McGraw Hill Math

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 8 Test existing for free of cost.

McGraw-Hill Math Grade 3 Chapter 8 Test Answer Key

What fraction of each shape is colored? Write the fraction.

Question 1.

Answer:
The name of the shape is a triangle.
It is divided into three equal parts. The name of the shaded fraction is one-third.

Question 2.

Answer:
The name of the shape is a rectangle.
It is divided into six equal parts. The name of the shaded fraction is half.
3/6 = 1/2

Question 3.

Answer:
The name of the shape is a circle.
It is divided into two equal parts. The name of the shaded fraction is half.

Shade part of the set to show the fraction.

Question 4.

\(\frac{2}{3}\) are shaded
Answer:

Question 5.

\(\frac{1}{4}\) is shaded
Answer:

Question 6.

\(\frac{3}{8}\) are shaded
Answer:

Use the information on the number line to answer the question.

Question 7.
Erik hikes I mile along a nature trail. He sees birds along the way. He stops \(\frac{1}{4}\) of the way through the trail. What color bird does Erik see?
Label the number line with the correct number of equal parts. Then draw a dot where Erik stops.
Answer:
Given,
Erik hikes I mile along a nature trail. He sees birds along the way.
He stops \(\frac{1}{4}\) of the way through the trail.

Write the missing fractions in the boxes.

Question 8.

Answer:

Question 9.

Answer:

Look at the fraction strips or number lines. Compare the fractions. Place a check mark next to equivalent or not equivalent.

Question 10.

\(\frac{1}{2}\) and \(\frac{2}{4}\)
_____________ equivalent
_____________ not equivalent
Answer:
\(\frac{1}{2}\) and \(\frac{2}{4}\) are equivalent fractions

Question 11.

\(\frac{2}{6}\) and \(\frac{3}{8}\)
_____________ equivalent
_____________ not equivalent
Answer:
\(\frac{2}{6}\) and \(\frac{3}{8}\) are not equivalent fractions.

Write the fraction that equals a whole number. Then write the whole number that the fraction equals. Draw number lines to help if you need to.

Question 12.
\(\frac{4}{1}\) \(\frac{2}{4}\) \(\frac{1}{4}\) __________ = ___________
Answer: \(\frac{4}{1}\) \(\frac{2}{4}\) \(\frac{1}{4}\) \(\frac{3}{4}\) = 4

Question 13.
\(\frac{1}{3}\) \(\frac{2}{3}\) \(\frac{3}{3}\) ____________ = ____________
Answer: 1

Complete the fraction in each number sentence.

Question 14.
1 = \(\frac{}{2}\)
Answer: 1 = \(\frac{2}{2}\)

Question 15.
1 = \(\frac{8}{}\)
Answer: 1 = \(\frac{8}{8}\)

Question 16.
6 = \(\frac{}{1}\)
Answer: 6 = \(\frac{6}{1}\)

Question 17.
2 = \(\frac{2}{}\)
Answer: 2 = \(\frac{2}{1}\)

Compare the fractions. Write >, <, or = in the .

Question 18.

\(\frac{1}{8}\) \(\frac{1}{8}\)
Answer: \(\frac{1}{8}\) = \(\frac{1}{8}\)

Question 19.

\(\frac{2}{3}\) \(\frac{2}{6}\)
Answer: \(\frac{2}{3}\) > \(\frac{2}{6}\)

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 9 Lesson 1 Metric Units of Length are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 9 Lesson 1 Metric Units of Length

Solve.
Question 1.
The Museum of Science and Industry in Chicago is about 11.600 meters from The Art Institute of Chicago. How many kilometers apart are the two buildings?
Answer:
Number of kilometers apart are the two buildings = 11.6.

Explanation:
Number of meters The Museum of Science and Industry in Chicago from The Art Institute of Chicago = 11.600.
Conversion:
1 kilometer = 1000 meters.
Number of kilometers apart are the two buildings = Number of meters The Museum of Science and Industry in Chicago from The Art Institute of Chicago ÷ 1000
= 11600 ÷ 1000
= 11.6.

