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 19
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-19
Explanation:
In the above image we can observe the angle is 81 degrees. The angle which measures less than 90 degrees is called as acute angle. So, the above angle is acute angle.

Question 87.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 20
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-20
In the above image we can observe the angle is 135 degrees. The angle which measures greater than 90 degrees and less than 180 degrees is called as obtuse angle. So, the above angle is obtuse angle.

Place a check mark below the figures that are not polygons.

Question 88.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 21
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-21
Explanation:
Oval shape and incomplete hexagon are not polygons. So, placed a check mark below the respected figures.

Question 89.
Anthony says that trapezoids are parallelograms because trapezoids have a pair of parallel sides. Do you agree? Why or why not?
Answer
No, I don’t agree with Anthony statement because a parallelogram has two pairs of parallel sides and trapezoid have one pair of parallel sides.

Question 90.
Find the volume of the object.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 22
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-22
Explanation:
First we have to separate the given object into two solids then we have to find the volume of each solid.
Volume of one solid:
Length (l) = 12 cm
Width (w) = 6 cm
height (h) = 8 cm
Volume (v) = (l x w) x h
v = (12 cm x 6 cm) x 8 cm
v = 576 cubic centimeters
Volume of another solid:
Length (l) = 6 cm
Width (w) = 6 cm
height (h) = 8 cm
Volume (v) = (l x w) x h
v = (6 cm x 6 cm) x 8 cm
v =288 cubic centimeters
Now we have to add the two volumes.
576 cubic cm + 288 cubic cm = 864 cubic cm
The volume of the object is 864 cubic cm.

Question 91.
The list of data shows the mass in kilograms of 6 flamingos at a zoo. Draw a line plot to show this data set. Then draw a circle around the outlier.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 23
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-21(1)
Explanation:
The above line plot is numbered from 1 to 4 with an interval of 1/4.
The given data is marked on the line plot with X on top of it.

Plot each set of points. Draw lines between the points. Identify the shape.
McGraw Hill Math Grade 5 Chapter 11 Posttest Answer Key 24

Question 92.
A (3, 2)
B (5, 2)
C (3, 7)
D (5, 7)
Identify the shape: __________________
Answer:
McGraw-Hill-Math-Grade-5-Chapter-11-Posttest-Answer-Key-24
Explanation:
After plotting and joining the given set of points we can see a rectangle on the grid.

McGraw Hill Math Grade 5 Posttest Answer Key Read More »

McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 14.1 Understanding Percent will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 14.1 Understanding Percent

Exercises

WRITE DECIMALS AND FRACTIONS

Question 1.
45% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
45% in the decimal form can be written as 0.45
45% in the fraction form can be written as 45/100

Question 2.
35% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
35% in the decimal form can be written as 0.35
35% in the fraction form can be written as 35/100

Question 3.
43% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
43% in the decimal form can be written as 0.43
43% in the fraction form can be written as 43/100

Question 4.
10% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
10% in the decimal form can be written as 0.10
10% in the fraction form can be written as 10/100

Question 5.
87% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
87% in the decimal form can be written as 0.87
87% in the fraction form can be written as 87/100

Question 6.
2% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
2% in the decimal form can be written as 0.2
2% in the fraction form can be written as 20/100

Question 7.
59% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
59% in the decimal form can be written as 0.59
59% in the fraction form can be written as 59/100

Question 8.
.1% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
0.1% in the decimal form can be written as 0.001
0.1% in the fraction form can be written as 1/1000

Question 9.
.45% = McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent 1
Answer:
0.45% in the decimal form can be written as 0.0045
0.45% in the fraction form can be written as 45/10000

Question 10.
Out of 100 questions, Yoshi answered 76 questions correct on his math exam. What percentage of questions did Yoshi answer correctly?
Answer:
Given,
Out of 100 questions, Yoshi answered 76 questions correct on his math exam.
76/100 = 76%
Yoshi answered 76% correctly.

Question 11.
Emily is dividing her birthday cake among 10 people. If each person receives an equal 10% of the cake, how could Emily use fractions to express a single piece of cake? How could she use decimals to express a single piece of cake?
Answer:
Given,
Emily is dividing her birthday cake among 10 people.
10% = 10/100 = 1/10 = 0.1
The fraction to express a single piece of cake is 1/10
The decimals to express a single piece of cake is 0.1

McGraw Hill Math Grade 6 Lesson 14.1 Answer Key Understanding Percent Read More »

McGraw Hill Math Grade 6 Lesson 14.2 Answer Key Percents and Fractions

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 14.2 Percents and Fractions will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 14.2 Percents and Fractions

Exercises

CONVERT

Convert the percent to a fraction and reduce where possible.

Question 1.
35%
Answer:
35% = \(\frac{35}{100}\)
35% can be written in the fraction form as \(\frac{35}{100}\)

Question 2.
47%
Answer:
47% = \(\frac{47}{100}\)
47% can be written in the fraction form as \(\frac{47}{100}\)

Question 3.
25%
Answer:
25% = \(\frac{25}{100}\)
25% can be written in the fraction form as \(\frac{25}{100}\)

Question 4.
6%
Answer:
6% = \(\frac{6}{100}\)
6% can be written in the fraction form as \(\frac{6}{100}\)

Question 5.
91%
Answer:
91% = \(\frac{91}{100}\)
91% can be written in the fraction form as \(\frac{91}{100}\)

Question 6.
52.3%
Answer:
52.3% = \(\frac{523}{1000}\)
52.3% can be written in the fraction form as \(\frac{523}{1000}\)

Question 7.
2.05%
Answer:
2.05% = \(\frac{205}{10000}\)
2.05% can be written in the fraction form as \(\frac{205}{10000}\)

Question 8.
17%
Answer:
17% = \(\frac{17}{100}\)
17% can be written in the fraction form as \(\frac{17}{100}\)

Question 9.
49.5%
Answer:
49.5% = \(\frac{495}{1000}\)
49.5% can be written in the fraction form as \(\frac{495}{1000}\)

Question 10.
.1%
Answer:
0.1% = \(\frac{1}{1000}\)
0.1% can be written in the fraction form as \(\frac{1}{1000}\)

Convert the fraction to a percent. Round to two digits to the right of the decimal.

Question 11.
\(\frac{5}{8}\)
Answer:
\(\frac{5}{8}\) = 0.625
\(\frac{5}{8}\) in the percent form can be written as 0.625 × 100 = 62.5%

Question 12.
\(\frac{1}{9}\)
Answer:
\(\frac{1}{9}\) = 0.11111
\(\frac{1}{9}\) in the percent form can be written as 0.11111 × 100 = 11.11%

Question 13.
\(\frac{15}{16}\)
Answer:
\(\frac{15}{16}\) = 0.9375
\(\frac{15}{16}\) in the percent form can be written as 0.9375 × 100 = 93.75%

Question 14.
\(\frac{3}{13}\)
Answer:
\(\frac{3}{13}\) = 0.23077
\(\frac{3}{13}\) in the percent form can be written as 0.23077 × 100 = 23.08%

Question 15.
\(\frac{1}{10}\)
Answer:
\(\frac{1}{10}\) = 0.1
\(\frac{1}{10}\) in the percent form can be written as 0.1 × 100 = 10%

Question 16.
\(\frac{3}{200}\)
Answer:
\(\frac{3}{200}\) = 0.015
\(\frac{3}{200}\) in the percent form can be written as 0.015 × 100 = 1.5%

Question 17.
\(\frac{5}{3000}\)
Answer:
\(\frac{5}{3000}\) = 0.00167
\(\frac{5}{3000}\) in the percent form can be written as 0.00167 × 100 = 0.17%

