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Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations

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Go Math Grade 8 Chapter 5 Writing Linear Equations Answer Key

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Lesson 1: Writing Linear Equations from Situations and Graphs 

Lesson 2: Writing Linear Equations from a Table

Lesson 3: Linear Relationships and Bivariate Data

Model Quiz

Mixed Review

Guided Practice – Writing Linear Equations from Situations and Graphs – Page No. 130

Question 1.
Li is making beaded necklaces. For each necklace, she uses 27 spacers, plus 5 beads per inch of necklace length. Write an equation to find how many beads Li needs for each necklace.
a. input variable:
____________

Answer:
The length of the necklace in inches

Question 1.
b. output variable:
____________

Answer:
The total number of beads in the necklace

Question 1.
c. equation:
Type below:
____________

Answer:
y = 5x

Writing Linear Equations Worksheet Answer Key Question 2.
Kate is planning a trip to the beach. She estimates her average speed to graph her expected progress on the trip. Write an equation in slope-intercept form that represents the situation.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 1: Writing Linear Equations from Situations and Graphs img 1
Type below:
____________

Answer:
y = -60x + 300

Explanation:
Choose two points on the graph to find the slope.
Find the slope
m = (y2 -y1)/(x2 – x1)
m = -300/5 = -60
Read the y-intercept from the graph: b = 300
Use your slope and y-intercept values to write an equation in slope-intercept
form.
y = -60x + 300

Question 3.
At 59 °F, crickets chirp at a rate of 76 times per minute, and at 65 °F, they chirp 100 times per minute. Write an equation in slope-intercept form that represents the situation.
Type below:
____________

Answer:
y = 4x – 160

Explanation:
Input variable: Temperature
Output variable: Number of chirps per minute
Slope:
m = (y2 -y1)/(x2 – x1) = (100 – 76)/(65 – 59) = 24/6 = 4
100 = 4(65) + b
y-intercept:
b = -160
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 4 and b = -160.
y = 4x – 160

Essential Question Check-In

Question 4.
Explain what m and b in the equation y = mx + b tell you about the graph of the line with that equation.
Type below:
____________

Answer:
The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept.
m = change in y-value/change in x-value
The y-intercept of this line is the value of y at the point where the line crosses the y-axis.

Independent Practice – Writing Linear Equations from Situations and Graphs – Page No. 131

Question 5.
A dragonfly can beat its wings 30 times per second. Write an equation in slope-intercept form that shows the relationship between flying time in seconds and the number of times the dragonfly beats its wings
Type below:
____________

Answer:
y = 30x

Explanation:
The linear equation is y = mx + b where m is the slope and b is the y-intercept.
y variable will be the number of times the dragonfly has beat its wings and the x variable will be the time.
A dragonfly can beat its wings 30 times per second.
To find b, let’s consider how many times the dragonfly has beat its wings at time 0s.
So, the equation of the line is y = 30x

5.1 Understanding Linear Functions Answer Key Question 6.
A balloon is released from the top of a platform that is 50 meters tall. The balloon rises at the rate of 4 meters per second. Write an equation in slope-intercept form that tells the height of the balloon above the ground after a given number of seconds.
Type below:
____________

Answer:
y = 4x + 50

Explanation:
Input variable: Number of seconds
Output variable: Height of the balloon
The balloon rises at a rate of 4 meters per second. m = 4;
A balloon is released from the top of a platform that is 50 meters tall. b = 50.
y = 4x + 50

The graph shows a scuba diver’s ascent over time.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 1: Writing Linear Equations from Situations and Graphs img 2

Question 7.
Use the graph to find the slope of the line. Tell what the slope means in this context.
Slope = _______ meters per second

Answer:
Slope = 1/8 or 0.125 meters per second

Explanation:
10m/80sec = 1/8
The scuba diver’s ascent gives up 1 meter per 16 seconds.

Question 8.
Identify the y-intercept. Tell what the y-intercept means in this context.
y-intercept = _______ meters

Answer:
y-intercept = -10 meters

Explanation:
The scuba divers start 10 meters below the water surface

Question 9.
Write an equation in slope-intercept form that represents the diver’s depth over time.
Type below:
____________

Answer:
y = 1/8 x – 10

Writing Linear Equations Quiz Answer Key Question 10.
The formula for converting Celsius temperatures to Fahrenheit temperatures is a linear equation. Water freezes at 0°C, or 32°F, and it boils at 100°C, or 212°F. Find the slope and y-intercept for a graph that gives degrees Celsius on the horizontal axis and degrees Fahrenheit on the vertical axis. Then write an equation in slope-intercept form that converts degrees Celsius into degrees Fahrenheit.
Type below:
____________

Answer:
Input variable: Celsius
Output variable: Fahrenheit
(0, 32) (100, 212)
m = (y2 -y1)/(x2 – x1) = (212 – 32)/(100 – 0) = 180/100 = 1.8
y intercepts = 32 when x = 0
F = 1.8C + 32

Question 11.
The cost of renting a sailboat at a lake is $20 per hour plus $12 for lifejackets. Write an equation in slope-intercept form that can be used to calculate the total amount you would pay for using this sailboat.
Type below:
____________

Answer:
y = 20x + 12

Explanation:
Input variable: Number of hours the sailboat is rented
Output variable: Total cost
The cost of renting a sailboat at a lake is $20 per hour plus $12 for lifejackets.
Slope m = 20; y-intercept b = 12
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 20 and b = 12.
y = 20x + 12

Writing Linear Equations from Situations and Graphs – Page No. 132

The graph shows the activity in a savings account.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 1: Writing Linear Equations from Situations and Graphs img 3

Question 12.
What was the amount of the initial deposit that started this savings account?
$ _______

Answer:
$1000

Explanation:
The amount of the initial deposit that started this savings account is $1000

Question 13.
Find the slope and y-intercept of the graphed line.
Type below:
____________

Answer:
slope = 500
y-intercept = 1000

Explanation:
slope m = (y2 -y1)/(x2 – x1) = (2000 – 1500)/(2 – 1) = 500/1 = 500
y-intercept = 1000

Chapter 5 Analyzing Linear Equations Answer Key Question 14.
Write an equation in slope-intercept form for the activity in this savings account.
Type below:
____________

Answer:
y = 500x + 1000

Explanation:
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 500 and b = 1000.
y = 500x + 1000

Question 15.
Explain the meaning of the slope in this graph.
Type below:
____________

Answer:
The slope represents the amount of money saved in dollars per month in the plan.

H.O.T.

Focus on Higher Order Thinking

Question 16.
Communicate Mathematical Ideas
Explain how you decide which part of a problem will be represented by the variable x, and which part will be represented by the variable y in a graph of the situation.
Type below:
____________

Answer:
y=mx+b
M-slope
B-Y intercept
and
(x,y)- would be any point on the graph and if you were to plug those points in for x and y the equation would solve if done properly

Question 17.
Represent Real-World Problems
Describe what would be true about the rate of change in a situation that could not be represented by a graphed line and an equation in the form y = mx + b.
Type below:
____________

Answer:
The rate of change would not be constant. Using different pairs of points in the slope formula would give different results.

Question 18.
Draw Conclusions
Must m, in the equation y = mx + b, always be a positive number? Explain.
Type below:
____________

Answer:
No; The slope m can be negative or positive. If the slope of the number is positive (the graph goes upward from left to right), then m will be positive, but if the slope is negative (the graph goes down from left to right), then m is negative.

Guided Practice – Writing Linear Equations from a Table – Page No. 136

Question 1.
Jaime purchased a $20 bus pass. Each time he rides the bus, a certain amount is deducted from the pass. The table shows the amount, y, left on his pass after x rides. Graph the data, and find the slope and y-intercept from the graph or from the table. Then write the equation for the graph in slope-intercept form.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 4
Type below:
____________

Answer:
Grade 8 Chapter 5 image 1
y = -5/4 x + 20

Explanation:
Slope = -20/16 = -5/4 = -1.25
y-intercepts = 20
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -1.25 and b = 20.
y = -5/4 x + 20

The table shows the temperature (y) at different altitudes (x). This is a linear relationship.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 5

Question 2.
Find the slope for this relationship.
_______

Answer:
Slope m = (y2 -y1)/(x2 – x1) = (51 – 59)/(2000 – 0) = -8/2000 = -0.004

Explanation:
(x1, y1) = (0, 59), (x2, y2) = (2000, 51)
Slope m = (y2 -y1)/(x2 – x1) = (51 – 59)/(2000 – 0) = -8/2000 = -0.004

Writing Equations from a Table Worksheet Answer Key Pdf Question 3.
Find the y-intercept for this relationship.
y-intercept = _______

Answer:
b = 50

Explanation:
y-intercept = 59 when x = 0

Question 4.
Write an equation in slope-intercept form that represents this relationship.
Type below:
____________

Answer:
y = -0.004x + 59

Explanation:
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -0.004 and b = 59.

Question 5.
Use your equation to determine the temperature at an altitude of 5000 feet.
_______ °F

Answer:
39°F

Explanation:
y = -0.004x + 59
y = -0.004(5000) + 59 = -20 + 59 = 39
The temperature is 39°F at the altitude of 5000 feet.

Essential Question Check-In

Question 6.
Describe how you can use the information in a table showing a linear relationship to find the slope and y-intercept for the equation.
Type below:
____________

Answer:
Use any two points from the table to fins teh slope.
Slope m = (y2 -y1)/(x2 – x1)
If the value of y-intercept, when x=0 is not given in the table, use the slope and any ordered pair from the table and substitute in slope-intercept from y=mx + b to find b.

Independent Practice – Writing Linear Equations from a Table – Page No. 137

Question 7.
The table shows the costs of a large cheese pizza with toppings at a local pizzeria. Graph the data, and find the slope and y-intercept from the graph. Then write the equation for the graph in slope-intercept form.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 6
Type below:
____________

Answer:
Grade 8 Chapter 5 image 2

Slope m = (y2 -y1)/(x2 – x1) = (10 – 8)/(1 – 0) = 2/1 = 2
y-intercept b = 8
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 2 and b = 8.
y = 2x + 8

Writing Linear Equations from a Table Worksheet Question 8.
The table shows how much an air-conditioning repair company charges for different numbers of hours of work. Graph the data, and find the slope and y-intercept from the graph. Then write the equation for the graph in slope-intercept form.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 7
Type below:
____________

Answer:
Grade 8 Chapter 5 image 3

Slope m = (y2 -y1)/(x2 – x1) = (100 – 50)/(1 – 0) = 50/1 = 50
y-intercept b = 50
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 50 and b = 50.
y = 50x + 50

Question 9.
A friend gave Ms. Morris a gift card for a local car wash. The table shows the linear relationship of how the value left on the card relates to the number of car washes.
a. Write an equation that shows the number of dollars left on the card.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 8
Type below:
____________

Answer:
y = -1.50x + 30

Explanation:
Slope m = (y2 -y1)/(x2 – x1) = (18 – 30)/(8 – 0) = -12/8 = -1.5
y-intercept b = 30
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -1.50 and b = 30.
y = -1.50x + 30

Question 9.
b. Explain the meaning of the negative slope in this situation.
Type below:
____________

Answer:
The negative slope means that the amount on the card decreased by $1.5 per car wash

Question 9.
c. What is the maximum value of x that makes sense in this context? Explain.
x = _______

Answer:
x = 20

Explanation:
0 = -1.50x + 30
1.5x = 30
x = 30/1.5 = 20
the maximum value of x = 20

The tables show linear relationships between x and y. Write an equation in slope-intercept form for each relationship.

Question 10.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 9
Type below:
____________

Answer:
Slope m = (y2 -y1)/(x2 – x1) = (3 – 1)/(2 – 0) =  2/2 = 1
y-intercept b = 1
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 1 and b = 1.
y =  x + 1

Writing Equations from a Table Worksheet y=mx+b Answer Key Question 11.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 10
Type below:
____________

Answer:
Slope m = (y2 -y1)/(x2 – x1) = (6 – 4)/(0 – 1) =  -2/1 = -2
y-intercept b = 6
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -2 and b = 6.
y = -2x + 6

Writing Linear Equations from a Table – Page No. 138

Question 12.
Finance
Desiree starts a savings account with $125.00. Every month, she deposits $53.50.
a. Complete the table to model the situation.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 11
Type below:
____________

Answer:
Grade 8 Chapter 5 image 4

Question 12.
b. Write an equation in slope-intercept form that shows how much money Desiree has in her savings account after x months.
Type below:
____________

Answer:
y = 53.5x + 125

Explanation:
Desiree starts a savings account with $125.00. Every month, she deposits $53.50.
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 53.5 and b = 125.
y = 53.5x + 125

Question 12.
c. Use the equation to find how much money Desiree will have in savings after 11 months.
$ ________

Answer:
$713.5

Explanation:
y = 53.5x + 125
The value of x is 11
y = 53.5 (11) + 125 = 588.5 + 125 = 713.5
Desiree will have $713.5 in savings after 11 months.

Graphing and Writing Linear Equations Answer Key Question 13.
Monty documented the amount of rain his farm received on a monthly basis, as shown in the table.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 2: Writing Linear Equations from a Table img 12
a. Is the relationship linear? Why or why not?
Type below:
____________

Answer:
No

Explanation:
The change in the months is constant but the change in rainfall is not constant.

Question 13.
b. Can an equation be written to describe the amount of rain? Explain.
Type below:
____________

Answer:
No

Explanation:
There is no apparent pattern in the given data.

H.O.T.

Focus on Higher Order Thinking

Question 14.
Analyze Relationships
If you have a table that shows a linear relationship, when can you read the value for b, in y = mx + b, directly from the table without drawing a graph or doing any calculations? Explain.
Type below:
____________

Answer:
You can read the value of b directly from the table whrn the table contains the input value of 0 and its corresponding output values (value of y when x = 0)

Question 15.
What If?
Jaíme graphed linear data given in the form (cost, number). The y-intercept was 0. Jayla graphed the same data given in the form (number, cost). What was the y-intercept of her graph? Explain.
Type below:
____________

Answer:
Jaíme graphed linear data given in the form (cost, number). The y-intercept was 0. Jayla graphed the same data given in the form (number, cost).
Jaíme’s graph contained (0, 0). Since Jayal’s data were the same y-intercept is 0 but x and y are switched.

Guided Practice – Linear Relationships and Bivariate Data – Page No. 144

Use the following graphs to find the equation of the linear relationship.

Question 1.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 13
Type below:
____________

Answer:
y = 30x

Explanation:
Grade 8 Chapter 5 image 5
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (1, 30) and (x2, y2) = (2, 60)
Slope m = (y2 -y1)/(x2 – x1) = (60 – 30)/(2 – 1) = 30/1 = 30
y-intercept b = 0
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 30 and b = 0.
y = 30x

Linear Relationships and Bivariate Data Answer Key Question 2.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 14
Type below:
____________

Answer:
y = 2.5x + 2

Explanation:
Grade 8 Chapter 5 image 6
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (2, 7) and (x2, y2) = (4, 12)
Slope m = (y2 -y1)/(x2 – x1) = (12 – 7)/(4 – 2) = 5/2 = 2.5
y-intercept b = 2
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 2.5 and b = 2.
y = 2.5x + 2

Question 3.
The graph shows the relationship between the number of hours a kayak is rented and the total cost of the rental. Write an equation of the relationship. Then use the equation to predict the cost of a rental that lasts 5.5 hours.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 15
Type below:
____________

Answer:
y = 20x + 30
The cost of a rental that lasts 5.5 hours is $140

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (2, 70) and (x2, y2) = (4, 110)
Slope m = (y2 -y1)/(x2 – x1) = (110 – 70)/(4 – 2) = 40/2 = 20
y-intercept b = 30
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 20 and b = 30.
y = 20x + 30
Substitute the value of x is 5.5 hrs
y = 20 (5.5) + 30
y = 110 + 30 = 140
The cost of a rental that lasts 5.5 hours is $140

Does each of the following graphs represent a linear relationship? Why or why not?

Question 4.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 16
____________

Answer:
Yes; The graph has a constant rate of change

Explanation:
Find the slope using two points from the graph by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (2, 6) and (x2, y2) = (5, 15)
Slope m = (y2 -y1)/(x2 – x1) = (15 – 6)/(5 – 2) = 9/3 = 3
y-intercept b = 6
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 3 and b = 6.
y = 3x + 6
The values change according to the constant change in the x values.

Question 5.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 17
____________

Answer:
No; The graph does not have a constant rate of change

Essential Question Check-In

Question 6.
How can you tell if a set of bivariate data shows a linear relationship?
Type below:
____________

Answer:
It is a linear relationship if the rate of change is constant or the graph is a straight line.

Independent Practice – Linear Relationships and Bivariate Data – Page No. 145

Does each of the following tables represent a linear relationship? Why or why not?

Question 7.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 18
____________

Answer:
Linear Relationship

Explanation:
Find Rate of Change using Slope m = (y2 -y1)/(x2 – x1)
Rate of Change = (45 – 15)/(9 – 3) = 30/6 = 5
Rate of Change = (105 – 45)/(21 – 9) = 60/12 = 5
It is a Linear Relationship as the rate of the change is constant.

Question 8.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 19
____________

Answer:
not a Linear Relationship

Explanation:
Find Rate of Change using Slope m = (y2 -y1)/(x2 – x1)
Rate of Change = (76.8 – 30)/(8 – 5) = 46./3 = 15.6
Rate of Change = (235.2 – 76.8)/(14 – 8) = 158.4/6 = 26.4
It is not a Linear Relationship as the rate of the change is varies.

Explain whether or not you think each relationship is linear.

Question 9.
the cost of equal-priced DVDs and the number purchased
____________

Answer:
y = cx

Explanation:
The relation between the cost of equal-priced DVDs and the number purchased is linear because the change rate is constant. If we denote with c the cost of a DVD, with x the number of purchased DVDs and with y the total cost of the purchased DVDs, we get an equation of the form:
y = cx

Question 10.
the height of a person and the person’s age
____________

Answer:
Non – Linear relationship

Explanation:
The height of a person does not increase at a constant rate with a person’s age

Question 11.
the area of a square quilt and its side length
____________

Answer:
Non – Linear relationship

Explanation:
The rate of change in the area of a square quilt increase as the side length increases.

Question 12.
the number of miles to the next service station and the number of kilometers
____________

Answer:
Linear relationship

Explanation:
The number of miles increases at a constant rate with the number of kilometers.

Question 13.
Multistep
The Mars Rover travels 0.75 feet in 6 seconds. Add the point to the graph. Then determine whether the relationship between distance and time is linear, and if so, predict the distance that the Mars Rover would travel in 1 minute.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 20
Distance traveled in 1 min.: _______ ft.

Answer:
Relationship is linear
Distance traveled in 1 min.: 7.5 ft.

Explanation:
Grade 8 Chapter 5 image 7
The graph is a straight line. So, the Relationship is linear
The equation representing the relationship between distance and time.
y = 0.125x
The value of x is 1 min = 60 sec
y = 0.125 (60) = 7.5 ft
Distance traveled in 1 min.: 7.5 ft.

Linear Relationships and Bivariate Data – Page No. 146

Question 14.
Make a Conjecture
Zefram analyzed a linear relationship, found that the slope-intercept equation was y=3.5x+16, and made a prediction for the value of y for a given value of x. He realized that he made an error calculating the y-intercept and that it was actually 12. Can he just subtract 4 from his prediction if he knows that the slope is correct? Explain.
____________

Answer:
Yes

Explanation:
The value of y is calculated using y = 3.5x+ 16. Since the slope of the point remains the same, 4 can be subtracted from the predicted answer as the value of y would be: y = 3.5x+ 16 – 4

H.O.T.

Focus on Higher Order Thinking

Question 15.
Communicate Mathematical Ideas
The table shows a linear relationship. How can you predict the value of y when x = 6 without finding the equation of the relationship?
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Lesson 3: Linear Relationships and Bivariate Data img 21
Type below:
____________

Answer:
57

Explanation:
Find Rate of Change using Slope m = (y2 -y1)/(x2 – x1)
Rate of Change = (76 – 38)/(8 – 4) = 38/4 = 9.5
Since the difference between 8 and S is 2, subtract twice the value of the rate of change from 76
y = 76 – (9.5 × 2) =57

Question 16.
Critique Reasoning
Louis says that if the differences between the values of x are constant between all the points on a graph, then the relationship is linear. Do you agree? Explain.
____________

Answer:
No

Explanation:
The difference between y should be constant for a constant interval of x.

Question 17.
Make a Conjecture
Suppose you know the slope of a linear relationship and one of the points that its graph passes through. How could you predict another point that falls on the graph of the line?
Type below:
____________

Answer:
Find the equation of the linear relationship using the slope and given point. The insert any x-value to find a y value on the graph of the line.

Question 18.
Explain the Error
Thomas used (7, 17.5) and (18, 45) from a graph to find the equation of a linear relationship as shown. What was his mistake?
m = \(\frac{45-7}{18-17.5}=\frac{38}{0.5}\) = 79
y = 79x + b =
49 = 79 × 18 + b
45 = 1422 + b, so b = −1337
The equation is y = 79x − 1377
Type below:
____________

Answer:
He subtracted the x value of the first point from the y of the second point and the y value of the second point from the x value of the first point.
Hence, the slope is incorrect and the equation is incorrect as well. The correct slope is
(45 – 17.5)/(18 – 7) = 27.5/11 = 2.5

5.1 Writing Linear Equations from Situations and Graphs – Model Quiz – Page No. 147

Write the equation of each line in slope-intercept form.

Question 1.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Model Quiz img 22
Type below:
____________

Answer:
y = 30x + 20

Explanation:
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 20), (x2, y2) = (2, 80)
Substitute the value of m and (x1, y1) = (0, 20), (x2, y2) = (2, 80)
Slope m = (y2 -y1)/(x2 – x1) = (80 – 20)/(2 – 0) = 60/2 = 30
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
80 = 30(2) + b
y-intercept b = 20
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 30 and b = 20.
y = 30x + 20

Writing Linear Equations from Situations and Graphs Lesson 5.1 Answer Key Question 2.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Model Quiz img 23
Type below:
____________

Answer:
y = -10x + 60

Explanation:
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (6, 0), (x2, y2) = (0, 60)
Substitute the value of m and (x1, y1) = (6, 0), (x2, y2) = (0, 60)
Slope m = (y2 -y1)/(x2 – x1) = (60 – 0)/(0 – 6) = -60/6 = -10
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
60 = -10(0) + b
y-intercept b = 60
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -10 and b = 60.
y = -10x + 60

5.2 Writing Linear Equations from a Table

Write the equation of each linear relationship in slope-intercept form.

Question 3.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Model Quiz img 24
Type below:
____________

Answer:
y = 0.35x + 1.5

Explanation:
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 1.5), (x2, y2) = (100, 36.5)
Substitute the value of m and (x1, y1) = (0, 1.5), (x2, y2) = (100, 36.5)
Slope m = (y2 -y1)/(x2 – x1) = (36.5 – 1.5)/(100 – 0) = 35/100 = 0.35
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
1.5 =0.35(0) + b
y-intercept b = 1.5
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 0.35 and b = 1.5.
y = 0.35x + 1.5

Question 4.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Model Quiz img 25
Type below:
____________

Answer:
y = -0.6x + 109

Explanation:
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (25, 94), (x2, y2) = (35, 88)
Substitute the value of m and (x1, y1) = (25, 94), (x2, y2) = (35, 88)
Slope m = (y2 -y1)/(x2 – x1) = (88 – 94)/(35 – 25) = -6/10 = -0.6
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
88 = -0.6(35) + b
y-intercept b = 109
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -0.6 and b = 109.
y = -0.6x + 109

5.3 Linear Relationships and Bivariate Data

Write the equation of the line that connects each set of data points.

Question 5.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Model Quiz img 26
Type below:
____________

Answer:
y = 2/3x + 26 2/3

Explanation:
Grade 8 Chapter 5 image 8
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (20, 40), (x2, y2) = (50, 60)
Substitute the value of m and (x1, y1) = (20, 40), (x2, y2) = (50, 60)
Slope m = (y2 -y1)/(x2 – x1) = (60 – 40)/(50 – 20) = 20/30 = 2/3
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
40 = 2/3(20) + b
y-intercept b = 26 2/3
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 2/3 and b = 26 2/3.
y = 2/3x + 26 2/3

8th Grade Math Linear Equations Question 6.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Model Quiz img 27
Type below:
____________

Answer:
y = -3x + 140

Explanation:
Grade 8 Chapter 5 image 9
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (25, 65), (x2, y2) = (30, 50)
Substitute the value of m and (x1, y1) = (25, 65), (x2, y2) = (30, 50)
Slope m = (y2 -y1)/(x2 – x1) = (50 – 65)/(30 – 25) = -15/5 = -3
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
50 = -3(30) + b
y-intercept b = 140
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -3 and b = 140.
y = -3x + 140

Essential Question

Question 7.
Write a real-world situation that can be represented by a linear relationship.
Type below:
____________

Answer:
There is an hourly fee of $15 for renting the ski gear per hour and an entry fee of $10 for the ski lodge.

