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McGraw Hill Math Grade 7 Lesson 16.3 Answer Key Scientific Notation

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McGraw-Hill Math Grade 7 Answer Key Lesson 16.3 Scientific Notation

Exercises

CONVERT

If the expression is in scientific notation, convert it to a number. If it is a number, convert it to scientific notation. Round all numbers to 6 places to the right of the decimal point when converting to scientific notation.

Question 1.
5 × 105 = ____________
Answer:
5 × 105 = 500,000
Explanation:
The given expression is in scientific notation. To convert it into a number first we have to solve 105. Here base is 10 and exponent is 5.  So, we have to multiply the base 10 by itself as five times the product is equal to 100,000. Multiply 5 with 100,000 the product is equal to 500,000.

Question 2.
478.23 = _____________
Answer:
478.23 = 4.7823 x 102
Explanation:
There is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved two place values. So, the count is 102. The number 478.23 in scientific notation as 4.7823 x 102.

Question 3.
89,786 = _____________
Answer:
89,786 = 8.9786 x 104
Explanation:
Imagine there is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved four place values. So, the count is 104. The number 89,786 in scientific notation as 8.9786 x 104.

Question 4.
6.721 × 106 = ____________
Answer:
6.721 × 106 = 6,721,000
Explanation:
The given expression is in scientific notation. To convert it into a number first we have to solve 106. Here base is 10 and exponent is 6. So, we have to multiply the base 10 by itself as six times the product is equal to 1,000,000. Multiply 6.721 with 1,000,000 the product is equal to 6,721,000.

Question 5.
2.9731 × 10-2 = ______________
Answer:
2.9731 × 10-2 = 0.029731
Explanation:
The given expression is in scientific notation. To convert it into a number first we have to solve 10-2. Here base is 10 and exponent is -2. So, we have to multiply the base 10 by itself as two times the product is equal to 0.01. Multiply 2.9731 with 0.01 the product is equal to 0.029731.

Question 6.
691,273 = _____________
Answer:
691,273 = 6.91273 x 105
Explanation:
Imagine there is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved five place values. So, the count is 105. The number 691,273 in scientific notation as 6.91273 x 105.

Question 7.
5,9178 × 10-3 = ____________
Answer:
5,9178 × 10-3 = 0.0059178
Explanation:
The given expression is in scientific notation. To convert it into a number first we have to solve 10-3. Here base is 10 and exponent is -3. So, we have to multiply the base 10 by itself as three times the product is equal to 0.001. Multiply 5,9178 with 0.001 the product is equal to 0.0059178.

Question 8.
8.72345 × 1010 = ______________
Answer:
8.72345 × 1010 = 87,234,500,000
Explanation:
The given expression is in scientific notation. To convert it into a number first we have to solve 1010. Here base is 10 and exponent is 10. So, we have to multiply the base 10 by itself as ten times. Multiply 8.72345 with 1010 the product is equal to 87,234,500,000.

Question 9.
6,664,475 = _____________
Answer:
6,664,475 = 6.664475 x 106
Explanation:
Imagine there is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved six place values. So, the count is 106. The number 6,664,475 in scientific notation as 6.664475 x 106.

Question 10.
.0005123 = ______________
Answer:
.0005123= 5.123 x 10-4
Explanation:
There is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the right, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved four place values to left . So, the count is 10-4. The number .0005123 in scientific notation as 5.123 x 10-4.

Question 11.
8.9 = ______________
Answer:
8.9 = 8.9 x 100
Explanation:
There is a decimal point to the right of the given number. The number 8 is greater than 1 and less than 10. Here I moved zero place values to right . So, the count is 100. The number 8.9 in scientific notation as 8.9 x 100.

Question 12.
100.235 = _______________
Answer:
100.235 = 1.00235 x 102
Explanation:
There is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved two place values. So, the count is 102. The number 100.235 in scientific notation as 1.00235 x 102.

Question 13.
963,764 = _____________
Answer:
963,764 = 9.63764 x 105
Explanation:
Imagine there is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved five place values. So, the count is 105. The number 963,764 in scientific notation as 9.63764 x 105.

Question 14.
4.6554 = _____________
Answer:
4.6554 = 4.6554 x 100
Explanation:
There is a decimal point to the right of the given number. The number 4 is greater than 1 and less than 10. Here I moved zero place values to right . So, the count is 100. The number 4.6554 in scientific notation as 4.6554 x 100.

Question 15.
789.23 = _______________
Answer:
789.23 = 7.8923 x 102
Explanation:
There is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved two place values. So, the count is 102. The number 789.23 in scientific notation as 7.8923 x 102.

Question 16.
15,896,000,000,000 = ______________
Answer:
15,896,000,000,000 = 1.5896 x 1013
Explanation:
Imagine there is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved thirteen place values. So, the count is 1013. The number 15,896,000,000,000 in scientific notation as 1.5896 x 1013.

Question 17.
8,999,345,000 = ________________
Answer:
8,999,345,000 = 8.999345 x 109
Explanation:
Imagine there is a decimal point to the right of the given number. To convert the given number into scientific notation we have to move the decimal point to the left, one place value at a time and we have to count each time we move it.
We have to stop the process when the number is greater than 1 and less than 10. Here I moved nine place values. So, the count is 109. The number 8,999,345,000 in scientific notation as 8.999345 x 109.

Question 18.
1.697324 × 104 = ______________
Answer:
1.697324 × 104 = 16,973.24
Explanation:
The given expression is in scientific notation. To convert it into a number first we have to solve 104. Here base is 10 and exponent is 4. So, we have to multiply the base 10 by itself as four times the product is equal to 10,000. Multiply 1.697324 with 10,000 the product is equal to 16,973.24.

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McGraw Hill Math Grade 7 Lesson 16.2 Answer Key Square Roots

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McGraw-Hill Math Grade 7 Answer Key Lesson 16.2 Square Roots

Exercises

CALCULATE

Identify the square root.

Question 1.
\(\sqrt{36}\) ______________
Answer:
\(\sqrt{36}\) = 6
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{36}\) is equal to 6 because 6 x 6 is equal to 36.

