McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key

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McGraw-Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key

Identify each angle as obtuse, acute or right.

Question 1.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 1
Answer:
Obtuse Angle
Explanation:
Any angle that is greater than 90° but less than 180° is known as obtuse angle.

Question 2.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 2
Answer:
Right Angle.
Explanation:
If the angle formed between two rays is exactly 90° then it is called a Right Angle.

Question 3.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 3
Answer:
Acute Angle
Explanation:
If two rays intersect at a vertex, forming an angle that is less than 90° is known as Acute Angle.

Question 4.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 4
Answer:
Acute Angle
Explanation:
If two rays intersect at a vertex, forming an angle that is less than 90° is known as Acute Angle.

Question 5.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 5
Answer:
Obtuse Angle
Explanation:
Any angle that is greater than 90° but less than 180° is known as obtuse angle.

Identify each pair of angles as supplementary, complementary, vertical, or not any of these. Explain why.

Question 6.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 6
Answer:
Complementary Angle;
Sum of the angle measures are 90°.
Explanation:
If the sum of two angles is 90 degrees,
then they are said to be complementary angles, and they form a right angle together.
52 ° + 38 ° = 90 °

Question 7.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 7
Answer:
Supplementary Angle;
Sum of the angles is 180°.
Explanation:
If the sum of two angles is 180 degrees,
then they are said to be supplementary angles, which form a linear angle together.
66 ° + 114 ° = 180 °

Question 8.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 8
Answer:
Complementary Angle;
Sum of the angle measures are 90°.
Explanation:
If the sum of two angles is 90 degrees,
then they are said to be complementary angles, and they form a right angle together.
66 ° + 24 ° = 90 °

Question 9.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 9
Answer:
Neither Complementary nor Supplementary Angle;
Sum of the angles are 89°.
Explanation:
If the sum of two angles is 90 degrees,
then they are said to be complementary angles, and they form a right angle together.
But the sum of the two angles in the given figure is less than 90 degrees.
So, it is neither Complementary nor Supplementary Angle.
44 ° + 45 ° = 89 °

Question 10.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 10
Answer:
Neither Complementary or Supplementary Angle;
Sum of the angles are 169°.
Explanation:
If the sum of two angles is 180 degrees,
then they are said to be supplementary angles, which form a linear angle together.
But the sum of the two angles in the given figure is less than 180 degrees.
So, it is neither Complementary nor Supplementary Angle.
144 ° + 25 ° = 169 °

Identity the following triangles as scalene, equilateral, or isosceles.

Question 11.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 11
Answer:
Equilateral Triangle.
Explanation:
An equilateral triangle is a triangle with all three sides of equal length.

Question 12.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 12
Answer:
Scalene Triangle.
Explanation:
All angles of a scalene triangle are unequal, all are of different size and length.

Question 13.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 13
Answer:
Isosceles Triangle.
Explanation:
An Isosceles triangle is a triangle with two equal sides.

Question 14.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 14
Answer:
Scalene Triangle.
Explanation:
All angles of a scalene triangle are unequal, all are of different size and length.

Question 15.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 15
Answer:
Equilateral Triangle.
Explanation:
An equilateral triangle is a triangle with all three sides of equal length.

Question 16.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 16
Answer:
Isosceles Triangle.
Explanation:
An Isosceles triangle is a triangle with two equal sides.

Identify the following triangles as obtuse, right, or acute.

Question 17.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 17
Answer:
Right Angle.
Explanation:
If the angle formed between two rays is exactly 90° then it is called a Right Angle.

Question 18.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 18
Answer:
Acute Angle.
Explanation:
If two rays intersect at a vertex, forming an angle that is less than 90° is known as Acute Angle.

Question 19.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 19
Answer:
Acute Angle.
Explanation:
If two rays intersect at a vertex, forming an angle that is less than 90° is known as Acute Angle.

Question 20.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 20
Answer:
Acute Angle.
Explanation:
If two rays intersect at a vertex, forming an angle that is less than 90° is known as Acute Angle.

Question 21.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 21
Answer:
Obtuse Angle.
Explanation:
Any angle that is greater than 90° but less than 180° is known as obtuse angle.

Question 22.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 22
Answer:
Right Angle.
Explanation:
If the angle formed between two rays is exactly 90° then it is called a Right Angle.

Answer the following questions by looking at the figure on the right.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 23

Question 23.
Name the center point
Answer:
Point A
Explanation:
The center of a circle is the point equidistant from the points on the edge.

Question 24.
Which segments are chords?
Answer:
\(\overline{HC}\),\(\overline{BD}\), \(\overline{BC}\), \(\overline{CD}\)
Explanation:
The chord of a circle is the line segment joining any two points on the circumference of the circle.

Question 25.
Which segment is the diameter?
Answer:
\(\overline{HG}\)
Explanation:
The diameter is the length of the line through which the center touches two points on the edge of the circle.

Question 26.
Which segments are radii?
Answer:
\(\overline{AG}\),\(\overline{AD}\), \(\overline{AH}\)
Explanation:
Radius of a circle is the distance from the center of the circle to any point on it’s circumference.

Identify the figures and fill in the missing information.

