Refer to our Texas Go Math Grade 7 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 7 Unit 5 Study Guide Review Answer Key.

## Texas Go Math Grade 7 Unit 5 Study Guide Review Answer Key

**Applications of Geometry Concepts**

**Essential Question**

How can you apply geometry concepts to solve real-world problems?

Example 1

Find (a) the value of x and (b) the measure of ∠APY.

a. ∠XPB and ∠YPB are supplementary.

3x + 78° = 180°

3x = 102°

x = 34°

b. ∠APY and ∠XPB are vertical angles,

m∠APY = m∠XPB = 3x = 102°

Example 2

Find the area of the composite figure. It consists of a semicircle and a rectangle.

Area of semicircle = o.5(πr^{2})

≈ 0.5(3.14)25

≈ 39.25 cm^{2}

Area of rectangle = lw

= 10(6)

= 60 cm^{2}

The area of the composite figure is approximately 99.25 square centimeters.

**Texas Go Math Grade 7 Unit 5 Exercises** **Answer Key**

Question 1.

Find the value of y and the measure of ∠YPS (Lesson 9.1)

Answer:

Angle on the straight line SPR will be 180° and the ∠YPS and YPR will be supplementary to each other so, the

sum of both angle will be 180°.

∠YPS + ∠YPR = 180°

∠YPS + 140° = 180

∠YPS = 180 – 140

∠YPS = 40°

Also ∠YPS and ∠RPZ are vertically opposite angle so both the angle will be equal in measure.

∠RPZ = ∠YPS

5y = 40°

y = \(\frac{40}{5}\)

y = 8°

∠YPS = 40°

Find the circumference and area of each circle. Round to the nearest hundredth. (Lessons 9.2, 9.3)

Question 2.

Answer:

Given diameter of the circle = 22 inch

Circumference of circle with diameter “D” is = πD

Circumference of circle = 22 . π

= 22 × 3.14 (π = 3.14)

≈ 69 inch

Area of circle with diameter “D” is = \(\frac{\pi D^{2}}{4}\)

Area of circle = \(\frac{\pi \cdot 22^{2}}{4}\)

= \(\frac{3.14 \times 484}{4}\)

≈ 380 inch^{2}

Circumference is 69 inch and area is 380 inch^{2}

Question 3.

Answer:

Given radius of the circle = 4.5 m

Circumference of circle with radius “r” is = 2πr

Circumference of circle = 2π × 4.5

= 9 × 3.14 (π = 3.14)

= 28.26 m

Area of circle with radius “r” is = πr^{2}

Area of circle = π × 45^{2}

= 3.24 × 20.25 (π = 3.14)

= 65.61 m^{2}

Circumference is 28.26 m and area is 65.61 m^{2}.

Find the area of each composite figure. Round to the nearest hundredth if necessary. (Lesson 9.4)

Question 4.

Answer:

Side length of the square = 9 in

Height of the triangle = 9 in

Base of the triangle = 13 – 9 = 4 in

Area of the composite figure will be the sum of area of square and the triangle.

Area of square = side^{2}

= 9^{2} in^{2}

= 81 in^{2}

Area of triangle = \(\frac{1}{2}\) × Base × Height

= \(\frac{1}{2}\) × 4 × 9 in^{2}

= 18 in^{2}

Area of composite figure = Sum of area of square and triangle

= 81 + 18 in^{2}

= 99 in^{2}

Hence, area of the composite figure will be 99 in^{2}.

Area of the composite figure will be 99 in^{2}

Question 5.

Answer:

Length ot the rectangle = 20 cm

Width of the rectangle = 16 cm

Radius of the semi circle = \(\frac{16}{2}\) = 8 cm

Area of the composite figure will be the sum of area of rectangle and the semi circle.

Area of rectangle = Length × width

= 16 × 20 in^{2}

= 320 in^{2}

Area of composite figure = Sum of area of rectangle and semi circle

= 320 + 100.18 cm^{2}

≈ 420 cm^{2}

Hence, area of the composite figure will be 420 cm^{2}.

**Volume and Surface Area**

Example

The height of the figure whose net is shown is 8 feet. Identify the figure. Then find its volume, lateral area, and total surface area.

The figure is a rectangular pyramid.

The volume of the rectangular pyramid is 384 cubic feet, the lateral surface area is 192 square feet, and the total

surface area is 336 square feet.

**Exercises**

Question 1.

Identify the figure represented by the net. Then find its lateral area and total surface area. (Less0n 10.3)

Answer:

The figure represented by the net is a triangular prism.

Lateral area:

One 13 ft. by 10 ft rectangle;

Two 13 ft by 13 ft. rectangles.

