McGraw Hill Math

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 12 Lesson 5 Using a Fraction to Describe Equal Parts of a Shape existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 12 Lesson 5 Using a Fraction to Describe Equal Parts of a Shape

Identify

What fraction of the total area is blue? Write the fraction.

Question 1.

Answer:
\(\frac{1}{3}\)

Question 2.

Answer:
\(\frac{1}{6}\)

Explanation:
There are 6 equal parts in the whole
1 part of the whole is shaded
So, the fraction that represents the shaded part is \(\frac{1}{6}\).

Question 3.

Answer:
\(\frac{5}{8}\)

Explanation:
There are 8 equal parts in the whole
6 parts of the whole are shaded
So, the fraction that represents the shaded part is \(\frac{5}{8}\).

Question 4.

Answer:
\(\frac{1}{2}\)

Explanation:
There are 2 equal parts in the whole
1 part of the whole is shaded
So, the fraction that represents the shaded part is \(\frac{1}{2}\).

Question 5.
The picture shows a tray in Mrs. Dixon’s jewelry box. The orange parts are for bracelets. The red parts for rings. The yellow parts are for necklaces. What fraction of the total area of the tray is for rings? How do you know?

Answer:
\(\frac{1}{8}\)

Explanation:
The picture shows a tray in Mrs. Dixon’s jewelry box
There are 4 orange parts, 3 yellow parts and 1 red part
The orange parts are for bracelets, the red parts for rings and the yellow parts are for necklaces
There are 8 parts in the whole
There is 1 red part that is 1 part for rings
So, the fraction that represents rings is \(\frac{1}{8}\).

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 12 Lesson 6 Finding a Perimeter or Unknown Side Length existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 12 Lesson 6 Finding a Perimeter or Unknown Side Length

Solve

Find the perimeter.

Question 1.

Answer:
16 cm

Question 2.

Answer:
15 ft

Explanation:
Perimeter of the triangle is sum of all the sides
That is 5 + 5 + 5 = 15
So, perimeter is 15 ft.

Question 3.

Answer:
4 m

Explanation:
Perimeter of the square is sum of all the sides
That is 1 + 1 + 1 + 1 = 4
So, perimeter is 4 m.

Find the length of the unknown side.

Question 4.

perimeter: 30 m
unknown side: ___________
Answer:
Unknown side = 10 m.

Explanation:
Given Perimeter = 30 m
Perimeter of the triangle is sum of all the sides
That is 10 + 10 + ? = 30
20 + ? = 30
30 – 20 = 10
So, unknown side = 10 m.

Question 5.

perimeter: 14 in
unknown side: _____________
Answer:
Unknown side = 4 in

Explanation:
Given perimeter = 14 in
Perimeter of a shape is sum of all the sides
2 + 3 + 2 + 3  + ? = 14
10 + ? = 14
14 – 10 = 4
So, unknown side = 4 in.

Question 6.

perimeter: 16 ft
unknown side: _____________
Answer:
Unknown side = 8 ft

Explanation:
Given Perimeter = 16  ft
Perimeter of the triangle is sum of all the sides
That is 2 + 6 + ? = 16
8 + ? = 16
16 – 8 = 8
So, unknown side = 8 ft.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 12 Lesson 7 Finding Area and Perimeter existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 12 Lesson 7 Finding Area and Perimeter

Solve

Look at the shape on the left. Then follow the directions and circle your answer.

Question 1.
Circle the shape with the same area but different perimeter.

Answer:

Explanation:
The area of the yellow rectangle is 24 in
The area of the red rectangle is 35 in
The area of the green rectangle is 24 in
So, i drew a circle around the green rectangle as its area is same with the yellow rectangle.

Question 2.
Circle the shape with the same perimeter but different area.

Answer:

Explanation:
The area perimeter of the yellow rectangle is 18 ft
The perimeter of the purple rectangle is 18 ft
The area of the blue rectangle is 14 ft
So, i drew a circle around the purple rectangle as it has the same perimeter as the yellow rectangle.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 12 Lesson 8 Problem Solving existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 12 Lesson 8 Problem Solving

Solve

Use the picture to help you find the answers.

Question 1.
Ramona wants to carpet the floor of her puppy’s doghouse. She cannot spend more than $27.00. Does she have enough money to buy blue carpeting? Explain.
Answer:
No, she don’t have enough money to buy blue carpeting

Explanation:
The area of the Doghouse is 3 x 3 = 9 square units
The price for each blue square unit is $5
9 x 5 = $45
Ramona cannot spend more than $27.00
So, she don’t have enough money to buy blue carpeting.

Question 2.
Which color carpeting should Ramona buy?
Answer:
Ramona should buy yellow carpeting

Explanation:
The area of the Doghouse is 3 x 3 = 9 square units
The price for each red square unit is $4
9 x 4 = $36
Ramona cannot spend more than $27.00
The area of the Doghouse is 3 x 3 = 9 square units
The price for each yellow square unit is $3.00
9 x 3 = $27
Ramona has $27.00
So, Ramona should buy yellow carpeting.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 12 Test existing for free of cost.

McGraw-Hill Math Grade 3 Chapter 12 Test Answer Key

Count or multiply to find the area of each figure.

Question 1.

Answer:
6 square units

Explanation:
I counted by 1’s
There are 6 squares in the above figure
So, the area of the given figure is 6 square units.

Question 2.

Answer:
4 square units

Explanation:
There are 3 squares and 2 triangles which is 1 square
So, the area of the figure is 4 square units.

Question 3.

Answer:
6 square units

Explanation:
I counted by 1’s
There are 6 squares in the above shape
So, the area of the given figure is 6 square units.

Question 4.

Answer:
12 square units

Explanation:
The multiplication sentence that tells the area of the above figure is 2 x 6 = 12
So, the area of the given figure is 12 square units.

Question 5.

Answer:
11 square units

Explanation:
I counted by 1’s
There are 11 squares in the above shape
So, the area of the given figure is 11 square units.

Question 6.

Answer:
22 square units

Explanation:
I counted by 1’s
There are 22 squares in the above shape
So, the area of the given figure is 22 square units.

Write a multiplication sentence for each area model.

Question 7.

Answer:
1 x 3 = 3

Explanation:
There is 1 row and 3 columns of squares
The multiplication sentence for the given area model is 1 x 3 = 3.

Question 8.

Answer:
5 x 5 = 25

Explanation:
There is 5 rows and 5 columns of squares
The multiplication sentence for the given area model is 5 x 5 = 25.

Question 9.

Answer:
2 x 7 = 14

Explanation:
There is 2 rows and 7 columns of squares
The multiplication sentence for the given area model is 2 x 7 = 14.

Look at the area model. Circle the multiplication sentence that matches.

Question 10.

4 × (4 + 2) = 16 square units
2 × (4 + 2) = 16 square units
4 × (2 + 2) = 16 square units
Answer:

Explanation:
There are 4 rows of squares
In that 2 columns are brown and 2 columns are yellow
So, the the multiplication sentence that matches with the area model is 4 x (2 + 2) = 16 square units.

Question 11.
Selma is decorating the cover of her journal with stickers. The cover is 6 units by 7 units. Each sticker covers 1 square unit. How many stickers does Selma need to decorate every unit of the whole journal cover? Find 6 × 7 by breaking apart 7. Use 3 for one of the addends. Use the area model to help you.

Answer:
Selma need 42 stickers to decorate every unit of the whole journal cover

Explanation:
Selma is decorating the cover of her journal with stickers
The cover is 6 units by 7 units
We need to find area of the journal cover
6 x 7
Breaking apart 7 as 3 ad 4
Area = 6 x ( 3 + 4 )
= (6 x 3) + (6 x 4)
= 18 + 24
= 42
So, area of the cover is 42 square units
Each sticker covers 1 square unit
So, Selma need 42 stickers to decorate every unit of the whole journal cover.

What fraction of the total area ¡s red? Write the fraction.

Question 12.

Answer:
\(\frac{1}{4}\)

Explanation:
There are 4 equal parts in the whole
1 part of the whole is shaded
So, the fraction that represents the shaded part is \(\frac{1}{4}\).

Question 13.

Answer:
\(\frac{1}{8}\)

Explanation:
There are 8 equal parts in the whole
1 part of the whole is shaded
So, the fraction that represents the shaded part is \(\frac{1}{8}\)

Question 14.

Answer:
\(\frac{1}{6}\)

Explanation:
There are 6 equal parts in the whole
1 part of the whole is shaded
So, the fraction that represents the shaded part is \(\frac{1}{6}\)

Find the perimeter.

Question 15.

Answer:
27 m

Explanation:
Perimeter of the triangle is sum of all the sides
That is 9 + 9 + 9
So, perimeter is 27 m.

Question 16.

Answer:
8 cm

Explanation:
Perimeter of the square is sum of all the sides
That is 2 + 2 + 2 + 2
So, perimeter is 8 cm.

Question 17.

Answer:
26 ft

Explanation:
Perimeter of the rectangle is sum of all the sides
Opposite sides of the rectangle are equal in lengths
That is 9 + 9 + 4 + 4
So, perimeter is 26 ft.

Find the length of the unknown side.

Question 18.

perimeter: 19 m
unknown side: _____________
Answer:
Unknown side = 5 m

Explanation:
Given perimeter = 19 m
Perimeter of a shape is sum of all the sides
4 + 3 + 4 + 3 + ? = 19
14 + ? = 19
19 – 14 = 5
So, unknown side = 5 m.

Question 19.

perimeter: 15 in
unknown side: ______________
Answer:
Unknown side = 6 in

Explanation:
Given Perimeter = 15 in
Perimeter of the triangle is sum of all the sides
That is 3 + 6 + ? = 15
9 + ? = 15
15 – 9 = 6
So, unknown side = 6 in.

Question 20.

perimeter: 13 ft
unknown side: _______________
Answer:
Unknown side = 3 ft

Explanation:
Given perimeter = 13 ft
Perimeter of a shape is sum of all the sides
2 + 2 + 2 + 4  + ? = 13
10 + ? = 13
13 – 10 = 3
So, unknown side = 3 ft.

Use the picture to help you solve.

Question 21.
An artist charges $8 for each square unit of surface space that she paints. How much did she charge for this painting?

Answer:
$80

Explanation:
An artist charges $8 for each square unit of surface space that she paints
The area of the painting is 2 x 5 = 10 square unit
So, multiply 10 with $8 to find the amount the artist charged for the painting
10 x $8 = $80
So, the artist charged $80 for this painting.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Posttest existing for free of cost.

McGraw-Hill Math Grade 3 Posttest Answer Key

Choose the correct term from the box to complete the sentence.

ones
tens
hundreds
hundred thousands

Question 1.
The value of the underlined digit in 98,156 is 5 ____________
Answer:
5 tens – 50

Explanation:
The value of the digit 5 in 156 is 5 tens that is 50.

Question 2.
The value of the underlined digit in 39 is 9 ______________
Answer:
9 ones – 9

Explanation:
The value of the digit 9 in 39 is 9 ones that is 9.

Question 3.
The value of the underlined digit in 725,492 is 7 ___________
Answer:
7 hundred thousands – 700,000

Explanation:
The value of the digit 7 in 725,492 is 7 hundred thousands that is 700,000.

Question 4.
The value of the underlined digit in 627,385 is 3 _______________
Answer:
3 hundred – 300

Explanation:
The value of the digit 3 in 627,385 is 3 hundreds that is 300.

Write each number in standard form.

Question 5.
600,000 + 40,000 + 6,000 + 9
Answer:
646,009

Explanation:
The standard form for the given expanded form is 646,009.

Question 6.
seven hundred sixty-two
Answer:
762

Explanation:
The standard form for the given number name is 762.

Question 7.
30,000 + 8,000 + 500 + 10 + 1
Answer:
38,511

Explanation:
The standard form for the given expanded form is 38,511.

