McGraw Hill Math

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 6 Lesson 5 Writing Numbers to 120 by 5s and 10s as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 6 Lesson 5 Writing Numbers to 120 by 5s and 10s

Count

Count by 5s. Write the missing numbers.

Answer:

Explanation:
The given series is skip by fives
to get skip by fives we have to add five.

Count by 10s. Write the missing numbers.

Answer:

Explanation:
The given series is skip by tens
to get skip by tens we have to add ten.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 6 Test as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Chapter 6 Test Answer Key

Count on. Write the missing numbers.

Count by 1s. Write the missing numbers.

Question 1.
103 104 ___ ___ ___
Answer:
103 104 105 106 107
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
104 + 1 = 105
105 + 1 = 106

Question 2.
106 107 ___ ___ ___
Answer:
106 107 108 109 110
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
107 + 1 = 108
108 + 1 = 109

Question 3.
114 115 ___ ___ ___
Answer:
114 115 116 117 118
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
115 + 1 = 116
116 + 1 = 117

Question 4.
41 42 ___ ___ ___
Answer:
41 42 43 44 45
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
42 + 1 = 43
43 + 1 = 44

Question 5.
56 57 ___ ___ ___
Answer:
56 57 58 59 60
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
58 + 1 = 59
59 + 1 = 60

Question 6.
67 68 ___ ___ ___
Answer:
67 68 69 70 71 72
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
69 + 1 = 70
70 + 1 = 71

Question 7.
97 98 ___ ___ ___
Answer:
97 98 99 100 101
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
97 + 1 = 98
98 + 1 = 99

Question 8.
75 76 ___ ___ ___
Answer:
75 76 77 78 79
Explanation:
The given pattern is skip by ones
In skip by ones we have to add number 1
76 + 1 = 77
77 + 1 = 78

Count by 10s. Write the missing numbers.

Question 9.
0 10 ___ ___ ___
Answer:
0 10 20 30 40 
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
10 + 10 = 20
20 + 10 = 30

Question 10.
80 90 ___ ___ ___
Answer:
80 90 100 110 120
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
90 + 10 = 100
100 + 10 = 120

Question 11.
50 60 ___ ___ ___
Answer:
50 60 70 80 90 
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
60 + 10 = 70
70 + 10 = 80

Question 12.
40 50 ___ ___ ___
Answer:
40 50 60 70 80
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
60 + 10 = 70
70 + 10 = 80

Question 13.
70 80 ___ ___ ___
Answer:
70 80 90 100 110
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
80 + 10 = 90
90 + 10 = 100

Question 14.
20 30 ___ ___ ___
Answer:
20 30 40 50 60
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
40 + 10 = 50
50 + 10 = 60

Question 15.
30 40 ___ ___ ___
Answer:
30 40 50 60 70
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
40 + 10 = 50
50 + 10 = 60

Question 16.
60 70 ___ ___ ___
Answer:
60 70 80 90 100
Explanation:
The given series is skip by tens
we have to add number 10 the given number.
70 + 10 = 80
80 + 10 = 90

Count by 5s. Write the missing number.

Question 17.
25 30 ___ ___ ___
Answer:
25 30 35 40 45
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
30 + 5 = 35
35 + 5 = 40

Question 18.
10 15 ___ ___ ___
Answer:
10 15 20 25 30
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
15 + 5 = 20
20 + 5 = 25

Question 19.
65 70 ___ ___ ___
Answer:
65 70 75 80 85
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
70 + 5 = 75
75 + 5 = 80

Question 20.
0 5 ___ ___ ___
Answer:
0 5 10 15 20
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
5 + 5 = 10
10 + 5 = 15

Question 21.
80 85 ___ ___ ___
Answer:
80 85 90 95 100
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
85 + 5 = 90
90 + 5 = 95

Question 22.
35 40 ___ ___ ___
Answer:
35 40 45 50 55
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
40 + 5 = 45
45+ 5 = 50

Question 23.
100 105 ___ ___
Answer:
100 105 110 115 120
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
105 + 5 = 110
110 + 5 = 115

Question 24.
15 20 ___ ___ ___
Answer:
15 20 25 30 35
Explanation:
The given series is skip by tens
we have to add number 5 to the given number.
25 + 5 = 30
30 + 5 = 35

Question 25.
Count by 5s. Write the missing numbers.