1 . (13 . 10) = 130

2 . (13 . 13) = 338

Lateral area: 130 + 338 = 468 ft^{2}.

The base has the shape of triangLe with lenght of 10 ft and height of 15 ft.

Base area:

2 . (\(\frac{1}{2}\) . 10 . 15) = 150 ft^{2}

The total surface area is 468 + 150 = 618 ft^{2}.

Lateral area: 468 ft^{2}.

The total surface area is 618 ft^{2}.

Find the volume of each figure. (Lessons 10.1,10.2)

Question 2.

Answer:

l = 7 in Length of base

w = 5 in Width of base

h = 12 in Height of a prism

Find the area of the base B. A prism has a base that is rectanguar, so use the formula:

B = l . w = 7 . 5 = 35 in^{2}

Use the formula for the volume of a rectangular prism.

V = B . h = 35 . 12 = 420 in^{3}

The volume of a rectangular prism is 420 in^{3}.

Question 3.

Answer:

A pyramid has a base that is right triangle.

a = 4 m Length of one side of the triangle

b = 6 m Length of other side of the triangle

h = 9m Heightofapyramid

Find the area of the base B.

Use the formula.

V = B . h = 12 . 9 = 108 m^{3}

The volume of a triangular pyramid is V = 108 m^{3}.

Question 4.

The volume of a rectangular pyramid is 1.32 cubic inches. The height of the pyramid is 1.1 inches and the length of the base is 1.2 inches. Find the width of the base of the pyramid. (Lesson 10.1) _____

Answer:

V = 1.32 in^{3} The volume of a rectangular pyramid

h = 1.1 in Length of pyramid

1 = 1.2 in Length of base

w = ? Width of base

Use the formula for the volume of a pyramid to find a width of the base.

V = \(\frac{1}{3}\) . l . w . h

1.32 = \(\frac{1}{3}\) . (1.2) . w . (1.1)

1.32 = \(\frac{1}{3}\) . (1.32) . w

Width of the base of the pyramid is w = 3 in

Question 5.

The volume of a triangular prism is 264 cubic feet. The area of a base of the prism is 48 square feet. Find the height of the prism.

(Lesson 10.2) ____

Answer:

V = B . h

B = 48 ft^{2} Base of prism

h =? Height of a prism

V = 264 ft^{3} The volume of a prism

Use the formula for the voume of a prism to find the height of the prism.

V = B . h

264 = 48 . h

Divide both sides by 48.

The height of the prism is h = 5.5 ft.

**Texas Go Math Grade 7 Unit 5 Performance Tasks** **Answer Key**

Question 1.

**Careers In Math Product Design** Engineer Miranda is a product design engineer working for a sporting goods company. She designs a tent in the shape of a triangular prism. The dimensions of the tent are shown in the diagram.

a. Draw a net of the triangular prism and label the dimensions.

Answer:

The net of the given tent which is a triangular prism.

b. How many square feet of material does Miranda need to make the tent (including the floor)? Show your work.

Answer:

Determine the surface area of the tent or the triangular prism:

SA = 3R + 2T

SA = 3(9.5 .8) + 2 (\(\frac{4 \cdot 6}{2}\))

SA = 3(76) + 2(12)

SA = 228 + 24

SA = 252 ft^{2}

c. What is the volume of the tent? Show your work.

Answer:

Determine the volume of the tent or triangular prism.

V = B . h

= \(\frac{4 \cdot 6}{2}\) . 5

= 12 . 9.5

= 114 ft^{3}

d. Suppose Miranda wants to increase the volume of the tent by 10%. The specifications for the height (6 feet) and the width (8 feet) must stay the same. How can Miranda meet this new requirement? Explain.

Answer:

The new volume of the tent is:

1.1V = 1.1 . 114 = 125.4 ft^{3}.

The length of the tent, or the height of the prism h is the parameter being changed, so:

V = B . h

The tent will get longer by 10.45 – 9.5 = 0.95 ft.

Question 2.

Li is making a stand to display a sculpture made in art class. The stand will be 45 centimeters wide, 25 centimeters long, and 1.2 meters high.

a. What is the volume of the stand? Write your answer in cubic centimeters.

Answer:

The stand is in a form of a rectangular prism, whose volume is calculated by

V = length . width . height

Since 1.2 m = 120 cm, the volume of the stand is

V = l . w . h Write the formula for the volume

V = 45. 25. 120 Substitute the values

V = 135,000 cm^{3} Multiply the values

b. Li needs to fill the stand with sand so that it is heavy and stable. Each piece of wood is 1 centimeter thick. The boards are put together as shown in the figure, which is not drawn to scale. How many cubic centimeters of sand does she need to fill the stand? Explain how you found your answer.

Answer:

Determine the volume of the interior of the stand. To obtain that we have to “remove” 2 cm from each dimension,

thus length will be 43 cm, width is 23 cm and height is 118 cm.

V = l . w . h Write the formula for the volume

V = 43 . 23 . 118 Substitute the new values

V = 116, 702 cm^{3} Multiply the values

**Texas Go Math Grade 7 Unit 5 Mixed Review Texas Test Prep** **Answer Key**

**Selected Response**

Question 1.

The dimensions of the pyramid are given in centimeters (cm). What is the volume of the pyramid?

(A) 222.5 cubic centimeters

(B) 330 cubic centimeters

(C) 445 cubic centimeters

(D) 990 cubic centimeters

Answer:

(B) 330 cubic centimeters

Explanation:

h = 11 cm Height of pyramid

l = 9 cm Length of base

w = 10 cm Width of base

Use the formula for the voLume of a rectangular pyramid

V = \(\frac{1}{3}\) . l . w . h

= \(\frac{1}{3}\) . 9 . 10 . 11

= \(\frac{1}{3}\) . 990

= 330 cm^{3}

The volume of the pyramid is 330 cm^{3}

Question 2.

The volume of a triangular pyramid is 437 cubic units. The height of the pyramid is 23 units. What is the area of the base of the pyramid?

(A) 6.3 square units

(B) 19 square units

(C) 38 square units

(D) 57 square units

Answer:

(D) 57 square units

Explanation:

Use formula for the volume of a triangular pyramid.

B = ? Base of pyramid

h = 23units Height of a pyramid

V = 437 cubic units The volume of a pyramid

Use the formula for the volume of a pyramid to find a base area of the pyramid.

V = \(\frac{1}{3}\) . B . h

437 = \(\frac{1}{3}\) . B . 23

437 = (7.66) . B

Divide both sides by 7.66.

The area of the base of a pyramid is 57 square units.

Hot Tip!

Make sure you look at all the answer choices before making your decision. Try substituting each answer choice into the problem if you are unsure of the answer.

Question 3.

What is the lateral surface area of the square pyramid whose net is shown?

(A) 216 square feet

(B) 388 square feet

(C) 568 square feet

(D) 776 square feet

Answer:

(A) 216 square feet

Explanation:

Lateral surface area of square pyramid will be the sum of areas of all the triangles except base in the given figure.

Base of the triangle = 12 ft

Height of the triangle = 9 ft

We know that area of the rectangle is = \(\frac{1}{2}\) × Base × Height

Area of triangle = \(\frac{1}{2}\) × 12 × 9

= 54 ft^{2}

Lateral surface area of pyramid = 4 × Area of triangle

= 4 × 54

= 216 ft^{2}

Hence, lateral surface area is 216 ft^{2} and option A is correct answer

Question 4.

A one-topping pizza costs $15.00. Each additional topping costs $1.25. Let x be the number of additional toppings. You have $20 to spend. Which equation can you solve to find the number of additional toppings you can get on your pizza?

(A) 15x + 1.25 = 20

(B) 1.25x + 15 = 20

(C) 15x – 1.25 = 20

(D) 1.25x – 15 = 20

Answer:

(B) 1.25x + 15 = 20

Explanation:

Given cost of one-topping pizza = $13.00

Cost of additional topping on pizza = $1.25

It is given we have to spend only $20 on pizza. For “x” number of additional topping cost will be 1.25 × x and the cost of one topping pizza will be $13. So the total cost on pizza will he sum of cost. of one-topping pizza and the

additional topping cost which will be equal to $20.

In form of equation : 1.25x + 15 = 20

Hence, option B is correct answer.

Question 5.

A bank offers a home improvement loan with simple interest at an annual rate of 12%. J.T. borrows $ 14,000 over a period of 3 years. How much will he pay back altogether?

(A) $15,680

(B) $17,360

(C) $19,040

(D) $20,720

Answer:

(C) $19,040

Explanation:

Principal amount of home loan (P) = $14. 000

Rate of the simple interest annually (r) = 12%

Duration for which loan is taken (t) = 3 years

We know that simple interest = \(\frac{P \times r \times t}{100}\)

Simple interest = \(\frac{14,000 \times 12 \times 3}{100}\)

= 140 × 36

= $5,040

Total which has to be paid = Principal Simple interest

= 14,000 + 5,040

= $19,040

Hence, option C is correct answer.

Question 6.

What is the volume of a triangular prism that is 75 centimeters long and that has a base with an area of 30 square centimeters?

(A) 2.5 cubic centimeters

(B) 750 cubic centimeters

(C) 1,125 cubic centimeters

(D) 2,250 cubic centimeters

Answer:

(D) 2,250 cubic centimeters

Explanation:

B = 30 cm^{2} Base of prism

h = 75 cm Height of a prism

Use the formula for the volume of the prism.

V = B . h

= 30 . 75

= 2250 cm^{3}

The volume of a triangular prism is 2250 cubic centimeters.

Question 7.

The radius of the circle is given in meters. What is the circumference of the circle? Use 3.14 for π.

(A) 25.12 meters

(B) 50.24 meters

(C) 200.96 meters

(D) 803.84 meters

Answer:

(B) 50.24 meters

Explanation:

Given radius of the circle (r) = 8 m

We know that circumference of circle of radius “r” is = 2πr

Circumference of circle = 2π × 8

= 16π

(π = 3.14)

= 16 × 3.14

= 50.24 meters.

hence, option B is correct answer.

Question 8.

The dimensions of the figure are given in millimeters. What is the area of the two-dimensional figure?

(A) 39 square millimeters

(B) 169 square millimeters

(C) 208 square millimeters

(D) 247 square millimeters

Answer:

(C) 208 square millimeters

Explanation:

The area of the two-dimensional figure has one 13mm. by 13 mm. square and one triangle with length of 13 mm. and height of 6 mm.

The area of the two-dimensional figure is:

(13 . 13) + (\(\frac{1}{2}\) . 13 . 6) = 169 + 39 = 208 mm^{2}

The area of the two-dimensional figure is 208 square millimeters.

Gridded Response

Question 9.

What is the measure in degrees of an angle that is supplementary to a 74° angle?

Answer:

Supplementary angle : supplementary angle means the pair of angle whose sum is 180°.

Given angle in problem: = 74°

Let the other supplementary angle be = x°

x° + 74° = 180°

x = 180° – 74°

r = 106°

Hence, other supplementary angle wilt be 106°

Steps to plot the given box are:

In 1^{st} column : mark ‘+’ sign

In 2^{nd} column : mark “0”

In 3^{rd} column : mark “1”

In 4^{th} column : mark “0”

In 5^{th} column : mark “6”

In 6^{th} column: mark “0”

In 7^{th} column : mark “0”

106°

Question 10.

What is the volume in cubic centimeters of a rectangular prism that has a length of 6.2 centimeters, a width of 3.5 centimeters, and a height of 10 centimeters?

Answer:

Given length of the rectangular prism = 6.2 cm

Given width of the rectangular prism = 3.5 cm

Given height of the rectangular prism = 10 cm

Volume of rectangular prism = length × width × height

Volume of rectangular prism = 6.2 × 3.5 × 10

= 6.2 × 35

= 217 cm^{3}

Hence, volume of the rectangular prism is 217 cm^{3}.

Steps to plot the given box are:

In 1^{st} column : mark ‘+’ sign

In 2^{nd} column : mark “0”

In 3^{rd} column : mark “2”

In 4^{th} column : mark “1”

In 5^{th} column : mark “7”

In 6^{th} column: mark “0”

In 7^{th} column : mark “0”

volume of the rectangular prism is 217 cm^{3}.

Hot Tip!

It is helpful to draw or redraw a figure. Answers to geometry problems may become clearer as you redraw the figure.

Question 11.

What is the area of the circle in square meters? Use 3.14 for π.

Answer:

Given diameter of the circle (D) = 18 m

We know that area of circle of diameter “D” is = \(\frac{\pi D^{2}}{4}\)

hence, option B is correct answer.

Steps to plot the given box are:

In 1^{st} column : mark ‘+’ sign

In 2^{nd} column : mark “0”

In 3^{rd} column : mark “2”

In 4^{th} column : mark “5”

In 5^{th} column : mark “4”

In 6^{th} column: mark “3”

In 7^{th} column : mark “4”

Area of circle is 254.34 m^{2}

**Texas Go Math Grade 7 Unit 5 Vocabulary Preview** **Answer Key**

Use the puzzle to preview key vocabulary from this unit. Unscramble the circled letters to answer the riddle at the bottom of the page.

Question 1.

NEONGTURC LANSEG

Answer:

Question 2.

LEOTECRAYMPMN SEGLAN

Answer:

Question 3.

RIMEUCEEFNRCC

Answer:

Question 4.

LEARATL ERAA

Answer:

Question 5.

PIECOTMOS GUISEFR

Answer:

1. Angles that have the same measure. (Lesson 9.1) .

2. Two angles whose measures have a sum of 90 degrees. (Lesson 9.1)

3. The distance around a circle. (Lesson 9.4)

4. The sum of the areas of the lateral faces of a prism. (Lesson 10.3) .

5. A two dimensional figure made from two or more geometric figures. (Lesson 9.4)

Q: What do you say when you see an empty parrot cage?

A: __ __ __ ___ __ __ ___ !