Refer to our Texas Go Math Grade 6 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 6 Module 16 Quiz Answer Key.

Question 1.
Find the area of the figure. Data:
b = 17$$\frac{1}{5}$$ = 17.2
h = 12$$\frac{1}{2}$$ = 12.5
Write equation of area of a parallelogram:
Area = b × h
Substitute values:
Area = 17.2 × 12.5
Evaluate:
Area = 215
Area of the given parallelogram is 215 square yards.

16.2 Area of Triangles

Question 2.
Find the area of the triangle. Find the area of the triangle.
b = 17 feet; h = 14 feet
A = $$\frac{1}{2}$$ bh
= $$\frac{1}{2}$$ (17 feet) (14 feet) Substitute
= 119 square feet Multiply
= 119 ft2

16.3 Solving Area Equations

Question 3.
A triangular pane of glass has a height of 30 inches and an area of 270 square inches. What is the length of the base of the pane?
What is the base of the triangular?
A = $$\frac{1}{2}$$ bh Write the formula
270 = $$\frac{1}{2}$$ b (30) Use the formula to write an equation
270 = 15b Multiply $$\frac{1}{2}$$ and 30
$$\frac{270}{15}=\frac{15 b}{15}$$ Divide both sides of the equation by 15
18 = b
The base of the triangular is 18 inches long.

Question 4.
A tabletop in the shape of a trapezoid has an area of 6,550 square centimeters. Its longer base measures 115 centimeters, and the shorter base is 85 centimeters. What is the height?
What is the height of the trapezoid?
A = $$\frac{1}{2}$$ h(b1 + b2) Write the formula
6550 = $$\frac{1}{2}$$ h(85 + 115) Use the formula to write an equation
6550 = $$\frac{1}{2}$$ h(200) Add inside parentheses
6550 = 100h Multiply $$\frac{1}{2}$$ and 200
$$\frac{6550}{100}=\frac{100 h}{100}$$ Divide both sides of the equation by 100
65.5 = h
The height of the trapezoid is 65.5 centimeters

16.4 Solving Volume Equations

Question 5.
A rectangular shoebox has a volume of 728 cubic inches. The base of the shoebox measures 8 inches by 6.5 inches. How long is the shoebox?
Determine the volume of the box.
V = lwh formula for the volume of a box
728 = l ∙ 8 ∙ 6 ∙ 5 substitute for the given values
728 = 52l simplify
$$\frac{728}{52}=\frac{52 l}{52}$$ divide both sides by 52
14 inches = l Length of the shoebox
The shoebox is 14 inches long.

Essential Question

Question 6.
How can you use equations to solve problems involving area and volume?
Equations will help in solving problems involving area and volume. Identify the dimensions of the figure then substitute for the given values in the equation.
Area of a Rectangle = l × W
Area of a Parallelogram = b × h
Area of aTriangle = $$\frac{1}{2}$$bh
Area of a Trapezoid = $$\frac{1}{2}$$h (b1 + b2)
Area of a Rhombus = $$\frac{1}{2}$$d1d2
Volume of a Rectangular Prism = l × w × h
Identify the dimensions then substitute for the given equations.

Texas Go Math Grade 6 Module 16 Mixed Review Texas Test Prep Answer Key

Selected Response

Question 1.
What is the area of the rhombus shown below? (A) 161 in2
(B) 322 in2
(C) 644 in2
(D) 966 in2
(B) 322 in2

Explanation:
Determine the area of the rhombus.
A = $$\frac{1}{2}$$ ∙ 23 ∙ 28 substitute for the given values
A = $$\frac{644}{2}$$ simplify
A = 322 in2 area of the rhombus
The area of the rhombus is 322 in2.

Question 2.
What is the area of the triangle shown below? (A) 4.44mm2
(B) 5.92 mm2
(C) 8.88 mm2
(D) 17.76 mm2
(C) 8.88 mm2

Explanation:
Determine the area of the triangle
A = $$\frac{1}{2}$$ ∙ 4.8 ∙ 3.7 substitute for the given values
A = $$\frac{17.76}{2}$$ simplify
A = 8.88 mm2 area of the triangle
The area of the triangle is 8.88 mm2.

Question 3.
A rectangular prism has a volume of 912 cubic meters. It has a length of 19 meters and a width of 12 meters. Which equation could be solved to find the height of the rectangular prism?
(A) 114h = 912
(B) 228h = 912
(C) 15.5h = 912
(D) 31h = 912
(B) 228h = 912

Explanation:
Determine the height of the rectangular prism.
V = lwh formula for the volume of the rectangular prism
912 = 19 ∙ 12 ∙ h substitute for the given values
912 = 228h simplify
4 meters = h volume of the rectangular prism
The equation to be used in solving the height of the rectangular prism is 228h = 912.

Question 4.
The trapezoid below has an area of 1,575 cm2. Which equation could you solve to find the height of the trapezoid?
(A) 45h = 1,575
(B) 90h = 1,575
(C) 850.5h = 1,575
(D) 1,70h = 1,575
(A) 45h = 1,575

Explanation:
What is the height of the trapezoid?
A = $$\frac{1}{2}$$h(b1 + b2) Write the formula
1575 = $$\frac{1}{2}$$ h(63 + 27) Use the formula to write an equation
1575 = $$\frac{1}{2}$$ h(90) Add inside parentheses
1575 = 45h Multiply $$\frac{1}{2}$$ and 90

Gridded Response

Question 5.
Cindy is designing a rectangular fountain in a courtyard. The rest of the courtyard will be covered in stone. The part of the courtyard that will be covered in stone has an area of 246 ft2. What is the width of the fountain in feet? Determine the area of the whole courtyard.
A = l × w formula for the area of a rectangle
A = 22 × 12 substitute for the given values
A = 264 ft2 area of the whole courtyard
Subtract the area of the courtyard covered in stone from the whole courtyard.
A = 264 – 246 substitute for the given values
A = 18 ft2 area of the fountain

Determine the width of the fountain.
A = l × w formula for the area of a rectangle
18 = 6w substitute for the given values
$$\frac{18}{6}=\frac{6 w}{6}$$ divide both sides of the equation by 6
3 ft = w width of the fountain
The gridded response is 3.00 ft which is the width of the fountain.

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