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McGraw-Hill Math Grade 7 Answer Key Lesson 7.2 Multiply Fractions: Reciprocals
Exercises Multiply
Question 1.
\(\frac{1}{2}\) × \(\frac{2}{3}\)
Answer:
\(\frac{1}{3}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{1}{2}\) × \(\frac{2}{3}\)
= \(\frac{1 X 2}{2 X 3}\)
= \(\frac{2}{6}\)
= \(\frac{1}{3}\)
Question 2.
\(\frac{5}{7}\) × \(\frac{3}{8}\)
Answer:
\(\frac{15}{56}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{5}{7}\) × \(\frac{3}{8}\)
= \(\frac{5 X 3}{7 X 8}\)
= \(\frac{15}{56}\)
Question 3.
\(\frac{20}{21}\) × \(\frac{2}{5}\)
Answer:
\(\frac{8}{21}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{20}{21}\) × \(\frac{2}{5}\)
= \(\frac{20 X 2}{21 X 5}\)
= \(\frac{40}{105}\)
= \(\frac{8}{21}\)
Question 4.
–\(\frac{3}{2}\) × \(\frac{3}{2}\)
Answer:
–\(\frac{9}{4}\) or -2\(\frac{1}{4}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{3}{2}\) × \(\frac{3}{2}\)
= –\(\frac{3 X 3}{2 X 2}\)
= –\(\frac{9}{4}\)
= -2\(\frac{1}{4}\)
Question 5.
\(\frac{2}{3}\) × \(\frac{3}{2}\)
Answer:
1
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{2}{3}\) × \(\frac{3}{2}\)
= \(\frac{2 X 3}{3 X 2}\)
= \(\frac{6}{6}\)
= 1
Question 6.
–\(\frac{7}{4}\) × \(\frac{16}{3}\)
Answer:
–\(\frac{28}{3}\) or -9\(\frac{1}{3}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{7}{4}\) × \(\frac{16}{3}\)
= –\(\frac{7 X 16}{2 X 3}\)
= –\(\frac{112}{6}\)
= –\(\frac{28}{3}\)
= -9\(\frac{1}{3}\)
Question 7.
\(\frac{5}{9}\) × \(\frac{90}{10}\)
Answer:
5
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{5}{9}\) × \(\frac{90}{10}\)
= \(\frac{5 X 90}{9 X 10}\)
= \(\frac{450}{90}\)
= 5
Question 8.
\(\frac{4}{7}\) × \(\frac{3}{28}\)
Answer:
\(\frac{3}{49}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{4}{7}\) × \(\frac{3}{28}\)
= \(\frac{4 X 3}{7 X 28}\)
= \(\frac{12}{196}\)
= \(\frac{3}{49}\)
Question 9.
\(\frac{3}{11}\) × \(\frac{11}{3}\)
Answer:
1
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{3}{11}\) × \(\frac{11}{3}\)
= \(\frac{3 X 11}{11 X 3}\)
= \(\frac{33}{33}\)
= 1
Question 10.
\(\frac{12}{13}\) × \(\frac{39}{2}\)
Answer:
18
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{12}{13}\) × \(\frac{39}{2}\)
= \(\frac{12 X 39}{13 X 2}\)
= \(\frac{468}{26}\)
=18
Question 11.
–\(\frac{3}{8}\) × –\(\frac{2}{13}\)
Answer:
\(\frac{3}{52}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{3}{8}\) × –\(\frac{2}{13}\)
= \(\frac{3 X 2}{8 X 13}\)
= \(\frac{6}{104}\)
= \(\frac{3}{52}\)
Question 12.
\(\frac{7}{8}\) × \(\frac{16}{3}\)
Answer:
\(\frac{14}{3}\) or 4\(\frac{2}{3}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{7}{8}\) × \(\frac{16}{3}\)
= \(\frac{7 X 16}{8 X 3}\)
= \(\frac{112}{24}\)
= \(\frac{14}{3}\)
= 4\(\frac{2}{3}\)
Question 13.
–\(\frac{81}{7}\) × –\(\frac{1}{9}\)
Answer:
\(\frac{9}{7}\) or 1\(\frac{2}{7}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{81}{7}\) × –\(\frac{1}{9}\)
= \(\frac{81 X 1}{7 X 9}\)
= \(\frac{81}{63}\)
= \(\frac{9}{7}\)
= 1\(\frac{2}{7}\)
Question 14.
\(\frac{7}{3}\) × \(\frac{3}{14}\)
Answer:
\(\frac{1}{2}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{7}{3}\) × \(\frac{3}{14}\)
= \(\frac{7 X 3}{3 X 14}\)
= \(\frac{21}{42}\)
= \(\frac{1}{2}\)
Question 15.
\(\frac{15}{16}\) × \(\frac{3}{5}\)
Answer:
\(\frac{9}{16}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{15}{16}\) × \(\frac{3}{5}\)
= \(\frac{15 X 3}{16 X 5}\)
= \(\frac{45}{80}\)
= \(\frac{9}{16}\)
Question 16.
\(\frac{10}{13}\) × \(\frac{52}{7}\)
Answer:
\(\frac{40}{7}\)or 5\(\frac{5}{7}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{10}{13}\) × \(\frac{52}{7}\)
= \(\frac{10 X 52}{7 X 7}\)
= \(\frac{520}{49}\)
= \(\frac{40}{49}\)
= 5\(\frac{5}{7}\)