Question 18.
\(\frac{5}{7}\)
Answer:
\(\frac{5}{7}\) = 0.71429
\(\frac{5}{7}\) in the percent form can be written as 0.71429 × 100 = 71.43%

Question 19.
\(\frac{454}{1000}\)
Answer:
\(\frac{454}{1000}\) = 0.454
\(\frac{454}{1000}\) in the percent form can be written as 0.454 × 100 = 45.4%

Question 20.
\(\frac{1}{400}\)
Answer:
\(\frac{1}{400}\) = 0.0025
\(\frac{1}{400}\) in the percent form can be written as 0.0025 × 100 = 0.25%

McGraw Hill Math Grade 6 Lesson 14.2 Answer Key Percents and Fractions Read More »

McGraw Hill Math Grade 6 Lesson 1.3 Answer Key Estimating Sums and Differences

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 1.3 Estimating Sums and Differences will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 1.3 Estimating Sums and Differences

Exercises Estimate

Question 1.
54 + 21
Answer:
54
+21
75
The sum of two numbers 54 and 21 is 75.
The actual sum is 75
The estimated sum is 80.

Question 2.
1124 – 555
Answer: 569
1124
-555
569
The difference of the two numbers 1124 and 555 is 569.
The actual difference is 569
The estimated difference is 600

Question 3.
3 + 44
Answer: 47
44
+3
47
The sum of two numbers 44 and 3 is 47.
The actual sum is 47
The estimated sum is 50.

Question 4.
5 + 29
Answer: 34
29
+5
34
The sum of two numbers 29 and 5 is 34
The actual sum is 34
The estimated sum is 30

Question 5.
44 + 46
Answer: 90
44
46
90
The sum of two numbers 44 and 46 is 90.
The actual sum is 90
The estimated sum is 100

Question 6.
670 + 650
Answer: 1320
670
+650
1320
The sum of the two numbers 670 and 650 is 1320
The actual sum is 1320
The estimated sum is 1300

Question 7.
67 – 33
Answer: 34
67
-33
34
The difference of the two numbers 67 and 33 is 34
The actual difference is 34
The estimated difference is 30

Question 8.
655 – 211
Answer: 444
655
-211
444
The difference of the two numbers 655 and 211 is 444
The actual difference is 444
The estimated difference is 400

Question 9.
431 – 251
Answer: 180
431
-251
180
The difference of the two numbers 431 and 251 is 180
The actual difference is 180
The estimated difference is 200

Question 10.
1110 + 250
Answer: 1360
1110
+250
1360
The sum of the two numbers 1110 and 250 is 1360
The actual sum is 1360
The estimated sum is 1400

Question 11.
645 + 655
Answer: 1300
655
+645
1300
The sum of the two numbers 645 and 655 is 1300
The actual sum is 1300
The estimated sum is 1300

Question 12.
533 + 566
Answer: 1099
533
+566
1099
The sum of the two numbers 533 and 566 is 1099
The actual sum is 1099
The estimated sum is 1100

Question 13.
133 + 5675
Answer: 5808
5675
+133
5808
The sum of the two numbers 5675 and 133 is 5808
The actual sum is 5808
The estimated sum is 5800

Question 14.
1333 + 56750
Answer: 58083
56750
+1333
58083
The sum of the two numbers 56750 and 1333 is 58083
The actual sum is 58083
The estimated sum is 58000

Question 15.
677 – 532
Answer: 145
677
-532
145
The difference of the two numbers 677 and 532 is 145
The actual difference is 145
The estimated difference is 150

Question 16.
444 + 555
Answer: 999
444
555
999
The sum of the two numbers 444 and 555 is 999
The actual sum is 999
The estimated sum is 1000

Question 17.
1267 + 3487
Answer: 4754
3487
+1267
4754
The sum of the two numbers 3487 and 1267 is 4754
The actual sum is 4754
The estimated sum is 5000.