Answer:

Explanation:
The given series is skip by tens
we have to add number 5 to the given number.

Question 26.
Count by 10s. Write the missing numbers.

Answer:

Explanation:
The given series is skip by tens
we have to add number 10 the given number.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 1 Adding in Different Order as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 1 Adding in Different Order

Add.

Write the sum.

Question 1.
3 + 1 = 4
1 + 3 = 4
Explanation:
In a equation the addends are different but the sum is same.

Question 2.
4 + 3 = ___
3 + 4 = ___
Answer:
4 + 3 = 7
3 + 4 = 7
Explanation:
In a equation the addends are different but the sum is same.

Question 3.
0 + 5 = ___
Answer:
0 + 5 = 5
Explanation:
If we add zero to the number the number remains the same.

Question 4.
6 + 0 = ___
Answer:
6 + 0 = 6
Explanation:
If we add zero to the number the number remains the same.

Question 5.
18 + 0 = ___
Answer:
18 + 0 = 18
Explanation:
If we add zero to the number the number remains the same.

Question 6.
0 + 19 = ___
Answer:
0 + 19 = 19
Explanation:
If we add zero to the number the number remains the same.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 2 Adding Three Numbers as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 2 Adding Three Numbers

Add

Write the sum.

Question 1.
(2 + 1) + 4 = 7
2 + (1 + 4) = 7
Explanation:
 Changing the order of addends does not change the sum.
According to the Commutative property

Question 2.
(5 + 3) + 1 = ___
5 + (3 + 1) = ___
Answer:
(5 + 3) + 1 = 8 + 1 = 9
5 + (3 + 1) = 5 + 4 = 9
Explanation:
 Changing the order of addends does not change the sum.
According to the Commutative property

Question 3.
(2 + 4) + 2 = ___
2 + (4 + 2) = ___
Answer;
(2 + 4) + 2 = 6 + 2 = 8
2 + (4 + 2) = 2 + 6 = 8
Explanation:
 Changing the order of addends does not change the sum.
According to the Commutative property

Question 4.
(1 + 5) + 7 = ____
1 + (5 + 7) = ___
Answer:
(1 + 5) + 7 = 6 + 7 = 13
1 + (5 + 7) = 1 + 12 = 13
Explanation:
 Changing the order of addends does not change the sum.
According to the Commutative property

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 3 Subtract to Find Missing Numbers as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 3 Subtract to Find Missing Numbers

Solve

Read the number sentences. Write the missing number

Question 1.
5 + = 6
6 – 5 = 1
5 + 1 = 6
Explanation:
In addition statement if there is a missing number
For that missing number we have to do subtraction.

Question 2.
2 + = 4
4 – 2 = ___
2 + ___ = 4
Answer:
4 – 2 = 2
2 + 2 = 4
Explanation:
In addition statement if there is a missing number
For that missing number we have to do subtraction.

Question 3.
9 + = 18
18 – 9 = ___
9 + ___ = 18
Answer:
18 – 9 = 9
9 + 9 = 18
Explanation:
In addition statement if there is a missing number
For that missing number we have to do subtraction.

Question 4.
4 + = 7
7 – 4 = ___
4 + ___ = 7
Answer:
7 – 4 = 3
4 + 3 = 7
Explanation:
In addition statement if there is a missing number
For that missing number we have to do subtraction.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 4 Counting to Add and Subtract as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 4 Counting to Add and Subtract

Add or subtract

Count on to add. Count back to subtract. Write the sum or difference.