Question 2.
Ms. Lee is 1.7 meters tall. Her daughter is 1.2 meters tall. How much taller is Ms. Lee in centimeters?
Answer:
50 centimeters taller is Ms. Lee than her daughter.

Explanation:
Number of meters tall Ms. Lee = 1.7.
Number of meters tall her daughter = 1.2.
Difference:
Number of meters is Ms. Lee – Number of meters is her daughter
= 1.7 – 1.2
= 0.5.
Conversion:
1 meters = 100 centimeters
=> 0.5 m = 100 × 0.5
=> 50 centimeters.

Question 3.
Doreen wants to put a model boat in a box. The model measures 252 mm tall and 459 mm wide. Can the model fit within a box that measures 28 cm tall and 32 cm wide? How do you know?
Answer:
Yes, the model fits within a box that measures 28 cm tall and 32 cm wide because Length of the box and Width of the box  are more than the model.

Explanation:
Length of model = 252 mm.
Width of model = 459 mm.
Length of the box = 28 cm.
Width of the box = 32 cm.
Conversion:
1 cm = 100 mm.
=> Length of the box  = 100 × 28 = 2800 mm.
=> Width of the box = 100 × 32 = 3200 mm.

Question 4.
An adult blue whale is 25.74 meters long. How long is the blue whale in centimeters?
Answer:
2574 cm is the blue whale in centimeters.

Explanation:
Length of an adult blue whale = 25.74 meters.
Conversion:
1 m = 100 cm.
=> 25.74 m = 100 × 25.74
= 2574 cm.

Question 5.
Ahmad and Eva are practicing for a bike race. Ahmad rode 3.4 km in one day. Eva rode 4.8 km the same day. How much farther did Eva ride in meters?
Answer:
1400 m farther Eva ride in meters.

Explanation:
Number of kilometers Ahmad rode the bike in one day = 3.4.
Number of kilometers Eva rode the bike the same day = 4.8.
Difference:
Number of kilometers Eva rode the bike the same day – Number of kilometers Ahmad rode the bike in one day
= 4.8 – 3.4.
= 1.4.
Conversion:
1 km = 1000 m.
=> 1.4 km = 1000 × 1.4
= 1400 m.

Question 6.
Steven has three crabapple trees in his yard. The height of one measures 610 cm. The second measures 760 cm and the third measures 910 cm. What is the sum of the heights of the trees in meters?
Answer:
22.8 m is the sum of the heights of the trees in meters.

Explanation:
Height of one measures = 610 cm.
Height of second measures =  760 cm.
Height of third measures = 910 cm.
Total height of three crabapple trees  = Height of one measures + Height of second measures + Height of third measures
= 610 cm+ 760 cm + 910 cm
= 1370 cm + 910 cm
= 2280 cm.
Conversion:
1 m = 100 cm.
=> 2280 cm = 2280 ÷ 100
=> 22.8 m.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 6 Lesson 9 Reasonable Estimate are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 6 Lesson 9 Reasonable Estimate

Solve

Estimate the sum or difference. Use front-end estimation.

Question 1.
32\(\frac{2}{9}\) + 12\(\frac{1}{7}\) _______________
Answer:
30 + 10 = 40

Question 2.
45\(\frac{1}{2}\) – 33\(\frac{1}{5}\) _______________
Answer:
50 – 30 = 20.

Explanation:
The difference between \(\frac{91}{2}\) – \(\frac{166}{5}\). The front end estimated is 50-30 which is 20.

Question 3.
77\(\frac{5}{9}\) – 21\(\frac{2}{5}\) _______________
Answer:
80 – 20 = 50.

Explanation:
The difference between \(\frac{698}{9}\) – \(\frac{107}{5}\). The front end estimated is 80-20 which is 50.

Question 4.
34\(\frac{7}{8}\) + 22\(\frac{2}{9}\) _______________
Answer:
30 + 20 = 50.

Explanation:
The addition of \(\frac{279}{8}\) + \(\frac{200}{9}\). The front end estimated is 30+20 which is 50.

Question 5.

Answer:
1 + 1 = 2.

