Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 13.7 Answer Key Customary and Metric Conversions.

## Texas Go Math Grade 5 Lesson 13.7 Answer Key Customary and Metric Conversions

**Essential Question**

How can you use the strategy to make a table to help you solve problems about customary and metric conversions?

Answer:

Conversion factors are used in solving problems in which a certain measurement must be expressed with different units. When a given measurement is multiplied by an appropriate conversion factor, the numerical value changes, but the actual size of the quantity measured remains the same.

**Unlock the Problem**

Aaron is making fruit punch for a family reunion. He needs to make 120 cups of punch. If he wants to store the fruit punch in gallon containers, how many gallon containers will Aaron need?

Use the graphic organizer below to help you solve the problem.

Solve

There are 16 cups in 1 gallon. So, each cup is \(\frac{1}{16}\) of a gallon.

Complete the table below.

So, Aaron needs \(\frac{15}{2}\) gallon containers to store the punch.

â€¢ Will all of the gallon containers Aaron uses be filled to capacity? Explain.

Answer:

From the above problem,

We can observe that

Aaron needs \(\frac{15}{2}\) gallon containers to store the punch

Now,

\(\frac{15}{2}\) = 7.5

So,

AllÂ of the 7-gallon containers will be filled and the 8th container will be half-filled

Hence, from the above.

We can conclude that

All the gallon containers of Aaron used are not filled to the capacity

**Try Another Problem**

Sharon is working on a project for art class. She needs to cut strips of wood that are each 1 decimeter long to complete the project. If Sharon has 7 strips of wood that are each 1 meter long, how many 1-decimeter strips can she cut?

So,

Sharon can cut 70 1-decimeter lengths to complete her project.

â€¢ What relationship did the table shows that you made?

Answer:

The given table is:

Now,

From the given table,

We can observe that

The given table shows the relationship between the metric lengths and the customary lengths

Hence, from the above,

We can conclude that

The given table shows the relationship between the metric lengths and the customary lengths

**Math Talk**

**Mathematical Processes**

Explain how you could use another strategy to solve this problem.

Answer:

The other strategy to solve the above problem is:

Step 1:

Write the given information

Step 2:

Formulate a strategy to solve the required information

Step 3:

Convert the metric units into customary units

Step 4:

Find the required quantity by using the given information

**Share and Show**

Question 1.

Edgardo has a drink cooler that holds 10 gallons of water. He is filling the cooler with a 1-quart container. How many times will he have to fill the quart container?

Answer:

It is given that

Edgardo has a drink cooler that holds 10 gallons of water. He is filling the cooler with a 1-quart container

Now,

Hence, from the above,

We can conclude that

Edgardo will need to fill the quart container 10 times

**Go Math Answer Key Grade 5 Customary and Metric Conversions Question 2.**

**What if** Edgardo only uses 32 quarts of water to fill the cooler? How many gallons of water does he use?

Answer:

It is given that

Edgardo only uses 32 quarts of water to fill the cooler

Now,

We know that,

1 gallon = 4 quarts

So,

The number of gallons of water does Edgardo used = \(\frac{32}{4}\)

= 8 gallons

Hence, from the above,

We can conclude that

The number of gallons of water Edgardo used is: 8 gallons

Question 3.

If Edgardo uses a 1-cup container to fill the cooler, how many times will he fill the 1-cup container?

Answer:

It is given that

Edgardo uses a 1-cup container to fill the cooler

Now,

We know that,

1 gallon = 16 cups

So,

The number of times will Edgardo fill the 1-cup container = 1 Ã— 16

= 16 times

Hence, from the above,

We can conclude that

The number of times will Edgardo fill the 1-cup container is: 16 times

**Problem Solving**

Question 4.

**Multi-Step** Jane is making 13 leather belts. Each belt is 6.4 decimeters long. How many meters of leather does she use?