Question 8.

Answer:
1,126

Explanation:
There is 1 thousands block, 1 hundreds block and 2 tens sticks and 6 ones cubes
So, the standard form for the given quick picture is 1,126.

Write the numbers from greatest to least.

Question 9.
37,960
37,999
36,848
Answer:
37,999
37,960
36,848

Explanation:
I put the numbers in orders from greatest to least.

Question 10.
8,029
8,229
8,209
Answer:
8,229
8,209
8,029

Explanation:
I put the numbers in orders from greatest to least.

Question 11.
What digit must be in the hundreds place of all numbers between 1,499 and 1,600? Circle the numeral.
4
5
6
Answer:

Explanation:
The digit that must be in the hundreds place of all numbers between 1,499 and 1,600 is 5
So, i circled the numeral 5.

Question 12.
Name three numbers that change to 90 when rounded to the nearest 10.
Answer:
89 – eighty nine
85 – eighty five
87 – eighty seven

Explanation:
I wrote the names of 3 numbers that change into 90 when rounded to nearest 10
They are 85, 87 and 89.

Add. Write the sum.

Question 13.

Answer:

Explanation:
The sum of 179 and 649 is 828.

Question 14.

Answer:

Explanation:
The sum of 532 and 368 is 900.

Question 15.

Answer:

Explanation:
The sum of 287 and 329 is 616.

Question 16.

Answer:

Explanation:
The sum of 482 and 379 is 861.

Question 17.

Answer:

Explanation:
The sum of 447 and 168 is 615.

Question 18.

Answer:

Explanation:
The sum of 276 and 256 is 532.

Question 19.

Answer:

Explanation:
The sum of 828 and 399 is 1,227.

Question 20.

Answer:

Explanation:
The sum of 646 and 294 is 940.

Add. Be sure to add the numbers in () first.

Question 21.
19 + (3 + 2) =
19 + ________ = _________
(19 + 3) + 2 = __________
__________ + 2 = __________
Answer:
24

Explanation:
19 + (3 + 2) =
19 + 5 = 24
(19 + 3) + 2 =
22 + 2 = 24
So, 19 + (3 + 2) = 24.

Question 22.
(11 + 6) + 9 =
11 + (6 + 9) = __________
__________ + 9 = __________
11 + __________ = __________
Answer:
26

Explanation:
(11 + 6) + 9 =
17 + 9 = 26
11 + (6 + 9) =
11 + 15 = 26
So, (11 + 6) + 9 = 26.

Subtract. Write the difference.

Question 23.

Answer:

Explanation:
The difference of 543 and 457 is 86.

Question 24.

Answer:

Explanation:
The difference of 386 and 187 is 199.

Question 25.

Answer:

Explanation:
The difference of 721 and 144 is 577.

Question 26.

Answer:

Explanation:
The difference of 865 and 477 is 386.

Question 27.

Answer:

Explanation:
The difference of 940 and 543 is 397.

Question 28.

Answer:

Explanation:
The difference of 644 and 366 is 278.

Question 29.

Answer:

Explanation:
The difference of 532 and 168 is 364.

Question 30.

Answer:

Explanation:
The difference of 325 and 139 is 186.

Question 31.
How many more pounds can Ivan lift than Hector?

Answer:

Multiply. Write the product

Question 32.

3 × 8 = _____________
Answer:
24

Explanation:
There are 3 rows of 8 buttons each row
So, 3 x 8 = 24.

Question 33.

2 × 6 = _____________
Answer:
12

Explanation:
There are 2 rows of 6 flowers in each row
So, 2 x 6 = 12.

Question 34.
9 × 1 = _____________
Answer:
9

Explanation:
9 x 1 = 9
The product of 9 and 1 is 9.

Question 35.
5 × 6 = _____________
Answer:
30

Explanation:
5 x 6 = 30
The product of 5 and 6 is 30.

Question 36.
7 × 4 = ______________
Answer:
28

Explanation:
7 x 4 = 28
The product of 7 and 4 is 28.

Question 37.

