McGraw Hill Math

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 10 Lesson 2 Ways to Measure as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 10 Lesson 2 Ways to Measure

Measure

Write or draw your answers.

Question 1.
Find a spoon. How long is the spoon? Use a ruler.
The spoon is ______________ inches long.
Answer: The spoon is 8 inches long.

Question 2.

Which object is heavier? Circle your answer.
Answer:

The weight of pineapple is heavier than a lemon.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 10 Lesson 10 Telling Time with Digital Clocks as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 10 Lesson 10 Telling Time with Digital Clocks

Tell Time

Write the time in each clock.

Question 1.
two o’clock.
Answer:
The time with digital clock is shown below

Question 2.
one thirty

Answer:
The time with digital clock is shown below

Question 3.
eight o’clock

Answer:
The time with digital clock is shown below

Question 4.
seven o’clock

Answer:
The time with digital clock is shown below

Question 5.
five thirty

Answer:
The time with digital clock is shown below

Question 6.
three o’clock

Answer:
The time with digital clock is shown below

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 10 Lesson 1 Length and Weight as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 10 Lesson 1 Length and Weight

Measure

Write your answer.

Question 1.
Find a pen. How long ¡s the pen? Use paper clips.
The pen is ____________ paper clips long.
Answer: The pen is 6 paper clips long.

Circle the object that is heavier.

Question 2.

Answer:

The weight of dog is heavier than a frog

Question 3.

Answer:

The weight of an apple is heavier than a strawberry.

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Unit Test Lessons 7–9 to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Unit Test Lessons 7–9 Answer Key

Round to the nearest tenth.

Question 1.
3406.997
Answer:
3407.0
Explanation:
If the digit in hundredth place is greater than 5 add 1 to the nearest tenth place.
So, 3406.997 is rounded to nearest tenth place is 3407.0

Question 2.
334,782.099
Answer:
334782.1
Explanation:
If the digit in hundredth place is greater than 5 add 1 to the nearest tenth place.
So, 334782.099 is rounded to nearest tenth place is 334782.1

Question 3.
65,529.0887
Answer:
65,529.1
Explanation:
If the digit in hundredth place is greater than 5 add 1 to the nearest tenth place.
So, 65,529.0887 is rounded to nearest tenth place is 65,529.1

Round to the nearest hundredth.

Question 4.
2,467,891.3554
Answer:
2,467,891.36
Explanation:
If the digit in thousandth place is greater than 5 add 1 to the nearest hundredth place.
So, 2,467,891.3554 is rounded to nearest hundredth place as 2,467,891.36

Question 5.
97.009
Answer:
97.01
Explanation:
If the digit in thousandth place is greater than 5 add 1 to the nearest hundredth place.
So, 97.009 is rounded to nearest hundredth place 97.01

Round to the nearest ten thousandth.

Question 6.
17.99986
Answer:
17.9999
Explanation:
If the digit in lakh place is greater than 5 add 1 to the nearest ten thousandth place.
So, 17.99986 is rounded to nearest ten thousandth place 17.9999

Question 7.
99.11115
Answer:
99.1112
Explanation:
If the digit in ten thousandth place is greater than 5 add 1 to the nearest thousandth place.
So, 99.11115 is rounded to nearest thousandth place 99.1112

Identify the place value of the underlined number.

Question 8.
1,683,679.57344
Answer:
4 is in ten thousandth place.
Explanation:
In decimals place value follows immediate right to the decimal starting from tenths place,
followed by hundredth, thousand , ten thousand and so on places.
So, count the numbers after the decimal and then write the place values as explained above.

Question 9.
1,499,667.5773
Answer:
7 is in hundredth place.
Explanation:
In decimals place value follows immediate right to the decimal starting from tenths place,
followed by hundredth, thousand , ten thousand and so on places.
So, count the numbers after the decimal and then write the place values as explained above.

Convert the decimal to a fraction.

