Texas Go Math Grade 7 Module 6 Answer Key Theoretical Probability and Simulations

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Texas Go Math Grade 7 Module 6 Answer Key Theoretical Probability and Simulations

Texas Go Math Grade 7 Module 6 Are You Ready? Answer Key

Write each fraction as a decimal and a percent.

Question 1.
\(\frac{3}{4}\) ____________
Answer:
Divide 3 by 4. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 5
The result is 0.75.
Move the decimal point two places to the right and add the “%” sign.
0.75 = 75%
\(\frac{3}{4}\) = 75%

Go Math Grade 7 Module 6 Answer Key Question 2.
\(\frac{2}{5}\) ____________
Answer:
Divide 2 by 5. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 6
The result is 0.40.
Move the decimal point two places to the right and add the “%” sign.
0.40 = 40%
\(\frac{2}{5}\) = 40%

Question 3.
\(\frac{9}{10}\) ____________
Answer:
Divide 9 by 10. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 7
The result is 0.90.
Move the decimal point two places to the right and add the “%” sign.
0.90 = 90%
\(\frac{9}{10}\) = 90%

Question 4.
\(\frac{7}{20}\) ____________
Answer:
Divide 7 by 20. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 8
The result is 0.35.
Move the decimal point two places to the right and add the “%” sign.
0.35 = 35%
\(\frac{7}{20}\) = 35%

Grade 7 Go Math Module 6 Answer Key Question 5.
\(\frac{7}{8}\) ____________
Answer:
Divide 7 by 8. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 9
The result is 0.875.
Move the decimal point two places to the right and add the “%” sign.
0.875 = 87.5%
\(\frac{7}{8}\) = 87.5%

Question 6.
\(\frac{1}{20}\) ____________
Answer:
Divide 1 by 20. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 10
The result is 0.05.
Move the decimal point two places to the right and add the “%” sign.
0.05 = 5%
\(\frac{1}{20}\) = 5%

Question 7.
\(\frac{19}{25}\) ____________
Answer:
Divide 19 by 25. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 11
The result is 0.76.
Move the decimal point two places to the right and add the “%” sign.
0.76 = 76%
\(\frac{19}{25}\) = 76%

Question 8.
\(\frac{23}{50}\) ____________
Answer:
Divide 23 by 50. Write a decimal point and insert extra zeros in the dividend.
Texas Go Math Grade 7 Module 6 Answer Key 12
The result is 0.46.
Move the decimal point two places to the right and add the “%” sign.
0.46 = 46%
\(\frac{23}{50}\) = 46%

Find each difference.

Question 9.
1 – \(\frac{1}{5}\) ___________
Answer:
1 – \(\frac{1}{5}\) = \(\frac{5}{5}\) – \(\frac{1}{5}\) Write 1 as \(\frac{5}{5}\).
= \(\frac{5-1}{5}\) Subtract the numerators.
= \(\frac{4}{5}\)

Question 10.
1 – \(\frac{2}{9}\) ___________
Answer:
1 – \(\frac{2}{9}\) = \(\frac{9}{9}\) – \(\frac{2}{9}\) Write 1 as \(\frac{9}{9}\).
= \(\frac{9-2}{9}\) Subtract the numerators.
= \(\frac{7}{9}\)

Grade 7 Module 6 Answer Key Go Math Question 11.
1 – \(\frac{8}{13}\) ___________
Answer:
1 – \(\frac{8}{13}\) = \(\frac{13}{13}\) – \(\frac{8}{13}\) Write 1 as \(\frac{13}{13}\).
= \(\frac{13-8}{13}\) Subtract the numerators.
= \(\frac{5}{13}\)

Question 12.
1 – \(\frac{3}{20}\) ___________
Answer:
1 – \(\frac{3}{20}\) = \(\frac{20}{20}\) – \(\frac{3}{20}\) Write 1 as \(\frac{20}{20}\).
= \(\frac{20-3}{20}\) Subtract the numerators.
= \(\frac{17}{20}\)

Multiply. Write each product in simplest form.

Grade 7 Module 6 Answer Key Go Math Question 13.
\(\frac{8}{15}\) × \(\frac{5}{8}\) ___________
Answer:
\(\frac{8}{15}\) × \(\frac{5}{8}\) = \(\frac{8}{15}\) × \(\frac{5}{8}\) Divide numerators and denominators by the common factors.
= \(\frac{1}{3}\) × \(\frac{1}{1}\)
= \(\frac{1 \cdot 1}{3 \cdot 1}\)
= \(\frac{1}{3}\)

Question 14.
\(\frac{2}{9}\) × \(\frac{3}{4}\) ___________
Answer:
\(\frac{2}{9}\) × \(\frac{3}{4}\) = \(\frac{2}{9}\) × \(\frac{3}{4}\) Divide numerators and denominators by the common factors.
= \(\frac{1}{3}\) × \(\frac{1}{2}\)
= \(\frac{1 \cdot 1}{3 \cdot 2}\)
= \(\frac{1}{6}\)

Question 15.
\(\frac{9}{16}\) × \(\frac{12}{13}\) ___________
Answer:
\(\frac{9}{16}\) × \(\frac{12}{13}\) = \(\frac{9}{16}\) × \(\frac{12}{13}\) Divide numerators and denominators by the common factors.
= \(\frac{9}{4}\) × \(\frac{3}{13}\)
= \(\frac{9 \cdot 3}{4 \cdot 13}\)
= \(\frac{27}{52}\)

Module 6 Answer Key Go Math Grade 7 Question 16.
\(\frac{7}{10}\) × \(\frac{5}{28}\) ___________
Answer:
\(\frac{7}{10}\) × \(\frac{5}{28}\) = \(\frac{7}{10}\) × \(\frac{5}{28}\) Divide numerators and denominators by the common factors.
= \(\frac{1}{2}\) × \(\frac{1}{4}\)
= \(\frac{1 \cdot 1}{2 \cdot 4}\)
= \(\frac{1}{8}\)

Texas Go Math Grade 7 Module 6 Reading Start-Up Answer Key

Visualize Vocabulary

Use the ✓ words to complete the graphic.

Texas Go Math Grade 7 Module 6 Answer Key 1
Texas Go Math Grade 7 Module 6 Answer Key 2

Understand Vocabulary

Match the term on the left to the correct expression on the right.
Texas Go Math Grade 7 Module 6 Answer Key 3
Answer:
1. Compound event – an event made of two or more simple events.

2. Theoretical probability – the ratio of the number of equally likely outcomes in an event to the total number of possible outcomes.

3. Complement – the set of all outcomes that are not the desired event.

Active Reading
Two-Panel Flip Chart Create a two-panel flip chart, to help you understand the concepts in this module. Label one flap “Simple Events and the other flap “Compound Events’ As you study each lesson, write important ideas under the appropriate flap. Include information that will help you remember the concepts later when you look back at your notes.
Texas Go Math Grade 7 Module 6 Answer Key 4

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