Question 18.
21111 – 14750
Answer: 6361
21111
-14750
6361
The difference of the two numbers 21111 and 14750 is 6361
The actual difference is 6361
The estimated difference is 6300

Question 19.
4545 + 5459
Answer: 10004
4545
+5459
10004
The sum of the two numbers 4545 and 5459 is 10004
The actual sum is 10004
The estimated sum is 10000.

Question 20.
750 – 449
Answer: 301
The difference of the two numbers 750 and 449 is 301
The actual difference is 301
The estimated difference is 300

McGraw Hill Math Grade 6 Lesson 1.3 Answer Key Estimating Sums and Differences Read More »

McGraw Hill Math Grade 6 Lesson 12.2 Answer Key Multiplying Money

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 12.2 Multiplying Money will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money

Exercises Multiply

Question 1.
$10.45 × 2.50
Answer: $26.1250
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_1
There are 4 decimal places in both numbers.
So, rewrite the product with 4 total decimals.
So, the product of 10.45 and 2.50 is $26.1250

Question 2.
$101.91 × 1.1
Answer: $112.101
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_2
There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 3 decimal places.
So, the answer is $112.101

Question 3.
$5.76 × 3.75
Answer: $21.6000
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_3
There are 4 decimal places in both numbers.
So, rewrite the product with 4 total decimals.
So, the answer is $21.6

Question 4.
$78.90 × 9.92
Answer: $782.6880
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_4
There are 4 decimal places in both numbers.
So, rewrite the product with 4 total decimals.
So, the answer is $782.6880

Question 5.
$7.29 × 5.5
Answer: 40.095
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_5
There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 3 decimal places.
So, the answer is $40.095

Question 6.
$89.21 × 3
Answer: 267.63
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_6
So, the answer is $267.63

Question 7.
$67.50 × 6.75
Answer: $455.6250
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_7
There are 4 decimal places in both numbers.
So, rewrite the product with 4 total decimals.
So, the answer is $455.6250

Question 8.
$10.00 × 2.3
Answer: 23
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_8
So, the answer is $23.0

Question 9.
$5.50 × 11
Answer: $60.5
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_9
The answer is $60.5

Question 10.
$4.75 × 9.5
Answer: $45.125
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_10
There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 3 decimal places.
So, the answer is $45.125

Question 11.
$85.30 × 5
Answer: $426.5
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_11
So, the answer is $426.5

Question 12.
$33.00 × 2.2
Answer: $72.6
McGraw-Hill Math Grade 6 Answer Key Lesson 12.2 Multiplying Money_12
So, the answer is $72.60

Question 13.
Petra needs to buy gasoline for her car. Gasoline costs $3.66 for a gallon, and she needs 6.75 gallons to fill her tank. How much money will Petra need to spend, in order to fill her tank?
Answer:
Given,
Petra needs to buy gasoline for her car. Gasoline costs $3.66 for a gallon, and she needs 6.75 gallons to fill her tank.
$3.66 × 6.75 = $24.7050
Thus Petra need to spend $24.7050 in order to fill her tank.

Question 14.
Jerry is going to start a collection of marbles with the $5 he received for his weekly allowance. He wants at least 120 marbles to begin his collection. If each individual marble costs 4 cents, will he have enough money to buy 120?
Answer:
Given,
4 cents × 120 = 480
$1 = 100 cents
480/100 = 4.8 dollars
Thus Jerry has enough money to buy marbles.

McGraw Hill Math Grade 6 Lesson 12.2 Answer Key Multiplying Money Read More »

McGraw Hill Math Grade 6 Lesson 12.1 Answer Key Multiplying Decimals

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 12.1 Multiplying Decimals will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 12.1 Multiplying Decimals

Exercises Multiply

Question 1.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 1
Answer: 9586.5
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-1
Thus the product is 9586.5

Question 2.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 2
Answer: 54.39
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-2
Thus the product is 54.39

Question 3.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 3
Answer: 17526.24
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-3
Thus the product is 17526.24

Question 4.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 4
Answer: 110.11
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-4
Thus the product is 110.11

Question 5.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 5
Answer: 137101.44
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-5
Thus the product is 137101.44

Question 6.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 6
Answer: 20340.9
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-6
Thus the product is 20340.9

Question 7.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 7
Answer: 4474.4
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-7
Thus the product is 4474.4

Question 8.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 8
Answer: 1747.20
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-8
Thus the product is 1747.20

Question 9.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 9
Answer: 484.8
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-9
Thus the product is 484.8

Question 10.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 10
Answer: 1484. 7
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-10
Thus the product is 1484.7

Question 11.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 11
Answer: 10.201
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-11
Thus the product is 10.201

Question 12.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 12
Answer: 308.025
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-12
Thus the product is 308.025

Question 13.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 13
Answer: 180.81
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-13
Thus the product is 180.81

Question 14.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 14
Answer: 145.2482
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-14
Thus the product is 145.2482

Question 15.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 15
Answer: 1730.3616
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-15
Thus the product is 1730.3616

Question 16.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 16
Answer: 8.37
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-16
Thus the product is 8.37

Question 17.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 17
Answer: 735.279
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-17
Thus the product is 735.279

Question 18.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 18
Answer: 3.83194
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-18
Thus the product is 3.83194

Question 19.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 19
Answer: 553.125
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-19
Thus the product is 553.125

Question 20.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 20
Answer: 600.7002
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-20
Thus the product is 600.7002

Question 21.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 21
Answer: 1990
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-21
Thus the product is 1990

Question 22.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 22
Answer: 24
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-22
Thus the product is 24

Question 23.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 23
Answer: 0.11234
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-23
Thus the product is 0.11234

Question 24.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 24
Answer: 0.0156
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-24
Thus the product is 0.0156

Question 25.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 25
Answer: 71,782
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-25
Thus the product is 71782

Question 26.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 26
Answer: 76760
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-26
Thus the product is 76760

Question 27.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 27
Answer: 13.2
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-27
Thus the product is 13.2

Question 28.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 28
Answer: 63450
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-28
Thus the product is 63450

Question 29.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 29
Answer: 0.001345
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-29
Thus the product is 0.001345

Question 30.
McGraw Hill Math Grade 6 Chapter 12 Lesson 12.1 Answer Key Multiplying Decimals 30
Answer: 11.11111
McGraw-Hill-Math-Grade-6-Chapter-12-Lesson-12.1-Answer-Key-Multiplying-Decimals-30
Thus the product is 11.11111

McGraw Hill Math Grade 6 Lesson 12.1 Answer Key Multiplying Decimals Read More »

McGraw Hill Math Grade 4 Chapter 12 Lesson 5 Answer Key Four-Sided Shapes

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 12 Lesson 5 Four-Sided Shapes to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 12 Lesson 5 Four-Sided Shapes

Solve

Question 1.
McGraw Hill Math Grade 4 Chapter 12 Lesson 5 Answer Key Four-Sided Shapes 1
How many parallel lines does this shape have?
Does the shape have perpendicular lines?
Are all four sides the same length?
Name the shape
Answer:
The shape has 2 parallel lines
No, the shape do not have perpendicular lines
No, the four sides are not same in length
Name of the shape: Trapezoid.

Question 2.
McGraw Hill Math Grade 4 Chapter 12 Lesson 5 Answer Key Four-Sided Shapes 2
How many parallel lines does this shape have?
Does the shape have perpendicular lines?
Are all four sides the same length?
Name the shape
Answer:
The shape has 4 parallel lines in the shape
Yes, the shape have perpendicular lines
Yes, all the four sides are same in length
Name of the shape: Square.

McGraw Hill Math Grade 4 Chapter 12 Lesson 5 Answer Key Four-Sided Shapes Read More »

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