Question 10.
.8 = _____________
Answer:
\(\frac{8}{10}\)
Explanation:
Use the place value farthest to the right as denominator,
the decimal number becomes the numerator.
0.8 = \(\frac{8}{10}\)

Question 11.
.875 = _____________
Answer:
\(\frac{7}{8}\)
Explanation:
Use the place value farthest to the right as denominator,
the decimal number becomes the numerator.
0.875 = \(\frac{875}{1000}\)
simplify both numerator and denominator with 5
= \(\frac{175}{200}\)

= \(\frac{35}{40}\)

= \(\frac{7}{8}\)

Question 12.
.08 = _____________
Answer:
\(\frac{8}{100}\)
Explanation:
Use the place value farthest to the right as denominator,
the decimal number becomes the numerator.
0.08 = \(\frac{8}{100}\)

Convert the fraction to a decimal.

Question 13.
\(\frac{3}{5}\) = _____________
Answer:
0.6
Explanation:
To convert fraction into decimal divide the numerator with denominator.
\(\frac{3}{5}\) = 0.6

Question 14.
\(\frac{8}{15}\) = ______________
Answer:
0.53
Explanation:
To convert fraction into decimal divide the numerator with denominator.
\(\frac{8}{15}\) = 0.53

Question 15.
\(\frac{3}{16}\) = _______________
Answer:
0.18
Explanation:
To convert fraction into decimal divide the numerator with denominator.
\(\frac{3}{16}\) = 0.18

Put the decimals in order from least to greatest.

Question 16.
.122, .1145, .616, .6165, .513, .3132, .2126, .819
Answer:
.1145, .122, .2126, .3132, .513, .616, .6165, .819
Explanation:
First arrange the decimals  one beneath the other in their original order,
.122,
.1145,
.616,
.6165,
.513,
.3132,
.2126,
.819
Next examine each decimal writing one or more zeros to the right of the last digit.
.12200,
.11450,
.61600,
.61650,
.51300,
.31320,
.21260,
.81900
So, that all decimals will have the same number of digits.
Then order the decimals from least to the greatest.
.1145, .122, .2126, .3132, .513, .616, .6165, .819

Question 17.
.217, .0217, .0133, .0487, .1243, .20413, .5257, .05257, .05205
Answer:
.0133, .0217, .0487, .05205, .05257, .1243, .20413, .217, .5257
Explanation:
First arrange the decimals  one beneath the other in their original order,
.217,
.0217,
.0133,
.0487,
.1243,
.20413,
.5257,
.05257,
.05205
Next examine each decimal writing one or more zeros to the right of the last digit.
.21700,
.02170,
.01330,
.04870,
.12430,
.20413,
.52570,
.05257,
.05205
So, that all decimals will have the same number of digits.
Then order the decimals from least to the greatest.
.0133, .0217, .0487, .05205, .05257, .1243, .20413, .217, .5257

Add or Subtract.

Question 18.

Answer:
3.472817
Explanation:
First line up all the addends according to their place value,
then ignore the decimals and add all the whole numbers to get the sum.
Finally count the number of decimals and put in the sum.

Question 19.

Answer:
6.53518656
Explanation:
First line up all the addends according to their place value,
then ignore the decimals and add all the whole numbers to get the sum.
Finally count the number of decimals and put in the sum.

Question 20.

Answer:
6.660933
Explanation:
First line up all the addends according to their place value,
then ignore the decimals and add all the whole numbers to get the sum.
Finally count the number of decimals and put in the sum.

Question 21.

Answer:
1.91916
Explanation:
Explanation:
First line up all the decimals according to their place values,
then insert zeros in placeholders if needed to calculate.

Question 22.

Answer:
1.428711
Explanation:
Explanation:
First line up all the decimals according to their place values,
then insert zeros in placeholders if needed to calculate.

Question 23.

Answer:
2.24946656
Explanation:
Explanation:
First line up all the decimals according to their place values,
then insert zeros in placeholders if needed to calculate.

Question 24.