Answer:

Explanation:
10 x 1 = 10
The product of 10 and 1 is 10.

Question 38.

Answer:

Explanation:
2 x 0 = 0
The product of any number with 0 will be 0.

Question 39.

Answer:

Explanation:
7 x 7 = 49
The product of 7 and 7 is 49.

Question 40.

Answer:

Explanation:
9 x 9 = 81
The product of 9 and 9 is 81.

Question 41.
Emily is helping her neighbors shovel their sidewalks after a big snowstorm. She charges $10 for each sidewalk. Emily shoveled 6 sidewalks on Wednesday. How much did she earn on Wednesday? If you need help finding the answer, draw pictures or use objects.
Answer:
$ 60

Explanation:
Emily is helping her neighbors shovel their sidewalks after a big snowstorm
She charges $10 for each sidewalk
Emily shoveled 6 sidewalks on Wednesday
To find the amount Emily earned multiply 6 with $10
6 x $10 = $60
So, Emily earned $60 on Wednesday.

Question 42.
Steven has 8 bags of shells he collected at the beach. There are 8 shells in each bag. How many shells does Steven have in all?
Answer:
64 shells

Explanation:
Steven has 8 bags of shells he collected at the beach
There are 8 shells in each bag
To find the total number of shells multiply the number of bags with the number of shells in each bag
8 x 8 = 64
So, Steven have 64 shells in all.

Question 43.
Richard uses 4 × 5 to find the total number of strawberries. Abby uses 5 × 4. Will they get the same product? Why or why not?

Answer:
Yes, Richard and Abby will get same product

Explanation:
Richard uses 4 × 5 to find the total number of strawberries
Abby uses 5 × 4.
The result of both the multiplication sentences is same as the factors are same only the order of the factors is different
So, Richard and Abby will get same product.

Divide. Write the quotient.

Question 44.
40 ÷ 10 = ___________
Answer:

Explanation:
The division of 40 and 10 is 4
So, 40 ÷ 10 = 4.

Question 45.
9 ÷ 3 = ____________
Answer:

Explanation:
The division of 9 and 3 results is 3.
9 ÷ 3 = 3.

Question 46.
7 ÷ 1 = _____________
Answer:

Explanation:
The division of 7 and 1 is 7
So, 7 ÷ 1 = 7.

Question 47.

Answer:

Explanation:
The division of 81 and 9 is 9
So, 81 ÷ 9 = 9.

Question 48.

Answer:

Explanation:
The division of 35 and 5 is 7
So, 35 ÷ 5 = 7.

Question 49.

Answer:

Explanation:
The division of 32 and 4 is 8
So, 32 ÷ 4 = 8.

Question 50.

Answer:

Explanation:
The division of 18 and 2 is 9
So, 18 ÷ 2 = 9.

Question 51.
Mrs. Fields is an art teacher. She teaches a total of 36 classes in 4 weeks. She teaches the same number of classes each week. How many classes does Mrs. Fields teach each week?
Answer:

Explanation:
Mrs. Fields is an art teacher
She teaches a total of 36 classes in 4 weeks
She teaches the same number of classes each week
To find the number of classes she teach in a week
Divide 36 with 4
36 ÷ 4 = 9
So, Mrs. Fields teach 9 classes each week.

Question 52.
Greg has 56 flowers to fill 8 flower vases. Greg wants to place the same number of flowers in each vase. How many flowers should he place in each vase?
Answer:

Explanation:
Greg has 56 flowers to fill 8 flower vases
Greg wants to place the same number of flowers in each vase
To find the number of flowers to be placed in each vase
Divide 56 with 8
56 ÷ 8 = 7
So, Greg should place 7 flowers in each vase.

Color part of the set to show the fraction.

Question 53.

\(\frac{1}{4}\) is blue
Answer:

Explanation:
I colored 1 part of the whole that is one fourth.

Question 54.

\(\frac{1}{3}\) is green
Answer:

Explanation:
I colored 1 part of the whole that is one third.

Question 55.

\(\frac{2}{3}\) are red
Answer:

Explanation:
I colored 2 parts of the whole that is two thirds.

Question 56.
Lois walks 1 mile from her office to her home. She made a stop when she was 2/3 of the way home. Where did Lois stop?

Answer:

Explanation:
Lois walks 1 mile from her office to her home
She made a stop when she was 2/3 of the way home
Lois stopped at the Farmer’s market
So, i marked the point on the line.

Complete the equivalent fraction. Write the missing numerator or denominator.

Question 57.

Answer:

Explanation:
The equivalents fraction to \(\frac{1}{2}\) is \(\frac{3}{6}\).

Question 58.

Answer:

Explanation:
The equivalents fraction to \(\frac{1}{3}\) is \(\frac{2}{6}\).

Question 59.
What time will it be in 3 hours?

Answer:
5:45

Explanation:
The time shown in the clock is 2:45
So, time in 3 hours will be 5:45.

Question 60.
What time will it be in 4 hours and 45 minutes?

Answer:
9:15

Explanation:
The time shown in the clock is 4:30
The time in 4 hours nd 45 minutes will be 9:15.

Question 61.
What time will it be in 2 hours and 5 minutes?

Answer:
9:35

Explanation:
The time shown in the clock is 7:30
The time in 2 hours 5 minutes will be 9:35.

Question 62.
Sharon spends 30 minutes mowing the lawn. She spends 10 minutes watering her plants, and 15 minutes walking her dog. Sharon finishes at 5:30. When did she start? Use the number line and work backward to help you solve.

Answer:

Explanation:
Sharon spends 30 minutes mowing the lawn
She spends 10 minutes watering her plants, and 15 minutes walking her dog
Sharon finishes at 5:30
I used the number line and marked the time backward from 5:30
15 minutes before 5:30 is 5:15
10 minutes before 5:15 is 5:05
30 minutes before 5:05 is 4:35
So, Sharon started at 4:35.

Circle the better estimate for the amount each can hold.

Question 63.

5 L
900 mL
Answer:

Explanation:
The container can hold about 5 L
So, i drew a circle around it.

Question 64.

1 L
15 mL
Answer:

Explanation:
The spoon can hold 15 mL
So, i drew a circle around it.

Question 65.

4 L
400 mL
Answer:

Explanation:
The above container can hold 4 L
So, i drew a circle around it.

Students voted for their favorite fruit snack. The bar graph shows how they voted.

Question 66.
How many students voted?
Answer:
29

Explanation:
4 students chose strawberries
6 students chose cherries
10 students chose apple
9 students chose banana
Add 4 + 6 + 10 + 9 = 29
So, 29 students voted for their favorite fruit snack.

Question 67.
Did more students choose Banana, or Strawberries and Cherries combined?
Answer:
More students chose Strawberries and cherries combined

Explanation:
4 students chose strawberries
6 students chose cherries
Strawberries and cherries combined 4 + 6 = 10
9 students chose banana
So, more students chose strawberries and cherries combined than banana.

Place a check mark next to the name of each.

Question 68.

___________ ray
___________ line segment
___________ angle
Answer:

Explanation:
The above given figure is a line segment
A line segment is a part of line that has two end points.

Question 69.

___________ ray
___________ line segment
___________ angle
Answer:

Explanation:
The above given figure is an angle
An angle is formed when two straight lines or rays meet at a common point.

Question 70.

___________ ray
___________ line segment
___________ angle
Answer:

Explanation:
The above figure is a ray
A ray is a line with 1 end point.

The perimeter of each shape is given, but the length of one side is unknown. Find the unknown side length.

Question 71.

perimeter: 24 feet
unknown side length: ____________
Answer:
Unknown side = 8 ft

Explanation:
Given Perimeter = 24 feet
Perimeter of the rectangle is sum of all the sides
That is 4 + 8 + 4 + ? = 24
16 + ? = 24
24 – 16 = 8
So, unknown side = 8 ft.

Question 72.

perimeter: 16 inches
unknown side length: ____________
Answer:
Unknown side = 4 in

Explanation:
Given Perimeter =  16 inches
Perimeter of the quadrilateral is sum of all the sides
That is 4 + 3 + 5 + ? = 16
12 + ? = 16
16 – 12 = 4
So, unknown side = 4 in.

Question 73.
Find the area of the rug by counting the unit squares. Then find the area by multiplying the sides.

Area found by counting: _____________ square feet
Area found by multiplying: _____________ square feet
Answer:
Area found by counting: 50 square feet
Area found by multiplying: 50 square feet

Explanation:
By counting unit squares:
I counted by 1’s
There are 50 unit squares
So, the area of the rug is 50 square feet
By multiplying the sides
There are 5 rows and 10 columns of units squares
Multiply: 5 x 10 = 50
So, the area of the rug is 50 square feet.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 11 Lesson 1 Identifying Rays, Line Segments, and Angles existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 11 Lesson 1 Identifying Rays, Line Segments, and Angles

Write

Name each figure as a line, line segment, ray, or angle.

Question 1.

Answer:
ray

Question 2.

Answer:
Line segment

Explanation:
The above given figure LM is a line segment
A line segment is a part of line that has two end points.

Question 3.

Answer:
Angle

Explanation:
The above given figure NOP is an angle
An angle is formed when two straight lines or rays meet at a common point.

Question 4.

Answer:
Line

Explanation:
The above given figure QR is a line
A line is defined as a line of points that extents infinitely in two directions.

Question 5.

Answer:
Angle

Explanation:
The above given figure STU is an angle
An angle is formed when two straight lines or rays meet at a common point.

Question 6.

Answer:
Line segment

Explanation:
The above given figure VW is a line segment
A line segment is a part of line that has two end points.

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 13.4 Solving 2-Step Equations to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 13.4 Solving 2-Step Equations

Exercises

SOLVE

Question 1.
10x – 7 = 23
Answer:
x = 3,

Explanation:
Given to solve 10x – 7 = 23,
So 10x = 23 + 7 = 30,
x = 30 ÷ 10 = 3.

Question 2.
14 = 12 + 2x
Answer:
x = 1,

Explanation:
Given to solve 14 = 12 + 2x,
So 2x = 14 – 12 = 2,
x = 2 ÷ 2 = 1.

Question 3.
21 + 4x = 28
Answer:
x = 1.75,

Explanation:
Given to solve 21 + 4x = 28,
So 4x = 28 – 21 = 7,
x = 7 ÷ 4 = 1.75.

Question 4.
200 + 15x = 425
Answer:
x = 15,

Explanation:
Given to solve 200 + 15x = 425,
So 15x = 425 – 200 = 225,
x = 225 ÷ 15 = 15.

Question 5.
5x + 39 = 41
Answer:
x = 0.4,

Explanation:
Given to solve 5x + 39 = 41,
So 5x =41 – 39 = 2,
x = 2 ÷ 5 = 0.4.

Question 6.
10z + 17 = 77
Answer:
z = 6,

Explanation:
Given to solve 10z + 17 = 77,
So 10z = 77 – 17 = 60,
z = 60 ÷ 10 = 6.

Question 7.
65 = 41 + 3x
Answer:
x = 8,

Explanation:
Given to solve 65 = 41 + 3x,
So 3x = 65 – 41 = 24,
x = 24 ÷ 3 = 8.

Question 8.
107 = 75 + 16r
Answer:
r = 2,

Explanation:
Given to solve 107 = 75 + 16r,
So 16r = 107 – 75 = 32,
r = 32 ÷ 16 = 2.

Question 9.
49 + 18d = 37
Answer:
d = -0.666,

Explanation:
Given to solve 49 + 18d = 37,
So 18d = 37 – 49 = -12,
d = 12 ÷ 18 = -0.666.

Question 10.
15b + 18 = 30
Answer:
b = 0.8,

Explanation:
Given to solve 15b + 18 = 30,
So 15b = 30 – 18 = 12,
b = 12 ÷ 15 = 0.8.

Question 11.
5q = 10q + 60
Answer:
q = -12,

Explanation:
Given to solve 5q = 10q + 60,
So 10q – 5q = -60,
q = -60 ÷ 5 = -12.

Question 12.
2f + 4f + 18 = 32
Answer:
f = 2.3333,

Explanation:
Given to solve 2f + 4f + 18 = 32,
So 6f = 32 – 18 = 14,
f = 14 ÷ 6 = 2.3333.

Question 13.
3j = 5j – 14
Answer:
j = 7,

Explanation:
Given to solve 3j = 5j – 14,
So 5j – 3j = 14,
j = 14 ÷ 2 = 7.

Question 14.
23 + 18r = 6r + 47
Answer:
r = 2,

Explanation:
Given to solve 23 + 18r = 6r + 47,
So 18r – 6r = 47 – 23,
12r = 24,
r = 24 ÷ 12 = 2.

Question 15.
13k + 14k + 10 = 13
Answer:
k = 0.1111,

Explanation:
Given to solve 13k + 14k + 10 = 13,
So 27k = 13 – 10 = 3,
k = 3 ÷ 27 = 0.1111.

Question 16.
14v = 10v – 5
Answer:
v = -1.25,

Explanation:
Given to solve 14v = 10v – 5,
So 14v – 10v = – 5,
4v = -5,
v = -5 ÷ 4 = -1.25.

Excel in your academics by accessing McGraw Hill Math Grade 3 Answer Key PDF Chapter 11 Lesson 2 Identifying Polygons and Nonpolygons existing for free of cost.

McGraw-Hill Math Grade 3 Answer Key Chapter 11 Lesson 2 Identifying Polygons and Non polygons

Identify

Place a check mark next to the name of each polygon.

Question 1.

____________ square
____________ rectangle
____________ triangle
Answer:

Explanation:
The above given figure has 4 sides it is a rectangle
So, i check marked next to rectangle.

Question 2.

____________ hexagon
____________ octagon
____________ square
Answer:

Explanation:
The above given figure has 6 sides it is a hexagon
So, i check marked next to hexagon.

Question 3.

____________ square
____________ triangle
____________ pentagon
Answer:

Explanation:
The above given figure has 5 sides it is a pentagon
So, i check marked next to pentagon.

Name each figure as a polygon or non polygon.

Question 4.

Answer:
Non polygon

Explanation:
The above figure is not a polygon as it is not a closed figure.

Question 5.

Answer:
Polygon

Explanation:
The above figure is a polygon as it is a closed figure with 3 or more sides.

Question 6.

Answer:
Non polygon

Explanation:
The above figure is not a polygon as it is not a closed figure.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 3 Lesson 2 Subtraction Facts Through 12 as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 3 Lesson 2 Subtraction Facts Through 12

Subtract

Write the difference. Use the number line to help.

Question 1.
10 – 3 = 7
Answer:
Subtract 3 from 10 then you get 7.
10 – 3 = 7

Question 2.
11 – 5 = ___
Answer:
Subtract 5 from 11 then you get 6.
11 – 5 = 6

Question 3.
8 – 6 = ___
Answer:
Subtract 6 from 8 then you get 2.
8 – 6 = 2

Question 4.
12 – 1 = ____
Answer:
Subtract 1 from 12 then you get 11.
12 – 1 = 11

Question 5.
10 – 5 = ___
Answer:
Subtract 5 from 10 then you get 5.
10 – 5 = 5

Question 6.
10 – 7 = ___
Answer:
Subtract 7 from 10 then you get 3.
10 – 7 = 3

Question 7.
7 – 2 = ___
Answer:
Subtract 2 from 7 then you get 5.
7 – 2 = 5

Question 8.
11 – 10 = ___
Answer:
Subtract 10 from 11 then you get 1.
11 – 10 = 1

Question 9.
9 – 3 = ___
Answer:
Subtract 3 from 9 then you get 6.
9 – 3 = 6

Question 10.
12 – 8 = ___
Answer:
Subtract 8 from 12 then you get 4.
12 – 8 = 4