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Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 3.1 Dividing Whole Numbers existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 3.1 Dividing Whole Numbers

Exercises Divide and Round To the nearest Hundredth

Question 1.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 395 and divisor is 7. Divide 395 by 7 the quotient is equal to 56.427 and remainder is 4.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 7 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 56.43.

Question 2.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 950 and divisor is 21. Divide 950 by 21 the quotient is equal to 45.238 and remainder is 2.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 8 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 45.24.

Question 3.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 9475 and divisor is 12. Divide 9475 by 12 the quotient is equal to 789.583 and remainder is 4.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 3 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 789.58.

Question 4.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 18980 and divisor is 36. Divide 18980 by 36 the quotient is equal to 527.222 and remainder is 8.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 2 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 527.22.

Question 5.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 8317 and divisor is 13. Divide 8317 by 13 the quotient is equal to 639.769 and remainder is 3.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 9 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 639.77.

Question 6.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 2000 and divisor is 44. Divide 2000 by 44 the quotient is equal to 45.454 and remainder is 24.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 4 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 45.45.

Question 7.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 256 and divisor is 3. Divide 256 by 3 the quotient is equal to 85.333 and remainder is 1.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 3 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 85.33.

Question 8.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 801 and divisor is 22. Divide 801 by 22 the quotient is equal to 36.409 and remainder is 2.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 9 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 36.41.

Question 9.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 788 and divisor is 14. Divide 788 by 14 the quotient is equal to 56.285 and remainder is 10.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 5 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 56.29.

Question 10.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 15412 and divisor is 16. Divide 15412 by 16 the quotient is equal to 963.25 and remainder is 0.

Question 11.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 40477 and divisor is 41. Divide 40477 by 41 the quotient is equal to 987.243 and remainder is 37.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 3 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 987.24.

Question 12.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 3041 and divisor is 37. Divide 3041 by 37 the quotient is equal to 82.189 and remainder is 7.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 9 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 82.19.

Question 13.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 9503 and divisor is 45. Divide 9503 by 45 the quotient is equal to 211.177 and remainder is 35.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 7 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 211.18.

Question 14.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 477 and divisor is 13. Divide 477 by 13 the quotient is equal to 36.692 and remainder is 13.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 2 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 36.69.

Question 15.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 4655 and divisor is 32. Divide 4655 by 32 the quotient is equal to 145.468 and remainder is 24.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 8 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 145.47.

Question 16.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 13183 and divisor is 89. Divide 13183 by 89 the quotient is equal to 148.123 and remainder is 53.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 3 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 148.12.

Question 17.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 4442 and divisor is 7. Divide 4442 by 7 the quotient is equal to 634.571 and remainder is 3.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 1 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 634.57.

Question 18.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 10602 and divisor is 11. Divide 10602 by 11 the quotient is equal to 963.818 and remainder is 1.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 8 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 963.82.

Question 19.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 13501 and divisor is 14. Divide 13501 by 14 the quotient is equal to 964.357 and remainder is 2.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 7 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 964.36.

Question 20.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 1444 and divisor is 32. Divide 1444 by 32 the quotient is equal to 45.125 and remainder is 0.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 5 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 45.13.

Question 21.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 2983 and divisor is 38. Divide 2983 by 38 the quotient is equal to 78.5 and remainder is 0.

Question 22.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 257 and divisor is 3. Divide 257 by 3 the quotient is equal to 85.666 and remainder is 2.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 6 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 85.67.

Question 23.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 1039 and divisor is 11. Divide 1039 by 11 the quotient is equal to 94.454 and remainder is 6.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 4 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 94.45.

Question 24.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 1484 and divisor is 33. Divide 1484 by 33 the quotient is equal to 44.969 and remainder is 23.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 9 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 44.97.

Question 25.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 2677 and divisor is 41. Divide 2677 by 41 the quotient is equal to 65.292 and remainder is 28.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 2 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 65.29.

Question 26.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 733 and divisor is 8. Divide 733 by 8 the quotient is equal to 91.625 and remainder is 0.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 5 which is greater than or equal to 5. So, we need to add 1 to the hundredths place in order to round it to the nearest hundredth. Finally after rounding the quotient will be 91.63.

Question 27.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 166 and divisor is 12. Divide 166 by 12 the quotient is equal to 13.833 and remainder is 4.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 3 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 13.83.

Question 28.

Answer:

Explanation:
Perform division operation on above two numbers. Here dividend is 11616 and divisor is 74. Divide 11616 by 74 the quotient is equal to 156.972 and remainder is 72.
We have to consider the thousandths place value when we are rounding quotient to the nearest hundredth.
We can see thousandths place value is 2 which is less than 5. So, we need to remove the digit. Finally after rounding the quotient will be 156.97.