Question 1.
4 + 5 = 9
Explanation:
The sum of 4 and 5 is 9
4 + 5 = 9

Question 2.
15 – 4 = _____
Answer:
11
Explanation:
The difference of 15 and 4 is 11
15 – 4 = 11

Question 3.
12 + 6 = _____
Answer:
18
Explanation:
The sum of 12 and 6 is 18
12 + 6 = 18

Question 4.
11 – 5 = _____
Answer:
6
Explanation:
11 – 5 = 6
The difference of 11 and 5 is 6

Question 5.
9 + 9 = _____
Answer:
18
Explanation:
The sum of 9 and 9 is 18
9 + 9 = 18

Question 6.
7 – 1 = _____
Answer:
6
Explanation:
The difference of 7 and 1 is 6
7 – 1 = 6

Question 7.
8 + 6 = _____
Answer:
14
Explanation:
The sum of 8 and 6 is 14
8 + 6 = 14

Question 8.
19 – 14 = _____
Answer:
5
Explanation:
The difference of 19 and 14 is 5
19 – 14 = 5

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 5 Adding by Making 10 as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 5 Adding by Making 10

Solve

Draw circles to make 10. Then write your answers.

Question 1.
7 + 5 = ?

10 + 2 = 12
so 7 + 5 = 12
Explanation:
In a ten frame there are 7 green dots showing the number 7
to make ten we need 3 more in first ten frame and 2 more in second ten frame.

Question 2.
9 + 7 = ?

10 + 6 = ___
so 9 + 7 = ___
Answer:

10 + 6 = 16
9 + 7 = 16
Explanation:
In a ten frame there are 9  yellow dots showing the number 9
to make ten we need 1 more in first ten frame and 6 more in second ten frame.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 7 Creating New Sums as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 7 Creating New Sums

Solve.

Look at the math fact. Write another fact with the same sum.

Question 1.
12 + 3 = 15
10 + 5 = 15
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 2.
5 + 3 = 8
_____ + ____ = 8
Answer:
5 + 3 = 8
3 + 5 = 8
4 + 4 = 8
2 + 6 = 8
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 3.
9 + 4 = 13
_____ + ____ = 13
Answer:
9 + 4 = 13
4 + 9 = 13
10 + 3 = 13
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 4.
6 + 5 = 11
_____ + _____ = 11
Answer:
5 + 6 = 11
10 + 1 = 11
7 + 4 = 11
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 5.
7 + 3 = 10
_____ + _____ = 10
Answer:
3 + 7 = 10
5 + 5 = 10
10 + 0 = 10
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 6.
5 + 0 = 5
_____ + ___ = 5
Answer:
2 + 3 = 5
4 + 1 = 5
3 + 2 = 5
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 7.
4 + 2 = 6
_____ + ___ = 6
Answer:
3 + 3 = 6
1 + 5 = 6
0 + 6 = 6
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

Question 8.
8 + 1 = 9
_____ + _____ = 9
Answer:
1 + 8 = 9
4 + 5 = 9
3 + 6 = 9
Explanation:
In addition for the same sum we can write multiple factors,
But the sum will not be changed.

All the solutions provided in McGraw Hill Math Grade 1 Answer Key PDF Chapter 7 Lesson 8 Solving Word Problems as per the latest syllabus guidelines.

McGraw-Hill Math Grade 1 Answer Key Chapter 7 Lesson 8 Solving Word Problems

Solve

Add or subtract to solve. Write the sum or difference. Use objects to help.

Question 1.
There are 14 bees. 5 bees fly away. How many bees are left?
14 – 5 = _________
Answer:
9
Explanation:
Total number of bees are 14
Number of bees flew away = 5
14 – 5 = 9

Question 2.
Ella draws 4 stars. She draws 2 more stars. How many stars does Ella draw?
4 + 2 = ___________
Answer:
Explanation:
Number of stars that Ella draw = 4
She draws two more
4 + 2 = 6

Practice questions available in McGraw Hill Math Grade 6 Answer Key PDF Unit Test Lessons 15-17 will engage students and is a great way of informal assessment.

McGraw-Hill Math Grade 6 Unit Test Lessons 15-17 Answer Key

Restate in exponential form, then calculate.

Question 1.
2 × 2 × 2 × 2 + 3 × 3 × 3 _____________
Answer:
The given expression is 2 × 2 × 2 × 2 + 3 × 3 × 3.
The exponential form of above given expression is 2⁴ + 3³.
= 2⁴ + 3³
= 16 + 27
= 43
So, 2⁴ + 3³ is equal to 43.