Question 2.
\(\sqrt{144}\) ______________
Answer:
\(\sqrt{144}\) = 12
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{144}\) is equal to 12 because 12 x 12 is equal to 144.

Question 3.
\(\sqrt{81}\) ______________
Answer:
\(\sqrt{81}\) = 9
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{81}\) is equal to 9 because 9 x 9 is equal to 81.

Question 4.
\(\sqrt{25}\) ______________
Answer:
\(\sqrt{25}\) = 5
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{25}\) is equal to 5 because 5 x 5 is equal to 25.

Question 5.
\(\sqrt{169}\) ______________
Answer:
\(\sqrt{169}\) = 13
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{169}\) is equal to 13 because 13 x 13 is equal to 169.

Question 6.
\(\sqrt{9}\) ______________
Answer:
\(\sqrt{9}\) = 3
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{9}\) is equal to 3 because 3 x 3 is equal to 9.

Question 7.
\(\sqrt{1}\) ______________
Answer:
\(\sqrt{1}\) = 1
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{1}\) is equal to 1 because 1 x 1 is equal to 1.

Question 8.
\(\sqrt{49}\) ______________
Answer:
\(\sqrt{49}\) = 7
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{49}\) is equal to 7 because 7 x 7 is equal to 49.

Question 9.
\(\sqrt{4}\) ______________
Answer:
\(\sqrt{4}\) = 2
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{4}\) is equal to 2 because 2 x 2 is equal to 4.

Question 10.
\(\sqrt{100}\) ______________
Answer:
\(\sqrt{100}\) = 10
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{100}\) is equal to 10 because 10 x 10 is equal to 100.

Question 11.
\(\sqrt{16}\) ______________
Answer:
\(\sqrt{16}\) = 4
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{16}\) is equal to 4 because 4 x 4 is equal to 16.

Question 12.
\(\sqrt{121}\) ______________
Answer:
\(\sqrt{121}\) = 11
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{121}\) is equal to 11 because 11 x 11 is equal to 121.

Question 13.
\(\sqrt{64}\) ______________
Answer:
\(\sqrt{64}\) = 8
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{64}\) is equal to 8 because 8 x 8 is equal to 64.

Question 14.
\(\sqrt{225}\) ______________
Answer:
\(\sqrt{225}\) = 15
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. The \(\sqrt{225}\) is equal to 15 because 15 x 15 is equal to 225.

Estimate.

Question 15.
\(\sqrt{12}\) is between ___________ and __________
Answer:
\(\sqrt{12}\) is between 3 and 4
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. We know that 3 x 3 = 9 and 4 x 4 = 16. The \(\sqrt{12}\) is in between 3 and 4.

Question 16.
\(\sqrt{41}\) is between ___________ and __________
Answer:
\(\sqrt{41}\) is between 6 and 7
Explanation:
The square root of a number is the number that, when multiplied by itself is equal to that number. We know that 6 x 6 = 36 and 7 x 7 = 49. The \(\sqrt{41}\) is in between 6 and 7.

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McGraw Hill Math Grade 7 Lesson 16.1 Answer Key Exponents

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McGraw-Hill Math Grade 7 Answer Key Lesson 16.1 Exponents

Exercises

CALCULATE

Question 1.
122 = _____________
Answer:
122 = 12 x 12 = 144
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 12 and exponent is 2.  So, we have to multiply the base 12 by itself as two times the product is equal to 144.

Question 2.
104 = _____________
Answer:
104 = 10 x 10 x 10 x 10 = 10,000
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 10 and exponent is 4.  So, we have to multiply the base 10 by itself as four times the product is equal to 10,000.

Question 3.
73 = _____________
Answer:
73 = 7 x 7 x 7 = 343
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 7 and exponent is 3.  So, we have to multiply the base 7 by itself as three times the product is equal to 343.

Question 4.
23 = _____________
Answer:
23 = 2 x 2 x 2 = 8
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 2 and exponent is 3.  So, we have to multiply the base 2 by itself as three times the product is equal to 8.

Question 5.
44 = _____________
Answer:
44 = 4 x 4 x 4 x 4 = 256
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 4 and exponent is 4.  So, we have to multiply the base 4 by itself as four times the product is equal to 256.

Question 6.
53 = _____________
Answer:
53 = 5 x 5 x 5 = 125
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 5 and exponent is 3.  So, we have to multiply the base 5 by itself as three times the product is equal to 125.

Question 7.
412 = _____________
Answer:
412 = 41 x 41= 1,681
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 41 and exponent is 2.  So, we have to multiply the base 41 by itself as two times the product is equal to 1,681.

Question 8.
55 = _____________
Answer:
55 = 5 x 5 x 5 x 5 = 3,125
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 5 and exponent is 5.  So, we have to multiply the base 5 by itself as five times the product is equal to 3,125.

Question 9.
67 = _____________
Answer:
67 = 6 x 6 x 6 x 6 x 6 x 6 x 6 = 279,936
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 6 and exponent is 7.  So, we have to multiply the base 6 by itself as seven times the product is equal to 279,936.

Question 10.
174 = _____________
Answer:
174 = 17 x 17 x 17 x 17 = 83,521
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 17 and exponent is 4.  So, we have to multiply the base 17 by itself as four times the product is equal to 83,521.

Question 11.
010 = _____________
Answer:
010 = 0
Explanation:
The exponent number tells how many times we have to multiply the base by itself.  Here base is 0 and exponent is 10.  So, we have to multiply the base 0 by itself as ten times the product is equal to 0.

Question 12.
1010 = _____________
Answer:
1010 = 1
A base raised to the zero power is equal to 1. So, 1010 is equal to 1.

Question 13.
121 = _____________
Answer:
121 = 12
A base raised to the first power is equal to the base. So, 121 is equal to 12.

Question 14.
240 = _____________
Answer:
240 = 1
A base raised to the zero power is equal to 1. So, 240 is equal to 1.

Question 15.
331 = _____________
Answer:
331 = 33
A base raised to the first power is equal to the base. So, 331 is equal to 33.

MULTIPLY OR DIVIDE

Question 1.
23 ÷ 2-5 = _____________
Answer:
23 ÷ 2-5 = 2(3 – (-5))  = 28 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 28.

Question 2.
55 × 5-6 = _____________
Answer:
55 × 5-6 = 5(5 + (-6))  = 5-1 = 1/5   
Explanation:
If we want to multiply a base raised to a power by the same base raised to a power then we have to add the exponents. Here both the bases are same. After adding the exponents the result is equal to 5-1.

Question 3.
1111 ÷ 114 = _____________
Answer:
1111 ÷ 114 = 11(11 – 4)  = 117 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 117.

Question 4.
544 ÷ 54-2 = _____________
Answer:
544 ÷ 54-2 = 54(4 – (-2)) = 54(4 + 2)= 546 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 546.

Question 5.
32 ÷ 30 = _____________
Answer:
32 ÷ 30 = 3(2 – 0) = 32 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 32.

Question 6.
81 × 88 = _____________
Answer:
81 × 88 = 8(1 + 8)  = 89    
Explanation:
If we want to multiply a base raised to a power by the same base raised to a power then we have to add the exponents. Here both the bases are same. After adding the exponents the result is equal to 89.

Question 7.
155 ÷ 154 = _____________
Answer:
155 ÷ 154 = 15(5 – 4) = 151 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 15.

Question 8.
86 ÷ 82 = _____________
Answer:
86 ÷ 82 = 8(6 – 2) = 84 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 84.

Question 9.
187 × 1821 = _____________
Answer:
187 × 1821 = 18(7 + 21)  = 1828    
Explanation:
If we want to multiply a base raised to a power by the same base raised to a power then we have to add the exponents. Here both the bases are same. After adding the exponents the result is equal to 1828.

Question 10.
8110 ÷ 817 = _____________
Answer:
8110 ÷ 817 = 81(10 – 7) = 813 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 813.

Question 11.
1919 × 1916 = _____________
Answer:
1919 × 1916 = 19(19 + 16)  = 1935    
Explanation:
If we want to multiply a base raised to a power by the same base raised to a power then we have to add the exponents. Here both the bases are same. After adding the exponents the result is equal to 1935.

Question 12.
212 ÷ 213 = _____________
Answer:
212 ÷ 213 = 21(2 – 3) = 21-1 = 1/21 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 1/21.

Question 13.
15-5 ÷ 156 = _____________
Answer:
15-5 ÷ 156 = 15(-5 – 6) = 15-11 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 15-11.

Question 14.
10-8 ÷ 10-12 = _____________
Answer:
10-8 ÷ 10-12 = 10(-8 – (-12)) =10(-8 + 12)= 104 
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 10,000.

Question 15.
1715 ÷ 1722 = _____________
Answer:
1715 ÷ 1722 = 17(15 – 22) = 17-7 = 1/177
Explanation:
If we want to divide a base raised to a power by the same base raised to a power then we have to subtract the exponents. Here both the bases are same. After subtracting the exponents the result is equal to 17-7.

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McGraw Hill Math Grade 8 Lesson 4.2 Answer Key Multiplying Two Fractions: Reciprocals

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 4.2 Multiplying Two Fractions: Reciprocals to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 4.2 Multiplying Two Fractions: Reciprocals

Exercises Multiply

Question 1.
\(\frac{3}{2}\) × \(\frac{4}{9}\)
Answer:
\(\frac{2}{3}\),

Explanation:
When we multiply \(\frac{3}{2}\) X \(\frac{4}{9}\), We get \(\frac{3 X 4}{2 X 9}\) = \(\frac{12}{18}\) both goes by 6 we get  \(\frac{6 X 2}{6 X 3}\) = \(\frac{2}{3}\).

Question 2.
\(\frac{5}{9}\) × \(\frac{12}{30}\)
Answer:
\(\frac{2}{9}\),

Explanation:
When we multiply \(\frac{5}{9}\) X \(\frac{12}{30}\) we get \(\frac{5 X 12}{9 X 30}\) = \(\frac{60}{270}\) both goes by 30, So \(\frac{2 X 30}{9 X 30}\) = \(\frac{2}{9}\).

Question 3.
\(\frac{15}{21}\) × \(\frac{6}{25}\)
Answer:
\(\frac{6}{35}\),

Explanation:
When we multiply \(\frac{15}{21}\) X \(\frac{6}{25}\) we get
\(\frac{15 X 6}{21 X 25}\) = \(\frac{90}{525}\) both goes by 15, So \(\frac{6 X 15}{35 X 15}\) = \(\frac{6}{35}\),

Question 4.
\(\frac{1}{2}\) × \(\frac{1}{2}\)
Answer:
\(\frac{1}{4}\),

Explanation:
When we multiply \(\frac{1}{2}\) X \(\frac{1}{2}\) we get \(\frac{1 X 1}{2 X 2}\) = \(\frac{1}{4}\).

Question 5.
\(\frac{2}{3}\) × \(\frac{3}{4}\)
Answer:
\(\frac{1}{2}\),

Explanation:
When we multiply \(\frac{2}{3}\) X \(\frac{3}{4}\) we get
\(\frac{2 X 3}{3 X 4}\) = \(\frac{6}{12}\) both goes by 6, So
\(\frac{1 X 6}{2 X 6}\) = \(\frac{1}{2}\).

Question 6.
\(\frac{5}{4}\) × \(\frac{16}{35}\)
Answer:
\(\frac{4}{7}\),

Explanation:
When we multiply \(\frac{5}{4}\) X \(\frac{16}{35}\) we get
\(\frac{5 X 16}{4 X 35}\) = \(\frac{80}{140}\) both goes by 20, So
\(\frac{4 X 20}{7 X 20}\) = \(\frac{4}{7}\),

Question 7.
\(\frac{5}{18}\) × \(\frac{9}{25}\)
Answer:
\(\frac{1}{10}\),

Explanation:
When we multiply \(\frac{5}{18}\) X \(\frac{9}{25}\) we get \(\frac{5 X 9}{18 X 25}\) = \(\frac{45}{450}\) both goes by 45, So
\(\frac{1 X 45}{10 X 45}\) = \(\frac{1}{10}\).

