McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key

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McGraw-Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key

Review the graph and answer the following questions.
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 1

Question 1.
Is there more trash on the beach due to plastic or paper?
Answer:
Plastic
Explanation:
Observe the graph of Trash on Beach,
Plastic is more than paper.
Total amount of plastic is 5000 and paper less than it.

Question 2.
Which material accounts for more than twice as much trash on the beach as Styrofoam?
Answer:
Cigarettes
Explanation:
Observe the graph of Trash on Beach,
Styrofoam is around 7000,
Cigarettes is around 14000,
So, Cigarettes are as twice as much trash on the beach as Styrofoam.

Question 3.
What material accounts for the least amount of trash on the beach?
Answer:
Wood
Explanation:
Observe the graph of Trash on Beach,
The least amount of trash is wood i.e., around 2000.

Use data from the graphs to answer the following questions.
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 2

Question 4.
Which city has the highest average temperature in the summer? ____________
The lowest? ____________________________
Answer:
Highest temperature is Orlando,
Lowest temperature is Omaha.
Explanation:
The above chart shows the U.S city summer temperatures.
When compared with all the city temperatures,
Highest temperature is Orlando more than 80 °F,
Lowest temperature is Omaha below 70 °F.

Question 5.
The average temperature of Chicago is 4 degrees warmer than Cleveland, true or false? ___________
Answer:
True
Explanation:
The above chart shows the U.S city summer temperatures.
When compared with the average temperature of Chicago it is 4 degrees warmer than Cleveland.

Question 6.
Which city is cooler during the summertime, San Francisco or Milwaukee?
Answer:
San Francisco
Explanation:
The above chart shows the U.S city summer temperatures.
When compared with the average temperature of San Francisco and Milwaukee,
San Francisco is cooler during summer time.

McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 3

Question 7.
On what day did Jason practice his guitar the most? __________
The least? ___________________
Answer:
Jason practice his guitar the most on Thursday.
The least on Monday.
Explanation:
Observe the above chart of Jason’s Guitar practice schedule.
On Thursday he practiced more number of hours rather than other days.
On Monday he practiced less hours.

Question 8.
Jason practices 2.5 hours more on Thursday than on what other day?
Answer:
Monday.
Explanation:
Observe the above chart of Jason’s Guitar practice schedule.
On Thursday he practiced he practiced for 3.5 hours
On Monday he practiced for one hour.
3.5 – 1 = 2.5
So, Jason practices 2.5 hours more on Thursday than on Monday.

Question 9.
What is the total number of hours that Jason practices from Monday to Saturday?
Answer:
13\(\frac{1}{2}\) or 13.5 hours.
Explanation:
Observe the above chart of Jason’s Guitar practice schedule.
On Monday he practiced for 1 hour.
On Tuesday he practiced for 1.5 hours.
On Wednesday he practiced for 3 hours.
On Thursday he practiced for 3.5 hours.
On Friday he practiced for 2 hours.
On Saturday he practiced for 2.5 hours.
The total number of hours that Jason practices from Monday to Saturday is,
1 + 1.5 + 3 + 3.5 + 2 + 2.5 = 13.5 hours
13\(\frac{1}{2}\) hours.

McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 4

Question 10.
In what year did Rocco hit more home runs than doubles?
Answer:
2009
Explanation:
From the above given chart of Rocco’s Baseball Statistics,
Rocco hit more home runs than doubles in 2006.

Question 11.
One year, Rocco injured his leg sliding into second base and missed some games while he recovered. What year do you think that was?
Answer:
2006
Explanation:
From the above given chart of Rocco’s Baseball Statistics,
In 2006 his score is less than compared with other years.
So, Rocco injured his leg sliding into second base and missed some games while he recovered.

Question 12.
Fredo is planning the menu for his restaurant. He conducted a survey of restaurant guests and converted that information into a circle graph. Based on the data, what is the most popular type of entree that Fredo’s restaurant serves?
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 5
Answer:
Chicken
Explanation:
The above chart shows the Meal Entree Orders of Fredo’s Restaurant.
The most popular type of entree that Fredo’s restaurant serves is chicken.

Question 13.
Based on the data, which is more popular as an entree, fish or meat?
Answer:
Fish
Explanation:
The above chart shows the Meal Entree Orders of Fredo’s Restaurant.
When compared with the fish or meat serves in the entree of Fredo’s restaurant is Fish.

Question 14.
Fredo would like to add more vegetarian entrees, but he won’t until at least 10% of the patrons want them. Should Fredo add more vegetarian entrees, and why?
Answer:
Yes, 17% ordered vegetarian meals.
Explanation:
The above chart shows the Meal Entree Orders of Fredo’s Restaurant.
Yes, Fredo would add more vegetarian entrees,
because 17% ordered vegetarian meals.

Question 15.
Look at the following data group: 2, 3, 5, 8, 8, 9, 16, 24, 28, 40, 44
What is the median of the data group? ____________________
What is the mean? ______________________
What is the range? ____________________
Answer:
Median = 9
Mean = 17
Range = 42
Explanation:
First Range of data is the difference between the highest and the lowest values of the data
data group: 2, 3, 5, 8, 8, 9, 16, 24, 28, 40, 44
Range = 44 – 2 = 42
Mean:
Find the sum of the values by adding them all up.
Divide the sum by the number of values in the data set.
Mean = \(\frac{2+3+5+8+8+9+16+24+28+40+44}{11}\)
= \(\frac{187}{11}\) = 17
Median:
 First, arrange the given data in ascending order.

Next, we need to pick the middlemost data.
For the odd number of data points, there is only one middle data point,
we can take it as the median of the data as 9 as rounded shown in the

Question 16.
Put the following data into a stem-and-leaf plot:
19, 22, 22, 25, 26, 27, 28, 30, 34, 36, 37, 44, 44, 44, 45, 48, 48, 49, 50, 53, 55, 57, 58, 64, 67
What is the mode of the set of data? ___________________
What is the median? ___________________
What is the mean? ___________________
Answer:
Mode = 44
Median = 44
Mean = 41.3
Explanation:
a stem-and-leaf plot:

The mode is the number or numbers that occur the most frequently.
44 is occur most frequently
as per the above stem leaf plot
mode of the above data is 44
Median:
 First, arrange the given data in ascending order.

Next, we need to pick the middlemost data.
For the odd number of data points, there is only one middle data point,
we can take it as the median of the data as 44 as rounded shown in the
Mean:
Find the sum of the values by adding them all up.
Divide the sum by the number of values in the data set.
Mean = \(\frac{19, 22, 22, 25, 26, 27, 28, 30, 34, 36, 37, 44, 44, 44, 45, 48, 48, 49, 50, 53, 55, 57, 58, 64, 67}{25}\)
= \(\frac{1032}{25}\) = 41.3

Question 17.
What is the approximate range of the third quartile?
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 6
What is the median of the data? ___________________
What is the range of the data? ___________________
Answer:
Third quartile range = 14
Median = 22
Range of data = 45
Explanation:

First Range of data is the difference between the highest and the lowest values of the data
max – min = 50 – 5 = 45
Median = 22 is the Q2 center of the data given in the picture
Third quartile range = Q3 – Q2 = 36 – 22 = 14

Question 18.
How many of the outcomes in this tree diagram result in having less than two tails?
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 7
Answer:
4
Explanation:

Less then two tails combination are rounded in the above picture, total 4 combinations are identified

Question 19.
James conducted a survey of students in his class. He found that out of the 50 people he surveyed, 35 used a backpack to carry their books and 28 carried calculators. If 13 students carried a calculator and a backpack, how many students carry only a backpack?
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 8
Fill in the Venn Diagram to model the problem.
Answer:
22

Explanation:
As in the above venn diagram yellow circle 22 students used backpack to carry their books.
A Venn diagram is an illustration that uses circles to show the relationships among things or finite groups of things. Circles that overlap have a commonality while circles that do not overlap do not share those traits. Venn diagrams help to visually represent the similarities and differences between two concepts.

Question 20.
What does this Venn Diagram tell you?
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 9
Answer:
7 people liked both volleyball and football;
47 people in total were surveyed;
20 people liked only volleyball and
20 people only liked football.
Explanation:
As in the above venn diagram
7 people liked both volleyball and football;
47 people in total were surveyed;
20 people liked only volleyball and
20 people only liked football.
A Venn diagram is an illustration that uses circles to show the relationships among things or finite groups of things. Circles that overlap have a commonality while circles that do not overlap do not share those traits.

Question 21.
You have a bag of 20 markers, 5 of which are green, 3 of which are red, 7 of which are yellow, 3 of which are blue, and 2 of which are orange. What is the chance of reaching into the bag and pulling out a yellow marker? _________________
Anything but a green marker? _________________
Answer:
Yellow marker \(\frac{7}{20}\);
Green marker \(\frac{15}{20}\) or \(\frac{3}{4}\)
Explanation:
First sample space ={5(green)+3(red)+7(yellow)+3(blue)+2(orange)} = 20 markers,
means if we pic one marker we can get either of the 5 of which are green, 3 of which are red, 7 of which are yellow, 3 of which are blue, and 2 of which are orange marker.
the chance of reaching into the bag and pulling out a yellow marker is the probability of yellow marker
Yellow marker = \(\frac{7}{20}\)
any market except Green marker = all markers – green markers divided by total markers
= \(\frac{20 – 5}{20}\)
= \(\frac{15}{20}\) or \(\frac{3}{4}\)

Question 22.
A grocery store did a taste test of 3 brands of cookies. In a random survey of 50 people walking down the street in front of the store, 20 people said they preferred Brand A, 14 people preferred Brand B, and 16 people preferred Brand C. Which of the following is the most valid conclusion?
(a) The grocery store should stop selling Brand B.
(b) Brands B and C have roughly the same popularity.
(c) Brand A is twice as popular as Brand B.
Answer:
B
Explanation:
A taste test of 3 brands of cookies in a random survey of 50 people walking down the street in front of the store, 20 people said they preferred brand A,
14 people preferred brand B,
and 16 people preferred brand C
brands B and C have roughly the same popularity.

Question 23.
Find the mean absolute deviation for the values below.
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 10
Answer:
MAD = 8
Explanation:
Average = \(\frac{sum of the scores}{number of the scores}\)
= \(\frac{84 + 68 + 92 + 76}{4}\)
= \(\frac{320}{4}\) = 80
finding the difference between score and average score
I 84 – 80 I = 4
I 68 – 80 I = 12
I 92 – 80 I = 12
I 76 – 80 I = 4
average of the differences,
= \(\frac{4 + 12 + 12 + 4}{4}\)
= \(\frac{32}{4}\) = 8
mean absolute deviation (MAD) = 8.

Question 24.
Andy did a random survey to find out what type of pet is most popular in his town. 17 people chose dogs, 18 people chose cats, and 6 people chose fish. Complete the probability model.
McGraw Hill Math Grade 7 Unit Test Lessons 21–23 Answer Key 11
Answer:

Explanation:
The probability model total samples are 17 + 18 + 6 = 41
probability of 17 people chose dogs out of 41 samples is
P(Dog) = \(\frac{Number of Dogs}{total samples}\)
= \(\frac{17}{41}\)
= 0.41
probability of 18 people chose cats out of 41 samples is
P(Dog) = \(\frac{Number of Cats}{total samples}\)
= \(\frac{18}{41}\)
= 0.44
probability of 6 people chose dogs out of 41 samples is
P(Dog) = \(\frac{Number of fish}{total samples}\)
= \(\frac{6}{41}\)
= 0.15

Question 25.
Alex rolls a pair of six-sided dice. What is the probability that he will roll a 2 and a 6?
Answer:
\(\frac{1}{36}\)
Explanation:
Alex rolls a pair of six-sided dice,
Probability of two dies with 6 sides.
6 x 6 = 36 samples
only one time we can see the combination that he will roll a 2 and a 6
as all combinations are given below.

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