Question 2.
4 × 4 × 4 × 4 – 5 × 5 × 5 _____________
Answer:
The given expression is 4 × 4 × 4 × 4 – 5 × 5 × 5.
The exponential form of above given expression is 4⁴ – 5³.
= 4⁴ – 5³
= 256 – 125
= 131
So, 4⁴ – 5³ is equal to 131.

Question 3.
2 × 2 × 2 × 2 × 2 × 2 + 6 × 6 – 5 × 5 _____________
Answer:
The given expression is 2 × 2 × 2 × 2 × 2 × 2 + 6 × 6 – 5 × 5.
The exponential form of above given expression is 2⁶ + 6² – 5².
= 2⁶ + 6² – 5²
= 64 + 36 – 25
= 75
So, 2⁶ + 6² – 5² is equal to 75.

Restate using scientific notation.

Question 4.
3,456,984.01 _____________
Answer:
The given number 3,456,984.01 already has a decimal move. Move the decimal to the left until have a number between 1 and 10. So, the number is 3.45698401.
Now count how many places the decimal moved. In this case, the decimal moved 6 places to the left, which means the power is positive.
The scientific notation for 3,456,984.01 is 3.45698401 x 10⁶.

Question 5.
8,694.1 _____________
Answer:
The given number 8,694.1 already has a decimal move. Move the decimal to the left until have a number between 1 and 10. So, the number is 8.6941.
Now count how many places the decimal moved. In this case, the decimal moved 3 places to the left, which means the power is positive.
The scientific notation for 8,694.1 is 8.6941 x 10³.

Question 6.
.00945 _____________
Answer:
The given number .00945 already has a decimal move. Move the decimal to the right until have a number between 1 and 10. So, the number is 9.45.
Now count how many places the decimal moved. In this case, the decimal moved 3 places to the right, which means the power is negative.
The scientific notation for .00945 is 9.45 x 10^-3.

Question 7.
1,094,659,041 _____________
Answer:
Place a decimal at the far right and move the decimal to the left until have a number between 1 and 10. So, the number is 1.094659041.
Now count how many places the decimal moved. In this case, the decimal moved 9 places to the left, which means the power is positive.
The scientific notation for 1,094,659,041 is 1.094659041 x 10⁹.

Question 8.
63.56 _____________
Answer:
The given number 63.56 already has a decimal move. Move the decimal to the left until have a number between 1 and 10. So, the number is 6.356.
Now count how many places the decimal moved. In this case, the decimal moved 1 places to the left, which means the power is positive.
The scientific notation for 63.56 is 6.356 x 10¹.

Calculate using order of operations (PEMDAS).

Question 9.
3 × (6 – 4)² + (15 – 5) × 5 + (5 – 3) × 4 + 3³ ________________
Answer:
We have to calculate the above given expression in order. The order of operation is PEMDAS. These letters stands for Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.
3 × (6 – 4)² + (15 – 5) × 5 + (5 – 3) × 4 + 3³ = ?
First solve the parts that are inside parenthesis.
3 × 2² + 10 × 5 + 2 × 4 + 3³ = ?
Second solve the parts that have exponents.
3 × 4 + 10 × 5 + 2 × 4 + 27 = ?
Third perform multiplication operation.
12 + 50 + 8 + 27 = ?
Fourth perform Addition operation.
12 + 50 + 8 + 27 = 97
So, the expression 3 × (6 – 4)² + (15 – 5) × 5 + (5 – 3) × 4 + 3³ is equal to 97.

Question 10.
17 – (9 + 5) + (5 – 3) × 2 + (9 – 4)² ________________
Answer:
We have to calculate the above given expression in order. The order of operation is PEMDAS. These letters stands for Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.
17 – (9 + 5) + (5 – 3) × 2 + (9 – 4)² = ?
First solve the parts that are inside parenthesis.
17 – 14 + 2 × 2 + 5² = ?
Second solve the parts that have exponents.
17 – 14 + 2 × 2 + 25 = ?
Third perform multiplication operation.
17 – 14 + 4 + 25 = ?
Fourth perform Addition and subtraction operation from left to right.
17 – 14 + 4 + 25 = ?
3 + 4 + 25 = 32
So, the expression 17 – (9 + 5) + (5 – 3) × 2 + (9 – 4)²  is equal to 32.

