McGraw Hill Math

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 3 Lesson 2 Associative and Distributive Properties of Multiplication are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 3 Lesson 2 Associative and Distributive Properties of Multiplication

Fill in the missing information. Name the property.

Question 1.
(17 × 5) × 20 = 17 × (5 × 20) = 17 × 100 = 1700
__________________________ Property
Answer:
Associative property.

Explanation:
Given the expression is (17 × 5) × 20 = 17 × (5 × 20) = 17 × 100 = 1700 and the property is Associative property where changing the group of factors does not change the product.

Question 2.
11 × 37 = (______ × 37) + (1 × ______) = 370 + ______ = ______
______ Property
Answer:
Distributive property.

Explanation:
Given the expression is 11 × 37 which is
= (10 × 37) + (1 × 37)
= 370 + 37
= 407.
As distributive property is a property of multiplication states that multiplication can be distributed over addition as well as subtraction.

Question 3.
(51 × 14) + (49 × 14) = (___ + 49) × 14 = ___ × 14 = ___
_________________________ Property
Answer:
Distributive property.

Explanation:
Given the expression is (51 × 14) + (49 × 14) which is
= (51 + 49) × 14
= 100 × 14
= 1400.
As distributive property is a property of multiplication states that multiplication can be distributed over addition as well as subtraction.

Solve.

Question 4.
What multiplication problem does this drawing represent?
______________________

Answer:
The above image represents commutative property. As commutative property means the answer will remain the same when multiplying numbers even if the order of the numbers is changed.

Question 5.
Which multiplication property does this drawing represent?
Answer:

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 10 Lesson 7 Problem Solving: Draw a Picture and Write an Equation to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 10 Lesson 7 Problem Solving: Draw a Picture and Write an Equation

Solve

Question 1.
Elsa is knitting a blanket. She used 4\(\frac{3}{8}\) meters of red yarn and 2\(\frac{4}{8}\) meters of gold yarn. How many meters of yarn did she use altogether?
Answer:
6\(\frac{7}{8}\) meters

Explanation:
Elsa is knitting a blanket
She used 4\(\frac{3}{8}\) meters of red yarn and
2\(\frac{4}{8}\) meters of gold yarn
Add to find the total number of meters of yarn
4\(\frac{3}{8}\) + 2\(\frac{4}{8}\) = 6\(\frac{7}{8}\) meters
So, Elsa used 6\(\frac{7}{8}\) meters of yarn altogether.

Question 2.
Katia is building a tree house. She needs 52 boards. Each board has to be 4 meters long. How much wood does Katia need?
Answer:
208 meters of wood

Explanation:
Katia is building a tree house
She needs 52 boards
Each board has to be 4 meters long
Multiply to find
52 x 4 = 208
So, Katia used 208 meters of wood.

Question 3.
Ms. Morton has 167\(\frac{3}{5}\) cm of string. She cuts the string into two pieces. One piece is 72\(\frac{1}{5}\) cm long. How long is the other piece?
Answer:

Explanation:
Ms. Morton has 167\(\frac{3}{5}\) cm of string
She cuts the string into two pieces
One piece is 72\(\frac{1}{5}\) cm long
Subtract to find the length of the other piece
167\(\frac{3}{5}\) – 72\(\frac{1}{5}\) = 95\(\frac{2}{5}\)
So, the other piece is 95\(\frac{2}{5}\).

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 10 Lesson 8 Problem Solving: Working Backward to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 10 Lesson 8 Problem Solving: Working Backward

Solve

Question 1.
The owner of a gift stop has a large spool of wrapping paper. She uses 13\(\frac{2}{5}\) yards of paper in one week and 16\(\frac{1}{5}\) yards of paper the next week. She has 41\(\frac{1}{5}\) yards of paper left over. How many yards of wrapping paper did she start with?
Answer:
70\(\frac{4}{5}\)

Explanation:
The owner of a gift stop has a large spool of wrapping paper
She uses 13\(\frac{2}{5}\) yards of paper in one week
16\(\frac{1}{5}\) yards of paper the next week
She has 41\(\frac{1}{5}\) yards of paper left over
Add to find
13\(\frac{2}{5}\) + 16\(\frac{1}{5}\) + 41\(\frac{1}{5}\) = 70\(\frac{4}{5}\)
The owner of a gift shop has 70\(\frac{4}{5}\) yards of wrapping paper she started with.

Question 2.
Toshi drove from home to work. Then he drove from work to Beth s house. He drove 13\(\frac{1}{4}\) miles south, then 29 miles east, then another 8\(\frac{1}{4}\) miles south. He drove a total of 55\(\frac{3}{4}\) miles for the entire day. How many miles did he drive from home to work?
Answer:
70\(\frac{4}{5}\)

Explanation:
Toshi drove from home to work
Then he drove from work to Beth s house
He drove 13\(\frac{1}{4}\) miles south
Then 29 miles east
Then another 8\(\frac{1}{4}\) miles south
13\(\frac{1}{4}\) + 29 + 8\(\frac{1}{4}\)  = 50\(\frac{2}{4}\)
He drove a total of 55\(\frac{3}{4}\) miles for the entire day
55\(\frac{3}{4}\) – 50\(\frac{2}{4}\) = 5\(\frac{1}{4}\)
So, Toshi drove 5\(\frac{1}{4}\) miles from home to work.

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 10 Lesson 9 Problem Solving: Using Formulas to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 10 Lesson 9 Problem Solving: Using Formulas

Solve

Question 1.
Mr. Smith wants to build a fence around his backyard. It is square-shaped and measures 7 meters on one side. How many meters of fence will Mr. Smith need to build?
Answer:
(2 × 7) + (2 × 7) = 28m

Explanation:
Mr. Smith wants to build a fence around his backyard
It is square-shaped and measures 7 meters on one side
Perimeter of a square = (2 x l) + (2 x w)
That is (2 × 7) + (2 × 7)
= 14 + 14
= 28
So, Mr. Smith need 28 m to build the fence.

Question 2.
Gary builds a rectangular rabbit pen. The pen measures 6 feet by 8 feet. How many square feet is the pen?
Answer:
48 square feet

Explanation:
Gary builds a rectangular rabbit pen
The pen measures 6 feet by 8 feet
Area of a rectangle = l x w
Length of the pen is 6 feet
Width of the pen is 8 feet
Area – l x w = 6 x 8 = 48 feet
So, the area of the rectangular pen is 48 square feet.

Question 3.
The town of Grand Sun marks off a large rectangular patch of land as a forest preserve. The land measures 14 kilometers long and 8 kilometers wide. What is the total area of the forest preserve?
Answer:
112 square kilometers

Explanation:
The town of Grand Sun marks off a large rectangular patch of land as a forest preserve
The land measures 14 kilometers long and 8 kilometers wide
Area of a rectangle = l x w
Length of the rectangular patch of land is 6 km
Width of the rectangular patch of the land is 8 km
Area – l x w = 14 x 8 = 112
So, the area of the rectangular patch of land is 112 square kilometers.

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 10 Test to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Chapter 10 Test Answer Key

Place a check mark next to the best answer.

Question 1.
About how long is a paperclip?

___________ about 1 inch
___________ about 1 foot
___________ about 1 yard
Answer:

Explanation:
The paperclip is about 1 inch long.

Question 2.
About how long is a horse?

___________ about 2 centimeters
___________ about 2 kilometers
___________ about 2 meters
Answer:

Explanation:
The horse is about 2 meters long.

Multiply to find each missing number.

Question 3.
3 yd = ___________ ft
Answer:
3 yd = 9 feet

Explanation:
1 yard = 3 feet
3 yards = 3 x 3 = 9 ft
So, 3 yd = 9 ft.

Question 4.
5 mi = ___________ yd
Answer:
5 mi = 8800 yd

Explanation:
1 mile = 1760 yd
5 miles = 5 x 1760 = 8800 yd
So, 5 miles = 8800 yards.

Question 5.
4 yd = ___________ in
Answer:
4 yd = 144 in

Explanation:
1 yard = 36 inches
4 yards = 4 x 36 = 144 in
So,4 yd = 144 in.

Question 6.
13 m = ___________ cm
Answer:
13 m = 1300 cm

Explanation:
1 m = 100 cm
13 m = 13 x 100 cm
1300 cm
So, 13 cm = 1300 cm

Question 7.
48 km = ___________ m
Answer:
48 km = 48000 m

Explanation:
1 km = 1000 m
48 km = 48 x 1000 m
= 48000 m
So, 48 km = 48000 m.

Question 8.
3 mi = ___________ ft
Answer:
3 mi = 15,480 ft

Explanation:
1 mi = 5,280 ft
3 mi = 3 x 5280 ft
= 15,480 ft
So, 3 mi = 15,480 ft.

Question 9.
11 yd = ___________ in
Answer:
11 yd = 396 in

Explanation:
1 yard = 36 inches
11 yards = 11 x 36 =  in
So,11 yd = 396 in.

Question 10.
17 m = ___________ cm
Answer:
17m = 1700 cm

Explanation:
1 m = 100 cm
17 m = 17 x 100 cm
= 1700 cm
So, 17 m = 1700cm.

Question 11.
5 mi = ___________ ft
Answer:
5 mi = 26,400 ft

Explanation:
1 mi = 5280 ft
5 mi = 5 x 5280 ft
26,400
So, 5 mi = 26,400 ft.

Question 12.
Draw a table to show the following data. Then convert each length to inches. Show both lengths in the table.
Maple Tree: 32 feet
Oak Tree: 75 feet
Birch Tree: 56 feet
Pine Tree: 95 feet
Answer:

Explanation:
I drew a table to show the given data
1 feet = 12 inches
So, i converted each length from feet to inches.

Question 13.
Draw a table to show the following data. Then convert each length to centimeters. Show both lengths in the table.
Height of Garden Shed: 3 meters
Height of Garage: 4 meters
Height of House: 22 meters
Height of Mailbox: 1 meter
Answer:

Explanation:
I drew a table to show the given data
1 meter = 100 centimeters
So, i converted each length from meters to centimeters.

Question 14.
What is the area of the rectangle?

Answer:
75 square inches

Explanation:
Area of a rectangle = length x width
Length of the given figure = 15 in
Width of the given figure = 5 in
Area – l x w = 15 x 5 = 75
So, the area of the given figure is 75 square inches.

Question 15.
What is the area of the square?

Answer:
169 square meters

Explanation:
Area of a square = length x width
Length of the given figure = 13 m
Width of the given figure = 13 m
Area – l x w = 13 x 13 = 169
So, the area of the given figure is 169 square meters.

Question 16.
What is the perimeter of the rectangle?

Answer:
54 kilometers

Explanation:
Perimeter of a rectangle = (2 x length) + (2 x width)
Length of the given figure = 18 km
Width of the given figure = 9 km
Perimeter = (2 x l) + (2 x w)
= (2 x 18) + (2 x 9)
= 36 + 18
= 54
So, perimeter of the given rectangle is 54 kilometers.

Solve.

Question 17.
Lauren and her brother went hiking. They hiked 44\(\frac{3}{8}\) kilometers along the Atlanta Trail. They also hiked 36\(\frac{2}{8}\) kilometers along the Hopper Trail. How many kilometers did they hike in all?
Answer:
80\(\frac{5}{8}\)

Explanation:
Lauren and her brother went hiking
They hiked 44\(\frac{3}{8}\) kilometers along the Atlanta Trail
They also hiked 36\(\frac{2}{8}\) kilometers along the Hopper Trail
44\(\frac{3}{8}\) + 36\(\frac{2}{8}\) = 80\(\frac{5}{8}\)
They hike 80\(\frac{5}{8}\) kilometers in all.

Question 18.
A fabric store has a sale. 22\(\frac{3}{5}\) yards of black fabric are sold the first day and 19\(\frac{1}{5}\) yards are sold the second day. 16\(\frac{1}{5}\) yards of black fabric are leftover. How many yards of black fabric were in the store to begin with?
Answer:
58 yards

Explanation:
A fabric store has a sale
22\(\frac{3}{5}\) yards of black fabric are sold the first day
19\(\frac{1}{5}\) yards are sold the second day
16\(\frac{1}{5}\) yards of black fabric are leftover
Add to find the total
22\(\frac{3}{5}\) + 19\(\frac{1}{5}\) + 16\(\frac{1}{5}\) = 58 yards
So, 58 yards of black fabric were in the store to begin.

Question 19.
Mr. Harrison is an architect. He designs a rectangular living room that is 8 meters wide and 11 meters long. What is the area of the living room?
Answer:
88 square meters

Explanation:
Mr. Harrison is an architect
He designs a rectangular living room that is 8 meters wide and 11 meters long
Area of a rectangle = length x width
Length of the living room = 11 meters
Width of the living room = 8 meters
Area – l x w = 11 x 8 = 88
So, the area of the living room is 8 square meters

Question 20.
What is the perimeter of the living room?
Answer:
38 meters

Explanation:
Perimeter of a rectangle = (2 x length) + (2 x width)
Length of the living room = 11 meters
Width of the living room = 8 meters
Perimeter = (2 x l) + (2 x w)
= (2 x 11) + (2 x 8)
= 22 + 16
= 38
So, perimeter of the living room is 38 meters.

Question 21.
Karen has a new roll of tape. She uses 3\(\frac{1}{6}\) feet to tape one package. She uses 5\(\frac{2}{6}\) feet to tape another package. Then she uses 4\(\frac{1}{6}\) feet to tape a third package. She has 12\(\frac{2}{6}\) feet of tape left over. How many feet of tape did she begin with?
Answer:
25 feet

Explanation:
Karen has a new roll of tape
She uses 3\(\frac{1}{6}\) feet to tape one package
She uses 5\(\frac{2}{6}\) feet to tape another package
Then she uses 4\(\frac{1}{6}\) feet to tape a third package
She has 12\(\frac{2}{6}\) feet of tape left over
Add to find the total
3\(\frac{1}{6}\) + 5\(\frac{2}{6}\) + 4\(\frac{1}{6}\) + 12\(\frac{2}{6}\) = 25 feet
So, Karen has 25 feet of tape with her at the beginning.

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 11 Lesson 1 Metric Units of Mass to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 11 Lesson 1 Metric Units of Mass

Solve.

Please a checkmark beside the best answer.

Question 1.
What is the mass of a paperclip?

__________ about 1 gram
__________ about 50 grams
__________ about 1 kilogram
__________ about 100 grams
Answer:

Explanation:
The mass of a paperclip is about 1 gram.

Question 2.
What is the mass of a cat?

__________ about 3 grams
__________ about 30 grams
__________ about 300 kilograms
__________ about 3 kilograms
Answer:

Explanation:
The mass of a cat is about 3 kilograms.

Multiply to find each missing number.

Question 3.
1 kg = __________ g
Answer:
1000g

Explanation:
1 kg is equal to 1000 grams.

Question 4.
4 kg = __________ g
Answer:
4000 g

Explanation:
1 kg = 1000 g
2 kg = 2 x 1000 = 2000 g
So, 2 kg = 2000 g.

Question 5.
13 kg = __________ g
Answer:
13000g

explanation:
1 kg = 1000 g
13 kg = 13 x 1000 = 13000 g
so, 13 kg = 13000 g.

Question 6.
57 kg = __________ g
Answer:
57,000g

Explanation:
1 kg = 1000 g
57 kg = 57 x1000 = 57,000 g
so, 57 kg = 57,000 g.

Question 7.
472 kg = __________ g
Answer:
472,000 g

Explanation:
1 kg = 1000 g
472 kg = 472 x 1000 = 472,000 g
so, 472 kg = 472,000 g.

Question 8.
397 kg = __________ g
Answer:
397,000 g

Explanation:
1 kg = 1000 g
397 kg = 397 x 1000 = 397,000 g
so, 397 kg = 397,000 g.

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 11 Lesson 2 Customary Units of Weight to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 11 Lesson 2 Customary Units of Weight

Solve

Place a check mark next to the best answer.

Question 1.
What does a baby rabbit weigh?
____________ about 1 ounce
____________ about 1 pound
____________ about 10 pounds
Answer:

Explanation:
A baby rabbit weigh about 1 pound.

Question 2.
What does a cherry weigh?
____________ about 1 ounce
____________ about 10 ounces
____________ about 1 pound
Answer:

Explanation:
A cherry weigh about 1 ounce.

Question 3.
What does a gallon jug of milk weigh?
____________ about 2 pounds
____________ about 9 pounds
____________ about 25 pounds
Answer:

Explanation:
A gallon jug of milk weigh about 9 pounds.

Question 4.
Multiply to complete the tables.

Answer:

Explanation:
I multiplied the tons with the number of pounds to complete the table and pound with ounces
1 ton = 2000 pounds and 1 pound = 16 ounces.

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 11 Lesson 3 Metric Units of Capacity to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 11 Lesson 3 Metric Units of Capacity

Solve

Place a check mark next to the best answer.

Question 1.
What is the capacity of a drinking glass?

____________ about 400 milliliters
____________ about 4 liters
____________ about 40 liters
____________ about 40 milliliters
Answer:

Explanation:
The capacity of a drinking glass is 400 milliliters.

Question 2.
What is the capacity of a cup?

____________ about 20 milliliters
____________ about 200 milliliters
____________ about 2 liters
____________ about 20 liters
Answer:

Explanation:
The capacity of a cup is about 200 milliliters.

Multiply to find each missing number.

Question 3.
2 L = ____________ mL
Answer:
2000 ml

Explanation:
1 L = 1000 m
2 L = 2 x 1000 = 2000 ml
So, 2 L = 2000 ml.

Question 4.
5 L = ____________ mL
Answer:
5000 ml

Explanation:
1 L = 1000 m
5 L = 5 x 1000 = 5000 ml
So, 5 L = 5000 ml.

Question 5.
13 L = ____________ mL
Answer:
13,000 ml

Explanation:
1 L = 1000 m
13 L = 13 x 1000 = 13000 ml
So, 13 L = 13000 ml.

Question 6.
62 L = ____________ mL
Answer:
62,000 ml

Explanation:
1 L = 1000 m
62 L = 62 x 1000 = 62,000 ml
So, 62 L = 62,000 ml.

Question 7.
113 L = ____________ mL
Answer:
113,000 ml

Explanation:
1 L = 1000 m
113 L = 113 x 1000 = 113,000 ml
So, 113 L = 113,000 ml.

Question 8.
494 L = ____________ mL
Answer:
494,000 ml

Explanation:
1 L = 1000 m
494 L = 494 x 1000 = 494,000 ml
So, 494 L = 494,000 ml.

Practice the questions of McGraw Hill Math Grade 4 Answer Key PDF Chapter 11 Lesson 4 Customary Units of Capacity to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 4 Answer Key Chapter 11 Lesson 4 Customary Units of Capacity

Solve

Place a check mark next to the best answer.

Question 1.
What is the capacity of a bucket?

____________ about 1 gallon
____________ about 100 gallons
____________ about 20 gallons
____________ about 50 gallons
Answer:

Explanation:
The capacity of a bucket is about 1 gallon.

Question 2.
What is the capacity of a small bowl?

____________ about \(\frac{1}{4}\) cup
____________ about 1 pint
____________ about 1 gallon
____________ about 1 quart
Answer:

Explanation:
The capacity of a small bowl is about \(\frac{1}{4}\) cup.

Multiply to find each missing number.

Question 3.
3 gal = ____________ pt
Answer:
24 pt

Explanation:
1 gal = 8 pt
3 gal = 3 x 8 = 24 pt
So, 8 gal = 24 pt.

Question 4.
6 pt = ____________ c
Answer:
12 c

Explanation:
1 pt = 2 c
6 pt = 6 x 2 = 12 c
So, 6 pt = 12 c.

Question 5.
9 gal = ____________ qt
Answer:
36 qt

Explanation:
1 gal = 4 qt
9 gal = 9 x 4 = 36 qt
So, 9 gal = 36 qt.

Question 6.
17 gal = ____________ c
Answer:
272 c

Explanation:
1 gal = 16 c
17 gal = 17 x 16 = 272 c
So, 17 gal = 272 c.

Question 7.
104 qt = ____________ pt
Answer:
208 pt

Explanation:
1 qt = 2 pt
104 qt = 104 x 2 = 208 pt
So, 104 qt = 208 pt.

Question 8.
365 gal = ____________ c
Answer:
5,840 c

Explanation:
1 gal = 16 c
365 gal = 365 x 16 = 5,840 c
So, 365 gal = 5,840 c.

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 14.4 Multiplying Percents and Fractions will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 14.4 Multiplying Percents and Fractions

Exercises

MULTIPLY

Give the answer as a fraction.

Question 1.
35% of \(\frac{1}{6}\)
Answer:
35% can be written as 35/100
35/100 × \(\frac{1}{6}\) = 0.058
0.058 in the fraction form can be written as \(\frac{58}{1000}\)

Question 2.
22% of \(\frac{6}{7}\)
Answer:
22% can be written as 22/100
22/100 × \(\frac{6}{7}\) = 0.18
0.18 in the fraction form can be written as \(\frac{18}{100}\)

Question 3.
25% of \(\frac{1}{4}\)
Answer:
25% can be written as 25/100
25/100 × \(\frac{1}{4}\) = \(\frac{1}{16}\)

Question 4.
78% of \(\frac{4}{5}\)
Answer:
78% can be written as 78/100
78/100 × \(\frac{4}{5}\) = \(\frac{312}{500}\) = 0.62
0.62 in the fraction form can be written as \(\frac{62}{100}\)

Question 5.
4% of \(\frac{2}{3}\)
Answer:
4% can be written as 4/100
4/100 × \(\frac{2}{3}\) = \(\frac{8}{300}\) = 0.02
0.02 in the fraction form can be written as \(\frac{2}{100}\)

Question 6.
56% of \(\frac{3}{7}\)
Answer:
56% can be written as 56/100
56/100 × \(\frac{3}{7}\) = \(\frac{168}{700}\) = 0.24
0.24 in the fraction form can be written as \(\frac{24}{100}\)

Question 7.
37% of \(\frac{3}{13}\)
Answer:
37% can be written as 37/100
37/100 × \(\frac{3}{13}\) = \(\frac{111}{1300}\) = 0.08
0.08 in the fraction form can be written as \(\frac{8}{100}\)

Question 8.
51% of \(\frac{1}{8}\)
Answer:
51% can be written as 51/100
51/100 × \(\frac{1}{8}\) = \(\frac{51}{800}\) = 0.06
0.06 in the fraction form can be written as \(\frac{6}{100}\)

Question 9.
44% of \(\frac{4}{9}\)
Answer:
44% can be written as 44/100
44/100 × \(\frac{4}{9}\) = \(\frac{176}{900}\) = 0.19
0.19 in the fraction form can be written as \(\frac{19}{100}\)

Question 10.
10% of \(\frac{3}{17}\)
Answer:
10% can be written as 10/100
10/100 × \(\frac{3}{17}\) = \(\frac{30}{1700}\) = 0.017
0.017 in the fraction form can be written as \(\frac{17}{1000}\)

Give the answer rounded to two digits to the right of the decimal point.

Question 11.
\(\frac{3}{5}\) of 20.2%
Answer:
\(\frac{3}{5}\) × 20.2%
\(\frac{3}{5}\) × \(\frac{202}{1000}\)
\(\frac{3}{5}\) × 0.202
0.6 × 0.202 = 0.12

Question 12.
\(\frac{1}{11}\) of 37%
Answer:
\(\frac{1}{11}\) of 37%
\(\frac{1}{11}\) × \(\frac{37}{100}\)
\(\frac{3}{5}\) × 0.37
0.09 × 0.37 = 0.03

Question 13.
\(\frac{3}{4}\) of 75.75%
Answer:
\(\frac{3}{4}\) of 75.75%
\(\frac{3}{4}\) × \(\frac{7575}{10000}\)
\(\frac{3}{4}\) × 0.7575
0.75 × 0.7575 = 0.57

Question 14.
\(\frac{2}{3}\) of 66%
Answer:
\(\frac{2}{3}\) of 66%
\(\frac{2}{3}\) × \(\frac{66}{100}\)
\(\frac{2}{3}\) × 0.66
0.66 × 0.66 = 0.44

Question 15.
\(\frac{1}{8}\) of 88.08%
Answer:
\(\frac{1}{8}\) of 88.08%
\(\frac{1}{8}\) × \(\frac{8808}{10000}\)
\(\frac{1}{8}\) × 0.8808
0.125 × 0.8808 = 0.11

Question 16.
\(\frac{3}{13}\) of 152%
Answer:
\(\frac{3}{13}\) of 152%
\(\frac{3}{13}\) × \(\frac{152}{100}\)
\(\frac{3}{13}\) × 1.52
0.23 × 1.52 = 0.35

Question 17.
\(\frac{3}{8}\) of 225%
Answer:
\(\frac{3}{8}\) of 225%
\(\frac{3}{8}\) × \(\frac{225}{100}\)
0.375 × 2.25 = 0.84

Question 18.
\(\frac{5}{6}\) of 11%
Answer:
\(\frac{5}{6}\) of 11%
\(\frac{5}{6}\) × \(\frac{11}{100}\)
0.83 × 0.11 = 0.09

Question 19.
\(\frac{2}{17}\) of 34.34%
Answer:
\(\frac{2}{17}\) of 34.34%
\(\frac{2}{17}\) × \(\frac{3434}{10000}\)
0.11 × 0.3434 = 0.04

Question 20.
\(\frac{1}{4}\) of .024%
Answer:
\(\frac{1}{4}\) of .024%
\(\frac{1}{4}\) × \(\frac{24}{100000}\)
0.25 × 0.00024 = 0.00006