Answer:
$6.75
Explanation:
First line up all the addends according to their place value,
then ignore the decimals and add all the whole numbers to get the sum.
Finally count the number of decimals and put in the sum.

Question 25.

Answer:
$2.78
Explanation:
First line up all the addends according to their place value,
then ignore the decimals and add all the whole numbers to get the sum.
Finally count the number of decimals and put in the sum.

Multiply or Divide.

Question 26.

Answer:
36.297
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 27.

Answer:
2,119.175
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 28.

Answer:
$0.1068
Explanation:

Question 29.

Answer:
7.48935
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 30.

Answer:
$91.84
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 31.

Answer:
2.9768005
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 32.

Answer:
$2.3625
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 33.

Answer:
1.478625
Explanation:
multiplying by 1000 on both numbers to remove decimals,
24 x 1000 = 24000
35.487 x 1000 = 35487
After dividing count the number of decimals in divisor and place in the quotient or answer.

Question 34.

Answer:
6.38080
Explanation:
multiplying by 100000 on both numbers to remove decimals,
2.24 x 1000 = 2240
14.293 x 1000 = 14293
After dividing count the number of decimals in divisor and place in the quotient or answer.

Question 35.

Answer:
11.6956
Explanation:
multiplying by 100 on both numbers to remove decimals,
0.23 x 100 = 25
2.69 x 100 = 269
After dividing count the number of decimals in divisor and place in the quotient or answer.

Question 36.

Answer:
23.22
Explanation:
multiplying by 10000 on both numbers to remove decimals,
0.025 x 10000 = 250
0.5805 x 10000 = 5805
After dividing count the number of decimals in divisor and place in the quotient or answer.

Question 37.

Answer:
0.383135
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 38.

Answer:
234.225
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 39.

Answer:
$0.25
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 40.

Answer:
6.65405
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 41.

Answer:
$1.027
Explanation:
while multiplying decimals ignore the decimals in the factors and multiply,
then count total number of decimal places in the factors.
Starting from the right of the product count the number of places,
then put the decimal point to the left of the last place.

Question 42.
Chad and his service club collected a total of 954.75 pounds of canned food for the local animal shelter. There are 15 people in the club. If each member collected the same amount of canned food, how many pounds did each member collect?
_____________ pounds
Answer:
63.65 pounds,
Explanation:
Chad and his service club collected a total of 954.75 pounds of canned food for the local animal shelter.
There are 15 people in the club.
If each member collected the same amount of canned food,
Number of pounds did each member collect 954.75 ÷ 15 = 63.65 pounds

Question 43.
Jane went to the store to buy food for a party of 6 neighbors. For each guest, she spent $2.55 for salad, $1.75 for a cold beverage, and $1.25 for a fruit cup. How much did she spend in total to buy the food? __________________
Jane has $35. Does she have enough money to buy everything she needs? __________________
If so, then how much change will Jane get back? __________________
Answer:
Money spent to buy on food $5.55.
Yes, she has enough money to buy food.
Jane will get a change of $29.45.
Explanation:
Jane went to the store to buy food for a party of 6 neighbors.
For each guest, she spent $2.55 for salad, $1.75 for a cold beverage, and $1.25 for a fruit cup.
She spend in total to buy the food $2.55 + $1.75 + $1.25 = $5.55
Jane has $35.
Does she have enough money to buy everything she needs $35 – $5.55 = $29.45
Total change will Jane get back $35 – $5.55 = $29.45

Question 44.
Rodney runs on a cross-country course that is 2.35 miles in length. During the week he ran the course 5\(\frac{1}{2}\) times. How far did he run that week?
Answer:
12.925 miles,
Explanation:
Rodney runs on a cross-country course that is 2.35 miles in length.
During the week he ran the course 5\(\frac{1}{2}\) times
= \(\frac{11}{2}\) = 5.5
Number of miles he runs in the week = 2.35 x 5.5 = 12.925 miles

