Refer to our Texas Go Math Grade 6 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 6 Module 16 Quiz Answer Key.

## Texas Go Math Grade 6 Module 16 Quiz Answer Key

**Texas Go Math Grade 6 Module 16 Ready to Go On? Answer Key**

**16.1 Area of Quadrilaterals**

Question 1.

Find the area of the figure.

Answer:

Data:

b = 17\(\frac{1}{5}\) = 17.2

h = 12\(\frac{1}{2}\) = 12.5

Write equation of area of a parallelogram:

Area = b × h

Substitute values:

Area = 17.2 × 12.5

Evaluate:

Area = 215

Area of the given parallelogram is 215 square yards.

**16.2 Area of Triangles**

Question 2.

Find the area of the triangle.

Answer:

Find the area of the triangle.

b = 17 feet; h = 14 feet

A = \(\frac{1}{2}\) bh

= \(\frac{1}{2}\) (17 feet) (14 feet) Substitute

= 119 square feet Multiply

= 119 ft^{2}

**16.3 Solving Area Equations**

Question 3.

A triangular pane of glass has a height of 30 inches and an area of 270 square inches. What is the length of the base of the pane?

Answer:

What is the base of the triangular?

A = \(\frac{1}{2}\) bh Write the formula

270 = \(\frac{1}{2}\) b (30) Use the formula to write an equation

270 = 15b Multiply \(\frac{1}{2}\) and 30

\(\frac{270}{15}=\frac{15 b}{15}\) Divide both sides of the equation by 15

18 = b

The base of the triangular is 18 inches long.

Question 4.

A tabletop in the shape of a trapezoid has an area of 6,550 square centimeters. Its longer base measures 115 centimeters, and the shorter base is 85 centimeters. What is the height?

Answer:

What is the height of the trapezoid?

A = \(\frac{1}{2}\) h(b_{1} + b2) Write the formula

6550 = \(\frac{1}{2}\) h(85 + 115) Use the formula to write an equation

6550 = \(\frac{1}{2}\) h(200) Add inside parentheses

6550 = 100h Multiply \(\frac{1}{2}\) and 200

\(\frac{6550}{100}=\frac{100 h}{100}\) Divide both sides of the equation by 100

65.5 = h

The height of the trapezoid is 65.5 centimeters

**16.4 Solving Volume Equations**

Question 5.

A rectangular shoebox has a volume of 728 cubic inches. The base of the shoebox measures 8 inches by 6.5 inches. How long is the shoebox?

Answer:

Determine the volume of the box.

V = lwh formula for the volume of a box

728 = l ∙ 8 ∙ 6 ∙ 5 substitute for the given values

728 = 52l simplify

\(\frac{728}{52}=\frac{52 l}{52}\) divide both sides by 52

14 inches = l Length of the shoebox

The shoebox is 14 inches long.

**Essential Question**

Question 6.

How can you use equations to solve problems involving area and volume?

Answer:

Equations will help in solving problems involving area and volume. Identify the dimensions of the figure then substitute for the given values in the equation.

Area of a Rectangle = l × W

Area of a Parallelogram = b × h

Area of aTriangle = \(\frac{1}{2}\)bh

Area of a Trapezoid = \(\frac{1}{2}\)h (b_{1} + b_{2})

Area of a Rhombus = \(\frac{1}{2}\)d_{1}d_{2}

Volume of a Rectangular Prism = l × w × h

Identify the dimensions then substitute for the given equations.

**Texas Go Math Grade 6 Module 16 Mixed Review Texas Test Prep Answer Key**

**Selected Response**

Question 1.

What is the area of the rhombus shown below?

(A) 161 in^{2}

(B) 322 in^{2}

(C) 644 in^{2}

(D) 966 in^{2}

Answer:

(B) 322 in^{2}

Explanation:

Determine the area of the rhombus.

A = \(\frac{1}{2}\) ∙ 23 ∙ 28 substitute for the given values

A = \(\frac{644}{2}\) simplify

A = 322 in^{2} area of the rhombus

The area of the rhombus is 322 in^{2}.

Question 2.

What is the area of the triangle shown below?

(A) 4.44mm^{2}

(B) 5.92 mm^{2}

(C) 8.88 mm^{2}

(D) 17.76 mm^{2}

Answer:

(C) 8.88 mm^{2}

Explanation:

Determine the area of the triangle

A = \(\frac{1}{2}\) ∙ 4.8 ∙ 3.7 substitute for the given values

A = \(\frac{17.76}{2}\) simplify

A = 8.88 mm^{2} area of the triangle

The area of the triangle is 8.88 mm^{2}.

Question 3.

A rectangular prism has a volume of 912 cubic meters. It has a length of 19 meters and a width of 12 meters. Which equation could be solved to find the height of the rectangular prism?

(A) 114h = 912

(B) 228h = 912

(C) 15.5h = 912

(D) 31h = 912

Answer:

(B) 228h = 912

Explanation:

Determine the height of the rectangular prism.

V = lwh formula for the volume of the rectangular prism

912 = 19 ∙ 12 ∙ h substitute for the given values

912 = 228h simplify

4 meters = h volume of the rectangular prism

The equation to be used in solving the height of the rectangular prism is 228h = 912.

Question 4.

The trapezoid below has an area of 1,575 cm^{2}.

Which equation could you solve to find the height of the trapezoid?

(A) 45h = 1,575

(B) 90h = 1,575

(C) 850.5h = 1,575

(D) 1,70h = 1,575

Answer:

(A) 45h = 1,575

Explanation:

What is the height of the trapezoid?

A = \(\frac{1}{2}\)h(b_{1} + b_{2}) Write the formula

1575 = \(\frac{1}{2}\) h(63 + 27) Use the formula to write an equation

1575 = \(\frac{1}{2}\) h(90) Add inside parentheses

1575 = 45h Multiply \(\frac{1}{2}\) and 90

**Gridded Response**

Question 5.

Cindy is designing a rectangular fountain in a courtyard. The rest of the courtyard will be covered in stone.

The part of the courtyard that will be covered in stone has an area of 246 ft^{2}. What is the width of the fountain in feet?

Answer:

Determine the area of the whole courtyard.

A = l × w formula for the area of a rectangle

A = 22 × 12 substitute for the given values

A = 264 ft^{2} area of the whole courtyard

Subtract the area of the courtyard covered in stone from the whole courtyard.

A = 264 – 246 substitute for the given values

A = 18 ft^{2} area of the fountain

Determine the width of the fountain.

A = l × w formula for the area of a rectangle

18 = 6w substitute for the given values

\(\frac{18}{6}=\frac{6 w}{6}\) divide both sides of the equation by 6

3 ft = w width of the fountain

The gridded response is 3.00 ft which is the width of the fountain.