# Texas Go Math Grade 7 Module 10 Answer Key Volume and Surface Area

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## Texas Go Math Grade 7 Module 10 Answer Key Volume and Surface Area

Essential Question
How can you use volume and surface area to solve real-world problems?

Complete these exercises to review skills you will need for this chapter.

Write a Mixed Number as an Improper Fraction

Example

Write each mixed number as an improper fraction.

1$$\frac{9}{10}$$ ____
Write mixed number as sum of one and his fraction.
1$$\frac{9}{10}$$ = 1 + $$\frac{9}{10}$$
centering Write one as
1 + $$\frac{9}{10}$$ = $$\frac{10}{10}$$ + $$\frac{9}{10}$$
For a sum of this two fractions: Denominator is the same for this two fractions so rewrite it. Numerator is a sum of
both numerators.
$$\frac{10}{10}$$ + $$\frac{9}{10}$$ = $$\frac{10+9}{10}$$ = $$\frac{19}{10}$$

Question 2.
2$$\frac{3}{4}$$ ____
Write mixed number as a sum of ones and his fraction.
2$$\frac{3}{4}$$ = 1 + 1 + $$\frac{3}{4}$$
centering Write one like $$\frac{4}{4}$$
1 + 1 + $$\frac{3}{4}$$ = $$\frac{4}{4}$$ + $$\frac{4}{4}$$ + $$\frac{3}{4}$$
Denominator is the same of this four fractions so rewrite it. Numerator is a sum of numerators of this four fractions.
$$\frac{4}{4}$$ + $$\frac{4}{4}$$ + $$\frac{3}{4}$$ = $$\frac{4+4+3}{4}$$
= $$\frac{11}{4}$$

Question 3.
4$$\frac{1}{6}$$ ____
Write mixed number as sum of ones and his fraction
4$$\frac{1}{6}$$ = 1 + 1 + 1 + 1 + $$\frac{1}{6}$$
centering Write one like $$\frac{6}{6}$$.
1 + 1 + 1 + 1 + $$\frac{1}{6}$$ = $$\frac{6}{6}$$ + $$\frac{6}{6}$$ + $$\frac{6}{6}$$ + $$\frac{6}{6}$$ + $$\frac{1}{6}$$
Denominator is the same for this five fractions so rewrite it Numerator is a sum of numerators for this five fractions.
$$\frac{6}{6}$$ + $$\frac{6}{6}$$ + $$\frac{6}{6}$$ + $$\frac{6}{6}$$ + $$\frac{1}{6}$$ = $$\frac{6+6+6+6+1}{6}$$
= $$\frac{25}{6}$$

Module 10 Form A Module Test Answer Key Question 4.
7$$\frac{2}{9}$$ ____
Mixed number write like sum of ones and his fraction

Use Repeated Multiplication

Find each product.

Question 5.
8 Ã— 8 Ã— 8

centering Find a product of two numbers on the box
8 . 8 = 64
centering Multiply the result by the third number
64 . 8 = 512

Question 6.
5 Ã— 5 Ã— 5

centering Multiply the first two numbers.
5 . 5 = 25
centering Multiply the result by the third number
25 . 5 = 125

Surface Area Texas Module 10 Go Math Question 7.
5.1 Ã— 5.1 Ã— 5.1
Multiply the first two numbers

Multiply the result by the third number.

132.651 â‰ˆ 132.7

Question 8.
4 Ã— 4 Ã— 4 Ã— 4

centering Find a product of two number on the box.
4 . 4 = 16
centering Multiply the result by the third number
16 . 4 = 64

Multiply Fractions

Multiply. Write each product in simplest form.

Question 9.
$$\frac{1}{2}$$ Ã— $$\frac{1}{3}$$
Multiply numerator with numerator and denominator with denominator.
$$\frac{1}{2}$$ . $$\frac{1}{3}$$ = $$\frac{1 \cdot 1}{2 \cdot 3}$$
= $$\frac{1}{6}$$

Question 10.
$$\frac{3}{4}$$ Ã— $$\frac{5}{6}$$
Multiply numerator with numerator and denominator with denominator.

Module 10 Form B Module Test Answer Key Question 11.
$$\frac{9}{10}$$ Ã— $$\frac{15}{16}$$
Multiply numerator with numerator and denominator with denominator.

Question 12.
$$\frac{2}{5}$$ Ã— $$\frac{5}{12}$$
Multiply numerator with numerator and denominator with denominator.

Question 13.
$$\frac{4}{7}$$ Ã— $$\frac{3}{16}$$
Multiply numerator with numerator and denominator with denominator.

Question 14.
$$\frac{5}{12}$$ Ã— $$\frac{3}{20}$$
Multiply numerator with numerator and denominator with denominator.

Question 15.
$$\frac{3}{8}$$ Ã— $$\frac{3}{5}$$
Multiply numerator with numerator and denominator with denominator
$$\frac{3}{8}$$ . $$\frac{3}{5}$$ = $$\frac{3 \cdot 3}{8 \cdot 5}$$
= $$\frac{9}{40}$$

$$\frac{5}{9}$$ Ã— $$\frac{7}{10}$$
Multiply numerator with numerator and denominator with denominator.

Visualize Vocabulary
Use the âœ“â€™ words to complete the graphic. You will put one word in each oval.

Understand Vocabulary

Match the term on the left to the correct expression on the right.