Selected Response – Mixed Review – Page No. 148

Question 1.
An hourglass is turned over with the top part filled with sand. After 3 minutes, there are 855 mL of sand in the top half. After 10 minutes, there are 750 mL of sand in the top half. Which equation represents this situation?
Options:
a. y = 285x
b. y = −10.5x + 900
c. y = −15x + 900
d. y = 75x

Answer:
c. y = −15x + 900

Explanation:
Identify the input and output variable
Input: Number of minutes
Output: Quantity of sand in the hourglass
Write the given information as ordered pair (3, 855), (10, 750)
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (10, 750), (x2, y2) =(3, 855)
Substitute the value of m and (x1, y1) = (10, 750), (x2, y2) =(3, 855)
Slope m = (y2 -y1)/(x2 – x1) = (855 – 750)/(3 – 10) = -105/7 = -15
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
750 = -15(10) + b
y-intercept b = 900
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -15 and b = 900.
y = -15x + 900

Linear Equations Project-Based Learning Answer Key Question 2.
Which graph shows a linear relationship?
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Mixed Review img 28
Options:
a. A
b. B
c. C
d. D

Answer:
b. B

Explanation:
Graph B represents the linear relationship
The data appears to lie on a straight line

Question 3.
What are the slope and y-intercept of the relationship shown in the table?
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Mixed Review img 29
Options:
a. slope = 0.05, y-intercept = 1,500
b. slope = 0.5, y-intercept = 1,500
c. slope = 0.05, y-intercept = 2,000
d. slope = 0.5, y-intercept = 2,000

Answer:
c. slope = 0.05, y-intercept = 2,000

Explanation:
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (10,000, 2,500), (x2, y2) =(20,000, 3,000)
Substitute the value of m and (x1, y1) = (10,000, 2,500), (x2, y2) =(20,000, 3,000)
Slope m = (y2 -y1)/(x2 – x1) = (3,000 – 2,500)/(20,000 – 10,000) = 500/10,000 = 0.05
Substituting the value of slope (m) and (x, y) in the slope intercept form to find y intercept (b):
3,000 = 0.05(20,000) + b
y-intercept b = 2,000

Question 4.
Which is the sum of 3.15 × 107 + 9.3 × 106? Write your answer in scientific notation.
Options:
a. 4.08 × 107
b. 4.08 × 106
c. 0.408 × 108
d. 40.8 × 106

Answer:
a. 4.08 × 107

Explanation:
Given 3.15 × 107 + 9.3 × 106?
(3.15 + 0.93) × 107
4.08 × 107

Mini-Task

Lesson 5 Skills Practice Graph A Line Using Intercepts Question 5.
Franklin’s faucet was leaking, so he put a bucket underneath to catch the water. After a while, Franklin started keeping track of how much water was in the bucket. His data is in the table below.
Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations Mixed Review img 30
a. Is the relationship linear or nonlinear?
_____________

Answer:
The relationship linear

Explanation:
Find the rate of change by Difference in Quarts/Hours
(6.5 – 5)/(3 – 2) = 1.5
(8 – 6.5)/(4 – 3) = 1.5
(9.5 – 8)/(5 – 4) = 1.5
Since the rate of change is constant, the relationship is linear.

Question 5.
b. Write the equation for the relationship.
Type below:
_____________

Answer:
Rate of change is the slope of the linear equation
m = 1.5

Question 5.
c. Predict how much water will be in the bucket after 14 hours if Franklin doesn’t stop the leak.
_______ quarts

Answer:
23 quarts

Explanation:
Substituting the value of slope (m) and (x, y) in the slope intercept form to find y-intercept (b)
y = mx + b
5 = 1.5(2) + b
y-intercept b = 2
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 1.5 and b = 2.
y = 1.5x + 2
The x value is 2
y = 1.5(2) + 2 = 23
There will be 23 quarts after 14 hrs.

Conclusion:

Go Math Grade 8 Answer Key Chapter 5 Writing Linear Equations PDF to Download. Learn the modern maths in a simple way with the help of Go Math Grade 8 Chapter 5 Answer Key. Quickly begin your learning by downloading a PDF of Go Math Grade 8 Chapter 5 Writing Linear Equations Solution Key.

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Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships

The best Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships PDF for more people who are seeking for math learning in an easy way. Find the top-suggested ways of math problem-solving methods and learn the best way to solve math. The list of all practice questions of Go Math Grade 8 Answer Key are given here in this article. The students can find and practice all the questions to score the good marks in the exam.

Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships

You can enjoy solving math problems with the help of Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships. Download Go Math Grade 8 Chapter 4 Nonproportional Relationships Solution Key. Many students refer to HMH Go Math Grade 8 Chapter 4 Answer Key for the best practice.

Lesson 1: Representing Linear Nonproportional Relationships

Lesson 2: Determining Slope and y-intercept

Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept

Lesson 4: Proportional and Nonproportional Situations 

Lesson 5: Representing Linear Nonproportional Relationships – Model Quiz

Mixed Review 

Guided Practice – Representing Linear Nonproportional Relationships – Page No. 98

Make a table of values for each equation.

Question 1.
y = 2x + 5
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 1
Type below:
____________

Answer:
grade 8 chapter 4 image 13

Explanation:
y = 2x + 5
Choose several values for x and substitute in the equation to find y.
x = 2(-2) + 5 = 1
x = 2(-1) + 5 = 3
x = 2(0) + 5 = 5
x = 2(1) + 5 = 7
x = 2(2) + 5 = 9

Graphing Linear Nonproportional Relationships Worksheet Answers Question 2.
y = \(\frac{3}{8}\)x − 5
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 2
Type below:
____________

Answer:
grade 8 chapter 4 image 14

Explanation:
y = \(\frac{3}{8}\)x − 5
Choose several values for x and substitute in the equation to find y.
x = 3/8(-8) – 5 = -8
x = 3/8(0) – 5 = -5
x = 3/8(8) – 5 = -2
x = 3/8(16) – 5 = 1
x = 3/8(24) – 5 = 4

Explain why each relationship is not proportional.

Question 3.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 3
First calculate \(\frac{y}{x}\) for the values in the table.
____________

Answer:
The relationship is not proportional

Explanation:
Find y/x
3/0 = undefined
7/2 = 3.5
11/4 = 2.75
15/6 = 2.5
19/8 = 2.375
The ratio is not constant, hence relationship is not proportional.

Question 4.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 4
__________________

Answer:
The graph is a straight line but does not pass through the origin. So, the relationship is not proportional.

Complete the table for the equation. Then use the table to graph the equation.

Question 5.
y = x − 1
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 5
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 6
Type below:
____________

Answer:
grade 8 chapter 4 image 15

grade 8 chapter 4 image 16

Explanation:
y = x – 1
Choose several values of x and substitute in the equation to find y to draw a table.
x = -2; y = -2 – 1 = -2
x = -1; y = -1 -1 = -2
x = 0; y = 0 -1 = -1
x = 1; y = 1 – 1 = 0
x = 2; y = 2 -1 = 1
Also, Plot the ordered pairs from the table. Then draw a line connecting the points to represent all the possible solutions

Essential Question Check-In

Question 6.
How can you choose values for x when making a table of values representing a real-world situation?
Type below:
____________

Answer:
When choosing values for x in a real-world situation, you choose positive values with an appropriate interval to represent the array of data.

Independent Practice – Representing Linear Nonproportional Relationships – Page No. 99

State whether the graph of each linear relationship is a solid line or a set of unconnected points. Explain your reasoning.

Question 7.
The relationship between the number of $4 lunches you buy with a $100 school lunch card and the money remaining on the card
____________

Answer:
Set of unconnected points.

Explanation:
You cannot buy a fractional part of a lunch.
Set of unconnected points.

Question 8.
The relationship between time and the distance remaining on a 3-mile walk for someone walking at a steady rate of 2 miles per hour.
____________

Answer:
A solid line

Explanation:
The relationship between time and the distance remaining on a 3-mile walk for someone walking at a steady rate of 2 miles per hour. The distance remaining can be a fraction. The time can be in a fraction as well.
A solid line

Nonproportional Relationship Graph Question 9.
Analyze Relationships
Simone paid $12 for an initial year’s subscription to a magazine. The renewal rate is $8 per year. This situation can be represented by the equation y = 8x + 12, where x represents the number of years the subscription is renewed and y represents the total cost.
a. Make a table of values for this situation.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 7
Type below:
____________

Answer:
grade 8 chapter 4 image 17

Explanation:
y = 8x + 12
Choose several values for x and substitute in the equation to find y.

Question 9.
b. Draw a graph to represent the situation. Include a title and axis labels.
Type below:
____________

Answer:
grade 8 chapter 4 image 18

Explanation:
Plot the ordered pairs from the table. Then draw a line connecting the points to represent all the possible solutions

Question 9.
c. Explain why this relationship is not proportional.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 8
Type below:
____________

Answer:
It is not proportional as the graph does not pass through the origin

Explanation:
When a relationship is proportional, the graph of the equation passes through the origin.
It is not proportional as the graph does not pass through the origin

Question 9.
d. Does it make sense to connect the points on the graph with a solid line? Explain.
Type below:
____________

Answer:
No

Explanation:
No; The subscription is renewed for the entire year and cannot be done for a fraction of the year. The number of years must be a whole numb, so the total cost goes up in $8 increments.

Representing Linear Nonproportional Relationships – Page No. 100

Question 10.
Analyze Relationships
A proportional relationship is a linear relationship because the rate of change is constant (and equal to the constant of proportionality). What is required of a proportional relationship that is not required of a general linear relationship?
Type below:
____________

Answer:
The ratio between one quantity to the other quantity should be constant for a proportional linear relationship. The graph should be a straight line that passes through the origin.

Lesson 4.1 Representing Linear Nonproportional Relationships Answer Key Question 11.
Communicate Mathematical Ideas
Explain how you can identify a linear non-proportional relationship from a table, a graph, and an equation.
Type below:
____________

Answer:
In a table, the ratios y/x will not be equal. A graph will not pass through the origin. An equation will be in the form y = mx + b where b is not equal to 0.

Focus on Higher Order Thinking

Question 12.
Critique Reasoning
George observes that for every increase of 1 in the value of x, there is an increase of 60 in the corresponding value of y. He claims that the relationship represented by the table is proportional. Critique George’s reasoning.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 1: Representing Linear Nonproportional Relationships img 9
Type below:
____________

Answer:
The ratio is not constant, hence the relationship cannot be proportional.

Explanation:
Find y/x
90/1 = 90
150/2 = 75
210/3 = 70
270/4 = 67.5
330/5 = 66
The ratio is not constant, hence the relationship cannot be proportional.

Question 13.
Make a Conjecture
Two parallel lines are graphed on a coordinate plane. How many of the lines could represent proportional relationships? Explain.
Type below:
____________

Answer:
Maximum one

Explanation:
When there are two parallel lines, only one can pass through the origin and a line representing a proportional relationship must pass through the origin.
Maximum one

Guided Practice – Determining Slope and y-intercept – Page No. 104

Find the slope and y-intercept of the line in each graph.

Question 1.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 10
slope m = _____ y-intercept b = _____
m = ____________
b = ____________

Answer:
slope m = -2 y-intercept b = 1
m = -2
b = 1

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 1) and (x2, y2) = (2, -3)
Slope m = (y2 -y1)/(x2 – x1) = (-3 – 1)/(2 – 0) = -4/2 = -2
From the graph when x = 0
y-intercept (b) = 1

Lesson 4.2 Determining Slope and Y-Intercept Answer Key Pdf Question 2.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 11
slope m = _____ y-intercept b = _____
m = ____________
b = ____________

Answer:
slope m = 5 y-intercept b = -15
m = 5
b = -15

Explanation:
Find the slope using two points from the graph by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (3, 0) and (x2, y2) = (0, -15)
Slope m = (y2 -y1)/(x2 – x1) = (-15 – 0)/(0 – 3) = 15/3 = 5
From the graph when x = 0
y-intercept (b) = -15

Question 3.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 12
slope m = _____ y-intercept b = _____
Type below:
____________

Answer:
slope m = 3/2 y-intercept b = -2
m = 3/2
b = -2

Explanation:
Find the slope using two points from the graph by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, -2) and (x2, y2) = (2, 1)
Slope m = (y2 -y1)/(x2 – x1) = (1 – (-2))/(2 – 0) = 3/2
From the graph when x = 0
y-intercept (b) = -2

Question 4.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 13
slope m = _____ y-intercept b = _____
m = ____________
b = ____________

Answer:
slope m = -3 y-intercept b = 9
m = -3
b = 9

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (3, 0) and (x2, y2) = (0, 9)
Slope m = (y2 -y1)/(x2 – x1) = (9 – 0))/(0 – 3) = -9/3 = -3
From the graph when x = 0
y-intercept (b) = 9

Find the slope and y-intercept of the line represented by each table.

Question 5.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 14
slope m = _____ y-intercept b = _____
m = ____________
b = ____________

Answer:
slope m = 3 y-intercept b = 1
m = 3
b = 1

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (8, 25) and (x2, y2) = (6, 19)
Slope m = (y2 -y1)/(x2 – x1) = (19 – 25)/(6 – 8) = 6/2 = 3
From the graph when x = 0
y-intercept (b) = 1

Question 6.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 15
slope m = _____ y-intercept b = _____
m = ____________
b = ____________

Answer:
slope m = -4 y-intercept b = 140
m = -4
b = 140

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (5, 120) and (x2, y2) = (15, 80)
Slope m = (y2 -y1)/(x2 – x1) = (80 – 120)/(15 – 5) = -40/10 = -4
From the graph when x = 0
y-intercept (b) = 140

Essential Question Check-In

Question 7.
How can you determine the slope and the y-intercept of a line from a graph?
Type below:
____________

Answer:
Choose any two points on the line from the graph and use it to find the slope. Determine the point where the line crosses the y-axis to find the y-intercept.

Independent Practice – Determining Slope and y-intercept – Page No. 105

Question 8.
Some carpet cleaning costs are shown in the table. The relationship is linear. Find and interpret the rate of change and the initial value for this situation.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 16
Type below:
_____________

Answer:
Find the slope using two points
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (1, 125) and (x2, y2) = (3, 225)
Slope m = (y2 -y1)/(x2 – x1) = (225 – 125)/(3 – 1) = 100/2 = 50
Find the initial value when the value of x is 0
Work backward from x = 1 to x = 0
(175 – 125)/(2 – 1) = 50/1 = 50
Subtract the difference of x and y from the first point.
x = 1 – 1 = 0
y = 125 – 50 = 75
y-intercept (b) = 75
The slope/rate of change represents the increase in the cost of cleaning the rooms for a unit increase in the number of rooms. The y-intercept shows the initial cost of carpet cleaning.

Question 9.
Make Predictions
The total cost to pay for parking at a state park for the day and rent a paddleboat are shown.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 17
a. Find the cost to park for a day and the hourly rate to rent a paddleboat.
Type below:
_____________

Answer:
$5

Explanation:
Find the slope using two points
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (1, 17) and (x2, y2) = (2, 29)
Slope m = (y2 -y1)/(x2 – x1) = (29 – 17)/(2 – 1) = 12/1 = 12
Find the initial value when the value of x is 0
Work backward from x = 1 to x = 0
(29 – 17)/(2 – 1) = 12/1 = 12
Subtract the difference of x and y from the first point.
x = 1 – 1 = 0
y = 17 – 12 = 5
The cost to park for a day is $5.

Question 9.
b. What will Lin pay if she rents a paddleboat for 3.5 hours and splits the total cost with a friend? Explain.
$ _____________

Answer:
$23.5

Explanation:
When Lin paddles for 3.5hr
Total Cost = 3.5(12) + 5 = 47
Lin’s cost = 47/2 = 23.5

Question 10.
Multi-Step
Raymond’s parents will pay for him to take sailboard lessons during the summer. He can take half-hour group lessons or half-hour private lessons. The relationship between cost and number of lessons is linear.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 18
a. Find the rate of change and the initial value for the group lessons.
Type below:
____________

Answer:
$25

Explanation:
Find the slope using two points
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (1, 55) and (x2, y2) = (2, 85)
Slope m = (y2 -y1)/(x2 – x1) = (85 – 55)/(2 – 1) = 30/1 = 30
Rate of change is $30 for per lesson
Find the initial value when the value of x is 0
Work backward from x = 1 to x = 0
(85 – 55)/(2 – 1) = 30/1 = 30
Subtract the difference of x and y from the first point.
x = 1 – 1 = 0
y = 55 – 30 = 25
The initial value of the group lesson is $25.

Question 10.
b. Find the rate of change and the initial value for the private lessons.
Type below:
_____________

Answer:
$25

Explanation:
Find the slope using two points
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (1, 75) and (x2, y2) = (2, 125)
Slope m = (y2 -y1)/(x2 – x1) = (125 – 75)/(2 – 1) = 50/1 = 50
The rate of change is $50 per lesson
Find the initial value when the value of x is 0
Work backward from x = 1 to x = 0
(125 – 75)/(2 – 1) = 50/1 = 50
Subtract the difference of x and y from the first point.
x = 1 – 1 = 0
y = 75 – 50 = 25
The initial value of the private lesson is $25.

Question 10.
c. Compare and contrast the rates of change and the initial values.
Type below:
_____________

Answer:
The initial value for both types of lessons is the same. The rate of change is higher for private lessons than group lesson

Explanation:
Compare the results of a and b
The initial value for both types of lessons is the same. The rate of change is higher for private lessons than group lesson

Vocabulary – Determining Slope and y-intercept – Page No. 106

Explain why each relationship is not linear.

Question 11.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 19
Type below:
_____________

Answer:
The rate of change is not constant, hence the relationship is not linear

Explanation:
Find the rate of change using two points Slope m = (y2 -y1)/(x2 – x1)
(6.5 – 4.5)/(2 – 1) = 2
(8.5 – 6.5)/(3 – 2) = 2
(11.5 – 8.5)/(4 – 3) = 3
The rate of change is not constant, hence the relationship is not linear

Question 12.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 20
Type below:
_____________

Answer:
The rate of change is not constant, hence the relationship is not linear

Explanation:
Find the rate of change using two points Slope m = (y2 -y1)/(x2 – x1)
(126 – 140)/(5 – 3) = -7
(110 – 126)/(7 – 5) = -8
(92 – 110)/(9 – 7) = -9
The rate of change is not constant, hence the relationship is not linear

Question 13.
Communicate Mathematical Ideas
Describe the procedure you performed to derive the slope-intercept form of a linear equation.
Type below:
_____________

Answer:
Express the slope m between a random point (x, y) on the line and the point (0, b) where the line crosses the y-axis. Then solve the equation for y.

H.O.T.

Focus on Higher Order Thinking

Question 14.
Critique Reasoning
Your teacher asked your class to describe a real-world situation in which a y-intercept is 100 and the slope is 5. Your partner gave the following description: My younger brother originally had 100 small building blocks, but he has lost 5 of them every month since.
a. What mistake did your partner make?
Type below:
_____________

Answer:
If the brother loses 5 blocks every month, the slope would be -5 and not 5.

Explanation:
When the initial value is decreasing, the slope is negative.
If the brother loses 5 blocks every month, the slope would be -5 and not 5.

Question 14.
b. Describe a real-world situation that does match the situation.
Type below:
_____________

Answer:
I bought a 100-card pack and buy 5 additional cards every month.

Explanation:
Real-world situation
I bought a 100-card pack and buy 5 additional cards every month.

Question 15.
Justify Reasoning
John has a job parking car. He earns a fixed weekly salary of $300 plus a fee of $5 for each car he parks. His potential earnings for a week are shown in the graph. At what point does John begin to earn more from fees than his fixed salary? Justify your answer.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 2: Determining Slope and y-intercept img 21
Type below:
_____________

Answer:
After parking 60 cars, John’s earnings become $600 double his initial base salary of $300.
Hence, after parking 61 cars, his earning from the fee becomes more than his fixed salary.

Explanation:
He earns the same in fees as his fixed salary for parking 300/5 = 60
After parking 60 cars, John’s earnings became $600 double his initial base salary of $300.
Hence, after parking 61 cars, his earning from the fee becomes more than his fixed salary.

Guided Practice – Graphing Linear Nonproportional Relationships Using Slope and Y-intercept – Page No. 110

Graph each equation using the slope and the y-intercept.

Question 1.
y = \(\frac{1}{2}\)x − 3
slope = _____ y-intercept = _____
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept img 22
Type below:
_____________

Answer:
slope = 1/2 y-intercept = -3
Grade 8 Chapter 4 image 1

Explanation:
y = 1/2 x – 3
The y-intercept is b = -3. Plot the point that contains the y-intercept (0, -3)
The slope m = 1/2. Use the slope to find a second point. From (0, -3) count 1 unit up and 2 unit right. The new point is (2, -2)
Draw a line through the points

Question 2.
y = −3x + 2
slope = _____ y-intercept = _____
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept img 23
Type below:
_____________

Answer:
slope = -3 y-intercept = 2
Grade 8 Chapter 4 image 2

Explanation:
y = -3x + 2
The y-intercept is b = 2. Plot the point that contains the y-intercept (0, 2)
The slope m = -3/1. Use the slope to find a second point. From (0, 2) count 3 unit down and 1 unit right. The new point is (1, -1)
Draw a line through the points

Nonproportional Relationships Worksheet Question 3.
A friend gives you two baseball cards for your birthday. Afterward, you begin collecting them. You buy the same number of cards once each week. The equation y = 4x + 2 describes the number of cards, y, you have after x weeks.
a. Find and interpret the slope and the y-intercept of the line that represents this situation. Graph y = 4x + 2. Include axis labels.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept img 24
Type below:
_____________

Answer:
Grade 8 Chapter 4 image 3

Explanation:
y = 4x + 2
The y-intercept is b = 2. Plot the point that contains the y-intercept (0, 2)
The slope m = 4. Use the slope to find a second point. From (0, 2) count 4 unit up and 1 unit right. The new point is (1, 6)
Draw a line through the points

Question 3.
b. Discuss which points on the line do not make sense in this situation. Then plot three more points on the line that do make sense.
Type below:
_____________

Answer:
Grade 8 Chapter 4 image 4

Explanation:
The points with a negative value of x or y do not make sense as the number of cards or weeks cannot be negative.

Essential Question Check-In

Question 4.
Why might someone choose to use the y-intercept and the slope to graph a line?
Type below:
_____________

Answer:
When the relationship is given in the form y = mx + b, the y-intercept (b) and the slope (m) are easily accessible and easily calculable. Therefore, it is a good practice to use them to graph the line.

Independent Practice – Graphing Linear Nonproportional Relationships Using Slope and Y-intercept – Page No. 111

Question 5.
Science
A spring stretches in relation to the weight hanging from it according to the equation y = 0.75x + 0.25 where x is the weight in pounds and y is the length of the spring in inches.
a. Graph the equation. Include axis labels.
Type below:
_____________

Answer:
grade 8 chapter 4 image 7

Explanation:
y = 0.75x + 0.25
Slope m = 0.75 and y-intercept = 0.25
Plot the point that contains the y-intercept (0, 0.25)
The slope is m = 0.75/1. Use the slope to find a second point. From (0,0.25) count 0.75 unit up and 1 unit right. The new point is (1, 1)

Question 5.
b. Interpret the slope and the y-intercept of the line.
Type below:
_____________

Answer:
The slope represents the increase in the length of spring in inches for each increase of pound of weight. y-intercept represents the unstretched length of the spring When there is no weight attached.

Question 5.
c. How long will the spring be if a 2-pound weight is hung on it? Will the length double if you double the weight? Explain
Type below:
_____________

Answer:
When there is a 2-pound weight hung, the length of the spring would be 1.75 inches. No, When there is a 4-pound weight hung, the length of the spring would be 3.25 inches and not 3.5 inches.

Look for a Pattern

Identify the coordinates of four points on the line with each given slope and y-intercept.

Question 6.
slope = 5, y-intercept = -1
Type below:
_____________

Answer:
(2, 9)
(3, 14)

Explanation:
slope = 5, y-intercept = -1
Plot the point that contains the y-intercept (0, -1)
The slope is m = 5/1. Use the slope to find a second point. From (0, -1) count 5 unit up and 1 unit right. The new point is (1, 4)
Follow the same procedure to find the remaining three points.
(2, 9)
(3, 14)

Question 7.
slope = -1, y-intercept = 8
Type below:
_____________

Answer:
(2, 6)
(3, 5)

Explanation:
slope = -1, y-intercept = 8
Plot the point that contains the y-intercept (0, 8)
The slope is m = -1/1. Use the slope to find a second point. From (0, 8) count 1 unit down and 1 unit right. The new point is (1, 7)
Follow the same procedure to find the remaining three points.
(2, 6)
(3, 5)

Question 8.
slope = 0.2, y-intercept = 0.3
Type below:
_____________

Answer:
(2, 0.7)
(3, 0.9)

Explanation:
slope = 0.2, y-intercept = 0.3
Plot the point that contains the y-intercept (0, 0.3)
The slope is m = 0.2/1. Use the slope to find a second point. From (0, 0.3) count 0.2 unit up and 1 unit right. The new point is (1, 0.5)
Follow the same procedure to find the remaining three points.
(2, 0.7)
(3, 0.9)

Question 9.
slope = 1.5, y-intercept = -3
Type below:
_____________

Answer:
(2, 0)
(3, 1.5)

Explanation:
slope = 1.5, y-intercept = -3
Plot the point that contains the y-intercept (0, -3)
The slope is m = 1.5/1. Use the slope to find a second point. From (0, -3) count 1.5 unit up and 1 unit right. The new point is (1, -1.5)
Follow the same procedure to find the remaining three points.
(2, 0)
(3, 1.5)

Question 10.
slope = −\(\frac{1}{2}\), y-intercept = 4
Type below:
_____________

Answer:
(4, 2)
(6, 1)

Explanation:
slope = −\(\frac{1}{2}\), y-intercept = 4
Plot the point that contains the y-intercept (0, 4)
The slope is m = −\(\frac{1}{2}\)/1. Use the slope to find a second point. From (0, 4) count 1 unit down and 2 unit right. The new point is (2, 3)
Follow the same procedure to find the remaining three points.
(4, 2)
(6, 1)

Question 11.
slope = \(\frac{2}{3}\), y-intercept = -5
Type below:
_____________

Answer:
(6, -1)
(9, 1)

Explanation:
slope = \(\frac{2}{3}\), y-intercept = -5
Plot the point that contains the y-intercept (0, -5)
The slope is m = \(\frac{2}{3}\). Use the slope to find a second point. From (0, -5) count 2 unit up and 3 unit right. The new point is (3, -3)
Follow the same procedure to find the remaining three points.
(6, -1)
(9, 1)

Question 12.
A music school charges a registration fee in addition to a fee per lesson. Music lessons last 0.5 hour. The equation y = 40x + 30 represents the total cost y of x lessons. Find and interpret the slope and y-intercept of the line that represents this situation. Then find four points on the line.
Type below:
_____________

Answer:
y = 40x + 30
Slope = 40
y-intercept = 30
The slope represents the fee of the classes per lesson and the y-intercept represents the registration fee.
Plot the point that contains the y-intercept (0, 30)
The slope is m = 40/1. Use the slope to find a second point. From (0, 30) count 40 units up and 1 unit right. The new point is (1, 70)
Follow the same procedure to find the remaining three points.
(2, 110)
(3, 150)

Graphing Linear Nonproportional Relationships Using Slope and Y-intercept – Page No. 112

Question 13.
A public pool charges a membership fee and a fee for each visit. The equation y = 3x + 50 represents the cost y for x visits.
a. After locating the y-intercept on the coordinate plane shown, can you move up three gridlines and right one gridline to find a second point? Explain.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept img 25
Type below:
_____________

Answer:
Yes

Explanation:
Yes; Since the horizontal and vertical gridlines each represent 25 units, hence moving up 3 gridlines and right 1 gridline represents a slope of 75/25 or 3

Question 13.
b. Graph the equation y = 3x + 50. Include axis labels. Then interpret the slope and y-intercept.
Type below:
_____________

Answer:
grade 8 chapter 4 image 8
The slope represents the fee per visit and the y-intercept represents the membership fee.

Explanation:
Slope = 3
y-intercept = 50
The slope represents the fee of the classes per lesson and the y-intercept represents the registration fee.
Plot the point that contains the y-intercept (0, 50)
The slope is m = 3/1. Use the slope to find a second point. From (0, 50) count 3 units up and 1 unit right. The new point is (1, 53)

Question 13.
c. How many visits to the pool can a member get for $200?
______ visits

Answer:
50 visits

Explanation:
You would get 50 visits for $200
grade 8 chapter 4 image 9

H.O.T.

Focus on Higher Order Thinking

Question 14.
Explain the Error
A student says that the slope of the line for the equation y = 20 − 15x is 20 and the y-intercept is 15. Find and correct the error.
Type below:
_____________

Answer:
The slope is -15 as it represents the change in y per unit change in x. The y-intercept is 20 when x = 0.

Explanation:
y = 20 − 15x
The slope is -15 as it represents the change in y per unit change in x. The y-intercept is 20 when x = 0.

Question 15.
Critical Thinking
Suppose you know the slope of a linear relationship and a point that its graph passes through. Can you graph the line even if the point provided does not represent the y-intercept? Explain.
Type below:
_____________

Answer:
Yes. You can plot the given point and use the slope to find a second point. Connect the points by drawing a line.

Question 16.
Make a Conjecture
Graph the lines y = 3x, y = 3x − 3, and y = 3x + 3. What do you notice about the lines? Make a conjecture based on your observation.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept img 26
Type below:
_____________

Answer:
grade 8 chapter 4 image 10

Explanation:
let’s tale the example
y = 3x
y = 3x – 3
y = 3x + 3
We notice that the lines are parallel to each other: the slopes of the lines are equal but the y-intersection point differs.

Guided Practice – Proportional and Nonproportional Situations – Page No. 117

Determine if each relationship is a proportional or nonproportional situation. Explain your reasoning.

Question 1.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 27
Look at the origin.
_____________

Answer:
Proportional relationship

Explanation:
Proportional relationship
The graph passes through the origin. Graph of a proportional relationship must pass through the origin

Question 2.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 28
_____________

Answer:
Non-proportional relationship

Explanation:
The graph does not pass through the origin. The graph of a proportional relationship must pass through the origin
Non-proportional relationship

Lesson 4 Skills Practice Proportional and Nonproportional Relationships Answer Key Question 3.
q = 2p + \(\frac{1}{2}\)
Compare the equation with y = mx + b.
_____________

Answer:
q = 2p + \(\frac{1}{2}\)
The equation is in the form y = mx + b, with p being used es the variable instead of x and q instead of y. The value of m is 2, and the value b is 1/2. Since b is not 0, the relationship presented through the above equation is non-proportional.

Question 4.
v = \(\frac{1}{10}\)u
_____________

Answer:
Proportional relationship

Explanation:
v = \(\frac{1}{10}\)u
Compare with the form of equation y = mx + b. The equation represents a proportional relationship if b = 0
Proportional relationship

Proportional and Nonproportional Situations – Page No. 118

The tables represent linear relationships. Determine if each relationship is a proportional or nonproportional situation.

Question 5.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 29
Find the quotient of y and x.
_____________

Answer:
proportional relationship

Explanation:
Find the ratio y/x
12/3 = 4
36/9 = 4
84/21 = 4
Since the ratio is constant, the relationship is proportional.

Lesson 4 Skills Practice Proportional and Nonproportional Relationships Question 6.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 30
_____________

Answer:
non-proportional

Explanation:
Find the ratio y/x
4/22 = 2/11
8/46 = 4/23
10/58 = 5/29
Since the ratio is not constant, the relationship is non-proportional.

Question 7.
The values in the table represent the number of households that watched three TV shows and the ratings of the shows. The relationship is linear. Describe the relationship in other ways.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 31
Type below:
_____________

Answer:
proportional relationship

Explanation:
Find the ratio y/x
12/15,000,000 = 0.0000008
16/20,000,000 = 0.0000008
20/25,000,000 = 0.0000008
Since the ratio is constant, the relationship is proportional.

Essential Question Check-In

Question 8.
How are using graphs, equations, and tables similar when distinguishing between proportional and nonproportional linear relationships?
Type below:
_____________

Answer:
The ratio between y to x is constant when the relationship is proportional. Graphs, tables, and equations all can be used to find the ratio. The ratio is not constant when the relationship is non-proportional.

Independent Practice – Proportional and Nonproportional Situations – Page No. 119

Question 9.
The graph shows the weight of a cross-country team’s beverage cooler based on how much sports drink it contains.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 32
a. Is the relationship proportional or nonproportional? Explain.
_____________

Answer:
Non-proportional

Explanation:
The graph does not pass through the origin. Graph of a proportional relationship must pass through the origin
Non-proportional

Question 9.
b. Identify and interpret the slope and the y-intercept.
Type below:
_____________

Answer:
Slope m = (y2 -y1)/(x2 – x1) = (12 – 10)/(4 – 0) = 0.5
y-intercept is the weight of the empty cooler, which is 10 lbs.

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 10) and (x2, y2) = (4, 12)
Slope m = (y2 -y1)/(x2 – x1) = (12 – 10)/(4 – 0) = 0.5
From the graph when x = 0
y-intercept (b) = 10
y-intercept is the weight of the empty cooler, which is 10 lbs.

In 10–11, tell if the relationship between a rider’s height above the first floor and the time since the rider stepped on the elevator or escalator is proportional or nonproportional. Explain your reasoning.

Question 10.
The elevator paused for 10 seconds after you stepped on before beginning to rise at a constant rate of 8 feet per second.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 33
_____________

Answer:
Non-proportional

Explanation:
As there is a pause of 10 seconds, it would be the y-intercept of the graph (when x = 0)
Non-proportional

Representing Linear Nonproportional Relationships Lesson 4.1 Answer Key Question 11.
Your height, h, in feet above the first floor on the escalator is given by h = 0.75t, where t is the time in seconds.
_____________

Answer:
Proportional

Explanation:
Comparing with y = mx + b, where b = 0
Proportional

Analyze Relationships

Compare and contrast the two graphs.

Question 12.
Graph A       Graph B
y = \(\frac{1}{3}\) x        y = \(\sqrt { x } \)
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 34
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 35
Type below:
_____________

Answer:
Graph A represents a linear relationship while Graph B represents an exponential relationship. They both pass through the origin and the value of y increases with an increase in x.

Proportional and Nonproportional Situations – Page No. 120

Question 13.
Represent Real-World Problems
Describe a real-world situation where the relationship is linear and nonproportional.
Type below:
_____________

Answer:
The entrance fee to the amusement park is $8 and there is a fee of $2 per ride.

H.O.T.

Focus on Higher Order Thinking

Question 14.
Mathematical Reasoning
Suppose you know the slope of a linear relationship and one of the points that its graph passes through. How can you determine if the relationship is proportional or nonproportional?
Type below:
_____________

Answer:
Use the graph and the given point to determine the second point. Connect the two points by a straight line. If the graph passes through the origin, the relationship is proportional and if the graph does not pass through the origin, the relationship is non-proportional.

Lesson 4 Proportional and Nonproportional Relationships Question 15.
Multiple Representations
An entrant at a science fair has included information about temperature conversion in various forms, as shown. The variables F, C, and K represent temperatures in degrees Fahrenheit, degrees Celsius, and kelvin, respectively.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Lesson 4: Proportional and Nonproportional Situations img 36
a. Is the relationship between kelvins and degrees Celsius proportional? Justify your answer in two different ways.
_____________

Answer:
No, the relationship is not proportional.

Explanation:
Compare the equation B to the form: y = mx + b. Since b is not equal to 0, the relationship is non-proportional.
Find the ratio between the Kelvin and Degrees Celsius. Since the ratio is not constant, the relationship is non-proportional.
281.15/8 = 35.14
288.15/15 = 19.21
309.15/36 = 8.59
No, the relationship is not proportional.

Question 15.
b. Is the relationship between degrees Celsius and degrees Fahrenheit proportional? Why or why not?
_____________

Answer:
No, the relationship is not proportional.

Explanation:
Compare the equation A to the form: y = mx + b. Since b is not equal to 0, the relationship is non-proportional.
No, the relationship is not proportional.

4.1 Representing Linear Nonproportional Relationships – Model Quiz – Page No. 121

Lesson 4.1 Representing Linear Nonproportional Relationships Question 1.
Complete the table using the equation y = 3x + 2.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Model Quiz img 37
Type below:
_____________

Answer:
grade 8 chapter 4 image 11

Explanation:
Given y = 3x + 2
grade 8 chapter 4 image 11
x = -1; y = 3(-1) + 2 = -3 + 2 = -1
x = 0; y = 3(0) +2 = 2
x = 1; y = 3(1) + 2 = 3 + 2 = 5
x = 2; y = 3(2) + 2 = 6 + 2 = 8
x = 3: y = 3(3) + 2 = 9 + 2 = 11

4.2 Determining Slope and Y-intercept

Question 2.
Find the slope and y-intercept of the line in the graph.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Model Quiz img 38
Type below:
_____________

Answer:
Slope = 3
y-intercept (b) = 1

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 1) and (x2, y2) = (1, 4)
Slope m = (y2 -y1)/(x2 – x1) = (4 – 1)/(1 – 0) = 3/1
From the graph when x = 0
y-intercept (b) = 1

4.3 Graphing Linear Nonproportional Relationships

Question 3.
Graph the equation y = 2x − 3 using slope and y-intercept.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Model Quiz img 39
Type below:
_____________

Answer:
grade 8 chapter 4 image 12

Explanation:
Slope = 2
y-intercept = -3
Plot the point that contains the y-intercept (0, -3)
The slope is m = 2/1. Use the slope to find a second point. From (0, -3) count 2 unit up and 1 unit right. The new point is (1, -1)
Draw a line through the points

4.4 Proportional and Nonproportional Situations

Question 4.
Does the table represent a proportional or a nonproportional linear relationship?
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Model Quiz img 40
_____________

Answer:
Since the ratio is constant, the table represents a proportional linear relationship.

Explanation:
Find the ratio y/x
4/1 = 4
8/2 = 4
12/3 = 4
16/4 = 4
20/5 = 4
Since the ratio is constant, the table represents a proportional linear relationship.

Question 5.
Does the graph in Exercise 2 represent a proportional or a nonproportional linear relationship?
_____________

Answer:
It represents a non-proportional linear relationship

Explanation:
The line of the graph does not pass through the origin. The graph of a proportional relationship must pass through the origin.
It represents a non-proportional linear relationship

Question 6.
Does the graph in Exercise 3 represent a proportional or a nonproportional relationship?
_____________

Answer:
It represents a non-proportional linear relationship

Explanation:
The line of the graph does not pass through the origin. The graph of a proportional relationship must pass through the origin
It represents a non-proportional linear relationship

Essential Question

Question 7.
How can you identify a linear nonproportional relationship from a table, a graph, and an equation?
Type below:
_____________

Answer:
In a table, the ratio of y/x is not constant for a non-proportional relationship.
In a graph, the line of the graph does not pass through the origin for a non-proportional relationship.
In an equation, the b is not equal to y = mx +b for a non-proportional relationship.

Selected Response – Mixed Review – Page No. 122

Question 1.
The table below represents which equation?
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Mixed Review img 41
Options:
a. y = −x − 10
b. y = −6x
c. y = −4x − 6
d. y = −4x + 2

Answer:
c. y = −4x − 6

Explanation:
From the table, you can see that the y-intercept (when x = 0) is b = -6. Comparable to y = mx + b
The table is represented by Option C y = -4x – 6

Question 2.
The graph of which equation is shown below?
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Mixed Review img 42
Options:
a. y = −2x + 3
b. y = −2x + 1.5
c. y = 2x + 3
d. y = 2x + 1.5

Answer:
a. y = −2x + 3

Explanation:
From the table, you can see that the y-intercept (when x = 0) is b = 3. Comparable to y = mx + b
The Option B and D are rejected.
Since the graph is slanting downwards, the slope is negative.
Option C is rejected
The graph represents y = -2x + 3

Question 3.
The table below represents a linear relationship.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Mixed Review img 43
What is the y-intercept?
Options:
a. -4
b. -2
c. 2
d. 3

Answer:
b. -2

Explanation:
Find the rate of change
(7 – 4)/(3 – 2) = (10 – 7)/(4 – 3) = 3
Find the value of y for x = 0
Works backward from x = 2 to x = 1
x = 2 – 1 = 1
y = 4 – 3 = 1
x = 1 – 1 = 0
y = 1 – 3 = -2
y-intercept = -2

Question 4.
Which equation represents a nonproportional relationship?
Options:
a. y = 3x + 0
b. y = −3x
c. y = 3x + 5
d. y = \(\frac{1}{3}\)x

Answer:
c. y = 3x + 5

Explanation:
For a non-proportional relationship, the equation is y = mx + b and b is not equal to 0.
Option C represents a non-proportional relationship y = 3x + 5

Question 5.
The table shows a proportional relationship. What is the missing y-value?
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Mixed Review img 44
Options:
a. 16
b. 20
c. 18
d. 24

Answer:
c. 18

Explanation:
Find the ratio y/x
6/4 = 3/2
Since the relationship is proportional, the ratio is constant.
Using the ratio to find missing y
3/2 = y/12
y = 3/2 × 12 = 18

Question 6.
What is 0.00000598 written in scientific notation?
Options:
a. 5.98 × 10-6
b. 5.98 × 10-5
c. 59.8 × 10-6
d. 59.8 × 10-7

Answer:
c. 59.8 × 10-6

Explanation:
0.00000598
Move the decimal 6 points
59.8 × 10-6

Mini-Task

Question 7.
The graph shows a linear relationship.
Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships Mixed Review img 45
a. Is the relationship proportional or nonproportional?
____________

Answer:
It represents a non-proportional linear relationship

Explanation:
The line of the graph does not pass through the origin. The graph of a proportional relationship must pass through the origin.
It represents a non-proportional linear relationship

Question 7.
b. What is the slope of the line?
_______

Answer:
Slope m = -2

Explanation:
Find the slope using two points from the graph by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, -2) and (x2, y2) = (2, 1)
Slope m = (y2 -y1)/(x2 – x1) = (-3 -1)/(0 + 2) = -4/2 = -2

Question 7.
c. What is the y-intercept of the line?
_______

Answer:
y-intercept (b) = -3

Explanation:
From the graph when x = 0
y-intercept (b) = -3

Question 7.
d. What is the equation of the line?
Type below:
____________

Answer:
y = -2x – 3

Explanation:
Substitute m and b in the form: y = mx + b
y = -2x – 3

Conclusion:

Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships for Download. All the beginners can easily start their practice and learn the maths in an easy way. Quickly start your practice with Go Math Grade 8 Answer Key.

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Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships

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Go Math Grade 8 Chapter 3 Proportional Relationships Answer Key

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Lesson 1: Representing Proportional Relationships

Lesson 2: Rate of Change and Slope

Lesson 3: Interpreting the Unit As Slope

Lesson 4: Representing Proportional Relationships – Model Quiz

Mixed Review

Guided Practice – Representing Proportional Relationships – Page No. 74

Question 1.
Vocabulary
A proportional relationship is a relationship between two quantities in which the ratio of one quantity to the other quantity is/is not constant.
______ constant

Answer:
is constant

Explanation:
The rent would be proportional so therefore it is.

Question 2.
Vocabulary
When writing an equation of a proportional relationship in the form y = kx, k represents the __________________________.
______________

Answer:
constant of proportionality

Explanation:
When writing an equation of a proportional relationship in the form y = kx, k represents the constant of proportionality.

Representing Proportional Relationships With Equations Answer Key Question 3.
Write an equation that describes the proportional relationship between the number of days and the number of weeks in a given length of time.
a. Complete the table.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 1
Type below:
______________

Answer:
Grade 8 Chapter 3 image 1

Question 3.
b. Let x represent _____.
Let y represent _____.
The equation that describes the relationship is _____.
Type below:
______________

Answer:
Let x represent the time in weeks.
Let y represent the time in days.
The equation that describes the relationship is y = 7x.

Each table or graph represents a proportional relationship. Write an equation that describes the relationship.

Question 4.
Physical Science
The relationship between the numbers of oxygen atoms and hydrogen atoms in water.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 2
Type below:
______________

Answer:
y = 2x
Grade 8 Chapter 3 image 2

Explanation:
x represents the Oxygen atoms
y represents the Hydrogen atoms
For every point of the x-axis, the y-axis is varying with 2x times.
y = 2x

Question 5.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 3
Type below:
______________

Answer:
y = 30x

Explanation:
x represents the Distance in inches
y represents the Actual Distance in miles
For every point of the x-axis, the y-axis is varying with 30x times.
y = 30x

Essential Question Check-In

Question 6.
If you know the equation of a proportional relationship, how can you draw the graph of the equation?
Type below:
______________

Answer:
Use the equation to make a table with x-values and y-values. Then graph the points (x, y) and draw a line through the points.

Independent Practice – Representing Proportional Relationships – Page No. 75

The table shows the relationship between temperatures measured on the Celsius and Fahrenheit scales.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 4

Question 7.
Is the relationship between the temperature scales proportional? Why or why not?
______________

Answer:
No. The ratios of the numbers in each column are not equal.

Explanation:
Fahrenheit Temperature/Celsius Temperature = 50/10 = 5
86/30 = 2.87
122/50 = 2.44
The relationship is not propotional as the ratio is not constant.

Question 8.
Describe the graph of the Celsius-Fahrenheit relationship.
Type below:
______________

Answer:
A line starting at (0, 32) and slanting upward to the right.

Explanation:
The graph is a straight line with a y-intercept of 32.

Representing Proportional Relationships Worksheet Question 9.
Analyze Relationships
Ralph opened a savings account with a deposit of $100. Every month after that, he deposited $20 more.
a. Why is the relationship described not proportional?
Type below:
______________

Answer:
The account had a balance of $100, to begin with.

Question 9.
b. How could the situation be changed to make the situation proportional?
Type below:
______________

Answer:
Have Ralph open the account with no money, to begin with, and then put $20 every month.

Question 10.
Represent Real-World Problems
Describe a real-world situation that can be modeled by the equation y = \(\frac{1}{20}\)x. Be sure to describe what each variable represents.
Type below:
______________

Answer:
If x is the number of nickels you have, y = \(\frac{1}{20}\)x is the amount of money you have in dollars.

Look for a Pattern

The variables x and y are related proportionally.

Question 11.
When x = 8, y = 20. Find y when x = 42.
_______

Answer:
y = 105

Explanation:
x = 8, y = 20
y/x = 20/8
y = 20x/8
when x = 42
y = (20 × 42)/8
y = 105

Using Proportional Relationships Answer Key Question 12.
When x = 12, y = 8. Find x when y = 12.
_______

Answer:
x = 18

Explanation:
x/y = 12/8
x = 12y/8
when y = 12
x = (12 × 12)/8
x = 18

Representing Proportional Relationships – Page No. 76

Question 13.
The graph shows the relationship between the distance that a snail crawls and the time that it crawls.
a. Use the points on the graph to make a table.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 5
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 6
Type below:
______________

Answer:
Grade 8 Chapter 3 image 10

Question 13.
b. Write the equation for the relationship and tell what each variable represents.
Type below:
______________

Answer:
y = 1/10 x, where y is the time in minutes and x is the distance in inches

Question 13.
c. How long does it take the snail to crawl 85 inches?
_______ minutes

Answer:
8.5 minutes

H.O.T.

Focus on Higher Order Thinking

Question 14.
Communicate Mathematical Ideas
Explain why all of the graphs in this lesson show the first quadrant but omit the other three quadrants.
Type below:
______________

Answer:
All of the graphs represent real-world data for which both x and y take on only nonnegative values, which graph in the first quadrant or on the axes. If either x or y or both could be negative, then other quadrants would be needed.

Representing Proportional Relationships Question 15.
Analyze Relationships
Complete the table.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 1: Representing Proportional Relationships img 7

Grade 8 Chapter 3 image 10
a. Are the length of a side of a square and the perimeter of the square related proportionally? Why or why not?
______________

Answer:
Yes. The ratio of the perimeter of a square to its side length is always 4.

Question 15.
b. Are the length of a side of a square and the area of the square related proportionally? Why or why not?
______________

Answer:
No. The ratio of the area of a square to its side length is not constant

Question 16.
Make a Conjecture
A table shows a proportional relationship where k is the constant of proportionality. The rows are then switched. How does the new constant of proportionality relate to the original one?
Type below:
______________

Answer:
It is the reciprocal of the original constant of proportionality

Guided Practice – Rate of Change and Slope – Page No. 80

Tell whether the rates of change are constant or variable.

Question 1.
building measurements _____
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 8
______________

Answer:
constant

Explanation:
Input variable: Feet
Output variable: Yard
For every point of the Yard, the Feet is increasing 3 times.
So, the answer is constant.

Question 2.
computers sold _____
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 9
______________

Answer:
variable

Explanation:
Identify the input and output variables
Input variable: Week
Output variable: The number sold
x-axis and y-axis points are not varying constantly. So, the answer is variable.

Question 3.
distance an object falls _____
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 10
______________

Answer:
variable

Explanation:
Identify the input and output variables
Input variable: Time
Output variable: Distance
x-axis and y-axis points are not varying constantly. So, the answer is variable.

Question 4.
cost of sweaters _____
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 11
______________

Answer:
constant

Explanation:
Identify the input and output variables
Input variable: Number
Output variable: Cost
x-axis and y-axis points are varying constantly. So, the answer is constant.

Erica walks to her friend Philip’s house. The graph shows Erica’s distance from home over time.

Question 5.
Find the rate of change from 1 minute to 2 minutes.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 12
\(\frac{\text { change in distance }}{\text { change in time }}=\frac{400-?}{2-?}=\frac{?}{?}=?\) ft per min
________ feet per minute

Answer:
200 feet per minute

Explanation:
(400 – 200)/(2 – 1)
200/1
200 feet per minute

Question 6 (request help)
Find the rate of change from 1 minute to 4 minutes.
______ feet per minute

Answer:
200 ft per min

Explanation:
change in distance/change in time
(800 – 200)/(4 – 1)
600/3 = 200 ft per min

Find the slope of each line.

