McGraw Hill Math – Page 17 – Go Math Answer Key

McGraw Hill Math Grade 6 Lesson 13.4 Answer Key Dividing Money

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 13.4 Dividing Money will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money

Exercises Divide

Question 1.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 1$
Answer: 0.450
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_1$
The quotient is $0.45

Question 2.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 2$
Answer: 2.5
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_2$
The quotient is 2.5

Question 3.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 3$
Answer: 5.589
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_3$
The quotient is 5.589

Question 4.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 4$
Answer: 34.937
Change the divisor 0.8 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_4$

Question 5.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 5$
Answer: 90.915
Change the divisor 1.07 to a whole number by moving the decimal point 2 places to the right. Then move the decimal point in the dividend the same, 2 places to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_5$

Question 6.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 6$
Answer: 8.542
Change the divisor 6.4 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_6$

Question 7.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 7$
Answer: 78.9
Change the divisor 2.3 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_7$

Question 8.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 8$
Answer: 91.1
Change the divisor 8.5 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_8$

Question 9.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 9$
Answer: 3.200
Change the divisor 65.9 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_9$

Question 10.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 10.$
Answer: 2.1
Change the divisor 64.3 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_10$

Question 11.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 11$
Answer: 96.3
Change the divisor 2.2 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_11$

Question 12.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 12$
Answer: 2.1
Change the divisor 63.2 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_12$

Question 13.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 13$
Answer: 424
Change the divisor 0.02 to a whole number by moving the decimal point 2 places to the right. Then move the decimal point in the dividend the same, 2 places to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_13$

Question 14.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 14$
Answer:8.5
Change the divisor 2.5 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_14$

Question 15.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 15$
Answer: 56.2
Change the divisor 3.7 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_15$

Question 16.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 16$
Answer: 20.1
Change the divisor 2.2 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_16$

Question 17.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 17$
Answer: 2.7
Change the divisor 5.8 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_17$

Question 18.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 18$
Answer: 2.7
Change the divisor 9.7 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_18$

Question 19.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 19$
Answer: 3.4
Change the divisor 44.9 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_19$

Question 20.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.4 Answer Key Dividing Money 20$
Answer: 8.1
Change the divisor 10.5 to a whole number by moving the decimal point 1 place to the right. Then move the decimal point in the dividend the same, 1 place to the right.
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.4 Dividing Money_20$

McGraw Hill Math Grade 6 Lesson 13.4 Answer Key Dividing Money Read More »

McGraw Hill Math Grade 6 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 13.1 Dividing Decimals by Whole Numbers will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers

Exercises Divide

Question 1.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 1$
Answer: 5.05
10.1 ÷ 2 = 5.050
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_1$
So, the quotient is 5.05

Question 2.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 2$
Answer: 5.6125
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_2$
So, the quotient is 5.6125

Question 3.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 3$
Answer: 7.825
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_3$
So, the quotient is 7.825

Question 4.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 4$
Answer: 2.02
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_4$
So, the quotient is 2.02

Question 5.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 5$
Answer: 0.96875
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_5$
So, the quotient is 0.96875

Question 6.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 6$
Answer: 2.9
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_6$
So, the quotient is 2.9

Question 7.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 7$
Answer: 3.89
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_7$
So, the quotient is 3.89

Question 8.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 8$
Answer: 1.515
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_8$
So, the quotient is 1.515

Question 9.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 9$
Answer: 17.33
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_9$
So, the quotient is 17.33

Question 10.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 10$
Answer: 27.9375
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_10$
So, the quotient is 27.9375

Question 11.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 11$
Answer: 25.39
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_11$
So, the quotient is 25.39

Question 12.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 12$
Answer: 132.8
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_12$
So, the quotient is 132.8

Question 13.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 13$
Answer: 132.8
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_12$
So, the quotient is 132.8

Question 14.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 14$
Answer: 4.02
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_14$
So, the quotient is 4.02

Question 15.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 15$
Answer: 1.71875
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_15$
So, the quotient is 1.71875

Question 16.
$McGraw Hill Math Grade 6 Chapter 13 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers 16$
Answer: 106.03
$McGraw-Hill Math Grade 6 Answer Key Lesson 13.1 Dividing Decimals by Whole Numbers_16$
So, the quotient is 106.03

McGraw Hill Math Grade 6 Lesson 13.1 Answer Key Dividing Decimals by Whole Numbers Read More »

McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Unit Test Lessons 1–5 will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key

Add or subtract.

Question 1.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 1$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-1$
Explanation:
Perform addition operation on above two given numbers. Add 447 with 58 the sum is equal to 505.

Question 2.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 2$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-2$
Explanation:
Perform addition operation on above two given numbers. Add 4339 with 567 the sum is equal to 4,906.

Question 3.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 3$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-3$
Explanation:
Perform addition operation on above two given numbers. Add 739 with 473 the sum is equal to 1,212.

Question 4.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 4$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-4$
Explanation:
Perform addition operation on above two given numbers. Add 639,089 with 13,487 the sum is equal to 652,576.

Question 5.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 5$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-5$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 49 from 887 the difference is equal to 838.

Question 6.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 6$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-6$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 249 from 1,468 the difference is equal to 1,219.

Question 7.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 7$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-7$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 144 from 6,539 the difference is equal to 6,395.

Question 8.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 8$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-8$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 993 from 5882 the difference is equal to 4,889.

Question 9.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 9$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-9$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 564 from 943 the difference is equal to 379.

Question 10.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 10$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-10$
Explanation:
Perform addition operation on above two given numbers. Add 6,234 with 14,788 the sum is equal to 21,022.

Question 11.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 11$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-11$
Explanation:
Perform addition operation on above two given numbers. Add 24,573 with 29,358 the sum is equal to 53,931.

Question 12.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 12$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-12$
Explanation:
Perform addition operation on above two given numbers. Add 57,722 with 8,989 the sum is equal to 66,711.

Question 13.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 13$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-13$
Explanation:
Perform addition operation on above two given numbers. Add 80,453 with 70,809 the sum is equal to 151,262.

Question 14.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 14$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-14$
Explanation:
Perform addition operation on above three given numbers. Add 12,661 with 44,867 and 9,059 the sum is equal to 66,587.

Question 15.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 15$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-15$
Explanation:
Perform addition operation on above three given numbers. Add 79,255 with 5,828 and 4,770 the sum is equal to 89,853.

Question 16.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 16$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-16$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 376 from 1,765 the difference is equal to 1,389.

Question 17.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 17$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-17$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 18,472 from 28,735,350 the difference is equal to 28,716,878.

Question 18.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 18$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-18$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 11,192 from 22,908 the difference is equal to 11,716.

