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## Texas Go Math Grade 5 Lesson 13.5 Answer Key Multi-Step Measurement Problems

**Essential Question**

How can you solve multi-step problems that include measurement conversions?

Answer:

The steps to solve the multi-step problems that include measurement conversions are:

Step 1:

Write the given information and what to find

Step 2:

Plan a strategy how to find the required information or quantity

Step 3:

If there are unit conversions, then convert them by using the following rules:

If we have to convert a small unit into a larger unit, then multiply

If we have to convert a larger unit into a small unit, then divide

**Unlock the Problem**

A leaky faucet in Jarodâ€™s house drips 2 cups of water each day. After 2 weeks of dripping, the faucet is fixed. Â¡fit dripped the same amount each day, how many quarts of water dripped from Jarodâ€™s leaky faucet in 2 weeks?

Use the steps to solve the multi-step problem.

Step 1

Record the information you are given.

The faucet drips 2 cups of water each day.

The faucet drips for 2 weeks.

Step 2

Find the total amount of water dripped in cups each day days in 2 weeks.

Since you are given the amount of water dripped each day, you must convert 2 weeks into days and multiply.

Think: There are 7 days in 1 week.

So,

The faucet drips 14 cups in 2 weeks.

Step 3

Convert from cups to quarts.

Think: There are 2 cups in 1 pint.

There are 2 pints in 1 quart.

2 cups = 2 pints

2 pints = 4 quarts

So,

Jarodâ€™s leaky faucet drips 56 quarts of water in 2 weeks.

â€¢ What if the faucet dripped for 4 weeks before it was fixed? How many quarts of water would have leaked?

Answer:

From the above Problem,

We can observe that

Jarodâ€™s leaky faucet drips 56 quarts of water in 2 weeks.

So,

The number of quarts of water if the faucet dripped for 4 weeks = 2 Ã— (The number of quarts of water if the faucet dripped for 2 weeks)

= 2 Ã— 56

= 112 quarts

Hence, from the above,

We can conclude that

The number of quarts of water if the faucet dripped for 4 weeks is: 112 quarts of water

Example

A carton of large, Grade A eggs weighs about 1.5 pounds. If a carton holds a dozen eggs, how many ounces does each egg weigh?

Step 1

In ounces, find the weight of a carton of eggs.

Think: 1 pound = 16 ounces

Weight of a carton (in ounces):

So,

The carton of eggs weighs about 24 ounces.

Step 2

In ounces, find the weight of each egg in a carton.

Think: 1 carton (dozen eggs) = 12 eggs

Weight of each egg (in ounces):

So,

Each egg weighs about 2 ounces.

**Share and Show**

Question 1.

After each soccer practice, Scott runs 4 sprints of 20 yards each. If he continues his routine, how many practices will it take for Scott to have sprinted a total of 2 miles combined?

Scott sprints ___ yards each practice.

Since there are ___ yards in 2 miles, he will need to continue his routine for ___ practices.

Answer:

It is given that

After each soccer practice, Scott runs 4 sprints of 20 yards each.

So,

The number of yards Scott sprints each practice = 4 Ã— 20

= 80 yards

Now,

We know that,

1 mile = 1,760 yards

So,

The number of practices will it take for Scott to have sprinted a total of 2 miles = \(\frac{2 Ã— 1,760}{80}\)

= 44 practices

Hence, from the above,

We can conclude that

The number of practices will it take for Scott to have sprinted a total of 2 miles is: 44 practices

**Go Math Answer Key Grade 5 Step Measurement Question 2.**

A worker at a mill is loading 5-lb bags of flour into boxes to deliver to a local warehouse. Each box holds 12 bags of flour. If the warehouse orders 3 tons of flour, how many boxes are needed to fulfill the order?

