# Texas Go Math Grade 7 Module 1 Answer Key Rational Numbers

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## Texas Go Math Grade 7 Module 1 Answer Key Rational Numbers

Multiply. Write the product in simplest form.

Question 1.
$$\frac{9}{14}$$ Ã— $$\frac{7}{6}$$ ____________
$$\frac{9}{14}$$ Ã— $$\frac{7}{6}$$
= $$\frac{3}{4}$$

Question 2.
$$\frac{3}{5}$$ Ã— $$\frac{4}{7}$$ ____________
We do not have any common factors here to divide with.
Simplify:
= $$\frac{12}{35}$$

$$\frac{11}{8}$$ Ã— $$\frac{10}{33}$$ ____________
$$\frac{11}{8}$$ Ã— $$\frac{10}{33}$$
= $$\frac{5}{12}$$

Question 4.
$$\frac{4}{9}$$ Ã— 3 ____________
Write 3 as $$\frac{3}{1}$$
$$\frac{4}{9}$$ Ã— $$\frac{3}{1}$$
= $$\frac{4}{3}$$

Divide.

Question 5.
$$\frac{1}{2}$$ Ã· $$\frac{1}{4}$$ ____________
= $$\frac{1}{2}$$ Ã— $$\frac{4}{1}$$ Multiply by the reciprocal of the divisor.
= $$\frac{1}{2}$$ Ã— $$\frac{4}{1}$$ Divide by the common factors.
= $$\frac{2}{1}$$ = 2 Simplify
= 2

Question 6.
$$\frac{3}{8}$$ Ã· $$\frac{13}{16}$$ ____________
= $$\frac{3}{8}$$ Ã— $$\frac{16}{13}$$ Multiply by the reciprocal of the divisor.
= $$\frac{3}{8}$$ Ã— $$\frac{16}{12}$$ Divide by the common factors.
= $$\frac{6}{13}$$ Simplify
= $$\frac{6}{13}$$

Question 7.
$$\frac{2}{5}$$ Ã· $$\frac{14}{15}$$ ____________
= $$\frac{2}{5}$$ Ã— $$\frac{15}{14}$$ Multiply by the reciprocal of the divisor.
= $$\frac{2}{5}$$ Ã— $$\frac{15}{15}$$ Divide by the common factors.
= $$\frac{3}{7}$$ Simplify
= $$\frac{3}{7}$$

$$\frac{4}{9}$$ Ã· $$\frac{16}{27}$$ ____________
= $$\frac{4}{9}$$ Ã— $$\frac{27}{16}$$ Multiply by the reciprocal of the divisor.
= $$\frac{4}{9}$$ Ã— $$\frac{27}{16}$$ Divide by the common factors.
= $$\frac{3}{4}$$ Simplify
= $$\frac{3}{4}$$

Question 9.
$$\frac{3}{5}$$ Ã· $$\frac{5}{6}$$ ____________
= $$\frac{3}{5}$$ Ã— $$\frac{6}{5}$$ Multiply by the reciprocal of the divisor.
= $$\frac{18}{25}$$ No common factors. Simplify
= $$\frac{18}{25}$$

Question 10.
$$\frac{1}{4}$$ Ã· $$\frac{23}{24}$$ ____________
= $$\frac{1}{4}$$ Ã— $$\frac{24}{23}$$ Multiply by the reciprocal of the divisor.
= $$\frac{1}{4}$$ Ã— $$\frac{24}{23}$$ Divide by the common factors.
= $$\frac{6}{23}$$ Simplify
= $$\frac{6}{23}$$

Question 11.
6 Ã· $$\frac{3}{5}$$ ____________
Write 6 as $$\frac{6}{1}$$
= $$\frac{6}{1}$$ Ã— $$\frac{5}{3}$$ Multiply by the reciprocal of the divisor.
= $$\frac{6}{1}$$ Ã— $$\frac{5}{3}$$ Divide by the common factors.
= $$\frac{10}{1}$$ = 10 Simplify
= 10

Texas Go Math Grade 7 Module 1 Answer Key Pdf Question 12.
$$\frac{4}{5}$$ Ã· 10 ____________
Write 10 as $$\frac{10}{1}$$
= $$\frac{4}{5}$$ Ã— $$\frac{10}{1}$$ Multiply by the reciprocal of the divisor.
= $$\frac{4}{5}$$ Ã— $$\frac{10}{1}$$ Divide by the common factors.
= $$\frac{8}{1}$$ = 8 Simplify
= 8

Evaluate each expression.

Question 13.
21 – 6 Ã· 3 _________
= 21 – 2 MultipLy and divide from Left to right.
= 19 Add and substract from left to right
= 19

Question 14.
18 + (7 – 4) Ã— 3 _________
If first step get rid of parentheses to obtain:
18 + (7 – 3) â€¢ 3 = 18 + 3 â€¢ 3
In second step multiply from left to right.
18 + 3 â€¢ = 18 + 9
Third step is where we add from left to right.
18 + 9 = 27
= 27

Question 15.
5 + (8 – 3)2 ___________
= 5 + (5)2 Operate within parenthesis.
= 5 + 25 SimpLify exponents
= 30 Add and subtract from Left to right.
= 30

Texas Go Math Rational Numbers Test Grade 7 Pdf with Answers Question 16.
9 + 18 Ã· 3 + 10 ________
= 9 + 6 + 10 MuLtiply and divide from Left to right
= 15 + 10 Add and subtract from Left to right.
= 25

Question 17.
60 – (3 – 1)4 Ã— 3 _________
= 60 – (2)4 Ã— 3 Operate within parenthesis.
= 60 – 16 Ã— 3 SimpLify exponents
= 60 – 48 MuLtiply and divide from Left to right
= 12 Add and subtract from left to right.
= 12

10 – 16 Ã· 4 Ã— 2 + 6 _________
= 10 – 4 Ã— 2 + 6 MuLtipLy and divide from Left to right
= 10 – 8 + 6 Add and subtract from Left to right.
= 2 + 6
= 8

Visualize Vocabulary
Use the âœ“ words to complete the graphic. You can put more than one word in each section of the triangle.

Understand Vocabulary

Complete the sentences using the preview words.

Question 1.
A group of items is a __________. A set contained within another set is a __________.