Question 8.
\(\frac{4}{14}\) × \(\frac{28}{64}\)
Answer:
\(\frac{1}{8}\),

Explanation:
When we multiply \(\frac{4}{14}\) X \(\frac{28}{64}\) we get
\(\frac{4 X 28}{14 X 64}\) = \(\frac{112}{896}\) both goes by 112, So \(\frac{1}{8}\).

Question 9.
\(\frac{13}{22}\) × \(\frac{11}{13}\)
Answer:
\(\frac{1}{2}\),

Explanation:
When we multiply \(\frac{13}{22}\) X \(\frac{11}{13}\) we get
\(\frac{13 X 11}{22 X 13}\) = \(\frac{143}{286}\) both goes by 143,
So \(\frac{1 X 143}{2 X 286}\).

Question 10.
\(\frac{12}{13}\) × \(\frac{52}{72}\)
Answer:
\(\frac{2}{3}\),

Explanation:
When we multiply \(\frac{12}{13}\) X \(\frac{52}{72}\) we get
\(\frac{12 X 52}{13 X 72}\) = \(\frac{624}{936}\) both goes by 312,
So \(\frac{2 X 312}{3 X 312}\) = \(\frac{2}{3}\).

Question 11.
\(\frac{2}{15}\) × \(\frac{2}{15}\)
Answer:
\(\frac{4}{225}\),

Explanation:
When we multiply \(\frac{2}{15}\) X \(\frac{2}{15}\) we get
\(\frac{2 X 2}{15 X 15}\) = \(\frac{4}{225}\).

Question 12.
\(\frac{21}{24}\) × \(\frac{8}{35}\)
Answer:
\(\frac{1}{5}\),

Explanation:
When we multiply \(\frac{21}{24}\) X \(\frac{8}{35}\) we get
\(\frac{21 X 8}{24 X 35}\) = \(\frac{168}{840}\) both goes by 168, \(\frac{1}{5}\).

Question 13.
\(\frac{48}{21}\) × \(\frac{42}{64}\)
Answer:
\(\frac{3}{2}\),

Explanation:
When we multiply \(\frac{48}{21}\) X \(\frac{42}{64}\) we get
\(\frac{48 X 42}{21 X 64}\) = \(\frac{2016}{1344}\) both goes by 672, So \(\frac{3}{2}\).

Question 14.
\(\frac{7}{9}\) × \(\frac{9}{14}\)
Answer:
\(\frac{1}{2}\),

Explanation:
When we multiply \(\frac{7}{9}\) X \(\frac{9}{14}\) we get
\(\frac{7 X 9}{9 X 14}\) = \(\frac{63}{126}\) both goes by 63, So \(\frac{1 x 63}{2 X 63}\) = \(\frac{1}{2}\).

Question 15.
\(\frac{15}{18}\) × \(\frac{9}{25}\)
Answer:
\(\frac{3}{10}\),

Explanation:
When we multiply \(\frac{15}{18}\) X \(\frac{9}{25}\) we get \(\frac{15 X 9}{18 X 25}\) = \(\frac{135}{450}\) both goes by 45, So \(\frac{3 X 45}{10 X 45}\) = \(\frac{3}{10}\).

Question 16.
\(\frac{10}{13}\) × \(\frac{26}{45}\)
Answer:
\(\frac{4}{9}\),

Explanation:
When we multiply \(\frac{10}{13}\) X \(\frac{26}{45}\) we get
\(\frac{10 X 26}{13 X 45}\) = \(\frac{260}{585}\) both goes by 65,
So \(\frac{4 X 65}{9 X 65}\) = \(\frac{4}{9}\).

Question 17.
Daisy runs on an oval track that is \(\frac{1}{4}\) of a mile long. If she runs \(\frac{5}{16}\) of the way around the track, how far did she run?
Answer:
\(\frac{5}{64}\) mile long Daisy ran on an oval track,

Explanation:
When Daisy runs we multiply \(\frac{1}{4}\) mile long track with  \(\frac{5}{16}\) way Daisy ran around the track  we get \(\frac{1 X 5}{4 X 16}\) = \(\frac{5}{64}\) mile long Daisy ran.

Question 18.
Bart’s family’s motorboat uses \(\frac{22}{6}\) gallons of gas every hour. If they run the boat for \(\frac{1}{3}\) of an hour, how much gas will they be using?
Answer:
\(\frac{11}{9}\) gallons of gas will be used every hour,

Explanation:
When we multiply Bart’s family’s motorboat uses  \(\frac{22}{6}\) gallons of gas is used every hour by Barts family’s boat  \(\frac{1}{3}\) of an hour, we get \(\frac{22 X 1}{6 X 3}\) = \(\frac{22}{18}\) both goes by 2 we get \(\frac{11 X 2}{9 X 2}\) =  \(\frac{11}{9}\) gallons of gas would be used for every hour.

McGraw Hill Math Grade 8 Lesson 4.2 Answer Key Multiplying Two Fractions: Reciprocals Read More »

McGraw Hill Math Grade 8 Lesson 4.1 Answer Key Multiplying Fractions and Whole Numbers

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 4.1 Multiplying Fractions and Whole Numbers to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 4.1 Multiplying Fractions and Whole Numbers

Exercises Multiply

Question 1.
13 × \(\frac{1}{4}\)
Answer:
\(\frac{13}{4}\),

Explanation:
When 13 is multiplied by \(\frac{1}{4}\) we get \(\frac{13 X 1}{4}\) = \(\frac{13}{4}\).

Question 2.
15 × \(\frac{2}{7}\)
Answer:
\(\frac{30}{7}\),

Explanation:
When 15 is multiplied by \(\frac{2}{7}\) we get \(\frac{15 X 2}{7}\) = \(\frac{15}{7}\).