Question 7.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 13
slope = _____
________

Answer:
slope = -2

Explanation:
From the given image, the x-axis is separated by 1 unit.
the y-axis is separated with 1 unit.
For every 1 unit of the x-axis, the slope is taken -2 units on the y-axis
The slope of the line is -2

Lesson 8 Graph Proportional Relationships and Define Slope Question 8.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 14
slope = _____
\(\frac{â–¡}{â–¡}\)

Answer:
\(\frac{3}{2}\)

Explanation:
From the given image, the slope is 3/2

Essential Question Check-In

Question 9.
If you know two points on a line, how can you find the rate of change of the variables being graphed?
Type below:
_____________

Answer:
Find the coordinates of two points on the line. Then divide the change in y-values from one point to the next by the change in x-values.

Independent Practice – Rate of Change and Slope – Page No. 81

Question 10.
Rectangle EFGH is graphed on a coordinate plane with vertices at E(-3, 5), F(6, 2), G(4, -4), and H(-5, -1).
a. Find the slopes of each side.
Type below:
_____________

Answer:
Slope EF = 1/3
slope FG = 3
slope GH = -1/3
slope HE =3

Question 10.
b. What do you notice about the slopes of opposite sides?
Type below:
_____________

Answer:
They are the same.

Question 10.
c. What do you notice about the slopes of adjacent sides?
Type below:
_____________

Answer:
They are negative reciprocals of one another.

Question 11.
A bicyclist started riding at 8:00 A.M. The diagram below shows the distance the bicyclist had traveled at different times. What was the bicyclist’s average rate of speed in miles per hour?
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 15
_______ miles per hour

Answer:
15 miles per hour

Explanation:
Total distance traveled by bicyclist = 4.5 mile + 7.5 mile = 12 mile
Total time taken by bicyclist = (8:48 A.M – 8:00 A.M) = 48 min = 0.8 hr
conversion used : ( 1 hour = 60 minute)
Average rate of speed = total distance/total time = 15 mile/hr

Lesson 3.2 Rate of Change and Slope Answer Key Question 12.
Multistep
A line passes through (6, 3), (8, 4), and (n, -2). Find the value of n.
_______

Answer:
n = -4

Explanation:
A line passes through (6, 3), (8, 4), and (n, -2).
From the given information, for every 2 points on the x-axis, the y-values are changing one point.
(4, 2), (2, 1), (0, 0), (-2, -1), (-4, -2)

Question 13.
A large container holds 5 gallons of water. It begins leaking at a constant rate. After 10 minutes, the container has 3 gallons of water left.
a. At what rate is the water leaking?
_______ gallons per minute

Answer:
1 gallon every 5 minutes, or 0.2 gal/min

Explanation:
Rate = (5 – 3)/(0 – 10)
= 2/-10
= -0.2
The rate of water leaking is 1 gallon every 5 minutes, or 0.2 gal/min

Question 13.
b. After how many minutes will the container be empty?
_______ minutes

Answer:
25 minutes

Explanation:
Number of minutes = 5/0.2 = 25
It will take 25 minutes for the container to be empty.

Question 14.
Critique Reasoning
Billy found the slope of the line through the points (2, 5) and (-2, -5) using the equation \(\frac{2-(-2)}{5-(-5)}=\frac{2}{5}\). What mistake did he make?
Type below:
_____________

Answer:
He used the change in x over the change in y instead of the change in y over the change in x.

Rate of Change and Slope – Page No. 82

Question 15.
Multiple Representations
Graph parallelogram ABCD on a coordinate plane with vertices at A(3, 4), B(6, 1), C(0, -2), and D(-3, 1).
a. Find the slope of each side.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 2: Rate of Change and Slope img 16
Type below:
_____________

Answer:
slope AB = -1;
slope BC = 1/2
slope CD = -1;
slope DA = 1/2

Explanation:
Grade 8 Chapter 3 image 5

Question 15.
b. What do you notice about the slopes?
Type below:
_____________

Answer:
The slopes of the opposite sides are the same.

Question 15.
c. Draw another parallelogram on the coordinate plane. Do the slopes have the same characteristics?
Type below:
_____________

Answer:
Yes; opposite sides still have the same slope.

H.O.T.

Focus on Higher Order Thinking

Question 16.
Communicate Mathematical Ideas
Ben and Phoebe are finding the slope of a line. Ben chose two points on the line and used them to find the slope. Phoebe used two different points to find the slope. Did they get the same answer? Explain.
_____________

Answer:
Yes. The slope of a line is constant. Therefore, the slope that you calculate will be the same no matter which two points you choose.

Proportional Relationships and Slope Question 17.
Analyze Relationships
Two lines pass through the origin. The lines have slopes that are opposites. Compare and contrast the lines.
Type below:
_____________

Answer:
One line has a positive slope and one has a negative slope. The lines are equally steep, but one slants upward left to right while the other slants downward left to right. The lines cross at the origin.

Question 18.
Reason Abstractly
What is the slope of the x-axis? Explain.
_____________

Answer:
Zero. The rise along the x-axis is zero, while the run along the x-axis is not zero. The slope zero/run or zero.

Guided Practice – Interpreting the Unit As Slope – Page No. 86

Give the slope of the graph and the unit rate.

Question 1.
Jorge: 5 miles every 6 hours
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 17
\(\frac{â–¡}{â–¡}\) miles per hour

Answer:
\(\frac{5}{6}\) miles per hour

Explanation:
Grade 8 Chapter 3 image 11
Slope = rise/run = 5/6
The unit rate a the distance traveled and the slope a the graph of the relationship is equal, 5/6 miles per hour
Calculate miles PER hour
5/6

Interpreting the Unit Rate as Slope Lesson 3.3 Answer Key Question 2.
Akiko
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 18
\(\frac{â–¡}{â–¡}\) miles per hour

Answer:
\(\frac{5}{4}\) miles per hour

Explanation:
Calculate miles PER hour
5 miles/4hours = 5/4 miles per hour

Question 3.
The equation y = 0.5x represents the distance Henry hikes, in miles, over time, in hours. The graph represents the rate which Clark hikes. Determine which hiker is faster. Explain.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 19
___________

Answer:
Clark is faster.

Explanation:
From the equation, Henry’s rate is equal to 0.5, or 1/2 mile per hour. Clark’s rate is the slope of the line, which is 3/2 or 1.5 miles per hour.

Write an equation relating the variables in each table.

Question 4.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 20
Type below:
___________

Answer:
y = 15x

Explanation:
y/x = 15/1
y = 15x
Multiply 15 with the x values to get the y values.
y = 15x

Constant of Proportionality Worksheet With Answers Question 5.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 21
Type below:
___________

Answer:
y = 3/8 x

Explanation:
y/x = 6/16
y/x = 3/8
y = 3/8 x

Essential Question Check-In

Question 6.
Describe methods you can use to show a proportional relationship between two variables, x and y. For each method, explain how you can find the unit rate and the slope.
Type below:
___________

Answer:
The ratio of y to x gives the unit rate and slope.

Explanation:
If the equation can be written as y = mx, then m is the unit rate and the slope. Graph: When the line passes through the origin, then the value of r at the point (1, r) is the unit rate and the slope.

Independent Practice – Interpreting the Unit As Slope – Page No. 87

Question 7.
A Canadian goose migrated at a steady rate of 3 miles every 4 minutes.
a. Fill in the table to describe the relationship.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 22
Type below:
___________

Answer:
Grade 8 Chapter 3 image 6

Explanation:
Canadian goose migrated at a steady rate of 3 miles every 4 minutes
y/x = 3/4; x/y = 4/3
y = 3/4 x; x = 4/3 y
If x = 8, y = 3/4 × 8 = 6
If y = 9, x = 4/3 × 9 = 12
If y = 12, x = 4/3 × 12 = 16
If x = 20, y = 3/4 × 20 = 15

Question 7.
b. Graph the relationship.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 23
Type below:
___________

Answer:
Grade 8 Chapter 3 image 7

Explanation:
The points are (4, 3), (8, 6), (12, 9), (16, 12), (20, 15)

Question 7.
c. Find the slope of the graph and describe what it means in the context of this problem.
Slope: \(\frac{â–¡}{â–¡}\) miles per minute

Answer:
Slope: \(\frac{3}{4}\) miles per minute

Explanation:
The unit rate of migration of the goose and the slope of the graph both equal 3/4 mi/min

Question 8.
Vocabulary
A unit rate is a rate in which the first quantity / second quantity in the comparison is one unit.
___________

Answer:
second quantity

Explanation:
A unit rate is a rate in which the “second quantity” in the comparison is one unit

Question 9.
The table and the graph represent the rate at which two machines are bottling milk in gallons per second.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 24
a. Determine the slope and unit rate of each machine.
Type below:
___________

Answer:
Machine 1: slope = unit rate = 0.6/1 = 0.6 gal/s
Machine 2: slope = unit rate = 3/4 = 0.75 gal/s

Question 9.
b. Determine which machine is working at a faster rate.
___________

Answer:
Machine 2 is working at a faster rate since 0.75 > 0.6

Interpreting the Unit As Slope – Page No. 88

Question 10.
Cycling
The equation y = \(\frac{1}{9}\) x represents the distance y, in kilometers, that Patrick traveled in x minutes while training for the cycling portion of a triathlon. The table shows the distance y Jennifer traveled in x minutes in her training. Who has the faster training rate?
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 25
___________

Answer:
Jennifer has a faster training rate

Explanation:
Patrick’s rate is 1/9 kilometer per minute. Jennifer’s rate is 1/8 kilometer per minute. 1/9 < 1/8. So, Jennifer has a faster training rate.

H.O.T.

Focus on Higher Order Thinking

Question 11.
Analyze Relationships
There is a proportional relationship between minutes and dollars per minute, shown on a graph of printing expenses. The graph passes through the point (1, 4.75). What is the slope of the graph? What is the unit rate? Explain.
______ dollars per minute

Answer:
$4.75/min

Explanation:
slope = unit rate = 4.75.
If the graph of a proportional relationship passes through the point (1, r), then r equals the slope and the unit rate, which is $4.75/min.

Question 12.
Draw Conclusions
Two cars start at the same time and travel at different constant rates. A graph for Car A passes through the point (0.5, 27.5), and a graph for Car B passes through (4, 240). Both graphs show distance in miles and time in hours. Which car is traveling faster? Explain.
___________

Answer:
Car B

Explanation:
The slope and unit rate of speed of Car A is (27.5 – 0)/(0.5 – 0) = 27.5/0.5 = 55 mi/h.
The slope and unit rate of speed of Car B is (240 – 0)/(4 – 0) = 240/4 = 60 mi/h.
60 > 55, so Car B is traveling faster.

Question 13.
Critical Thinking
The table shows the rate at which water is being pumped into a swimming pool. Use the unit rate and the amount of water pumped after 12 minutes to find how much water will have been pumped into the pool after 13 \(\frac{1}{2}\) minutes. Explain your reasoning.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Lesson 3: Interpreting the Unit As Slope img 26
______ gallons

Answer:
243 gallons

Explanation:
The unit rate is 36/2 = 18gal/min.
So, 1 1/2 minutes after 12 minutes, an additional 18 × 1 1/2 = = 27 gallons will be pumped in.
So, the total is 216 + 27 = 243 gal.

3.1 Representing Proportional Relationships – Model Quiz – Page No. 89

Question 1.
Find the constant of proportionality for the table of values.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Model Quiz img 27
______

Answer:
1.5

Explanation:
constant of proportionality
k = y/x = 3/2 = 1.5
k = y/x = 4.5/3 = 1.5
k = y/x = 6/4 = 1.5
k = y/x = 7.5/5 = 1.5

Proportional Relationship 8th Grade Question 2.
Phil is riding his bike. He rides 25 miles in 2 hours, 37.5 miles in 3 hours, and 50 miles in 4 hours. Find the constant of proportionality and write an equation to describe the situation.
Type below:
___________

Answer:
The constant of proportionality is 12.5 miles per hour.

Explanation:
The equation is d = 12.5 × t
25 miles ÷ 2 hours = 12.5 miles/hour
A direct proportionality d = 12.5 × t

3.2 Rate of Change and Slope

Find the slope of each line.

Question 3.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Model Quiz img 28
______

Answer:
Slope = 3

Question 4.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Model Quiz img 29
______

Answer:
Slope = -5

3.3 Interpreting the Unit Rate as Slope

Question 5.
The distance Train A travels is represented by d = 70t, where d is the distance in kilometers and t is the time in hours. The distance Train B travels at various times is shown in the table. What is the unit rate of each train? Which train is going faster?
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Model Quiz img 30
____________

Answer:
Train A: 70 km per hour; Train B: 75 km per hour; Train B is faster.

Explanation:
The distance Train A travels is represented by d = 70t
where d is the distance in kilometers and t is the time in hours
The speed of train A is 70 kilometer per hour
To find the speed of train B use the table
Slope = (300 – 150)/(4 – 2) = 75
The speed of train B is 75 km per hour
The speed of train B is more

Essential Question

Question 6.
What is the relationship among proportional relationships, lines, rates of change, and slope?
Type below:
____________

Answer:
The relationship between the x-axis and y-axis of any graph is a proportional Relationship which is defined by slope i.e. calculating the rate of change of the plotted line.
1) Here proportional change and rate of change are algebraic quantities which specify how one quantity changes with respect to another.
2) Line and Slope are geometric quantities which describe the graph of any equation.

Selected Response – Mixed Review – Page No. 90

Question 1.
Which of the following is equivalent to 5-1?
Options:
a. 4
b. \(\frac{1}{5}\)
c. −\(\frac{1}{5}\)
d. -5

Answer:
b. \(\frac{1}{5}\)

Explanation:
5-1
1/5

Question 2.
Prasert earns $9 an hour. Which table represents this proportional relationship?
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Mixed Review img 31
Options:
a. A
b. B
c. C
d. D

Answer:
a. A

Explanation:
a. 36/4 = 9; 54/6 = 9; 72/8 = 9
b. 36/4 = 9; 45/6 = 7.5; 54/8 = 6.75
c. 9/2 = 4.5
d. 18/2 = 9; 27/3 = 9; 54/4 = 13.5

Chapter 3 Math Test 8th Grade Answers Question 3.
A factory produces widgets at a constant rate. After 4 hours, 3,120 widgets have been produced. At what rate are the widgets being produced?
Options:
a. 630 widgets per hour
b. 708 widgets per hour
c. 780 widgets per hour
d. 1,365 widgets per hour

Answer:
c. 780 widgets per hour

Explanation:
A factory produces widgets at a constant rate. After 4 hours, 3,120 widgets have been produced.
3,120/4 = 780 widgets per hour

Question 4.
A full lake begins dropping at a constant rate. After 4 weeks it has dropped 3 feet. What is the unit rate of change in the lake’s level compared to its full level?
Options:
a. 0.75 feet per week
b. 1.33 feet per week
c. -0.75 feet per week
d. -1.33 feet per week

Answer:
c. -0.75 feet per week

Explanation:
A full lake begins dropping at a constant rate. After 4 weeks it has dropped 3 feet.
(-3 ft)/(4 weeks) = -3/4 ft/wk = -0.75 ft/wk

Question 5.
What is the slope of the line below?
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Mixed Review img 32
Options:
a. -2
b. −\(\frac{1}{2}\)
c. \(\frac{1}{2}\)
d. 2

Answer:
c. \(\frac{1}{2}\)

Explanation:
(-1.5, 1.5) & (1.5, 0)
(0 – 1..5)/(1.5 – (-1.5))
1.5/3
= 1/2

Question 6.
Jim earns $41.25 in 5 hours. Susan earns $30.00 in 4 hours. Pierre’s hourly rate is less than Jim’s, but more than Susan’s. What is his hourly rate?
Options:
a. $6.50
b. $7.75
c. $7.35
d. $8.25

Answer:
b. $7.75

Explanation:
Jim earns $41.25 in 5 hours.
$41.25/5 = 8.25
Jim’s unit rate is $8.25 per hour
30/4 = 7.5
Pierre’s hourly rate is is less than $8.25 but more than $7.50
$7.75

Mini-Task

Question 7.
Joelle can read 3 pages in 4 minutes, 4.5 pages in 6 minutes, and 6 pages in 8 minutes.
a. Make a table of the data.
Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships Mixed Review img 33
Type below:
______________

Answer:
Grade 8 Chapter 3 image 8

Explanation:
Joelle can read 3 pages in 4 minutes,
y/x = 3/4
y = 3/4 x
If x = 6, y = 3/4 × 6 = 4.5
If x = 8, y = 3/4 × 8 = 6

Question 7.
b. Use the values in the table to find the unit rate.
_______ pages per minute

Answer:
0.75 pages per minute

Explanation:
3/4 = 0.75
4.5/6 = 0.75
6/8 = 0.75
The unit rate is 0.75 pages per minute

Question 7.
c. Graph the relationship between minutes and pages read.
Type below:
______________

Answer:
Grade 8 Chapter 3 image 9

Conclusion:

All the students refer to Go Math Grade 8 Answer Key Chapter 3 Proportional Relationships PDF to practice maths. Students can definitely score good marks in the exam with the help of the Go Math Grade 8 Chapter 3 Proportional Relationships Answer Key. Practice all the questions and finish your learning of Chapter 3 Proportional Relationships.

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go-math-grade-8-answer-key-chapter-7-solving-linear-equations

Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations

Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations PDF is available for free. Learn all the best maths tactics and ways of solving with the help of the Go Math Grade 8 Chapter 7 Solving Linear Equations Solution Key. You can practice all the questions to have a perfect grip on the Grade 8 maths subject. Go Math Grade 8 Answer Key is the best source to practice maths. Don’t leave your home to learn maths in the best way with the help of Go Math Grade 8 Solution Key.

Go Math Grade 8 Chapter 7 Solving Linear Equations Answer Key

Students who use Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations will enjoy solving math questions. Every student is entitled not only to download but also practice them online. Don’t need to use a single paper to practice. Just practice online by looking into the questions and answers available on Go Math Grade 8 Answer Key.

Lesson 1: Equations with the Variable on Both Sides

Lesson 2: Equations with Rational Numbers

Lesson 3: Equations with the Distributive Property

Lesson 4: Equations with Many Solutions or No Solution

Lesson 5: Equations with the Variable on Both Sides

Reviews

Guided Practice – Equations with the Variable on Both Sides – Page No. 200

Use algebra tiles to model and solve each equation.

Question 1.
x + 4 = -x – 4
x = ________

Answer:
x = -4

Explanation:
Model x + 4 on the left side of the mat and -x -4 on the right side.
grade 8 chapter 7 image 1
Add one c-tile to both sides. This represents adding x to both sides of the equation. Remove zero pairs.
grade 8 chapter 7 image 2
Place four -1-tiles on both sides. This represents subtracting -4 from both sides of the equation. Remove zero pairs.
grade 8 chapter 7 image 3
Separate each side into 2 equal groups. One x-tile is equivalent to four -1-tiles.
grade 8 chapter 7 image 4
x = -4

Question 2.
2 – 3x = -x – 8
x = ________

Answer:

Explanation:
Given 2 – 3x = -x – 8
Model 2-3x on the left side of the mat and -x-8 on the right side.
grade 8 chapter 7 image 5
Place one x tile to both sides. This represents subtracting from both sides of the equation.
grade 8 chapter 7 image 6
Remove 2 1 tiles from sides. This represents subtracting from both sides of the equation.
grade 8 chapter 7 image 7
Separate each side into 2 equal groups. One -x tile is equivalent to 5 – 1 tile.
grade 8 chapter 7 image 8
The solution is -x = -5 or x = 5

Solving Linear Equations Grade 8 Question 3.
At Silver Gym, membership is $25 per month, and personal training sessions are $30 each. At Fit Factor, membership is $65 per month, and personal training sessions are $20 each. In one month, how many personal training sessions would Sarah have to buy to make the total cost at the two gyms equal?
________ sessions

Answer:
4 sessions

Explanation:
At Silver Gym, membership is $25 per month, and personal training sessions are $30 each.
Membership + Personal training session = 25 + 30x
At Fit Factor, membership is $65 per month, and personal training sessions are $20 each.
Membership + Personal training session = 65 + 20x
Membership at Silver Gym = Membership at Fit Factor
25 + 30x = 65 + 20x
30x – 20x = 65 – 25
10x = 40
x = 4
Sarah would have to buy 4 sessions for the total cost at the two gyms to be equal.

Question 4.
Write a real-world situation that could be modeled by the equation 120 + 25x = 45x.
Type below:
_______________

Answer:
120 + 25x = 45x
Sarah offers a plan to tutor a student at $25 per her plus a one-time registration fee of $ 120.
Surah offers an alternative plan to tutor a student at $45 per hour and no registration fee.
120 + 25x = 45x

Question 5.
Write a real-world situation that could be modeled by the equation 100 – 6x = 160 – 10x.
Type below:
_______________

Answer:
100 – 6x = 160 – 10x
The initial water in Tank A is 100 gallons and leaks at 6 gallons per week.
The initial water in Tank B is 160 gallon and leaks at 10 gallons per week
100 – 6x = 160 – 10x

Essential Question Check-In

Question 6.
How can you solve an equation with the variable on both sides?
Type below:
_______________

Answer:
Isolate the variable on one side. Add/subtract the variable with a lower coefficient from both sides. Add/subtract the constant (with the variable) from both sides. Divide both sides by coefficient of the isolated variable.

Independent Practice – Equations with the Variable on Both Sides – Page No. 201

Question 7.
Derrick’s Dog Sitting and Darlene’s Dog Sitting are competing for new business. The companies ran the ads shown.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 1: Equations with the Variable on Both Sides img 1
a. Write and solve an equation to find the number of hours for which the total cost will be the same for the two services.
________ hours

Answer:
3 hours

Explanation:
Hourly rate + One time fee = 5x + 12
Hourly rate + One time fee = 3x + 18
5x + 12 = 3x + 18
5x – 3x = 18 – 12
2x = 6
x = 3
The cost of the two dog sitting would be the same for 3 hrs.

Question 7.
b. Analyze Relationships
Which dog-sitting service is more economical to use if you need 5 hours of service? Explain.
____________

Answer:
Darlene’s Dog Sitting would be cheaper

Explanation:
Let y be the cost of dog sitting after x hours for both companies
y = 5x +12
y = 3x +18
Substitute x = 5
y = 5(5) + 12 = 37
y = 3 (5) + 18 = 33
Compare the cost for both companies for x = 5hr.
$37 > $33
Darlene’s Dog Sitting would be cheaper

Linear Equations 8th Grade Question 8.
Country Carpets charges $22 per square yard for carpeting and an additional installation fee of $100. City Carpets charges $25 per square yard for the same carpeting and an additional installation fee of $70.
a. Write and solve an equation to find the number of square yards of carpeting for which the total cost charged by the two companies will be the same.
_______ square yards

Answer:
10 square yards

Explanation:
Unit square rate + One time installation fee = 22x + 100
Unit square rate + One time installation fee = 25x + 70
22x + 100 = 25x + 70
25x – 22x = 100 – 70
3x = 30
x = 10
The total cost charged by the two companies will be the same for 10 square yards of carpeting.

Question 8.
b. Justify Reasoning
Mr. Shu wants to hire one of the two carpet companies to install carpeting in his basement. Is he more likely to hire Country Carpets or City Carpets? Explain your reasoning.
___________

Answer:
City Carpets are cheaper when x < 10
y = 25(9) + 70 = 295
y = 22(9) + 100 = 298
Country Carpets are cheaper when x > 10
y = 25(11) + 70 = 345
y = 25(11) + 100 = 342
If Mr.Shu needs the carpeting done for less than 10 square yards, he will hire City Carpets and if he needs carpeting for more than 10 square yards, he will hire Country Carpets.

Write an equation to represent each relationship. Then solve the equation.

Question 9.
Two less than 3 times a number is the same as the number plus 10.
________

Answer:
3x – 2 = x + 10
x = 6

Explanation:
Two less than 3 times a number is the same as the number plus 10.
Two less than 3 times x is the same as the x plus 10.
Two less than 3x is the same as the x + 10
3x – 2 is the same as x + 10
3x – 2 = x + 10
3x – x = 10 + 2
2x = 12
x = 6

Question 10.
A number increased by 4 is the same as 19 minus 2 times the number.
______

Answer:
x + 4 = 19 – 2x
x = 5

Explanation:
A number increased by 4 is the same as 19 minus 2 times the number.
x increased by 4 is the same as 19 minus 2x.
x + 4 is the same as 19 – 2x
x + 4 = 19 – 2x
x + 2x = 19 – 4
3x = 15
x = 15/3
x = 5

Question 11.
Twenty less than 8 times a number is the same as 15 more than the number.
Type below:
____________

Answer:
8x – 20 = x + 15
x = 5

Explanation:
Twenty less than 8 times a number is the same as 15 more than the number.
Twenty less than 8 times x is the same as 15 more than the x.
Twenty less than 8x is the same as 15 more than the x
8x – 20 is the same as x + 15
8x – 20 = x + 15
8x – x = 15 + 20
7x = 35
x = 35/7 = 5
x = 5

Equations with the Variable on Both Sides – Page No. 202

Question 12.
The charges for an international call made using the calling card for two phone companies are shown in the table.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 1: Equations with the Variable on Both Sides img 2
a. What is the length of a phone call that would cost the same no matter which company is used?
_______ minutes

Answer:
10 minutes

Explanation:
Cost of minutes + One time fee = 3x + 35
Cost of minutes + One time fee = 2x + 45
3x + 35 = 2x + 45
3x – 2x = 45 – 35
x = 10
The cost would be same for 10 minutes.

