Texas Go Math Grade 7 Module 9 Quiz Answer Key

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Texas Go Math Grade 7 Module 9 Quiz Answer Key

Texas Go Math Grade 7 Module 9 Ready to Go On? Answer Key

9.1 Angle Relationships

Use the diagram to name a pair of each type of angle.

Question 1.
Supplementary angles _____
Answer:
∠DFC and ∠BFC

Go Math Module 9 Answer Key Module 9 Test Question 2.
Complementary angles. _____
Answer:
∠AFB and ∠BFC

Question 3.
Vertical angles. _____
Answer:
∠EFD and ∠BFC

9.2, 9.3 Finding Circumference and Area of Circles

Find the circumference and area of each circle. Use 3.14 for π.

Question 4.
Circumference ≈ _____
Answer:
d = 36 cm
Use the formula for the circumference of the circle when given diameter
C = π(d) Substitute 36 for d, and 3.14 for π.
C ≈ 3.14(36)
C ≈ 113.04
The circumference of the circle is 113.04 cm
C ≈ 113.04 cm

Question 5.
area ≈ ___
Answer:
Use the formula for the area of the circle.
Since the diameter is twice a radius, the formula for area of a circle, when given the diameter, is
A = π\(\left(\frac{d}{2}\right)^{2}\) Substitute 36 for d, and 3.14 for π.
A ≈ 3.14 . \(\left(\frac{36}{4}\right)^{2}\)
A ≈ 3.14 18²
A ≈ 3.14 . 324
A ≈ 1017.36
The area of the circle is about 1017.36 cm².

A ≈ 1017.36 cm²

Question 6.
Circumference ≈ _____
Answer:
The radius of the circle is 7 m.
Use the formula for the circumference of the circle.
C = 2π(r) Substitute 7 for r, and \(\frac{22}{7}\) for π.

The circumference is about 44 m.

C ≈ 44

Grade 7 Math Module Answer Key Pdf Circles Question 7.
area ≈ ___
Answer:
Use the formula for the area of the circle
A = Substitute 7 for r, and 314 for w.
A ≈ 3.14(7)²
A ≈ 3.14 49
A ≈ 153.86
The area of the circle is about 153.86 m²

A ≈ 153.86 m².

9.4 Area of Composite Figures

Find the area of each figure. Use 3.14 for π.

Question 8.

Answer:
Separate the figure into a triangle and one semicircle.
Area of the triangle
base = 14 m
height = 10 m
Use the formula for the area of the triangle.
A₁ = \(\frac{1}{2} b \cdot h\)
A₁ = \(\frac{1}{2} 14 \cdot 10\)
A₁ = \(\frac{70}{2}\)
A₁ = 35
The area of the triangle is 35 m₂.

Area of the circle
diameter = 14 m
Use the formula for the area of the circle when given the diameter
A_c = \(\pi\left(\frac{d}{2}\right)^{2}\) Subsitute 14 for d and 3.14 for π.
A_c = 3.14\(\left(\frac{14}{2}\right)^{2}\)
A_c = 3.14 . 7²
A_c = 3.14 . 49
A_c = 153.86
Area of the semicircle is half the area of the circle.
A₂ = \(\frac{A_{c}}{2}\) = \(\frac{153.86}{2}\) = 76.93
The area of the semicircle is 76.93 m².
Add the areas to find the total area.
A = A₁ + A₂ = 35 + 76.93 = 111.93
The area of the figure is 111.93 m².

Quiz for Grade 7 Math Module 9 Question 9.

Answer:
Separate the figure into a rectangle and a parallelogram.
Area of the rectangle
length = 20 cm
width = 5.5 cm
Use the formula for the area of the rectangle.
A₁ = l . w
A₁ = 20 . 5.5
A₁ = 110
The area of the rectangle is 110 cm².
Area of the parallelogram
b = 20 cm
h = 4.5 cm
Use the formula for the area of the parallelogram.
A₂ = b . h
A₂ = 20 . 4.5
A₂ = 90
The area of the parallelogram is 90 cm²

Add the areas to find the total area.
A = A¹ + A² = 110 + 90 = 200
The area of the figure is 200 cm².

Essential Question

Question 10.
How can you use geometric formulas in real-world situations?
Answer:
There are times that we need to determine the area perimeter or volume of a certain object or even a place and
the only given is the dimensions, the geometric formulas are very helpful in such a way that we can calculate it by ourselves.

The geometric formulas are very helpful.

Texas Go Math Grade 7 Module 9 Mixed Review Texas Test Prep Answer Key 

Selected Response

Use the diagram for Exercises 1-3.

Question 1.
What is the measure of ∠BFC?
(A) 18°
(B) 72°
(C) 108°
(D) 144°
Answer:
(C) 108°

Explanation:
∠AFB and ∠BFC are supplement angles, hence
∠AFB + ∠BFC = 180° Substitute 72° for ∠AFB
72° + ∠BFC = 180° Subtract 72° from both sides.
∠BFC = 180° – 72°
∠BFC = 108°

Math Quiz for Grade 7 Module 9 Test Question 2.
Which describes the relationship between ∠BFA and ∠CFD?
(A) adjacent angles
(B) complementary angles
(C) supplementary angles
(D) vertical angles
Answer:
(D) vertical angles

Question 3.
Which information would allow you to identify ∠BFA and ∠AFE as complementary angles?
(A) m∠AFE = 108°
(B) ∠DFE is a right angle.
(C) ∠BFA and ∠BFC are supplementary angles.
(D) ∠BFA and ∠BFC are adjacent angles.
Answer:
(B) ∠DFE is a right angle.

Explanation:
∠DFE is a right angle, as we see in the diagram.

Question 4.
David pays $7 per day to park his car. He uses a debit card each time. By what amount does his bank account change due to parking charges over a 40-day period?
(A) -$280
(B) -$47
(C) $47
(D) $280
Answer:
(A) -$280

Explanation:
David pays $7 each day for 40 days, so amount on his bank account decreases for $7 . 40 = $280.

Question 5.
What is the circumference of the circle? Use 3.14 for π.

(A) 34.54 m
(B) 69.08 m
(C) 379.94 m
(D) 1,519.76 m
Answer:
(B) 69.08 m

Explanation:
r = 11 m
Use the formula for circumference.
C = 2πr(r) Substitute 11 for r and 314 for π
C ≈ 2 3.14 . 11
C ≈ 69.08
The circumference of the circle is 69.08 m.

7th Grade Module 9 Quiz Answers Question 6.
What is the area of the circle? Use 3.14 for π.

(A) 23.55 m²
(B) 176.625 m²
(C) 47.1 m²
(D) 706.5 m²
Answer:
(B) 176.625 m²

Explanation:
d = 15m
Use the formula for the area of the circle.
A = πr²
Since the diameter is twice a radius, the formula for area of a circle, when given the diameter, is
A = π(r)² Substitute \(\frac{d}{2}\) for r.
A = \(\pi\left(\frac{d}{2}\right)^{2}\) Substitute 15 for d, and 3.14 for π.
A ≈ 3.14 . \(\left(\frac{15}{2}\right)^{2}\)
A ≈ 3.14 . (7.5)²
A ≈ 3.14 . 56.25
A ≈ 176.62
The area of the circle is about 176.62 m².

Gridded Response

Grade 7 Math Module 9 Answer Key Question 7.
Find the area in square meters of the figure below. Use 3.14 for π.

Answer:
Separate the figure into a square and a quarter of circle.
Area of the square
side = 6 m
Use the formula for the area of the square
A₁ = 8²
A₁ = 6²
A₁ = 36
The area of the square is 36 m².
To find the area of the quarter of a circle, find the area of the circle and divide it by 4.
Area of the circle
radius = 6 m
Use the formula for the area of the circle when given a radius.
A_c = πr² Substitute 10 for r and 314 for w.
A_c = 3.14(6)²
A_c = 3.14 . 36
A_c = 113.04
A₂ = \(\frac{A_{c}}{4}\) = \(\frac{113}{404}\) = 28.26
The area of the quarter of the circle is 28.26 m².
Add the areas to find the total area.
A = A₁ + A₂ = 36 + 28.26 = 64.26
The area of the figure is 64.26 m².