Question 3.
22 × \(\frac{3}{8}\)
Answer:
\(\frac{33}{4}\),

Explanation:
When 22 is multiplied by \(\frac{3}{8}\) we get \(\frac{22 X 3}{8}\) = \(\frac{33}{4}\).

Question 4.
24 × \(\frac{3}{4}\)
Answer:
\(\frac{72}{4}\) = 18,

Explanation:
When 24 is multiplied by \(\frac{3}{4}\) we get \(\frac{24 X 3}{4}\) = \(\frac{72}{4}\) = 18.

Question 5.
18 × \(\frac{7}{20}\)
Answer:
\(\frac{63}{10}\),

Explanation:
When 18 is multiplied by \(\frac{7}{20}\) we get \(\frac{18 X 7}{20}\) = \(\frac{63}{10}\).

Question 6.
31 × \(\frac{2}{17}\)
Answer:
\(\frac{62}{17}\),

Explanation:
When 31 is multiplied by \(\frac{2}{17}\) we get \(\frac{31 X 2}{17}\) = \(\frac{62}{17}\).

Question 7.
6 × \(\frac{7}{24}\)
Answer:
\(\frac{7}{4}\),

Explanation:
When 6 is multiplied by \(\frac{7}{24}\) we get \(\frac{6 X 7}{24}\) = \(\frac{7}{4}\).

Question 8.
14 × \(\frac{10}{11}\)
Answer:
\(\frac{140}{11}\),
Explanation:
When 14 is multiplied by \(\frac{10}{11}\) we get \(\frac{14 X 10}{11}\) = \(\frac{140}{11}\).

Question 9.
16 × \(\frac{5}{36}\)
Answer:
\(\frac{20}{9}\),

Explanation:
When 16 is multiplied by \(\frac{5}{36}\) we get \(\frac{16 X 5}{36}\) = \(\frac{20}{9}\).

Question 10.
7 × \(\frac{2}{3}\)
Answer:
\(\frac{14}{3}\),

Explanation:
When 7 is multiplied by \(\frac{2}{3}\) we get \(\frac{7 X 2}{3}\) = \(\frac{14}{3}\).

Question 11.
16 × \(\frac{3}{5}\)
Answer:
\(\frac{48}{5}\),

Explanation:
When 16 is multiplied by \(\frac{3}{5}\) we get \(\frac{16 X 3}{5}\) = \(\frac{48}{5}\).

Question 12.
14 × \(\frac{11}{28}\)
Answer:
\(\frac{11}{2}\),

Explanation:
When 14 is multiplied by \(\frac{11}{28}\) we get \(\frac{14 X 11}{28}\) = \(\frac{154}{28}\) both goes by 14 as \(\frac{14 X 1 X 11}{14 X 2}\) = \(\frac{11}{2}\).

Question 13.
44 × \(\frac{6}{7}\)
Answer:
\(\frac{264}{7}\),

Explanation:
When 44 is multiplied by \(\frac{6}{7}\) we get \(\frac{44 X 6}{7}\) = \(\frac{264}{7}\).

Question 14.
20 × \(\frac{23}{40}\)
Answer:
\(\frac{23}{2}\),

Explanation:
When 20 is multiplied by \(\frac{23}{40}\) we get \(\frac{20 X 23}{40}\) = \(\frac{460}{40}\) both goes by 20 we get \(\frac{20 X 1 X 23}{20 X 1 X 2}\) = \(\frac{1 X 23}{1 X 2}\) = \(\frac{23}{2}\).

Question 15.
33 × \(\frac{6}{11}\)
Answer:
\(\frac{198}{11}\) = 18,

Explanation:
When 33 is multiplied by \(\frac{6}{11}\) we get \(\frac{33 X 6}{11}\) = \(\frac{11 X 3 X 6}{11}\) = 3 X 6 = 18.

Question 16.
25 × \(\frac{16}{45}\)
Answer:
\(\frac{80}{9}\),

Explanation:
When 25 is multiplied by \(\frac{16}{45}\) we get \(\frac{25 X 16}{45}\) = \(\frac{400}{45}\) both goes in 5 as \(\frac{80 X 5}{9 X 5}\) = \(\frac{80}{9}\).

Question 17.
Before setting out on a bike ride, each rider was given \(\frac{5}{8}\) gallons of water to carry with them on the trip. If there are 28 people on the bike, ride, how much water was dispensed?
Answer:
\(\frac{35}{2}\) gallons of water,

Explanation:
When 28 people on the bike is multiplied by \(\frac{5}{8}\) gallons of water to carry with them on the trip we get \(\frac{28 X 5}{8}\) = \(\frac{140}{8}\) both goes by 4 so \(\frac{35}{2}\). Therefore \(\frac{35}{2}\) water was dispensed before setting out on a bike ride.

Question 18.
Norbert estimates that it takes 1\(\frac{2}{7}\) hours to complete one load of laundry. If Norbert’s dad has 8 loads of laundry to do, how long will it take him to finish?
Answer:
\(\frac{72}{7}\) or 10\(\frac{2}{7}\),

Explanation:
Given Norbert estimates that it takes 1\(\frac{2}{7}\) hours to complete one load of laundry. Then 1\(\frac{2}{7}\) hours = \(\frac{1 X 7 + 2}{7}\)
= \(\frac{9}{7}\) now long it will take Norbet to finish the work is \(\frac{9}{7}\) X 8 = \(\frac{9 X 8}{7}\) = \(\frac{72}{7}\) as numerator
is greater than denominator we write in mixed fraction as \(\frac{10 X 7 + 2}{7}\) = 10\(\frac{2}{7}\).

McGraw Hill Math Grade 8 Lesson 4.1 Answer Key Multiplying Fractions and Whole Numbers Read More »

McGraw Hill Math Grade 8 Lesson 3.6 Answer Key Reducing Fractions

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 3.6 Reducing Fractions to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 3.6 Reducing Fractions

Exercises Multiply

Question 1.
\(\frac{8}{20}\)
Answer:
\(\frac{2}{5}\),

Explanation:
Given to reduce \(\frac{8}{20}\) as both goes by 4 we get \(\frac{8}{20}\) = \(\frac{2 X 4}{5 X 4}\) = \(\frac{2}{5}\).

