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## Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships

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**Lesson 1: Representing Linear Nonproportional Relationships**

- Representing Linear Nonproportional Relationships – Page No. 98
- Representing Linear Nonproportional Relationships â€“ Page No. 99
- Representing Linear Nonproportional Relationships â€“ Page No. 100

**Lesson 2: Determining Slope and y-intercept**

- Determining Slope and y-intercept â€“ Page No. 104
- Determining Slope and y-intercept â€“ Page No. 105
- Determining Slope and y-intercept â€“ Page No. 106

**Lesson 3: Graphing Linear Nonproportional Relationships Using Slope and y-intercept**

- Graphing Linear Nonproportional Relationships Using Slope and y-intercept â€“ Page No. 110
- Graphing Linear Nonproportional Relationships Using Slope and y-intercept â€“ Page No. 111
- Graphing Linear Nonproportional Relationships Using Slope and y-intercept â€“ Page No. 112

**Lesson 4: Proportional and Nonproportional SituationsÂ **

- Proportional and Nonproportional Situations â€“ Page No. 117
- Proportional and Nonproportional Situations â€“ Page No. 118
- Proportional and Nonproportional Situations â€“ Page No. 119
- Proportional and Nonproportional Situations â€“ Page No. 120

**Lesson 5: Representing Linear Nonproportional Relationships â€“ Model Quiz**

**Mixed ReviewÂ **

### Guided Practice – Representing Linear Nonproportional Relationships – Page No. 98

**Make a table of values for each equation.**

Question 1.

y = 2x + 5

Type below:

____________

Answer:

Explanation:

y = 2x + 5

Choose several values for x and substitute in the equation to find y.

x = 2(-2) + 5 = 1

x = 2(-1) + 5 = 3

x = 2(0) + 5 = 5

x = 2(1) + 5 = 7

x = 2(2) + 5 = 9

**Graphing Linear Nonproportional Relationships Worksheet Answers Question 2.**

y = \(\frac{3}{8}\)x âˆ’ 5

Type below:

____________

Answer:

Explanation:

y = \(\frac{3}{8}\)x âˆ’ 5

Choose several values for x and substitute in the equation to find y.

x = 3/8(-8) – 5 = -8

x = 3/8(0) – 5 = -5

x = 3/8(8) – 5 = -2

x = 3/8(16) – 5 = 1

x = 3/8(24) – 5 = 4

**Explain why each relationship is not proportional.**

Question 3.

First calculate \(\frac{y}{x}\) for the values in the table.

____________

Answer:

The relationship is not proportional

Explanation:

Find y/x

3/0 = undefined

7/2 = 3.5

11/4 = 2.75

15/6 = 2.5

19/8 = 2.375

The ratio is not constant, hence relationship is not proportional.

Question 4.

__________________

Answer:

The graph is a straight line but does not pass through the origin. So, the relationship is not proportional.

**Complete the table for the equation. Then use the table to graph the equation.**

Question 5.

y = x âˆ’ 1

Type below:

____________

Answer:

Explanation:

y = x – 1

Choose several values of x and substitute in the equation to find y to draw a table.

x = -2; y = -2 – 1 = -2

x = -1; y = -1 -1 = -2

x = 0; y = 0 -1 = -1

x = 1; y = 1 – 1 = 0

x = 2; y = 2 -1 = 1

Also, Plot the ordered pairs from the table. Then draw a line connecting the points to represent all the possible solutions

**Essential Question Check-In**

Question 6.

How can you choose values for x when making a table of values representing a real-world situation?

Type below:

____________

Answer:

When choosing values for x in a real-world situation, you choose positive values with an appropriate interval to represent the array of data.

### Independent Practice – Representing Linear Nonproportional Relationships – Page No. 99

**State whether the graph of each linear relationship is a solid line or a set of unconnected points. Explain your reasoning.**

Question 7.

The relationship between the number of $4 lunches you buy with a $100 school lunch card and the money remaining on the card

____________

Answer:

Set of unconnected points.

Explanation:

You cannot buy a fractional part of a lunch.

Set of unconnected points.

Question 8.

The relationship between time and the distance remaining on a 3-mile walk for someone walking at a steady rate of 2 miles per hour.

____________

Answer:

A solid line

Explanation:

The relationship between time and the distance remaining on a 3-mile walk for someone walking at a steady rate of 2 miles per hour. The distance remaining can be a fraction. The time can be in a fraction as well.

A solid line

**Nonproportional Relationship Graph Question 9.**

Analyze Relationships

Simone paid $12 for an initial yearâ€™s subscription to a magazine. The renewal rate is $8 per year. This situation can be represented by the equation y = 8x + 12, where x represents the number of years the subscription is renewed and y represents the total cost.

a. Make a table of values for this situation.

Type below:

____________

Answer:

Explanation:

y = 8x + 12

Choose several values for x and substitute in the equation to find y.

Question 9.

b. Draw a graph to represent the situation. Include a title and axis labels.

Type below:

____________

Answer:

Explanation:

Plot the ordered pairs from the table. Then draw a line connecting the points to represent all the possible solutions

Question 9.

c. Explain why this relationship is not proportional.

Type below:

____________

Answer:

It is not proportional as the graph does not pass through the origin

Explanation:

When a relationship is proportional, the graph of the equation passes through the origin.

It is not proportional as the graph does not pass through the origin

Question 9.

d. Does it make sense to connect the points on the graph with a solid line? Explain.

Type below:

____________

Answer:

No

Explanation:

No; The subscription is renewed for the entire year and cannot be done for a fraction of the year. The number of years must be a whole numb, so the total cost goes up in $8 increments.

### Representing Linear Nonproportional Relationships – Page No. 100

Question 10.

Analyze Relationships

A proportional relationship is a linear relationship because the rate of change is constant (and equal to the constant of proportionality). What is required of a proportional relationship that is not required of a general linear relationship?

Type below:

____________

Answer:

The ratio between one quantity to the other quantity should be constant for a proportional linear relationship. The graph should be a straight line that passes through the origin.

**Lesson 4.1 Representing Linear Nonproportional Relationships Answer Key Question 11.**

Communicate Mathematical Ideas

Explain how you can identify a linear non-proportional relationship from a table, a graph, and an equation.

Type below:

____________

Answer:

In a table, the ratios y/x will not be equal. A graph will not pass through the origin. An equation will be in the form y = mx + b where b is not equal to 0.

**Focus on Higher Order Thinking**

Question 12.

Critique Reasoning

George observes that for every increase of 1 in the value of x, there is an increase of 60 in the corresponding value of y. He claims that the relationship represented by the table is proportional. Critique Georgeâ€™s reasoning.

Type below:

____________

Answer:

The ratio is not constant, hence the relationship cannot be proportional.

Explanation:

Find y/x

90/1 = 90

150/2 = 75

210/3 = 70

270/4 = 67.5

330/5 = 66

The ratio is not constant, hence the relationship cannot be proportional.

Question 13.

Make a Conjecture

Two parallel lines are graphed on a coordinate plane. How many of the lines could represent proportional relationships? Explain.

Type below:

____________

Answer:

Maximum one

Explanation:

When there are two parallel lines, only one can pass through the origin and a line representing a proportional relationship must pass through the origin.

Maximum one

### Guided Practice – Determining Slope and y-intercept – Page No. 104

**Find the slope and y-intercept of the line in each graph.**

Question 1.

slope m = _____ y-intercept b = _____

m = ____________

b = ____________

Answer:

slope m = -2 y-intercept b = 1

m = -2

b = 1

Explanation:

Find the slope using two points from the grapgh by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (0, 1) and (x2, y2) = (2, -3)

Slope m = (y2 -y1)/(x2 â€“ x1) = (-3 â€“ 1)/(2 â€“ 0) = -4/2 = -2

From the graph when x = 0

y-intercept (b) = 1

**Lesson 4.2 Determining Slope and Y-Intercept Answer Key Pdf Question 2.**

slope m = _____ y-intercept b = _____

m = ____________

b = ____________

Answer:

slope m = 5 y-intercept b = -15

m = 5

b = -15

Explanation:

Find the slope using two points from the graph by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (3, 0) and (x2, y2) = (0, -15)

Slope m = (y2 -y1)/(x2 â€“ x1) = (-15 â€“ 0)/(0 â€“ 3) = 15/3 = 5

From the graph when x = 0

y-intercept (b) = -15

Question 3.

slope m = _____ y-intercept b = _____

Type below:

____________

Answer:

slope m = 3/2 y-intercept b = -2

m = 3/2

b = -2

Explanation:

Find the slope using two points from the graph by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (0, -2) and (x2, y2) = (2, 1)

Slope m = (y2 -y1)/(x2 â€“ x1) = (1 â€“ (-2))/(2 â€“ 0) = 3/2

From the graph when x = 0

y-intercept (b) = -2

Question 4.

slope m = _____ y-intercept b = _____

m = ____________

b = ____________

Answer:

slope m = -3 y-intercept b = 9

m = -3

b = 9

Explanation:

Find the slope using two points from the grapgh by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (3, 0) and (x2, y2) = (0, 9)

Slope m = (y2 -y1)/(x2 â€“ x1) = (9 â€“ 0))/(0 â€“ 3) = -9/3 = -3

From the graph when x = 0

y-intercept (b) = 9

**Find the slope and y-intercept of the line represented by each table.**

Question 5.

slope m = _____ y-intercept b = _____

m = ____________

b = ____________

Answer:

slope m = 3 y-intercept b = 1

m = 3

b = 1

Explanation:

Find the slope using two points from the grapgh by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (8, 25) and (x2, y2) = (6, 19)

Slope m = (y2 -y1)/(x2 â€“ x1) = (19 â€“ 25)/(6 â€“ 8) = 6/2 = 3

From the graph when x = 0

y-intercept (b) = 1

Question 6.

slope m = _____ y-intercept b = _____

m = ____________

b = ____________

Answer:

slope m = -4 y-intercept b = 140

m = -4

b = 140

Explanation:

Find the slope using two points from the grapgh by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (5, 120) and (x2, y2) = (15, 80)

Slope m = (y2 -y1)/(x2 â€“ x1) = (80 â€“ 120)/(15 â€“ 5) = -40/10 = -4

From the graph when x = 0

y-intercept (b) = 140

**Essential Question Check-In**

Question 7.

How can you determine the slope and the y-intercept of a line from a graph?

Type below:

____________

Answer:

Choose any two points on the line from the graph and use it to find the slope. Determine the point where the line crosses the y-axis to find the y-intercept.

### Independent Practice – Determining Slope and y-intercept – Page No. 105

Question 8.

Some carpet cleaning costs are shown in the table. The relationship is linear. Find and interpret the rate of change and the initial value for this situation.

Type below:

_____________

Answer:

Find the slope using two points

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (1, 125) and (x2, y2) = (3, 225)

Slope m = (y2 -y1)/(x2 â€“ x1) = (225 â€“ 125)/(3 â€“ 1) = 100/2 = 50

Find the initial value when the value of x is 0

Work backward from x = 1 to x = 0

(175 – 125)/(2 – 1) = 50/1 = 50

Subtract the difference of x and y from the first point.

x = 1 – 1 = 0

y = 125 – 50 = 75

y-intercept (b) = 75

The slope/rate of change represents the increase in the cost of cleaning the rooms for a unit increase in the number of rooms. The y-intercept shows the initial cost of carpet cleaning.

Question 9.

Make Predictions

The total cost to pay for parking at a state park for the day and rent a paddleboat are shown.

a. Find the cost to park for a day and the hourly rate to rent a paddleboat.

Type below:

_____________

Answer:

$5

Explanation:

Find the slope using two points

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (1, 17) and (x2, y2) = (2, 29)

Slope m = (y2 -y1)/(x2 â€“ x1) = (29 â€“ 17)/(2 â€“ 1) = 12/1 = 12

Find the initial value when the value of x is 0

Work backward from x = 1 to x = 0

(29 â€“ 17)/(2 â€“ 1) = 12/1 = 12

Subtract the difference of x and y from the first point.

x = 1 – 1 = 0

y = 17 – 12 = 5

The cost to park for a day is $5.

Question 9.

b. What will Lin pay if she rents a paddleboat for 3.5 hours and splits the total cost with a friend? Explain.

$ _____________

Answer:

$23.5

Explanation:

When Lin paddles for 3.5hr

Total Cost = 3.5(12) + 5 = 47

Lin’s cost = 47/2 = 23.5

Question 10.

Multi-Step

Raymondâ€™s parents will pay for him to take sailboard lessons during the summer. He can take half-hour group lessons or half-hour private lessons. The relationship between cost and number of lessons is linear.

a. Find the rate of change and the initial value for the group lessons.

Type below:

____________

Answer:

$25

Explanation:

Find the slope using two points

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (1, 55) and (x2, y2) = (2, 85)

Slope m = (y2 -y1)/(x2 â€“ x1) = (85 â€“ 55)/(2 â€“ 1) = 30/1 = 30

Rate of change is $30 for per lesson

Find the initial value when the value of x is 0

Work backward from x = 1 to x = 0

(85 â€“ 55)/(2 â€“ 1) = 30/1 = 30

Subtract the difference of x and y from the first point.

x = 1 – 1 = 0

y = 55 – 30 = 25

The initial value of the group lesson is $25.

Question 10.

b. Find the rate of change and the initial value for the private lessons.

Type below:

_____________

Answer:

$25

Explanation:

Find the slope using two points

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (1, 75) and (x2, y2) = (2, 125)

Slope m = (y2 -y1)/(x2 â€“ x1) = (125 â€“ 75)/(2 â€“ 1) = 50/1 = 50

The rate of change is $50 per lesson

Find the initial value when the value of x is 0

Work backward from x = 1 to x = 0

(125 â€“ 75)/(2 â€“ 1) = 50/1 = 50

Subtract the difference of x and y from the first point.

x = 1 – 1 = 0

y = 75 – 50 = 25

The initial value of the private lesson is $25.

Question 10.

c. Compare and contrast the rates of change and the initial values.

Type below:

_____________

Answer:

The initial value for both types of lessons is the same. The rate of change is higher for private lessons than group lesson

Explanation:

Compare the results of a and b

The initial value for both types of lessons is the same. The rate of change is higher for private lessons than group lesson

### Vocabulary – Determining Slope and y-intercept – Page No. 106

**Explain why each relationship is not linear.**

Question 11.

Type below:

_____________

Answer:

The rate of change is not constant, hence the relationship is not linear

Explanation:

Find the rate of change using two points Slope m = (y2 -y1)/(x2 â€“ x1)

(6.5 – 4.5)/(2 – 1) = 2

(8.5 – 6.5)/(3 – 2) = 2

(11.5 – 8.5)/(4 – 3) = 3

The rate of change is not constant, hence the relationship is not linear

Question 12.

Type below:

_____________

Answer:

The rate of change is not constant, hence the relationship is not linear

Explanation:

Find the rate of change using two points Slope m = (y2 -y1)/(x2 â€“ x1)

(126 – 140)/(5 – 3) = -7

(110 – 126)/(7 – 5) = -8

(92 – 110)/(9 – 7) = -9

The rate of change is not constant, hence the relationship is not linear

Question 13.

Communicate Mathematical Ideas

Describe the procedure you performed to derive the slope-intercept form of a linear equation.

Type below:

_____________

Answer:

Express the slope m between a random point (x, y) on the line and the point (0, b) where the line crosses the y-axis. Then solve the equation for y.

**H.O.T.**

**Focus on Higher Order Thinking**

Question 14.

Critique Reasoning

Your teacher asked your class to describe a real-world situation in which a y-intercept is 100 and the slope is 5. Your partner gave the following description: My younger brother originally had 100 small building blocks, but he has lost 5 of them every month since.

a. What mistake did your partner make?

Type below:

_____________

Answer:

If the brother loses 5 blocks every month, the slope would be -5 and not 5.

Explanation:

When the initial value is decreasing, the slope is negative.

If the brother loses 5 blocks every month, the slope would be -5 and not 5.

Question 14.

b. Describe a real-world situation that does match the situation.

Type below:

_____________

Answer:

I bought a 100-card pack and buy 5 additional cards every month.

Explanation:

Real-world situation

I bought a 100-card pack and buy 5 additional cards every month.

Question 15.

Justify Reasoning

John has a job parking car. He earns a fixed weekly salary of $300 plus a fee of $5 for each car he parks. His potential earnings for a week are shown in the graph. At what point does John begin to earn more from fees than his fixed salary? Justify your answer.

Type below:

_____________

Answer:

After parking 60 cars, John’s earnings become $600 double his initial base salary of $300.

Hence, after parking 61 cars, his earning from the fee becomes more than his fixed salary.

Explanation:

He earns the same in fees as his fixed salary for parking 300/5 = 60

After parking 60 cars, John’s earnings became $600 double his initial base salary of $300.

Hence, after parking 61 cars, his earning from the fee becomes more than his fixed salary.

### Guided Practice – Graphing Linear Nonproportional Relationships Using Slope and Y-intercept – Page No. 110

**Graph each equation using the slope and the y-intercept.**

Question 1.

y = \(\frac{1}{2}\)x âˆ’ 3

slope = _____ y-intercept = _____

Type below:

_____________

Answer:

slope = 1/2 y-intercept = -3

Explanation:

y = 1/2 x – 3

The y-intercept is b = -3. Plot the point that contains the y-intercept (0, -3)

The slope m = 1/2. Use the slope to find a second point. From (0, -3) count 1 unit up and 2 unit right. The new point is (2, -2)

Draw a line through the points

Question 2.

y = âˆ’3x + 2

slope = _____ y-intercept = _____

Type below:

_____________

Answer:

slope = -3 y-intercept = 2

Explanation:

y = -3x + 2

The y-intercept is b = 2. Plot the point that contains the y-intercept (0, 2)

The slope m = -3/1. Use the slope to find a second point. From (0, 2) count 3 unit down and 1 unit right. The new point is (1, -1)

Draw a line through the points

**Nonproportional Relationships Worksheet Question 3.**

A friend gives you two baseball cards for your birthday. Afterward, you begin collecting them. You buy the same number of cards once each week. The equation y = 4x + 2 describes the number of cards, y, you have after x weeks.

a. Find and interpret the slope and the y-intercept of the line that represents this situation. Graph y = 4x + 2. Include axis labels.

Type below:

_____________

Answer:

Explanation:

y = 4x + 2

The y-intercept is b = 2. Plot the point that contains the y-intercept (0, 2)

The slope m = 4. Use the slope to find a second point. From (0, 2) count 4 unit up and 1 unit right. The new point is (1, 6)

Draw a line through the points

Question 3.

b. Discuss which points on the line do not make sense in this situation. Then plot three more points on the line that do make sense.

Type below:

_____________

Answer:

Explanation:

The points with a negative value of x or y do not make sense as the number of cards or weeks cannot be negative.

**Essential Question Check-In**

Question 4.

Why might someone choose to use the y-intercept and the slope to graph a line?

Type below:

_____________

Answer:

When the relationship is given in the form y = mx + b, the y-intercept (b) and the slope (m) are easily accessible and easily calculable. Therefore, it is a good practice to use them to graph the line.

### Independent Practice – Graphing Linear Nonproportional Relationships Using Slope and Y-intercept – Page No. 111

Question 5.

Science

A spring stretches in relation to the weight hanging from it according to the equation y = 0.75x + 0.25 where x is the weight in pounds and y is the length of the spring in inches.

a. Graph the equation. Include axis labels.

Type below:

_____________

Answer:

Explanation:

y = 0.75x + 0.25

Slope m = 0.75 and y-intercept = 0.25

Plot the point that contains the y-intercept (0, 0.25)

The slope is m = 0.75/1. Use the slope to find a second point. From (0,0.25) count 0.75 unit up and 1 unit right. The new point is (1, 1)

Question 5.

b. Interpret the slope and the y-intercept of the line.

Type below:

_____________

Answer:

The slope represents the increase in the length of spring in inches for each increase of pound of weight. y-intercept represents the unstretched length of the spring When there is no weight attached.

Question 5.

c. How long will the spring be if a 2-pound weight is hung on it? Will the length double if you double the weight? Explain

Type below:

_____________

Answer:

When there is a 2-pound weight hung, the length of the spring would be 1.75 inches. No, When there is a 4-pound weight hung, the length of the spring would be 3.25 inches and not 3.5 inches.

**Look for a Pattern**

**Identify the coordinates of four points on the line with each given slope and y-intercept.**

Question 6.

slope = 5, y-intercept = -1

Type below:

_____________

Answer:

(2, 9)

(3, 14)

Explanation:

slope = 5, y-intercept = -1

Plot the point that contains the y-intercept (0, -1)

The slope is m = 5/1. Use the slope to find a second point. From (0, -1) count 5 unit up and 1 unit right. The new point is (1, 4)

Follow the same procedure to find the remaining three points.

(2, 9)

(3, 14)

Question 7.

slope = -1, y-intercept = 8

Type below:

_____________

Answer:

(2, 6)

(3, 5)

Explanation:

slope = -1, y-intercept = 8

Plot the point that contains the y-intercept (0, 8)

The slope is m = -1/1. Use the slope to find a second point. From (0, 8) count 1 unit down and 1 unit right. The new point is (1, 7)

Follow the same procedure to find the remaining three points.

(2, 6)

(3, 5)

Question 8.

slope = 0.2, y-intercept = 0.3

Type below:

_____________

Answer:

(2, 0.7)

(3, 0.9)

Explanation:

slope = 0.2, y-intercept = 0.3

Plot the point that contains the y-intercept (0, 0.3)

The slope is m = 0.2/1. Use the slope to find a second point. From (0, 0.3) count 0.2 unit up and 1 unit right. The new point is (1, 0.5)

Follow the same procedure to find the remaining three points.

(2, 0.7)

(3, 0.9)

Question 9.

slope = 1.5, y-intercept = -3

Type below:

_____________

Answer:

(2, 0)

(3, 1.5)

Explanation:

slope = 1.5, y-intercept = -3

Plot the point that contains the y-intercept (0, -3)

The slope is m = 1.5/1. Use the slope to find a second point. From (0, -3) count 1.5 unit up and 1 unit right. The new point is (1, -1.5)

Follow the same procedure to find the remaining three points.

(2, 0)

(3, 1.5)

Question 10.

slope = âˆ’\(\frac{1}{2}\), y-intercept = 4

Type below:

_____________

Answer:

(4, 2)

(6, 1)

Explanation:

slope = âˆ’\(\frac{1}{2}\), y-intercept = 4

Plot the point that contains the y-intercept (0, 4)

The slope is m = âˆ’\(\frac{1}{2}\)/1. Use the slope to find a second point. From (0, 4) count 1 unit down and 2 unit right. The new point is (2, 3)

Follow the same procedure to find the remaining three points.

(4, 2)

(6, 1)

Question 11.

slope = \(\frac{2}{3}\), y-intercept = -5

Type below:

_____________

Answer:

(6, -1)

(9, 1)

Explanation:

slope = \(\frac{2}{3}\), y-intercept = -5

Plot the point that contains the y-intercept (0, -5)

The slope is m = \(\frac{2}{3}\). Use the slope to find a second point. From (0, -5) count 2 unit up and 3 unit right. The new point is (3, -3)

Follow the same procedure to find the remaining three points.

(6, -1)

(9, 1)

Question 12.

A music school charges a registration fee in addition to a fee per lesson. Music lessons last 0.5 hour. The equation y = 40x + 30 represents the total cost y of x lessons. Find and interpret the slope and y-intercept of the line that represents this situation. Then find four points on the line.

Type below:

_____________

Answer:

y = 40x + 30

Slope = 40

y-intercept = 30

The slope represents the fee of the classes per lesson and the y-intercept represents the registration fee.

Plot the point that contains the y-intercept (0, 30)

The slope is m = 40/1. Use the slope to find a second point. From (0, 30) count 40 units up and 1 unit right. The new point is (1, 70)

Follow the same procedure to find the remaining three points.

(2, 110)

(3, 150)

### Graphing Linear Nonproportional Relationships Using Slope and Y-intercept – Page No. 112

Question 13.

A public pool charges a membership fee and a fee for each visit. The equation y = 3x + 50 represents the cost y for x visits.

a. After locating the y-intercept on the coordinate plane shown, can you move up three gridlines and right one gridline to find a second point? Explain.

Type below:

_____________

Answer:

Yes

Explanation:

Yes; Since the horizontal and vertical gridlines each represent 25 units, hence moving up 3 gridlines and right 1 gridline represents a slope of 75/25 or 3

Question 13.

b. Graph the equation y = 3x + 50. Include axis labels. Then interpret the slope and y-intercept.

Type below:

_____________

Answer:

The slope represents the fee per visit and the y-intercept represents the membership fee.

Explanation:

Slope = 3

y-intercept = 50

The slope represents the fee of the classes per lesson and the y-intercept represents the registration fee.

Plot the point that contains the y-intercept (0, 50)

The slope is m = 3/1. Use the slope to find a second point. From (0, 50) count 3 units up and 1 unit right. The new point is (1, 53)

Question 13.

c. How many visits to the pool can a member get for $200?

______ visits

Answer:

50 visits

Explanation:

You would get 50 visits for $200

**H.O.T.**

**Focus on Higher Order Thinking**

Question 14.

Explain the Error

A student says that the slope of the line for the equation y = 20 âˆ’ 15x is 20 and the y-intercept is 15. Find and correct the error.

Type below:

_____________

Answer:

The slope is -15 as it represents the change in y per unit change in x. The y-intercept is 20 when x = 0.

Explanation:

y = 20 âˆ’ 15x

The slope is -15 as it represents the change in y per unit change in x. The y-intercept is 20 when x = 0.

Question 15.

Critical Thinking

Suppose you know the slope of a linear relationship and a point that its graph passes through. Can you graph the line even if the point provided does not represent the y-intercept? Explain.

Type below:

_____________

Answer:

Yes. You can plot the given point and use the slope to find a second point. Connect the points by drawing a line.

Question 16.

Make a Conjecture

Graph the lines y = 3x, y = 3x âˆ’ 3, and y = 3x + 3. What do you notice about the lines? Make a conjecture based on your observation.

Type below:

_____________

Answer:

Explanation:

let’s tale the example

y = 3x

y = 3x – 3

y = 3x + 3

We notice that the lines are parallel to each other: the slopes of the lines are equal but the y-intersection point differs.

### Guided Practice – Proportional and Nonproportional Situations – Page No. 117

**Determine if each relationship is a proportional or nonproportional situation. Explain your reasoning.**

Question 1.

Look at the origin.

_____________

Answer:

Proportional relationship

Explanation:

Proportional relationship

The graph passes through the origin. Graph of a proportional relationship must pass through the origin

Question 2.

_____________

Answer:

Non-proportional relationship

Explanation:

The graph does not pass through the origin. The graph of a proportional relationship must pass through the origin

Non-proportional relationship

**Lesson 4 Skills Practice Proportional and Nonproportional Relationships Answer Key Question 3.**

q = 2p + \(\frac{1}{2}\)

Compare the equation with y = mx + b.

_____________

Answer:

q = 2p + \(\frac{1}{2}\)

The equation is in the form y = mx + b, with p being used es the variable instead of x and q instead of y. The value of m is 2, and the value b is 1/2. Since b is not 0, the relationship presented through the above equation is non-proportional.

Question 4.

v = \(\frac{1}{10}\)u

_____________

Answer:

Proportional relationship

Explanation:

v = \(\frac{1}{10}\)u

Compare with the form of equation y = mx + b. The equation represents a proportional relationship if b = 0

Proportional relationship

### Proportional and Nonproportional Situations – Page No. 118

**The tables represent linear relationships. Determine if each relationship is a proportional or nonproportional situation.**

Question 5.

Find the quotient of y and x.

_____________

Answer:

proportional relationship

Explanation:

Find the ratio y/x

12/3 = 4

36/9 = 4

84/21 = 4

Since the ratio is constant, the relationship is proportional.

**Lesson 4 Skills Practice Proportional and Nonproportional Relationships Question 6.**

_____________

Answer:

non-proportional

Explanation:

Find the ratio y/x

4/22 = 2/11

8/46 = 4/23

10/58 = 5/29

Since the ratio is not constant, the relationship is non-proportional.

Question 7.

The values in the table represent the number of households that watched three TV shows and the ratings of the shows. The relationship is linear. Describe the relationship in other ways.

Type below:

_____________

Answer:

proportional relationship

Explanation:

Find the ratio y/x

12/15,000,000 = 0.0000008

16/20,000,000 = 0.0000008

20/25,000,000 = 0.0000008

Since the ratio is constant, the relationship is proportional.

**Essential Question Check-In**

Question 8.

How are using graphs, equations, and tables similar when distinguishing between proportional and nonproportional linear relationships?

Type below:

_____________

Answer:

The ratio between y to x is constant when the relationship is proportional. Graphs, tables, and equations all can be used to find the ratio. The ratio is not constant when the relationship is non-proportional.

### Independent Practice – Proportional and Nonproportional Situations – Page No. 119

Question 9.

The graph shows the weight of a cross-country teamâ€™s beverage cooler based on how much sports drink it contains.

a. Is the relationship proportional or nonproportional? Explain.

_____________

Answer:

Non-proportional

Explanation:

The graph does not pass through the origin. Graph of a proportional relationship must pass through the origin

Non-proportional

Question 9.

b. Identify and interpret the slope and the y-intercept.

Type below:

_____________

Answer:

Slope m = (y2 -y1)/(x2 â€“ x1) = (12 – 10)/(4 â€“ 0) = 0.5

y-intercept is the weight of the empty cooler, which is 10 lbs.

Explanation:

Find the slope using two points from the grapgh by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (0, 10) and (x2, y2) = (4, 12)

Slope m = (y2 -y1)/(x2 â€“ x1) = (12 – 10)/(4 â€“ 0) = 0.5

From the graph when x = 0

y-intercept (b) = 10

y-intercept is the weight of the empty cooler, which is 10 lbs.

**In 10â€“11, tell if the relationship between a riderâ€™s height above the first floor and the time since the rider stepped on the elevator or escalator is proportional or nonproportional. Explain your reasoning.**

Question 10.

The elevator paused for 10 seconds after you stepped on before beginning to rise at a constant rate of 8 feet per second.

_____________

Answer:

Non-proportional

Explanation:

As there is a pause of 10 seconds, it would be the y-intercept of the graph (when x = 0)

Non-proportional

**Representing Linear Nonproportional Relationships Lesson 4.1 Answer Key Question 11.**

Your height, h, in feet above the first floor on the escalator is given by h = 0.75t, where t is the time in seconds.

_____________

Answer:

Proportional

Explanation:

Comparing with y = mx + b, where b = 0

Proportional

**Analyze Relationships**

**Compare and contrast the two graphs.**

Question 12.

Graph AÂ Â Â Â Graph B

y = \(\frac{1}{3}\) xÂ Â Â Â y = \(\sqrt { x } \)

Type below:

_____________

Answer:

Graph A represents a linear relationship while Graph B represents an exponential relationship. They both pass through the origin and the value of y increases with an increase in x.

### Proportional and Nonproportional Situations – Page No. 120

Question 13.

Represent Real-World Problems

Describe a real-world situation where the relationship is linear and nonproportional.

Type below:

_____________

Answer:

The entrance fee to the amusement park is $8 and there is a fee of $2 per ride.

**H.O.T.**

**Focus on Higher Order Thinking**

Question 14.

Mathematical Reasoning

Suppose you know the slope of a linear relationship and one of the points that its graph passes through. How can you determine if the relationship is proportional or nonproportional?

Type below:

_____________

Answer:

Use the graph and the given point to determine the second point. Connect the two points by a straight line. If the graph passes through the origin, the relationship is proportional and if the graph does not pass through the origin, the relationship is non-proportional.

**Lesson 4 Proportional and Nonproportional Relationships Question 15.**

Multiple Representations

An entrant at a science fair has included information about temperature conversion in various forms, as shown. The variables F, C, and K represent temperatures in degrees Fahrenheit, degrees Celsius, and kelvin, respectively.

a. Is the relationship between kelvins and degrees Celsius proportional? Justify your answer in two different ways.

_____________

Answer:

No, the relationship is not proportional.

Explanation:

Compare the equation B to the form: y = mx + b. Since b is not equal to 0, the relationship is non-proportional.

Find the ratio between the Kelvin and Degrees Celsius. Since the ratio is not constant, the relationship is non-proportional.

281.15/8 = 35.14

288.15/15 = 19.21

309.15/36 = 8.59

No, the relationship is not proportional.

Question 15.

b. Is the relationship between degrees Celsius and degrees Fahrenheit proportional? Why or why not?

_____________

Answer:

No, the relationship is not proportional.

Explanation:

Compare the equation A to the form: y = mx + b. Since b is not equal to 0, the relationship is non-proportional.

No, the relationship is not proportional.

### 4.1 Representing Linear Nonproportional Relationships – Model Quiz – Page No. 121

**Lesson 4.1 Representing Linear Nonproportional Relationships Question 1.**

Complete the table using the equation y = 3x + 2.

Type below:

_____________

Answer:

Explanation:

Given y = 3x + 2

x = -1; y = 3(-1) + 2 = -3 + 2 = -1

x = 0; y = 3(0) +2 = 2

x = 1; y = 3(1) + 2 = 3 + 2 = 5

x = 2; y = 3(2) + 2 = 6 + 2 = 8

x = 3: y = 3(3) + 2 = 9 + 2 = 11

**4.2 Determining Slope and Y-intercept**

Question 2.

Find the slope and y-intercept of the line in the graph.

Type below:

_____________

Answer:

Slope = 3

y-intercept (b) = 1

Explanation:

Find the slope using two points from the grapgh by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (0, 1) and (x2, y2) = (1, 4)

Slope m = (y2 -y1)/(x2 â€“ x1) = (4 – 1)/(1 â€“ 0) = 3/1

From the graph when x = 0

y-intercept (b) = 1

**4.3 Graphing Linear Nonproportional Relationships**

Question 3.

Graph the equation y = 2x âˆ’ 3 using slope and y-intercept.

Type below:

_____________

Answer:

Explanation:

Slope = 2

y-intercept = -3

Plot the point that contains the y-intercept (0, -3)

The slope is m = 2/1. Use the slope to find a second point. From (0, -3) count 2 unit up and 1 unit right. The new point is (1, -1)

Draw a line through the points

**4.4 Proportional and Nonproportional Situations**

Question 4.

Does the table represent a proportional or a nonproportional linear relationship?

_____________

Answer:

Since the ratio is constant, the table represents a proportional linear relationship.

Explanation:

Find the ratio y/x

4/1 = 4

8/2 = 4

12/3 = 4

16/4 = 4

20/5 = 4

Since the ratio is constant, the table represents a proportional linear relationship.

Question 5.

Does the graph in Exercise 2 represent a proportional or a nonproportional linear relationship?

_____________

Answer:

It represents a non-proportional linear relationship

Explanation:

The line of the graph does not pass through the origin. The graph of a proportional relationship must pass through the origin.

It represents a non-proportional linear relationship

Question 6.

Does the graph in Exercise 3 represent a proportional or a nonproportional relationship?

_____________

Answer:

It represents a non-proportional linear relationship

Explanation:

The line of the graph does not pass through the origin. The graph of a proportional relationship must pass through the origin

It represents a non-proportional linear relationship

**Essential Question**

Question 7.

How can you identify a linear nonproportional relationship from a table, a graph, and an equation?

Type below:

_____________

Answer:

In a table, the ratio of y/x is not constant for a non-proportional relationship.

In a graph, the line of the graph does not pass through the origin for a non-proportional relationship.

In an equation, the b is not equal to y = mx +b for a non-proportional relationship.

### Selected Response – Mixed Review – Page No. 122

Question 1.

The table below represents which equation?

Options:

a. y = âˆ’x âˆ’ 10

b. y = âˆ’6x

c. y = âˆ’4x âˆ’ 6

d. y = âˆ’4x + 2

Answer:

c. y = âˆ’4x âˆ’ 6

Explanation:

From the table, you can see that the y-intercept (when x = 0) is b = -6. Comparable to y = mx + b

The table is represented by Option C y = -4x – 6

Question 2.

The graph of which equation is shown below?

Options:

a. y = âˆ’2x + 3

b. y = âˆ’2x + 1.5

c. y = 2x + 3

d. y = 2x + 1.5

Answer:

a. y = âˆ’2x + 3

Explanation:

From the table, you can see that the y-intercept (when x = 0) is b = 3. Comparable to y = mx + b

The Option B and D are rejected.

Since the graph is slanting downwards, the slope is negative.

Option C is rejected

The graph represents y = -2x + 3

Question 3.

The table below represents a linear relationship.

What is the y-intercept?

Options:

a. -4

b. -2

c. 2

d. 3

Answer:

b. -2

Explanation:

Find the rate of change

(7 – 4)/(3 – 2) = (10 – 7)/(4 – 3) = 3

Find the value of y for x = 0

Works backward from x = 2 to x = 1

x = 2 – 1 = 1

y = 4 – 3 = 1

x = 1 – 1 = 0

y = 1 – 3 = -2

y-intercept = -2

Question 4.

Which equation represents a nonproportional relationship?

Options:

a. y = 3x + 0

b. y = âˆ’3x

c. y = 3x + 5

d. y = \(\frac{1}{3}\)x

Answer:

c. y = 3x + 5

Explanation:

For a non-proportional relationship, the equation is y = mx + b and b is not equal to 0.

Option C represents a non-proportional relationship y = 3x + 5

Question 5.

The table shows a proportional relationship. What is the missing y-value?

Options:

a. 16

b. 20

c. 18

d. 24

Answer:

c. 18

Explanation:

Find the ratio y/x

6/4 = 3/2

Since the relationship is proportional, the ratio is constant.

Using the ratio to find missing y

3/2 = y/12

y = 3/2 Ã— 12 = 18

Question 6.

What is 0.00000598 written in scientific notation?

Options:

a. 5.98 Ã— 10^{-6}

b. 5.98 Ã— 10^{-5}

c. 59.8 Ã— 10^{-6}

d. 59.8 Ã— 10^{-7}

Answer:

c. 59.8 Ã— 10^{-6}

Explanation:

0.00000598

Move the decimal 6 points

59.8 Ã— 10^{-6}

**Mini-Task**

Question 7.

The graph shows a linear relationship.

a. Is the relationship proportional or nonproportional?

____________

Answer:

It represents a non-proportional linear relationship

Explanation:

The line of the graph does not pass through the origin. The graph of a proportional relationship must pass through the origin.

It represents a non-proportional linear relationship

Question 7.

b. What is the slope of the line?

_______

Answer:

Slope m = -2

Explanation:

Find the slope using two points from the graph by

Slope m = (y2 -y1)/(x2 â€“ x1) where (x1, y1) = (0, -2) and (x2, y2) = (2, 1)

Slope m = (y2 -y1)/(x2 â€“ x1) = (-3 -1)/(0 + 2) = -4/2 = -2

Question 7.

c. What is the y-intercept of the line?

_______

Answer:

y-intercept (b) = -3

Explanation:

From the graph when x = 0

y-intercept (b) = -3

Question 7.

d. What is the equation of the line?

Type below:

____________

Answer:

y = -2x – 3

Explanation:

Substitute m and b in the form: y = mx + b

y = -2x – 3

### Conclusion:

Go Math Grade 8 Answer Key Chapter 4 Nonproportional Relationships for Download. All the beginners can easily start their practice and learn the maths in an easy way. Quickly start your practice with Go Math Grade 8 Answer Key.