Question 19.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 19$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-19$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 55,690 from 93,556 the difference is equal to 37,866.

Question 20.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 20$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-20$
Explanation:
Perform subtraction operation on above two given numbers. Subtract 11,188 from 18,172 the difference is equal to 6,984.

Multiply or divide.

Question 21.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 21$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-21$
Explanation:
Perform multiplication operation on above two numbers. Multiply 68 with 9 the product is equal to 612.

Question 22.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 22$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-22$
Explanation:
Perform multiplication operation on above two numbers. Multiply 253 with 4 the product is equal to 1,012.

Question 23.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 23$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-23$
Explanation:
Perform multiplication operation on above two numbers. Multiply 645 with 6 the product is equal to 3,870.

Question 24.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 24$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-24$
Explanation:
Perform multiplication operation on above two numbers. Multiply 865 with 7 the product is equal to 6,055.

Question 25.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 25$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-25$
Explanation:
Perform division operation on above two numbers. Here dividend is 78 and divisor is 9. Divide 78 by 9 the quotient is equal to 8 and remainder is 6.

Question 26.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 26$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-26$
Explanation:
Perform division operation on above two numbers. Here dividend is 85 and divisor is 6. Divide 85 by 6 the quotient is equal to 14 and remainder is 1.

Question 27.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 27$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-27$
Explanation:
Perform division operation on above two numbers. Here dividend is 798 and divisor is 63. Divide 798 by 63 the quotient is equal to 12 and remainder is 42.

Question 28.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 28$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-28$
Explanation:
Perform division operation on above two numbers. Here dividend is 651 and divisor is 26. Divide 651 by 26 the quotient is equal to 25 and remainder is 1.

Question 29.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 29$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-29$
Explanation:
Perform division operation on above two numbers. Here dividend is 348 and divisor is 81. Divide 348 by 81 the quotient is equal to 4 and remainder is 24.

Question 30.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 30$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-30$
Explanation:
Perform multiplication operation on above two numbers. Multiply 618 with 94 the product is equal to 58,092.

Question 31.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 31$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-31$
Explanation:
Perform multiplication operation on above two numbers. Multiply 459 with 82 the product is equal to 37,638.

Question 32.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 32$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-32$
Explanation:
Perform multiplication operation on above two numbers. Multiply 7,604 with 35 the product is equal to 266,140.

Question 33.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 33$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-33$
Explanation:
Perform multiplication operation on above two numbers. Multiply 97,253 with 684 the product is equal to 66,521,052.

Question 34.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 34$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-34$
Explanation:
Perform multiplication operation on above two numbers. Multiply 3,845 with 566 the product is equal to 2,176,270.

Question 35.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 35$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-35$
Explanation:
Perform multiplication operation on above two numbers. Multiply 78,865 with 877 the product is equal to 69,164,605.

Question 36.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 36$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-36$
Explanation:
Perform division operation on above two numbers. Here dividend is 588 and divisor is 28. Divide 588 by 28 the quotient is equal to 21 and remainder is 0.

Question 37.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 37$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-37$
Explanation:
Perform division operation on above two numbers. Here dividend is 773 and divisor is 17. Divide 773 by 17 the quotient is equal to 45 and remainder is 8.

Question 38.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 38$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-38$
Explanation:
Perform division operation on above two numbers. Here dividend is 285 and divisor is 46. Divide 285 by 46 the quotient is equal to 6 and remainder is 9.

Question 39.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 39$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-39$
Explanation:
Perform division operation on above two numbers. Here dividend is 798 and divisor is 63. Divide 798 by 63 the quotient is equal to 12 and remainder is 42.

Question 40.
$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 40$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-40$
Explanation:
Perform division operation on above two numbers. Here dividend is 43456 and divisor is 36. Divide 43456 by 36 the quotient is equal to 1207 and remainder is 4.

Solve the equation and indicate the point on the number line that corresponds with the answer.

$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 41$

Question 41.
—8 + 10 — 5 _________
Answer:
= – 8 + 10 – 5
= -13 + 10
= -3
Explanation:
After solving the given equation the result is – 3 which indicates the point A on the above given number line.

Question 42.
—10 + 5 + 4 _________
Answer:
= -10 + 5 + 4
= -10 + 9
= -1
Explanation:
After solving the given equation the result is -1 which indicates the point D on the above given number line.

Question 43.
—8 + (—5) + 8 __________________
Answer:
= -8 + (-5) + 8
= -13 + 8
= -5
Explanation:
After solving the given equation the result is – 5 which indicates the point B on the above given number line.

Question 44.
7 — 5 + (—10) _____
Answer:
= 7 – 5 + (-10)
= 7 – 15
= – 8
Explanation:
After solving the given equation the result is – 8 which indicates the point C on the above given number line.

Absolute value

Question 45.
|—17.34| = _______
Answer:
|—17.34| = 17.34
The absolute value of |—17.34| is 17.34.

Question 46.
|2²| = ________
Answer:
|2²| = |4| = 4
The absolute value of |2²| is 4.

Question 47.
Which is greater: |7| or |8|? _____
Answer:
The absolute value of |7| is 7.
The absolute value of |8| is 8.
So, |8| is greater than |7|.

Question 48.
Which is greater: |7| or |-8|? ______
Answer:
The absolute value of |7| is 7.
The absolute value of |-8| is 8.
So, |-8| is greater than |7|.

Question 49.
Principal Haines is planning for the school’s upcoming academic year. There are 335 students in Grade 6, 407 in Grade 7, and 298 in Grade 8. How many students are in Principal Haines’s middle school?
Answer:
In Grade 6 there are 335 students.
In Grade 7 there are 407 students.
In Grade 8 there are 298 students.
335 + 407 + 298 = 1,040 students
There are 1,040 students in Principal Haines’s middle school.

Question 50.
If Principal Haines wanted to lower the class size to 23 students in each class, how many classes will she have in Grade 6? _________________
Grade 7? _________________ Grade 8? _________________
(Count the remainder as another class.)
Answer:
Principal Haines wanted to lower the class size to 23 students in each class.
For grade 6:
Total number of students in Grade 6 is 335 students.
Divide 335 by 23 the quotient is equal to 14 and remainder is 13. Here remainder is counted as another class.
14 + 1 = 15 classes
She have 15 classes in Grade 6.

For grade 7:
Total number of students in Grade 7 is 407 students.
Divide 407 by 23 the quotient is equal to 17 and remainder is 16. Here remainder is counted as another class.
17 + 1 = 18 classes
She have 18 classes in Grade 7.

For grade 8:
Total number of students in Grade 8 is 298 students.
Divide 298 by 23 the quotient is equal to 12 and remainder is 22. Here remainder is counted as another class.
12 + 1 = 13 classes
She have 13 classes in Grade 8.