Question 2.
\(\frac{49}{588}\)
Answer:
\(\frac{1}{12}\),

Explanation:
Given to reduce \(\frac{49}{588}\) as both goes by 49 we get \(\frac{49}{588}\) \(\frac{1 X 49}{12 X 49}\) = \(\frac{1}{12}\).

Question 3.
\(\frac{525}{1890}\)
Answer:
\(\frac{105}{378}\),

Explanation:
Given to reduce \(\frac{525}{1,890}\) as both goes by 5 we get \(\frac{525}{1,890}\) = \(\frac{105 X 5}{378 X 5}\) = \(\frac{105}{378}\).

Question 4.
\(\frac{168}{3080}\)
Answer:
\(\frac{21}{385}\),

Explanation:
Given to reduce \(\frac{168}{3,080}\) as both goes by 8 we get \(\frac{168}{3,080}\) = \(\frac{21 X 8}{385 X 8}\) = \(\frac{21}{385}\).

Question 5.
\(\frac{24}{150}\)
Answer:
\(\frac{4}{25}\),

Explanation:
Given to reduce \(\frac{24}{150}\) as both goes by 6 we get \(\frac{24}{150}\) = \(\frac{4 X 6}{25 X 6}\) = \(\frac{4}{25}\).

Question 6.
\(\frac{18}{546}\)
Answer:
\(\frac{3}{91}\),

Explanation:
Given to reduce \(\frac{18}{546}\) as both goes by 6 we get \(\frac{18}{546}\) = \(\frac{3 X 6}{91 X 6}\) = \(\frac{3}{91}\).

Question 7.
\(\frac{120}{336}\)
Answer:
\(\frac{5}{14}\),

Explanation:
Given to reduce \(\frac{120}{336}\) as both goes by 24 we get \(\frac{120}{336}\) = \(\frac{5 X 24}{14 X 24}\) = \(\frac{5}{14}\).

Question 8.
\(\frac{220}{650}\)
Answer:
\(\frac{22}{65}\),

Explanation:
Given to reduce \(\frac{220}{650}\) as both goes by 10 we get \(\frac{220}{650}\) = \(\frac{22 X 10}{65 X 10}\) = \(\frac{22}{65}\).

Question 9.
\(\frac{3}{18}\)
Answer:
\(\frac{1}{6}\),

Explanation:
Given to reduce \(\frac{3}{18}\) as both goes by 3 we get \(\frac{3}{18}\) = \(\frac{1 X 3}{6 X 3}\) = \(\frac{1}{6}\).

Question 10.
\(\frac{42}{110}\)
Answer:
\(\frac{21}{55}\),

Explanation:
Given to reduce \(\frac{42}{110}\) both goes by 2 we get \(\frac{42}{110}\) = \(\frac{21 X 2}{55 X 2}\) = \(\frac{21}{55}\).

Question 11.
\(\frac{3276}{5712}\)
Answer:
\(\frac{39}{68}\),

Explanation:
Given to reduce \(\frac{3,276}{5,712}\) both goes by 84 we get \(\frac{3,276}{5,712}\) = \(\frac{39 X 84}{68 X 84}\) = \(\frac{39}{68}\).

Question 12.
\(\frac{686}{2000}\)
Answer:
\(\frac{343}{1,000}\),

Explanation:
Given to reduce \(\frac{686}{2,000}\) both goes by 2 as \(\frac{686}{2,000}\) = \(\frac{343 X 2}{1,000 X 2}\) = \(\frac{343}{1,000}\).

Question 13.
\(\frac{210}{315}\)
Answer:
\(\frac{2}{3}\),

Explanation:
Given to reduce \(\frac{210}{315}\) both goes by 105 we get \(\frac{210}{315}\) = \(\frac{2 X 105}{3 X 105}\).

Question 14.
\(\frac{66}{528}\)
Answer:
\(\frac{1}{8}\),

Explanation:
Given to reduce \(\frac{66}{528}\) both goes by 66 we get \(\frac{66}{528}\) = \(\frac{1 X 66}{8 X 66}\) = \(\frac{1}{8}\)

Question 15.
\(\frac{360}{1650}\)
Answer:
\(\frac{12}{55}\),

Explanation:
Given to reduce \(\frac{360}{1,650}\) both goes by 30 we get \(\frac{360}{1,650}\) = \(\frac{12 X 30}{55 X 30}\).

Question 16.
\(\frac{182}{512}\)
Answer:
\(\frac{91}{256}\),

Explanation:
Given to reduce \(\frac{182}{512}\) both goes by 2 as \(\frac{182}{512}\) = \(\frac{91 X 2}{256 X 2}\) = \(\frac{91}{256}\).

McGraw Hill Math Grade 8 Lesson 3.6 Answer Key Reducing Fractions Read More »

McGraw Hill Math Grade 7 Lesson 1.3 Answer Key Estimating Sums and Differences

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 1.3 Estimating Sums and Differences existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 1.3 Estimating Sums and Differences

Estimate

Question 1.
122 + 82
Answer: 204
122
+82
204
The sum of two numbers 122 and 82 is 204.
The estimated sum is 200.

Question 2.
249 + 357
Answer: 606
249
+357
606
The sum of the two numbers 249 and 357 is 606.
The estimated sum is 606.

Question 3.
25 + 78
Answer: 103
25
+78
103
The sum of two numbers 25 and 78 is 103.
The estimated sum is 100.

Question 4.
239 + 555
Answer: 794
239
+555
794
The sum of two numbers 239 and 555 is 794.
The estimated sum is 800.

Question 5.
31 + 131
Answer: 162
131
+31
162
The sum of two numbers 131 and 31 is 162
The estimated sum is 160.

Question 6.
45 + 21
Answer: 66
45
+21
66
The sum of two numbers 45 and 21 is 66.
The estimated sum is 70.

Question 7.
147 + 97
Answer: 244
147
+97
244
The sum of two numbers 147 and 97 is 244.
The estimated sum is 240.

Question 8.
333 – 203
Answer: 130
333
-203
130
The difference between 333 and 203 is 130.
The estimated difference is 130.

Question 9.
2119 – 932
Answer: 1187
2119
-932
1187
The difference between 2119 and 932 is 1187.
The estimated difference is 1200.

Question 10.
575 + 639
Answer: 1214
575
+639
1214
The sum of two numbers 575 and 639 is 1214.
The estimated sum is 1200.

Question 11.
711 – 236
Answer: 475
711
-236
475
The difference of 711 and 236 is 475.
The estimated difference is 500.

Question 12.
23 + 11
Answer: 34
23
+11
34
The sum of two numbers is 23 and 11 is 34
The estimated sum is 30.

Question 13.
57450 – 4997
Answer: 52453
57450
-4997
52453
The difference of 57450 and 4997 is52453.
The estimated difference is 52500.

Question 14.
4723 + 154
Answer: 4877
4723
+154
4877
The sum of two numbers 4723 and 154 is 487.
The estimated sum is 4877.

Question 15.
45 + 557 + 78
Answer: 680
557
+78
+45
680
The sum of the three numbers is 557, 78, 45, and 680.
The estimated sum is 700.

Question 16.
345 + 167
Answer: 512
345
+167
512
The sum of two numbers 345 and 167 is 512.
The estimated sum is 500.

Question 17.
105555 – 15559
Answer: 89996
105555
-15559
89996
The difference of the two numbers 105555 and 15559 is 89996.
The estimated difference is 90,000

Question 18.
3454 + 549 + 777
Answer: 4780
3454
549
+777
4780
The sum of three numbers 3454, 549 and 777 is 4780.
The estimated sum is 5000.

Question 19.
10329 – 5784
Answer: 4545
10329
-5784
4545
The difference of two numbers 10329 and 5784 is 4545.
The estimated difference is 4500.

McGraw Hill Math Grade 7 Lesson 1.3 Answer Key Estimating Sums and Differences Read More »

McGraw Hill Math Grade 7 Lesson 1.1 Answer Key Place Value

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 1.1 Place Value existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 1.1 Place Value

Exercises Solve

Question 1.
In 231,739,465, the underlined digit is in which place? ________
Answer:
In 231,739,465, the underlined digit 9 is in thousand’s place.

Question 2.
In 92.609, the number 6 is in which place? ________
Answer:
In the number 92.609, the value 6 is in tenths place.

Question 3.
In 2,867,403, the underlined digit is in which place? ________
Answer:
In the number 2,867,403 the value 8 is in hundred thousand place.

Question 4.
In 1.609, the number 1 is in which place? ________
Answer:
In the number 1.609, the value 1 is ones place.

Question 5.
The standard form of the number 7,305.92 has the number 3 in which place? ________
Answer:
In the number 7,305.92, the value 3 is in the hundreds place.

Question 6.
Which digit is in the hundredths place in the number 4,007.951? ________
Answer:
Given number is 4,007.951
We have to find the hundredths place from the given number.
The value 5 is in hundredths place.

Question 7.
In 58,601, the underlined digit is in which place? ________
Answer:
In the number 58,601, the value 6 is in the hundreds place.

Question 8.
The standard form of the number 987 has the number 7 in which place? ____
Answer:
In the standard form of the number 987, the number 7 is in tens place.

Question 9.
In 842.793, the number 9 is in which place? _____
Answer:
In the number 842.793 the value 9 is in hundredth place.

Question 10.
In 753,964,933.41, the number 1 is in which place? ________
Answer:
In the number 753,964,933.41, the number 1 is in hundredths place.

Question 11.
Write the number 7,642 in expanded form. _____
Answer:
The expanded form of 7642 is (7 × 1000) + (6 × 100) + (4 × 10) + (2 × 1)

Question 12.
Write the number 4,340,200 in word form. _____
Answer:
The word form of 4,340,200 is Four million three hundred and forty thousand two hundred.

Question 13.
Write the number (3 × 100,000) + (2 × 10,000) + (6 × 1,000) + (5 × 100) + (2 × 10) + (3 × 1) in standard form. __________
Answer:
The standard form of (3 × 100,000) + (2 × 10,000) + (6 × 1,000) + (5 × 100) + (2 × 10) + (3 × 1) is 326523.

Question 14.
Write the number 4 million, thirty-five in standard form. ________
Answer:
The number 4 million, thirty-five in standard form is 4,000,035.

Question 15.
Write the number 435,401 in expanded form. ________
Answer:
435,401 in the expanded form is (4 × 100,000) + (3 × 10,000) + (5 × 1000) + (4 × 100) + (1 × 1)

Question 16.
Write the number (7 × 10,000) + (9 × 1,000) + (3 × 100) + (2 × 1) in word form. ________
Answer:
The number (7 × 10,000) + (9 × 1,000) + (3 × 100) + (2 × 1) in standard form is 79302.
79302 in word form is seventy nine thousand three hundred and two.

Question 17.
Write the number 7,000,213,034 in expanded form. _____
Answer:
7,000,213,034 in the expanded form is (7 × 1,000,000,000) + (2 × 100,000) + (1 × 10,000) + (3 × 1000) + (3 × 10) + (4 × 1)

Question 18.
Write the number (6 × 100,000) + (8 × 10,000) + (2 × 1,000) + (6 × 100) + (6 × 10) + (5 × 1) in standard form. ________
Answer:
The number (6 × 100,000) + (8 × 10,000) + (2 × 1,000) + (6 × 100) + (6 × 10) + (5 × 1) in standard form is 682665.