Question 11.
24 + (3 + 5) × 5 + (6 – 3)² ______________
Answer:
We have to calculate the above given expression in order. The order of operation is PEMDAS. These letters stands for Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.
24 + (3 + 5) × 5 + (6 – 3)² = ?
First solve the parts that are inside parenthesis.
24 + 8 × 5 + 3² = ?
Second solve the parts that have exponents.
24 + 8 × 5 + 9 = ?
Third perform multiplication operation.
24 + 40 + 9 = ?
Fourth perform Addition operation.
24 + 40 + 9 = 73
So, the expression 24 + (3 + 5) × 5 + (6 – 3)²  is equal to 73.

Question 12.
33 – (4 – 2)³ + 6 × 2 + (5)² – 3 ______________
Answer:
We have to calculate the above given expression in order. The order of operation is PEMDAS. These letters stands for Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.
33 – (4 – 2)³ + 6 × 2 + (5)² – 3 = ?
First solve the parts that are inside parenthesis.
33 – 2³ + 6 × 2 + (5)² – 3= ?
Second solve the parts that have exponents.
33 – 8 + 6 × 2 + 25 – 3= ?
Third perform multiplication operation.
33 – 8 + 12 + 25 – 3 = ?
Fourth perform Addition and subtraction operation from left to right.
33 – 8 + 12 + 25 – 3 = ?
25 + 12 + 25 – 3 = ?
37 + 25 – 3 = ?
62 – 3 = 59
So, the expression 33 – (4 – 2)³ + 6 × 2 + (5)² – 3 is equal to 59.

What number property does each expression display?

Question 13.
3 + 4 + 5 = 5 + 4 + 3 ______________
Answer:
The expression 3 + 4 + 5 = 5 + 4 + 3 is commutative property of addition.
Explanation:
The commutative property of addition states that the addends are added in any order without changing the sum.
3 + 4 + 5 = 12
5 + 4 + 3 = 12

Question 14.
3(4 + 6) = 3(4) + 3(6) _______________
Answer:
The expression 3(4 + 6) = 3(4) + 3(6) is Distributive property of multiplication over addition.
Explanation:
The Distributive property of multiplication over addition states that when we multiply numbers, we have to multiply the numbers each separately and then add their products.
3(4 + 6) = 30
3(4) + 3(6) = 30

Question 15.
(15 + 16) + 18 = 15 + (16 + 18) ________________
Answer:
The expression (15 + 16) + 18 = 15 + (16 + 18) is Associative property of addition.
Explanation:
The Associative property of addition states that the addends are grouped in any way without changing the sum.
(15 + 16) + 18 = 49
15 + (16 + 18) = 49

Question 16.
34(1) = 34 _______________
Answer:
The expression 34(1) = 34 is Multiplication Identity property of 1.
Explanation:
In multiplication, the identity element is 1. Any factor or factors multiplying with 1 the product will not change.
34(1) = 34

Question 17.
3 + 0 = 3 _____________
Answer:
The expression 3 + 0 = 3 is Zero Identity of Addition.
Explanation:
In addition, the identity element is 0. Any addend + 0 will not change the total.
3 + 0 = 3

Question 18.
16(5 – 3) = (16 × 5) – (16 × 3) ______________
Answer:
The expression 16(5 – 3) = (16 × 5) – (16 × 3) is Distributive property of multiplication over subtraction.
Explanation:
The Distributive property of multiplication over subtraction states that when we multiply numbers, we have to multiply the numbers each separately and then subtract their products.
16(5 – 3) = 16(2) = 32
(16 × 5) – (16 × 3) = 80 – 48 = 32

Question 19.
15 × 5 = 5 × 15 _______________
Answer:
The expression 15 × 5 = 5 × 15 is commutative property of multiplication.
Explanation:
The commutative property of multiplication states that the numbers are multiplied in any order without changing the product.
15 × 5 = 75
5 × 15 = 75

Question 20.
33(0) + (33 + 0) = 0 + 33 = 33 ______________
Answer:
The expression 33(0) + (33 + 0) = 0 + 33 = 33 is Zero property of addition and multiplication.
Explanation:
Zero property of addition and multiplication states that any addend + 0 will not change the total and any number multiplied with 0 is equal to 0.
33(0) + (33 + 0) = 0 + 33 = 33

Question 21.
(7 × 4) × 20 = 7 × (4 × 20) _____________
Answer:
The expression (7 × 4) × 20 = 7 × (4 × 20) is Associative property of Multiplication.
Explanation:
The Associative property of multiplication states that the numbers are grouped in any way without changing the product.
(7 × 4) × 20 = 560
7 × (4 × 20) = 560

Solve for x.

Question 22.
4 + x = 7
Answer:
Given equation is 4 + x = 7.
To calculate x value we need to subtract both sides of the equation with 4.
x + 4 – 4= 7 – 4
x = 3

Question 23.
x – 5 = 12
Answer:
Given equation is x – 5 = 12
To calculate x value we need to add both sides of the equation with 5.
x – 5 + 5 = 12 + 5
x = 17

Question 24.
29 – x = 25
Answer:
Given equation is 29 – x = 25
To calculate x value we need to subtract both sides of the equation with 29.
29 – x – 29 = 25 – 29
– x = -4
x = 4

Question 25.
x + 30 = 90
Answer:
Given equation is x + 30 = 90
To calculate x value we need to subtract both sides of the equation with 30.
x + 30 – 30= 90 – 30
x = 60

Question 26.
4x + 5 = 13
Answer:
Given equation is 4x + 5 = 13
To calculate x value first we need to perform subtraction operation and then division operation.
Subtract 5 from 13 the difference is equal to 8.
4x = 13 – 5
4x = 8
x = 8/4
x = 2

Question 27.
3x – 5 = 13
Answer:
Given equation is 3x – 5 = 13
To calculate x value first we need to perform addition operation and then division operation.
Add 13 with 5 the sum is equal to 18
3x = 13 + 5
3x = 18
x = 18/3
x = 6

Question 28.
5x + 4 = 39
Answer:
Given equation is 5x + 4 = 39
To calculate x value first we need to perform subtraction operation and then division operation.
Subtract 4 from 39 the difference is equal to 35.
5x = 39 – 4
5x = 35
x = 35/5
x = 7

Question 29.
3x + 4 = 28
Answer:
Given equation is 3x + 4 = 28
To calculate x value first we need to perform subtraction operation and then division operation.
Subtract 4 from 28 the difference is equal to 24.
3x = 28 – 4
3x = 24
x = 24/3
x = 8

Question 30.
-4x + 4 = -28
Answer:
Given equation is -4x + 4 = -28
To calculate x value first change all numbers to one sides and variable to another side.
28 + 4 = 4x
Second perform addition operation and then division operation.
32 = 4x
32/4 = x
x = 8

Question 31.
\(\frac{x}{4}\) + 5 = 25
Answer:
Given equation is \(\frac{x}{4}\) + 5 = 25
To calculate x value first we have to perform subtraction operation and then multiplication operation.
\(\frac{x}{4}\) = 25 – 5
\(\frac{x}{4}\) = 20
x = 20 x 4
x = 80

Question 32.
\(\frac{x}{2}\) – 5 = 30
Answer:
Given equation is \(\frac{x}{2}\) – 5 = 30
To calculate x value first we have to perform addition operation and then multiplication operation.
\(\frac{x}{2}\) = 30 + 5
\(\frac{x}{2}\) = 35
x = 35 x 2
x = 70

Question 33.
\(\frac{2}{3}\)x – 4 = 26
Answer:
Given equation is \(\frac{2}{3}\)x – 4 = 26
To calculate x value first we have to perform addition operation, second multiplication operation and then division operation.
\(\frac{2}{3}\)x = 26 + 4
\(\frac{2}{3}\)x = 30
2x = 30 x 3
2x = 90
x = 90/2
x = 45

Find all the factors.

Question 34.
24
Answer:
The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24.
Explanation:
The numbers that divide 24 exactly without leaving a remainder are the factors of 24. The number 24 is an even number. The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24.

Question 35.
15
Answer:
The factors of 15 are 1, 3, 5 and 15.
Explanation:
The numbers that divide 15 exactly without leaving a remainder are the factors of 15. The number 15 is an odd number. The factors of 15 are 1, 3, 5 and 15.

Question 36.
20
Answer:
The factors of 20 are 1, 2, 4, 5, 10 and 20.
Explanation:
The numbers that divide 20 exactly without leaving a remainder are the factors of 20. The number 20 is an even number. The factors of 20 are 1, 2, 4, 5, 10 and 20.

Question 37.
8
Answer:
The factors of 8 are 1, 2, 4 and 8.
Explanation:
The numbers that divide 8 exactly without leaving a remainder are the factors of 8. The number 8 is an even number. The factors of 8 are 1, 2, 4 and 8.

Question 38.
13
Answer:
The factors of 13 are 1, 13.
Explanation:
The numbers that divide 13 exactly without leaving a remainder are the factors of 13. The number 13 is an odd number. The factors of 13 are 1,13.

Question 39.
21
Answer:
The factors of 21 are 1, 3, 7 and 21.
Explanation:
The numbers that divide 21 exactly without leaving a remainder are the factors of 21. The number 21 is an odd number. The factors of 21 are 1, 3, 7 and 21.

List the first five multiples.

Question 40.
5
Answer:
The first five multiples of 5 are 5,10,15, 20, 25.

Question 41.
3
Answer:
The first five multiples of 3 are 3, 6, 9, 12, 15.

Question 42.
7
Answer:
The first five multiples of 7 are 7,14, 21, 28, 35.

Question 43.
11
Answer:
The first five multiples of 11 are 11, 22, 33, 44, 55.

Solve the inequalities.

Question 44.
2x ≤ 14
Answer:
The given equation is 2x ≤ 14.
Divide both sides of the equation by 2.
2x/2 ≤ 14/2
x ≤ 7
The value of x should be less than or equal to 7.

Question 45.
x + 8 ≥ 2
Answer:
The given equation is x + 8 ≥ 2.
Subtract both sides of the equation with 8.
x + 8 – 8 ≥ 2 – 8
x ≥ – 6
The value of x should be greater than or equal to -6.

Question 46.
3 < \(\frac{x}{6}\)
Answer:
The given equation is 3 < \(\frac{x}{6}\).
Multiply both sides of the equation with 6.
3 x 6 < \(\frac{x}{6}\) x 6
18 < x
The value of x should be greater than 18.

Question 47.
x – 7 > 4
Answer:
The given equation is x – 7 > 4.
Add both sides of the equation with 7.
x – 7 + 7 > 4 + 7
x > 11
The value of x should be greater than 11.

Question 48.
x + 3x > 16
Answer:
The given equation is x + 3x > 16.
4x > 16
Divide both sides of the equation by 4.
4x/4 > 16/4
x > 4
The value of x should be greater than 4.

Question 49.
Elba has four tiles marked 1, 2, 3, and 4. If she needs to choose a tile that solves the equation x – 1 > 2, which one will she choose?
Answer:
Elba has four tiles marked 1, 2, 3, and 4.
If she choose a tile 1 then the equation becomes 0 > 2. So, she will not choose tile 1.
If she choose a tile 2 then the equation becomes 1 > 2. So, she will not choose tile 2.
If she choose a tile 3 then the equation becomes 2 > 2. So, she will not choose tile 3.
If she choose a tile 4 then the equation becomes 3 > 2. So, she will choose tile 4.

Question 50.
Vicki’s mother tells her to pack at least 4 shirts for a trip. Write an inequality that expresses that command, using the letter x for the number of shirts.
Answer:
Vicki’s mother tells her to pack at least 4 shirts for a trip. Which means 4 shirts or more.
The inequality that expresses the command is x ≥ 4.