Question 45.
Stan is preparing pots for planting flowers. He has 23.5 pounds of potting soil. If Stan fills each pot with 1.35 pounds of potting soil, how many pots can he fill?
Answer:
17 pots,
Explanation:
Stan has 23.5 pounds of potting soil.
If Stan fills each pot with 1.35 pounds of potting soil,
Number of pots he fill 23.5 ÷ 1.35 = 17.407 or 17 pots

Question 46.
Billy charges 45ยข per square foot to varnish patio decks. If the patio deck he is varnishing is 220.25 square feet in area, how much should Billy charge for the job?
Answer:
9,911.25 ยข per square foot.
Explanation:
Billy charges 45ยข per square foot to varnish patio decks.
If the patio deck he is varnishing is 220.25 square feet in area,
Total amount Billy charge for the job 45 x 220.25 = 9,911.25

Question 47.
Tacy mixed cold beverages for all of the teams participating in a local baseball tournament. For each batch, she mixed 3.25 gallons of lemonade with 1.3 gallons of iced tea. If Tracy made 8\(\frac{3}{4}\) batches, how many gallons of cold beverage did she make?
______________ gallons
Answer:
39.8125 gallons.
Explanation:
For each batch, Tacy mixed 3.25 gallons of lemonade with 1.3 gallons of iced tea.
3.25 + 1.3 = 4.55
If Tracy made 8\(\frac{3}{4}\) batches,
\(\frac{35}{4}\) = 8.75 batches.
So, number of gallons of cold beverage she make 4.55 x 8.75 = 39.8125

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 12.3 Estimating Decimal Products will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 12.3 Estimating Decimal Products

Exercise Estimate

Question 1.
23.01 × 8.1
Answer: 186.381

There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 3 decimal places.
So, the product is 186.381
Estimated product is 186

Question 2.
$6.75 × 4.73
Answer: 31.9275

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is 31.9275
Estimated product is 32

Question 3.
101.51 × 4.5
Answer: 456.795

There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 3 decimal places.
So, the product is 456.795
Estimated product is 457

Question 4.
32.25 × 21.1
Answer: 680.475

There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 3 decimal places.
So, the product is 680.475
Estimated product is 680

Question 5.
$2.25 × 49.999
Answer: 112.49775

There are 5 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 5 decimal places.
So, the product is $112.49775
Estimated product is $112.5

Question 6.
.230 × 4.657
Answer: 1.07111

There are 6 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 6 decimal places.
So, the product is 1.07111
Estimated product is 1

Question 7.
10.501 × $5.43
Answer: 57.02

There are 5 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 5 decimal places.
So, the product is $57.02043
Estimated product is $57

Question 8.
45.45 × 21.21
Answer: 963.9945

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is 963.9945
Estimated product is 964

Question 9.
57.35 × .499
Answer: 28.61765

There are 5 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
Rewrite the product with 5 decimal places.
So, the product is 28.61765
Estimated product is 29

Question 10.
.867 × $19.3
Answer: $16.7331

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is $16.7331
Estimated product is $17

Question 11.
.75 × 25.43
Answer: 19.0725

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is 19.0725
Estimated product is 19

Question 12.
1.95 × 36.36
Answer: 70.902

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is 70.902
Estimated product is 71

Question 13.
23.986 × 11.111
Answer: 266.508446

There are 6 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 6 total decimals.
So, the product is 266.508446
Estimated product is 266.5

Question 14.
22.989 × $13.89
Answer: $319.31721

There are 5 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 5 total decimals.
So, the product is $319.31721
Estimated product is $320

Question 15.
1.8 × 1.982
Answer: 3.5676

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is 3.5676
Estimated product is 3.6

Question 16.
27.63 × $3.54
Answer: $97.8102

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is $97.8102
Estimated product is $98

Question 17.
10.1010 × 7.3
Answer: 73.7373

There are 5 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 5 total decimals.
So, the product is 73.7373
Estimated product is $74