Answer:

It is given that

A worker at a mill is loading 5-lb bags of flour into boxes to deliver to a local warehouse. Each box holds 12 bags of flour

Now,

According to the given information,

The total number of bags of flour = (The total number of bags) Ã— 5

= 5 Ã— 12

= 60 bags of flour

Now,

We know that,

1 Ton = 2,000 Pounds

So,

The total number of boxes needed to fulfill the given order = (The total quantity of the order) Ã· (The number of bags of flour)

= \(\frac{3 Ã— 2,000}{60}\)

= \(\frac{6,000}{60}\)

= 100 boxes

Hence, from the above,

We can conclude that

The total number of boxes needed to fulfill the given order is: 100 boxes

Question 3.

Cory brings five 1-gallon jugs of juice to serve during parent night at his school. If the paper cups he is using for drinks can hold 8 fluid ounces, how many drinks can Cory serve for parent night?

Answer:

It is given that

Cory brings five 1-gallon jugs of juice to serve during parent night at his school

Now,

We know that,

1 Gallon = 4 Quarts

1 Quart = 2 Pints

1 Pint = 2 cups

1 cup = 8 fluid ounces

So,

1 Gallon = 4 Ã— 2 Ã— 2 Ã— 8

= 8 Ã— 16

= 128 fluid ounces

Now,

The number of drinks that Cory can serve for Parent night = \(\frac{128}{8}\)

= 16 drinks

Hence, from the above,

We can conclude that

The number of drinks that Cory can serve for Parent night is: 16 drinks

**Math Talk**

**Mathematical Processes**

Explain the steps you took to solve Exercise 2?

Answer:

The steps that you took to solve Exercise 2 are:

Step 1:

Find the number of bags of flour

Step 2:

Convert 3 tons into pounds

Step 3:

Divide the result in Step 3 and the result in Step 2 respectively to find the number of boxes that are needed to fulfill the order

**Problem Solving**

**Solve.**

Question 4.

**Apply** A science teacher needs to collect lake water for a lab she is teaching about purifying water. The lab requires each student to use 4 fluid ounces of lake water. If 68 students are participating, how many pints of lake water will the teacher need to collect?

Answer:

It is given that

A science teacher needs to collect lake water for a lab she is teaching about purifying water. The lab requires each student to use 4 fluid ounces of lake water

Now,

We know that,

1 cup = 8 fluid ounces

1 pint = 2 cups

So,

4 fluid ounces = \(\frac{1}{4}\) pint

So,

According to the given information,

The number of pints of lake water the teacher will be needed to collectÂ = 68 Ã— 4 fluid ounce

= 272 fluid ounces

= \(\frac{272}{16}\)

= 17 pints

Hence, from the above,

We can conclude that

The number of pints of lake water the teacher will need to collect is: 17 pints

**Go Math Grade 5 Multiple-Step Problems Answer Key Question 5.**

**H.O.T.** **Use Diagrams** A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug. If the lights on the string are spaced 4 inches apart, how many lights are there on the string? Draw a picture to help you solve the problem.

Answer:

It is given that

A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug and the lights on the string are spaced 4 inches apart

Now,

We know that,

1 feet = 12 inches

So,

The total length of a string = 28 Ã— 12

= 336 inches

Now,

The remaining length of the string = (The total length of the string) – (The distance of the first light on the string)

= 336 – 16

= 320 inches

So,

The total number of lights that are present on the string = (The remaining length of the string) Ã· (The distance of each light placed)

= \(\frac{320}{4}\)

= 80 lights

Hence, from the above,

We can conclude that

The total number of lights that are present on the string is: 80 lights

Question 6.

**Multi-Step** When Jamie’s car moves forward such that each tire makes one full rotation, the car has traveled 72 inches. How many full rotations do the tires make when Jamie’s car travels 10 yards?

Answer:

It is given that

When Jamie’s car moves forward such that each tire makes one full rotation, the car has traveled 72 inches

Now,

The distance travelled in one rotation = 72 inches,

So,

The number of rotation the car travelled for 72 inches = 1

Now,

The number of rotations the car travelled for 1 inches= \(\frac{1}{72}\)

Also,

It is given that

The car travelled 10 yards

Now,

We know that,

1 yard = 36 inches

So,

The distance travelledÂ by the car = 36 Ã— 10

= 360 inches

So,

The number of rotations the car travelled for 360 inches = \(\frac{360}{72}\)

= 5 rotations

Hence, from the above,

We can conclude that

The number of rotations the car travelled for 360 inches is: 5 rotations

Question 7.

