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## Texas Go Math Grade 5 Module 2 Assessment Answer Key

**Vocabulary**

**Choose the best term from the box.**

**Vocabulary**

compatible numbers

partial quotients

place value

Question 1.

You can use _____________ to estimate quotients because they are easy to compute with mentally. (p. 53)

Answer:

We know that,

You can use “Compatible numbers” to estimate quotients because they are easy to compute with mentally.

Hence, from the above,

We can conclude that

The best term that is suitable for the given statement is: Compatible numbers

Question 2.

To decide where to place the first digit in the quotient you can estimate or use __________. (p. 37)

Answer:

We know that,

To decide where to place the first digit in the quotient you can estimate or use “Place Value”

Hence, from the above,

We can conclude that

The best term that is suitable for the given statement is: Place Value

**Concept and Skills**

**Estimate. Then find the product. (TEKS 5.3.A, 5.3.B)**

Question 3.

Estimate: ____________

Answer:

The given expression is: 576 × 3

Now,

Estimate:

576 × 3 = 580 × 3

= 1,740

Now,

By using the Long Multiplication,

Hence, from the above,

We can conclude that

The value of the given expression is: 1,728

Question 4.

Estimate: ____________

Answer:

The given expression is: 219 × 6

Now,

Estimate:

219 × 6 = 220 × 6

= 1,320

Now,

By using the Long Multiplication,

Hence, from the above,

We can conclude that

The value of the given expression is: 1,314

Question 5.

Estimate: _____________

Answer:

The given expression is: 72 × 37

Now,

Estimate:

72 × 37 = 70 × 40

= 2,800

Now,

By using the Long Multiplication,

Hence, from the above,

We can conclude that

The value of the given expression is: 2,664

Question 6.

Estimate: _____________

Answer:

The given expression is: 359 × 18

Now,

Estimate:

359 × 18 = 360 × 18

= 6,480

Now,

By using the Long Multiplication,

Hence, from the above,

We can conclude that

The value of the given expression is: 6,462

Question 7.

Estimate: _____________

Answer:

The given expression is: 804 × 37

Now,

Estimate:

804 × 37 = 800 × 40

= 32,000

Now,

By using the Long Multiplication,

Hence, from the above,

We can conclude that

The value of the given expression is: 29,748

**Use compatible numbers to estimate the quotient. (TEKS 5.3. A)**

Question 8.

522 ÷ 60

Answer:

The given division expression is: 522 ÷60

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

522 ÷ 60 = 8 R 42

Question 9.

1,285 ÷ 32

Answer:

The given division expression is: 1,285 ÷ 32

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

1,285 ÷ 32 = 40 R 5

Question 10.

6,285 ÷ 89

Answer:

The given division expression is: 6,285 ÷ 89

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

6,285 ÷ 89 = 70 R 55

**Divide. (TEKS 5.3.C)**

Question 11.

156 ÷ 13

Answer:

The given division expression is: 156 ÷13

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

156 ÷ 13 = 12

Question 12.

318 ÷ 53

Answer:

The given division expression is: 318 ÷ 53

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

318 ÷ 53 = 6

Question 13.

1,562 ÷ 34

Answer:

The given division expression is: 1,562 ÷ 34

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

1,562 ÷ 34 = 45 R 32

Question 14.

4,024 ÷ 68

Answer:

The given division expression is: 4,024 ÷ 68

Now,

By using the Long Division,

Hence, from the above,

We can conclude that

4,024 ÷ 68 = 59 R 12

**Fill in the bubble completely to show your answer.**

Question 15.

Dylan’s dog weighs 12 times as much as his pet rabbit. The dog and rabbit weigh 104 pounds altogether. How much does Dylan’s dog weigh? (TEKS 5.3.C)

(A) 88 pounds

(B) 96 pounds

(C) 104 pounds

(D) 8 pounds

Answer:

It is given that

Dylan’s dog weighs 12 times as much as his pet rabbit. The dog and rabbit weigh 104 pounds altogether

Now,

Let the weight of Dylan’s pet rabbit be: x Pounds

So,

The weight of Dylan’s dog is: 12x Pounds

Now,

According to the given information,

12x + x = 104 Pounds

13x = 104 Pounds

x = \(\frac{104}{13}\)

x = 8 Pounds

So,

The weight of Dylan’s dog is: 96 Pounds

Hence, from the above,

We can conclude that

The weight of Dylan’s dog is:

Question 16.

Tickets for the basketball game cost $14 each. If the sale of the tickets brought in $2,212, how many tickets were sold? (TEKS 5.3.C)

(A) 172

(B) 158

(C) 150

(D) 168

Answer:

It is given that

The tickets for the basketball game cost $14 each and the sale of the tickets brought in $2,212

So,

According to the given information,

The number of tickets that were sold = \(\frac{$2,212}{$14}\)

Now,

Hence, from the above,

We can conclude that

The tickets that were sold are:

Question 17.

Adele earns $194 every two weeks delivering newspapers. She spends $30 of each paycheck and saves the rest. If she is paid 26 times this year, how much will Adele save? (TEKS 5.3.B)

(A) $3,244

(B) $4,264

(C) $772

(D) $5,044

Answer:

It is given that

Adele earns $194 every two weeks delivering newspapers. She spends $30 of each paycheck and saves the rest. If she is paid 26 times this year

Now,

The amount of money saved by Adele = $194 – $30

= $164

Now,

According to the given information,

The total amount of money saved by Adele in this year = $164 × 26

Now,

Hence, from the above,

We can conclude that

The total amount of money saved by Adele this year is:

Question 18.

A local orange grower processes 2,330 oranges from his grove this year. The oranges are packaged in crates that each holds 96 oranges. All but one crate is full. How many oranges are in this last crate? Record your answer and fill in the bubbles on the grid. Be sure to use the correct place value. (TEKS 5.3.C)

Answer:

It is given that

A local orange grower processes 2,330 oranges from his grove this year. The oranges are packaged in crates that each holds 96 oranges. All but one crate is full

So,

According to the given information,

The number of crates = \(\frac{2,330}{96}\)

Now,

So,

The number of oranges that are present in the last crate is: 26 oranges

Hence, from the above,

We can conclude that

The number of oranges that are present in the last crate is: