# Texas Go Math Grade 7 Module 3 Quiz Answer Key

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## Texas Go Math Grade 7 Module 3 Quiz Answer Key

Texas Go Math Grade 7 Module 3 Ready to Go On? Answer Key

3.1 Converting Between Measurement Systems

Convert each measurement.

Question 1.
20 gallons ≈ _______ liters
1 gallon ≈ 3.79 liters.
Write the conversion factor as a ratio: $$\frac{3.79 \text { liters }}{1 \text { gallon }}$$
20 gallons × $$\frac{3.79 \text { liters }}{1 \text { gallon }}$$ ≈ 75.8 liters

Question 2.
36ounces ≈ _______ grams
1 ounce ≈ 27.4 liters.
Write the conversion factor as a ratio: $$\frac{28.4 \text { grams }}{1 \text { ounce }}$$
36 ounces × $$\frac{28.4 \text { grams }}{1 \text { ounce }}$$ ≈ 1022.4 grams

Question 3.
43 yards ≈ ________ meters
1 yard ≈ 0.914 liters.
Write the conversion factor as a ratio: $$\frac{0.914 \text { meter }}{1 \text { yard }}$$
43 yard × $$\frac{0.914 \text { meter }}{1 \text { yard }}$$ ≈ 39.302 meters

Question 4.
5 miles ≈ _________ kilometers
1 mile ≈ 1.61 kilometer.
Write the conversion factor as a ratio: $$\frac{1.61 \text { kilometer }}{1 \text { mile }}$$
5 miles × $$\frac{1.61 \text { kilometer }}{1 \text { mile }}$$ ≈ 8.05 kilometers

3.2 Percent Increase and Decrease

Find the percent change from the first value to the second.

Question 5.
36; 63 ____________________
Find the amount of change.
Amount of Change = Greater Value – Lesser value
= 63 – 36
= 27
Find the percent increase Round to the nearest percent
Percent Change = $$\frac{\text { Amount of Change }}{\text { Original Amount }}$$
= $$\frac{27}{36}$$
= 0.75
= 75%

Question 6.
50; 35 ____________________
Find the amount of change.
Amount of Change = Greater Value – Lesser value
= 50 – 35
= 15
Find the percent decrease Round to the nearest percent
Percent Change = $$\frac{\text { Amount of Change }}{\text { Original Amount }}$$
= $$\frac{15}{50}$$
= 0.3
= 30%

Question 7.
40; 72 __________________
Find the amount of change.
Amount of Change = Greater Value – Lesser value
= 72 – 40
= 32
Find the percent increase Round to the nearest percent
Percent Change = $$\frac{\text { Amount of Change }}{\text { Original Amount }}$$
= $$\frac{32}{72}$$
= 0.4
= 44%

Question 8.
92; 69 ___________________
Find the amount of change.
Amount of Change = Greater Value – Lesser value
= 92 – 69
= 23
Find the percent increase Round to the nearest percent
Percent Change = $$\frac{\text { Amount of Change }}{\text { Original Amount }}$$
= $$\frac{23}{92}$$
= 0.25
= 25%

3.3 Markup and Markdown

Use the original price and the markdown or markup to find the retail price.

Question 9.
Original price: $60; Markup: 15%; Retail price: ___________________ Answer: Markup = 15% = 0.15 Retail price = Original cost + Markup = x + 0.15x = 1.15x = 1.15 ×$60
= $69 Question 10. Original price:$32; Markup: 12.5%; Retail price: ___________________
Markup = 12.5% = 0.125
Retail price = Original cost + Markup
= x + 0.125x
= 1.125x
= 1.125 × $32 =$36

Question 11.
Original price: $50; Markdown: 22%; Retail price: __________________ Answer: Markdown = 22% = 0.22 Retail price = Original cost Markdown = x – 0.22x = 0.78x = 0.78 ×$50
= $39 Question 12. Original price:$125; Markdown: 30%; Retail price: _________________
Markdown = 30% = 0.3
Sale price = Original cost Markdown
= x – 0.3x
= 0.7x
= 0.7 × $125 =$87.5

3.4 Applications of Percent

Question 13.
Mae Ling earns a weekly salary of $325 plus a 6.5% commission on sales at a gift shop. How much would she make in a work week if she sold$4,800 worth of merchandise? __________________________________________
The commision is 6.5%.
Mae Ling earns the sum of her weekly salary and the comission of her sales.
Commision: $4,800 × 0.065 =$312
Total salary: $325 +$312 = $637 She would make$637 in a week.

Question 14.
Ramon earns $1,735 each month and pays$53.10 on electricity. To the nearest tenth of a percent, what percent of Ramon’s earnings are spent on electricity each month? ______________________________________
We have to divide electricity cost by his salary to calculate the percentage of his salary that is spent on electricity
$53.10 ÷$1, 375 ≈ 0.039 × 100% = 3.9%
3.9% of Ramon’s earnings are spent on electricity.

Essential Question

Question 15.
Give three examples of how percents are used in the real-world. Tell whether each situation represents a percent increase or a percent decrease.
First example:
Discount, markdown, sales. Percent decrease.
Second example:
Companies describe their success or faiLure as an increase or decrease in profit levels. Percent increase or decrease.
Third example:
Interest Percent increase,

Texas Go Math Grade 7 Module 3 Mixed Review Texas Test Prep Answer Key

Selected Response

Question 1.
Zalmon walks $$\frac{3}{4}$$ of a mile in $$\frac{3}{10}$$ of an hour. What is his speed in miles per hour?
A. 0.225 miles per hour
B. 2.3 miles per hour
C. 2.5 miles per hour
D. 2.6 miles per hour
C. 2.5 miles per hour

Determine the units of the rate.
The rate is distance in mites per time in hours
Find Julio’s rate of walking in distance walked per time. Question 2.
Shaylyn measured her house as 5 meters tall. Which of these is an equivalentmeasurement?
A. 0.3 miles
B. 16.4 feet
C. 7.3 yards
D. 27.2 inches
B. 16.4 feet

From the given choices. we can rule out A. C. D because we can sec that 5 meters differ from these values in given unit of measure.
Now, we just have to check for B.
1 meter ≈ 3.28 ft
Write the conversion factor as a ratio: $$\frac{3.28 \text { feet }}{1 \text { meter }}$$
5 meters × $$\frac{3.28 \text { feet }}{1 \text { meter }}$$ = 16.4 feet

Question 3.
Find the percent change from 70 to 56.
A. 20% decrease
B. 20% decrease
C. 25% increase
D. 25% increase
A. 20% decrease

Find the amount of change.
Amount of Change = Greater Value – Lesser value
= 70 – 56
= 14
Find the percent decrease Round to the nearest percent
Percent Change = $$\frac{\text { Amount of Change }}{\text { Original Amount }}$$
= $$\frac{14}{70}$$
= 0.2
= 20%

Question 4.
Delia uses 3.5 skeins of yarn to knit one scarf. How many scarves can she complete if she has 19 skeins of yarn?
A. 4 scarves
B. 5 scarves
C. 6 scarves
D. 7 scarves
B. 5 scarves

Let y represent scarves, and x skeins of yarn.
If she need 3.5 skeins of yarn to knit one scarf, then y = $$\frac{x}{3.5}$$
x = 19
y = $$\frac{x}{3.5}$$
y = $$\frac{19}{3.5}$$
y = 5.43
She can make almost 5 and a half scarves, that means she can complete 5 whole scarves.

Question 5.
The rainfall ball two years ago was 10.2 inches. Last year’s total was 20% greater. What was last year’s rainfall total?
A. 8.16 inches
B. 11.22 inches
C. 12.24 inches
D. 20.4 inches
C. 12.24 inches

First, find the amount of change.
10.2 × 0.2 = 2.04
Then, find the new amount of rainfall.
New amount = Original amount + Amount of Change
= 10.2 + 2.04
= 12.24
Last yearns rainfall total was 12.24 inches.

Question 6.
A pair of basketball shoes was originally priced at $80, but was marked up 37.5%. What was the retail price of the shoes? A.$50
B. $83 C.$110
D. $130 Answer: C.$110

Markup = 37.5% = 0.375
Retail price = Original cost – Markup
= s + 0.375s
= 1.375s
= 1.375 × $80 =$110

Question 7.
The day after Halloween, candy was marked down 40%. Which expression represents the new retail price?
A. 0.4p
B. 0.6p
C. 1.4p
D. 1.6p
B. 0.6p

Markdown = 40% = 0.4
Sale price = Original cost Markdown
= p – 0.4p
= 0.6 p

Question 8.
The sales tax rate in Jan’s town is 7.5%. If she buys 3 lamps for $23.59 each and a sofa for$769.99, how much sales tax does she owe?
A. $58.85 B.$63.06
C. $67.26 D.$71.46
B. $63.06 Sales tax rate = 7.5% = 0.075 First, sum up the cost of items, then apply saLes tax rate to see how much sales tax she owes Sum of items = 3 ×$23.59 + $769.99 =$70.77 + $769.99 =$840.76
Sales tax = Sum of items × Sales tax rate
= $840.76 × 0.075 =$63.06

Question 9.
A bank offers an annual simple interest rate of 8% on home improvement loans. How much would Tobias owe if he borrowed $17,000 over a period of 2 years? A.$1,360
B. $2,720 C.$18.360
D. $19,720 Answer: B.$2,720

Find the amount of interest earned in one year. Then calculate the amount of interest for 2 years.
Interest Rate × Initial loan = Interest for 1 year
0.08 × $17000 =$1360
Interest for 1 year × 2 years = Interest for 2 years
$1360 × 2 =$2720
Tobias would owe $2720. Gridded Response Question 10. The granola Summer buys used to cost$6.00 per pound, but it has been marked up 15%. How much in dollars and cents will Summer pay for 2.6 pounds of granola at the new price? Initial, cost of granoLa per pound = $6.00 Percentage increase in cost of granola = 15% New cost of granoLa per pound = 6 × (1 + $$\frac{15}{100}$$) = 6 × 1.15 =$6.9
= $17.94 hence, the cost of 2.6 pounds of granola is$17.94