Question 29.
A tailor can repair about 20 garments in a day. How many days will it take him to repair 300 garments?
Answer:
20 garments = 1 day
300 garments = ? days
(300 x 1)/20 = 15 days
To repair 300 garments a tailor can take 15 days.

Question 30.
Ms. Bailey is making information packets for all attendees at an education seminar. Each packet contains a total of 28 pages. If Ms. Bailey uses 1,400 sheets of paper, how many people plan to attend the education seminar?
Answer:
Given,
Ms. Bailey is making information packets for all attendees at an education seminar.
Each packet contains a total of 28 pages.
Ms. Bailey uses 1,400 sheets of paper
1400 ÷ 28 = 50

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 23.1 Calculating Probabilities existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 23.1 Calculating Probabilities

Exercises

CALCULATE

Question 1.
If there are 4 girls and 8 boys in a gym class, what is the probability of picking a girl as the person to lead the exercises?
Answer:
\(\frac{4}{12}\) = \(\frac{1}{3}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
P = \(\frac{f}{o}\)
= \(\frac{4}{4+8}\)
= \(\frac{4}{12}\)
= \(\frac{1}{3}\)

Question 2.
In a deck of 52 cards, what is the probability of drawing a king from the deck?
Answer:
\(\frac{4}{52}\) = \(\frac{1}{13}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
P = \(\frac{f}{o}\)
In a deck of 52 cards, there are 4 kings,
possible out comes 4 out of 52
= \(\frac{4}{52}\)
= \(\frac{1}{13}\)
Question 3.
There are 4 pizzas: 2 cheese, 1 vegetable and 1 everything. What is the probability that if you open a box it will be a cheese pizza?
Answer:
\(\frac{2}{4}\) = \(\frac{1}{2}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
P = \(\frac{2}{4}\)
P = \(\frac{1}{2}\)

Question 4.
George is 1 of 5 white horses that is in a group of 15 horses in total. If you see a white horse, what is the probability that it is George?
Answer:
\(\frac{1}{5}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
o = 5 white horse
f = George is one of white horse
P = \(\frac{1}{5}\)
Question 5.
You have change in your pocket: 5 quarters, 3 dimes, 2 nickels, and 4 pennies. If you pull a coin out of your pocket, what is the probability that it will be a dime?
Answer:
\(\frac{3}{14}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
5 quarters, 3 dimes, 2 nickels, and 4 pennies total 14 coins
the probability that it will be a dime
P = \(\frac{f}{o}\)
P = \(\frac{3}{5 + 3 + 2 + 4}\)
P = \(\frac{3}{14}\)

Question 6.
There are 3 different prizes at the fair: 1 first prize of $100, 3 second prizes of $50, and 5 third prizes of $10. If there are 35 participants in the contest, what is the probability that you will win a prize?
Answer:
\(\frac{9}{35}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
f = 1 + 3 + 5 = 9 prizes
o = 35 participants
P = \(\frac{f}{o}\)
= \(\frac{9}{35}\)

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 23.2 Probability Models existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 23.2 Probability Models

Exercises

SOLVE

Question 1.
Complete the probability model.

Answer:

Explanation:
A probability model is a chart or table that shows the different out comes possible for an event and their relative probabilities.

Question 2.
If Lynda plays one more game. what is the approximate probability that the game will end in a draw?
Answer:
0.59
Explanation:

Question 3.
If Lynda plays 7 more games and wins them all, how does that change her probability model?

Answer:

Explanation:
A probability model is a chart or table that shows the different out comes possible for an event and their relative probabilities.

Question 4.
What is the probability that a game will end in a draw now?
Answer:
0.55
Explanation:
A probability model is a chart or table that shows the different out comes possible for an event and their relative probabilities.

Question 5.
Based on the new model, how many times more likely is Lynda to win than to lose?
Answer:
Two times.
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P
P = \(\frac{f}{o}\)
P = \(\frac{30}{97}\)
P = \(\frac{14}{97}\)
2 times more likely is Lynda to win than to lose.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 23.3 Probability of Compound Events existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 23.3 Probability of Compound Events

Exercises

CALCULATE

Question 1.
Zane rolls a six-sided die twice. What is the probability that he will roll a 3 and then a 4?
Answer:
\(\frac{1}{36}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
P = \(\frac{f}{o}\)
= \(\frac{1}{36}\)

Question 2.
Marisa draws a coin from a box that contains 7 quarters, 5 dimes, 10 nickels, and 8 pennies. After looking at the coin, she puts it back and draws another. What is the probability that the coins she drew were a dime and then a penny?
Answer:
\(\frac{2}{45}\)
Explanation:
There is a formula to figure out probability (P)
It is the number of favorable out comes (f) divided by the total number of all possible outcomes (o).
In mathematical terms P = \(\frac{f}{o}\)
a box that contains 7 quarters, 5 dimes, 10 nickels, and 8 pennies
7 + 5 + 10 + 8 = 30
P = \(\frac{f}{o}\)
= \(\frac{2}{45}\)

Question 3.
Mrs. Castanon chose two students’ names from a hat (she chose the second name without replacing the first name). There are 30 students in her class. What is the probability that she chose John and then Nicholle?
Answer:
\(\frac{1}{870}\)
Explanation:
Probability of choosing John = \(\frac{1}{30}\)
Remaining names of students in the hat = 30 – 1 = 29
Probability of choosing Nicholle = \(\frac{1}{29}\)
Total probability of choosing Jhon and Nicholle = \(\frac{1}{30}\) x \(\frac{1}{29}\)
The probability that Castanon chose John and then Nicholle = \(\frac{1}{870}\)

Question 4.
Lori and Sergio love lollipops. At the same time, they each take one lollipop from a bag containing 8 cherry, 4 orange, and 7 grape lollipops. What is the probability that they both got an orange one?
Answer:
\(\frac{2}{57}\)
Explanation:
Total number of lollipops = 8 + 4 + 7 = 19
Number of orange lollipops = 4
number of orange lollipops taken = 2
Probability of Lori choosing an orange lollipop = \(\frac{4}{19}\)
Remaining number of orange lollipops in the bag = 4 – 1 = 3
Probability of Lori choosing an orange lollipop = \(\frac{3}{18}\)
the probability that they both got an orange lollipop = \(\frac{4}{19}\) x \(\frac{3}{18}\)
= \(\frac{2}{57}\)

Question 5.
Kalee and Nick are choosing two different movies to watch. In their collection, they have 10 sci-fi movies, 12 comedies, and 5 dramas. If Kalee chooses the first movie at random and then Nick chooses the second movie at random, what is the probability that they both choose sci-fi movies?
Answer:
\(\frac{5}{39}\)
Explanation:
Total number of movies = 10 + 12 + 5 = 27
Number of sci-fi movies = 10
Probability of choosing an sci-fi movies = \(\frac{10}{27}\)
Remaining number of sci-fi movies = 10 – 1 = 9
Probability of choosing a sci-fi movie = \(\frac{9}{26}\)
the probability that they both got an orange lollipop = \(\frac{10}{27}\) x \(\frac{9}{26}\)
= \(\frac{5}{39}\)

Question 6.
Amee wants to make a simulation to help her find the probability that there will be one girl and one boy from her class chosen for student council, if two students in the class are chosen at random. How can she design her simulation?
Answer:
Answer may vary.
Explanation:
Probability is about estimating or calculating how likely or ‘probable’ something is to happen.
Amee should use black squares of paper to represent the number of boys,
and white squares of paper to represent the number of girls.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.7 Mean Absolute Deviation existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.7 Mean Absolute Deviation

Exercises

CALCULATE

Sarah and Sadie recorded the numbers of points they scored in each of 5 basketball games.

Question 1.
What is Sarah’s average?
Answer:
4.6
Explanation:
Average = \(\frac{sum of the scores}{number of the scores}\)
= \(\frac{4 + 6 + 5 + 4 + 4}{5}\)
= \(\frac{23}{5}\) = 4.6

Question 2.
What is Sadie’s average?
Answer:
4
Explanation:
Average = \(\frac{sum of the scores}{number of the scores}\)
= \(\frac{3 + 7 + 2 + 6 + 2}{5}\)
= \(\frac{20}{5}\) = 4

Question 3.
What is the mean absolute deviation for Sarah’s scores?
Answer:
mean = 0.72
Explanation:
Sarah’s scores
Average = \(\frac{sum of the scores}{number of the scores}\)
= \(\frac{4 + 6 + 5 + 4 + 4}{5}\)
= \(\frac{23}{5}\) = 4.6
finding the difference between score and average score
I 4 – 4.6 I = 0.6
I 6 – 4.6 I = 1.4
I 5 – 4.6 I = 0.4
I 4 – 4.6 I = 0.6
I 4 – 4.6 I = 0.6
average of the differences =
= \(\frac{0.6 + 1.4 + 0.4 + 0.6 + 0.6}{5}\)
= \(\frac{3.6}{5}\) = 0.72
mean absolute deviation (MAD) = 0.72

Question 4.
What is the mean absolute deviation for Sadie’s scores?
Answer:
mean = 2
Explanation:
Sarah’s scores
Average = \(\frac{sum of the scores}{number of the scores}\)
= \(\frac{3 + 7 + 2 + 6 + 2}{5}\)
= \(\frac{20}{5}\) = 4
finding the difference between score and average score
I 3 – 4 I = 1
I 7 – 4 I = 3
I 2 – 4 I = 2
I 6 – 4 I = 2
I 2 – 4 I = 2
average of the differences,
= \(\frac{1 + 3 + 2 + 2 + 2}{5}\)
= \(\frac{10}{5}\) = 2
mean absolute deviation (MAD) = 2.

Question 5.
How many times greater is the mean absolute deviation of Sadie’s scores than for Sarah’s scores?
Answer:
1.28
Explanation:
the mean absolute deviation of Sadie’s score
mean absolute deviation (MAD) = 2
the mean absolute deviation of Sarah’s score
mean absolute deviation (MAD) = 0.72
The mean absolute deviation of Sadie’s scores than for Sarah’s scores difference,
= 2.0 – 0.72
= 1.28

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.6 Sampling existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.6 Sampling

Exercises

EVALUATE

Question 1.
To predict who will become the next president of the United States, a news organization asked people leaving voting sites around the country who they had just voted for. Who is the population in this situation? What is the sample group in this situation?
Answer:
All the voters in the United States;
People who voted at certain voting sites.
Explanation:
A sample is a group with in the larger population surveys or poll are done on just a sample of the population, and the results are projected on to the larger population.
As whole for the conclusions drawn to be valid the sample must be representative of the population.
To predict who will become the next president of the United States,
a news organization asked people leaving voting sites around the country who they had just voted.
The population in this situation is voters in the United States;
People who voted at certain voting sites are the sample group in this situation.

Question 2.
The high school principle wants to find out which elective class the 200 students at her school prefer. Which sampling method should she use?
(a) ask all the students in the chess club
(b) ask all the seniors
(c) ask the first 25 students in an alphabetical list of all the students
Answer:
Option(C)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
The high school principle wants to find out which elective class the 200 students at her school prefer,
ask the first 25 students in an alphabetical list of all the students.

Question 3.
Kai has a giant bag of red, yellow, and blue marbles. He wants to find out approximately what percent are blue, but doesn’t want to count every marble in the bag. Which sampling method should he use?
(a) Shake up the bag, pull out 30 marbles, and see how many are blue.
(b) Reach into the bag and grab the biggest marbles he can feel.
(c) Pull out three marbles from the top of the bag and see how many are blue.
Answer:
Option(A)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
To find out approximately what percent are blue,
but doesn’t want to count every marble in the bag,
Shake up the bag, pull out 30 marbles, and see how many are blue.

Question 4.
Mrs. Webster is the coordinator for the school field trip and is trying to decide between a trip to the museum or a trip to the zoo. She decides to do a survey of some of the students about their preference. Who should she survey?
(a) 30 students chosen at random by the office computer
(b) all the girls in the school
(c) the first 30 students to arrive at school
Answer:
Option(A)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
Mrs. Webster is the coordinator for the school field trip and is trying to decide between a trip to the museum or a trip to the zoo.
She decides to do a survey of some of the students about their preference 30 students chosen at random by the office computer.

Question 5.
In a random sampling of 100 fish caught in a fishing net in a river, there were 39 trout, 19 flounder, and 42 perch. Which of the following is the most valid conclusion?
(a) Perch is the most common fish in the river.
(b) The river has about twice as many perch and trout as it does flounder.
(c) There are only three kinds of fish in the river.
Answer:
Option(B)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
In a random sampling of 100 fish caught in a fishing net in a river,
there were 39 trout, 19 flounder, and 42 perch,
the river has about twice as many perch and trout as it does flounder.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.5 Venn Diagrams existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.5 Venn Diagrams

Exercises

DIAGRAM

Question 1.
This Venn Diagram represents numbers that are even and numbers that are divisible by the variable b. What does their intersection represent?

Answer:
Numbers that are even and divisible by b.
Explanation:
The above Venn Diagram represents the numbers of even and odd numbers,
pink circle represents even numbers and blue circle is divisible by b numbers.
The intersecting point in mid is even numbers of divisible by b.

Question 2.
Make a Venn Diagram of people who are kickball fans, and people who are baseball fans. The only person that is a fan of both is your friend Kelsey.

