McGraw Hill Math Grade 7 Lesson 18.6 Answer Key Volume of a Solid
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McGraw-Hill Math Grade 7 Answer Key Lesson 18.6 Volume of a Solid
Exercises
SOLVE
Question 1.
What is the volume of a cube with sides of 10 inches?

Answer:
Volume of the cube = 1,000 cubic inches.
Explanation:
Sides of the cube = 10 inches.
Volume of the cube = Sides of the cube × Sides of the cube × Sides of the cube
= 10 × 10 × 10
= 100 × 10
= 1,000 cubic inches.
Question 2.
A shoe box has dimensions of 12 inches by 8 inches by 6 inches. How many cubic feet is it?
Answer:
Volume of the show box = 0.33 cubic feet.
Explanation:
Length of the show box = 12 inches.
Width of the show box = 8 inches.
Height of the show box = 6 inches.
Volume of the show box = Length of the show box × Width of the show box × Height of the show box
= 12 × 8 × 6
= 96 × 6
= 576 cubic inches.
Conversion:
1 cubic feet = 1728 cubic inches
?? cubic feet = 576 cubic inches
=> 1 × 576 = 1728 × ??
=> 576 ÷ 1728 = ??
=> 0.33 cubic feet = ??
Question 3.
A rectangular solid with sides of 9 ft by 5 ft by 13 ft has what volume?
Answer:
Volume of the rectangular solid = 585 cubic feet.
Explanation:
Length of the rectangular solid = 13 ft.
Width of the rectangular solid = 9 ft.
Height of the rectangular solid = 5 ft.
Volume of the rectangular solid = Length of the rectangular solid × Width of the rectangular solid × Height of the rectangular solid
= 13 × 9 × 5
= 117 × 5
= 585 cubic feet.
Question 4.
A cube that has sides of 120 inches has how many cubic yards of volume?
Answer:
Volume of the cube = 37.037 cubic yards.
Explanation:
Side of the cube = 120 inches.
Volume of the cube = Side of the cube × Side of the cube × Side of the cube
= 120 × 120 × 120
= 14400 × 120
= 17,28,000 cubic inches.
Conversion:
1 cubic yard = 46,656 cubic inches.
?? cubic yard = 17,28,000 cubic inches.
=> 1 × 17,28,000 = 46,656 × ??
=> 17,28,000 ÷ 46,656 = ??
=> 37.037 cubic yards = ??
Question 5.
A storage container in the form of a rectangular solid has dimensions of 12 inches by 30 inches by 16 inches. If a pound of sugar takes up \(\frac{1}{4}\) sq ft, how many pounds of sugar can you put in the container?
Answer:
Number of pounds of sugar can be put in the container = 23,040.
Explanation:
Length of the rectangular solid = 30 inches.
Width of the rectangular solid = 16 inches.
Height of the rectangular solid = 12 inches.
Volume of the rectangular solid = Length of the rectangular solid × Width of the rectangular solid × Height of the rectangular solid
= 30 × 16 × 12
= 480 × 12
= 5,760 cubic inches.
Area of the pound of sugar = \(\frac{1}{4}\) sq ft.
Number of pounds of sugar can be put in the container = Volume of the rectangular solid ÷ Area of the pound of sugar
= 5,760 ÷ \(\frac{1}{4}\)
= 5,760 × \(\frac{4}{1}\)
= 23,040.
Question 6.
A parking lot measures 420 ft long and 162 ft wide. If a construction company is told that it needs to have 3 feet of asphalt under the parking lot for proper drainage, how many cubic yards do they need to order?
Answer:
Volume of the asphalt under the parking lot for proper drainage required = 7,560 cubic yards.
Explanation:
Length of the parking lot = 420 ft.
Width of the parking lot = 162 ft.
Area of the parking lot = Length of the parking lot × Width of the parking lot
= 420 × 162
= 68,040 square feet.
Length of the asphalt under the parking lot for proper drainage = 3 feet.
Volume of the asphalt under the parking lot for proper drainage required = Area of the parking lot × Length of the asphalt under the parking lot for proper drainage
= 68,040 × 3
= 204,120 cubic feet.
Conversion:
1 cubic yard = 27 cubic feet.
?? cubic yards = 2,04,120 cubic feet.
=> 1 × 2,04,120 = 27 ÷ ??
=> 2,04,120 ÷ 27 = ??
=> 7,560 cubic yards = ??
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