Explanation:
The addition of \(\frac{5}{6}\) + \(\frac{6}{7}\). The front end estimated is 1+1 which is 2.

Question 6.

Answer:
1 – 0 = 1.

Explanation:
The difference between \(\frac{5}{8}\) – \(\frac{3}{7}\). The front end estimated is 1-0 which is 1.

Question 7.

Answer:
1 – 0 = 1.

Explanation:
The difference between \(\frac{2}{3}\) – \(\frac{1}{4}\). The front end estimated is 1-0 which is 1.

Question 8.

Answer:
0 + 1 = 1.

Explanation:
The addition of \(\frac{1}{9}\) + \(\frac{7}{11}\). The front end estimated is 0+1 which is 1.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 9 Lesson 2 Metric Units of Mass are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 9 Lesson 2 Metric Units of Mass

Solve.
Question 1.
Mr. Wayne bought a watermelon with a mass of 1.89 kilograms. What is the mass of the watermelon in grams?
Answer:
1890 g is the mass of the watermelon in grams.

Explanation:
Number of kilograms is the watermelon Mr. Wayne bought = 1.89.
Conversion:
1 kg = 1000 g.
Number of grams is the watermelon Mr. Wayne bought = 1.89 × 1000
= 1890.

Question 2.
Ken’s dog is 4,200 grams. Sharon’s dog is 7,600 grams. What is the sum of the mass of both dogs in kilograms?
Answer:
11.8 kg is the sum of the mass of both dogs in kilograms.

Explanation:
Number of grams Ken’s dog = 4200.
Number of grams Sharon’s dog = 7600.
Total number of grams of both dogs = Number of grams Ken’s dog + Number of grams Sharon’s dog
= 4200 + 7600
= 11800.
Conversion:
1 kg = 1000 g.
=> 11800 g = 11800 ÷ 1000
=> 11.8 kg.

Question 3.
A company has a pile of steel pipes with a total mass of 19,450 kg. The pipes need to be shipped by truck, but the company’s truck can safely hold only 10 metric tons. How many trips will it take to ship all of the steel pipes? How do you know?
Answer:
Number of trips will it take to ship all of the steel pipes = 1.945.

Explanation:
Total number of kilograms a company has a pile of steel pipes = 19,450.
Number of metric tons the company’s truck can safely hold = 10.
Conversion:
1 metric ton = 1000 kilograms.
=> Total number of kilograms a company has a pile of steel pipes = 19450 ÷ 1000
=> 19.45 metric tons.
Number of trips will it take to ship all of the steel pipes = 19.45 ÷ 10
= 1.945.

Question 4.
A serving of cottage cheese is considered to be 113 grams. What is the mass of a serving of cottage cheese in milligrams?
Answer:
113000 mg is the mass of a serving of cottage cheese in milligrams.

Explanation:
Number of grams of a serving of cottage cheese is considered to be = 113.
Conversion:
1 gram  = 1000 milligrams.
Number of milligrams of a serving of cottage cheese is considered to be = 113 × 1000
= 113000.

Question 5.
A science experiment calls for 130 mg of cobalt chloride and 190 mg of water. What is the difference between these two amounts in grams?
Answer:
0.06 g is the difference between these two amounts in grams.

Explanation:
Number of milligrams a science experiment calls for of cobalt chloride = 130.
Number of milligrams a science experiment calls for of water = 190.
Difference:
Number of milligrams a science experiment calls for of water – Number of milligrams a science experiment calls for of cobalt chloride
= 190 – 130
= 60.
Conversion:
1 g = 1000 mg.
=> 60mg = 60 ÷ 1000 = 0.06 g.

Question 6.
An elephant at a zoo has a mass of 6.8 metric tons. A rhinoceros at the same zoo has a mass of 2.2 metric tons, and a hippopotamus has a mass of 2.9 metric tons. What is the sum of the mass of these three animals in kilograms?
Answer:
11900 kgs is the sum of the mass of these three animals in kilograms.

Explanation:
Number of metric tons an elephant at a zoo = 6.8.
Number of metric tons a rhinoceros at a zoo = 2.2.
Number of metric tons a hippopotamus at a zoo = 2.9.
Total number of metric tons of three animals = Number of metric tons an elephant at a zoo + Number of metric tons a rhinoceros at a zoo + Number of metric tons a hippopotamus at a zoo
= 6.8 + 2.2 + 2.9
= 9.0 + 2.9
= 11.9.
Conversion:
1 metric ton = 1000 kgs.
=> Total number of metric tons of three animals = 11.9 × 1000
=> 11900.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 15.1 Understanding Percent existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 15.1 Understanding Percent

Exercises

WRITE DECIMALS AND FRACTIONS

Convert to a decimal and a fraction.

Question 1.
7% = ____________ = ____________
Answer:
7% = 0.07 = 7/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 7% in decimal form as 0.07 and fraction form as 7/100.

Question 2.
16% = ____________ = ____________
Answer:
16% = 0.16 = 16/100 or 4/25
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 16% in decimal form as 0.16 and fraction form as 16/100.

Question 3.
100% = ____________ = ____________
Answer:
100% = 1.00 = 1/1
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 100% in decimal form as 1.00 and fraction form as 1/1.

Question 4.
25% = ____________ = ____________
Answer:
25% = 0.25 = 25/100 or 1/4
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 25% in decimal form as 0.25 and fraction form as 1/4.

Question 5.
1% = ____________ = ____________
Answer:
1% = 0.01 = 1/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 1% in decimal form as 0.01 and fraction form as 1/100.

Question 6.
20% = ____________ = ____________
Answer:
20% = 0.20 = 20/100 or 1/5
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 20% in decimal form as 0.20 and fraction form as 20/100 or 1/5.

Question 7.
44% = ____________ = ____________
Answer:
44% = 0.44 = 44/100 or 11/25
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 44% in decimal form as 0.44 and fraction form as 44/100.

Question 8.
99% = ____________ = ____________
Answer:
99% = 0.99 = 99/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 99% in decimal form as 0.99 and fraction form as 99/100.

Question 9.
23% = ____________ = ____________
Answer:
23% = 0.23 = 23/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 23% in decimal form as 0.23 and fraction form as 23/100.

Question 10.
3% = ____________ = ____________
Answer:
3% = 0.03 = 3/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 3% in decimal form as 0.03 and fraction form as 3/100.

Question 11.
0% = ____________ = ____________
Answer:
0% = 0.0 = 0/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 0% in decimal form as 0.0 and fraction form as 0/100.

Question 12.
71% = ____________ = ____________
Answer:
71% = 0.71 = 71/100
A percentage is displayed as decimal or a fraction with a denominator of 100. Here 71% in decimal form as 0.71 and fraction form as 71/100.

Question 13.
Out of 100 questions on an exam, Geraldine answered 89 questions correctly. What percentage of questions did Geraldine answer correctly?
Answer:
In exam out of 100 questions Geraldine answered 89 questions correctly.
Geraldine answered 89% of questions correctly.

Question 14.
Frederick is dividing his birthday cake among 10 friends. If each person receives an equal 10% of the cake, how can Frederick use fractions to express a single slice of cake? How can Frederick use decimals to express a single slice of cake?
Answer:
Frederick is dividing his birthday cake among 10 friends.
Each person receives an equal 10% of the cake.
10% = 10/100 = 1/10
Frederick use fractions to express a single slice of cake is 1/10.
1/10 = 0.1
Fedrick use decimals to express a single slice of cake is 0.1.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 9 Lesson 5 Volume in Cups, Pints, Quarts, and Gallons existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 9 Lesson 5 Volume in Cups, Pints, Quarts, and Gallons

Estimate

Place a check mark beside the better estimate for the amount each can hold.

Question 1.

__________ 1 gal
__________ 1 c
Answer:
The estimated capacity of the glass is 1 c.

Question 2.

__________ 1 gal
__________ 1 c
Answer:
The estimated capacity of the given object is 1 gal.

Question 3.

__________ 1 c
__________ 1 gal
Answer:
The estimated capacity of the given object is 1 gal.

Question 4.

__________ 1 qt
__________ 1 c
Answer:
The estimated capacity of the given object is 1 qt.

Fill in the blank with the reasonable measurement.

Question 5.
Patty drank ____________ of water after dance class.
6 gallons
2 cups
Answer:
Patty drank 2 cups of water after dance class.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 9 Lesson 6 Mass in Grams and Kilograms existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 9 Lesson 6 Mass in Grams and Kilograms

Estimate

Place a check mark beside the better estimate of each object’s mass.

Question 1.

__________ 28 g
__________ 1 kg
Answer:
The estimated weight of the pencil is 28 grams.

Question 2.

__________ 30 kg
__________ 30 g
Answer:
The estimated weight of monkey is 30 kg.

Question 3.

__________ 10 kg
__________ 12 g
Answer:
The estimated weight of the strawberry is 12 grams.

Question 4.

__________ 5 g
__________ 1 kg
Answer:
The estimated weight of the book is 5 grams.

Question 5.
What do you think is the mass of a small grape? Of a jar of pickles? Write your estimates. If possible, check your estimates using a scale that measures grams and kilograms. Write the measurements.

Answer:
The mass of a small graph is measured in grams with pan balance.
The mass of a jar of pickles is measured in kilograms.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 9 Lesson 7 Estimating and Weighing in Ounces and Pounds existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 9 Lesson 7 Estimating and Weighing in Ounces and Pounds

Estimate

Place a check mark beside the better estimate of each object’s weight.

Question 1.

__________ 1 lb
__________ 1 oz
Answer:
The estimated weight of the object is 1 lb.

Question 2.

__________ 3 oz
__________ 3 lb
Answer:
The estimated weight of the object is 3 oz.

Question 3.

__________ 500 oz
__________ 155 lb
Answer:
The estimated weight of the object is 155 lb.

Question 4.

__________ 10 lb
__________ 14 oz
Answer:
The estimated weight of the object is 14 oz.

Question 5.
Which weighs more: 16 ounces of feathers or 1 pound of marbles? Explain.
Answer:
1 pound = 16 ounces
So, the weight of 16 ounces of feathers and 1 pound of marbles are the same.

Question 6.
How many pounds do you think a pair of your shoes weigh? Write your estimate. If possible, check your estimate using a scale. Write the number of pounds.
Estimate: ________ lb
Measurement: _______ lb
Answer:
The estimated weight of pair of shoes is 1.5 lbs
The actual weight of pair of shoes is 2 lbs.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 9 Test existing for free of cost.

McGraw-Hill Math Grade 3 Chapter 9 Test Answer Key

Look at the clock. Write the time using numbers or words.

Question 1.

__________ : ___________
Answer: 12:17
Explanation:
The shorthand is on 12 and the minute hand is on 17. So, the time is 12:17
In words Twelve Seventeen.

Question 2.

Answer:
5:55 in words is Five Fifty-Five or Five minutes to Six.

Question 3.

__________ : ___________
Answer: 10:20
The hour hand is on 10 and the minute hand is on 4. So, the time is 10:20.
In words Ten Twenty

Write how much time has passed

Question 4.
start 10:00
end 1:15
Answer:
1:15 can be written in the 24-hour format as 13:15
To find how much time has passed we have to subtract 10 from 1:15
13 hour 15 mins
-10 hour 00 min
3 hour 15 mins
Thus the answer is 3 hours 15 mins.

Question 5.
start 6:40
end 3:00
Answer:
3:00 can be written as 15:00
15 hour 00 mins
-6 hour 40 mins
8 hour 20 mins
Thus the answer is 8 hours 20 mins.

Question 6.
start 4:30
end 7:20
Answer:
7 hour 20 mins
-4 hour 30 mins
2 hour 50 mins
Thus the answer is 2 hours 50 mins.

Question 7.
Cameron finishes his chores at 1:30. He spent 5 minutes watering houseplants, 30 minutes raking leaves, and 5 minutes making his bed. When did he start his chores? Use the number line and work backward to help you solve.

Answer:
Cameron finishes his chores at 1:30.
He spent 5 minutes watering houseplants, 30 minutes raking leaves, and 5 minutes making his bed.
5 + 30 + 5 = 40 minutes
We have to draw the number line backward.
Subtract 40 minutes from 1:30
1 hour 30 minutes – 40 minutes = 12:50

Thus Cameron starts his chores at 12:50.

Place a check mark beside the better estimate for the amount each can hold.

Question 8.

___________ 3 L
___________ 5 mL
Answer:
The spoon is small so it can hold 5 mL.
So, the estimated answer is 5mL.

Question 9.

___________ 30 L
___________ 300 mL
Answer:
The cup can hold 300 mL
So, the estimated answer is 300 mL

Question 10.

___________ 100 mL
___________ 3 L
Answer:
The container can hold 3 Liters.
So, the estimated answer is 3 L

Question 11.

___________ 180 L
___________ 180 mL
Answer:
The glass can hold 180 mL.
So, the estimated answer is 180 mL.

Place a check mark beside the better estimate of each object’s mass.

Question 12.

___________ 3 g
___________ 3 kg
Answer: 3 g
The estimated mass of the given object is 3 grams.

Question 13.

___________ 100 kg
___________ 300 g
Answer:
The estimated mass of the given object is 100 kg.

Question 14.

___________ 170 g
___________ 2 kg
Answer:
The estimated mass of the given object is 170 grams.

Question 15.

___________ 4 g
___________ 4 kg
Answer:
The estimated mass of the given object is 4 kg.

Question 16.
Find a heavy book or a container of laundry soap. Estimate how much the book or the laundry soap container weighs in pounds. If possible, check your estimate using a scale. Write the number of pounds.
Estimate: _______ lb
Measurement: ________ lb
Answer:
The estimated weight of the laundry soap is about 3 lbs.
The measurement of the laundry soap is 3.5 lbs.

Place a check mark beside the better estimate of each object’s weight.

Question 17.

___________ 900 lb
___________ 900 oz
Answer:
The better estimate of the given object cow is 900 lbs.

Question 18.

___________ 4 lb
___________ 7 oz
Answer:
The better estimate of the given object 7 ounces.

Question 19.

___________ 35 lb
___________ 70 oz
Answer:
The better estimate of the given object dog is 35 lbs.

Question 20.

___________ 10 lb
___________ 10 oz
Answer:
The better estimate of the given object 10 oz.

Choose the correct operation and solve the word problem.

Question 21.
Mr. Hunter waters several large plants using this watering can. Each plant needs the amount of water in I full can. How many plants did Mr. Hunter water if he used 14 liters of water in all?

Answer:
Given,
Mr. Hunter waters several large plants using this watering can.
Each plant needs the amount of water in I full can.
The capacity of the can is 2 liters
To find:
How many plants did Mr. Hunter water if he used 14 liters of water in all?
14 ÷ 2 = 7
Thus Mr. Hunter waters 7 plants with 14 liters of water.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 9 Lesson 8 Problem Solving: Volume and Mass existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 9 Lesson 8 Problem Solving: Volume and Mass

Solve

Read. Choose the correct operation and solve.

Question 1.
Dr. Torres pours water into 2 containers. How much water did she pour in all?

Answer:
Given,
Dr. Torres pours water into 2 containers.
By seeing the above containers we can add the quantity.
1 + 3 = 4
She poured 4 liters in all.

Question 2.
A nickel has a mass of 5 grams. A dime has a mass of about 3 grams. Shari has 4 nickels and 1 dime. What is the mass of all 5 coins?
Answer:
Given,
A nickel has a mass of 5 grams.
A dime has a mass of about 3 grams.
Shari has 4 nickels and 1 dime.
5 × 4 = 20
1 × 3 = 3
20 + 3 = 23 grams
The mass of all 5 coins is 23 grams.

Question 3.
Megan used 36 liters of water to fill some fishbowls at the pet shop. She poured 4 liters into each bowl. How many fishbowls did she fill?
Answer:
Given,
Megan used 36 liters of water to fill some fishbowls at the pet shop.
She poured 4 liters into each bowl.
36 ÷ 4 = 9
Thus Megan fills water into 9 bowls.