Question 51.
Last year Todd had 435 stamps in his stamp collection. This year Todd added 76 more. How many stamps does he have in his collection now?
Answer:
Last year Todd had 435 stamps in his stamp collection.
This year Todd added 76 more stamps to his collection.
Add 435 stamps with 76 stamps the sum is equal to 511 stamps.
435 + 76 = 511 stamps
Now, Todd have 511 stamps in his collection.

Question 52.
Eurydice’s favorite book has 47 chapters. Each chapter averages 17 pages in length. About how many pages are in the book? ________
How many pages exactly? _______
Answer:
Eurydice’s favorite book has 47 chapters. Each chapter averages 17 pages in length.
There are about 1,000 pages in the book.
Multiply 47 with 17 the product is equal to 799.
47 x 17 = 799 pages
There are exactly 799 pages in the book.

Question 53.
At 1,622 feet in length, the Commodore John Barry Bridge in Philadelphia is one of the longest cantilevered bridges in the world. What is the length of the bridge written in word form?
Answer:
Length of the bridge is 1,622 feet.
The length of the bridge written in word form as one thousand, six hundred and twenty two.

Question 54.
Matthew owes his mother $7.00. He borrows another $2.00 from her, then earns $12.00 for baby’s thing. After he pays his mother back everything he owes her, how much does he have left?
Answer:
Matthew owes his mother $7.00. He borrows another $2.00 from her.
$7 .00 + $ 2.00 = $9.00
Total money he owes form his mother is $9.00.
He earns $12.00 for baby’s thing.
$12.00 – $9.00 = $3.00
Matthew left with $3.00 after he pay his mother everything back he owes from her.

Question 55.
During the latest census, in 2000, the estimated population of the United States was two hundred seventy-four million, nine hundred forty-three thousand, four hundred ninety-six. What is the standard
form of that number?
_________________________
The results of the 2010 Census are expected to show an increase of 30,500,950 in the population estimate. What is the new estimated population of the United States written in standard form?
_________________________
In expanded form?
_________________________
Answer:
In 2000, the estimated population of the United States was two hundred seventy-four million, nine hundred forty-three thousand, four hundred ninety-six. The standard form of that number is 274,943,496.
The results of the 2010 Census are expected to show an increase of 30,500,950 in the population estimate.
274,943,496 + 30,500,950 = 305,444,446
The new estimated population of the United States written in standard form as 305,444,446.
The expanded form of 305,444,446 = ( 3 x 100,000,000) + (5 x 1,000,000) + (4 x 100,000) + (4 x 10,000) + (4 x 1,000) + (4 x 100) + (4 x 10) + (6 x 1)

$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 42$

Provide the ordered pairs for the points plotted on the graph.

Question 56.
A _____
Answer:
The ordered pairs for the point A is (2, 3).

Question 57.
B _____
Answer:
The ordered pairs for the point B is (3, 4).

Question 58.
C _____
Answer:
The ordered pairs for the point C is (-3, 4).

Question 59.
D _____
Answer:
The ordered pairs for the point D is (3, -4).

Question 60.
E ____
Answer:
The ordered pairs for the point E is (-3, -4).

Question 61.
F _____
Answer:
The ordered pairs for the point F is (6, 7).

Question 62.
G ____
Answer:
The ordered pairs for the point G is (-4, 5).

Question 63.
H _____
Answer:
The ordered pairs for the point H is (-5, -5).

Question 64.
Plot the following points on the grid provided.
A (4, 4)
B (8, 4)
C (8, 7)
D(-5, 5)
E(-3, -8)
F(4, -7)

$McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key 43$
Answer:
$McGraw-Hill-Math-Grade-6-Unit-Test-Lessons-1–5-Answer-Key-43$
The given points A, B, C, D, E, F are plotted on the above provided grid as we can observe in the above image.

Question 65.
What is the distance between the coordinate points (3, 6) and (3, 14)?
Answer:
The distance between the coordinate points (3, 6) and (3, 14) is 8.
14 – 6 = 8

McGraw Hill Math Grade 6 Unit Test Lessons 1–5 Answer Key Read More »

McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid: Metric

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 19.4 Perimeter, Area, and Volume of a Solid: Metric will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 19.4 Perimeter, Area, and Volume of a Solid: Metric

Exercises
SOLVE
Question 1.
What is the perimeter of a 5-meter square?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 1$
Answer:
Perimeter of the square = 20 m.

Explanation:
Side of the square = 5 m.
Perimeter of the square = 4 × Side of the square
= 4 × 5
= 20 m.

Question 2.
What is the area of a rectangle with sides of 27 km and 1.1 km?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 2$
Answer:
Area of a rectangle = 29.7 square km.

Explanation:
Length of the rectangle = 27 km.
Width of the rectangle = 1.1 km.
Area of a rectangle = Length of the rectangle × Width of the rectangle
= 27 × 1.1
= 29.7 square km.

Question 3.
A cube with sides of 2 m has what volume?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 3$
Answer:
Volume of a cube = 8 cubic m.

Explanation:
Side of a cube = 2m.
Volume of a cube = Side of a cube × Side of a cube × Side of a cube
= 2 × 2 × 2
= 4 × 2
= 8 cubic m.

Question 4.
A square with sides of 1.2 m has an area of how many sq cm?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 4$
Answer:
A square with sides of 1.2 m has an area of 14,400 sq cm.

Explanation:
Side of a square = 1.2 m.
Area of the square = Side of a square × Side of a square
= 1.2 × 1.2
= 1.44 square m.
Conversion:
1 sq m = 10,000 sq cm.
=> 1.44 square m = 1.44 × 10,000
=> 14,400 sq cm.

Question 5.
A cube with sides of 3.6 km has a volume of how many cubic meters?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 5$
Answer:
A cube with sides of 3.6 km has a volume of 46,65,60,000 cubic m.

Explanation:
Side of the cube = 3.6 km.
Volume of the cube = Side of the cube × Side of the cube × Side of the cube
= 3.6 × 3.6 × 3.6
= 12.96 × 3.6
= 46.656 cubic km.
Conversion:
1 cubic km = 1000000000 cubic m.
=> 46.656 cubic km = 1,00,00,00,000 × 46.656
=> 46,65,60,000 cubic m.

Question 6.
What is the area of a triangle with a base of 11 m and a height of 18 m?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 6$
Answer:
Area of the triangle = 99 square m.

Explanation:
Base of the triangle = 11m.
Height of the triangle = 18m.
Area of the triangle = $\frac{1}{2}$ × Base of the triangle × Height of the triangle
= $\frac{1}{2}$ × 11 × 18
= 11 × 9
= 99 square m.

Question 7.
A rectangular prism has a base of 3 m by 10 m and a height of 4 m. What is its volume?
Answer:
Volume of the rectangular prism = 120 cubic m.

Explanation:
Length of the rectangular prism = 10 m.
Width of the rectangular prism = 3m
Height of the rectangular prism = 4m.
Volume of the rectangular prism = Length of the rectangular prism × Width of the rectangular prism × Height of the rectangular prism
= 10 × 3 × 4
= 30 × 4
= 120 cubic m.

Question 8.
What is the volume of air contained in a 500-m-high tent over a field that measures 300 m by 400 m?
Answer:
Volume of the tent = 6,00,00,000 cubic m.

Explanation:
volume of air contained in a 500-m-high tent over a field that measures.
Length of the tent = 400 m.
Width of the tent = 300 m.
Height of the tent = 500 m.
Volume of the tent = Length of the tent × Width of the tent × Height of the tent
= 400 × 300 × 500
= 120000 × 500
= 6,00,00,000 cubic m.

Question 9.
Rita walks 5 km to the east before walking 4 km to the north. She then turns to the west and walks 5 km. How many kilometers will she have to walk to return to her starting point. What was her total distance in meters?
Answer:
Total distance travelled = 18 km.

Explanation:
Number of kilometers Rita walks to the east = 5.
Number of kilometers Rita walks to the north = 4.
Number of kilometers Rita walks to the west = 5.
Number of kilometers Rita walks to the starting point = 4.
Total distance travelled = Number of kilometers Rita walks to the east + Number of kilometers Rita walks to the north + Number of kilometers Rita walks to the west + Number of kilometers Rita walks to the starting point
= 5 + 4 + 5 + 4
= 9 + 5 + 4
= 14 + 4
= 18 km.

Question 10.
Calculate the volume, in cubic meters, of a swimming pool with a level bottom. It is in the shape of a rectangle with sides of 15 m by 9 m, and with a depth of 3 m.
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 7$
Answer:
volume of the swimming pool = 405 cubic m.

Explanation:
Length of the swimming pool = 15 m.
Width of the swimming pool = 9m.
Height of the swimming pool = 3m.
Volume of the swimming pool = Length of the swimming pool × Width of the swimming pool × Height of the swimming pool
= 15 × 9 × 3
= 135 × 3
= 405 cubic m.

Question 11.
What is the area of a triangle with a base of 10 m and a height of 8 m?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 8$
Answer:
Area of a triangle = 40 square m.

Explanation:
Base of the triangle = 10 m.
Height of the triangle = 8 m.
Area of a triangle = $\frac{1}{2}$ × Base of the triangle × Height of the triangle
= $\frac{1}{2}$ × 10 × 8
= 5 × 8
= 40 square m.

Question 12.
What is the volume of a rectangular solid that is 2 km by 13 km by 8 km?
$McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid Metric 9$
Answer:
Volume of the rectangular solid = 208 cubic km.

Explanation:
Length of the rectangular solid = 13 km.
Width of the rectangular solid = 8 km.
Height of the rectangular solid = 2 km.
Volume of the rectangular solid = Length of the rectangular solid × Width of the rectangular solid × Height of the rectangular solid
= 13 × 8 × 2
= 104 × 2
= 208 cubic km.

Question 13.
If you are traveling at 100 kph, how many meters would you travel in 15 minutes?
Answer:
Number of kilometers 15 minutes travelled = 20.

Explanation:
Number of kilometers per hour travelled = 100.
Conversion:
1 hour = 60 minutes.
Number of kilometers 15 minutes travelled = (100 × 15) ÷ 60
= 1500 ÷ 60
= 20.

Question 14.
What is the area of a rectangle with sides of 4 m and 7 m?
Answer:
Area of a rectangle = 28 square m.

Explanation:
Length of the rectangle = 7m.
Width of the rectangle = 4m.
Area of a rectangle = Length of the rectangle × Width of the rectangle
= 7 × 4
= 28 square m.

Question 15.
A carpet store charges by the square meter for carpet, and the store rounds up to the next square meter. How much carpet should be ordered for a room that is 5.5 m by 7.1 m?
Answer:
Area of the carpet = 39.05 square m.

Explanation:
Length of the carpet = 7.1 m.
Width of the carpet = 5.5 m.
Area of the carpet = Length of the carpet × Width of the carpet
= 7.1 × 5.5
= 39.05 square m.

Question 16.
Jim is calculating how much dirt he will have to haul away when he digs a hole for the foundation of a house. He knows that a dump truck can carry 6 cubic meters of dirt at a time. The hole for the house is going to be 10 m by 7 m and 2 m deep. How many truckloads will he be filling?
Answer:
Number of truckloads will he be filling = 23.33.

Explanation:
Number of cubic meters of dirt at a time a dump truck can carry = 6.
Lengths of the hole for the house = 10m, 7m, and 2m.
Volume of the hole for the house = 10m × 7m × 2m
= 70 × 2
= 140 cubic meters .
Conversion:
Number of truckloads will he be filling = Volume of the hole for the house ÷ Number of cubic meters of dirt at a time a dump truck can carry
= 140 ÷ 6
= 23.3.

McGraw Hill Math Grade 6 Lesson 19.4 Answer Key Perimeter, Area, and Volume of a Solid: Metric Read More »

McGraw Hill Math Grade 6 Lesson 19.3 Answer Key Metric Units of Mass

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 19.3 Metric Units of Mass will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 19.3 Metric Units of Mass

Exercises
CALCULATE
Question 1.
100 g = ____________ kg
Answer:
100 g = 0.1 kg.

Explanation:
100 g = ?? kg.
Conversion:
1 kg = 1,000 g.
100 g = 100 ÷ 1000
= 0.1 kg.

Question 2.
15 kg = ____________ mg
Answer:
15 kg = 1,50,00,000 mg.

Explanation:
15 kg = ?? mg.
Conversion:
1 kg = 10,00,000 mg.
15 kg = 15 × 10,00,000
= 1,50,00,000 mg.

Question 3.
550 g = ____________ kg
Answer:
550 g = 0.550 kg.

Explanation:
550 g = ?? kg.
Conversion:
1 kg = 1,000 g.
550 g = 550 ÷ 1,000
= 0.550 kg.

Question 4.
5600 mg = ____________ g
Answer:
5600 mg = 5.6 g.

Explanation:
5600 mg = ?? g.
Conversion:
1 g = 1,000 mg.
5,600 mg = 5,600 ÷ 1,000
= 5.6 g.

Question 5.
1.1 kg = ____________ mg
Answer:
1.1 kg = 11,00,000 mg.

Explanation:
1.1 kg = ?? mg.
Conversion:
1 kg = 10,00,000 mg.
1.1 kg = 1.1 × 10,00,000
= 11,00,000 mg.