Question 27.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 24
Figure _____________
Base is _____________
Number of faces _____________
Number of edges _____________
Number of vertices _____________
Answer:
Figure is Cube,
Base is Square,
Number of faces 6,
Number of edges 12,
Number of vertices 8.
Explanation:
A Cube is a solid three-dimensional figure,
which has 6 square faces, 8 vertices and 12 edges.
Base of a cube is has four sides looks like square.
It is also said to be a regular hexahedron.

Question 28.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 25
Figure _____________
Base is _____________
Number of faces _____________
Number of edges _____________
Number of vertices _____________
Answer:
Figure is Rectangular solid,
Base is Rectangle,
Number of faces 6,
Number of edges 12,
Number of vertices 8.
Explanation:
A Rectangular solid is also known as Cuboid.
Rectangular solids are 3D shapes with six rectangle sides all meeting perpendicularly.
Number of faces of a rectangular solid are 6, edges 12 and vertices 8.

Question 29.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 26
Figure _____________
Base is _____________
Number of faces _____________
Number of edges _____________
Number of vertices _____________
Answer:
Figure is Rectangular Pyramid,
Base is Rectangle,
Number of faces 5,
Number of edges 8,
Number of vertices 5.
Explanation:
Pyramids are three-dimensional structures having triangle faces with a polygon shape at its base.
If the base of a pyramid is rectangular, then it is called a rectangular pyramid.
It has 5 faces, 8 edges and 5 vertices.

Question 30.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 27
Figure _____________
Base is _____________
Number of faces _____________
Number of edges _____________
Number of vertices _____________
Answer:
Figure is Cone,
Base is Circle,
Number of faces 1,
Number of edges – no Edges,
Number of vertices 1.
Explanation:
A Cone always passes through a fixed point  or the vertex.
Cone has circular base with no edges.
It has one circular face and one vertex (corner).

Question 31.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 28
Figure _____________
Base is _____________
Number of faces _____________
Number of edges _____________
Number of vertices _____________
Answer:
Figure is Triangular Pyramid,
Base is Triangle,
Number of faces 4,
Number of edges 6,
Number of vertices 4.
Explanation:
A triangular pyramid is a pyramid with a triangular base.
All triangular-based pyramids, either regular or irregular, have four vertices and faces.
Triangular-based pyramids have 6 edges.

Question 32.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 29
Figure _____________
Base is _____________
Number of faces _____________
Number of edges _____________
Number of vertices _____________
Answer:
Figure is Triangular Prism,
Base is Triangle,
Number of faces 5,
Number of edges 9,
Number of vertices 6.
Explanation:
A triangular prism is a polyhedron made up of two triangular bases and three rectangular sides.
It is a three-dimensional shape that has three side faces and two base faces,
connected to each other through nine edges.
Base of a triangular prism is triangle with 6 vertices.

Identify the figures.

Question 33.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 30
Answer:
Pentagon.
Explanation:
Penta denotes five and gon denotes angle.
A pentagon is a simple polygon, which has five sides and five angles.

Question 34.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 31
Answer:
Hexagon.
Explanation:
Hexa means six and gona means angles.
A hexagon is a closed two-dimensional polygon with six sides.
Hexagon has 6 vertices and 6 angles.

Question 35.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 32
Answer:
Heptagon.
Explanation:
Hepta means seven and gon means sides.
A Heptagon is a polygon with seven sides and seven angles.
It has seven straight sides and seven corners or vertices.

Question 36.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 33
Answer:
Octagon.
Explanation:
An Octagon is an 8-sided polygon, also called 8-gon, in a two-dimensional plane.
Octagon is a polygon that has 8 sides and 8 angles.
The number of vertices and edges of an octagon is 8.

Question 37.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 34
What is the circumference of the circle? (Use 3.14 for π). What is the area of the circle?
Answer:
Circumference = 18.84 cm;
Area = 28.26 sq units.
Explanation:
A = π r2
r = 3 cm
A = 3.14 x 3 x 3
A = 28.26 sq cm
The circumference of the circle (Use 3.14 for π)
C = 2πr
C = 2 x 3.14 x 3
C = 18.84 cm

Question 38.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 35
Jerome bought a present that came in a box that looked like the figure above. If he wants to wrap the present before he gives it to his sister, how much wrapping paper will he need to wrap the present?
Answer:
148 sq cm
Explanation:
TSA – Total Surface Area to be calculated
the surface area of a cuboid, add the areas of all 6 faces.
We can also label the length (l), width (w), and height (h) of the prism and use the formula,
SA = 2lw + 2lh + 2hw, to find the surface area
TSA = 2(5 x 6 + 6 x 4 + 4 x 5)
TSA = 2(30 + 24 + 20)
TSA = 2 x 74
TSA = 148 sq cm

Question 39.
McGraw Hill Math Grade 7 Unit Test Lessons 24–26 Answer Key 36
How many 1-inch cube wooden blocks can fit in the box shown in the figure?
Answer:
120 wooden blocks.
Explanation:
The formula for the volume of the cuboid can be derived from the concept explained on rectangular sheets.
Let the area of a rectangular sheet of paper be ‘A’,
the height up to which they are stacked be ‘h’ and the volume of the cuboid be ‘V’.
Then, the volume of the cuboid is given by multiplying the base area and height.
The volume of cuboid = Base area × Height
The base area for cuboid = l × b
Hence, the volume of a cuboid, V = l × b × h = lbh
Volume of a cuboid = (length × breadth × height) cubic units.
= (l × b × h) cubic units.
= (10 x 6 x 2) cubic units
= 120 cubic units

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