Question 12.
b. Analyze Relationships
When is it better to use the card from Company B?
Type below:
____________

Answer:
y = 3x + 35
y = 3(11) + 35 = $68
y = 2x + 45
y = 2(11) + 45 = $67
Since when x > 10, Company B is cheaper so it should be better to use when the length of the call is greater than 10 minutes.

H.O.T.

Focus on Higher Order Thinking

Question 13.
Draw Conclusions
Liam is setting up folding chairs for a meeting. If he arranges the chairs in 9 rows of the same length, he has 3 chairs left over. If he arranges the chairs in 7 rows of that same length, he has 19 left over. How many chairs does Liam have?
______ chairs

Answer:
75 chairs

Explanation:
Number of chairs in 9 row + leftover chairs = 9x + 3
Number of chairs in 7 row + leftover chairs = 7x + 19
9x + 3 = 7x + 19
9x – 7x = 19 – 3
2x = 16
x = 16/2
x = 8
Total number of chairs = 9(8) + 3 = 75

Solving Linear Equations 8th Grade Question 14.
Explain the Error
Rent-A-Tent rents party tents for a flat fee of $365 plus $125 a day. Capital Rentals rents party tents for a flat fee of $250 plus $175 a day. Delia wrote the following equation to find the number of days for which the total cost charged by the two companies would be the same:
365x + 125 = 250x + 175
Find and explain the error in Delia’s work. Then write the correct equation.
Type below:
____________

Answer:
Delia’s equation
365x + 125 = 250x + 175
The error is that she attached the variable with the flat fee (which is constant) and put the daily rent as a constant (which is variable).
Correct equation
125x + 365 = 175x + 250

Question 15.
Persevere in Problem-Solving
Lilliana is training for a marathon. She runs the same distance every day for a week. On Monday, Wednesday, and Friday, she runs 3 laps on a running trail and then runs 6 more miles. On Tuesday and Sunday, she runs 5 laps on the trail and then runs 2 more miles. On Saturday, she just runs laps. How many laps does Lilliana run on Saturday?
________ laps

Answer:
2 laps

Explanation:
Miles covered by lap + Addition number of miles = 3x + 6
Miles covered by lap + Addition number of miles = 5x + 2
3x + 6 = 5x + 2
5x – 3x = 6 – 2
2x = 4
x = 4/2
x = 2

Guided Practice – Equations with Rational Numbers – Page No. 206

Question 1.
Sandy is upgrading her Internet service. Fast Internet charges $60 for installation and $50.45 per month. Quick Internet has free installation but charges $57.95 per month.
a. Write an equation that can be used to find the number of months at which the Internet service would cost the same.
Type below:
____________

Answer:
50.45x + 60 = 57.95x

Explanation:
Write an equation for Fast Internet, where x is the number of months.
Charge per Month × Number of Months + Installation Fee
50.45x + 60
Write an equation for Quick Internet, where x is the number of months.
Charge per Month × Number of Months + Installation Fee
57.95x
50.45x + 60 = 57.95x

Question 1.
b. Solve the equation.
_______ hours

Answer:
8

Explanation:
50.45x + 60 = 57.95x
57.95x – 50.45x = 60
7.5x = 60
x = 60/7.5
x = 8
The total cost will be the same for 8 months.

Solve.

Question 2.
\(\frac{3}{4}\) n – 18 = \(\frac{1}{4}\) n – 4
______

Answer:
n = 28

Explanation:
3/4 . n – 18 = 1/4 . n – 4
Determine the least common multiple of the denominators
LCM is 4
Multiply both sides of the equation by the LCM
4(3/4 . n – 18) = 4(1/4 . n – 4)
3n – 72 = n – 16
3n – n = -16 + 72
2n = 56
n = 56/2
n = 28

Question 3.
6 + \(\frac{4}{5}\) b = \(\frac{9}{10}\) b
_______

Answer:
b = 60

Explanation:
6 + \(\frac{4}{5}\) b = \(\frac{9}{10}\) b
LCM is 10
10(6 + \(\frac{4}{5}\) b) = 10(\(\frac{9}{10}\) b)
60 + 8b = 9b
9b – 8b = 60
b = 60

Solving Linear Equations Worksheets Grade 8 Pdf Question 4.
\(\frac{2}{11}\) m + 16 = 4 + \(\frac{6}{11}\) m
_______

Answer:
m = 33

Explanation:
\(\frac{2}{11}\) m + 16 = 4 + \(\frac{6}{11}\) m
The LCM is 11
11(\(\frac{2}{11}\) m + 16) = 11(4 + \(\frac{6}{11}\) m)
2m + 176 = 44 + 6m
6m – 2m = 176 – 44
4m = 132
m = 132/4
m = 33

Question 5.
2.25t + 5 = 13.5t + 14
_______

Answer:
t = -0.8

Explanation:
2.25t + 5 = 13.5t + 14
13.5t – 2.25t = 5 – 14
11.25t = -9
t = -9/11.25
t = -0.8

Question 6.
3.6w = 1.6w + 24
_______

Answer:
w = 12

Explanation:
3.6w = 1.6w + 24
3.6w – 1.6w = 24
2w = 24
w = 24/2
w = 12

Question 7.
-0.75p – 2 = 0.25p
_______

Answer:
p = -2

Explanation:
-0.75p – 2 = 0.25p
-2 = 0.25p + 0.75p
-2 = p
p = -2

Question 8.
Write a real-world problem that can be modeled by the equation 1.25x = 0.75x + 50.
Type below:
______________

Answer:
1.25x = 0.75x + 50.
Cell offers Plan A for no base fee and $1.25 per minute.
Cell offers Plan B for a $50 base fee and $0.75 per minute.
The equation shows when the total cost of the plan would be equal.

Essential Question Check-In

Question 9.
How does the method for solving equations with fractional or decimal coefficients and constants compare with the method for solving equations with integer coefficients and constants?
Type below:
______________

Answer:
When solving equations with fractional or decimal coefficients, the equations need to be multiplied by the multiple of the denominator such that the equations have integer coefficients and constants.

Independent Practice – Equations with Rational Numbers – Page No. 207

Question 10.
Members of the Wide Waters Club pay $105 per summer season, plus $9.50 each time they rent a boat. Nonmembers must pay $14.75 each time they rent a boat. How many times would a member and a non-member have to rent a boat in order to pay the same amount?
_______ times

Answer:
20 times

Explanation:
Members of the Wide Waters Club pay $105 per summer season, plus $9.50 each time they rent a boat.
9.5x + $105
Nonmembers must pay $14.75 each time they rent a boat.
9.5x + $105 = 14.75x
9.5x – 14.75x = $105
5.25x = 105
x = 105/5.25
x = 20
The cost for members and non-members will be the same for 8 visits.

Question 11.
Margo can purchase tile at a store for $0.79 per tile and rent a tile saw for $24. At another store, she can borrow the tile saw for free if she buys tiles there for $1.19 per tile. How many tiles must she buy for the cost to be the same at both stores?
_______ tiles

Answer:
60 tiles

Explanation:
Margo can purchase tile at a store for $0.79 per tile and rent a tile saw for $24.
0.79x + 24
At another store, she can borrow the tile saw for free if she buys tiles there for $1.19 per tile.
1.19x
0.79x + 24 = 1.19x
1.19x – 0.79x = 24
0.4x = 24
x = 24/0.4
x = 60
Margo should buy 60 tiles for the cost to be the same at both stores.

Question 12.
The charges for two shuttle services are shown in the table. Find the number of miles for which the cost of both shuttles is the same.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 2: Equations with Rational Numbers img 3
_______ miles

Answer:
40 miles

Explanation:
0.1x + 10
0.35x
0.1x + 10 = 0.35x
0.35x – 0.1x = 10
0.25x = 10
x = 10/0.25
x = 40
The cost of shuttles would be the same for 40 miles.

Question 13.
Multistep
Rapid Rental Car charges a $40 rental fee, $15 for gas, and $0.25 per mile driven. For the same car, Capital Cars charges $45 for rental and gas and $0.35 per mile.
a. For how many miles is the rental cost at both companies the same?
_______ miles

Answer:
100 miles

Explanation:
0.25x + 40 + 15 = 0.35x + 45
0.35x – 0.25x = 55 – 45
0.1x = 10
x = 10/0.1
x = 100
The cost of car rentals would be the same for 100 miles.

Question 13.
b. What is that cost?
$ _______

Answer:
$80

Explanation:
Let y be the total cost. Substitute 100 miles in any one of the two equations
y = 0.35x + 45
y = 0.35(100) + 45 = $80
Total cost would be $80.

Question 14.
Write an equation with the solution x = 20. The equation should have the variable on both sides, a fractional coefficient on the left side, and a fraction anywhere on the right side.
Type below:
______________

Answer:
4/3x + 10 = 50/3 + x

Explanation:
Write an equation with the solution x = 20. The equation should have the variable on both sides, a fractional coefficient on the left side, and a fraction anywhere on the right side.
1/3 . x = 1/3 . 20
1/3 . x + x = 1/3 . 20 + x
4/3x = 20/3 + x
4/3x + 10 = 20/3 + x + 10
4/3x + 10 = 50/3 + x

Question 15.
Write an equation with the solution x = 25. The equation should have the variable on both sides, a decimal coefficient on the left side, and a decimal anywhere on the right side. One of the decimals should be written in tenths, the other in hundredths.
Type below:
______________

Answer:
x=25
divide both sides by 25
x/25 = 1
convert 1/25 to decimal form 0.04
0.04x = 1
add x on both sides
1.04x = 1 + x
add 0.1 on both sides
1.04x + 0.1 = x + 1.1

Question 16.
Geometry
The perimeters of the rectangles shown are equal. What is the perimeter of each rectangle?
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 2: Equations with Rational Numbers img 4
Perimeter = _______

Answer:
Perimeter = 3.2

Explanation:
Perimeter of the first rectangle
P = 2(n + n + 0.6) = 2(2n + 0.6) = 4n + 1.2
Perimeter of the second rectangle
P = 2(n + 0.1 + 2n) = 2(3n + 0.1) = 6n + 0.2
the perimeter is equal
4n + 1.2 = 6n + 0.2
6n – 4n = 1.2 – 0.2
2n = 1
n = 1/2
n = 0.5
P = 4n + 1.2 = 4(0.5) + 1.2 = 3.2

Question 17.
Analyze Relationships
The formula F = 1.8C + 32 gives the temperature in degrees Fahrenheit (F) for a given temperature in degrees Celsius (C). There is one temperature for which the number of degrees Fahrenheit is equal to the number of degrees Celsius. Write an equation you can solve to find that temperature and then use it to find the temperature
Type below:
______________

Answer:
x = 1.8x + 32

Explanation:
F = 1.8C +32
let x be the temperature such that it is the same in both Celsius and in Fahrenheit
Then the required equation is
x = 1.8x + 32
subtract 1.8x from both sides
-0.8x = 32
divide by -0.8 on both sides
x = -40
So -40 degree celsius

Equations with Rational Numbers – Page No. 208

Question 18.
Explain the Error
Agustin solved an equation as shown. What error did Agustin make? What is the correct answer?
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 2: Equations with Rational Numbers img 5
x = _______

Answer:
x = -12

Explanation:
Agustin did not multiply by 12 on both sides in step 2. He only partially multiplied the variable and left the constants as such, which doesn’t make any sense.
The correct solution is
12(x/3 – 4) = 12(3x/4 + 1)
4x – 48 = 9x + 12
subtract 12 on both sides
4x – 60 = 9x
subtract 4x on both sides
-60 = 5x
x = -12

H.O.T.

Focus on Higher Order Thinking

Question 19.
Draw Conclusions
Solve the equation \(\frac{1}{2} x-5+\frac{2}{3} x=\frac{7}{6} x+4\). Explain your results.
Type below:
_____________

Answer:
\(\frac{1}{2} x-5+\frac{2}{3} x=\frac{7}{6} x+4\)
The least common multiple of the denominators: LCM(2, 3, 6) = 6
6(\(\frac{1}{2} x-5+\frac{2}{3} x=\frac{7}{6} x+4\))
6.1/2x – 6.5 + 6.2/3x = 6.7/6x +6.4
3x – 30 + 4x = 7x + 24
7x – 30 = 7x + 24
-30 = 24
This is not true. The equation has no solution.

Question 20.
Look for a Pattern
Describe the pattern in the equation. Then solve the equation.
0.3x + 0.03x + 0.003x + 0.0003x + .. = 3
x = ______

Answer:
x = 9

Explanation:
0.3x + 0.03x + 0.003x + 0.0003x + .. = 3
0.3x = 3
0.9x = 9
x = 9

Question 21.
Critique Reasoning
Jared wanted to find three consecutive even integers whose sum was 4 times the first of those integers. He let k represent the first integer, then wrote and solved this equation : k + (k + 1) + (k + 2) = 4k. Did he get the correct answer? Explain.
__________

Answer:
No, it is wrong on two accounts.
First, he has not specified if k is even or not. An easy way of doing so would assume x to be any integer and k=2a
This ensures that k is an even integer.
Nest the question asks for 3 consecutive even integers, Jared just took 3 consecutive integers, and thus at least 1 of them is odd.
So correct representation would be
k + (k+2) + (k + 4) = 4k
which upon solving yields k=6

Guided Practice – Equations with the Distributive Property – Page No. 212

Solve each equation.

Question 1.
4(x + 8) – 4 = 34 – 2x
________

Answer:
x = 1

Explanation:
4(x + 8) – 4 = 34 – 2x
4x + 32 – 4 = 34 – 2x
4x + 2x = 34 – 28
6x = 6
x = 6/6
x = 1

7.3 Equations with the Distributive Property Question 2.
\(\frac{2}{3}\)(9 + x) = -5(4 – x)
________

Answer:
x = 6

Explanation:
\(\frac{2}{3}\)(9 + x) = -5(4 – x)
2/3(9 + x) = -5(4 – x)
3 (2/3(9 + x)) = 3(-5(4 – x))
2(9 + x ) = -15 (4 – x)
18 + 2x = -60 + 15x
15x – 2x = 18 + 60
13x = 78
x = 78/13
x = 6

Question 3.
-3(x + 4) + 15 = 6 – 4x
________

Answer:
x = 3

Explanation:
-3(x + 4) + 15 = 6 – 4x
-3x – 12 + 15 = 6 – 4x
-3x + 3 = 6 – 4x
-3x + 4x = 6 – 3
x = 3

Question 4.
10 + 4x = 5(x – 6) + 33
________

Answer:
x = 7

Explanation:
10 + 4x = 5(x – 6) + 33
10 + 4x = 5x – 30 + 33
10 + 4x = 5x + 3
5x – 4x = 10 – 3
x = 7

Question 5.
x – 9 = 8(2x + 3) – 18
________

Answer:
x = -1

Explanation:
x – 9 = 8(2x + 3) – 18
x – 9 = 16x + 24 – 18
x – 9 = 16x + 6
16x – x = -9 – 6
15x = – 15
x = -15/15
x = -1

Question 6.
-6(x – 1) – 7 = -7x + 2
________

Answer:
x = 3

Explanation:
-6(x – 1) – 7 = -7x + 2
-6x + 6 – 7 = -7x + 2
-6x – 1 = -7x + 2
-7x + 6x = -1 -2
-x = -3
x = 3

Question 7.
\(\frac{1}{10}\)(x + 11) = -2(8 – x)
________

Answer:
x = 9

Explanation:
\(\frac{1}{10}\)(x + 11) = -2(8 – x)
10(\(\frac{1}{10}\)(x + 11)) = 10 (-2(8 – x))
x + 11 = -20(8 – x)
x + 11 = -160 + 20x
20x – x = 11 + 160
19x = 171
x = 171/19 = 9

Question 8.
-(4 – x) = \(\frac{3}{4}\)(x – 6)
________

Answer:
x = -2

Explanation:
-(4 – x) = \(\frac{3}{4}\)(x – 6)
4(-(4 – x)) = 4 (3/4(x – 6))
-16 + 4x = 3x – 18
4x – 3x = -18 + 16
x = -2

Question 9.
-8(8 – x) = \(\frac{4}{5}\)(x + 10)
________

Answer:
x = 10

Explanation:
-8(8 – x) = \(\frac{4}{5}\)(x + 10)
5(-8(8 – x)) = 5(\(\frac{4}{5}\)(x + 10))
-40(8 – x) = 4(x + 10)
-320 + 40x = 4x + 40
40x – 4x = 40 + 320
36x = 360
x = 360/36
x = 10

Question 10.
\(\frac{1}{2}\)(16 – x) = -12(x + 7)
________

Answer:
x = 8

Explanation:
\(\frac{1}{2}\)(16 – x) = -12(x + 7)
2 (\(\frac{1}{2}\)(16 – x)) = 2 (-12(x + 7))
16 – x = -24 (x + 7)
16 – x = -24x – 168
24x – x = -168 – 16
23x = 184
x = 184/23
x = 8

Lesson 7.3 Equations with the Distributive Property Answer Key Question 11.
Sandra saves 12% of her salary for retirement. This year her salary was $3,000 more than in the previous year, and she saved $4,200.What was her salary in the previous year?
Write an equation _____
Sandra’s salary in the previous year was _____
Salary = $ _____

Answer:
Write an equation 0.12x + 360 = 4200
Sandra’s salary in the previous year was $32000
Salary = $3000

Explanation:
0.12(x + 3000) = 4200
0.12x + 360 = 4200
0.12x = 4200 – 360
0.12x = 3840
x = 3840/0.12
x = 32000
Sandra’s salary in the previous year was $32000

Essential Question Check-In

Question 12.
When solving an equation using the Distributive Property, if the numbers being distributed are fractions, what is your first step? Why?
Type below:
___________

Answer:
Multiply both sides by the denominator of the fraction

Independent Practice – Equations with the Distributive Property – Page No. 213

Question 13.
Multistep
Martina is currently 14 years older than her cousin Joey. In 5 years she will be 3 times as old as Joey. Use this information to answer the following questions.
a. If you let x represent Joey’s current age, what expression can you use to represent Martina’s current age?
Type below:
___________

Answer:
y = x + 14

Explanation:
y = x + 14
where x is Joey’s current age and t is Martna’s current age.

Question 13.
b. Based on your answer to part a, what expression represents Joey’s age in 5 years? What expression represents Martina’s age in 5 years?
Type below:
___________

Answer:
Ages in 5 years
Joey’s age = x + 5
Martina’s age = x + 14 + 5 = x + 19

Question 13.
c. What equation can you write based on the information given?
Type below:
___________

Answer:
3(x + 5) = x + 19

Explanation:
In 5 years, Martina will be three times as old as Joey
3(x + 5) = x + 19

Question 13.
d. What is Joey’s current age? What is Martina’s current age?
Joey’s current age ___________
Martina’s current age ___________

Answer:
Joey’s current age 2
Martina’s current age 16

Explanation:
3(x + 5) = x + 19
3x + 15 = x + 19
3x – x = 19 – 15
2x = 4
x = 2

Question 14.
As part of a school contest, Sarah and Luis are playing a math game. Sarah must pick a number between 1 and 50 and give Luis clues so he can write an equation to find her number. Sarah says, “If I subtract 5 from my number, multiply that quantity by 4, and then add 7 to the result, I get 35.” What equation can Luis write based on Sarah’s clues and what is Sarah’s number?
Type below:
___________

Answer:
x = 12

Explanation:
As part of a school contest, Sarah and Luis are playing a math game. Sarah must pick a number between 1 and 50 and give Luis clues so he can write an equation to find her number. Sarah says, “If I subtract 5 from my number, multiply that quantity by 4, and then add 7 to the result, I get 35.”
4 (x – 5) + 7 = 35
4x – 20 + 7 = 35
4x – 13 = 35
4x = 35 + 13
4x = 48
x = 48/4
x = 12

Question 15.
Critical Thinking
When solving an equation using the Distributive Property that involves distributing fractions, usually the first step is to multiply by the LCD to eliminate the fractions in order to simplify computation. Is it necessary to do this to solve \(\frac{1}{2}\)(4x + 6) = 13(9x – 24)? Why or why not?
___________

Answer:
It is not necessary. In this case, distributing the fractions directly results in whole-number coefficients and constants, however, if the results are not in whole-number coefficients and constants it is harder to solve fractions.

Question 16.
Solve the equation given in Exercise 15 with and without using the LCD of the fractions. Are your answers the same?
___________

Answer:
x = 11

Explanation:
\(\frac{1}{2}\)(4x + 6) = 13(9x – 24)
6(\(\frac{1}{2}\)(4x + 6)) = 6(13(9x – 24))
3(4x + 6) = 2(9x – 24)
12x + 18 = 18x – 48
18x – 12x = 18 + 48
6x = 66
x = 66/6
x = 11

Equations with the Distributive Property – Page No. 214

Question 17.
Represent Real-World Problems
A chemist mixed x milliliters of 25% acid solution with some 15% acid solution to produce 100 milliliters of a 19% acid solution. Use this information to fill in the missing information in the table and answer the questions that follow.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 3: Equations with the Distributive Property img 6
a. What is the relationship between the milliliters of acid in the 25% solution, the milliliters of acid in the 15% solution, and the milliliters of acid in the mixture?
Type below:
_____________

Answer:
The milliliters of acid in the 25% solution plus the milliliters of acid in the 15% solution equals the milliliters of acid in the mixture

Explanation:
grade 8 chapter 7 image 9

Question 17.
b. What equation can you use to solve for x based on your answer to part a?
Type below:
_____________

Answer:
0.25x + 0.15(100 – x) = 19

Question 17.
c. How many milliliters of the 25% solution and the 15% solution did the chemist use in the mixture?
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 3: Equations with the Distributive Property img 7
Type below:
_____________

Answer:
0.25x + 0.15(100 – x) = 19
0.25x + 15 – 0.15x = 19
0.1x + 15 = 19
0.1x = 4
x = 4/0.1
x = 40
The chemist used 40ml of the 25% solution and 100 – 40 = 60ml of the 15% solution.

H.O.T.

Focus on Higher Order Thinking

Question 18.
Explain the Error
Anne solved 5(2x) – 3 = 20x + 15 for x by first distributing 5 on the left side of the equation. She got the answer x = -3. However, when she substituted -3 into the original equation for x, she saw that her answer was wrong. What did Anne do wrong, and what is the correct answer?
x = ________

Answer:
x = -1.8

Explanation:
Dado que 5 solo se multiplica por 2x, no tiene sentido usar la distribución aquí. Básicamente, distribuir 5 fue el problema
Solución correcta:
5 (2x) – 3 = 20x + 15
10x -3 = 20x + 15
restar 15 en ambos lados
10x – 18 = 20x
restar 10x de ambos lados
-18 = 10x
x = -1.8

Question 19.
Communicate Mathematical Ideas
Explain a procedure that can be used to solve 5[3(x + 4) – 2(1 – x)] – x – 15 = 14x + 45. Then solve the equation.
x = ________

Answer:
x = 1

Explanation:
5[3(x + 4) – 2(1 – x)] – x – 15 = 14x + 45
5[3x + 12 – 2 + 2x] – x – 15 = 14x + 45
5[5x + 10] – x – 15 = 14x + 45
25x + 50 – x – 15 = 14x + 45
24x + 35 = 14x + 45
24x – 14x = 45 – 35
10x = 10
x = 1

Guided Practice – Equations with Many Solutions or No Solution – Page No. 218

Use the properties of equality to simplify each equation. Tell whether the final equation is a true statement.

Question 1.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 4: Equations with Many Solutions or No Solution img 8
The statement is: _______

Answer:
The statement is: true

Explanation:
3x – 2 = 25 – 6x
3x + 6x -2 = 25 -6x + 6x
9x – 2 = 25
9x -2 + 2 = 25 + 2
9x = 27
x = 27/9
x = 3
The statement is true.

Solving Equations by Clearing Fractions Worksheet Question 2.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 4: Equations with Many Solutions or No Solution img 9
____________

Answer:
The statement is false.

Explanation:
2x – 4 = 2(x – 1) + 3
2x – 4 = 2x – 2 + 3
2x – 4 = 2x + 1
2x – 4 – 2x = 2x + 1 – 2x
-4 not equal to 1
The statement is false.

Question 3.
How many solutions are there to the equation in Exercise 2?
____________

Answer:
There is no solution to exercise 2.

Question 4.
After simplifying an equation, Juana gets 6 = 6. Explain what this means.
____________

Answer:
When 6 = 6, there are infinite solutions.

Write a linear equation in one variable that has infinitely many solutions.

Question 5.
Start with a _____ statement.
Add the _____ to both sides.
Add the _____ to both sides.
Combine _____ terms.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 4: Equations with Many Solutions or No Solution img 10
Type below:
____________

Answer:
Start with a “true” statement
Add the “same variable” to both sides
Add the “same constant” to both sides
Combine “like” terms

Explanation:
Start with a “true” statement
10 = 10
Add the “same variable” to both sides
10 + x = 10 + x
Add the “same constant” to both sides
10 + x + 5 = 10 + x + 5
Combine “like” terms
15 + x = 15 + x

Essential Question Check-In

Question 6.
Give an example of an equation with an infinite number of solutions. Then make one change to the equation so that it has no solution.
Type below:
____________

Answer:
An equation with infinitely many solutions
x – 2x + 3 = 3 – x
-x + 3 = 3 – x
+x/3 = +x/3
An equation for no solution
x – 2x + 3 = 3 – x + 4
-x + 3 = 7 – x
-x/3 = -x/7

Independent Practice – Equations with Many Solutions or No Solution – Page No. 219

Tell whether each equation has one, zero, or infinitely many solutions.

Question 7.
-(2x + 2) – 1 = -x – (x + 3)
____________

Answer:
The statement is true

Explanation:
-(2x + 2) – 1 = -x – (x + 3)
-2x – 2 – 1 = -x – x + 3
-2x – 3 = -2x + 3
-3 = -3
The statement is true

Question 8.
-2(z + 3) – z = -z – 4(z + 2)
____________

Answer:
The statement is false.

Explanation:
-2(z + 3) – z = -z – 4(z + 2)
-3z – 6 = -3z -8
-3z -6 + 3z = -3z – 8 + 3z
-6 not equal to -8
The statement is false.

Create an equation with the indicated number of solutions.

Question 9.
No solution:
3(x – \(\frac{4}{3}\)) = 3x + _____
Type below:
______________

Answer:
3(x – \(\frac{4}{3}\)) = 3x + ?
3x – 4 = 3x + ?
3x – 4 = 3x + 2
When there is no solution, the statement should be false. Any number except -4 would make the equation have no solutions.

Question 10.
Infinitely many solutions:
2(x – 1) + 6x = 4( _____ – 1) + 2
Type below:
______________

Answer:
2(x – 1) + 6x = 4( _____ – 1) + 2
2(x – 1) + 6x = 4( ? – 1) + 2
2x – 2 + 6x = 4(? – 1) + 2
8x – 2 = 4(? – 1) + 2
8x – 2 = 4(2x – 1) + 2
8x – 2 = 8x – 4 + 2
8x – 2 = 8x – 2
When there are infinitely many solutions, the statement should be true

Question 11.
One solution of x = -1:
5x – (x – 2) = 2x – ( _____ )
Type below:
______________

Answer:
Put x = -1 in the equation
-5 – (-1 – 2) = -2 – blank
simplifying
-2 = -2 – blank
add 2 on both sides
0 = blank

Question 12.
Infinitely many solutions:
-(x – 8) + 4x = 2( _____ ) + x
Type below:
______________

Answer:
-(x – 8) + 4x = 2( ?) + x
-x + 8 + 4x = 2(?) + x
3x + 8 = 2(?) + x
3x + 8 = 2 (x + 4) + x
3x + 8 = 2x + 8x + x
3x + 8 = 3x + 8
When there are infinitely many solutions, the statement should be true.

Question 13.
Persevere in Problem Solving
The Dig It Project is designing two gardens that have the same perimeter. One garden is a trapezoid whose nonparallel sides are equal. The other is a quadrilateral. Two possible designs are shown at the right.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 4: Equations with Many Solutions or No Solution img 11
a. Based on these designs, is there more than one value for x? Explain how you know this.
______________

Answer:
There are more than one value of x

Explanation:
Perimeter of the trapezoid
P = 2x – 2 + x + 1 + x + x + 1 = 5x
Perimeter of the quadrilateral
P = 2x – 9 + x + x + 8 + x + 1 = 5x
5x = 5x
There are more than one value of x

Question 13.
b. Why does your answer to part a make sense in this context?
Type below:
______________

Answer:
The condition was that the two perimeters are to be equal. However, a specific number was not given, so there are an infinite number of possible perimeters

Explanation:
Interpretation of part a in this context
The condition was that the two perimeters are to be equal. However, a specific number was not given, so there are an infinite number of possible perimeters

Question 13.
c. Suppose the Dig It Project wants the perimeter of each garden to be 60 meters. What is the value of x in this case? How did you find this?
______ meters

Answer:
12 meters

Explanation:
2x – 2 + x + 1 + x + x + 1 = 60
5x = 60
x = 60/5
x = 12

Equations with Many Solutions or No Solution – Page No. 220

Question 14.
Critique Reasoning
Lisa says that the indicated angles cannot have the same measure. Marita disagrees and says she can prove that they can have the same measure. Who do you agree with? Justify your answer.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Lesson 4: Equations with Many Solutions or No Solution img 12
I agree with: ______________

Answer:
I agree with: Marita

Explanation:
9x – 25 + x = x + 50 + 2x – 12
10x – 25 = 3x + 38
10x – 3x = 38 + 25
7x = 63
x = 63/7
x = 9
When x = 9 the angles will be same and for any other value of x, the angles will not be the same.

Question 15.
Represent Real-World Problems
Adele opens an account with $100 and deposits $35 a month. Kent opens an account with $50 and also deposits $35 a month. Will they have the same amount in their accounts at any point? If so, in how many months and how much will be in each account? Explain.
______________

Answer:
Adele’s amount after x months
A = 100 + 35x
Kent’s amount after x months
A = 50 + 35x
100 + 35x = 50 + 35x
100 is not equal to 50
The statement is false, the amounts in two accounts would never be equal.

H.O.T.

Focus on Higher Order Thinking

Question 16.
Communicate Mathematical Ideas
Frank solved an equation and got the result x = x. Sarah solved the same equation and got 12 = 12. Frank says that one of them is incorrect because you cannot get different results for the same equation. What would you say to Frank? If both results are indeed correct, explain how this happened.
Frank is: ____________

Answer:
Both of them can be correct as both equations give the same result i.e. there are infinitely many solutions. Frank eliminated the constant from both sides while Sarah eliminated the variable from both sides.

Question 17.
Critique Reasoning
Matt said 2x – 7 = 2(x – 7) has infinitely many solutions. Is he correct? Justify Matt’s answer or show how he is incorrect.
Matt is: ____________

Answer:

Explanation:
2x – 7 = 2(x – 7)
2x – 7 = 2x – 14
-7 not equal to -14
The statement is false, there is no solution. Matt is incorrect.

7.1 Equations with the Variable on Both Sides – Model Quiz – Page No. 221

Solve.

Question 1.
4a – 4 = 8 + a
_______

Answer:
a = 4

Explanation:
4a – 4 = 8 + a
4a – a = 8 + 4
3a = 12
a = 12/3
a = 4

Question 2.
4x + 5 = x + 8
_______

Answer:
x = 1

Explanation:
4x + 5 = x + 8
4x – x = 8 – 5
3x = 3
x = 3/3
x = 1

Homework and Practice Solving Linear Equations 7.1 Answer Key Question 3.
Hue is arranging chairs. She can form 6 rows of a given length with 3 chairs left over, or 8 rows of that same length if she gets 11 more chairs. Write and solve an equation to find how many chairs are in that row length.
_______ chairs

Answer:
7 chairs

Explanation:
Hue is arranging chairs. She can form 6 rows of a given length with 3 chairs left over, or 8 rows of that same length if she gets 11 more chairs.
6x + 3 = 8x – 11
8x – 6x = 3 + 11
2x = 14
x = 14/2
x = 7
There are 7 chairs in each row.

7.2 Equations with Rational Numbers

Solve.

Question 4.
\(\frac{2}{3} n-\frac{2}{3}=\frac{n}{6}+\frac{4}{3}\)
_______

Answer:
n = 4

Explanation:
\(\frac{2}{3} n-\frac{2}{3}=\frac{n}{6}+\frac{4}{3}\)
The LCM is 6.
6(2/3n – 2/3) = 6(n/6 + 4/3)
6(2/3n) -6(2/3) = 6(n/6) + 6(4/3)
4n – 4 = n + 8
4n – n = 8 + 4
3n = 12
n = 12/3
n = 4

Question 5.
1.5d + 3.25 = 1 + 2.25d
_______

Answer:
d = 3

Explanation:
1.5d + 3.25 = 1 + 2.25d
2.25d – 1.5d = 3.25 – 1
0.75d = 2.25
d = 2.25/0.75
d = 3

Question 6.
Happy Paws charges $19.00 plus $1.50 per hour to keep a dog during the day. Woof Watchers charges $14.00 plus $2.75 per hour. Write and solve an equation to find for how many hours the total cost of the services is equal.
_______ hours

Answer:
3.2 hours

Explanation:
Happy Paws charges $19.00 plus $1.50 per hour to keep a dog during the day.
1.5x + 19
Woof Watchers charges $14.00 plus $2.75 per hour.
2.75x + 15
1.5x + 19 = 2.75x + 15
2.75x – 1.5x = 19 – 15
1.25x = 4
x = 4/1.25
x = 3.2
The total cost of the services is equal after 3.2 hrs.

7.3 Equations with the Distributive Property

Solve.

Question 7.
14 + 5x = 3(-x + 3) – 11
_______

Answer:
x = -2

Explanation:
14 + 5x = 3(-x + 3) – 11
14 + 5x = -3x + 9 – 11
14 + 5x = -3x – 2
5x + 3x = -2 –  14
8x = – 16
x = -16/8
x = -2

Question 8.
\(\frac{1}{4}\)(x – 7) = 1 + 3x
_______

Answer:
x = -1

Explanation:
\(\frac{1}{4}\)(x – 7) = 1 + 3x
4(\(\frac{1}{4}\)(x – 7)) = 4(1 + 3x)
(x – 7) = 4 + 12x
12x – x = -7 – 4
11x = -11
x = -11/11
x = -1

Question 9.
-5(2x – 9) = 2(x – 8) – 11
_______

Answer:
x = 6

Explanation:
-5(2x – 9) = 2(x – 8) – 11
-10x + 45 = 2x – 16 – 11
-10x + 45 = 2x – 27
2x + 10x = 45 + 27
12x = 72
x = 72/12
x = 6

Question 10.
3(x + 5) = 2(3x + 12)
_______

Answer:
x = -3

Explanation:
3(x + 5) = 2(3x + 12)
3x + 15 = 6x + 24
6x – 3x = 15 – 24
3x = -9
x = -9/3
x = -3

7.4 Equations with Many Solutions or No Solution

Tell whether each equation has one, zero, or infinitely many solutions.

Question 11.
5(x – 3) + 6 = 5x – 9
____________

Answer:
There are infinitely many solutions

Explanation:
5(x – 3) + 6 = 5x – 9
5x – 15 + 6 = 5x – 9
5x – 9 = 5x – 9
The statement is true. There are infinitely many solutions.

Question 12.
5(x – 3) + 6 = 5x – 10
____________

Answer:
There are no solutions

Explanation:
5(x – 3) + 6 = 5x – 10
5x – 15 + 6 = 5x – 10
5x – 9 = 5x – 10
-9 not equal to -10
The statement is false. There are no solutions.

Question 13.
5(x – 3) + 6 = 4x + 3
____________

Answer:
There is one solution

Explanation:
5(x – 3) + 6 = 4x + 3
5x – 15 + 6 = 4x + 3
5x – 9 = 4x + 3
5x – 4x = 3 + 9
x = 12
There is one solution

Selected Response – Mixed Review – Page No. 222

Question 1.
Two cars are traveling in the same direction. The first car is going 40 mi/h, and the second car is going 55 mi/h. The first car left 3 hours before the second car. Which equation could you solve to find how many hours it will take for the second car to catch up to the first car?
Options:
a. 55t + 3 = 40t
b. 55t + 165 = 40t
c. 40t + 3 = 55t
d. 40t + 120 = 55t

Answer:
d. 40t + 120 = 55t

Explanation:
Two cars are traveling in the same direction. The first car is going 40 mi/h, and the second car is going 55 mi/h. The first car left 3 hours before the second car.
3 × 40 + 40t = 120 + 40t
55t
40t + 120 = 55t

Question 2.
Which linear equation is represented by the table?
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Mixed Review img 13
Options:
a. y = -x + 5
b. y = 2x – 1
c. y = x + 3
d. y = -3x + 11

Answer:
a. y = -x + 5

Explanation:
Find the slope using
m = (y2 – y1)/(x2 – x1)
where (x1, y1) = (3, 2), (x2, y2) = (1, 4)
Slope = (4 – 2)/(1 – 3) = -2/2 = -1

Question 3.
Shawn’s Rentals charges $27.50 per hour to rent a surfboard and a wetsuit. Darla’s Surf Shop charges $23.25 per hour to rent a surfboard plus $17 extra for a wetsuit. For what total number of hours are the charges for Shawn’s Rentals the same as the charges for Darla’s Surf Shop?
Options:
a. 3
b. 4
c. 5
d. 6

Answer:
b. 4

Explanation:
Shawn’s Rentals charges $27.50 per hour to rent a surfboard and a wetsuit.
27.5x
Darla’s Surf Shop charges $23.25 per hour to rent a surfboard plus $17 extra for a wetsuit.
23.25x + 17
23.25x + 17 = 27.5x
27.5x – 23.25x = 17
4.25x = 17
x = 17/4.25
x = 4
The charge would be equal after 4 hrs

Question 4.
Which of the following is irrational?
Options:
a. -8
b. 4.63
c. \(\sqrt { x } \)
d. \(\frac{1}{3}\)

Answer:
c. \(\sqrt { x } \)

Explanation:
\(\sqrt { x } \) is irrational

Question 5.
Greg and Jane left a 15% tip after dinner. The amount of the tip was $9. Greg’s dinner cost $24. Which equation can you use to find x, the cost of Jane’s dinner?
Options:
a. 0.15x + 24 = 9
b. 0.15(x + 24) = 9
c. 15(x + 24) = 9
d. 0.15x = 24 + 9

Answer:
b. 0.15(x + 24) = 9

Explanation:
Let x be the cost of Jane’s dinner. The amount of tip is the 15% of the total cost of dinner.
0.15(x + 24) = 9

Question 6.
For the equation 3(2x − 5) = 6x + k, which value of k will create an equation with infinitely many solutions?
Options:
a. 15
b. -5
c. 5
d. -15

Answer:
d. -15

Explanation:
3(2x – 5) = 6x + k
6x – 15 = 6x + k
6x – 15 = 6x – 15
The statement is true. k = -15

Question 7.
Which of the following is equivalent to 2−4?
Options:
a. \(\frac{1}{16}\)
b. \(\frac{1}{8}\)
c. -2
d. -16

Answer:
a. \(\frac{1}{16}\)

Explanation:
2−4
1/24
1/16

Mini-Task

Question 8.
Use the figures below for parts a and b.
Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations Mixed Review img 14
a. Both figures have the same perimeter. Solve for x.
_______

Answer:
x=12

Explanation:
4x+10=3x+22
4x – 3x = 22 – 10
x = 12
Answer: x=12

Question 8.
b. What is the perimeter of each figure?
_______

Answer:
Both are 58

Explanation:
x + x + 5 + x + x + 5
12 + 12 + 5 + 12 + 12 + 5
58
x + 7 + x + 4 + x + 11
12 + 7 + 12 + 4 + 12 + 11
58

Conclusion:

Go Math Grade 8 Answer Key Chapter 7 Solving Linear Equations are available along with the all practice questions here. Get all the questions, answers and also Go Math Grade 8 text books for free online. Refer to Go Math Grade 8 Chapter 7 Solving Linear Equations Answer Key to learn the quick maths in an easy way.

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Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

This chapter can improve student’s math skills, by referring to the Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test, and with the help of this Go Math Grade 3 Assessment Test Answer Key, students can score good marks in the examination

Go Math Grade 3 Answer Key Chapter 12 contains all the topics of chapter 12 which helps to test the student’s knowledge. Through this assessment test, students can check their knowledge. This assessment test is also helpful for the teachers to know how much a student understood the topics.

Chapter 12:

Test – Page 1 – Page No. 121

Question 1.
Which words describe this shape? Mark all that apply.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 1 img 1
Options:
a. polygon
b. hexagon
c. open shape
d. quadrilateral

Answer: a. Polygon

Explanation: In geometry, a polygon is a plane figure that is described by a finite number of straight-line segments connected to form a closed polygonal chain or polygonal circuit.

Question 2.
Sam drew one side of a rhombus with at least 1 right angle. Draw the other 3 sides to complete Sam’s shape.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 1 img 2

Explanation:

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

A rhombus is a Parallelogram with 4 equal sides. Because it is a parallelogram, opposite angles are congruent. And because it is a quadrilateral the sum of all angles must be equal to 360 degrees. So, if one angle is right then the opposite angle is 90 degrees. Then the 1st pair has a sum of 180 degrees, then 360–180 = 180, so the other pair of angles sum to 180 degrees. But the other pair of angles are also opposite of each other so must be congruent, so each of the other two angles is also 90 degrees. So, if one angle is right all 4 angles are right angles. These kinds of rhombi, or rhombuses, are called squares. Squares are a subset of rhombi.
So after completing the shape with the other three sides we get a Square.

Question 3.
Louie has a stamp with this shape.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 1 img 3
For numbers 3a–3d, select True or False for each statement about the shape.
a. The shape has no right angles.
i. True
ii. False

Answer: True.

Explanation: Pentagon can have right angles too. It can have a maximum of 3 right angles but here the given diagram seems like a regular Pentagon, which is having each interior angle of a regular pentagon = 108 degrees. Thus there is no right angle.

Question 3.
b. The shape has 5 angles greater than a right angle.
i. True
ii. False

Answer: True.

Explanation: The sum of the interior angles should be equal to 540°. Since here in the current pentagon, there is no right angle if we divide 540/5 minimum angle would be 108°. Hence the shape has 5 angles greater than a right angle.

Question 3.
c. The shape has 2 angles less than a right angle.
i. True
ii. False

Answer: False.

Explanation: Given shape is a regular pentagon which is having a regular interior angle of 108° each.

Question 3.
d. The shape has 1 right angle.
i. True
ii. False

Answer: False.

Explanation: Given shape is a regular pentagon which is having a regular interior angle of 108° each.

Test – Page 2 – Page No. 122

Question 4.
Jane used a Venn diagram to sort shapes.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 2 img 4
Part A
Draw a plane shape that belongs inside the overlap region of the diagram.

Answer: Square, rectangle

Explanation: Overlap region has Quadrilateral/Polygons having right angles which are Square and rectangle.

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

Question 4.
Part B
How can you describe the shapes that belong in the section where the circles overlap?

Answer: To understand clearly the intersection part first we have to understand Polygon with the right angle and Quadrilaterals.

Explanation:
Polygon: In geometry, a polygon is a plane figure that is described by a finite number of straight-line segments connected to form a closed polygonal chain or polygonal circuit. The solid plane region, the bounding circuit, or the two together, maybe called a polygon

Right-angled Polygon: A polygon whose interior angles are 90°.

Quadrilaterals: In geometry, a quadrilateral is a polygon with four edges and four vertices.

So here in the given diagram intersection part comes under a Polygon/Quadrilateral having one or more interior angles

Question 5.
Write one of the following words to name each part of the figure.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 2 img 5
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 2 img 6

Answer:

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

Question 6.
Describe the angles and sides of this triangle.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 2 img 7

Answer: All triangles have interior angles adding to 180°. When one of those interior angles is 90°, it is a right angle and the triangle is known as the right triangle. In drawing the interior 90° angle is indicated with a small square in the vertex. The side opposite to the right angle is its hypotenuse, which is the longest side of all three. The other two angles in a right triangle add to 90°, they are complementary. The sides opposite to the complementary angles are the triangle’s legs.

Test – Page 3 – Page No. 123

Question 7.
Which words describe this shape? Mark all that apply.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 3 img 8
Options:
a. rectangle
b. rhombus
c. quadrilateral
d. square

Answer: b. rhombus, c. quadrilateral

Explanation:
Quadrilaterals: In geometry, a quadrilateral is a polygon with four edges and four vertices.
Rhombus: A rhombus is a quadrilateral whose four sides all have the same length.
The given figure is having 4 edges and 4 vertices that come under Quadrilateral also seem like having all the four sides of the same length which comes under rhombus too.

Question 8.
Divide each shape into the number of equal parts shown.
Then write the fraction that describes each part of the whole.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 3 img 9

Answer:

Explanation:

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test    The given shape is dived into 4 equal parts. Therefore, the fraction of each part of the whole is ¼ (one fourth).

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment TestThe given shape has been divided into 6 equal parts. Therefore, the fraction of each part of the whole is 1/6.

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test The given shape has been divided into eight equal parts. Therefore, the fraction of each part of the whole is 1/8.

Question 9.
Cho drew a triangle with 3 angles that are each less than a right angle.
For numbers 9a–9d, choose Yes or No to tell whether that triangle could be the triangle Cho drew.
a. Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 3 img 10
i. yes
ii. no

Answer: Yes.

Explanation: Cho drew a triangle having all the angles less than 90 degrees. So it could be Cho’s triangle.

Question 9.
b. Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 3 img 11
i. yes
ii. no

Answer: No.

Explanation: This triangle is having a right angle (90 degrees). So it could not Cho’s triangle.

Question 9.
c. Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 3 img 12
i. yes
ii. no

Answer: Yes.

Explanation: Tt is possible to be triangle drew by Cho. Since it is not having an angle which is a greater right angle.

Question 9.
d. Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 3 img 13
i. yes
ii. no

Answer: Yes.

Explanation: It could be Cho’s triangle too as it is not having an angle which is a greater right angle.

Test – Page 4 – Page No. 124

Question 10.
Look at this group of shapes.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 4 img 14
Part A
Sort the shapes by sides. How many groups did you make? Explain how you sorted the shapes.

Answer: Two groups

Explanation: We can sort by using the number of sides. The first group with two triangles having three sides each, Second group with Quadrilaterals having four edges and four vertices.

Question 10.
Part B
Sort the shapes by angles. How many groups did you make? Explain how you sorted the shapes.

Answer: Two groups.

Explanation: Sorted the shapes by angles, Right-angled polygons, and non-right angled polygons.

Question 11.
Gina drew a quadrilateral that always has 4 sides of equal length and 4 right angles. What quadrilateral did she draw?

Answer: Square

Explanation: Square is the quadrilateral having 4 sides of equal length with 4 right interior angles.

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

Test – Page 5 – Page No. 125

Question 12.
Lacy used a Venn diagram to sort shapes. What label could she use for circle A?
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 5 img 15

Answer: Polygons.

Explanation: Polygons with all sides of equal length.

Question 13.
Victor drew lines to divide a trapezoid into equal parts that represent \(\frac{1}{3}\) of the whole area. Draw lines to show how Victor divided the trapezoid.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 5 img 16

Answer:

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

Question 14.
Luisa drew this hexagon. Select the pairs of sides that appear to be parallel. Mark all that apply.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 5 img 17
Options:
a. a and b
b. b and e
c. c and f
d. d and a

Answer: b,d.

Explanation: b and e, d and a are the pairs of sides that appear to be parallel.

Test – Page 6 – Page No. 126

Question 15.
Tell why this shape is NOT a polygon.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 6 img 18

Answer: A polygon by definition has straight line segments as its sides. If a geometrical figure has curved sides, it is not considered a polygon. Thus the given shape is not a Polygon.

Question 16.
Paige drew the triangle below. What statements describe the angles? Mark all that apply.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 6 img 19
Options:
a. At least one is less than a right angle.
b. One is a right angle.
c. All are less than a right angle.
d. One is greater than a right angle.

Answer: a,b.

Explanation: Since one angle is the right angle other two angles are less than the right angle.

Question 17.
Bella drew a quadrilateral with 2 pairs of opposite sides that are parallel. The shape has no right angles and has sides that are of equal length. Draw a shape Bella could have drawn.

Answer: Could be a parallelogram as it will have parallel opposite sides without any right angle.

Explanation:

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test

Question 18.
For 18a–18d, select True or False for each description of a line segment.
Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Test - Page 6 img 20
a. straight
i. True
ii. False

Answer: True

Explanation: This is known as a line as it is an infinitely thin, infinitely long collection of points extending in two opposite directions

Question 18.
For 18a–18d, select True or False for each description of a line segment.
b. has 2 endpoints
i. True
ii. False

Answer: True.

Explanation: It is having two endpoints.

Question 18.
c. continues in 1 direction
i. True
ii. False

Answer: False.

Explanation: Line segment continue forever in zero directions.

Question 18.
d. part of a line
i. True
ii. False

Answer: True.

Explanation: Part of the line that connects two points.

Conclusion:

This assessment test helps students to check their math skills. Go Math Grade 3 Chapter 10 questions are explained in detail that students can understand easily.

Go Math Grade 3 Answer Key Chapter 12 Two-Dimensional Shapes Assessment Test Read More »

Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test

Go Math Grade 3 Answer Key Chapter 11 contains all the topics of chapter 11 which helps to test the student’s knowledge. Through this assessment test, students can check their knowledge. This assessment test is also helpful for the teachers to know how much a student understood the topics.