Question 6.
100 mg = ____________ g
Answer:
100 mg = 0.1 g.

Explanation:
100 mg = ?? g.
Conversion:
1 g = 1,000 mg.
100 mg = 100 ÷ 1,000
= 0.1 g.

Question 7.
400 g + 300 mg = ____________ g
Answer:
400 g + 300 mg = 400.3 g.

Explanation:
400 g + 300 mg = ?? g.
Conversion:
1 g = 1,000 mg.
400 g + 300 mg = 400 + (300 ÷ 1000)
= 400 + 0.3
= 400.3 g.

Question 8.
3 kg + 200 g = ____________ g
Answer:
3 kg + 200 g = 3,200 g.

Explanation:
3 kg + 200 g = ?? g.
Conversion:
1 kg = 1,000 g.
3 kg + 200 g = (3 × 1000) + 200
= 3,000 + 200
= 3,200 g.

Question 9.
550 g + .32 kg = ____________ g
Answer:
550 g + .32 kg = 870 g.

Explanation:
550 g + .32 kg = ?? g.
Conversion:
1 kg = 1,000 g.
550 g + .32 kg = 550 + (0.32 × 1,000)
= 550 + 320
= 870 g.

Question 10.
10 kg – 233 g = ____________ kg
Answer:
10 kg – 233 g = 9.767 kg.

Explanation:
10 kg – 233 g = ?? kg.
Conversion:
1 kg = 1,000 g.
10 kg – 233 g = 10 + (233 ÷ 1,000)
= 10 – 0.233
= 9.767 kg.

Question 11.
45 g – 200 mg = ____________ g
Answer:
45 g – 200 mg = 44.8 g.

Explanation:
45 g – 200 mg = ?? g.
Conversion:
1 g = 1,000 mg.
45 g – 200 mg = 45 – (200 ÷ 1,000)
= 45 – 0.2
= 44.8 g.

Question 12.
3300 g + 1100 mg = ____________ kg
Answer:
3300 g + 1100 mg = 3.3011 kg.

3300 g + 1100 mg = ?? kg.
Conversion:
1 kg = 1,000 g.
1 kg = 10,00,000 mg.
3,300 g + 1,100 mg = (3,300 ÷ 1,000) + (1,100 ÷ 10,00,000)
= 3.3 + 0.0011
= 3.3011 kg.

Question 13.
2200 g – 340 mg = ____________ g
Answer:
2200 g – 340 mg = 2199.66 g.

Explanation:
2200 g – 340 mg = ?? g.
Conversion:
1 g = 1,000 mg.
2200 g – 340 mg = 2200 – (340 ÷ 1,000)
= 2200 – 0.34
= 2199.66 g.

Question 14.
2.3 kg + .66kg = ____________ g
Answer:
2.3 kg + .66kg = 2,960 g.

Explanation:
2.3 kg + .66kg = ?? g.
Conversion:
1 kg = 1,000 g.
2.3 kg + .66kg = (2.3 × 1,000) + (0.66 × 1,000)
= 2300 + 660
= 2,960 g.

Question 15.
1 mg + 1 g + 1 kg = ____________ kg
Answer:
1 mg + 1 g + 1 kg = 1.001001 kg.

Explanation:
1 mg + 1 g + 1 kg = ?? kg.
Conversion:
1 kg = 1,000 g.
1 kg = 10,00,000 mg.
1 mg + 1 g + 1 kg = (1 ÷ 10,00,000) + (1 ÷ 1,000) + 1
= 0.000001 + 0.001 + 1
= 1.001001 kg.

Question 16.
15 g – 15 cg – 15 mg = __________ g
Answer:
15 g – 15 cg – 15 mg = 14.835 g.

Explanation:
15 g – 15 cg – 15 mg = ?? g.
Conversion:
1 g = 100 cg.
1 g = 1,000 mg.
15 g – 15 cg – 15 mg = 15 – (15 ÷ 100) – (15 ÷ 1,000)
= 15 – 0.15 – 0.015
=14.85 – 0.015
= 14.835 g.

Question 17.
42 g + 100 mg = ___________ cg
Answer:
42 g + 100 mg = 4,210 cg.

Explanation:
42 g + 100 mg = ?? cg.
Conversion:
1 g = 100 cg.
1 mg = 0.1 cg.
42 g + 100 mg = (100 × 42) + (100 × 0.1)
= 4,200 + 10
= 4,210 cg.

Question 18.
35 g + 3500 g = ____________ kg
Answer:
35 g + 3500 g = 3.535 kg.

Explanation:
35 g + 3500 g = ?? kg.
Conversion:
1 kg = 1,000 g.
35 g + 3500 g = (35 ÷ 1,000) + (3,500 ÷ 1,000)
= 0.035 + 3.5
= 3.535 kg.

Question 19.
100 kg – 2100 g = ____________ kg
Answer:
100 kg – 2100 g = 97.9 kg.

Explanation:
100 kg – 2100 g = ?? kg.
Conversion:
1 kg = 1,000 g.
100 kg – 2,100 g = 100 – (2,100 ÷ 1,000)
= 100 – 2.1
= 97.9 kg.

Question 20.
33 g + 33 cg + 33 mg = ____________ g
Answer:
33 g + 33 cg + 33 mg = 33.363 g.

Explanation:
33 g + 33 cg + 33 mg = ?? g.
Conversion:
1 g = 1,000 mg.
1 g = 100 cg.
33 g + 33 cg + 33 mg = 33 + (33 ÷ 100) + (33 ÷ 1,000)
= 33 + 0.33 + 0.033
= 33.33 + 0.033
= 33.363 g.

McGraw Hill Math Grade 6 Lesson 19.3 Answer Key Metric Units of Mass Read More »

McGraw Hill Math Grade 6 Lesson 4.2 Answer Key Adding with Negative Numbers

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 4.2 Adding with Negative Numbers will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 4.2 Adding with Negative Numbers

Exercises Solve

Question 1.
12 + (-4)
Answer:
Sum of 12 + (-4), we get 8.

Explanation:
12 + (-4)
= 12 – 4
= 8.

Question 2.
(-14) + 8
Answer:
Sum of (-14) + 8, we get -6.

Explanation:
(-14) + 8
= – 14 + 8
= -6.

Question 3.
3 + (-13)
Answer:
Sum of 3 + (-13), we get -10.

Explanation:
3 + (-13)
= 3 – 13
= -10.

Question 4.
45 + (-23)
Answer:
Sum of 45 + (-23), we get 22.

Explanation:
45 + (-23)
= 45 – 23
= 22.

Question 5.
123 + (-43) + 22
Answer:
Sum of 123 + (-43) + 22, we get 102.

Explanation:
123 + (-43) + 22
= 123 – 43 + 22
= 80 + 22
= 102.

Question 6.
90 + (-45) + (-3)
Answer:
Sum of 90 + (-45) + (-3), we get 42.

Explanation:
90 + (-45) + (-3)
= 90 – 45 – 3
= 45 – 3
= 42.

Question 7.
(-10) + (-10) + 3
Answer:
Sum of (-10) + (-10) + 3, we get -17.

Explanation:
(-10) + (-10) + 3
= – 10 – 10 + 3
= – 20 + 3
= -17.

Question 8.
45 + (-32) + 2
Answer:
Sum of 45 + (-32) + 2, we get 15.

Explanation:
45 + (-32) + 2
= 45 – 32 + 2
= 47 – 32
= 15.

Question 9.
15 + (-14)
Answer:
Sum of 15 + (-14), we get 1.

Explanation:
15 + (-14)
= 15 – 14
= 1.

Question 10.
16 + 14 + (-13)
Answer:
Sum of 16 + 14 + (-13), we get 17.

Explanation:
16 + 14 + (-13)
= 16 + 14 – 13
= 30 – 13
= 17.

Question 11.
(-15) + 14
Answer:
Sum of (-15) + 14, we get -1.

Explanation:
(-15) + 14
= – 15 + 14
= -1.

Question 12.
67 + 12 + 13 + (-14)
Answer:
Sum of 67 + 12 + 13 + (-14), we get 88.

Explanation:
67 + 12 + 13 + (-14)
= 67 + 12 + 13 – 14
= 89 + 13 – 14
= 102 – 14
= 88.

Question 13.
43 + (-32) + 5
Answer:
Sum of 43 + (-32) + 5, we get 16.

Explanation:
43 + (-32) + 5
= 43 – 32 + 5
= 48 – 32
= 16.

Question 14.
(-43) + 32 + (-5)
Answer:
Sum of (-43) + 32 + (-5), we get -16.

Explanation:
(-43) + 32 + (-5)
= – 43 + 32 – 5
= – 11 – 5
= -16.

Question 15.
2 + 2 + (-3) + (-2)
Answer:
Sum of 2 + 2 + (-3) + (-2), we get -1.

Explanation:
2 + 2 + (-3) + (-2)
= 2 + 2 – 3 – 2
= 4 – 3 – 2
= 1 – 2
= -1.

Question 16.
4 + (-5) + 5
Answer:
Sum of 4 + (-5) + 5, we get 4.

Explanation:
4 + (-5) + 5
= 4 + – 5 + 5
= 9 – 5
= 4.

Question 17.
21 + (-45)
Answer:
Sum of 21 + (-45), we get – 24.

Explanation:
21 + (-45)
= 21 – 45
= – 24.

Question 18.
45 + (-43)
Answer:
Sum of 45 + (-43), we get 2.

Explanation:
45 + (-43)
= 45 – 43
= 2.

McGraw Hill Math Grade 6 Lesson 4.2 Answer Key Adding with Negative Numbers Read More »

McGraw Hill Math Grade 6 Lesson 4.1 Answer Key Negative Numbers

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 4.1 Negative Numbers will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 4.1 Negative Numbers

Exercices
Solve

Question 1.
(-8) + 8 = ____
Answer:
Sum of (-8) + 8, we get the result 0.

Explanation:
(-8) + 8 = – 8 + 8
= 0.

Question 2.
(-134) + 134 = ____
Answer:
Sum of (-134) + 134, we get the result 0.

Explanation:
(-134) + 134 = – 134 + 134
= 0.

Question 3.
(-12) + 13 + 11 + (-13)
Answer:
Sum of (-12) + 13 + 11 + (-13), we get the result -1.

Explanation:
(-12) + 13 + 11 + (-13)
= -12 + 13 + 11 – 13
= -12 + 24 – 13
= 12 – 13
= -1.

Question 4.
100 + (-100) = ____
Answer:
Sum of 100 + (-100), we get the result 0.

Explanation:
100 + (-100) = 100 – 100
= 0.

Question 5.
20 + (-17) = ____
Answer:
Sum of 20 + (-17) , we get the result 3.

Explanation:
20 + (-17) = 20 – 17
= 3.

Question 6.
(-65) + 65 + 61 + (-58) =
Answer:
Sum of (-65) + 65 + 61 + (-58) , we get the result 3.

Explanation:
(-65) + 65 + 61 + (-58)
= – 65 + 65 + 61 – 58
= – 65 + 126 – 58
= 61 – 58
= 3.

Question 7.
$\frac{1}{2}$ + $\left(-\frac{1}{2}\right)$ = ____
Answer:
Sum of $\frac{1}{2}$ + $\left(-\frac{1}{2}\right)$, we get the result 0.

Explanation:
$\frac{1}{2}$ + $\left(-\frac{1}{2}\right)$
= $\frac{1}{2}$ – $\left(\frac{1}{2}\right)$
= 0.

Question 8.
212 + 200 + (-212) + (-212) = ____
Answer:
Sum of 212 + 200 + (-212) + (-212), we get the result -12.

Explanation:
212 + 200 + (-212) + (-212)
= 212 + 200 – 212 – 212
= 412 – 212 – 212
= 200 – 212
= -12.

Question 9.
31 + (-34) + 0 = ___
Answer:
Sum of 31 + (-34) + 0, we get the result -3..

Explanation:
31 + (-34) + 0
= 31 – 34 + 0
= 31 – 34
= -3.

Question 10.
76 + $\frac{1}{4}$ + $\left(-\frac{1}{4}\right)$ + (-76) = ____
Answer:
Sum of 76 + $\frac{1}{4}$ + $\left(-\frac{1}{4}\right)$ + (-76), we get the result 0.

Explanation:
76 + $\frac{1}{4}$ + $\left(-\frac{1}{4}\right)$ + (-76)
= 76 + $\frac{1}{4}$ – $\left(\frac{1}{4}\right)$ – 76
= $\frac{304+1}{4}$ – $\left(\frac{1}{4}\right)$ – 76
= $\frac{305}{4}$ – $\left(\frac{1}{4}\right)$ – 76
= $\frac{305- 1}{4}$ – 76
= $\frac{304}{4}$ – 76
= 76 – 76
= 0.

Question 11.
Is -6 to the left or the right of -6.2 on the number line?
Answer:
-6 lies to the left on the number line because it is a negative integer.

Explanation:
-6 is negative integer.
$McGraw-Hill-Math-Grade-6-Answer-Key-Lesson-4.1-Negative-Numbers-Exercises-Solve-11$

Question 12.
Is -4.5 greater or less than -4.0?
Answer:
– 4.0 is greater than – 4.5 because its an integer where greater comes first later lesser integer.

Explanation:
– 4.5 is less than – 4.0.

McGraw Hill Math Grade 6 Lesson 4.1 Answer Key Negative Numbers Read More »

McGraw Hill Math Grade 6 Lesson 20.2 Answer Key Changing from Metric Units to Customary Units

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 20.2 Changing from Metric Units to Customary Units will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 20.2 Changing from Metric Units to Customary Units

Exercises

CALCULATE

Question 1.
Which is larger, a 2-liter bottle of soda or a 2-quart bottle?
Answer:
Convert from liter to quarts.
1 liter = 1.05 quart
2 liter = 2 × 1.05 = 2.11 quart
2.11 quart > 2 quart
Therefore 2-liter bottle of soda is larger than a 2-quart bottle.

Question 2.
A 2-meter long snake is how many inches long?
Answer:
Convert from meter to inch
1 meter = 39.37 inch
2 meters = 2 × 39.37 = 78.74 inch
Therefore 2-meter long snake is 78.74 inch

Question 3.
A man weighs 91 kilograms. How many pounds is that?
Answer:
A man weighs 91 kilograms.
Convert from kilogram to pound
1 kg = 2.2 pound
91 kgs = 91 × 2.2 ≈ 200 pounds

Question 4.
The police officer said that you were traveling at a speed of 100 kilometers an hour. How many miles per hour were you traveling?
Answer:
Given,
The police officer said that you were traveling at a speed of 100 kilometers an hour.
We have to convert from kilometer to mile.
1 kilometer = 0.62 mile
100 kilometer = 0.6 × 100 = 62 miles
Thus you were traveling 62 miles per hour.

Question 5.
The weight limit on a bridge is 15,000 kilograms. How many tons is that?
Answer:
Given,
The weight limit on a bridge is 15,000 kilograms.
Convert from kilograms to tons.
1 kg = 0.0011 ton
15000 kg = 15000 × 0.0011 = 16.53 tons

Question 6.
100 meters is how many yards?
Answer:
Convert from meter to yards.
1 meter = 1.09 yard
100 meter = 100 × 1.09 = 109 yards
Thus 100 meters is 109 yards.

Question 7.
Is $5.00 a gallon for gas more than $1.75 a liter?
Answer:
Convert from gallon to liter
1 gallon = 3.78 liters
1 liter = $1.75
3.78 liters = 3.78 × 1.75 = $6.61
Thus $5.00 a gallon of gas is not more than $1.75 a liter

Question 8.
7 liters of water is about how many quarts?
Answer:
Convert from liter to quarts
1 liter = 1.05 quart
7 liters = 7 × 1.05 = 7.39 quarts

Question 9.
Which is shorter, 15 millimeters or .75 inches?
Answer:
Convert from millimeter to inch to find which is shorter.
1 millimeter = 0.039 inch
15 millimeters = 15 × 0.039 = 0.59 inch
0.59 < 0.75
So, 15 millimeters is shorter than 0.75 inches.

Question 10.
Which is larger, a 200-gram steak or a $\frac{1}{2}$ pound one?
Answer:
Convert from pound to gram
1 pound = 453.6 grams
$\frac{1}{2}$ = 453.6/2 = 226.8 grams
Thus $\frac{1}{2}$ pound is larger than 200 gram steak.

McGraw Hill Math Grade 6 Lesson 20.2 Answer Key Changing from Metric Units to Customary Units Read More »

McGraw Hill Math Grade 6 Lesson 20.1 Answer Key Changing from Customary Units to Metric Units

McGraw Hill Math / Go Math Answer Key / January 26, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 20.1 Line Segments and Rays will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 20.1 Changing from Customary Units to Metric Units

Exercises

CALCULATE

Question 1.
3 feet is how many meters?
Answer: 0.9144

Explanation:
We have to convert feet to meters
1 foot = 0.3048 meters
3 feet = 3 × 0.3048 = 0.9144 meters
So, 3 feet = 0.9144 meters

Question 2.
A $\frac{1}{2}$ gallon is how many liters?
Answer: 2273.05

Explanation:
We have to convert from gallons to liters
1 gallon = 4.54 liter
1/2 gallon = 4.54/2 = 2.27
Therefore $\frac{1}{2}$ gallon is 2.27 liters

Question 3.
Which is larger, a 16-ounce soda bottle, or a $\frac{1}{2}$ liter soda bottle?
Answer: $\frac{1}{2}$ liter soda bottle

Explanation:
In order to compare which soda bottle is larger we have to convert from liter to ounce
We know that
1 liter = 33.814 ounce
1/2 liter = 33.814/2 = 16.907 ounce ≈ 17 ounce
Therefore $\frac{1}{2}$ liter soda bottle is larger than 16-ounce soda bottle

Question 4.
A 200-pound person weighs how many kilograms?
Answer: 90.71 kilograms

Explanation:
We have to convert the given weight from pounds to kilograms.
1 pound = 0.45 kg
200 pounds = 200 × 0.45 = 90.71 kgs
Thus 200 pound person weighs 90.70 kilograms.

Question 5.
If the highway exit sign says it is 2 miles to the next exit, how many kilometers is that?
Answer:
1 mile = 1.6 kilometer
2 mile = 2 × 1.6 = 3.21 kilometers
Thus 2 miles to the next exit means 3.21 kilometers.

Question 6.
Which race should take longer, the 100-yard or 100-meter dash?
Answer:
1 yard = 0.9 meters
100 yard = 100 × 0.9 = 91.44 meters
100 meter > 91.44 meters
Therefore 100 meters dash is longer than 100 yard.

Question 7.
If a tank has a 105.68 gallon capacity, how many liters is that?
Answer:
1 gallon = 4.54 liter
We have to convert from gallons to liters
105.68 gallon = 105.68 × 4.54 = 480.43 liters

Question 8.
Which is heavier, a 16-ounce steak or a .5-kilogram steak?
Answer:
Convert from ounce to kilogram
1 ounce = 0.02 kilogram
16 ounce = 0.45 kilograms
Thus 0.5-kilogram steak is heavier than a 16-ounce steak.

Question 9.
A 2-ton truck weighs how many kilograms?
Answer:
Convert from ton to kilogram
1 ton = 907.18
2 ton = 2 × 907.18 = 1814.37 kilograms
Thus a 2-ton truck weighs 1814.37 kilograms.

Question 10.
If a man is 6.56 feet tall, how many meters tall is he?
Answer:
We have to convert feet to meters
1 foot = 0.3048 meters
6.56 feet = 6.56 × 0.3 = 1.99 ≈ 2 meters

McGraw Hill Math Grade 6 Lesson 20.1 Answer Key Changing from Customary Units to Metric Units Read More »

McGraw Hill Math Grade 6 Lesson 19.2 Answer Key Metric Units of Liquid Volume

McGraw Hill Math / Go Math Answer Key / January 25, 2024

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Lesson 19.2 Metric Units of Liquid Volume will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Answer Key Lesson 19.2 Metric Units of Liquid Volume

Exercises
CALCULATE
Question 1.
1.1 L = ___________ mL
Answer:
1.1 L = 1,100 mL.

Explanation:
1.1 L = ___________ mL.
Conversion:
1 L = 1000 mL.
1.1 L = 1.1 × 1000
= 1,100 mL.

Question 2.
700 L = _____________ mL
Answer:
700 L = 7,00,000 mL.

Explanation:
700 L = ?? mL.
Conversion:
1 L = 1,000 mL.
700 L = 1,000 × 700
= 7,00,000 mL.

Question 3.
.56 L = __________ mL
Answer:
.56 L = 560 mL.

Explanation:
.56 L = ?? mL.
Conversion:
1 L = 1000 mL.
.56 L = 0.56 × 1000
= 560 mL.

Question 4.
35 L = ____________ mL
Answer:
35 L = 35,000 mL.

Explanation:
35 L = ?? mL.
Conversion:
1 L = 1,000 mL.
35 L = 1,000 × 35
= 35,000 mL.

Question 5.
3 kL = _________ mL
Answer:
3 kL = 30,00,000 mL.

Explanation:
3 kL = ?? mL.
Conversion:
1 kL = 10,00,000 mL.
3 kL = 3 × 10,00,000
= 30,00,000 mL.

Question 6.
21 mL = __________ L
Answer:
21 mL = 0.021 L.

Explanation:
21 mL = ?? L.
Conversion:
1 L = 1,000 mL.
21 mL = 21 ÷ 1,000
= 0.021 L.

Question 7.
457 mL = ____________ kL
Answer:
457 mL = 0.000457 kL.

Explanation:
457 mL = ?? kL.
Conversion:
1 kl = 10,00,000 mL.
457 mL = 457 ÷ 10,00,000
= 0.000457 kL.

Question 8.
77 mL + 77 L = ____________ L
Answer:
77 mL + 77 L = 77.077 L.

Explanation:
77 mL + 77 L = ?? L.
Conversion:
1 L = 1,000 mL.
77 mL + 77 L = (77 ÷ 1,000) + 77
= 0.077 + 77
= 77.077 L.

Question 9.
1 kL + 35 L = ___________ L
Answer:
1 kL + 35 L = 1,035 L.

Explanation:
1 kL + 35 L = ?? L.
Conversion:
1 kL = 1000 L.
1 kL + 35 L = (1,000 × 1) + 35
= 1,000 + 35
= 1,035 L.

Question 10.
41 mL + 41 L = ___________ kL
Answer:
41 mL + 41 L = 0.041041 kL.

Explanation:
41 mL + 41 L = ?? kL.
Conversion:
1 kL = 1000 L.
1 kL = 10,00,000 mL.
41 mL + 41 L = (41 ÷ 10,00,000) + (41 ÷ 1,000)
= 0.000041 + 0.041
= 0.041041 kL.

Question 11.
4 kL – 325 L = ___________ L
Answer:
4 kL – 325 L = 3,675 L.

Explanation:
4 kL – 325 L = ?? L.
Conversion:
1 kL = 1,000 L.
4 kL – 325 L = (4 × 1,000) – 325
= 4000 – 325
= 3,675 L.

Question 12.
35 kL + 3500 L = ___________ kL
Answer:
35 kL + 3500 L = 38.5 kL.

Explanation:
35 kL + 3500 L = ?? kL.
Conversion:
1 kL = 1,000 L.
35 kL + 3500 L = 35 + (3,500 ÷ 1,000)
= 35 + 3.5
= 38.5 kL.

Question 13.
23 L + .23 mL = _________ L
Answer:
23 L + .23 mL = 23.00023 L.

Explanation:
23 L + .23 mL = ?? L.
Conversion:
1 L = 1,000 mL.
23 L + .23 mL = 23 + (0.23 ÷ 1,000)
= 23 + 0.00023
= 23.00023 L.

Question 14.
41 L – 23 mL = _________ mL
Answer:
41 L – 23 mL = 40,977 mL.

Explanation:
41 L – 23 mL = ?? mL.
Conversion:
1 L = 1,000 mL.
41 L – 23 mL = (41 × 1000) – 23
= 41,000 – 23
= 40,977 mL.

Question 15.
If a water cooler holds 30 liters of water, and each cup of water holds 250 milliliters, how many cups can you fill before the water cooler is empty?
Answer:
Number of water cups can fill before the water cooler is empty = 120.

Explanation:
Number of liters of water a water cooler holds = 30.
Number of milliliters each cup of water holds = 250.
Conversion:
1 L = 1,000 mL.
Number of milliliters of water a water cooler holds = 30 L = 1000 × 30 = 30,000 mL.
Number of water cups can fill before the water cooler is empty = Number of milliliters of water a water cooler holds ÷ Number of milliliters each cup of water holds
= 30,000 ÷ 250
= 120.

Question 16.
If there are 35 students and each expects to drink 10 half-liter bottles of water in a week, how many many total liters is this?
Answer:
Total number of liters bottles of water they drank = 700 L.

Explanation:
Number of students = 35.
Number of half liters bottles of water in a week each expects to drink = 10.
Conversion:
=> 10 half liters = 5 liters.
Total number of half liters bottles of water they drank = Number of students × Number of half liters bottles of water in a week each expects to drink
= 35 × 10
= 350.
Conversion:
1 L = half liter + half liter.
Total number of liters bottles of water they drank =
=> 350 half liters = 350 + 350 L.
=> 700 L.

Question 17.
A half-liter bottle of soda is a common size. How many bottles of soda would it take to fill a 10-liter container?
Answer:
Number of half-liter bottle of soda it takes to fill a 10-liter container = 20.

Explanation:
Number of liters container = 10.
Conversion:
1 L = half-liter + half-liter
=> Number of half-liter bottle of soda it takes to fill a 10-liter container = Number of liters container × 2
= 10 × 2
= 20.

Question 18.
If a reservoir holds 100,000,000 liters of water, then how many kiloliters of water does it hold?
Answer:
Number of kiloliters of water it holds = 100,000.

Explanation:
Number of liters of water a reservoir holds = 100,000,000.
Conversion:
1 kL = 1,000 L.
=> Number of kiloliters of water it holds = 100,000,000 ÷ 1,000
=> 100,000.

McGraw Hill Math Grade 6 Lesson 19.2 Answer Key Metric Units of Liquid Volume Read More »