**Multi-Step** A male African elephant weighs 7 tons. If a male African lion at the local zoo weighs 13,650 pounds less than the male African elephant, how many pounds does the lion weigh?

Answer:

It is given that

A male African elephant weighs 7 tons and a male African lion at the local zoo weighs 13,650 pounds less than the male African elephant

Now,

We know that,

1 Ton = 2,000 pounds

So,

The weight of a male African elephant = 7 Ã— 2,000 pounds

= 14,000 pounds

Now,

According to the given information,

The weight of a male African lion = 14,000 – 13,650

= 350 Pounds

Hence, from the above,

We can conclude that

The weight of a male African elephant is: 350 pounds

**Problem Solving**

Question 8.

**Multi-Step** An office supply company is shipping a case of pencils to a store. There are 64 boxes of pencils in the case. If each box of pencils weighs 2.5 ounces, what is the weight, in pounds, of the case of pencils?

Answer:

It is given that

An office supply company is shipping a case of pencils to a store. There are 64 boxes of pencils in the case. If each box of pencils weighs 2.5 ounces

So,

The total weight of the case of pencils = 64 Ã— (The weight of each box of pencils)

= 64 Ã— 2.5

= 160 ounces

Now,

We know that,

1 pound = 16 ounces

1 ounce = \(\frac{1}{16}\) pounds

So,

The total weight of the case of pencils in pounds = 160 Ã— \(\frac{1}{16}\)

= 10 pounds

Hence, from the above,

We can conclude that

The total weight of the case of pencils in pounds is: 10 pounds

**Go Math 5th Grade Lesson 13.5 Answer Key Question 9.**

**H.O.T.** At a local animal shelter, there are 12 small-size dogs and 5 medium-size dogs. Every day, the small-size dogs are each given 12.5 ounces of dry food and the medium-size dogs are each given 18 ounces of the same dry food. How many pounds of dry food does the shelter serve in one day?

Answer:

It is given that

At a local animal shelter there are 12 small-size dogs and 5 medium-size dogs. Every day, the small-size dogs are each given 12.5 ounces of dry food and the medium-size dogs are each given 18 ounces of the same dry food.

Now,

According to the given information,

The number of ounces of dry food does the shelter serve in one day = (12 Ã— 12.5) + (5 Ã— 18)

= 150 + 90

= 240 ounces

Now,

We know that,

1 Pound = 16 ounces

1 ounce = \(\frac{1}{16}\) pound

So,

The number of pounds of dry food does the shelter serve in one day = 240 Ã— \(\frac{1}{16}\) pounds

= 15 pounds

Hence, from the above,

We can conclude that

The number of pounds of dry food does the shelter serve in one day is: 15 pounds

**Daily Assessment Task**

**Fill in the bubble completely to show your answer.**

Question 10.

**Analyze** A 2.3-ton shark is on one side of a pan balance in a cartoon. Seals are piling up on the other side, trying to “outweigh” the shark. What is the least number of 150-pound seals that would have a combined weight greater than the shark’s weight?

(A) 28 seals

(B) 30 seals

(C) 29 seals

(D) 31 seals

Answer:

It is given that

A 2.3-ton shark is on one side of a pan balance in a cartoon. Seals are piling up on the other side, trying to “outweigh” the shark

Now,

We know that,

1 Ton = 2,000 Pounds

So,

The weight of a shark = 2.3 Ã— 2,000 pounds

= 4,600 pounds

So,

According to the given information,

The least number of 150-pound seals that would have a combined weight greater than the shark’s weight = \(\frac{4,600}{150}\)

= 30.66

â‰… 31 seals

Hence, from the above,

We can conclude that

The least number of 150-pound seals that would have a combined weight greater than the shark’s weight is:

Question 11.

Sara has 2 pounds of chicken. She uses 5 ounces of chicken while cooking. How can you determine the mass of chicken that she has left?

(A) Divide 2 by 16, and then subtract 5.

(B) Divide 2 by 16, and then add 5.

(C) Multiply 2 by 16, and then subtract 5.

(D) Multiply 2 by 16, and then add 5.

Answer;

It is given that

Sara has 2 pounds of chicken. She uses 5 ounces of chicken while cooking

Now,

We know that,

1 pound = 16 ounces

So,

The total amount of chicken Sara has = 2 Ã— 16

= 32 ounces

Now,

The mass of the chicken that Sara has left = (16 Ã— 2) – 5

= 32 – 5

= 27 ounces

Hence, from the above,

We can conclude that

The mass of the chicken that Sara has left is:

**5th Grade Math Answer Key Lesson 13.5 Question 12.**

**Multi-Step** Leo has three pieces of ribbon. One piece is 4 yards long, another piece is 5 feet long, and the last piece is 10 inches long. How much ribbon does Leo have in all?

(A) 214 inches

(B) 118 inches

(C) 19 inches

(D) 57 inches

Answer:

It is given that

Leo has three pieces of ribbon. One piece is 4 yards long, another piece is 5 feet long, and the last piece is 10 inches long

Now,

We know that,

1 yard = 36 inches

1 feet = 12 inches

So,

The total length of the ribbon = (4 Ã— 36) + (5 Ã— 12) + 10

= 144 + 60 + 10

= 214 inches

Hence, from the above,

We can conclude that

The total length of the ribbon is:

**Texas Test Prep**

Question 13.

For a class assignment, students are asked to record the total amount of water they drink in one day. Melinda records that she drank four 8-fluid ounce glasses of water and two 1-pint bottles. How many quarts of water did Melinda drink during the day?

(A) 2 quarts

(B) 4 quarts

(C) 3 quarts

(D) 8 quarts

Answer:

It is given that

For a class assignment, students are asked to record the total amount of water they drink in one day. Melinda records that she drank four 8-fluid ounce glasses of water and two 1-pint bottles

Now,

We know that,

1 pint = 16 fluid ounces

1 quart = 32 fluid ounces

1 fluid ounce = \(\frac{1}{32}\) quarts

Now,

According to the given information,

The number of quarts of water did Melinda drink during the day = (4 Ã— 8 fluid ounces) + (2 Ã— 1 pint)

= (32 Ã— \(\frac{1}{32}\) quarts) + (2 Ã— \(\frac{1}{2}\) quarts)

= 1 + 1

= 2 quarts

Hence, from the above,

We can conclude that

The number of quarts of water did Melinda drink during the day is:

### Texas Go Math Grade 5 Lesson 13.5 Homework and Practice Answer Key

**Solve.**

Question 1.

Diego drinks 16 ounces of his favorite sport drink every day after soccer practice for 2 weeks. How many quarts of the sport drink does Diego consume in 2 weeks?

Answer:

It is given that

Diego drinks 16 ounces of his favorite sport drink every day after soccer practice for 2 weeks

Now,

We know that,

1 cup = 8 fluid ounces

1 pint = 2 cups

1 quart = 2 pints

1 week = 7 days

1 quart = 32 ounces

So,

The number of quarts of the sport drink does Diego consume in 2 weeks = 2 Ã— 7 Ã—Â \(\frac{16}{32}\)

= 14 Ã— \(\frac{1}{2}\)

= 7 quarts

Hence, from the above,

We can conclude that

The number of quarts of the sport drink does Diego consume in 2 weeks is: 7 quarts

Question 2.

A rancher is putting a fence around a square animal pen. The perimeter of the pen is 32 feet. The fence posts will be 16 inches apart. She starts by putting 1 fence post at each corner of the pen. How many fence posts does she use altogether? Draw a picture to model the problem.

Answer:

It is given that

A rancher is putting a fence around a square animal pen. The perimeter of the pen is 32 feet. The fence posts will be 16 inches apart. She starts by putting 1 fence post at each corner of the pen

Now,

We know that,

1 feet = 12 inches

So,

The perimeter of the pen = 32 Ã— 12

= 384 inches

So,

The number of fence posts does a rancher used altogether = \(\frac{384}{16}\)

= 24 fence posts

Hence, from the above,

We can conclude that

The number of fence posts a rancher uses altogether is: 24 fence posts

**5th Grade Go Math Answer Key Lesson 13.5 Question 3.**

A koala weighs 20 pounds. In her pouch, she carries her joey which weighs 20 ounces. What is the combined weight of the adult koala and her joey in ounces?

Answer:

It is given that

A koala weighs 20 pounds. In her pouch, she carries her Joey which weighs 20 ounces

Now,

We know that,

1 pound = 16 ounces

So,

The combined weight of the adult koala and her joey in ounces = (20 Ã— 16) + 20

= 320 + 20

= 340 ounces

Hence, from the above,

We can conclude that

The combined weight of the adult koala and her joey in ounces is: 340 ounces

Question 4.

On Friday, 32 students in Mr. Tanika’s class are each served 6 ounces of milk for lunch. How many quarts of milk are served to the class on Friday?

Answer:

It is given that

On Friday, 32 students in Mr. Tanika’s class are each served 6 ounces of milk for lunch

Now,

We know that,

1 quart = 32 ounces

So,

The number of quarts of milk are served to the class on Friday = 32 Ã— 6 ounces

= 192 ounces

= \(\frac{192}{32}\)

= 6 quarts

Hence, from the above,

We can conclude that

The number of quarts of milk are served to the class on Friday is: 6 quarts

**Problem Solving**

Question 5.

Vanessa bought 5 feet of ribbon. She cut off 36 inches to wrap a package and 18 inches to decorate her scrapbook. How much ribbon does Vanessa have left?

Answer:

It is given that

Vanessa bought 5 feet of ribbon. She cut off 36 inches to wrap a package and 18 inches to decorate her scrapbook

Now,

We know that,

1 feet = 12 inches

So,

According to the given information,

The amount of ribbon does Vanessa has left = (5 Ã— 12) – (36 + 18)

= 60 – 54

= 6 inches

Hence, from the above,

We can conclude that

The amount of ribbon does Vanessa has left is: 6 inches

Question 6.

Students fill beanbags to play a classroom number game. Each beanbag contains 3 cups of beans. They have a 1-pint container, a 1-quart container, and a 1-gallon container filled with beans to use for the beanbags. What is the greatest number of beanbags they can make?

Answer:

It is given that

Students fill beanbags to play a classroom number game. Each beanbag contains 3 cups of beans. They have a 1-pint container, a 1-quart container, and a 1-gallon container filled with beans to use for the beanbags

Now,

We know that,

1 pint = 2 cups

1 quart = 2 pints

1 gallon = 4 quarts

So,

The number of beanbags present in a 1-pint container = 3 Ã— 2 = 6 beanbags

The number of beanbags present in a 1-quart container = 3 Ã— 2 Ã— 6 = 36 beanbags

The number of beanbags present in a 1-gallon container = 3 Ã— 4 Ã— 36 = 432 beanbags

Hence, from the above,

We can conclude that

The greatest number of beanbags the students can make is: 432 beanbags

**Texas Prep**

**Lesson Check**

**Fill in the bubble completely to show your answer.**

Question 7.

A large brick weighs 8 pounds. A small brick weighs 52 ounces. How can you determine the difference in weight between the large brick and the small brick?

(A) Divide 16 by 8, and then add 52.

(B) Divide 16 by 8, and then subtract 52.

(C) Multiply 8 by 16, and then add 52.

(D) Multiply 8 by 16, and then subtract 52.

Answer:

It is gievn that

A large brick weighs 8 pounds. A small brick weighs 52 ounces

Now,

We know that,

1 Pound = 16 Ounces

So,

According to the given information,

The difference in weight between the large brick and the small brick = (8 Ã— 16) – 52

Hence, from the above,

We can conclude that

The difference in weight between the large brick and the small brick is given by:

**Go Math Multi Step Word Problems 5th Grade Question 8.**

Ariel has a gallon container of juice and a one-quart container of juice. How many 1-cup servings of juice does Ariel have?

(A) 20

(B) 36

(C) 12

(D) 44

Answer:

It is given that

Ariel has one-gallon container of juice and one-quart container of juice

Now,

We know that,

1 pint = 2 cups

1 quart = 2 pints

1 gallon = 4 quarts

So,

According to the given information,

The number of 1-cup servings of juice does Ariel have = (1 Ã— 4 Ã— 2) + (1 Ã— 4)

= 8 + 4

= 12 1-cup servings

Hence, from the above,

We can conclude that

The number of 1-cup servings of juice does Ariel have is:

Question 9.

The veterinarian weighs Jim’s two dogs. His collie weighs 37 pounds. His terrier weighs 240 ounces. What is the total weight of Jim’s dogs?

(A) 592 ounces

(B) 52 pounds

(C) 53 pounds

(D) 12 pounds

Answer:

It is given that

The veterinarian weighs Jim’s two dogs. His collie weighs 37 pounds. His terrier weighs 240 ounces

Now,

We know that,

1 pound = 16 ounces

So,

The total weight of Jim’s dogs = (37 Ã— 16)+ 240

= 592 + 240

= 832 ounces

= \(\frac{832}{16}\)

= 52 pounds

Hence, from the above,

We can conclude that

The total weight of Jim’s dogs is:

Question 10.

An elevator has a maximum weight limit of 1.5 tons. Rozell Company workers load boxes that weigh 150 pounds each into the elevator to transport them to the first floor. What is the greatest number of boxes the elevator can hold?

(A) 16

(B) 13

(C) 10

(D) 20

Answer:

It is given that

An elevator has a maximum weight limit of 1.5 tons. Rozell Company workers load boxes that weigh 150 pounds each into the elevator to transport them to the first floor

Now,

We know that,

1 Ton = 2,000 Pounds

So,

According to the given information,

The greatest number of boxes the elevator can hold = \(\frac{1.5 Ã— 2,000}{150}\)

= 20 boxes

Hence, from the above,

We can conclude that

The greatest number of boxes the elevator can hold is:

Question 11.

**Multi-Step** An artist painted a rectangular mural on the wall. Two sides are each 26 inches long. The other two sides are each 2 yards long. What is the perimeter of the mural?

(A) 98 inches

(B) 196 inches

(C) 62 inches

(D) 144 inches

Answer:

It is given that

An artist painted a rectangular mural on the wall. Two sides are each 26 inches long. The other two sides are each 2 yards long

Now,

We know that,

1 feet = 12 inches

1 yard = 36 inches

So,

According to the given information,

The perimeter of the mural = (2 Ã— 26) + (2 Ã— 2 Ã— 36)

= 52 + 144

= 196 inches

Hence, from the above,

We can conclude that

The perimeter of the mural is:

Question 12.

**Multi-Step** Vince has a rectangular rug in his room with an area of 10 feet. The length of the rug is 18 inches longer than the width. What could be the dimensions of the rug?

(A) length: 4 feet; width 2.5 feet

(B) length: 2 feet; width 3 feet

(C) length: 5 feet; width 2 feet

(D) length: 2.5; width 4 feet

Answer:

It is given that

Vince has a rectangular rug in his room with an area of 10 feet. The length of the rug is 18 inches longer than the width

Now,

We know that,

1 feet = 12 inches

Now,

Let the width of the rectangular rug be x inches

So,

According to the given information,

10 = x (x + 1.5)

Hence, from the above,

We can conclude that

The dimensions of the rug are: