Texas Go Math Grade 7 Module 10 Quiz Answer Key

Refer to our Texas Go Math Grade 7 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 7 Module 10 Quiz Answer Key.

Texas Go Math Grade 7 Module 10 Quiz Answer Key

Texas Go Math Grade 7 Module 10 Ready to Go On? Answer Key

10.1 Volume of Rectangular Prisms and Pyramids

Find the volume of each figure.

Question 1.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 1
Answer:
l = 11 yd length of base
w = 9 yd Width of base
h = 7 yd Height of a prism
Find the area of the base B. A prism has a base that is rectangular, so use the formula:
B = l.w = 11.9 = 99 yd2
Use the formula for the volume of a rectangular prism.
V = B.h = 99 . 7 = 693 yd3

The volume of a rectangular prism is 693 yd3.

Grade 7 Math Module 10 Answer Key Question 2.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 2
Answer:
l = 12 ft length of base
w = 16 ft Width of base
h = 18 ft Height of a pyramid

Find the area of the base B.

B = l . w = 12 . 16 = 192 ft2
Use the formula for the volume of a rectangular pyramid.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 10
The volume of a rectangular pyramid is 1152 ft3.

The volume of a rectangular pyramid is 1152 ft3.

10.2 Volume of Triangular Prisms and Pyramids

Find the volume of each figure.

Question 3.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 3
Answer:
A prism has a base that is right triangle.
a = 8 cm length of one side of the triangle
b = 17 cm length of other side of the triangle
Find the area of the base B. Use the formula:
Texas Go Math Grade 7 Module 10 Quiz Answer Key 11
B = 68 cm2 Base of prism
h = 40 cm Height of a prism
Use the formula.
V = B . h = 68 . 40 = 2720 cm3
The volume of a triangular prism is 2720 cm3.

Module 10 Form B Module Test Answer Key Question 4.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 4
Answer:
b = 5 m length of base
hB = 15 m height of base
h = 22 m Height of a pyramid
Find the area of the base B. Use the formula:
B = \(\frac{1}{2}\) . b . hB = \(\frac{1}{2}\) . 5 . 15 = 37.5 m2
Use the formula for the voLume of a triangular pyramid:
V = \(\frac{1}{3}\)B . h = \(\frac{1}{3}\) . (37.5) . 22 = 275 m3
The volume of a triangular pyramid is 275 m3.

10.3 Lateral and Total Surface Area

Find the lateral and total surface area of each figure using its net.

Question 5.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 5
Answer:
Find the Lateral area of the triangular pyramid.
We have three triangles with base of 19.2 m. and height of 40 m.
b = 19.2 m length of base
hB = 40 m Height of base
Lateral area:
Texas Go Math Grade 7 Module 10 Quiz Answer Key 12
For the area of the base:
b = 24 m length of base
hb = 15 m Height of base
The area of the base is
Texas Go Math Grade 7 Module 10 Quiz Answer Key 13
The total surface area is 1152 + 180 = 1332 m2

The Lateral area is 1152 m2.
The total surface area is 1332 m2.

Module 10 Quiz Ready To Go On Answers 7th Grade Question 6.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 6
Answer:
Find the Lateral area of the rectangular prism.
We have:
Two 12 in. by 6 in. rectangle;
Two 10 in. by 6 in. rectangle;
2 . (12 . 6) = 144
2 . (10 . 6) = 120
Lateral area: 144 + 120 = 264 cm2
Each base is 12 in. by 10 in.
2 . (12 . 10) = 2 . 120 = 240 cm2
The total surface area is 264 + 240 = 504 cm2.

The Lateral area is 264 cm.
The total surface area is 504 cm2.

Essential Question

Question 7.
How can you use volume and surface area to solve real-world problems?
Answer:
Volume and surface area can be used in many ways to solve the real-world problems such as:
For example we are making a new thing of copper and we know the volume of that thing so we can know the exact amount of copper required for making that thing by using the density = \(\begin{gathered}
\text { Mass } \\
\hline \text { Volume }
\end{gathered}\)of copper

In another example suppose a wall is to be painted and the cost of paint one square meter of wall is given then we can easily calculate the total cost for painting wall by using the total surface area of wall.

Volume can be use for calculating amount of material required for making something.

Texas Go Math Grade 7 Module 10 Mixed Review Texas Test Prep Answer Key 

Selected Response

Question 1.
The volume of a triangular pyramid is 232 cubic units. The area of the base of the pyramid is 29 square units. What is the height of the pyramid?
(A) 8 units
(B) 12 units
(C) 16 units
(D) 24 units
Answer:
(D) 24 units

Explanation:
Use formula for the volume of a triangular pyramid.
B = 29 square units Base of pyramid
h = ? Height of a pyramid
V = 232 cubic units The volume of a pyramid
Use the formula for the volume of a pyramid to find a height of the pyramid.
V = \(\frac{1}{3}\) . B . h.
232 = \(\frac{1}{3}\) . 29 . h
232 = (9.66) . h
Divide both sides by 9.66.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 14
The height of the pyramid is 24 units

Question 2.
What is the volume of a rectangular prism that has a length of 8.5 centimeters (cm), a width of 3.2 centimeters, and a height of 6 centimeters?
(A) 19.2 cm3
(B) 27.2 cm3
(C) 51 cm3
(D) 163.2 cm3
Answer:
(D) 163.2 cm3

Explanation:
h = 6 cm Height of prism
l = 8.5 cm Length of base
w = 3.2 cm Width of base
Use the formula for the volume of a rectangular prism
V = B . h = l . w . h
= (8.5) (3.2) . h
= (27.2) . 6
= 163.2 cm3
The volume of a rectangular prism is V = 163.2 cm3

Question 3.
What is the volume of the rectangular pyramid shown?
Texas Go Math Grade 7 Module 10 Quiz Answer Key 7
(A) 1,650 yd3
(B) 2,200 yd3
(C) 3,300 yd3
(D) 6,600 yd3
Answer:
h = 22 yd Height of pyramid
l = 15 yd Length of base
w = 20 yd Width of base
Use the formula for the volume of a rectangular pyramid.
V = \(\frac{1}{3}\) . B . h. = \(\frac{1}{3}\) . l . w . h.
= \(\frac{1}{3}\) . 15 . 20 . 22
= 2200 yd3

The volume of the rectangular pyramid is V = 2200 yd3.

Module 10 Volume Quiz Answer Key Question 4.
A circle has a circumference of 56π centimeters (cm). What is the radius of the circle?
(A) 28 cm
(B) 56 cm
(C) 88 cm
(D) 112 cm
Answer:
(A) 28 cm

Explanation:
Given circumference of circle in probem = 56π cm
We know that circumference of circle of radius “r” = 2π . r
2π . r = 56π (By using above formula)
r = \(\frac{56 \pi}{2 \pi}\) (Dividing both side by 2π)
r = 28 cm (Simplifying)
hence, option A is correct answer.

Question 5.
What is the volume of a triangular prism that has a height of 45 meters and has a base with an area of 20 square meters?
(A) 225 m3
(B) 300 m3
(C) 450 m3
(D) 900 m3
Answer:
(D) 900 m3

Explanation:
h = 45 m Height of a prism
B = 20 m2 Base area
Use the formula for the volume of a triangular prism.
V = B . h
= 20 . 45
= 900 m3

The volume of a triangular prism is V = 900 m3.

Question 6.
What is the total surface area of the square pyramid whose net is shown?
Texas Go Math Grade 7 Module 10 Quiz Answer Key 8
(A) 256 in2
(B) 336 in2
(C) 576 in2
(D) 896 in2
Answer:
(C) 576 in2

Explanation:
For lateral area:
There are four triangles with base of 16 in. and height of 10 in.
Texas Go Math Grade 7 Module 10 Quiz Answer Key 15
Lateral area: 320 in2
The base has the shape of 16 in. by 16 in. rectangle.
Base area:
1 (16 . 16) = 256 in2
The total surface area is 320 + 256 = 576 in2

The surface area is 576 in2.

Gridded Response

Volume and Surface Area Quiz Answers Module 10 Question 7.
What is the lateral area in square meters of the prism?
Texas Go Math Grade 7 Module 10 Quiz Answer Key 16
Answer:
Lateral area of the prism will be the sum of areas of all the surface except base in the given figure.
Length of the rectangle = 18 in
Breadth of the rectangle = 10 m
Base of the triangle = 12 in
Height of the triangle = 8 in
We know that area of the rectangle is = Length × Breadth
We know that area of the triangle is = \(\frac{1}{2}\) × Base × Height
Area of rectangle = 18 × 10 m2
= 180 m2
Area of triangle = \(\frac{1}{2}\) × 12 × 8 m2
= 48 m2

Lateral area of prism = 2 × Area of rectangle + 2 × Area of triangle
= (2 × 180) + (2 × 48)
= 360 + 96
= 456 m2

Hence, lateral area of the prism is 456 m2

Steps to plot the given box are:
In 1st column : mark “+” sign
In 2nd column : mark “0”
In 3rd coumn: mark “4”
In 4th column : mark “5”
In 5th column : mark “6”
In 6th column : mark “0”
In 7th column : mark “0”

Lateral area of the prism is 456 m2

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