Question 19.
Write the number three million, four hundred thirty-one thousand, four hundred in standard form. __________
Answer:
The number three million, four hundred thirty-one thousand, four hundred in standard form is 3,431,400

Question 20.
Write the number 6,000,101 in expanded form. ________
Answer:
The number 6,000,101 in expanded form is (6 × 1,000,000) + (1 × 100) + (1 × 1)

McGraw Hill Math Grade 7 Lesson 1.1 Answer Key Place Value Read More »

McGraw Hill Math Grade 7 Lesson 1.2 Answer Key Adding and Subtracting Whole Numbers

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McGraw-Hill Math Grade 7 Answer Key Lesson 1.2 Adding and Subtracting Whole Numbers

Exercises Add or Subtract

Question 1.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 1
Answer: 12
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-1
By adding 7 and 5 we get 12.

Question 2.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 2
Answer: 110
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-2
By adding 33 and 77 is 110.

Question 3.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 3
Answer: 2121
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-3
By adding 21 and 2100 is 2121.

Question 4.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 4
Answer: 88
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-4
By subtracting 100 and 22 is 88.

Question 5.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 5
Answer: 1222
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-5
By adding three given numbers 1100, 111, and 11 we get 1222.

Question 6.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 6
Answer: 99
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-6
By subtracting 155 and 56 we get 99.

Question 7.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 7
Answer: 167
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-7
By adding 122, 35, and 10 we get 167.

Question 8.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 8
Answer: 550
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-8
By adding 45, 450, and 55 we get 550.

Question 9.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 9
Answer: 24
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-9
By subtracting 213 from 237 we get 24.

Question 10.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 10
Answer: 898
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-10
By subtracting 311 and 1209 we get 898.

Question 11.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 11
Answer: 69
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-11
By subtracting 78 from 167 we get 69.

Question 12.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 12
Answer: 692
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-12
By subtracting 2764 from 3456 we get 692.

Question 13.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 13
Answer: 997655
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-13
By subtracting 2345 from 1000000 we get 997655.

Question 14.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 14
Answer: 98
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-14
By subtracting 113 from 211 is 48.

Question 15.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 15
Answer: 5678
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-15
By adding 5151 and 527 we get 5678.

Question 16.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 16
Answer: 9310
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-16
By adding 8932 and 378 is 9310.

Question 17.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 17
Answer: 382
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-17
By adding 33, 333, 3, and 13 we get 382.

Question 18.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 18
Answer: 955
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-18
By adding the three given numbers 595, 25 and 335 we get 955.

Question 19.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 19
Answer: 917
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-19
By subtracting 444 from 1361 we get 917.

Question 20.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 20
Answer: 3649
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-20
By adding three numbers 415, 3001 and 233 we get 3649.

Question 21.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 21
Answer: 1109
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-21
By subtracting 3333 from 4442 we get 1109.

Question 22.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 22
Answer: 421
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-22
By adding 34, 344 and 43 we get 421.

Question 23.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 23
Answer: 1002
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-23
By subtracting 999 from 2001 we get 1002.

Question 24.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 24
Answer: 610
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-24
By adding 44, 555 and 11 we get 610.

Question 25.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 25
Answer: 858
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-25
By adding 48, 49 and 761 we get 858.

Question 26.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 26
Answer: 82
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-26
By subtracting 1729 from 1811 we get 82.

Question 27.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 27
Answer: 172
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-27
By adding 10, 11, 12, 13, 15 and 111 we get 172.

Question 28.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 28
Answer: 180
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-28
By subtracting 49 from 229 we get 180.

Question 29.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 29
Answer: 5098
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-29
By subtracting 790 from 5888 we get 5098.

Question 30.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 30
Answer: 1889
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-30
By adding 544, 322, and 1023 we get 1889.

Question 31.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 31
Answer: 1112
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-31
By subtracting 8888 from 10000 we get 1112.

Question 32.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 32
Answer: 1332
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-32
By adding 1010, 11 and 311 we get 1332.

Question 33.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 33
Answer: 589
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-33
By adding 212, 355 and 22 we get 589.

Question 34.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 34
Answer: 13
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-34
By subtracting 988 from 1001 we get 13.

Question 35.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 35
Answer: 1514
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-35
By adding 5, 1055 and 454 we get 1514.

Question 36.
McGraw Hill Math Grade 7 Chapter 1 Lesson 1.2 Answer Key Place Value 36
Answer: 2876
McGraw-Hill-Math-Grade-7-Chapter-1-Lesson-1.2-Answer-Key-Place-Value-36
By subtracting 4567 from 7443 we get 5876.

McGraw Hill Math Grade 7 Lesson 1.2 Answer Key Adding and Subtracting Whole Numbers Read More »

McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 24.4 Circle Graphs will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 24.4 Circle Graphs

Exercises

INTERPRET

Question 1.
In the circle graph, which is the smallest department in terms of new hires for the year?
McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs 1
Answer: From the given circle graph we observe that Marketing is the smallest department in terms of new hires for the year.

Question 2.
The circle graphs display how people in a company communicated in 2004 and 2008. What information can you gather from the two graphs?
McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs 2
Answer:
From the two graphs, we observed that Electronic has increased from 5% to 37% from 2004 to 2008.

Question 3.
Is the total of items A, E, and B more than C and D?
McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs 3
Answer:
A = 33%
B = 25%
C = 18%
D = 15%
E = 9%
A + E + B = 33 + 9 + 25 =67%
C + D = 18 + 15 = 33%
So, yes the total of items A, E, and B is more than C and D.

Question 4.
Do the Americas represent more than 50% of the total?
McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs 4
Answer:
No Americans do not represent more than 50% of the total.

Question 5.
According to the circle graph, are the combined sales for Atlanta and Sydney more than sales for Paris?
McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs 5
Answer:
Sales for Atlanta = $66,687
Sales for Paris = $85,885
Sales for Sydney = $53,114
66687 + 53,114 = $119801
So, the combined sales for Atlanta and Sydney are more than the sales for Paris.

Question 6.
In the circle graph, which age group makes up the majority of students who attend Basic Skills Summer School?
McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs 6
Answer:
Between 15 and 18 years = 23%
Between 19 to 24 years = 12%
Over 25 years = 65%
Over 25 years 65% majority of students who attend Basic Skills Summer School.

McGraw Hill Math Grade 6 Lesson 24.4 Answer Key Circle Graphs Read More »

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