McGraw Hill Math Grade 4 Chapter 11 Lesson 7 Answer Key Using Line Plots to Solve Problems

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 11 Lesson 7 Using Line Plots to Solve Problems to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 11 Lesson 7 Using Line Plots to Solve Problems

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The line plot shows the height in feet of a number of parade balloons.
McGraw Hill Math Grade 4 Chapter 11 Lesson 7 Answer Key Using Line Plots to Solve Problems 1

Question 1.
What is the difference between the tallest balloon and the shortest balloon shown on the line plot?
Answer:
4\(\frac{1}{4}\)

Explanation:
The above line plot tells that the tallest balloon is 49\(\frac{3}{4}\) fee
The shortest balloon is 45\(\frac{2}{4}\) feet
Subtract to find the difference
49\(\frac{3}{4}\) – 45\(\frac{2}{4}\)  = 4\(\frac{1}{4}\) feet
So, the difference between tallest balloon and the shortest balloon shown on the line plot is 4\(\frac{1}{4}\) feet.

Question 2.
What is the difference of the most common height shown and the shortest height shown?
Answer:
2 feet

Explanation:
The above line plot tells that the height of the most common balloon is 47\(\frac{2}{4}\)
The height of the shortest balloon is 45\(\frac{2}{4}\)
Subtract to find the difference
47\(\frac{2}{4}\) – 45\(\frac{2}{4}\) = 2
So, the difference of the most common height shown and the shortest height is 2 feet.

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