Refer to our Texas Go Math Grade 8 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 8 Module 11 Quiz Answer Key.

11.1 Equations with the Variable on Both Sides

Solve.

Question 1.
4a – 4 = 8 + a ____________
4a – 4 = 8 + a
(Subtract a from both sides.) 4a – 4 – a = 8 + a – a
(Add 4 to both sides.) 3a – 4 = 8
(Divide both sides by 3.) 3a = 12
a = 4
The statement is true. There is one solution.

Question 2.
4x + 5 = x + 8 ___________
4x + 5 = x + 8
(Subtract x from both sides) 4x + 5 – x = x + 8 – x
(Subtract 5 from both sides.) 3x + 5 = 8
(Divide both sides by 3.) 3x = 3
x = 1
The statement is true. There is one solution.

Question 3.
Hue is arranging chairs. She can form 6 rows of a given length with 3 chairs left over, or 8 rows of that same length if she gets 11 more chairs. Write and solve an equation to find how many chairs are in that row length.
(Write an equation) 6x + 3 = 8x – 11
(Subtract 3 from both sides.) 6x + 3 – 3 = 8x – 11 – 3
(Subtract 8x from both sides.) 6x = 8x – 14
(Divide by -2.)  – 2x = -14
x = 7
There are 7 chairs in each row.

11.2 Equations with Rational Numbers

Solve.

Question 4.
$$\frac{2}{3}$$s – $$\frac{2}{3}$$ = $$\frac{s}{6}$$ + $$\frac{4}{3}$$ ____________
(Multiply both sides by the LCM(3, 6) = 6) $$\frac{2}{3}$$s – $$\frac{2}{3}$$ = $$\frac{s}{6}$$ + $$\frac{4}{3}$$
6 ∙ $$\frac{2}{3}$$s – 6 ∙ $$\frac{2}{3}$$ = 6 ∙ $$\frac{s}{6}$$ + 6 ∙ $$\frac{4}{3}$$
4s – 4 = n + 8
(Add 4 to both sides) 4s – 4 + 4 = s + 8 + 4
4s = s + 12
(Subtract n from both sides) 4s – s = s + 12 – s
3s = 12
(Divide both sides by 3) $$\frac{3s}{3}$$ = $$\frac{12}{3}$$
s = 4

Question 5.
1.5d + 3.25 = 1 + 2.25d _____________
1.5d + 3.25 = 1 + 2.25d
(Subtract 3.25 from both sides) 1.5d + 3.25 – 3.25 = 1 + 2.25d – 3.25
1.5d = 2.25d – 2.25
(Subtract 2.25d from both sides.) 1.5d – 2.25d = 2.25d – 2.25 – 2.25d
-0.75d = -2.25
(Divide both sides by -0.75) $$\frac{-0.75d}{-0.75}$$ = $$\frac{-2.25}{-0.75}$$
d = 3

Question 6.
Happy Paws charges $19.00 plus$1.50 per hour to keep a dog during the day. Woof Watchers charges $15.00 plus$2.75 per hour. Write and solve an equation to find for how many hours the total cost of the services is equal.
Happy Paws charge for x hours
1.5x + 19
Woof Watchers charge for x hours
2.75x + 15
Put two expressions as equal
2.75x + 15 = 1.5x + 19
Subtract 1.5 from both sides
2.75x + 15 – 1.5x = 1.5x + 19 – 1.5x
1.25x + 15 = 19
Subtract 15 from both sides
1.25x + 15 – 15 = 19 – 15
1.25x = 4
Divide both sides by 1.25
x = $$\frac{4}{1.25}$$ = 3.2
The total cost of the services is equal after $3.2 hrs. 11.3 inequalities with the Variable on Both Sides Question 7. Write an inequality to represent the relationship “Two less than 2 times a number is greater than the number plus 64″. Then solve your inequality. Answer: 11.4 Inequalities with Rational Numbers Question 8. One prepaid cell phone company charges$0.028 per minute and a $3 monthly fee. Another company charges$0.034 per minute with no monthly fee. For what numbers of minutes per month are the charges for the first company cheaper?

Essential Question

Question 9.
How can you use equations with the variable on both sides to solve real-world problems?

Texas Go Math Grade 8 Module 11 Mixed Review Texas Test Prep Answer Key

Selected Response

Question 1.
Two cars are traveling in the same direction. The first car is going 40 mi/h and the second car is going 55 mi/h. The first car left 3 hours before the second car. Which equation could you solve to find how many hours it will take for the second car to catch up to the first car?
(A) 55t + 3 = 40t
(B) 55t + 165 = 40t
(C) 40t + 3 = 55t
(D) 40t + 120 = 55t
(D) 40t + 120 = 55t

Explanation:
We write an expression representing the distance that car A has traveled. Let’s denote the time by t.
3 * 40 + 40t = 120 + 40t
We write an expression representing the distance that car B has traveled. Let’s denote the time by t
55t
We write an equation that can be solved to find the time it will take for the second car to catch up to the first car.
40t + 120 = 55t

Question 2.
A wide screen television display measures approximately 15 inches high and 27 inches wide. A television is advertised by giving the approximate length of the diagonal of its screen. How should the television be advertised?
(A) 36 inches
(B) 31 inches
(C) 30 inches
(D) 21 inches

Question 3.
Shawn’s Rentals charges $27.50 per hour to rent a surfboard and a wet suit. Darla’s Surf Shop charges$23.25 per hour to rent a surfboard plus $17 extra for a wetsuit. For what total number of hours are the charges for Shawn’s Rentals the same as the charges for Darla’s Surf Shop? (A) 3 (B) 4 (C) 5 (D) 6 Answer: (B) 4 Explanation: Shawn’s rentaL charge after x hrs 27.5x Darlas surf shop charge after x hr 23.25x + 17 Equate the two expressions 23.25x + 17 = 27.5x Subtract 23.25x from both sides 23.25x + 17 – 23.25x = 27.5x – 23.25x 4.25x = 17 Divide both sides by 4.25 x = $$\frac{17}{4.25}$$ = 4 The charge would be equal after$4 hrs.

Question 4.
Which of the following is an irrational number?
(A) -8
(B) 4.63
(C) $$\sqrt{11}$$
(D) $$\frac{1}{3}$$
(C) $$\sqrt{11}$$

Explanation:
$$\sqrt{11}$$ is irrational.

Question 5.
Carlos has at least as many action figures in his collection as Josh. Carlos has 5 complete sets plus 4 individual figures. Josh has 3 complete sets plus 14 individual figures. Which inequality represents how many action figures can be in a complete set?
(A) x ≥ 7
(B) x ≤ 7
(C) x ≥ 5
(D) x ≤ 5

Question 6.
Which inequality represents the solution to 1,25x + 2.5 < 2.75x – 6.5?
(A) x > 6
(B) x < 6
(C) x > 2.25
(D) x < 2.25 