Go Math Answer Key

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 6.7 Subtracting Mixed Numbers with Unlike Denominators will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 6.7 Subtracting Mixed Numbers with Unlike Denominators

Exercises Subtract

Question 1.
2\(\frac{5}{8}\) – 1\(\frac{1}{4}\)
Answer:
2\(\frac{5}{8}\) – 1\(\frac{1}{4}\) = 1\(\frac{3}{8}\)

Explanation:
2\(\frac{5}{8}\) – 1\(\frac{1}{4}\)
= {[(2 × 8) + 5] ÷ 8} – {[(1 × 4) + 1] ÷ 4}
= [(16 + 5) ÷ 8] – [(4 + 1) ÷ 4]
= (21 ÷ 8) – (5 ÷ 4)

Question 2.
4\(\frac{6}{7}\) – 2\(\frac{3}{4}\)
Answer:
4\(\frac{6}{7}\) – 2\(\frac{3}{4}\) = 2\(\frac{3}{28}\)

Explanation:
4\(\frac{6}{7}\) – 2\(\frac{3}{4}\)
={[(4 × 7) + 6] ÷ 7} – {[(2 × 4) + 3] ÷ 4}
= [(28 + 6) ÷ 7] – [(8 + 3) ÷ 4]
= (34 ÷ 7) – (11 ÷ 4)

Question 3.
5\(\frac{4}{9}\) – 2\(\frac{1}{3}\)
Answer:
5\(\frac{4}{9}\) – 2\(\frac{1}{3}\) = 3\(\frac{1}{9}\)

Explanation:
5\(\frac{4}{9}\) – 2\(\frac{1}{3}\)
= {[(5 × 9) + 4] ÷ 9} – {[(2 × 3) + 1] ÷ 3}
= [(45 + 4) ÷ 9] – [(6 + 1) ÷ 3]
= (49 ÷ 9) – (7 ÷ 3)

Question 4.
7\(\frac{7}{8}\) – 5\(\frac{1}{5}\)
Answer:
7\(\frac{7}{8}\) – 5\(\frac{1}{5}\) = 2\(\frac{27}{40}\)

Explanation:
7\(\frac{7}{8}\) – 5\(\frac{1}{5}\)
= {[(7 × 8) + 7] ÷ 8} – {[(5 × 5) + 1] ÷ 5}
= [(56 + 7) ÷ 8] – [(25 + 1) ÷ 5]
= (63 ÷ 8) – (26 ÷ 5)

Question 5.
2\(\frac{1}{10}\) – 1\(\frac{1}{11}\)
Answer:
2\(\frac{1}{10}\) – 1\(\frac{1}{11}\) = 1\(\frac{1}{110}\)

Explanation:
2\(\frac{1}{10}\) – 1\(\frac{1}{11}\)
= {[(2 × 10) + 1] ÷ 10} – {[(1 × 11) + 1] ÷ 11}
= [(20 + 1) ÷ 10] – [(11 + 1) ÷ 11]
= (21 ÷ 10) – (12 ÷ 11)

Question 6.
5\(\frac{3}{4}\) – 4\(\frac{2}{3}\)
Answer:
5\(\frac{3}{4}\) – 4\(\frac{2}{3}\) = -2\(\frac{1}{4}\)

Explanation:
5\(\frac{3}{4}\) – 4\(\frac{2}{3}\)
= {[(5 × 4) + 3] ÷ 4} – {[(4 × 3) + 2] ÷ 3}
= [(20 + 3) ÷ 4] – [(12 + 2) ÷ 3]
= (23 ÷ 4) – (24 ÷ 3)

Question 7.
7\(\frac{7}{9}\) – 2\(\frac{1}{4}\)
Answer:
7\(\frac{7}{9}\) – 2\(\frac{1}{4}\) = 5\(\frac{19}{36}\)

Explanation:
7\(\frac{7}{9}\) – 2\(\frac{1}{4}\)
= {[(7 × 9) + 7] ÷ 9} – {[(2 × 4) + 1] ÷ 4}
= [(63 + 7) ÷ 9] – [(8 + 1) ÷ 4]
= (70 ÷ 9) – (9 ÷ 4)

Question 8.
5\(\frac{3}{7}\) – 2\(\frac{1}{6}\)
Answer:
5\(\frac{3}{7}\) – 2\(\frac{1}{6}\) = 3\(\frac{11}{42}\)

Explanation:
5\(\frac{3}{7}\) – 2\(\frac{1}{6}\)
= {[(5 × 7) + 3] ÷ 7} – {[(2 × 6) + 1] ÷ 6}
= [(35 + 3) ÷ 7] – [(12 + 1) ÷ 6]
= (38 ÷ 7) – (13 ÷ 6)

Question 9.

Answer:
5\(\frac{1}{4}\) – 2\(\frac{2}{13}\) = 3\(\frac{5}{52}\)

Explanation:
5\(\frac{1}{4}\) – 2\(\frac{2}{13}\)
= {[(5 × 4) + 1] ÷ 4} – {[(2 × 13) + 2] ÷ 13}
= [(20 + 1) ÷ 4] – [(26 + 2) ÷ 13]
= (21 ÷ 4) – (28 ÷ 13)

Question 10.

Answer:
19\(\frac{6}{7}\) – 3\(\frac{3}{10}\) = 16\(\frac{39}{70}\)

Explanation:
19\(\frac{6}{7}\) – 3\(\frac{3}{10}\)
= {[(19 × 7) + 6] ÷ 7} – {[(3 × 10) + 3] ÷ 10}
= [(133 + 6) ÷ 7] – [(30 + 3) ÷ 10]
= (139 ÷ 7) – (33 ÷ 10)

Question 11.

Answer:
4\(\frac{2}{3}\) – 1\(\frac{1}{8}\) = 3\(\frac{13}{24}\)

Explanation:
4\(\frac{2}{3}\) – 1\(\frac{1}{8}\)
= {[(4 × 3) + 2] ÷ 3} – {[(1 × 8) + 1] ÷ 8}
= [(12 + 2) ÷ 3] – [(8 + 1) ÷ 8]
= (14 ÷ 3) – (9 ÷ 8)

Question 12.

Answer:
10\(\frac{7}{10}\) – 7\(\frac{5}{9}\) = 3\(\frac{13}{90}\)

Explanation:
10\(\frac{7}{10}\) – 7\(\frac{5}{9}\)
= {[(10 × 10) + 7] ÷ 10} – {[(7 × 9) + 5] ÷ 9}
= [(100 + 7) ÷ 10] – [(63 + 5) ÷ 9]
= (107 ÷ 10) – (68 ÷ 9)

Question 13.
Mario is selling lemonade to raise money for his school. He started with 8\(\frac{1}{2}\) gallons of lemonade and has, so far, sold 3\(\frac{7}{8}\) gallons. How many gallons does he have left to sell?
Answer:
Number of gallons of lemonade he left to sell = 4\(\frac{5}{8}\)

Explanation:
Number of gallons of lemonade he started with = 8\(\frac{1}{2}\)
Number of gallons of lemonade he sold = 3\(\frac{7}{8}\)
Number of gallons of lemonade he left to sell = Number of gallons of lemonade he started with – Number of gallons of lemonade he sold
= 8\(\frac{1}{2}\) – 3\(\frac{7}{8}\)
= {[(8 × 2) + 1] ÷ 2} – {[(3 × 8) + 7] ÷ 8}
= [(16 + 1) ÷ 2] – [(24 + 7) ÷ 8]
= (17 ÷ 2) – (31 ÷ 8)
=

Question 14.
Bethany is making strawberry shortcake for her entire family. The recipe calls for 1\(\frac{3}{5}\) pounds of strawberries. If Bethany purchases 1\(\frac{7}{8}\) pounds, but drops \(\frac{1}{4}\) pound of strawberries on her way home, will she have enough to complete the recipe?
Answer:
Yes, she has enough to complete the recipe.

Explanation:
Number of pounds of recipe calls of strawberries = 1\(\frac{3}{5}\)
Number of pounds Bethany purchases = 1\(\frac{7}{8}\)
Number of pounds of strawberries Bethany drops on her way home = \(\frac{1}{4}\)
Number of pounds of strawberries Bethany is left = Number of pounds Bethany purchases – Number of pounds of strawberries Bethany drops on her way home
= 1\(\frac{7}{8}\) – \(\frac{1}{4}\)
= {[(1 × 8) + 7] ÷ 8} – \(\frac{1}{4}\)
= [(8 + 7) ÷ 8] – \(\frac{1}{4}\)
= \(\frac{15}{8}\) – \(\frac{1}{4}\)

Number of pounds of recipe calls of strawberries = 1\(\frac{3}{5}\)
Number of pounds of strawberries Bethany is left = 1\(\frac{5}{8}\)
Equating:
=> 1\(\frac{3}{5}\) = 1\(\frac{5}{8}\)
=> {[(1 × 5) + 3] ÷ 5} = {[(1 × 8) + 5] ÷ 8}
=> [(5 + 3) ÷ 5] = [(8 + 5) ÷ 8]
=> (8 ÷ 5) = (13 ÷ 8)
LCD of 5 and 8: 40.
=> [(8 × 8) ÷ 40 = (13 × 5) ÷ 40
=> (64 ÷ 40) = (65 ÷ 40)
=> 1.6 = 1.625.
=> Number of pounds of strawberries Bethany is left with him are more than the Number of pounds of recipe calls of strawberries.