Question 18.
7.75 × 4.1
Answer: 31.775

There are 3 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 3 total decimals.
So, the product is 31.775
Estimated product is 32

Question 19.
17.11 × 1.499
Answer: 25.64789

There are 5 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 5 total decimals.
So, the product is 25.64789
Estimated product is 26

Question 20.
$19.45 × 1.73
Answer: $33.6485

There are 4 decimal places in both numbers.
Ignore the decimals and complete the multiplication operation.
So, rewrite the product with 4 total decimals.
So, the product is $33.6485
Estimated product is $34

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Test are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Chapter 10 Test Answer Key

Use the diagram for exercises 1-3.

Question 1.
Identify two line segments.
Answer:
A line segment is part of a line and it has two end points.
One line segment is AB.
Second line segment is DC.

Question 2.
Identify two parallel lines.
Answer:
Parallel lines never meet and the lines are equidistant from each other.
The two parallel lines are AE and BD.

Question 3.
Identify two intersecting lines that are not perpendicular.
Answer:
The two intersecting lines that are not perpendicular are AE and CE.

Classify each angle as straight, right, obtuse, or acute. Then, use a protractor to measure each angle. You may need to extend its sides.

Question 4.

Answer:

Acute angle
Explanation:
In the above image we can observe the measured angle 22 degrees. The angle which measures less than 90 degrees is called as acute angle. So, the above angle is acute angle.

Question 5.

Answer:

Obtuse angle
Explanation:
In the above image we can observe the measured angle 164 degrees. The angle which measures greater than 90 degrees and less than 180 degrees is called as obtuse angle. So, the above angle is obtuse angle.

Question 6.

Answer:

Explanation:
In the above image we can observe the measured angle 180 degrees. The angle which measures exactly 180 degrees is called as straight angle. So, the above angle is straight angle.

Question 7.
Place a checkmark under the equilateral triangle.

Answer:

Explanation:
An equilateral triangle has three sides of equal length. In the above image we can observe four triangles, in that first triangle having three sides with a same length as 4 m. So, the above first triangle is equilateral triangle. So, placed a checkmark under the equilateral triangle.

Question 8.
Which shape is not a polygon? Place a checkmark under it.

Answer:

Explanation:
A polygon is a closed figure having finite number of line segments. In the above shapes, the third shape circle is not a polygon. Because a circle is made up of points which is equidistant from center. So, placed a checkmark under the third shape circle.

Question 9.
Place a checkmark under the trapezoid.

Answer:

Explanation:
A trapezoid has four sides and having one pair of parallel sides. In the above image we can observe four different shapes. In that first shape is trapezoid. So, placed a checkmark under the first shape trapezoid.

Find the area of each shape.

Question 10.

Answer:
Given
length = 13 m
Width = 5 m
Area of the rectangle (A) = length x width
A = 13 m x 5m
A = 65 square meters
Area of the rectangle is equal to 65 square meters.

Question 11.
a square with one side measuring 17 cm
Answer:
Given one Side of the square = 17 cm
In square all sides are equal.
Area of the square (A) = Side x Side
A = 17 cm x 17 cm
A = 289 square centimeters
Area of the square is equal to 289 square centimeters.

Find the volume of each object.

Question 12.

Answer:
Volume = length x width x height
volume = 3 mm x 3 mm x 3 mm = 27 cubic millimeters
Since the measure is in mm, the volume of the object is 27 cubic millimeters.

Question 13.

Answer:
The above object is square, so length, width and height are equal to 6 mi
Volume of the square object (V) = (length x width) x height
V = (6 mi x 6 mi) x 6 mi
V = 216 cubic mi
The volume of square object is 216 cubic mi.

Question 14.

Answer:
From the above object,
length = 16 km
Width = 9 km
Height = 4 km
Volume of the rectangular object (V) = (length x width) x height
V = (16 km x 9 km) x 4 km
V = 144 square km x 4 km
V = 576 cubic kilometers
The volume of rectangular object is 576 cubic kilometers.

Question 15.

Answer:
From the above object,
length = 27 yards
Width = 31 yards
Height = 9 yards
Volume of the rectangular object (V) = (length x width) x height
V = (27 yd x 31 yd) x 9 yd
V = 837 square yards x 9 yd
V = 7,533 cubic yards
The volume of rectangular object is 7,533 cubic yards.

Question 16.

Answer:

Explanation:
First we have to separate the given object into two solids then we have to find the volume of each solid.
Volume of one solid:
Length (l) = 16 feet
Width (w) = 8 feet
height (h) = 11 feet
Volume (v) = (l x w) x h
v = (16 ft x 8 ft) x 11 ft
v = 1,408 cubic feet
Volume of another solid:
Length (l) = 8 feet
Width (w) = 8 feet
height (h) = 11 feet
Volume (v) = (l x w) x h
v = (8 ft x 8 ft) x 11 ft
v =704 cubic feet
Now we have to add the two volumes.
1,408 cubic feet + 704 cubic feet = 2,112 cubic feet
The volume of the object is 2,112 cubic feet.

Question 17.

Answer:

Explanation:
First we have to separate the given object into two rectangular prisms then we have to find the volume of each solid.
Volume of one rectangular prism:
Length (l) = 13 cm
Width (w) = 10 cm
height (h) = 2 cm
Volume (v) = (l x w) x h
v = (13 cm x 10 cm) x 2 cm
v = 260 cubic centimeters
Volume of another rectangular prism:
Length (l) = 13 cm
Width (w) = 6 cm
height (h) = 4 cm
Volume (v) = (l x w) x h
v = (13 cm x 6 cm) x 4 cm
v = 312 cubic centimeters
Now we have to add the two volumes.
260 cubic centimeters + 312 cubic centimeters = 572 cubic centimeters
The volume of the object is 572 cubic centimeters.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Lesson 9 Measuring Volume with Unit Cubes are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 10 Lesson 9 Measuring Volume with Unit Cubes

Count

Count the cubes in each solid object. Write the volume.

Question 1.

Question 2.

Answer:
In the above object we can observe 4 rows. There are total 7 cubes in each row.
7 + 7 + 7 + 7 = 28 cubes
In one layer there are 28 cubes.
Now we have to add the number of cubes in each layer.
There are three layers in the above object.
28 + 28 + 28 = 84 cubes
The total number of cubes in the above object are 84.
Volume = length x width x height
volume = 4 in x 7 in x 3 in = 84 cubic inches
Since the measure is in inches, the volume of the object is 84 cubic inches.

Question 3.
Look at the cubes below. Write a number sentence to find the volume. Use specific units.

Answer:

Volume (V) = length x width x height
V = 3 cm x 8 cm x 2 cm
V = 48 cubic centimeters
Since the measure is in centimeters, the volume of the object is 48 cubic centimeters.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Lesson 8 Counting Unit Cubes and Volume are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 10 Lesson 8 Counting Unit Cubes and Volume

Count

Count the cubes in each object. Write the total.

Question 1.

Question 2.

Answer:

Explanation:
In the above object we can observe 3 rows. There are total 3 cubes in each row.
3 + 3 + 3 = 9 cubes
In one layer there are 9 cubes.
Now we have to add the number of cubes in each layer.
There are three layers in the above object.
9 + 9 + 9 = 27 cubes
The total number of cubes in the above object are 27.

Question 3.

Answer:

Explanation:
In the above object we can observe 3 rows. There are total 2 cubes in each row.
2 + 2 + 2 = 6 cubes
In one layer there are 6 cubes.
Now we have to add the number of cubes in each layer.
There are four layers in the above object.
6 + 6 + 6 + 6 = 24 cubes
The total number of cubes in the above object are 24.

Question 4.

Answer:

Explanation:
In the above object we can observe 2 rows. There are total 3 cubes in each row.
3 + 3 = 6 cubes
In one layer there are 6 cubes.
Now we have to add the number of cubes in each layer.
There are three layers in the above object.
6 + 6 + 6 = 18 cubes
The total number of cubes in the above object are 18.

Question 5.

Answer:

Explanation:
In the above object we can observe 5 rows. There are total 1 cubes in each row.
1 + 1 + 1 + 1 + 1 = 5 cubes
In one layer there are 5 cubes.
Now we have to add the number of cubes in each layer.
There are three layers in the above object.
5 + 5 + 5 = 15 cubes
The total number of cubes in the above object are 15.

Question 6.

Answer:

Explanation:
In the above object we can observe 4 rows. There are total 2 cubes in each row.
2 + 2 + 2 + 2 = 8 cubes
In one layer there are 8 cubes.
Now we have to add the number of cubes in each layer.
There are two layers in the above object.
8 + 8 = 16 cubes
The total number of cubes in the above object are 16.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Lesson 7 Finding the Area of a Rectangle are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 10 Lesson 7 Finding the Area of a Rectangle

Multiply

Find the area of each shape.

Question 1.

Question 2.

Answer:
The above shape is a square.
Given Side = 74.2 km
Area of the square (A) = Side x Side
A = 74.2 km x 74.2 km
A = 5,505.64 square kilometers
Area of the square is equal to 5,505.64 square kilometers.

Question 3.
A rectangle with a length of 105.7 mm and a width 66.8 mm
Answer:
Given
length = 105.7 mm
Width = 66.8 mm
Area of the rectangle (A) = length x width
A = 105.7 mm x 66.8 mm
A = 7,060.76 square millimeters
Area of the rectangle is equal to 7,060.76 square millimeters.

Question 4.

Answer:
The above shape is a square.
Given side = 64 cm
Area of the square (A) = Side x Side
A = 64 cm x 64 cm
A = 4,096 square centimeters
Area of the square is equal to 4,096 square centimeters.

Question 5.

Answer:
The above shape is rectangle.
Given
length = 81\(\frac{3}{4}\) in
Width = 47\(\frac{1}{4}\)
Convert the mixed fraction into fraction.
Length = \(\frac{327}{4}\)
Width = \(\frac{189}{4}\)
Area of the rectangle (A) = length x width
A = \(\frac{327}{4}\) x \(\frac{189}{4}\)
A = \(\frac{61803}{16}\)
Convert the fraction into mixed fraction.
A = 3862\(\frac{11}{16}\) square inches
Area of the rectangle is equal to 3862\(\frac{11}{16}\) square inches.

Question 6.
A square with a side that measures \(\frac{4}{5}\) mi
Answer:
Given side = \(\frac{4}{5}\) mi
Area of the square (A) = Side x Side
A = \(\frac{4}{5}\) mi x \(\frac{4}{5}\) mi
A = \(\frac{16}{25}\) square mi
Area of the square is equal to \(\frac{16}{25}\) square mi.

Question 7.
Which has a greater area: a rectangle that measures 15 m by 17 m or a square with a side that measures 16 m? What is the area of each plane shape?
Answer:
Given
length of the rectangle = 17 m
Width of the rectangle = 15 m
Area of the rectangle (A) = length x width
A = 17 m x 15 m
A = 255 square meters
Area of the rectangle is equal to 255 square meters.
Given
Side of a square = 16 m
Area of the square (A) = Side x Side
A = 16 m x 16 m
A = 256 square meters
Area of the square is equal to 256 square meters.
The square has the greater area.

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Lesson 6 Classifying Polygons are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 10 Lesson 6 Classifying Polygons

Identify and Classify

Identify each plane shape as regular or irregular.

Question 1.

Question 2.

Answer:
The above polygon is a pentagon. The shape of the pentagon is regular shape.

Question 3.

Answer:
The above polygon is a rhombus. The shape of the rhombus is regular shape.

The flowchart below classifies triangles and quadrilaterals. Fill in the blanks with the correct term.

Answer: