Refer to ourÂ Texas Go Math Grade 7 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 7 Module 6 Answer Key Theoretical Probability and Simulations.

## Texas Go Math Grade 7 Module 6 Answer Key Theoretical Probability and Simulations

**Texas Go Math Grade 7 Module 6 Are You Ready? Answer Key**

**Write each fraction as a decimal and a percent.**

Question 1.

\(\frac{3}{4}\) ____________

Answer:

Divide 3 by 4. Write a decimal point and insert extra zeros in the dividend.

The result is 0.75.

Move the decimal point two places to the right and add the “%” sign.

0.75 = 75%

\(\frac{3}{4}\) = 75%

**Go Math Grade 7 Module 6 Answer Key Question 2.**

\(\frac{2}{5}\) ____________

Answer:

Divide 2 by 5. Write a decimal point and insert extra zeros in the dividend.

The result is 0.40.

Move the decimal point two places to the right and add the “%” sign.

0.40 = 40%

\(\frac{2}{5}\) = 40%

Question 3.

\(\frac{9}{10}\) ____________

Answer:

Divide 9 by 10. Write a decimal point and insert extra zeros in the dividend.

The result is 0.90.

Move the decimal point two places to the right and add the “%” sign.

0.90 = 90%

\(\frac{9}{10}\) = 90%

Question 4.

\(\frac{7}{20}\) ____________

Answer:

Divide 7 by 20. Write a decimal point and insert extra zeros in the dividend.

The result is 0.35.

Move the decimal point two places to the right and add the “%” sign.

0.35 = 35%

\(\frac{7}{20}\) = 35%

**Grade 7 Go Math Module 6 Answer Key Question 5.**

\(\frac{7}{8}\) ____________

Answer:

Divide 7 by 8. Write a decimal point and insert extra zeros in the dividend.

The result is 0.875.

Move the decimal point two places to the right and add the “%” sign.

0.875 = 87.5%

\(\frac{7}{8}\) = 87.5%

Question 6.

\(\frac{1}{20}\) ____________

Answer:

Divide 1 by 20. Write a decimal point and insert extra zeros in the dividend.

The result is 0.05.

Move the decimal point two places to the right and add the “%” sign.

0.05 = 5%

\(\frac{1}{20}\) = 5%

Question 7.

\(\frac{19}{25}\) ____________

Answer:

Divide 19 by 25. Write a decimal point and insert extra zeros in the dividend.

The result is 0.76.

Move the decimal point two places to the right and add the “%” sign.

0.76 = 76%

\(\frac{19}{25}\) = 76%

Question 8.

\(\frac{23}{50}\) ____________

Answer:

Divide 23 by 50. Write a decimal point and insert extra zeros in the dividend.

The result is 0.46.

Move the decimal point two places to the right and add the “%” sign.

0.46 = 46%

\(\frac{23}{50}\) = 46%

**Find each difference.**

Question 9.

1 – \(\frac{1}{5}\) ___________

Answer:

1 – \(\frac{1}{5}\) = \(\frac{5}{5}\) – \(\frac{1}{5}\) Write 1 as \(\frac{5}{5}\).

= \(\frac{5-1}{5}\) Subtract the numerators.

= \(\frac{4}{5}\)

Question 10.

1 – \(\frac{2}{9}\) ___________

Answer:

1 – \(\frac{2}{9}\) = \(\frac{9}{9}\) – \(\frac{2}{9}\) Write 1 as \(\frac{9}{9}\).

= \(\frac{9-2}{9}\) Subtract the numerators.

= \(\frac{7}{9}\)

**Grade 7 Module 6 Answer Key Go Math Question 11.**

1 – \(\frac{8}{13}\) ___________

Answer:

1 – \(\frac{8}{13}\) = \(\frac{13}{13}\) – \(\frac{8}{13}\) Write 1 as \(\frac{13}{13}\).

= \(\frac{13-8}{13}\) Subtract the numerators.

= \(\frac{5}{13}\)

Question 12.

1 – \(\frac{3}{20}\) ___________

Answer:

1 – \(\frac{3}{20}\) = \(\frac{20}{20}\) – \(\frac{3}{20}\) Write 1 as \(\frac{20}{20}\).

= \(\frac{20-3}{20}\) Subtract the numerators.

= \(\frac{17}{20}\)

**Multiply. Write each product in simplest form.**

**Grade 7 Module 6 Answer Key Go Math Question 13.**

\(\frac{8}{15}\) Ã— \(\frac{5}{8}\) ___________

Answer:

\(\frac{8}{15}\) Ã— \(\frac{5}{8}\) = \(\frac{8}{15}\) Ã— \(\frac{5}{8}\) Divide numerators and denominators by the common factors.

= \(\frac{1}{3}\) Ã— \(\frac{1}{1}\)

= \(\frac{1 \cdot 1}{3 \cdot 1}\)

= \(\frac{1}{3}\)

Question 14.

\(\frac{2}{9}\) Ã— \(\frac{3}{4}\) ___________

Answer:

\(\frac{2}{9}\) Ã— \(\frac{3}{4}\) = \(\frac{2}{9}\) Ã— \(\frac{3}{4}\) Divide numerators and denominators by the common factors.

= \(\frac{1}{3}\) Ã— \(\frac{1}{2}\)

= \(\frac{1 \cdot 1}{3 \cdot 2}\)

= \(\frac{1}{6}\)

Question 15.

\(\frac{9}{16}\) Ã— \(\frac{12}{13}\) ___________

Answer:

\(\frac{9}{16}\) Ã— \(\frac{12}{13}\) = \(\frac{9}{16}\) Ã— \(\frac{12}{13}\) Divide numerators and denominators by the common factors.

= \(\frac{9}{4}\) Ã— \(\frac{3}{13}\)

= \(\frac{9 \cdot 3}{4 \cdot 13}\)

= \(\frac{27}{52}\)

**Module 6 Answer Key Go Math Grade 7 Question 16.**

\(\frac{7}{10}\) Ã— \(\frac{5}{28}\) ___________

Answer:

\(\frac{7}{10}\) Ã— \(\frac{5}{28}\) = \(\frac{7}{10}\) Ã— \(\frac{5}{28}\) Divide numerators and denominators by the common factors.

= \(\frac{1}{2}\) Ã— \(\frac{1}{4}\)

= \(\frac{1 \cdot 1}{2 \cdot 4}\)

= \(\frac{1}{8}\)

**Texas Go Math Grade 7 Module 6 Reading Start-Up Answer Key**

**Visualize Vocabulary**

Use the âœ“ words to complete the graphic.

**Understand Vocabulary**

Match the term on the left to the correct expression on the right.

Answer:

1. Compound event – an event made of two or more simple events.

2. Theoretical probability – the ratio of the number of equally likely outcomes in an event to the total number of possible outcomes.

3. Complement – the set of all outcomes that are not the desired event.

**Active Reading**

Two-Panel Flip Chart Create a two-panel flip chart, to help you understand the concepts in this module. Label one flap â€œSimple Events and the other flap â€œCompound Eventsâ€™ As you study each lesson, write important ideas under the appropriate flap. Include information that will help you remember the concepts later when you look back at your notes.