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 6.8 Estimating Sums and Differences of Fractions and Mixed Numbers will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 6.8 Estimating Sums and Differences of Fractions and Mixed Numbers

Exercises Estimate

Question 1.
\(\frac{3}{4}\) + \(\frac{5}{6}\)
Answer:
\(\frac{3}{4}\) + \(\frac{5}{6}\) = 1 \(\frac{7}{12}\)

Explanation:
\(\frac{3}{4}\) + \(\frac{5}{6}\)

Question 2.
\(\frac{4}{5}\) + \(\frac{1}{7}\)
Answer:
\(\frac{4}{5}\) + \(\frac{1}{7}\) = \(\frac{33}{35}\)

Explanation:
\(\frac{4}{5}\) + \(\frac{1}{7}\)

Question 3.
\(\frac{1}{3}\) + \(\frac{4}{7}\)
Answer:
\(\frac{1}{3}\) + \(\frac{4}{7}\) = \(\frac{19}{21}\)

Explanation:
\(\frac{1}{3}\) + \(\frac{4}{7}\)

Question 4.
\(\frac{5}{6}\) + \(\frac{4}{8}\)
Answer:
\(\frac{5}{6}\) + \(\frac{4}{8}\) = 1\(\frac{1}{3}\)

Explanation:
\(\frac{5}{6}\) + \(\frac{4}{8}\)

Question 5.
1\(\frac{1}{5}\) + 2\(\frac{5}{6}\)
Answer:
1\(\frac{1}{5}\) + 2\(\frac{5}{6}\) = 4\(\frac{1}{30}\)

Explanation:
1\(\frac{1}{5}\) + 2\(\frac{5}{6}\)
= {[(1 × 5) + 1] ÷ 5} + {[(2 × 6) + 5] ÷ 6}
= [(5 + 1) ÷ 5] + [(12 + 5) ÷ 6]
= (6 ÷ 5) + (17 ÷ 6)

Question 6.
7\(\frac{4}{5}\) + 4\(\frac{1}{3}\)
Answer:
7\(\frac{4}{5}\) + 4\(\frac{1}{3}\) = 12\(\frac{2}{15\)

Explanation:
7\(\frac{4}{5}\) + 4\(\frac{1}{3}\)
= {[(7 × 5) + 4] ÷ 5} + {[(4 × 3) + 1] ÷ 3}
= [(35 + 4) ÷ 5] + [(12 + 1) ÷ 3]
= (39 ÷ 5) + (13 ÷ 3)

Question 7.
5\(\frac{1}{5}\) – 2\(\frac{3}{5}\)
Answer:
5\(\frac{1}{5}\) – 2\(\frac{3}{5}\) = 2\(\frac{3}{5}\)

Explanation:
5\(\frac{1}{5}\) – 2\(\frac{3}{5}\)
= {[(5 × 5) + 1] ÷ 5} – {[(2 × 5) + 3] ÷ 5}
= [(25 + 1) ÷ 5] – [(10 + 3) ÷ 5]
= (26 ÷ 5) – (13 ÷ 5)

Question 8.
7\(\frac{1}{2}\) – \(\frac{3}{4}\)
Answer:
7\(\frac{1}{2}\) – \(\frac{3}{4}\) = 6\(\frac{3}{4}\)

Explanation:
7\(\frac{1}{2}\) – \(\frac{3}{4}\)
{[(7 × 2) + 1] ÷ 2} – \(\frac{3}{4}\)
= [(14 + 1) ÷ 2] – \(\frac{3}{4}\)
= (15 ÷ 2) – (3 ÷ 4)

Question 9.
12\(\frac{1}{8}\) – \(\frac{2}{3}\)
Answer:
12\(\frac{1}{8}\) – \(\frac{2}{3}\) = 11\(\frac{11}{24}\)

Explanation:
12\(\frac{1}{8}\) – \(\frac{2}{3}\)
= {[(12 × 8) + 1] ÷ 8} – \(\frac{2}{3}\)
= [(96 + 1) ÷ 8] – \(\frac{2}{3}\)
= (97 ÷ 8) – (2 ÷ 3)

Question 10.
4\(\frac{4}{7}\) + 4\(\frac{4}{7}\)
Answer:
4\(\frac{4}{7}\) + 4\(\frac{4}{7}\) = 9\(\frac{1}{7}\)

Explanation:
4\(\frac{4}{7}\) + 4\(\frac{4}{7}\)
{[(4 × 7) + 4] ÷ 7} + {[(4 × 7) + 4] ÷ 7}
= [(28 + 4) ÷ 7] + [(28 + 4) ÷ 7]
= (32 ÷ 7) + (32 ÷ 7)

Question 11.
13\(\frac{5}{8}\) – 12\(\frac{1}{4}\)
Answer:
13\(\frac{5}{8}\) – 12\(\frac{1}{4}\) = 1\(\frac{3}{8}\)

Explanation:
13\(\frac{5}{8}\) – 12\(\frac{1}{4}\)
{[(13 × 8) + 5] ÷ 8} – {[(12 × 4) + 1] ÷ 4}
= [(104 + 5) ÷ 8] – [(48 + 1) ÷ 4]
= (109 ÷ 8) – (49 ÷ 4)

Question 12.
17\(\frac{1}{7}\) – 13\(\frac{3}{4}\)
Answer:
17\(\frac{1}{7}\) – 13\(\frac{3}{4}\) = 3\(\frac{11}{28}\)

Explanation:
17\(\frac{1}{7}\) – 13\(\frac{3}{4}\)
{[(17 × 7) + 1] ÷ 7} – {[(13 × 4) + 3] ÷ 4}
= [(119 + 1) ÷ 7] – [(52 + 3) ÷ 4]
= (120 ÷ 7) – (55 ÷ 4)

Question 13.
Leslie had 25\(\frac{4}{9}\) ounces of cat food left in a bag. If she feeds each of her two cats 1\(\frac{7}{8}\) ounces of food, about how much cat food will she have left?
Answer:
Number of ounces of cat food left with her = 21\(\frac{25}{36}\)

Explanation:
Number of ounces of cat food Leslie had left in a bag = 25\(\frac{4}{9}\)
Number of ounces of cat food she feeds each of her two cats = 1\(\frac{7}{8}\)
Number of ounces of cat food left with her = Number of ounces of cat food Leslie had left in a bag – Number of ounces of cat food she feeds each of her two cats
= 25\(\frac{4}{9}\)  – 2(1\(\frac{7}{8}\))
= {[(25 × 9 ) + 4] ÷ 9} – 2{[(1 × 8) + 7] ÷ 8}
= [(225 + 4) ÷ 9] – 2[(8 + 7) ÷ 8]
= (229 ÷ 9) – 2(15 ÷ 8)
= (229 ÷ 9) – (15 ÷ 4)

Question 14.
James was gathering wood for the fireplace. He already had 1\(\frac{4}{5}\) cords of wood and he gathered another 2\(\frac{1}{3}\) cords today. About how many cords of wood does James have now?
Answer:
Number of cords of wood he has now = 4\(\frac{2}{15}\)

Explanation:
Number of cords of wood he already had = 1\(\frac{4}{5}\)
Number of cords of wood he again gathered today = 2\(\frac{1}{3}\)
Number of cords of wood he has now = Number of cords of wood he already had + Number of cords of wood he again gathered today
= 1\(\frac{4}{5}\) + 2\(\frac{1}{3}\)
= {[(1 × 5) + 4] ÷ 5} + {[(2 × 3) + 1] ÷ 3}
= [(5 + 4) ÷ 5] + [(6 + 1) ÷ 3]
= (9 ÷ 5) + (7 ÷ 3)

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 2 Lesson 5 Addition Facts from 0 to 20 as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 2 Lesson 5 Addition Facts from 0 to 20

Add.

Use the number line to find how many in all. Write the sum.

Question 1.

Answer:
Add 3 with 3 then you get 6.

Question 2.

9 + 2 = ____
Answer:
Add 9 with 2 then you get 11.
9 + 2 = 11

Question 3.
5 + 10 = ____
Answer:
Add 5 with 10 then you get 15.
5 + 10 = 15

Question 4.
1 + 1 = ___
Answer:
Add 1 with 1 then you get 2.
1 + 1 = 2

Question 5.
13 + 7 = ____
Answer:
Add 13 with 7 then you get 20.
13 + 7 = 20

Question 6.
14 + 0 = ____
Answer:
Add 14 with 0 then you get 14,
14 + 0 = 14

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 2 Test as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Chapter 2 Test Answer Key

Add to find how many in all. Write the sum. Use the number line to help.

Question 1.

2 + 2 = ____ dogs
Answer:
Add 2 dogs with 2 dogs then you get 4 dogs.
2 + 2 = 4

Question 2.

2 + 1 = ___ cats
Answer:
Add 2 cats with 1 cat then you get 3 cats.
2 + 1 = 3

Question 3.

3 + 2 = ___ cows
Answer:
Add 3 cows with 2 cows then you get 5 cows.
3 + 2 = 5

Question 4.

7 + 4 = ___ horses
Answer:
Add 7 horses with 4 horses then you get 11 horses.
7 + 4 = 11

Question 5.

4 + 4 = ____ pigs
Answer:
Add 4 pigs with 4 pigs then you get 8 pigs.
4 + 4 = 8

Question 6.

2 + 0 = ___ rabbits
Answer:
Add 2 rabbits with 0 rabbits then you get 2 rabbits.
2 + 0 = 2

Question 7.

4 + 1 = ___ sheep
Answer:
Add 4 sheep’s with 1 sheep then you get 5 sheep’s.
4 + 1 = 5

Question 8.

3 + 9 = ___ fish
Answer:
Add 3 fishes with 9 fishes then you get 12 fishes.
3 + 9 = 12

Add. Write the sum.

Question 9.
5 + 5 = ___
Answer:
Add 5 with 5 then you get 10.
5 + 5 = 10.

Question 10.
2 + 7 = ___
Answer:
Add 2 with 7 then you get 9.
2 + 7 = 9

Question 11.
1 + 1 = ___
Answer:
Add 1 with 1then you get 2.
1 + 1 = 2

Question 12.
6 + 3 = ____
Answer:
Add 6 with 3 then you get 9.
6 + 3 = 9.

Question 13.
1 + 11 = ___
Answer:
Add 1 with 11 then you get 12.
1 + 11 = 12.

Question 14.
3 + 5 = ___
Answer:
Add 3 with 5 then you 8.
3 + 5 = 8

Question 15.
14 + 5 = ___
Answer:
Add 14 with 5 then you get 19.
14 + 5 = 19

Question 16.
8 + 5 = ___
Answer:
Add 8 with 5 then you get 13.
8 + 5 = 13

Question 17.
9 + 8 = ___
Answer:
Add 9 with 8 then you get 17.
9 + 8 = 17

Question 18.
0 + 14 = ___
Answer:
Add 0 with 14 then you get 14.
0 + 14 = 14

Solve. Write the sum. Use the number line to help.

Question 19.
There are 5 pups playing. There are 2 pups sleeping. How many pups are there?
5 + 2 = ___ pups
Answer:
Given that,
The total number of pups playing = 5
The total number of pups sleeping = 2
Therefore the total number of pups are  5 + 2 = 7.

Question 20.
Ed has 7 pens. His mom has 5 pens. How many do they have in all?
7 + 5 = ___ pens
Answer:
Given that,
The total number of pens near Ed = 7
The total number of pens near his mother = 5
Therefore the total number of pens in all is 7 + 5 = 12.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 3 Lesson 3 Subtraction Facts from 0 to 12 as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 3 Lesson 3 Subtraction Facts from 0 to 12

Subtract

Write the difference. Use the number line to help.

Question 1.
6 – 5 = 1
Answer:
Subtract 5 from 6 then you get 1.
6 – 5 = 1

Question 2.
10 – 2 = ___
Answer:
Subtract 2 from 10 then you get 8.
10 – 2 = 8

Question 3.
11 – 11 = ___
Answer:
Subtract 11 from 11 then you get 0
11 – 11 = 0

Question 4.
7 – 4 = ____
Answer:
Subtract 4 from 7 then you get 3.
7 – 4 = 3

Question 5.
7 – 1 = ___
Answer:
Subtract 1 from 7 then you get 6.
7 – 1 = 6

Question 6.
12 – 7 = ___
Answer:
Subtract 7 from 12 then you get 5.
12 – 7 = 5

Question 7.
9 – 7 = ___
Answer:
Subtract 7 from 9 then you get 2.
9 – 7 = 2

Question 8.
11 – 10 = ___
Answer:
Subtract 10 from 11 then you get 1.
11 – 10 = 1

Question 9.
12 – 12 = ___
Answer:
Subtract 12 from 12 then you get 0.
12 – 12 = 0

Question 10.
8 – 4 = ___
Answer:
Subtract 4 from 8 then you get 4.
8 – 4 = 4

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 3 Lesson 4 Subtraction Facts Through 20 as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 3 Lesson 4 Subtraction Facts Through 20

Subtract

Write the difference. Use objects to help.

Question 1.
15 – 5 = 10
Answer:
Subtract 5 from 15 then you get 10.
15 – 5 = 10.

Question 2.
12 – 3 = ___
Answer:
Subtract 3 from 12 then you get 9.
12 – 3 = 9

Question 3.
18 – 12 = ___
Answer:
Subtract 12 from 18 then you get 6
18 – 12 = 6

Question 4.
14 – 13 = ___
Answer:
Subtract 13 from 14 then you get 1.
14 – 13 = 1

Question 5.
9 – 5 = ___
Answer:
Subtract 5 from 9 then you get 4.
9 – 5 = 4

Question 6.
6 – 4 = ___
Answer:
Subtract 4 from 6 then you get 2.
6 – 4 = 2

Question 7.
17 – 6 = ___
Answer:
Subtract 6 from 17 then you get 11.
17 – 6 = 11

Question 8.
20 – 4 = ___
Answer:
Subtract 4 from 20 then you get 16.
20 – 4 = 16

Question 9.
19 – 7 = ___
Answer:
Subtract 7 from 19 then you get 12.
19 – 7 = 12

Question 10.
8 – 1 = ___
Answer:
Subtract 1 from 8 then you get 7.
8 – 1 = 7

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 3 Lesson 5 Subtraction Facts from 0 to 20 as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 3 Lesson 5 Subtraction Facts from 0 to 20

Subtract

Write the difference. Use objects to help.

Question 1.
7 – 4 = 3
Answer:

Subtract 4 circles from 7 circles then you get 3 circles.
7 – 4 = 3

Question 2.
13 – 3 = ___
Answer:

Subtract 3 circles from 13 circles then you get 10 circles.
13 – 3 = 10.

Question 3.
17 – 4 = ___
Answer:

Subtract 4 circles from 17 circles then you get 13 circles.
17 – 4 = 13

Question 4.
11 – 4 = ___
Answer:

Subtract 4 circles from 11 circles then you get 7 circles.
11 – 4 = 7

Question 5.
4 – 2 = ___
Answer:

Subtract 2 circles from 4 circles then you get 2 circles.
4 – 2 = 2

Question 6.
9 – 0 = ___
Answer:

Subtract 0 circles from 9 circles then you get 9 circles.
9 – 0 = 9

Question 7.
18 – 6 = ___
Answer:

Subtract 6 circles from 18 circles then you get 12 circles.
18 – 6 = 12

Question 8.
20 – 15 = ___
Answer:

Subtract 15 circles from 20 circles then you get 5 circles.
20 – 15 = 5.

Question 9.
3 – 2 = ___
Answer:

Subtract 2 circles from 3 circles then you get 1 circle.
3 – 2 = 1

Question 10.
19 – 8 = ___
Answer:

Subtract 8 circles from 19 circles then you get 11 circles.
19 – 8 = 11

Question 11.
16 – 16 = ___
Answer:

Subtract 16 circles from 16 circles then you get 0 circles.
16 – 16 = 0

Question 12.
14 – 6 = ___
Answer:

Subtract 6 circles from 14 circles then you get 8 circles.
14 – 6 = 8

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 3 Lesson 9 Dividing by 1-Digit Whole Numbers are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 3 Lesson 9 Dividing by 1-Digit Whole Numbers

Divide.

Question 1.
39 ÷ 3 3
Answer:
39 ÷ 3 = 13.

Explanation:
By dividing 39 ÷ 3 we will get 13.

Question 2.
60 ÷ 5 ___
Answer:
60 ÷ 5 = 12.

Explanation:
By dividing 60 ÷ 5 we will get 12.

Question 3.
96 ÷ 4 ____
Answer:
96 ÷ 4 = 24.

Explanation:
By dividing 96 ÷ 4 we will get 24.

Question 4.
27 ÷ 9 _______
Answer:
27 ÷ 9 = 3.

Explanation:
By dividing 27 ÷ 9 we will get 3.

Question 5.
69 ÷ 3 _______
Answer:
69 ÷ 3 = 23.

Explanation:
By dividing 69 ÷ 3 we will get 23.

Question 6.
84 ÷ 6 ____
Answer:
84 ÷ 6 = 14.

Explanation:
By dividing 84 ÷ 6 we will get 14.

Question 7.
18 ÷ 6 ______
Answer:
18 ÷ 6 = 3.

Explanation:
By dividing 18 ÷ 6 we will get 3.

Question 8.
18 ÷ 3 ____
Answer:
18 ÷ 3 = 6.

Explanation:
By dividing 18 ÷ 3 we will get 6.

Question 9.
57 ÷ 3 ____
Answer:
57 ÷ 3 = 19.

Explanation:
By dividing 57 ÷ 3 we will get 19.

Question 10.
42 ÷ 7 ____
Answer:
42 ÷ 7 = 6.

Explanation:
By dividing 42 ÷ 7 we will get 6.

Question 11.
56 ÷ 4 _____
Answer:
56 ÷ 4 = 14.

Explanation:
By dividing 56 ÷ 4 we will get 14.

Question 12.
56 ÷ 8 ____
Answer:
56 ÷ 8 = 7.

Explanation:
By dividing 56 ÷ 8 we will get 7.

Question 13.
Explain the strategy you used to find the answer to exercise 12.
Answer:
Here, the strategy used is division for exercise 12.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 4 Lesson 3 Multiplying Decimals by Powers of Ten are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 4 Lesson 3 Multiplying Decimals by Powers of Ten

Solve.

Estimate. Then multiply.

Question 1.
17.76 × 10² =
Estimate: <1,800
Product: _______________________________
Answer:
Estimate: 1,800
Product: 1,776.

Explanation:
Given the expression is 17.76 × 10² which is
= 17.76 × 10 × 10
= 1,776.

Question 2.
10.24 × 10³ = ____
Estimate: ________
Product: _______________________________
Answer:
Estimate: 10,000.
Product: 10,240.

Explanation:
Given the expression is 10.24 × 10³ which is
= 10.24 × 10 × 10 × 10
= 10.24 × 1000
= 10,240.

Question 3.
1.10 × 10⁴ = ____
Estimate: ________
Product: _______________________________
Answer:
Estimate: 11,000.
Product: 11,000.

Explanation:
Given the expression is 1.10 × 10⁴ which is
= 1.10 × 10 × 10 × 10 × 10
= 1.10 × 10000
= 11,000.

Question 4.
9.9 × 10⁵ = ____
Estimate: ________
Product: _______________________________
Answer:
Estimate: 1,000,000.
Product: 990,000.

Explanation:
Given the expression is 9.9 × 10⁵ which is
= 9.9 × 10 × 10 × 10 × 10 × 10
= 9.9 × 1,00,000
= 990,000.

Choose from the following terms to complete the sentences below:

product right exponent

Question 5.
The ________________ above the 10 tells how many times you multiply by 10. The _____ becomes ten times greater every time the exponent increases by 1. Every time you multiply by 10, the decimal point moves one place to the _____
Answer:
The exponent above the 10 tells how many times you multiply by 10. The product becomes ten times greater every time the exponent increases by 1. Every time you multiply by 10, the decimal point moves one place to the right.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 3 Test are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Chapter 3 Test Answer Key

Simplify. Find the product. Name the property.

Question 1.
12 × 37 = (____ × 37) + (2 × ____) = ____
_______ property
Answer:
12 × 37 = (10 × 37) + (2 × 37)
= 444.

Explanation:
Given the expression is 12 × 37 by using distributive property we will get
= (10 × 37) + (2 × 37)
= 370 + 74
= 444.

Question 2.
(51 × 19) + (49 × 19) = (___ + 49) × 19 = ____ × 19 = _____
____ Property
Answer:
(51 × 19) + (49 × 19) = (51+49) × 19
= 1900.

Explanation:
Given the expression is (51 × 19) + (49 × 19), so by associative property we will get
= (51+49) × 19
= 100 × 19
= 1900.

Find the product. List the related multiplication and division facts.

Question 3.
5 × 8 = ______ _____ _____ ______
Answer:
5 × 8 = 40, 45, 50, 55, 60.

Explanation:
Given the expression is 5 × 8 and the product is 40. The list of related multiples is 40, 45, 50, 55, and 60.

Question 4.
7 × 9 = ______ _____ _____ ______
Answer:
7 × 9 = 63, 70, 77, 84, and 91.

Explanation:
Given the expression is 7 × 9 and the product is 63. The list of related multiples is 63, 70, 77, 84, and 91.

Multiply.

Question 5.

Answer:
114 × 4 = 456.

Explanation:
The product of 114 and 4 is 114 × 4 which is 456.

Question 6.

Answer:
90 × 80 = 7,200.

Explanation:
The product of 90 and 80 is 90 × 80 which is 7,200.

Question 7.

Answer:
44 × 11 = 484.

Explanation:
The product of 44 × 11 which is 484.

Question 8.

Answer:
402 × 13 = 5,226.

Explanation:
The product of 402 × 13 which is 5,226.

Question 9.
10.6 × 10² _____
Answer:
10.6 × 10² = 1,060.

Explanation:
The product of 10.6 × 10² which is
= 10.6 × 10 × 10
= 1,060.

Question 10.
525 × 10² _____
Answer:
525 × 10² = 52,500.

Explanation:
The product of 525 × 10² which is
= 525 × 10 × 10
= 52,500.

Question 11.
33 × 10³ _____
Answer:
33 × 10³ = 33,000.

Explanation:
The product of 33 × 10³ which is
= 33 × 10 × 10 × 10
= 33,000.

Divide.

Question 12.
101 ÷ 10¹ _____
Answer:
101 ÷ 10¹ = 10.1

Explanation:
Given that 101 ÷ 10¹ which is
= 101 ÷ 10¹
= 10.1

Question 13.
747 ÷ 10² _____
Answer:
747 ÷ 10² = 7.47.

Explanation:
Given that 747 ÷ 10² which is
= 747 ÷ 10 × 10
= 747 ÷ 100
= 7.47.

Question 14.
506 ÷ 10³ _____
Answer:.
506 ÷ 10³ = 0.506

Explanation:
Given that 506 ÷ 10³ which is
= 506 ÷ 10 × 10 × 10
= 506 ÷ 1000
= 0.506

Solve the following word problems.

Question 15.
Aaron and Kate cut a rope into 8-foot lengths. How many lengths can they get from 78 feet of rope?
Answer:
The length of the rope is 684 feet.

Explanation:
Given that Aaron and Kate cut a rope into 8-foot lengths. So the length that can get from 78 feet of rope is 78 × 8 = 684 foot length.

Question 16.
A camp prepares 67 life jackets for rafts that will travel down the river. Each raft must have 9 life
jackets. How many rafts can they equip?__________ __________________________________________________
How many extra life jackets will be available? ______________________________________________
Answer:
The number of rafts the can equip is 603.

Explanation:
Given that a camp prepares 67 life jackets for rafts that will travel down the river and each raft must have 9 life jackets. So the number of rafts the can equip is 67 × 9 which is 603.

Question 17.
An expedition to study tropical plants needs to bring 1,525 pounds of food, tents, and other
supplies for a 15-day trip. Ten mules will carry all the supplies. How much will each mule carry if
each carries about the same weight? _____________________________________________________
Answer:
Each mule carries 152.5 pounds.

Explanation:
Given that an expedition to study tropical plants needs to bring 1,525 pounds of food, tents, and other supplies for a 15-day trip. So each mule carries 1525 ÷ 10 which is 152.5 pounds.

Question 18.
Researchers need to ship 4,500 pounds of dinosaur fossils back to the research lab. The fossils will be packed in boxes that hold 100 pounds. It costs $75.00 to ship each container How much will it cost to ship the fossils?
Answer:
The cost to ship the fossils is $3,375.

Explanation:
Given that researchers need to ship 4,500 pounds of dinosaur fossils back to the research lab and the fossils will be packed in boxes that hold 100 pounds the cost will be $75.00. As there are 4,500÷100 which is 45 containers, so the cost to ship the fossils is 45×75 which is $3,375.

Question 19.
Ronny took dozens of photographs during his trip to Glacier National Park. He has 4 times as many moose photos as brown bear photos. The number of eagle photos is divisible by 6. Ronny has 50 photos in all. How many moose photos does he have? Draw a table to help you find the answer.
Answer:
16 moose,
4 bears,
30 eagles.

Explanation:
Given that Ronny has 4 times as many moose photos as brown bear photos. As 4 times of 4 is equal to 16. So there are 16 moose as the eagle photos are divisible by 6. So the eagle photos will be 30, so 16 moose + 4 bears + 30 eagles = 50 photos.

DRAWING OF TABLE:

Question 20.
The school lunchroom staff makes 40 sandwiches for the field trip. They make three times as many cheese sandwiches as chicken sandwiches. The rest of the sandwiches are made with hazelnut spread. If they make 15 cheese sandwiches, how many are made with hazelnut spread? Draw a table to help you find the answer.
Answer:
The number of hazelnut spread sandwiches will be 20 sandwiches.

Explanation:
Given that the school lunchroom staff makes 40 sandwiches for the field trip and they make three times as many cheese sandwiches as chicken sandwiches So the rest of the sandwiches are made with hazelnut spread as if they make 15 cheese sandwiches. So the number of chicken sandwiches will be 15÷3 which is 5 as there are three times as many cheese sandwiches as chicken sandwiches. So the number of hazelnut spread sandwiches will be 40-15-5 which is 20 sandwiches.

DRAWING OF TABLE:

Question 21.
Gary has $40.00 to spend on camping supplies. He wants to buy a water bottle, compass, insulated lunch bag, and mirror. Does he have enough money to also buy a thermal blanket? Explain.

Answer:
Gary does not have enough money.

Explanation:
Given that Gary has $40.00 to spend on camping supplies and he wants to buy a water bottle, compass, insulated lunch bag, and mirror which costs $17+$8.50+$4+$1.50 = $31. The remaining money will be $40-$31 which is $9 and the cost of thermal blanket is $12.50. So he does have enough money.