Answer:

Explanation:
The above Venn Diagram represents people who are kickball fans and baseball fans.
The intersecting point between these two circles is fans who likes both the kickball and baseball,
a fan of both is your friend Kelsey.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.4 Tree Diagrams existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.4 Tree Diagrams

Exercises

INTERPRET AND CREATE

Question 1.
The tree diagram at the right illustrates the outcomes when you choose two balls from a bag that contains a large number of red, white, and green balls. How many of these outcomes result in you not choosing at least 1 white ball? How many of these outcomes result in you choosing both a red ball and a green ball?

Answer:
4-Red and 2-Green,
Explanation:
Number of outcomes result in not choosing at least 1 white ball,
total there are 9 out comes.
Out of 9 out comes 4 out comes are with out white ball.

Number of outcomes result in choosing both a red ball and a green ball.
Green Red balls and Red and Green balls as shown below.

Question 2.
Draw a tree diagram to describe the following situation: You go to the ice cream store and you have a choice of vanilla, chocolate, or strawberry ice cream. On your ice cream, you can get either nuts or sprinkles.
Answer:

Explanation:
A tree diagram is a tool in the fields of general mathematics, probability, and statistics,
that helps calculate the number of possible outcomes of an event or problem.
The ice cream store have a choice of
vanilla (V) ice cream, chocolate (C) ice cream, or strawberry (S) ice cream.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.3 Box-and-Whisker Plots existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.3 Box-and-Whisker Plots

Exercises

INTERPRET

Question 1.
Which of the three classes has the widest range of scores? The smallest range?

Widest Range ______________
Smallest Range _______________
Answer:
Widest Range is Botany.
Smallest Range is Zoology.
Explanation:
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
The lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.
Widest Range is Botany.
Smallest Range is Zoology.

Question 2.
Which class has the highest median score?
Answer:
Zoology
Explanation:

The highest median score is zoology.
Box – and – Whisker plot
which allows us to quickly look at data to tell where most of the numbers lie.
The lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.

Make a box-and-whisker plot with the following data:
Minimum – 15
Q1 – 25
Q2 – 35
Q3 – 45
Maximum – 55
Explanation:

Lower extreme(Minimum) – 15
Q1 – 25
Q2 – 35
Q3 – 45
Upper extreme(Maximum) – 55
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
the lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.
Question 3.
What is the range of this plot? The median?
Range _______________
Median _______________
Answer:
Range = 40;
median = 35.
Explanation:
Lower extreme(Minimum) – 15
Q1 – 25
Q2 – 35
Q3 – 45
Upper extreme(Maximum) – 55
Range =Upper extreme(Maximum) – Lower extreme(Minimum) = 55 -15 = 40
median = (Q3 + Q1)/2
= (45 + 25)/2 = 35
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
the lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.

Question 4.
What is the lower quartile? The upper quartile?
Lower Quartile _______________
Upper Quartile _______________
Answer:
Lower Quartile 15-25
Upper Quartile 45-55
Explanation:
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
the lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.
Lower Quartile 15-25
Upper Quartile 45-55

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.2 Stem-and-Leaf Plots existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.2 Stem-and-Leaf Plots

Exercises

INTERPRET

Question 1.
What is the range of the numbers represented in the stem-and-leaf plot below?

Answer:
Range = 80
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
Range is the difference between,
First row Stem 9 Leaf 6,
Last row Stem 1 leaf 1.
So, the range of the numbers represented in the stem-and-leaf plot above,
96 – 16 = 80

Question 2.
Generate the number set represented by the stem-and-leaf plot below.

Answer:
10, 17, 19
21, 21, 23, 24,26, 27, 28
30, 31, 33, 35,36, 37, 37,
40, 41, 41, 41, 42
69
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
numbers written as,
Frist row stem and leaf as written below up to last stem and last leaf.
10, 17, 19
21, 21, 23, 24,26, 27, 28
30, 31, 33, 35,36, 37, 37,
40, 41, 41, 41, 42
69

Question 3.
Generate the number set represented by the stem-and-leaf plot below.

Answer:
80, 85
71, 75, 76,
51, 56, 58,
40, 46
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
numbers written as,
Frist row stem and leaf as written below up to last stem and last leaf
80, 85
71, 75, 76,
51, 56, 58,
40, 46.

Question 4.
What is the range of the numbers represented by the stem-and-leaf plot below?

Answer:
Range = 45
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
Range is the difference between,
First row Stem 2 Leaf 2,
Last row Stem 6 leaf 7.
So, the range of the numbers represented in the stem-and-leaf plot above,
67 – 22 = 45.