This chapter can improve student’s math skills, by referring to the Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test, and with the help of this Go Math Grade 3 Assessment Test Answer Key, students can score good marks in the examination

Chapter 11: Perimeter and Area Assessment Test

Test – Page 1 – Page No. 111

Question 1.
Find the perimeter of each figure on the grid. Identify the figures that have a perimeter of 16 units. Mark all that apply.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 1 img 1
Options:
a. A
b. B
c. C
d. D

Answer: a,c,d have a perimeter of 16 units.

Explanation: To find the perimeter we will add the total length of the lines that form a shape.
The perimeter of shape A is 1+4+1+1+1+3+2+3+= 16 units.
The perimeter of shape B is 1+4+5+4+2+2+2+2= 22 units.
The perimeter of shape C is 4+4+2+1+2+3= 16 units.
The perimeter of shape D is 1+1+1+1+1+1+1+4+4+1= 16 units.

Question 2.
Mr. Howard is putting wood trim around his window. How many feet of wood trim does Mr. Howard need for the perimeter of the window?
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 1 img 2
_____ feet

Answer: 10 feet.

Explanation: The perimeter of the window is 3+2+3+2= 10 ft.

Question 3.
Greg drew this figure on dot paper. What is the area of the figure?
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 1 img 3
_____ square units

Answer: 17 square units.

Explanation: To find the area we need to count the square units.
So, the area of the figure is 17 square units.

Test – Page 2 – Page No. 112

Question 4.
Brady is placing square tiles on the floor of the kitchen. Each unit square is 1 square foot.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 4
Which equations can Brady use to find the area of the kitchen floor? Mark all that apply.
Options:
a. 4 × 6 = 24
b. 4 + 4 + 4 + 4 + 4 = 20
c. 4 + 6 + 4 + 6 = 20
d. 6 + 6 + 6 + 6 = 24
e. 4 × 5 = 20
f. 6 × 4 = 24

Answer: f

Explanation: The area of the kitchen floor is 6 × 4 = 24  = 20.

Question 5.
Glenda used square tiles to make a rectangle. The rectangle has a perimeter of 8 units and an area of 4 square units. Which could be Glenda’s rectangle?
Options:
a. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 5
b. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 6
c. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 7
d. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 8

Answer: d

Explanation: As in the above figures the option d has a perimeter of 8 units and an area of 4 square units.

Question 6.
Jill uses a ruler to draw a square. The perimeter of the square is 20 inches. Select a number to complete the sentence.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 9
The square has a side length of Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 2 img 10 inches.
_____

Answer: 5 inches.

Explanation: As the perimeter of the square is 20 inches. So the side length of the square is
P= 4c
20= 4c
c= 20/4
= 5 inches.

Test – Page 3 – Page No. 113

Question 7.
Rosa drew two rectangles on grid paper. Circle the words that make the sentence true.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 3 img 11
Rectangle A has an area that is Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 3 img 12 area of Rectangle B, and a perimeter that is Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 3 img 13 the perimeter of Rectangle B.
Area: Rectangle A ________ Rectangle B
Perimeter: Rectangle A __________ Rectangle B

Answer:
Area: Rectangle A is as same as Rectangle B.
Perimeter: Rectangle A is greater than Rectangle B.

Explanation:
Rectangle A has an area that is Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Testarea of Rectangle B and a perimeter that is Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Testthe perimeter of Rectangle B.

Question 8.
Ryan drew this figure on grid paper. What is the perimeter of the figure?
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 3 img 14
______ units

Answer: 16 units.

Explanation: The perimeter of the figure  is 3+4+1+1+1+1+1+4= 16 units.

Question 9.
What is the area of the figure shown? Each unit square is 1 square foot.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 3 img 15
______ square feet

Answer: 23 square feet.

Explanation: The area of the figure is 23 square feet.

Test – Page 4 – Page No. 114

Question 10.
Ella drew a rectangle that was 3 units wide and 4 units long. Draw a different rectangle that has the same perimeter but a different area.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 4 img 16

Answer: The dimensions are 5 units of length and 2 units of width.

Explanation:

Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test

First, we will find the perimeter of the given rectangle P=2(L+W)
P= 2(3+4)
= 2(7)
= 14.
Now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let’s make out the width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length. So
14= 2L+2×2
14= 2L+4
14 – 4 = 2L
10= 2L
L= 5.
So the dimensions are 5 units of length and 2 units of width.

Question 11.
Kendra glued ribbon around the outside border of the shape shown below. She used 30 centimeters of ribbon for the border. What is the unknown side length?
Show your work.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 4 img 17
b = ______ centimeters

Answer: 5 cm.

Explanation:
The unknown side length is
6+9+4+4+2+b= 30 cm
25+b= 30
b= 30- 25
b= 5 cm.

Question 12.
A carpenter made two tables. The first table is 4 feet wide and 10 feet long. The second table is half as long as the first table. The area of the second table is one fourth the area of the first table.
For numbers 12a–12d, select True or False.
a. The width of the second table is 2 feet.
i. True
ii. False

Answer: True.

Explanation: As the second table is half as long as the first table, so the wide of the second table is 2 feet.

Question 12.
b. The area of the second table is 10 square feet.
i. True
ii. False

Answer: True.

Explanation:
The area of the first table is 4×10= 40 square feet.
As the area of the second table is one fourth the area of the first table, so the area of the second table is 1/4×40= 10 square feet.

Question 12.
c. The length of the second table is 8 feet.
i. True
ii. False

Answer: False.

Explanation: The length of the second table is 5 feet.

Question 12.
d. The area of the first table is 28 square feet.
i. True
ii. False

Answer: false.

Explanation: The area of the first table is 40 square feet.

Test – Page 5 – Page No. 115

Question 13.
Fiona bought some pictures. Each picture had a perimeter of 24 inches. Which could be one of the pictures Fiona bought? Mark all that apply.
Options:
a. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 5 img 18
b. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 5 img 19
c. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 5 img 20
d. Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 5 img 21

Answer: b,c.

Explanation:
The perimeter of figure b is 7+5+7+5= 24 in.
The perimeter of figure c is 2+10+2+10= 24 in.

Question 14.
Tasha wants to fence in two different rectangular pens for her chickens, each with an area of 36 square feet. She will buy fencing to build each pen.
Part A
Each unit square on the grid below is 1 square foot. Draw two possible pens. Label each with a letter.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 5 img 22

Answer: The two rectangles with 36 square feet each are drawn below.

Explanation:
A                                      B
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test

Question 14.
Part B
Which of the pens will take more fencing to make?
Explain how you know.

Answer: Pen A will take more time for fencing.

Explanation: Pen A perimeter is 4+9+4+9= 26 feet and pen B perimeter is 6+6+6+6= 24 feet. So the pen A will take more time for fencing.

Test – Page 6 – Page No. 116

Question 15.
Simon draws a sketch of the floor of his tree house on grid paper. Each unit square is 1 square foot. Write and solve a multiplication equation that can be used to find the area of the floor in square feet.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 6 img 23
_____ square feet

Answer: 42 square feet.

Explanation: The multiplication equation of the area of the floor in square feet is 6×7= 42 square feet.

Question 16.
Rachel uses grid paper to plan a mural to paint at her school. The design will be made of two connected rectangles. The larger rectangle will have an area between 35 square feet and 45 square feet. The smaller rectangle will have an area between 10 square feet and 20 square feet. Draw and label a diagram to show what Rachel could plan. Explain how to find the total area.
Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Test - Page 6 img 24

Answer: 57 feet.

Explanation:

Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test

The area of rectangle A is 6×7= 42 feet and the area of rectangle B is 5×3= 15 feet. So the total area is 42+15= 57 feet.

Conclusion:

This assessment test helps students to check their math skills. Go Math Grade 3 Chapter 10 questions are explained in detail that students can understand easily.

Go Math Grade 3 Answer Key Chapter 11 Perimeter and Area Assessment Test Read More »

Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test

This chapter can improve student’s math skills, by referring to the Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test, and with the help of this Go Math Grade 3 Assessment Test Answer Key, students can score good marks in the examination.

Go Math Grade 3 Answer Key Chapter 10 contains all the topics of chapter 10 which helps to test the student’s knowledge. Through this assessment test, students can check their knowledge. This assessment test is also helpful for the teachers to know how much a student understood the topics.

Chapter 10: Time, Length, Liquid Volume, and Mass Assessment Test

Test – Page 1 – Page No. 101

Question 1.
Chris left to take his dog for a walk at 6:25 P.M. He returned home after 26 minutes. He talked to his neighbor for 10 minutes before going back into his house.
Write the time that Chris got home and the time he went back into the house. Explain how you found each time.

Answer: Chris got back home at 6:51 PM and he went into the house at 7:01 PM.

Explanation:

Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test

Question 2.
Kayla measured an object with an inch ruler. It was about 1 inch wide.
For numbers 2a–2d, choose Yes or No to tell whether the object could be the one Kayla measured.
a. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 1 img 1
i. yes
ii. no

Answer: Yes.

Explanation: It seems like a stamp that can be measured. 

Question 2.
b. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 1 img 2
i. yes
ii. no

Answer: Yes.

Explanation: It is a pin that is less than can be measured. 

Question 2.
c. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 1 img 3
i. yes
ii. no

Answer: No

Explanation: The pencil can be more than an inch.

Question 2.
d. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 1 img 4
i. yes
ii. no

Answer: No

Explanation: The rope can be more than an inch.

Test – Page 2 – Page No. 102

Question 3.
Luz left for the park at 2:27 P.M. She arrived at 3:09 P.M. How long did it take Luz to get to the park?
_____ minutes

Answer: 42 minutes.

Explanation: The time difference between 3:09 P.M and 2:27 P.M is 42 minutes.

Question 4.
Terry wakes up for school at five minutes before seven in the morning. At what time does Terry wake up?
Circle a time that makes the sentence true.
Terry wakes up at Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 2 img 5
__________

Answer: Terry wakes up at 6:55 A.M.

Explanation:

Terry wakes up at  Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test

Question 5.
Select the objects with a mass less than 1 kilogram.
Mark all that apply.
Options:
a. desk
b. eyeglasses
c. eraser
d. plastic fork

Answer: b,c,d

Explanation: Eyeglasses, eraser, plastic fork will be less than 1 kilogram.

Question 6.
A batch of muffins needs to bake in the oven for 22 minutes. They need to cool for at least 15 minutes before they should be eaten. Wade puts the muffins in the oven at 10:17 A.M.
For numbers 6a–6d, select True or False for each statement.
a. Wade can eat the muffins at 10:39 P.M.
i. True
ii. False

Answer: True.

Explanation: If Wade put a muffin in an oven at 10:17 A.M he has to take out then at 10:39 A.M (which is after 22mins), they should be cooled down at least for 15mins once they have taken out. So they can eat after 10:54 A.M.

Question 6.
b. Wade can eat the muffins at 10:44 A.M.
i. True
ii. False

Answer: False.

Explanation: The muffins are not cool, so Wade cannot eat.

Question 6.
c. Wade should take the muffins out of the oven at 10:39 P.M.
i. True
ii. False

Answer: False.

Explanation: No, Wade should take the muffins out of the oven at 10:39 A.M.

Question 6.
d. Wade should take the muffins out of the oven at 10:39 A.M.
i. True
ii. False

Answer: Yes.

Explanation: If Wade put a muffin in the oven at 10:17 A.M he has to take out then at 10:39 A.M which is after 22mins.

Test – Page 3 – Page No. 103

Question 7.
Kirk went to a friend’s house after dinner. He left his house at the time shown on the clock and returned home at 8:05 P.M.
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 3 img 6
Part A
How long was Kirk gone?
______ minutes

Answer: 36 mins.

Explanation: Kirk left home at 7:29 PM and returned after 8:05 PM. Thus he has gone for 36 mins.

Question 7.
Part B
Explain how you found your answer.

Answer: Counted 31 mins from 7:29 to 8:00, 5 mins from 8:00 to 8:05. Then summing up all give 31 mins + 5 mins = 36 mins.

Question 8.
Brad looked at the clock on his way to the football game. What time is shown on Brad’s clock? Mark all that apply.
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 3 img 7
Options:
a. thirteen minutes before ten
b. nine forty-seven
c. quarter to ten
d. nine forty

Answer: Options a and b.

Explanation: The time has shown on Brad’s clock is thirteen minutes before ten and nine forty-seven.

Question 9.
Andrea uses a balance scale to compare mass.
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 3 img 8
Circle a symbol that makes the comparison true.
The mass of the erasers Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 3 img 9 the mass of the paper clips.
_____

Answer: >

Explanation:

The mass of the erasers Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test the mass of the paper clips.

Test – Page 4 – Page No. 104

Question 10.
A bucket of water holds about 19 liters.
For numbers 10a−10e, choose Yes or No to tell whether the container will hold all of the water.
a. bath tub
i. yes
ii. no

Answer: Yes.

Explanation: The bathtub can hold all of the water.

Question 10.
b. large water bottle
i. yes
ii. no

Answer: No.

Explanation: A large water bottle cannot hold all of the water.

Question 10.
c. soup bowl
i. yes
ii. no

Answer: No

Explanation: A soup bowl cannot hold all of the water.

Question 10.
d. large fish tank
i. yes
ii. no

Answer: Yes.

Explanation: A large fish tank can hold all of the water.

Question 10.
e. kitchen sink
i. yes
ii. no

Answer: Yes.

Explanation: A kitchen sink can hold all of the water.

Question 11.
Select the animals that would be best measured in kilograms. Mark all that apply.
Options:
a. dog
b. mouse
c. goat
d. sheep

Answer: a,c,d.

Explanation: Dog, Goat, Sheep are best measured in kilograms.

Question 12.
Luisa is planning her day on Saturday. Write the letter for each activity next to the time she plans to do it.
Options:
A. Wake up. ______ 3:30 P.M.
B. Play soccer game. ______ 8:30 P.M.
C. Eat lunch. ______ 7:30 A.M.
D. Go to a movie. ______ 12:30 P.M.
E. Go to bed. ______ 9:00 A.M.

Answer:

A. Wake up at 7:30 A.M.
B. Play soccer game 9:00 A.M.
C. Eat lunch at 12:30 P.M
D. Go to a movie at 3:30 P.M.
E. Go to bed at 8:30 P.M.

Test – Page 5 – Page No. 105

Question 13.
Stephen has 28 teaspoons of lemon juice. He uses 5 teaspoons of juice for each glass of lemonade he makes. He adds 2 teaspoons of juice to each glass of iced tea he makes.
Stephen makes 4 glasses of lemonade. Does he have enough lemon juice to make 4 glasses of iced tea?
Explain how you solved the problem.
______

Answer: Yes

Explanation:
How much lemon juice he used to make 4 glasses of lemonade = 4 x 5 = 20
Total no of teaspoons of lemon juice he had = 28
No of teaspoons of lemon juice needed to make iced tea = 4 x 2 = 8
Therefore total he needed = 20 + 8 = 28
Thus he has enough lemon juice to make 4 glasses of iced tea.

Question 14.
Use an inch ruler to measure.
Part A
What is the length of the flower to the nearest fourth-inch?
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 5 img 10
_____ \(\frac{â–¡}{â–¡}\)

Answer: 2 ¼ inches.

Explanation: The length of the rose diagram on the ruler is closest to 2.25 – inch mark (6 cm nearly). So taken as 2 ¼ inches which are nearest to the fourth inch.

Question 14.
Part B
Explain how your answer would change if you measured the length of the flower to the nearest inch instead of fourth-inch.

Answer: The length of the rose diagram on the ruler is closest to 2 – inch mark 6 cm nearly.

Question 15.
A football game begins at 11:32 A.M. The game lasts 3 hours 16 minutes. When does the game end?

Answer: The football game end at 2:48 P.M.

Explanation: As the football game begins at 11:32 A.M and the game lasts 3 hours 16 minutes. So the game ends at 2:48 P.M

Question 16.
Alicia buys two packets of flower seeds. She buys a total of 75 grams of seeds. Select the packets she buys.
Options:
a. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 5 img 11
b. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 5 img 12
c. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 5 img 13
d. Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 5 img 14

Answer: options b and d.

Explanation: As she buys a total of 75 grams, so 30g + 45g = 75g.

Test – Page 6 – Page No. 106

Question 17.
Mr. Barton measures the screws on his workbench. He records the measurements in a chart.
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 6 img 15
Part A
Mr. Barton found another screw. Use an inch ruler to measure. Record the measurement in the chart.
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 6 img 16
____ inches

Answer: 3 inches approx. (8 cm).

Explanation:

Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test

Question 17.
Part B
Complete the line plot to show the data in the chart. How many screws are longer than 2 inches? Tell how you know.
Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Test - Page 6 img 17
_____ screws

Answer: 2 screws.

Explanation: Screw with 2 ½ inches and 3, thus two screws longer than 2 inches.

Question 18.
Abby fills a mug with hot cocoa. Is the amount of cocoa more than 1 liter, about 1 liter, or less than 1 liter? Explain how you know.

Explanation: A liter is about the amount in a medium bottle of water. The amount would not fit a mug, so the full mug has less than 1 liter.

Conclusion:

This assessment test helps students to check their math skills. Go Math Grade 3 Chapter 10 questions are explained in detail that students can understand easily.

Go Math Grade 3 Answer Key Chapter 10 Time, Length, Liquid Volume, and Mass Assessment Test Read More »

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test

This chapter can improve student’s math skills, by referring to the Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test, and with the help of this Go Math Grade 3 Assessment Test Answer Key, students can score good marks in the examination.

Go Math Grade 3 Answer Key Chapter 9 contains all the topics of chapter 9 which helps to test the student’s knowledge. Through this assessment test, students can check their knowledge. This assessment test is also helpful for the teachers to know how much a student understood the topics.

Chapter 9: Compare Fractions Assessment Test

Test – Page 1 – Page No. 91

Question 1.
Frank and Dwayne weed their gardens that are the same size. Frank’s garden is divided into 6 equal sections. Dwayne’s garden is divided into 4 equal sections. Each boy has weeded 2 sections of his garden.
Write a fraction to describe what part of his garden each boy has weeded. Then tell who weeded a larger area. Explain
_________

Answer: Dwayne’s part 2/4 > Frank’s part 2/6.

Explanation:
Frank and Dwayne has the same size of gardens
Frank’s garden is divided into 6 equal sections
Dwayne’s garden is divided into 4 equal sections
Since each has weeded 2 sections of their gardens, Frank’s part would be = 2/6,
Dwayne’s part would be = 2/4.
Therefore Dwayne’s part 2/4 > Frank’s part 2/6,
Since the garden with a greater number of sections will have a smaller area per section.

Question 2.
Eli, Beth, and Cory are reading the same book for class. Eli read \(\frac{3}{4}\) of his book. Beth read \(\frac{3}{8}\) of her book and Cory read \(\frac{3}{6}\) of his book. For 2a–2d, choose Yes or No to indicate whether the comparisons are correct.
a. \(\frac{3}{4}\) > \(\frac{3}{8}\)
i. yes
ii. no

Answer: Yes.

Explanation: 3/4 > 3/8. Since both are reading the same book and book with a greater number of sections will have a lesser value.

Question 2.
b. \(\frac{3}{6}\) < \(\frac{3}{8}\)
i. yes
ii. no

Answer: No, 3/6 < 3/8.

Explanation: It’s not true, Since both are reading the same book, and books with a greater number of sections will have a lesser value. Therefore 3/6 > 3/8).

Question 2.
c. \(\frac{3}{8}\) = \(\frac{3}{6}\)
i. yes
ii. no

Answer: No

Explanation: 3/8 = 3/6. Both are not equal, since the same book has been divided into different no of parts. Therefore both are not equal.

Question 2.
d. \(\frac{3}{6}\) < \(\frac{3}{4}\)
i. yes
ii. no

Answer: Yes.

Explanation: 3/6 < 3/4. Since both are reading the same book and book with a greater number of sections will have a lesser value.

Question 3.
Mark and Lisa are on the swim team. Mark swims \(\frac{3}{8}\) mile each day. Lisa swims \(\frac{5}{8}\) mile each day. Which statement is correct? Mark all that apply.
Options:
a. Mark swims farther than Lisa each day.
b. Lisa swims the same distance as Mark each day.
c. Lisa swims less than 1 mile each day.
d. Lisa swims farther than Mark each day.

Answer: Both c and d are correct.

Explanation: Lisa swims less than 1 mile while 5/8 mile each day and She swims farther than Mark each day. i.e. 5/8 > 3/8.

Test – Page 2 – Page No. 92

Question 4.
MacKenzie and Cassie used fabric to make costumes for a play. MacKenzie used \(\frac{3}{4}\) yard of fabric and Cassie used \(\frac{5}{6}\) yard. Who used more fabric? Explain the strategy you used to solve the problem.
_________

Answer:
MacKenzie divided fabric into 4 equal parts and used 3/4 of it. So, 1/4 of it is left. Cassie divided the same yard of fabric into 6 equal parts and used 5/6 of it. Here 1/6 part of it is left, by comparing leftover pieces we can conclude 1/4 > 1/6. Since the larger piece was left with MacKenzie, Cassie has used more fabric.

Question 5.
The soccer team practices passing for \(\frac{3}{4}\) hour and shooting for \(\frac{4}{5}\) hour. On which drill does the team spend less time? Explain how you can use the model to find the answer.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 2 img 1

Answer: From the model, we can understand that team has spent less time on Passing. Since the model for 3/4 is shorter than the model for 4/5.

Question 6.
Andrew bought \(\frac{7}{8}\) pound of mixed nuts. Margaret bought \(\frac{5}{8}\) pound of mixed nuts. Use the fractions and symbols to show which amount is greater.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 2 img 2

Answer: 5/8 < 7/8 or 7/8 > 5/8

Explanation:

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test

Test – Page 3 – Page No. 93

Question 7.
Mr. Worth opened new jars of 4 different colors of paint for an art project. All of the jars were the same size.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 3 img 3
Part A Draw lines to show how Mr. Worth could divide one jar of paint into halves, one into thirds, one into fourths, and one into sixths.
Part B Students in his class used an equivalent amount of two paint colors. Use the models to show the amount of paints used. Write two pairs of equivalent fractions to represent the models.

Answer: The below figure represents halves, one-third, one into fourth, one into sixths.

Explanation:

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test
Representing Halves           one-third                      one into fourth           one into sixths
Therefore from the above figure, two pairs of equivalent fractions representing the models are 1/2 = 2/4, 1/3 = 2/6.

Question 8.
Dalton rode his skateboard for \(\frac{3}{4}\) mile. Amelia rode her skateboard for an equal distance. What is an equivalent fraction that describes how far Amelia rode? Use the models to show your work.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 3 img 4
\(\frac{3}{4}\) = \(\frac{â–¡}{â–¡}\)

Answer: \(\frac{3}{4}\) = \(\frac{6}{8}\).

Explanation: Below two pictures give Dalton and Amelia distance covered while riding a skateboard. Though they both rode the same distance to represent them in similar different fractions. We can divide Dalton’s covered as in the 1st circle and Amelia’s in 2nd Circle. From the pictures, equivalent fractions will be 3/4 for Dalton and 6/8 for Amelia.

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test

Question 9.
Mr. Barrows opens 2 packs of paper. He puts \(\frac{2}{5}\) of a pack in one pile and \(\frac{3}{5}\) of a pack in another pile. Which pile has more paper? Show your work.
\(\frac{â–¡}{â–¡}\) of a pack

Answer: 3/5 of a pack has more papers.

Explanation: The pile with 3/5 of a pack has more papers. Since 2/5 is there in another pack.

Test – Page 4 – Page No. 94

Question 10.
Treyvon watched \(\frac{2}{8}\) a movie. Juan watched \(\frac{2}{6}\) of the same movie. Use >, =, or < to compare the parts that they watched.
\(\frac{2}{8}\) _____ \(\frac{2}{6}\)

Answer: \(\frac{2}{8}\) < \(\frac{2}{6}\) or \(\frac{2}{6}\) > \(\frac{2}{8}\).

Question 11.
Alison used \(\frac{7}{8}\) quart of orange juice and \(\frac{3}{8}\) quart of cranberry juice to make some punch.
For 11a–11d, select True or False for each comparison.
a. \(\frac{7}{8}\) < \(\frac{3}{8}\)
i. True
ii. False

Answer: False.

Explanation: 7/8 is greater than 3/8.

Question 11.
b. \(\frac{7}{8}\) > \(\frac{3}{8}\)
i. True
ii. False

Answer: True.

Explanation: Since both have the same denominators, we can compare their numerators directly. Here 7 is greater than 3, therefore 7/8 is greater than 3/8.

Question 11.
c. \(\frac{3}{8}\) < \(\frac{7}{8}\)
i. True
ii. False

Answer: True.

Explanation: \(\frac{3}{8}\) < \(\frac{7}{8}\)

Question 11.
d. \(\frac{3}{8}\) = \(\frac{7}{8}\)
i. True
ii. False

Answer: False.

Explanation: Both are not equal.

Question 12.
Will, Ann, and Jim are working on their science fair projects. Will has finished \(\frac{1}{4}\) of his project. Ann has finished \(\frac{3}{4}\) of her project, and Jim has finished \(\frac{2}{3}\) of his project.
Part A
Who has finished less of their project, Will or Ann?
Explain how you know.
__________

Answer: Will has finished less compared to Ann.

Explanation: Given that will has finished 1/4 of his project wherein Ann has finished 3/4 of her project. Since 1/4 and 3/4 have the same denominator, so we can compare the numerator directly. Since 1 is less than 3, we can say 1/4 is less than 3/4. Thus Will has finished less part of his project compared to Ann.

Question 12.
Part B
Who has finished less of their project, Ann or Jim?
Explain how you know.
__________

Answer: 2/3 is less than 3/4. Therefore, Jim has finished less part of his project compared to Ann.

Explanation: Given that Jim has finished 2/3 of his project were in Ann has finished 3/4 of her project. Since denominators are not the same to compare first we shall make the same. Therefore multiply Jim’s work (2/3) with (4/4) which gives = 8/12 and Ann’s work (3/4) with (3/3) which gives = 9/12. Now by comparing numerators 8/12 is less than 9/12, which means Jim has finished less part of his project compared to Ann.

Test – Page 5 – Page No. 95

Question 13.
Sarah needs \(\frac{4}{6}\) yard of ribbon to wrap a gift. She has 6 pieces of ribbon with the following lengths. She can cut the piece if it is too long. Mark all of the pieces of ribbon that Sarah could use.
Options:
a. \(\frac{1}{2}\) yard
b. \(\frac{6}{6}\) yard
c. \(\frac{3}{8}\) yard
d. \(\frac{4}{4}\) yard
e. \(\frac{1}{3}\) yard
f. \(\frac{5}{6}\) yard

Answer: Sarah could use 6/6 yard, 4/4 yard and 5/6 yard of ribbons to wrap gift.

Explanation:
Given that Sarah needs a 4/6 yard of ribbon to wrap a gift.
Lengths of available ribbons are 1/2, 6/6, 3/8, 4/4,1/3, and 5/6.
Comparing all the lengths with 4/6 – 6/6 and 5/6 are having the same denominators. So we compare only their numerators, both 6 and 5 are greater than 4. So these two ribbons are more than enough for her gift wrapping. With ribbon length, 4/4 yard – since complete ribbons all the parts of the ribbon are available thus this length also enough to wrap the gift. Remaining 1/2, 3/8, and 1/3 – we shall make their denominators equal to 4/6 to compare
multiply (1/2) with (3/3) = 3/6, 3 is less than 4 in 4/6. So this is not having enough length
multiply (1/3) with (2/2) = 2/6, 2 is also less than 4. So this also not having enough length.
multiply (3/8) with (6/6) = 18/48 and (4/6) with (8/8) = 32/48. Since 18 is less than 32, this ribbon length also won’t be enough to wrap gifts. Thus Sarah could use only 6/6 yard, 4/4 yard, and 5/6 yard of ribbons to wrap the gift.

Question 14.
There are 8 people having breakfast. Each person wants \(\frac{1}{2}\) of an omelet. How many whole omelets are needed? Use the models to show your answer.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 5 img 5
_____ omelets

Answer: Total they need 4 omelets.

Explanation:
Total no of having omelets are = 8
Each person need 1/2 of omelette, so for 8 persons = (1/2) * 8 = 4.

Question 15.
Michele mixed \(\frac{3}{4}\) cup of flour with \(\frac{1}{2}\) cup of water to make paste for an art project. Compare the fractions. Choose the symbol that makes the statement true.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 5 img 6
\(\frac{3}{4}\) _____ \(\frac{1}{2}\)

Answer: \(\frac{3}{4}\) > \(\frac{1}{2}\).

Explanation:

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test
Let’s make 3/4 and 1/2 denominators the same (1/2) * (2/2) = 2/4.
Since 3 is greater than 2, 3/4 > 1/2.

Question 16.
Jeff has three boxes that weigh \(\frac{5}{8}\), \(\frac{1}{8}\), and \(\frac{3}{8}\) pound. Write the weights in order from least to greatest.

Answer: \(\frac{1}{8}\), \(\frac{3}{8}\), \(\frac{5}{8}\).

Explanation: Weights in the least to greatest form 1/8, 3/8, 5/8.

Test – Page 6 – Page No. 96

Question 17.
Ben measures the lengths of three insects. Draw a line to match each length on the left to the word on the right that describes its place in the order of lengths.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 6 img 7

Answer:

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test

Question 18.
Kerri drew a model to show equivalent fractions.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 6 img 8
Use the model to complete the number sentence.
\(\frac{2}{3}\) = \(\frac{â–¡}{â–¡}\)

Answer: \(\frac{2}{3}\) = \(\frac{4}{6}\).

Explanation: Here from the model four parts are shaded out of 6, which also equal to \(\frac{2}{3}\) by value.

Question 19.
Elaine brought \(\frac{3}{4}\) pound of potato salad to a picnic. Jake brought \(\frac{2}{3}\) pound of macaroni salad. Who brought more salad? Explain the strategy you used to solve the problem.

Answer: Elaine has brought more Salad compared to Jake.

Explanation:
Elaine has brought \(\frac{3}{4}\) pound of potato salad
Jake brought \(\frac{2}{3}\) pound of macaroni salad
Lets compare both parts by making their denominators same.Therefore multiply (3/4) * (3/3) = (9/12) and (2/3) * (4/4) = (8/12)
Since 8 is less than 9,\(\frac{8}{12}\)  < \(\frac{9}{12}\).
Which means \(\frac{2}{3}\) < \(\frac{3}{4}\). Thus Elaine has brought more Salad compared to Jake.

Question 20.
It took Mike \(\frac{2}{6}\) hour to clean his room.
Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Test - Page 6 img 9
What fraction is equivalent to \(\frac{2}{6}\) ?
\(\frac{2}{6}\) = \(\frac{â–¡}{â–¡}\)

Answer: \(\frac{2}{6}\) = \(\frac{1}{3}\).

Conclusion:

This assessment test helps students to check their math skills. Go Math Grade 3 Chapter 10 questions are explained in detail that students can understand easily.

Go Math Grade 3 Answer Key Chapter 9 Compare Fractions Assessment Test Read More »

Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test

This chapter can improve student’s math skills, by referring to the Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test, and with the help of this Go Math Grade 3 Assessment Test Answer Key, students can score good marks in the examination.

Go Math Grade 3 Answer Key Chapter 7 contains all the topics of chapter 7 which helps to test the student’s knowledge. Through this assessment test, students can check their knowledge. This assessment test is also helpful for the teachers to know how much a student understood the topics.

Chapter 7: Division Facts and Strategies Assessment Test

Test – Page 1 – Page No. 71

Question 1.
Shang shared 28 postcards among 7 different people. Each person received the same number of postcards. How many postcards did Shang give to each person?
28 ÷ 7 = n
7 × n = 28
Options:
a. 4
b. 5
c. 6
d. 21

Answer: a

Explanation:
As Shang shared 28 postcards to 7 different people so 28 ÷ 7 = 4 , 7 × 4 = 28. Shang gave 4 postcards to each person.

Question 2.
Lionel has 14 mittens.
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 1 img 1
Select one number from each column to show the division equation represented by the picture.
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 1 img 2
14 ÷ ______ = ______

Answer: 14 ÷ 2 = 7.

Explanation: 14 ÷ 2 = 7 which is 7 pairs of mitten given the model.

Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test

Test – Page 2 – Page No. 72

Question 3.
Fifteen people are going rafting. They brought 5 rafts. An equal number of people ride in each raft. How many people will be in each raft?
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 2 img 3
______ people

Answer: 3 people.

Explanation:
No of people going for rafting = 15
Total no of rafts available = 5
No of people will be in each raft = 15 ÷ 5 = 3 people.

Question 4.
Circle a number for the unknown factor and quotient that makes the equation true.
4 × Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 2 img 4 = 24
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 2 img 5 = 24 ÷ 4
4 × ______ = 24 ;               ______ = 24 ÷ 4

Answer:
4×6= 24
6= 24 ÷ 4

Explanation:

4×= 24

Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test= 24 ÷ 4

Question 5.
There are 20 students in science class. There are 10 students sitting at each table. How many tables are there?
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 2 img 6
Write a division equation to represent the repeated subtraction.
______ ÷ ______ = ______

Answer: 20 ÷ 10 = 2.

Explanation:
Total no of students in class = 20
No of students sitting at each table = 10
Therefore no of tables = 20 ÷ 10 = 2

Question 6.
Complete the chart to show the quotients.
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 2 img 7

Answer:
63÷9= 7.
72÷9= 8.
81÷9= 9.
90÷9= 10.

Explanation:

Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test

Test – Page 3 – Page No. 73

Question 7.
For numbers 7a–7e, select True or False for each equation.
a. 0 ÷ 6 = 6
i. True
ii. False

Answer: False

Explanation: 0 ÷ 6 = 0, so the answer is false. 

Question 7.
b. 6 ÷ 6 = 1
i. True
ii. False

Answer: True

Explanation: As 6 ÷ 6 = 1, so the answer is true.

Question 7.
c. 18 ÷ 6 = 2
i. True
ii. False

Answer: False.

Explanation: As 18 ÷ 6 = 3, so the answer is false.

Question 7.
d. 54 ÷ 6 = 9
i. True
ii. False

Answer: True.

Explanation: As 54 ÷ 6 = 9, so the answer is true.

Question 7.
e. 60 ÷ 10 = 6
i. True
ii. False

Answer: True.

Explanation: As 60 ÷ 10 = 6, so the answer is true.

Question 8.
Kaitlyn says that 8 ÷ 2 × 4 is the same as 4 × 2 ÷ 8.
Is Kaitlyn correct or incorrect? Explain.

Answer: No. 8 ÷ 2 × 4 and 4 × 2 ÷ 8 are not the same.

Expplanation:Lets calculate 8 ÷ 2 × 4 = 4 × 4 = 16 by using BODMAS, first we did division later multiplication
4 × 2 ÷ 8 = 4 × ¼ = 1. Thus both results are not same.

Question 9.
Brian is dividing 64 baseball cards equally among 8 friends. How many baseball cards will each friend get?
_______ baseball cards

Answer: 8 baseball cards.

Explanation:
Total cards available = 64
No of friends = 8
No of baseball cards each gets = 64 ÷ 8 = 8

Question 10.
Tara made $18 selling cookies. She wants to know how many cookies she sold. Tara used this number line.
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 3 img 8
Write the division equation that the number line represents.
______ ÷ ______ = ______

Answer: 18 ÷ 3 = 6.

Explanation:
Possible answers could be if she sells each cookie at $ 3 then 18 ÷ 3 = 6 were sold

Test – Page 4 – Page No. 74

Question 11.
Each team at a science competition has 6 players. How many teams are there if 42 players are at the competition? Explain the strategy you used to solve the problem.
_____ teams

Answer: 7 teams.

Explanation:
Given that there is a total of 42 players
Each team has 6 players, therefore the total number of teams = 42 ÷ 6 = 7 teams.

Question 12.
Carly bought 3 packs of baseball cards. Each pack had the same number of cards. She gave 5 cards to her sister. Now she has 19 cards. How many baseball cards were in each pack? Explain how you solved the problem.
_____ baseball cards

Answer: 24 ÷ 3 = 8 baseball cards.

Explanation:
Total packs bought were = 3
No of cards she has = 19
No of cards given to her sister = 5
Total number cards = 19+5 = 24
No of cards in each pack = 24 ÷ 3 = 8 cards.

Question 13.
Andrea used 35 craft sticks to make 7 door hangers. She used the same number of craft sticks for each door hanger. How many craft sticks did Andrea use for each door hanger?
_____ craft stick

Answer: 5 craft sticks.

Explanation:
Total no of craft sticks used by Andrea = 35
No of door hangers made = 7
Therefore no of craft sticks used for each door hanger = (Total no of craft sticks ÷  no of door hangers)
= 35 ÷ 7
= 5 craft sticks.

Question 14.
For numbers 14a–14e, use the order of operations. Select True or False for each equation.
a. 45 ÷ 5 − 3 = 6
i. True
ii. False

Answer: True.

Explanation:
By BODMAS rule
45 ÷ 5 − 3
= 9 – 3
= 6

Question 14.
b. 12 + 4 ÷ 4 = 13
i. True
ii. False

Answer: True.

Explanation:
By BODMAS rule
12 + 4 ÷ 4
= 12 + 1
= 13

Question 14.
c. 3 + 7 × 8 = 80
i. True
ii. False

Answer: false.

Explanation:
By BODMAS rule
3 + 7 × 8
= 3 + 56
= 59

Question 14.
d. 32 ÷ 8 × 2 = 2
i. True
ii. False

Answer: false.

Explanation:
By BODMAS rule
32 ÷ 8 × 2
= 4 × 2
= 8.

Question 14.
e. 40 − 10 × 3 = 10
i. True
ii. False

Answer: True.

Explanation:
By BODMAS rule
40 − 10 × 3
= 40 – 30
= 10.

Test – Page 5 – Page No. 75

Question 15.
Patrick sells homemade pretzels in bags with 9 pretzels in each bag. He sells 54 pretzels in all. How many bags of pretzels does he sell?
______ bags

Answer: 6 bags.

Explanation:
No of bags sold = (Total no of pretzels / no of pretzels in each bag)
= 54/9
= 6 bags.

Question 16.
Enrique started a table showing a division pattern.
Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Test - Page 5 img 9
Part A
Complete the table.
Compare the quotients when dividing by 10 and when dividing by 5. Describe a pattern you see in the quotients.

Answer:
10÷10= 1
10÷5= 2
20÷10= 2
20÷5= 4
30÷10= 3
30÷5= 6
40÷10= 4
40÷5= 8.

Explanation:

Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test

Question 16.
Part B
Find the quotient, a.
80 ÷ 10 = a
a = ______

Answer: 8.

Explanation:
80 ÷ 10 = 8.
The quotient is 8.

How could you use a to find the value of n?
Find the value of n.
80 ÷ 5 = n
n = ______
a = ______
n = ______

Answer:
a= 8.
n= 16.

Explanation: By doubling the value of ‘a’ we can get the value of ‘n’. As the value of ‘a’ is 8, so the value of ‘n’= 8+8= 16

Question 17.
Eve needs 2 limes to make a glass of limeade. If limes come in bags of 12, how many glasses of limeade can she make using one bag?
______ glasses

Answer: 6 glasses.

Explanation: The limes in the bags are 12 and Eve needs 2 glasses of limeade, so the number of glasses she can make is 12÷2= 6 glasses.

Test – Page 6 – Page No. 76

Question 18.
For numbers 18a–18e, select True or False for each equation.
a. 18 ÷ 9 = 2
i. True
ii. False

Answer: True

Explanation: As 18 ÷ 9 = 2, so the answer is true.

Question 18.
b. 27 ÷ 9 = 4
i. True
ii. False

Answer: False.

Explanation: As 27 ÷ 9 = 3, so the answer is false.

Question 18.
c. 45 ÷ 9 = 5
i. True
ii. False

Answer: True.

Explanation: As 45 ÷ 9 = 5, so the answer is true.

Question 18.
d. 72 ÷ 9 = 7
i. True
ii. False

Answer: False

Explanation: As 72 ÷ 9 = 8, so the answer is false.

Question 18.
e. 81 ÷ 9 = 8
i. True
ii. False

Answer: False.

Explanation: As 81 ÷ 9 = 9, so the answer is true.

Question 19.
Holly is making 4 vegetable trays for a party. She wants to divide 36 carrot sticks equally among the trays. How many carrot sticks will she put on each tray?
______ carrot sticks

Answer: 9 carrot sticks.

Explanation: No of carrot sticks on each tray = (Total carrot sticks ÷ no of vegetable trays)
= 36 ÷ 4
= 9 carrot sticks in each tray

Question 20.
Hector is buying books at a book store.
Part A
He buys 2 used books and 1 new book for $26. The new book costs $18. Each used book costs the same amount. What is the price of each used book? Explain the steps you used to solve the problem.
$ ______

Answer: Each used book costs $ 4.

Explanation:
Given that cost of one new book = $ 18
Cost of 2 used books + 1 new book = $ 26
Cost of 2 used books = 26 – 18 = 8
Cost of 1 used book = 8/2 = $4

Question 20.
Part B
Hector also buys a reading light for $12 and 2 journals for $8 each to give as gifts. Write one equation to describe the total amount Hector spends on gifts. Explain how to use the order of operations to solve the equation.
Total amount: $ ______

Answer: $ 28.

Explanation:
Hector bought a reading light for $12
2 journals for $8 each
Total money spent on gifts = 12 + (2 x 8)
= 12 + 16
= $ 28.

Conclusion:

This assessment test helps students to check their math skills. Go Math Grade 3 Chapter 10 questions are explained in detail that students can understand easily.

Go Math Grade 3 Answer Key Chapter 7 Division Facts and Strategies Assessment Test Read More »

Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test

This chapter can improve student’s math skills, by referring to the Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test, and with the help of this Go Math Grade 3 Assessment Test Answer Key, students can score good marks in the examination.

Go Math Grade 3 Answer Key Chapter 6 contains all the topics of chapter 6 which helps to test the student’s knowledge. Through this assessment test, students can check their knowledge. This assessment test is also helpful for the teachers to know how much a student understood the topics.

Chapter 6: Understand Division Assessment Test

Test – Page 1 – Page No. 61

Question 1.
For numbers 1a–1d, select True or False for each equation.
a. 5 ÷ 1 = 5
i. True
ii. False

Answer: True.

Explanation: 5 ÷ 1 = 5, so answer is true.

Question 1.
b. 3 ÷ 3 = 1
i. True
ii. False

Answer: True.

Explanation: 3 ÷ 3 = 1, so the answer is true.

Question 1.
c. 4 ÷ 1 = 1
i. True
ii. False

Answer: False.

Explanation: 4 ÷ 1 = 4, not 1. So the answer is False.

Question 1.
d. 0 ÷ 1 = 0
i. True
ii. False

Answer: True.

Explanation: 0 ÷ 1 = 0, so the answer is true.

Question 2.
Elian is making 36 ounces of punch. He pours the same amount into each of 6 cups. How many ounces of punch does he pour into each cup?
Circle the amount to complete the sentence.
Elian pours Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 1 img 1 ounces of punch into each cup.
_____

Answer: 6 each cup.

Explanation:

Elian pours Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test ounces of punch into each cup.

Question 3.
Gina arranges her 21 puzzles in 7 equal stacks. How many puzzles does Gina put in each stack?
Shade squares to make an array to model the problem.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 1 img 2

Answer: 3 puzzles.

Explanation:

Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test

Test – Page 2 – Page No. 62

Question 4.
Philip has 30 pennies that he exchanges for nickels. He exchanges 5 pennies for each nickel. How many nickels does Philip get?
Make equal groups to model the problem.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 2 img 3
_____ nickels

Answer: 6 nickels.

Explanation: As Philips has 30 pennies and he exchanges 5 pennies for each nickel, so Philips get 30÷5= 6 nickels.

Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test

Question 5.
A book has 54 pages divided into 6 equal chapters.
How many pages are in each chapter?
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 2 img 4
_____ pages

Answer: 9 pages.

Explanation: 54÷6= 9 pages.

Question 6.
Select the equations that the array represents.
Mark all that apply.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 2 img 5
Options:
a. 2 × 4 = 8
b. 3 × 2 = 6
c. 6 ÷ 3 = 2
d. 2 × 3 = 6
e. 6 ÷ 2 = 3
f. 8 ÷ 2 = 4

Answer: b,c,d,e.

Explanation:
3 × 2 = 6
6 ÷ 3 = 2
2 × 3 = 6
6 ÷ 2 = 3

Test – Page 3 – Page No. 63

Question 7.
The 16 players at tennis camp are divided into 4 equal groups. How many players are in each group?
Part A
Draw jumps on the number line to model the problem.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 3 img 6
Type below:
___________

Answer:

Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test

Question 7.
Part B
Write a division equation to represent the model.
_____ ÷ _____ = _____

Answer: 4

Explanation: 16÷4= 4

Question 8.
Max writes a total of 45 lines in his journal. Each journal entry is 9 lines long. How many journal entries does Max make?
Choose a number from the box to complete the sentence.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 3 img 7
Max makes _____ journal entries.
_____

Answer: 5

Explanation: Max writes a total of 45 lines in his journal and each journal entry is 9 lines long, so 45÷9= 5 journal entries does Max makes.

Question 9.
A farmer sells baskets that hold 6 peaches each. Etta buys a total of 18 peaches. How many baskets of peaches does Etta buy?
Complete each equation to represent the problem.
6 × _____ = 18;    18 ÷ 6 = _____ ;     _____ baskets

Answer: 3 baskets.

Explanation: As the farmer sells baskets that hold 6 peaches each and Etta buys a total of 18 peaches, the number of baskets of peaches does Etty bought is 18÷6= 3 baskets.
6 × 3 = 18;
18 ÷ 6 = 3

Question 10.
Penn has 12 eggs to use in some recipes. Select a way that he could divide all of the eggs equally among the recipes. Mark all that apply.
Options:
a. 6 eggs in each of 2 recipes
b. 5 eggs in each of 3 recipes
c. 3 eggs in each of 4 recipes
d. 4 eggs in each of 4 recipes
e. 2 eggs in each of 6 recipes
f. 4 eggs in each of 3 recipes

Answer: a,c,e,f.

Explanation:
6×2= 12
3×4= 12
2×6= 12
4×3= 12

Test – Page 4 – Page No. 64

Question 11.
Nancy made this array to model a division equation. Which equation could Nancy have modeled? Mark all that apply.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 4 img 8
Options:
a. 63 ÷ 7 = 9
b. 54 ÷ 6 = 9
c. 72 ÷ 9 = 8
d. 63 ÷ 9 = 7

Answer: a,d.

Explanation:
63 ÷ 7 = 9
63 ÷ 9 = 7

Question 12.
Rico went for a bike ride around a 3-mile loop. He rode a total of 12 miles. How many times did Rico ride his bike around the loop?
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 4 img 9
_____ times

Answer: 4 times.

Explanation: As Rico went for a bike ride around a 3-mile loop and rode a total of 12 miles, so 12÷3= 4 times Rico ride his bike around the loop.

Question 13.
Write the letter for each problem in the box next to its quotient.
Options:
A. 5 ÷ 5 _____ 0
B. 0 ÷ 5 _____ 5
C. 5 ÷ 1 _____ 1

Answer:
5 ÷ 5= 1
0 ÷ 5= 0
5 ÷ 1= 5.

Question 14.
Karson earns $6 each hour babysitting. Last week she earned a total of $48 babysitting. How many hours did Karson babysit last week?
Choose a number from the box.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 4 img 10
______ hours

Answer: 8 hours.

Explanation: As Karson earns $6 each hour babysitting and in last week she earned a total of $48 babysitting, so $48÷$6= 8 hours did Karson earn in babysit last week.

Test – Page 5 – Page No. 65

Question 15.
Write the division equation to represent the repeated subtraction.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 5 img 11
_____ ÷ _____ = _____

Answer: 3.

Explanation:
15÷5= 3

Question 16.
Write the related facts for the array.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 5 img 12

Answer:
5×5= 25
25÷5= 5

Explain why there are not more related facts for the array.

Answer: There are only two equations, as both factors are the same.

Question 17.
Sierra separates 14 animal cards into equal piles with none left over.
Draw a picture to show how Sierra divides the cards and complete the sentence.
Sierra made ______ piles of cards.

Answer: 2 piles of cards.

Explanation: Here we must know how 14 can be divided. So 14 can be divided into two ways, 7×2= 14 and 2×7= 14. So Sierra made 2 piles of cards.

Could Sierra have separated the cards into 4 equal piles with none left over? Explain why or why not.

Answer: No.

Explanation: Sierra cannot separate into 4 equal piles, as 14 cannot be divided into 4 groups of equal size.

Test – Page 6 – Page No. 66

Question 18.
Circle numbers to complete the related facts.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 6 img 13 × 6 = 42 42 ÷ Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 6 img 14 = 6
_____ _____

Answer: 7,6.

Explanation:
7×6= 42
42÷7= 6

Question 19.
Use numbers from the box to write related multiplication and division facts.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 6 img 15
_____ × _____ = _____
_____ × _____ = _____
_____ ÷ _____ = _____
_____ ÷ _____ = _____

Answer:
8×4= 32
4×8= 32
32÷4= 8
32÷8= 4

Question 20.
Angela plants 24 rosebushes in flowerbeds in her yard. She plants the same number of rosebushes in each of 6 flowerbeds.
How many rosebushes does Angela plant in each flowerbed? Show your work.
Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Test - Page 6 img 16
______ rosebushes

Answer: 4 rosebushes.

Explanation: As Angela plants 24 rosebushes in flowerbeds in her yard and she plants the same number of rosebushes in each of 6 flowerbeds, so 24÷6= 4 rosebushes.

Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test

Conclusion:

This assessment test helps students to check their math skills. Go Math Grade 3 Chapter 10 questions are explained in detail that students can understand easily.

Go Math Grade 3 Answer Key Chapter 6 Understand Division Assessment Test Read More »

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