Answer:

It is given that

Jane is making 13 leather belts. Each belt is 6.4 decimeters long

Now,

We know that,

1 decimeter = 0.1 meters

1 meter = 10 decimeters

So,

The number of decimeters of leather did Jane used = 13 Ã— 6.4

= 83.2 decimeters

So,

The number of meters of leather did jane used = 83.2 Ã— 0.1 meters

= 8.32 meters

Hence, from the above,

We can conclude that

The number of meters of leather did jane used is: 8.32 meters

Question 5.

**H.O.T.** **Evaluate** Carl is packing sports equipment in a box that can hold 22 kilograms. He packed equipment with a mass of 220 dekagrams and says the box canâ€™t hold anymore. Is Carl right? Explain.

Answer:

It is given that

Carl is packing sports equipment in a box that can hold 22 kilograms. He packed equipment with a mass of 220 dekagrams and says the box canâ€™t hold any more

Now,

We know that,

1 kg = 1,000 grams

1 dekagram = 0.01 kg

So,

220 dekagrams = 220 Ã— 0.01 kg

= 2.2 kg

So,

2.2 kg < 22 kg

Hence, from the above,

We can conclude that

Carl is not right

**Metric Conversion Answer Key 5th Grade Go Math Question 6.**

**Multi-Step** Maria put trim around a banner that is the shape of a triangle. Each side is 22 inches long. Maria has \(\frac{1}{2}\) foot of trim left. What was the length of the trim when she started? Write your answer in yards.

Answer:

It is given that

Maria put trim around a banner that is the shape of a triangle. Each side is 22 inches long. Maria has \(\frac{1}{2}\) foot of trim left

So,

The total length of the banner = 22 Ã— 3

= 66 inches

Now,

We know that,

1 feet = 12 inches

1 yard = 3 feet

So,

The total length of the banner in feet = \(\frac{66}{12}\)

= 5.5 feet

So,

The total length of the trim when Maria started = 5.5 + 0.5

= 6 feet

So,

The total length of the trim when Maria started in yards = \(\frac{6}{3}\)

= 2 yards

Hence, from the above,

We can conclude that

The total length of the trim, when Maria started in yards, is: 2 yards

**Daily Assessment Task**

**Fill in the bubble completely to show your answer.**

Question 7.

**Representations** Three lizards ran across a patch of grass. Larry ran 3.6 meters, Lou ran 2,600 millimeters, and Lola ran 310 centimeters. Which statement correctly compares the distances the lizards ran?

(A) Larry ran the farthest.

(B) Lou ran farther than Lola.

(C) Lola ran farther than Larry.

(D) Lola ran the shortest distance.

Answer:

It is given that

Three lizards ran across a patch of grass. Larry ran 3.6 meters, Lou ran 2,600 millimeters, and Lola ran 310 centimeters

Now,

We know that,

1 meter = 1,000 mm

1 cm = 10 mm

So,

The distance Larry ran = 3.6 Ã— 1,000

= 3,600 mm

The distance Lou ran = 2,600 mm

The distance Lola ran = 310 Ã— 10

= 3,100 mm

Hence, from the above,

We can conclude that

The statement that correctly compares the distances the lizards ran is:

**Metric Conversions Answer Key Go Math Grade 5 Question 8.**

Miranda is making lemonade from a powdered mix. She needs to add 3 cups of powdered mix to a large pitcher of water, but she only has a scoop that holds 2 ounces. How many 2-ounce scoops will she use?

(A) 4 scoops

(B) 8 scoops

(C) 10 scoops

(D) 12 scoops

Answer:

It is given that

Miranda is making lemonade from a powdered mix. She needs to add 3 cups of powdered mix to a large pitcher of water, but she only has a scoop that holds 2 ounces

Now,

We know that,

1 cup = 8 fluid ounces

So,

The number of ounces of powdered mix that needs to add to a large pitcher of water = 3 Ã— 8

= 24 fluid ounces

So,

The number of 2-ounce scoops will Mirands used = \(\frac{24}{2}\)

= 12 2-ounce scoops

Hence, from the above,

We can conclude that

The number of 2-ounce scoops will Mirands used is:

Question 9.

**Multi-Step** Mrs. Gonzalez is adding a border to her bulletin board. She has a strip of green border that is 8 feet long. How many 16-inch pieces can she cut from the strip?

(A) 4 pieces

(B) 6 pieces

(C) 8 pieces

(D) 12 pieces

Answer:

It is given that

Mrs. Gonzalez is adding a border to her bulletin board. She has a strip of green border that is 8 feet long

Now,

We know that,

1 feet = 12 inches

So,

8 feet = 8 Ã— 12

= 96 inches

Now,

The number of 16-inch pieces can Mrs. Gonzalez cut from the strip = \(\frac{96}{16}\)

= 6Â pieces

Hence, from the above,

We can conclude that

The number of 16-inch pieces can Mrs. Gonzalez cut from the strip is:

**Texas Test Prep**

**Grade 5 Go Math Answer Key Length 13.7 Question 10.**

Tony needs 16-inch-long pieces of gold chain to make each of the 3 necklaces. He has a piece of chain that is 4 feet 6 inches long. How much chain will he have left after making the necklaces?

(A) 6 inches

(B) 12 inches

(C) 18 inches

(D) 24 inches

Answer:

It is given that

Tony needs 16-inch-long pieces of gold chain to make each of the 3 necklaces. He has a piece of chain that is 4 feet 6 inches long.

Now,

We know that,

1 feet = 12 inches

So,

4 feet 6 inches = (4 Ã— 12) + 6

= 54 inches

Now,

The total length of the 3 necklaces = 16 Ã— 3

= 48 inches

So,

The amount of chain will Tony have left after making the necklaces = 54 – 48

= 6 inches

Hence, from the above,

We can conclude that

The amount of chain will Tony have left after making the necklaces is:

### Texas Go Math Grade 5 Lesson 13.7 Homework and Practice Answer Key

Question 1.

Jeremy walks through a maze. He begins by walking 25 feet, turning right, and walking 6 yards. Then he walks 32 more feet. He has 13 more yards to walk to complete the maze. What is the length of the maze? Write your answer in yards.

Answer:

It is given that

Jeremy walks through a maze. He begins by walking 25 feet, turning right, and walking 6 yards. Then he walks 32 more feet. He has 13 more yards to walk to complete the maze

Now,

We know that,

1 feet = \(\frac{1}{3}\) yard

So,

The total length of the maze = 25 feet + 6 yards + 32 feet + 13 yards

= 57 feet + 19 yards

= \(\frac{57}{3}\) yards + 19 yards

= 19 yards + 19 yards

= 38 yards

Hence, from the above,

We can conclude that

The total length of the maze is: 38 yards

Question 2.

Randy uses a pedometer to keep track of the distances he walks each day. He discovers that the trip to his mailbox and back is 300 meters. How many kilometers does Randy walk to his mailbox and back if he collects his mail 6 days a week for 4 weeks?

Answer:

It is given that

Randy uses a pedometer to keep track of the distances he walks each day. He discovers that the trip to his mailbox and back is 300 meters

Now,

We know that,

1 meter = \(\frac{1}{1,000}\) kilometers

So,

The number of meters does Randy walk to his mailbox and back if he collects his mail 6 days a week for 4 weeks = 300 Ã— 6 Ã— 4 meters

= 300 Ã— 24 meters

= 7,200 meters

So,

The number of kilometers Randy walks to his mailbox and back if he collects his mail 6 days a week for 4 weeks = 7,200 Ã— \(\frac{1}{1,000}\)

= 7.2 kilometers

Hence, from the above,

We can conclude that

The number of kilometers Randy walks to his mailbox and back if he collects his mail 6 days a week for 4 weeks is: 7.2 kilometers

**Go Math Answer Key Grade 5 Homework Length 13.7 Question 3.**

Team members are participating in a scavenger hunt. They meet at the starting point and ride their bikes 2 kilometers. They find the first clue that says the second clue is 10 hectometers away. When they reach the second clue, they are told to go back 300 dekameters. Will the team members reach the point where they started after they follow the instructions for the second clue? Explain.

Answer:

It is given that

Team members are participating in a scavenger hunt. They meet at the starting point and ride their bikes 2 kilometers. They find the first clue that says the second clue is 10 hectometers away. When they reach the second clue, they are told to go back 300 dekameters

Now,

Let us convert our given distance in meters.

So,

1 km = 1,000 meter.

So,

2 km = 2 Ã— 1,000 meters

= 2,000 meters

Now,

1 hectometer = 100 meters

So,

10 hectometers = 10 Ã— 100 meters

= 1,000 meters

Now,

1 Decameter = 10 meters

So,

300 decameters = 300 Ã— 10 meters

= 3,000 meters

Now,

Let us Assume that team members traveled in a straight line.

So,

The distance between the starting point and the 2nd clue = 2,000 + 1,000

= 3,000 meters

Now,

Since the second clue asked the participants to go back 300 decameters,

We will subtract 300 decameters from the total distance covered to reach 2nd clue.

So,

The change in the position = 3,000 – 3,000

= 0

Hence, from the above,

We can conclude that

The team members will reach the point where they started after they follow the instructions for the second clue.

**Problem Solving**

Question 4.

Mrs. Arnold is serving hamburgers to her family of 6 tonight for dinner. She uses \(\frac{1}{2}\) pound of ground meat for each hamburger patty. She buys a package of meat that weighs 50 ounces. Will Mrs. Arnold have enough meat? Explain.

Answer:

It is given that

Mrs. Arnold is serving hamburgers to her family of 6 tonight for dinner. She uses \(\frac{1}{2}\) pound of ground meat for each hamburger patty. She buys a package of meat that weighs 50 ounces

Now,

The total number of pieces of hamburgers Mrs. Arnold is serving = 6 Ã·\(\frac{1}{2}\)

= 6 Ã— 2

= 12 pieces

Now,

We know that,

1 pound = 16 ounces

So,

The total weight of the total number of pieces of hamburgers Mrs. Arnold is serving = 12 Ã— 2 Ã— 16

= 24 Ã— 16

= 384 ounces

So,

384 ounces > 50 ounces

Hence, from the above,

We can conclude that

Mrs. Arnold will have enough meat

**Lesson Check**

**Fill in the bubble completely to show your answer.**

Question 5.

The lengths of three snakes exhibited in the zoo’s reptile house are labeled. The king snake is 65 inches. The eastern diamondback rattlesnake is 2 yards. The ridge-nosed rattlesnake is 4 feet. Which statement correctly compares the lengths of the snakes?

(A) The king snake is the longest snake.

(B) The ridge-nosed rattlesnake is longer than the eastern diamondback rattlesnake.

(C) The eastern diamondback rattlesnake is the longest snake.

(D) The eastern diamondback rattlesnake is shorter than the king snake.

Answer:

It is given that

The lengths of three snakes exhibited in the zoo’s reptile house are labeled. The king snake is 65 inches. The eastern diamondback rattlesnake is 2 yards. The ridge-nosed rattlesnake is 4 feet

Now,

We know that,

1 feet = 12 inches

1 yard = 36 inches

So,

The length of the King snake = 65 inches

The length of eastern diamondback rattlesnake = 2 Ã—36 = 72 inches

The length of ridge-nosed rattlesnake = 4 Ã— 12 = 48 inches

Hence, from the above,

We can conclude that

The statement that correctly compares the lengths of the snakes is:

**Go Math Answer Key 5th Grade Length 13.7 Question 6.**

Mr. Martinez has 2.5 kilograms of colored sand for his art students to use on their sand art projects. He packages the sand into individual bags with 125 grams in each bag. How many bags of sand can Mr. Martinez make?

(A) 2.5

(B) 16

(C) 20

(D) 200

Answer:

It is given that

Mr. Martinez has 2.5 kilograms of colored sand for his art students to use on their sand art projects. He packages the sand into individual bags with 125 grams in each bag

Now,

We know that,

1 kg = 1,000 grams

So,

2.5 kilograms = 2.5 Ã— 1,000

= 2,500 grams

So,

The number of bags of sand Mr. Martinez can make = \(\frac{2,500}{125}\)

= 20 bags

Hence, from the above,

We can conclude that

The number of bags of sand Mr. Martinez can make is:

Question 7.

A baker needs 6 quarts of milk for a cupcake frosting recipe. He only has an 8-ounce measuring cup to measure the milk into the bowl. How many cups of milk will he use?

(A) 16 cups

(B) 24 cups

(C) 20 cups

(D) 32 cups

Answer:

It is given that

A baker needs 6 quarts of milk for a cupcake frosting recipe. He only has an 8-ounce measuring cup to measure the milk into the bowl.

Now,

We know that,

1 cup = 8 fluid ounces

1 quart = 32 fluid ounces

So,

6 quarts = 6 Ã— 32

= 192 cups

8 ounces = 1 cup

So,

The number of cups will a baker use = \(\frac{192}{8}\)

= 24 cups

Hence, from the above,

We can conclude that

The number of cups will a baker use is:

Question 8.

When Rosa makes lemonade, she uses 500 milliliters of lemon juice for every liter of water. If she made 12 liters of lemonade, how much lemon juice did she use?

(A) 4,000 milliliters

(B) 6,000 milliliters

(C) 8,000 milliliters

(D) 2,000 milliliters

Answer:

It is given that

When Rosa makes lemonade, she uses 500 milliliters of lemon juice for every liter of water and she made 12 liters of lemonade

Now,

We know that,

1 liter = 1,000 milliliters

So,

12 liters = 12 Ã— 1,000

= 12,000 milliliters

So,

The amount of lemon juice did Rosa used = 12,000 – (12 Ã— 500)

= 12,000 – 6,000

= 6,000 milliliters

Hence, from the above,

We can conclude that

The amount of lemon juice did Rosa used is:

**5th Grade Go Math Answer Key Customary and Metric Conversions Question 9.**

**Multi-Step** A Komodo dragon is 3 meters long. A dwarf gecko is 15 millimeters long. How many dwarf geckos lined up end-to-end would match the length of the Komodo dragon?

(A) 200

(B) 100

(C) 150

(D) 300

Answer:

It is given that

A Komodo dragon is 3 meters long. A dwarf gecko is 15 millimeters long

Now,

We know that,

1 meter = 1,000 mm

So,

3 meters = 3 Ã— 1,000 mm

= 3,000 mm

So,

The number of dwarf geckos lined up end-to-end would match the length of the Komodo dragon = \(\frac{3,000}{15}\)

= 200

Hence, from the above,

We can conclude that

The number of dwarf geckos lined up end-to-end would match the length of the Komodo dragon is:

Question 10.

**Multi-Step** Campers use a roll of string that is 250 yards long to make kites. Each kite will have 50 feet of kite line. How many kite lines can they cut from the roll of string?

(A) 5

(B) 50

(C) 150

(D) 15

Answer:

It is given that

Campers use a roll of string that is 250 yards long to make kites. Each kite will have 50 feet of kite line

Now,

We know that,

1 yard= 3 feet

So,

250 yards = 250 Ã— 3 feet

= 750 feet

So,

The number of kite lines that can the Campers cut from the roll of string = \(\frac{750}{50}\)

= 15 kite lines

Hence, from the above,

We can conclude that

The number of kite lines can the Campers cut from the roll of string is: