Rama

Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length

Learn the multiple ways to solve a problem using Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length. Top math experts are worked to provide the best and simple solutions for students. The students who want to prepare math easily, they can use the Go Math Grade 6 Chapter 6 Convert Units of Length Solution Key. Learn Online maths using HMH Go Math Grade 6 Answer Key.

Go Math Grade 6 Chapter 6 Convert Units of Length Answer Key

You can find the ultimate guide to learn the Convert Units of Lengths i.e, HMH Go Math Grade 6 Answer Key. Start enjoying maths with the help of Go Math Grade 6 Convert Units of Length Answer Key. Go Math Grade 6 Chapter 6 Convert Units of Length Solution Key is free. So, quickly begin your practice by getting your Grade 6 Go Math Answer Key PDF Now.

Lesson 1: Convert Units of Length

Lesson 2: Convert Units of Capacity

Lesson 3: Convert Units of Weight and Mass

Mid-Chapter Checkpoint

Lesson 4: Transform Units

Lesson 5: Problem Solving • Distance, Rate, and Time Formulas

Chapter 6 Review/Test

Share and Show – Page No. 317

Convert to the given unit.

Question 1.
3 miles = ? yards
_______ yd

Answer:
5280 yd

Explanation:
3 miles = ? yards
1 yard = 3 feet
1 mile = 5280 feet
So, 3 miles = 3 x 5280 feet
= 15,840 feet
3 feet = 1 yard
Then, 15,840 feet = 15,840 ÷ 3
= 5280 yards
So, 3 miles = 5280 yards

Question 2.
43 dm = ? hm
_______ hm

Answer:
0.043 hm

Explanation:
43 dm= ?hm
10 decimeters = 1 meter
1 hectometer = 100 meters
1 meter = 10 decimeter
100 meters = 10×100 decimeters = 1000 decimeters
So 1 hectometer = 1000 decimeters
Then, 43 decimeters = 43/1000 = 0.043 hectometers
So, 43 dm = 0.043 hm

Question 3.
9 yd = ? in.
_______ inches

Answer:
324 inches

Explanation:
9 yd= ? in.
1 yard = 36 inches
So 9 yards = 9×36 = 324 inches
9 yards = 324 inches

Question 4.
72 ft = 24 yd
_______ yd

Answer:
24 yd

Explanation:
72 ft = 24 yd
1 yard = 3 feet
So, 1 feet = 1/3 yard
Then, 72 feet = 72/3 yard
So, 72 feet = 24 yards

Question 5.
7,500 mm = ? dm
_______ dm

Answer:
75 dm

Explanation:
7,500 mm = ?dm
1000 millimeters = 1 meter
10 decimeters = 1 meter
So, 1000 millimeters = 10 decimeters
Then 1 millimeter = 10/1000 decimeter = 1/100 decimeters
So 7500 millimeters = 7500/100 decimeters
Then 7500 mm = 75 dm

On Your Own

Question 6.
Rohan used 9 yards of ribbon to wrap gifts. How many inches of ribbon did he use?
_______ inches

Answer:
324 inches

Explanation:
As per the given data,
Rohan used 9 yards of ribbon to wrap gifts
1 yard = 36 inches
So, 9 yards = 9×36 = 324 inches
So, Rohan used 324 inches of ribbon to wrap gifts

Lesson 6 Classwork 6.1 Question 7.
One species of frog can grow to a maximum length of 12.4 millimeters. What is the maximum length of this frog species in centimeters?
_______ cm

Answer:
1.24 cm

Explanation:
One species of frog can grow to a maximum length of 12.4 millimeters.
From the given information
One species of frog can grow to a maximum length of 12.4 millimeters
1000 millimeters = 1 meter
100 centimeters = 1 meter
So, 1000 millimeters = 100 centimeters
1 millimeter = 100/1000 centimeters = 1/10 centimeters
So, 12.4 millimeters = 12.4/10 centimeters = 1.24 centimeters
12.4 millimeters = 1.24 centimeters

Question 8.
The height of the Empire State Building measured to the top of the lightning rod is approximately 443.1 meters. What is this height in hectometers?
_______ hectometers

Answer:
4.431 hectometers

Explanation:
The height of the Empire State Building measured to the top of the lightning rod is approximately 443.1 meters.
443.1 meters in hectometers
1 hectometer = 100 meters
Then, 1 meter = 1/100 hectometers
So, 443.1 meters = 443.1/100 hectometers
443.1 meters = 4.431 hectometers

Question 9.
A snail moves at a speed of 2.5 feet per minute. How many yards will the snail have moved in half of an hour?
_______ yards

Answer:
25 yards

Explanation:
From the given information
A snail moves at a speed of 2.5 feet per minute
1 hour = 60 minutes
1 minute = 2.5 feet speed
60 minutes = 60×2.5 feet = 150 feet
1 yard = 3 feet
So 1 feet = 1/3 yards
Then, 150 feet = 150/3 yards = 50 yards per hour
For half of an hour, a snail moves 25 yards

Practice: Copy and Solve Compare. Write <, >, or =.

Question 10.
32 feet _______ 11 yards

Answer:
32 feet < 11 yards

Explanation:
32 feet _______ 11 yards
1 yard = 3 feet
So, 11 yards = 11×3 = 33 feet
So, 32 feet < 11 yards

Question 11.
537 cm _______ 5.37 m

Answer:
537 cm = 5.37 m

Explanation:
537 cm _______ 5.37 m
100 centimeters = 1 meter
1 centimeter = 0.01 meter
So, 537 centimeters = 537×0.01 meters
That is 537 centimeters = 5.37 meters

Question 12.
75 inches _______ 6 feet

Answer:
75 inches > 6 feet

Explanation:
75 inches _______ 6 feet
1 foot = 12 inches
6 feet = 6×12 = 72 inches
So, 75 inches > 6 feet

Problem Solving + Applications – Page No. 318

What’s the Error?

Question 13.
The Redwood National Park is home to some of the largest trees in the world. Hyperion is the tallest tree in the park, with a height of approximately 379 feet. Tom wants to find the height of the tree in yards.
Tom converted the height this way :
3 feet = 1 yard
conversion factor: \(\frac{3 \mathrm{ft}}{1 \mathrm{yd}}\)
\(\frac{379 \mathrm{ft}}{1} \times \frac{3 \mathrm{ft}}{1 \mathrm{yd}}\) = 1,137 yd
Find and describe Tom’s error.
Show how to correctly convert from 379 feet to yards.
Explain how you knew Tom’s answer was incorrect.
Type below:
____________

Answer:
conversion factor: 3ft1yd
379ft1 × 3ft1yd = 1,137 yd
We need to divide the 379 feet with 3 to get the height of the Hyperion tree, but tom multiplies the 379 with 3 and that is the error part
1 yard = 3 feet
1 feet = 1/3 yards
So, 379 feet = 379/3 yards = 126.3 yards
So, the height of the Hyperion tree is 126.3 yards

Question 14.
Choose <, >, or =.
14a. 12 yards Ο 432 inches
14b. 321 cm Ο 32.1 m
12 yards _______ 432 inches
321 cm _______ 32.1 m

Answer:
14a. 12 yards Ο 432 inches
14b. 321 cm Ο 32.1 m
12 yards = 432 inches
321 cm < 32.1 m

Explanation:
14a. 12 yards Ο 432 inches
1 yard = 36 inches
12 yards = 12×36 = 432 inches
So, 12 yards = 432 inches
14b. 321 cm Ο 32.1 m
100 centimeters = 1 meter
1 centimeter = 0.01 meter
321 centimeters = 321×0.01 meters = 3.21 meters
3.21 < 32.1
So, 321 centimeters < 32.1 meters

Convert Units of Length – Page No. 319

Convert to the given unit.

Question 1.
42 ft = ? yd
_______ yd

Answer:
14yd

Explanation:
42 ft= ?yd
3 feet = 1 yard
1 feet = 1/3 yard
So, 42 feet = 42/3 = 14 yard
So, 42 feet = 14 yards

Question 2.
2,350 m = ? km
_______ km

Answer:
2.350 km

Explanation:
2,350 m = ? km
1 kilometer = 1000 meters
1 meter = 1/1000 kilometers
Then, 2350 meters = 2350/1000 kilometers
2350 meters = 2.350 kilometers

Question 3.
18 ft = ? in.
_______ inches

Answer:
216 inches

Explanation:
18 ft= ? in
1 foot = 12 inches
18 feet = 12×18 = 216 inches
18 feet = 216 inches

Question 4.
289 m = ? dm
_______ dm

Answer:
2890 dm

Explanation:
289 m = ?dm
10 decimeters = 1 meter
289 meters = 289×10 decimeters
So, 289 meters = 2890 decimeters

Question 5.
5 mi = ? yd
_______ yd

Answer:
8,800 yd

Explanation:
1. 5 mi = ? yd
1 mile = 1760 yards
5 miles = 5×1760 = 8800 yards
5 mi = 8,800 yards

Chapter 6 Lesson 1 Answer Key Question 6.
35 mm = ? cm
_______ cm

Answer:
3.5 cm

Explanation:
35 mm = ? cm
1000 millimeters = 1 meter
100 centimeters = 1 meter
So, 1000 millimeters = 100 centimeters
1 millimeter = 100/1000 centimeters
Then, 35 millimeters = 35×100/1000 centimeters = 3.5 centimeters
35 millimeters = 3.5 centimeters

Compare. Write <, >, or =.

Question 7.
1.9 dm _______ 1,900 mm

Answer:
1.9 dm < 1,900 mm

Explanation:
1.9 dm _______ 1,900 mm
10 decimeters = 1 meter
1000 millimeters = 1 meter
So, 10 decimeters = 1000 millimeters
1 decimeter = 100 millimeters
1.9 decimeters = 1.9 x 100 = 190 millimeters
So, 1.9 decimeters = 190 millimeters
So, 1.9 dm < 1900 mm

Question 8.
12 ft _______ 4 yd

Answer:
12 ft  = 4 yd

Explanation:
12 ft _______ 4 yd
3 feet = 1 yard
3×4 feet = 12 feet = 1×4 = 4 yard
So, 12 feet = 4 yards

Question 9.
56 cm _______ 56,000 km

Answer:
56 cm < 56,000 km

Explanation:
56 cm _______ 56,000 km
100 centimeters = 1 meter
1 kilometer = 1000 meters
0.01 kilometer = 1 meter
So, 100 centimeters = 0.01 kilometers
1 centimeter = 0.01/100 kilometers
56 centimeters = 56 x 0.01/100 kilometers =0.0056 kilometers
So, 56 cm < 56,000 km

Question 10.
98 in. _______ 8 ft

Answer:
98 in. > 8 ft

Explanation:
98 in. _______ 8 ft
1 foot = 12 inches
8 feet = 8×12 = 96 inches
So, 98 in > 8 feet

Question 11.
64 cm _______ 630 mm

Answer:
64 cm  > 630 mm

Explanation:
64 cm _______ 630 mm
1000 millimeters = 1 meter
100 centimeters = 1 meter
So, 100 centimeters = 1000 millimeters
1 centimeter = 10 millimeters
so, 64 centimeters = 64×10 millimeters = 640 millimeters
then, 64 cm > 630 mm

Question 12.
2 mi _______ 10,560 ft

Answer:
2 mi  = 10,560 ft

Explanation:
1 mi _______ 10,560 ft
1 mile = 5280 feet
so, 2 miles = 2×5280 = 10560 feet
then, 2 miles = 10,560 feet

Question 13.
The giant swallowtail is the largest butterfly in the United States. Its wingspan can be as large as 16 centimeters. What is the maximum wingspan in millimeters?
_______ mm

Answer:
160 mm

Explanation:
The giant swallowtail is the largest butterfly in the United States. Its wingspan can be as large as 16 centimeters.
100 centimeters = 1 meter
1000 millimeters = 1 meter
So, 100 centimeters = 1000 millimeters
1 centimeters = 10 millimeters
then 16 centimeters = 16×10 millimeters = 160 millimeters
So, giant swallowtail wingspan is 160 millimeters large

Lesson 6 Exit Ticket 6.1 Answer Key Question 14.
The 102nd floor of the Sears Tower in Chicago is the highest occupied floor. It is 1,431 feet above the ground. How many yards above the ground is the 102nd floor?
_______ yd

Answer:
477 yd

Explanation:
The 102nd floor of the Sears Tower in Chicago is the highest occupied floor. It is 1,431 feet above the ground.
3 feet = 1 yard
1 feet = 1/3 yard
Then, 1431 feet = 1431/3 yard = 477 yards
So, the height of the 102nd floor from the ground = 477 yards

Question 15.
Explain why units can be simplified first when measurements are multiplied.
Type below:
____________

Answer:
Units can be simplified first, because if (60 min)/(1 hr) = 1, then I can multiply any measurement by that fraction and not change its value.

Lesson Check – Page No. 320

Question 1.
Justin rides his bicycle 2.5 kilometers to school. Luke walks 1,950 meters to school. How much farther does Justin ride to school than Luke walks to school?
_______ meters

Answer:
550 meters

Explanation:
Justin rides his bicycle 2.5 kilometers to school. Luke walks 1,950 meters to school.
1 kilometer = 1000 meters
Then, 2.5 kilometers = 2.5 x 1000 = 2500 meters
So, Justin rides his bicycle 2500 meters and Luke walks 1950 meters
2500 – 1950 = 550 meters
So, Justin rides more 550 meters than Luke to school

Lesson 6 Practice Problems Answer Key Grade 6 Question 2.
The length of a room is 10 \(\frac{1}{2}\) feet. What is the length of the room in inches?
_______ inches

Answer:
126 inches

Explanation:
1 feet = 12 inches
10 1/2 feet = ?
10 1/2 = 21/2
21/2 × 12 = 21 × 6 = 126
126 inches

Spiral Review

Question 3.
Each unit on the map represents 1 mile. What is the distance between the campground and the waterfall?
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 1
_______ miles

Answer:
4 miles

Explanation:
Each unit on the map represents 1 mile
The distance between the campground and the waterfall is 4 units that is 4 miles

Question 4.
On a field trip, 2 vans can carry 32 students. How many students can go on a field trip when there are 6 vans?
_______ students

Answer:
96 students

Explanation:
On a field trip, 2 vans can carry 32 students
So, 1 van can carry the students = 32/2 = 16 students
Then, students can go in 6 vans = 6×16 = 96 students

Question 5.
According to a 2008 survey, \(\frac{29}{50}\) of all teens have sent at least one text message in their lives. What percent of teens have sent a text message?
_______ %

Answer:
58%

Explanation:
From the given information
According to a 2008 survey
29/50 of all teens have sent at least one text message in their lives
Percent of teens have sent a text message = 29/50 x 100 = 58%
So, 58% of teens have sent text messages

Question 6.
Of the students in Ms. Danver’s class, 6 walk to school. This represents 30% of her students. How many students are in Ms. Danver’s class?
_______ students

Answer:
20 students

Explanation:
Of the students in Ms. Danver’s class, 6 walk to school
It represents 30% of her students
That is 30% = 6 students
Then 100% = (100×6)/30 = 20
Total number of students in Ms. Danver’s class = 20 students

Share and Show – Page No. 323

Convert to the given unit.

Question 1.
5 quarts = ? cups
_______ cups

Answer:
20 cups

Explanation:
5 quarts = ? cups
4cups = 1 quart
So, 5 quarts = 5×4 = 20 cups
5 quarts = 20 cups

Question 2.
6.7 liters = ? hectoliters
_______ hectoliters

Answer:
0.067 hectoliters

Explanation:
1.7 liters = ? hectoliters
1 hectoliter= 100 liters
1 liter = 1/100 hectoliters
6.7 liters = 6.7/100 hectoliters = 0.067 hectoliters

Question 3.
5.3 kL = ? L
_______ L

Answer:
5300 L

Explanation:
5.3 kL= ? L
1 Kiloliter = 1000 liters
Then, 5.3 kiloliters = 5.3 x 1000 = 5300 liters
So, 5.3 kL = 5300 L

Question 4.
36 qt = ? gal
_______ gal

Answer:
9 gal

Explanation:
36 qt = ? gal
4 quarts = 1 gallon
So, 36 qts = 9×4 quarts = 9×1 gallons
So, 36 qt = 9 gallons

Convert Units of Capacity Lesson 6.2 Homework Answers Question 5.
5,000 mL = ? cL
_______ cL

Answer:
500 cL

Explanation:
5,000 mL = ?cL
1000 milliliters = 1 liter
100 centiliters = 1 liter
So, 1000 milliliters = 100 centiliters
Then, 5000 milliliters = 5×100 centiliters = 500 centiliters
5000 milliliters = 500 centiliters

On Your Own

Question 6.
It takes 41 gallons of water for a washing machine to wash a load of laundry. How many quarts of water does it take to wash one load?
_______ quarts

Answer:
164 quarts

Explanation:
It takes 41 gallons of water for a washing machine to wash a load of laundry.
41 gallons of water is required for a washing machine to wash a load of laundry
1 gallon = 4 quarts
Then, 41 gallons = 41×4 quarts = 164 quarts
164 quarts of water us required for a washing machine to wash a load of laundry

Question 7.
Sam squeezed 237 milliliters of juice from 4 oranges. How many liters of juice did Sam squeeze?
_______ L

Answer:
0.237 L

Explanation:
Sam squeezed 237 milliliters of juice from 4 oranges
1000 liliters = 1 liter
1 milliliter = 1/1000 liter
237 milliliters = 237/1000 liters
237 milliliters = 0.237 liters

Question 8.
Reason Quantitatively A bottle contains 3.78 liters of water. Without calculating, determine whether there are more or less than 3.78 deciliters of water in the bottle. Explain your reasoning
Type below:
____________

Answer:
Reason Quantitatively A bottle contains 3.78 liters of water
1 liter = 10 deciliters
Then 3.78 liters = 3.78×10 = 37.8 deciliters
So, bottle contains more than 3.78 deciliters of water

Question 9.
Tonya has a 1-quart, a 2-quart, and a 3-quart bowl. A recipe asks for 16 ounces of milk. If Tonya is going to triple the recipe, what is the smallest bowl that will hold the milk?
The _______ bowl

Answer:
The 3 quarts bowl

Explanation:
Tonya has a 1-quart, a 2-quart, and a 3-quart bowl
A recipe asks for 16 ounces of milk
If Tonya triples the recipe, then 1 quart = 3, 2 quart = 6, 3 quart = 9
The smallest bowl is 3 quarts

Practice: Copy and Solve Compare. Write <, >, or =.

Question 10.
700,000 L _______ 70 kL

Answer:
700,000 L > 70 kL

Explanation:
700,000 L _______ 70 kL
1 kiloliter = 1000 liters
Then, 70 kiloliters = 70×1000 liters = 70,000 liters
So, 700,000 liters > 70 kiloliters

Question 11.
6 gal _______ 30 qt

Answer:
6 gal < 30 qt

Explanation:
6 gal _______ 30 qt
4 quarts = 1 gallon
So, 6 gallons = 6×4 = 24 quarts
So, 6 gallons < 30 quarts

Question 12.
54 kL _______ 540,000 dL

Answer:
54 kL  = 540,000 dL

Explanation:
54 kL _______ 540,000 dL
1 kiloliter = 1000 liters
1 liter = 10 deciliters
Then, 1000 liters = 10×1000 = 10,000 deciliters
So, 1 kiloliter = 10,000 deciliters
Then, 54 kiloliters = 54×10,000 = 540,000 deciliters
So, 54 kL = 540,000 dL

Lesson 6.2 Answer Key 6th Grade Question 13.
10 pt _______ 5 qt

Answer:
10 pt  = 5 qt

Explanation:
10 pt _______ 5 qt
1 pints = 1 quart
then, 10 pints = 2×5 pints = 1×5 quart = 5 quarts
So, 10 pints = 5 quarts

Question 14.
500 mL _______ 50 L

Answer:
500 mL  < 50 L

Explanation:
500 mL _______ 50 L
1000 milliliters = 1 liter
Then, 1000/2 milliliters = 500 milliliters = ½ liters= 0.5 liters
So, 500 mL < 50 L

Question 15.
14 c _______ 4 qt

Answer:
14 c  < 4 qt

Explanation:

14 c _______ 4 qt
4 cups = 1 quart
1 cup = ¼ quart
Then, 14 cups = 14/4 quarts = 3.5 quarts
So, 14 cups < 4 quarts

Unlock the Problem – Page No. 324

Question 16.
Jeffrey is loading cases of bottled water onto a freight elevator. There are 24 one-pint bottles in each case. The maximum weight that the elevator can carry is 1,000 pounds. If 1 gallon of water weighs 8.35 pounds, what is the maximum number of full cases Jeffrey can load onto the elevator?
a. What do you need to find?
Type below:
____________

Answer:
The maximum number of full cases Jeffrey can load onto the elevator

Question 16.
b. How can you find the weight of 1 case of bottled water? What is the weight?
Type below:
____________

Answer:
Using one-pint bottles and 1 gallon of water weighs 8.35 pounds Information

Explanation:

Question 16.
c. How can you find the number of cases that Jeffrey can load onto the elevator?
Type below:
____________

Answer:
1 US liquid pint is equivalent to 0.125 US liquid gallons.
So, 24 one-pint bottles is equivalent to (24 × 0.125) =3 gallons.
Therefore, one full case of bottled water is equal to 3 gallons.
Now, 1 gallon is equal to 8.35 pounds
And hence, 3 gallons is equal to (8.35 × 3) = 25.05 pounds.

Question 16.
d. What is the maximum number of full cases Jeffrey can load onto the elevator?
_______ cases

Answer:
39 cases

Explanation:
1 US liquid pint is equivalent to 0.125 US liquid gallons.
So, 24 one-pint bottles is equivalent to (24 × 0.125) =3 gallons.
Therefore, one full case of bottled water is equal to 3 gallons.
Now, 1 gallon is equal to 8.35 pounds
And hence, 3 gallons is equal to (8.35 × 3) = 25.05 pounds.
If the maximum weight that the elevator can carry is 1000 pounds, then the maximum number of cases of bottled water that the elevator can carry is ≈ 39
We can not take the number as 40, because then the total weight will become more than 1000 pounds which is not allowed.

Lesson 6 Classwork 6.2 Answer Key Question 17.
Monica put 1 liter, 1 deciliter, 1 centiliter, and 1 milliliter of water into a bowl. How many milliliters of water did she put in the bowl?
_______ milliliters

Answer:
1111 milliliters

Explanation:
Monica put 1 liter, 1 deciliter, 1 centiliter, and 1 milliliter of water into a bowl
1 liter = 1000 milliliters
1 liter = 10 deciliters
so, 10 deciliters = 1000 milliliters
then, 1 deciliter = 100 milliliters
1 liter = 100 centiliters
So, 100 centiliters = 1000 milliliters
Then, 1 centiliter = 10 milliliters
1 liter + 1 deciliter + 1 centiliter + 1 milliliter
= 1000 milliliters + 100 milliliters + 10 milliliters + 1 milliliter
= 1111 milliliters
Monica filled the bowl with 1111 milliliters of water

Question 18.
Select the conversions that are equivalent to 235 liters. Mark all that apply.
Options:
a. 235,000 milliliters
b. 0.235 milliliters
c. 235,000 kiloliters
d. 0.235 kiloliters

Answer:
a. 235,000 milliliters

Explanation:
a. 235,000 milliliters
1000 milliliters = 1 liter
Then, 235×1000 milliliters = 1×235 liters = 235 liters
So, 235,000 milliliters are equivalent to 235 liters

Convert Units of Capacity – Page No. 325

Convert to the given unit.

Question 1.
7 gallons = ? quarts
_______ quarts

Answer:
28 quarts

Explanation:
6 gallons = ? quarts
4 quarts = 1 gallon
then, 7 gallons = 4×7 = 28 quarts

Question 2.
5.1 liters = ? kiloliters
_______ kiloliters

Answer:
0.0051 kiloliters

Explanation:
5.1 liters = ? kiloliters
1 kiloliter = 1000 liters
So, 1 liter = 1/1000 kiloliter
Then, 5.1 liters = 5.1/1000 kiloliters
5.1 liters = 0.0051 kiloliters

Question 3.
20 qt = ? gal
_______ gal

Answer:
5 gal

Explanation:
20 t = ? gal
4 quarts = 1 gallon
Then, 4×5 quarts = 1×5 gallons
That is 20 quarts = 5 gallons

Question 4.
40 L = ? mL
_______ mL

Answer:
40,000 mL

Explanation:
40 L = ? mL
1000 milliliters = 1 liter
Then, 40 liters = 40×1000 milliliters = 40,000 milliliters
40 L = 40,000 mL

Question 5.
33 pt = ? qt ? pt
_______ qt _______ pt

Answer:
33/2 quarts = 16.5 quarts

Explanation:
33 pt= ?qt ? pt
1 pints = 1 quart
1 pint = ½ quart
then, 33 pint = 33/2 quarts = 16.5 quarts

Question 6.
29 cL = ? daL
_______ daL

Answer:
0.029 daL

Explanation:
29 cL = ? daL
100 centiliters = 1 liter
1 dekaliter = 10 liters
So, 1 liter = 1/10 dekaliters
Then, 100 centiliters = 1/10 dekaliters
1 centiliter = 1/1000 dekaliters
then, 29 centiliters = 29/1000 dekaliters = 0.029 dekaliters
29 cL = 0.029 daL

Lesson 6 Problem Set 6.2 Answer Key Question 7.
7.7 kL = ? cL
_______ cL

Answer:
7,70,000 cL

Explanation:
6.7 kL = ? cL
1 kiloliter = 1000 liters
100 centiliters = 1 liter
So, 1000 liters = 100×1000 centiliters = 1,00,000 centiliters
Then, 1 kiloliter = 1,00,000 centiliters
Then, 7.7 kiloliters = 7.7 x 1,00,000 centiliters = 7,70,000 centiliters

Question 8.
24 fl oz = ? pt ? c
_______ pt _______ c

Answer:
3/2 pt and 3 cups

Explanation:
24 floz= ?pt ? c
6 fluids ounces = 1 cup
then, 24 fluid ounces = 8×3 = 1×3 cups = 3 cups
1 cups = 1 pint
then, 1 cup = ½ pint
then, 3 cups = 3/2 pint
so, 24 fluids ounces = 3/2 pint and 3 cups

Problem Solving

Question 9.
A bottle contains 3.5 liters of water. A second bottle contains 3,750 milliliters of water. How many more milliliters are in the larger bottle than in the smaller bottle?
_______ mL

Answer:
250 mL

Explanation:
A bottle contains 3.5 liters of water. A second bottle contains 3,750 milliliters of water.
A bottle contains 3.5 liters of water
A second bottle contains 3,750 milliliters of water
1000 milliliters = 1 liter
Then, 3.5 liters = 3.5×1000 = 3500 milliliters
So, 3750 – 3500 = 250 milliliters
250 milliliters of water is more than in the larger bottle than the smaller bottle

Question 10.
Arnie’s car used 100 cups of gasoline during a drive. He paid $3.12 per gallon for gas. How much did the gas cost?
$ _______

Answer:
$19.5

Explanation:
Arnie’s car used 100 cups of gasoline during a drive. He paid $3.12 per gallon for gas.
Arnie’s car used 100 cups of gasoline during a drive
He paid $3.12 per gallon for gas
1 gallon = 4 quarts
1 quart = 4 cups
then, 4 quarts = 4×4 cups = 16 cups
So, 1 gallon = 16 cups
Then, 1 cup = 1/16 gallons
Then, 100 cups = 100/16 gallons = 6.25 gallons
Total gas cost = $3.12 x 6.25 = $19.5

Question 11.
Explain how units of length and capacity are similar in the metric system.
Type below:
____________

Answer:
In the metric system, The unit of length is a meter (m) and the unit of capacity is the liter (L)

Lesson Check – Page No. 326

Question 1.
Gina filled a tub with 25 quarts of water. What is this amount in gallons and quarts?
_______ gallons _______ quart

Answer:
6 gallons and 1 quart

Explanation:
Gina filled a tub with 25 quarts of water
4quarts = 1 gallon
1 quart = ¼ gallon
25 quarts = 25/4 gallon = 6 gallons and 1 quart
Gina filled a tub with 6 gallons and 1 quart

Question 2.
Four horses are pulling a wagon. Each horse drinks 45,000 milliliters of water each day. How many liters of water will the horses drink in 5 days?
_______ liters

Answer:
900 liters

Explanation:
Four horses are pulling a wagon
Each horse drinks 45,000 milliliters of water each day
Then, four horses drinks 4×45,000 milliliters = 1,80,000
1000 milliliters = 1 liter
Then, 180×1000 = 1,80,000 milliliters = 180 liters
180 x 5 = 900 liters
Horses drink 900 liters of water in 5 days

Spiral Review

Question 3.
The map shows Henry’s town. Each unit represents 1 kilometer. After school, Henry walks to the library. How far does he walk?
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 2
_______ kilometers

Answer:
7 kilometers

Explanation:
The map shows Henry’s town. Each unit represents 1 kilometer. After school, Henry walks to the library.
Each unit represents 1 kilometer
After school, Henry walks to the library
Distance between school and library = 7 kilometers
So, henry walks 7 kilometers from school to library

Question 4.
An elevator travels 117 feet in 6.5 seconds. What is the elevator’s speed as a unit rate?
_______ feet per second

Answer:
18 feet per second

Explanation:
An elevator travels 117 feet in 6.5 seconds.
The elevator’s speed as a unit rate = 117/6.5 = 18 feet per second

Question 5.
Julie’s MP3 player contains 860 songs. If 20% of the songs are rap songs and 15% of the songs are R&B songs, how many of the songs are other types of songs?
_______ songs

Answer:
559 songs

Explanation:
Julie’s MP3 player contains 860 songs
20% of the songs are rap songs = 860×20/100 = 172
15% of the songs are R & B songs = 860×15/100 = 129
Other types of songs = 860 – 172-129 = 559

Question 6.
How many kilometers are equivalent to 3,570 meters?
_______ kilometers

Answer:
3.57 kilometers

Explanation:
1 kilometer = 1000 meters
then,1 meter = 1/1000 kilometer
So, 3570 meters = 3570/1000 kilometer
3570 meters = 3.57 kilometers

Share and Show – Page No. 329

Convert to the given unit.

Question 1.
9 pounds = ? ounces
_______ ounces

Answer:
144 ounces

Explanation:
6 pounds = ? ounces
1 pound = 16 ounces
then, 9 pounds = 9×16 ounces = 144 ounces

Question 2.
3.77 grams = ? dekagram
_______ dekagram

Answer:
0.377 dekagram

Explanation:
3.77 grams = ? dekagram
1 dekagram = 10 grams
1 gram = 1/10 dekagram
Then, 3.77 grams = 3.77/10 dekagram = 0.377 dekagram
So, 3.77 grams = 0.377 dekagram

Question 3.
Amanda’s computer weighs 56 ounces. How many pounds does it weigh?
_______ pounds

Answer:
3.5 pounds

Explanation:
Amanda’s computer weighs 56 ounces
1 pound = 16 ounces
then, 1 ounce = 1/16 pound
So, 56 ounces = 56/16 pounds = 3.5 pounds

Question 4.
A honeybee can carry 40 mg of nectar. How many grams of nectar can a honeybee carry?
_______ grams

Answer:
0.04 grams

Explanation:
A honeybee can carry 40 mg of nectar.
1000 milligrams = 1 gram
1 milligram = 1/1000 grams
Then, 40 milligrams = 40/1000 grams = 0.04 grams
So, the honeybee can carry 0.04 grams of nectar

On Your Own

Convert to the given unit.

Question 5.
4 lb = ? oz
_______ oz

Answer:
64 oz

Explanation:
4lb = ?oz
1 pound (lb) = 16 ounces
then, 4 pounds = 4×16 ounces = 64 ounces

Question 6.
7.13 g = ? cg
_______ cg

Answer:
713 cg

Explanation:
7.13g = ? cg
100 centigrams = 1 gram
Then, 7.13 grams = 100×7.13 = 713 centigrams
So, 7.13 grams = 713 centigrams

Question 7.
3 T = ? lb
_______ lb

Answer:
6000 lb

Explanation:
3T = ?lb
1 ton = 2000 pounds (lb)
then, 3 tons = 3×2000 = 6000 pounds (lb)

Question 8.
The African Goliath frog can weigh up to 7 pounds. How many ounces can the Goliath frog weigh?
_______ ounces

Answer:
112 ounces

Explanation:
The African Goliath frog can weigh up to 7 pounds.
1 pound = 16 ounces
7 pounds = 7×16 = 112 pounds
So, the Goliath frog can weigh up to 112 pounds

Question 9.
The mass of a standard hockey puck must be at least 156 grams. What is the minimum mass of 8 hockey pucks in kilograms?
_______ kg

Answer:
1.248 kg

Explanation:
The mass of a standard hockey puck must be at least 156 grams.
1 kilogram = 1000 grams
1 gram = 1/1000 kilogram
then, 156 grams = 156/1000 kilograms = 0.156 kilograms
mass of a hockey puck is 0.156 kilograms
then, the mass of 8 hockey pucks is 8×0.156 = 1.248 kilograms

Practice: Copy and Solve Compare. Write <, >, or =.

Question 10.
250 lb _______ 0.25 T

Answer:
250 lb < 0.25 T

Explanation:
250 lb_______ 0.25 T
1 ton = 2000 pounds(lb)
then, 0.25 tons =0.25×2000 = 500 pounds = 500lb
So, 250 lb < 0.25 T

Question 11.
65.3 hg _______ 653 dag

Answer:
65.3 hg = 653 dag

Explanation:
65.3 hg _______ 653 dag
1 hectogram = 100 grams
Then, 65.3 hectograms = 65.3×100 = 6530 grams
1 dekagram = 10 grams
then, 653 dekagram = 6530 grams
So, 65.3 hectogram = 653 dekagram

Question 12.
5 T _______ 5,000 lb

Answer:
5 T  > 5,000 lb

Explanation:
5 T _______ 5,000 lb
1 ton = 2000 pounds (lb)
5 tons = 5×2000 lb = 10,000 lb
Then, 5 T > 5000 lb

Question 13.
Masses of precious stones are measured in carats, where 1 carat = 200 milligrams. What is the mass of a 50-dg diamond in carats?
_______ carats

Answer:
25 carats

Explanation:
Masses of precious stones are measured in carats, where 1 carat = 200 milligrams.
1 carat = 200 milligrams
6 decigrams = 1 gram
1000 milligrams = 1 gram
So, 10 decigrams = 1000 milligrams
Then, 1 decigram = 100 milligram
2 decigrams = 200 milligrams = 1 carat
then, 50 decigrams = 2×25 decigrams = 25×200 milligrams = 25 carats

Problem Solving + Applications – Page No. 330

Use the table for 14–17.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 3

Question 14.
Express the weight range for bowling balls in pounds.
_______ lb

Answer:
16 lb

Explanation:
Weight range for bowling balls = 160 to 256 ounces
1 pound = 16 ounces
So, 1 ounce = 1/16 pounds
Then, 160 ounces = 160/16 pounds = 10 pounds
256 ounces = 256/16 pounds = 16 pounds
So, the weight range for bowling balls is 10 to 16 pounds

Question 15.
How many more pounds does the heaviest soccer ball weigh than the heaviest baseball? Round your answer to the nearest hundredth.
_______ lb

Answer:
0.68 lb

Explanation:
The heaviest soccer ball weight = 16 ounces
1 pound = 16 ounces
Heaviest baseball weight = 5.25 ounces
1 pound = 16 ounces
1 ounce = 1/16 pounds
then, 5.25 ounces = 5.25/16 = 0.32 pounds
difference between soccer ball and baseball weight = 1 – 0.32 = 0.68 pounds
So, the soccer ball weight is 0.68 pounds more than the weight of the baseball.

Lesson 6.3 Answer Key 6th Grade Question 16.
A manufacturer produces 3 tons of baseballs per day and packs them in cartons of 24 baseballs each. If all of the balls are the minimum allowable weight, how many cartons of balls does the company produce each day?
_______ cartons

Answer:
800 cartons

Explanation:
3 tons = 6000 lbs.
Baseball = 5 ounces
16 ounces in 1 pound
6000 × 16 = 96,000
96,000/5 = 19,200
19,200/24 = 800

Question 17.
Communicate Explain how you could use mental math to estimate the number of soccer balls it would take to produce a total weight of 1 ton.
Type below:
____________

Answer:
Soccer balls range from 14 to 16 ounces
1 ton = 2000 pounds
then, 1 pound = 1/2000 tons
1 pound = 16 ounces
So, 16 ounces = 1/2000 tons = 0.0005 tons
1 ounce = 1/32000 tons
then, 14 ounces = 14/32000 tons =0.0004375 tons
So, the range of soccer balls is 0.0005 to 0.0004375 tons

Question 18.
The Wilson family’s newborn baby weighs 84 ounces. Choose the numbers to show the baby’s weight in pounds and ounces.
_______ pounds and _______ ounces

Answer:
5 pounds and 4 ounces

Explanation:
The Wilson family’s newborn baby weighs 84 ounces
1 pound = 16 ounces
then, 1 ounce = 1/16 pounds
So, 84 ounces = 84/16 pounds = 5 pounds and 4 ounces

Convert Units of Weight and Mass – Page No. 331

Convert to the given unit.

Question 1.
5 pounds = ? ounces
_______ ounces

Answer:
80 ounces

Explanation:
5 pounds = ? ounces
1 pound = 16 ounces
Then, 5 pounds = 5×16 = 80 ounces
So, 5 pounds = 80 ounces

Question 2.
2.36 grams = ? hectograms
_______ hectograms

Answer:
0.0236 hectograms

Explanation:
1.36 grams = ? hectograms
1 hectogram = 100 grams
1 gram = 1/100 hectograms
then, 2.36 grams = 2.36/100 hectograms = 0.0236 hectograms
So, 2.36 grams = 0.0236 hectograms

Question 3.
30 g = ? dg
_______ dg

Answer:
300 dg

Explanation:
29 g = ? dg
10 decigrams = 1 gram
then, 30 grams = 30×10 decigrams = 300 decigrams
30 grams = 300 decigrams

Question 4.
17.2 hg = ? g
_______ g

Answer:
1720 g

Explanation:
17.2 hg = ? g
1 hectogram = 100 grams
Then, 17.2 hectograms = 17.2×100 = 1720 grams
So, 17.2 hectograms = 1720 grams

Question 5.
400 lb = ? T
_______ T

Answer:
0.2 T

Explanation:
1. 400 lb = ? T
1 ton = 2000 pounds (lb)
400 lb = 2000/5 pounds (lb) = 1/5 tons
So, 400 lb = 0.2 tons

Question 6.
38,600 mg = ? dag
_______ dag

Answer:
3.86 dag

Explanation:
38,600 mg = ? dag
1000 milligrams = 1 gram
1 dekagram = 10 grams
So, 1 gram = 1/10 dekagram
Then, 1000 milligrams = 1/10 dekagrams
1 milligram = 1/10,000 dekagrams
So, 38,600 milligrams = 38,600/10,000 = 3.86 dekagrams
38,600 milligrams = 3.86 dekagrams

Question 7.
87 oz = ? lb ? oz
_______ pounds _______ ounces

Answer:
5 pounds and 7 ounces

Explanation:
87 oz = ? lb ? oz
1 pound = 16 ounces
1 ounce = 1/16 pounds
then, 87 ounces = 87/16 pounds
87 ounces = 5 pounds and 7 ounces

Question 8.
0.65 T = ? lb
_______ lb

Answer:
1300 lb

Explanation:
0.65 T = ?lb
1 ton = 2000 pounds
Then, 0.65 tons = 0.65×2000 = 1300 pounds
0.65 T = 1300 lb

Problem Solving

Question 9.
Maggie bought 52 ounces of swordfish selling for $6.92 per pound. What was the total cost?
$ _______

Answer:
$22.49

Explanation:
Maggie bought 52 ounces of swordfish selling for $6.92 per pound.
Maggie bought 52 ounces of swordfish selling for $6.92 per pound
1 pound = 16 ounces
1 ounce = 1/16 pounds
then, 52 ounces = 52/16 pounds = 3.25 pounds
1 pound cost = $6.92
then, 3.25 pounds cost = $6.92 x 3.25 = $22.49
So, the cost for swordfish is $22.49

Question 10.
Three bunches of grapes have masses of 1,000 centigrams, 1,000 decigrams, and 1,000 grams, respectively. What is the total combined mass of the grapes in kilograms?
_______ kg

Answer:
1.11 kg

Explanation:
Three bunches of grapes have masses of 1,000 centigrams, 1,000 decigrams, and 1,000 grams, respectively.
Three bunches of grapes have masses of 1,000 centigrams, 1,000 decigrams, and 1,000 grams
100 centigrams = 1 gram
then, 1000 centigrams = 10×100 centigrams = 10 grams
1 kilogram = 1000 grams
So, 1 gram = 1/1000 kilograms
Then, 10 grams = 10/1000 = 1/100 kilograms = 0.01 kilograms
10 decigrams = 1 gram
then, 100×10 decigrams = 100×1 gram = 100 grams
1000 grams = 1 kilogram
Then, 100 grams = 1/10 kilograms = 0.1 kilograms
1000 grams = 1 kilogram
Total weight of the grapes = 1 + 0.1 + 0.01 = 1.11 kilograms

Question 11.
Explain how you would find the number of ounces in 0.25T.
Type below:
____________

Answer:
number of ounces in 0.25T
1 ton = 2000 pounds
then, 1 pound = 1/2000 tons
1 pound = 16 ounces
so, 16 ounces = 1/2000 tons
then, 1 ton = 16×2000 ounces = 32000 ounces
So, 0.25 tons = 0.25×32000 ounces = 8000 ounces
8000 ounces = 0.25 T

Lesson Check – Page No. 332

Question 1.
The mass of Denise’s rock sample is 684 grams. The mass of Pauline’s rock sample is 29,510 centigrams. How much greater is the mass of Denise’s sample than Pauline’s sample?
_______ centigrams

Answer:
38900 centigrams

Explanation:
The mass of Denise’s rock sample is 684 grams
The mass of Pauline’s rock sample is 29,510 centigrams
100 centigrams = 1 gram
1 centigram = 1/100 gram
then, 29,510 centigrams = 29,510/100 grams = 295.1 grams
So, the mass of Pauline’s rock sample is 295.1 grams
By comparing Denise’s rock sample with Pauline’s rock sample
684 – 295 = 389
The mass of Denise’s rock sample is 389 grams more than the mass of Pauline’s rock sample
389 grams = 38900 centigrams

Solving Conversion Problems Home Link 6.3 Answer Key Question 2.
A sign at the entrance to a bridge reads: Maximum allowable weight 2.25 tons. Jason’s truck weighs 2,150 pounds. How much additional weight can he carry?
_______ pounds

Answer:
2,350 pounds

Explanation:
A sign at the entrance to a bridge reads: Maximum allowable weight 2.25 tons
Jason’s truck weighs 2,150 pounds
1 ton = 2000 pounds
then, 2.25 tons = 2.25×2000 = 4500 pounds
So, maximum allowable weight = 4500 pounds
4500 – 2150 = 2350
So, Jason can carry an additional 2350 pounds’ of weight

Spiral Review

Question 3.
There are 23 students in a math class. Twelve of them are boys. What is the ratio of girls to total number of students?
Type below:
____________

Answer:
11 : 23

Explanation:
There are 23 students in a math class. Twelve of them are boys.
Number of students in a math class = 23
Number of boys in a class = 12
Number of girls in a class = 23-12 = 11
Then, the ratio of girls to the total number of students = 11/23

Question 4.
Miguel hiked 3 miles in 54 minutes. At this rate, how long will it take him to hike 5 miles?
_______ minutes

Answer:
90 minutes

Explanation:
Miguel hiked 3 miles in 54 minutes.
Then, time for 5 miles = 5×54/3 = 90 minutes
So, Miguel hikes 5 miles in 90 minutes

Question 5.
Marco borrowed $150 from his brother. He has paid back 30% so far. How much money does Marco still owe his brother?
$ _______

Answer:
$60

Explanation:
Marco borrowed $150 from his brother
He has paid back 30% of amount = 30/100 (150) = $45
Remaining amount = 150 -45 = 60
So, still $60 amount Marco need to give his brother

Question 6.
How many milliliters are equivalent to 2.7 liters?
_______ milliliters

Answer:
2,700 milliliters

Explanation:
2.7 liters
1000 milliliters = 1 liter
Then, 2.7 liters = 2.7 x 1000 = 2700 milliliters
So, 2,700 milliliters are equivalent to 2.7 liters

Mid-Chapter Checkpoint – Vocabulary – Page No. 333

Choose the best term from the box to complete the sentence.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 4

Question 1.
A _____ is a rate in which the two quantities are equal, but use different units.
Type below:
____________

Answer:
Conversion factor

Question 2.
_____ is the amount a container can hold.
Type below:
____________

Answer:
Capacity

Concepts and Skills

Convert units to solve.

Question 3.
A professional football field is 160 feet wide. What is the width of the field in yards?
_____ \(\frac{□}{□}\) yd

Answer:
53\(\frac{1}{3}\) yd

Explanation:
A professional football field is 160 feet wide
3feet = 1 yard
Then, 160 feet = 160/3 = 53.33
So, the width of football field is 53.33 yards
160/3 = 53 1/3

Question 4.
Julia drinks 8 cups of water per day. How many quarts of water does she drink per day?
_____ quarts

Answer:
2 quarts

Explanation:
Julia drinks 8 cups of water per day.
4 cups = 1 quart
Then, 8 cups = 8/4 = 2 quarts
So, Julia drinks 2 quarts of water per day

Question 5.
The mass of Hinto’s math book is 4,458 grams. What is the mass of 4 math books in kilograms?
_____ kilograms

Answer:
17.832 kilograms

Explanation:
The mass of Hinto’s math book is 4,458 grams
1kilogram = 1000 grams
Then, 4,458 grams = 4,458/1000 = 4.458 kilograms
Then, the mass of 4 math books = 4×4.458 = 17.832 kilograms
The mass of 4 math books is 17.832 kilograms

Question 6.
Turning off the water while brushing your teeth saves 379 centiliters of water. How many liters of water can you save if you turn off the water the next 3 times you brush your teeth?
_____ liters

Answer:
11.37 liters

Explanation:
Turning off the water while brushing your teeth saves 379 centiliters of water
100centiliters = 1 liter
Then, 379 centiliters = 379/100 = 3.79 liters
if you turn off the water the next 3 times = 3×3.79 liters = 11.37 liters
So, you can save 11.37 liters of water when you turn off the water for 3 times

Convert to the given unit.

Question 7.
34.2 mm = ? cm
_____ cm

Answer:
3.42 cm

Explanation:
34.2 mm = ? cm
1000 millimeters = 1 meter
100centimeters = 1 meter
so, 1000 millimeters = 100 centimeters
then, 10 millimeters = 1 centimeter
then, 34.2 millimeters = 34.2/10 = 3.42 centimeters
So, 34.2 mm = 3.42 cm

Question 8.
42 in. = ? ft
_____ \(\frac{□}{□}\) ft

Answer:
3\(\frac{1}{2}\) ft

Explanation:
41 in. = ? ft
12 inches = 1 foot
then, 42 inches = 42/12 = 3.5 feet
So, 42 in = 3.5 ft
42/12 = 3 1/2

Question 9.
1.4 km = ? hm
_____ hm

Answer:
140 hm

Explanation:
1.4 km = ? hm
1 kilometer = 1000 meters
1 hectometer = 100 meters
So, 1 meter = 0.001 kilometers
1 meter = 0.01 hectometers
Now, 0.001 kilometer = 0.01 hectometer
That is 0.1 kilometer = 1 hectometer
Then, 1.4 kilometer = 1.4/0.1 = 140 hectometers
So, 1.4 km = 140 hm

Question 10.
4 gal = ? qt
_____ qt

Answer:
16 qt

Explanation:
4gal = ?qt
1gallon = 4 quarts
Then, 4 gallons = 4×4 = 16 quarts
So, 4 gal = 16 qt

Question 11.
53 dL = ? daL
_____ daL

Answer:
0.53 daL

Explanation:
53 dL = ? daL
10deciliters = 1 liter
1 dekaliter = 10 liters that is 0.1 dekaliters = 1 liter
So, 10 dL = 0.1 daL
Then, 53 dL = 53×0.1/10 =0.53 daL
So, 53 dL = 0.53 daL

Question 12.
28 c = ? pt
_____ pt

Answer:
14 pt

Explanation:
28 c = ?pt
1 cups = 1pint
then, 28 cups = 28/2 = 14 pints
So, 28 c = 14 pt

Page No. 334

Question 13.
Trenton’s laptop is 32 centimeters wide. What is the width of the laptop in decimeters?
_____ dm

Answer:
3.2 dm

Explanation:
Trenton’s laptop is 32 centimeters wide.
100 centimeters = 1 meter
10decimeters = 1 meter
So, 100 centimeters = 10 decimeters
Then, 32 centimeters = 32×10/100 = 3.2 decimeters
So, the width of the laptop is 3.2 decimeters

Question 14.
A truck is carrying 8 cars weighing an average of 4,500 pounds each. What is the total weight in tons of the cars on the truck?
_____ tons

Answer:
18 tons

Explanation:
A truck is carrying 8 cars weighing an average of 4,500 pounds each.
So, total weight = 8 x 4500 pounds = 36,000 pounds
2000 pounds = 1 ton
Then, 36,000 pounds = 36,000 / 2000 = 18 tons
So, total weight of the cars in truck is 18 tons

Question 15.
Ben’s living room is a rectangle measuring 10 yards by 168 inches. By how many feet does the length of the room exceed the width?
_____ feet

Answer:
16 feet

Explanation:
Ben’s living room is a rectangle measuring 10 yards by 168 inches.
12inches = 1 foot
Then, 168 inches = 168/12 = 14 feet
1 yard = 3 feet
then, 10 yards = 10×3 = 30 feet
30-14 = 16 feet
So, the length of the room exceeds 16 feet in width

Grade 6 Unit 6 Answer Key Question 16.
Jessie served 13 pints of orange juice at her party. How many quarts of orange juice did she serve?
_____ quarts

Answer:
6.5 quarts

Explanation:
Jessie served 13 pints of orange juice at her party
1 pints = 1 quart
then, 13 pints = 13/2 = 6.5 quarts
So, Jessie served 6.5 quarts of orange juice at her party

Question 17.
Kaylah’s cell phone has a mass of 50,000 centigrams. What is the mass of her phone in grams?
_____ grams

Answer:
500 grams

Explanation:
Kaylah’s cell phone has a mass of 50,000 centigrams
100 centigrams = 1 gram
then, 50,000 centigrams = 50,000/100 = 500 grams
So, the mass of Kaylah’s phone is 500 grams

Share and Show – Page No. 337

Question 1.
A dripping faucet leaks 12 gallons of water per day. How many gallons does the faucet leak in 6 days?
_____ gallons

Answer:
72 gallons

Explanation:
A dripping faucet leaks 12 gallons of water per day
Then, faucet leaks how many gallons of water per 6 days = 12 x 6 = 72 gallons

Question 2.
Bananas sell for $0.44 per pound. How much will 7 pounds of bananas cost?
$ _____

Answer:
$3.08

Explanation:
Bananas sell for $0.44 per pound
1 pound banana cost is $0.44
then, 7 pounds bananas cost is = 7 x 0.44 = $3.08

Question 3.
Grizzly Park is a rectangular park with an area of 24 square miles. The park is 3 miles wide. What is its length in miles?
_____ miles

Answer:
8 miles

Explanation:
Grizzly Park is a rectangular park with an area of 24 square miles
The park is 3 miles wide
Rectangular park area = length x breadth
That is 24 = 3 x b
So, breadth = 8 miles
The rectangular park length is 8 miles

On Your Own

Multiply or divide the quantities.

Question 4.
\(\frac{24 \mathrm{kg}}{1 \mathrm{min}}\) × 15 min
_____ kg

Answer:
6 kg

Explanation:
24kg1min × 15 min
24 kg / 1min x 15 min
60 min = 1 hour
Then, 15 min = 15/60 = ¼ hours
24 kg x 1/ 4 = 6 kg

Question 5.
216 sq cm÷8 cm
_____ cm

Answer:
27 cm

Explanation:
216 sq cm ÷ 8 cm
216 sq cm/ 8 cm = 27 cm

Question 6.
\(\frac{17 \mathrm{L}}{1 \mathrm{hr}}\) × 9 hr
_____ L

Answer:
153 L

Explanation:
17L1hr x 9 hr
17L/1hr x 9 hr = 153 L

Question 7.
The rectangular rug in Marcia’s living room measures 12 feet by 108 inches. What is the rug’s area in square feet?
_____ square feet

Answer:
108 square feet

Explanation:
The rectangular rug in Marcia’s living room measures 12 feet by 108 inches
1 foot = 12 inches
108 inches = 108/12 = 9 feet
12 x 9 = 108 square feet
Are of rug is 108 square feet

Question 8.
Make Sense of Problems A box-making machine makes cardboard boxes at a rate of 72 boxes per minute. How many minutes does it take to make 360 boxes?
_____ minutes

Answer:
5 minutes

Explanation:
A box-making machine makes cardboard boxes at a rate of 72 boxes per minute
Then, time for 360 boxes = 360/72 = 5 minutes
So, it takes 5 minutes’ time to make 360 boxes

Question 9.
The area of an Olympic-size swimming pool is 1,250 square meters. The length of the pool is 5,000 centimeters. Select True or False for each statement.
9a. The length of the pool is 50 meters.
9b. The width of the pool is 25 meters.
9c. The area of the pool is 1.25 square kilometers
9a. ____________
9b. ____________
9c. ____________

Answer:
9a. True
9b. True
9c. True

Explanation:
The area of an Olympic-size swimming pool is 1,250 square meters
The length of the pool is 5,000 centimeters
100centimeters = 1meter
Then, 5000 centimeters = 5000/100 = 50 meters
Areas of the swimming pool = length x width
1250 square meters = 50 length x 25 width
Then, width = 25 meters
1000 meters = 1 kilometer
then, 1250 square meters = 1250/1000 = 1.25 square meters

Make Predictions – Page No. 338

A prediction is a guess about something in the future. A prediction is more likely to be accurate if it is based on facts and logical reasoning.

The Hoover Dam is one of America’s largest producers of hydroelectric power. Up to 300,000 gallons of water can move through the dam’s generators every second. Predict the amount of water that moves through the generators in half of an hour.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 5
Use what you know about transforming units to make a prediction.
You know the rate of the water through the generators, and you are given an amount of time. Rate of flow:
\(\frac{300,000 \text { gallons }}{1 \text { sec }}\); time: \(\frac{1}{2}\) hr
You want to find the amount of water. Amount of water : ? gallons
Convert the amount of time to seconds to match the units in the rate. \(\frac{1}{2}\) hr=30 min
Multiply the rate by the amount of time to find the amount of water. \(\frac{300,000 \text { gallons }}{1 \mathrm{sec}} \times \frac{1,800 \mathrm{sec}}{1}\) = 540,000,000 gal
So, a good prediction of the amount of water that moves through the generators in half of an hour is 540,000,000 gallons.
Transform units to solve.

Question 10.
An average of 19,230 people tour the Hoover Dam each week. Predict the number of people touring the dam in a year.
_____ people

Answer:
999,960 people

Explanation:
An average of 19,230 people tour the Hoover Dam each week
Number of weeks per year = 52
Then, total number of people tour the hoover dam in the year = 52 x 19, 230 = 999,960
So, 999,960 people touring the hoover dam per year

Question 11.
The Hoover Dam generates an average of about 11,506,000 kilowatt-hours of electricity per day. Predict the number of kilowatt-hours generated in 7 weeks.
_____ kilowatt-hours

Answer:
563,794 kilowatt-hours

Explanation:
The Hoover Dam generates an average of about 11,506,000 kilowatt-hours of electricity per day
1 week = 7 days
7weeks = 7 × 7 = 49 days
Then, Hoover Dam generated electricity per 7 weeks = 49 × 11,506,000 = 563,794,000
So, the total number of kilowatt-hours generated in 7 weeks by the Hoover Dam is 563,794,000

Transform Units – Page No. 339

Multiply or divide the quantities.

Question 1.
\(\frac{62 \mathrm{g}}{1 \mathrm{day}}\) × 4 days
_____ g

Answer:
248 g

Explanation:
62g1day × 4 days
62 g÷1 day × 4 days
Then, 62 g × 4 = 248 g

Question 2.
322 sq yd ÷ 23 yd
_____ yd

Answer:
14 yd

Explanation:
322 sqyd ÷ 23 yd
322 sqyd / 23 yd = 14 sq

Question 3.
\(\frac{128 \mathrm{kg}}{1 \mathrm{hr}}\) × 10 hr
_____ kg

Answer:
1,280 kg

Explanation:
128kg1hr × 10 hr
128 kg/1hr * 10hr
So, 1,280 kg

Question 4.
136 sq km ÷ 8 km
_____ km

Answer:
17 km

Explanation:
136 sq km ÷ 8 km
136 sq km / 8 km
136 sq / 8 = 17

Question 5.
\(\frac{88 \mathrm{lb}}{1 \mathrm{day}}\) × 12 days
_____ lb

Answer:
1,056 lb

Explanation:
88lb1day × 12 days
88lb / 1 day × 12days
That is 88lb × 12 = 1,056 lb

Question 6.
154 sq mm ÷ 11 mm
_____ mm

Answer:
14  mm

Explanation:
154 sq mm ÷ 11 mm
154 sq / 11 = 14

Question 7.
\(\frac{\$ 150}{1 \mathrm{sq} \mathrm{ft}}\) × 20 sq ft
$ _____

Answer:
$30,020 sqft

Explanation:
$1501sqft × 20 sqft
Multiplication of 1501 and 20 is
30,020
That is $1501sqft x 20 sqft = $30,020 sqft

Question 8.
234 sq ft÷18 ft
_____ ft

Answer:
13 ft

Explanation:
234 sq ft÷18 ft
234 sq / 18 = 13

Problem Solving

Question 9.
Green grapes are on sale for $2.50 a pound. How much will 9 pounds cost?
$ _____

Answer:
$22.5

Explanation:
Green grapes are on sale for $2.50 a pound
1 pound = $2.50
then, 9 pounds cost = 9*$2.50 = $22.5
green grapes cost for 9 pounds is $22.5

Question 10.
A car travels 32 miles for each gallon of gas. How many gallons of gas does it need to travel 192 miles?
_____ gallons

Answer:
6 gallons

Explanation:
A car travels 32 miles for each gallon of gas
Then, 192 miles is = 192/ 32 = 6 gallons of gas
So, total 6 gallons of gas is required to travel 192 miles

Question 11.
Write and solve a problem in which you have to transform units. Use the rate 45 people per hour in your question.
Type below:
____________

Answer:
A fast-food restaurant is trying to find out how many customers they had in the last 3 hours, and they know they get 45 people per hour. How many customers were served in the last 3 hours? The answer is 135 people.

Lesson Check – Page No. 340

Question 1.
A rectangular parking lot has an area of 682 square yards. The lot is 22 yards wide. What is the length of the parking lot?
_____ yards

Answer:
31 yards

Explanation:
A rectangular parking lot has an area of 682 square yards
Width of the parking lot = 22 yards wide
Area = length *width
682 square yards= length * 22 yards wide
So, length = 682 square yards / 22 yards = 31 yards
Then, length of the parking lot = 31 yards

Question 2.
A machine assembles 44 key chains per hour. How many key chains does the machine assemble in 11 hours?
_____ key chains

Answer:
484 key chains

Explanation:
A machine assembles 44 key chains per hour
Then, the machine assembles key chains per 11 hours = 11*44 = 484 key chains
So, the machine assembles totally 484 key chains in 11 hours

Spiral Review

Question 3.
Three of these ratios are equivalent to \(\frac{8}{20}\). Which one is NOT equivalent?
\(\frac{2}{5} \quad \frac{12}{24} \quad \frac{16}{40} \quad \frac{40}{100}\)
\(\frac{□}{□}\)

Answer:
\(\frac{8}{20}\)

Explanation:
The below mentioned ratios are equivalent to 8/20
i. 2/5
Multiply the numerator and denominator with 4
That is (2*4)/(5*4) = 8/20
ii. 12/24
Divide the numerator and denominator with 6
That is (12÷6)/(24÷6) = 2/4
Now, multiply the numerator and denominator with 4
That is (2*4)/(4*4) = 8/16
So, 12/14 is not equal to 8/20
iii. 16/40
Divide the numerator and denominator with 2
That is, (16÷2)/(40÷2) = 8/20
iv. 40/100
Divide the numerator and denominator with 5
That is (40÷5)/(100÷5) = 8/20

Question 4.
The graph shows the money that Marco earns for different numbers of days worked. How much money does he earn per day?
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 6
$ _____

Answer:
$80

Explanation:
Total number of days worked = 7
Total earned money = 560 dollars
560 / 7 = 80 dollars per day

Question 5.
Megan answered 18 questions correctly on a test. That is 75% of the total number of questions. How many questions were on the test?
_____ questions

Answer:
24 questions

Explanation:
Megan answered 18 questions correctly
That is 75% of the total number of questions = 18
Then, 100% of the questions = 18*100/75 = 24
So, the total number of questions on the test = 24 questions

Share and Show – Page No. 343

Question 1.
Mariana runs at a rate of 180 meters per minute. How far does she run in 5 minutes?
_____ meters

Answer:
900 meters

Explanation:
Mariana runs at a rate of 180 meters per minute
Then, Mariana runs per 5 minutes = 5×180 = 900 meters
So, Mariana runs 900 meters per 5 minutes

Question 2.
What if Mariana runs for 20 minutes at the same speed? How many kilometers will she run?
_____ kilometers

Answer:
3.6 kilometers

Explanation:
From the given information
Marians runs at a rate of 180 meters per minute
Then the speed of Mariana = 180/1 = 180 meters per minute
If Mariana runs 20 minutes then the covered distance = 20×180 = 3600 meters
1000 meters = 1 kilometer
Then, 3600 meters = 3600/1000 = 3.6 kilometers
So, Mariana runs 3.6 kilometers in 20 minutes

Question 3.
A car traveled 130 miles in 2 hours. How fast did the car travel?
_____ miles per hour

Answer:
65 miles per hour

Explanation:
A car travelled 130 miles in 2 hours
Then the speed of the car = Distance/Time
That is, Speed of the car = 130 miles/ 2 hours = 65 miles per hour
So, the car travels 65 miles per hour

Question 4.
A subway car travels at a rate of 32 feet per second. How far does it travel in 16 seconds?
_____ feet

Answer:
512 feet

Explanation:
A subway car travels at a rate of 32 feet per second
1 second = 32 feet
then, 16 seconds = 16 x 32/1 = 512 feet
So, a subway car travels 512 feet per 16 seconds

Question 5.
A garden snail travels at a rate of 2.6 feet per minute. At this rate, how long will it take for the snail to travel 65 feet?
_____ minutes

Answer:
25 minutes

Explanation:
A garden snail travels at a rate of 2.6 feet per minute
So, 2.6 feet = 1 minute
Then, 65 feet = 65/2.6 = 650/26 = 25 minutes
So, the snail travels 65 feet in 25 minutes

Question 6.
A squirrel can run at a maximum speed of 12 miles per hour. At this rate, how many seconds will it take the squirrel to run 3 miles?
_____ seconds

Answer:
900 seconds

Explanation:
A squirrel can run at a maximum speed of 12 miles per hour
1 hour = 3600 seconds
So, the squirrel can run 12 miles in 3600 seconds
Then, the squirrel can run 3 miles in 3×3600/12 = 900 seconds
So, the squirrel can take 900 seconds of time to run 3 miles

Question 7.
A cyclist rides 8 miles in 32 minutes. What is the speed of the cyclist in miles per hour?
_____ miles per hour

Answer:
15 miles per hour

Explanation:
A cyclist rides 8 miles in 32 minutes
32minutes = 8 miles
Then, 60 minutes = 60×8/32 = 15 miles
So, a cyclist rides 15 miles in 60 minutes that is one hour
So, the speed of the cyclist per hour = 15 miles/ 1 = 15 miles per hour

Share and Show – Page No. 344

On Your Own

Question 8.
A pilot flies 441 kilometers in 31.5 minutes. What is the speed of the airplane?
_____ kilometers per minute

Answer:
14 kilometers per minute

Explanation:
From the given information
A pilot flies 441 kilometers in 31.5 minutes
Speed = Distance / Time
Here, distance = 441 kilometers
Time = 31.5 minutes
Speed of the airplane = 441/31.5 = 4410/315 = 14 kilometers per minute

Question 9.
Chris spent half of his money on a pair of headphones. Then he spent half of his remaining money on CDs. Finally, he spent his remaining $12.75 on a book. How much money did Chris have to begin with?
$ _____

Answer:
$51

Explanation:
Total money with the Chris= x amount
Chris spent half of his money on a pair of headphones = x/2
Then he spent half of his remaining money on CDs = x/4
Finally, he spent his remaining $12.75 on a book
So, total amount x = x/2+x/4+$12.75
$12.75 = (x-x/2-x/4)
= (4x-2x-x)/4
$12.75 = x/4
Then, x = $12.75×4 = $51
So, Chris have to begin with $51

Question 10.
André and Yazmeen leave at the same time and travel 75 miles to a fair. André drives 11 miles in 12 minutes. Yazmeen drives 26 miles in 24 minutes. If they continue at the same rates, who will arrive at the fair first? Explain.
____________

Answer:
André and Yazmeen leave at the same time and travel 75 miles to a fair
André drives 11 miles in 12 minutes
So, Andre can reach 75 miles in = 75×12/11
That is, Andre can travel 75 miles in 81 minutes
Yazmeen drives 26 miles in 24 minutes
So, Yazmeen can reach 75 miles in = 75×24/26 = 69 minutes
That means, Yazmeen can reach 75 miles in 69 minutes
So, Yazmeen can reach the fair first

Question 11.
Make Arguments Bonnie says that if she drives at an average rate of 40 miles per hour, it will take her about 2 hours to drive 20 miles across town. Does Bonnie’s statement make sense? Explain.
____________

Answer:
Make Arguments Bonnie says that if she drives at an average rate of 40 miles per hour, it will take her about 2 hours to drive 20 miles across town
Speed of the Bonnie = 40 miles per hour
Then, Bonnie can cover the distance in 2 hours = 2×40 = 80 miles
So, Bonnie statement is wrong

Question 12.
Claire says that if she runs at an average rate of 6 miles per hour, it will take her about 2 hours to run 18 miles. Do you agree or disagree with Claire? Use numbers and words to support your answer.
____________

Answer:
Claire says that if she runs at an average rate of 6 miles per hour, it will take her about 2 hours to run 18 miles
Claire runs in 1 hour = 6 miles
Then, Claire runs in 2 hours = 2×6 = 12 miles
So, the Claire statement is wrong

Problem Solving Distance, Rate, and Time Formulas – Page No. 345

Read each problem and solve.

Question 1.
A downhill skier is traveling at a rate of 0.5 mile per minute. How far will the skier travel in 18 minutes?
_____ miles

Answer:
9 miles

Explanation:
A downhill skier is traveling at a rate of 0.5 miles per minute
1 minute = 0.5 mile
then, 18 minutes = 18×0.5 = 9 miles
So, the skier travel 9 miles in 18 minutes

Question 2.
How long will it take a seal swimming at a speed of 8 miles per hour to travel 52 miles?
_____ hours

Answer:
6.5 hours

Explanation:
A seal swimming at a speed of 8 miles per hour
Then,52 miles = 52/8 = 6.5 hours
So, A seal swimming can travel 52 miles in 6.5 hours

Question 3.
A dragonfly traveled at a rate of 35 miles per hour for 2.5 hours. What distance did the dragonfly travel?
_____ miles

Answer:
87.5 miles

Explanation:
A dragonfly traveled at a rate of 35 miles per hour for 2.5 hours
That means, 1 hour = 35 miles
Then, 2.5 hours = 2.5×35 = 87.5 miles
So, a dragonfly travels 87.5 miles in 2.5 hours

Question 4.
A race car travels 1,212 kilometers in 4 hours. What is the car’s rate of speed?
_____ kilometers per hour

Answer:
303 kilometers per hour

Explanation:
A race car travels 1,212 kilometers in 4 hours
Speed = Distance/ Time
Here, distance = 1212 kilometers
Time = 4 hours
Then, Speed of the race car = 1212/4 = 303 kilometers per hour

Question 5.
Kim and Jay leave at the same time to travel 25 miles to the beach. Kim drives 9 miles in 12 minutes. Jay drives 10 miles in 15 minutes. If they both continue at the same rate, who will arrive at the beach first?
____________

Answer:
Kim reaches the beach first

Explanation:
Kim and Jay leave at the same time to travel 25 miles to the beach
Kim drives 9 miles in 12 minutes
Then, Kim travels 25 miles in = 25×12/9 = 33 minutes
Jay drives 10 miles in 15 minutes
Then, Jay travels 25 miles in = 25×15/10 = 37.5 minutes
So, Kim reaches the beach first

Question 6.
Describe the location of the variable d in the formulas involving rate, time, and distance.
Type below:
____________

Answer:
Formula Distance = Rate x Time
Distance (d) = Rate x Time

Lesson Check – Page No. 346

Question 1.
Mark cycled 25 miles at a rate of 10 miles per hour. How long did it take Mark to cycle 25 miles?
_____ hours

Answer:
2.5 hours

Explanation:
Mark cycled 25 miles at a rate of 10 miles per hour
That means, 10 miles = 1 hour
Then, 25 miles = 25/10 =2.5 hours
So, Mark take 2.5 hours to cycle 25 miles

Question 2.
Joy ran 13 miles in 3 \(\frac{1}{4}\) hours. What was her average rate?
_____ miles per hour

Answer:
4 miles per hour

Explanation:
Joy ran 13 miles in 3 ¼ hours
3 ¼ = 13/4 = 3.25 hours
Then, the average rate of the Joy = 13/3.25 hours = 4 miles per hour

Spiral Review

Question 3.
Write two ratios that are equivalent to \(\frac{9}{12}\).
Type below:
____________

Answer:
3/4 and 18/24

Explanation:
Equivalent ratios of 9/12 is 3/4 and 18/24
Multiply the numerator and denominator of ¾ with 3
That is 3×3/4×3 = 9/12
Divide the numerator and denominator of 18/24 with 2
That is (18/2)/(24/2) = 9/12

Question 4.
In the Chang family’s budget, 0.6% of the expenses are for internet service. What fraction of the family’s expenses is for internet service? Write the fraction in simplest form.
\(\frac{□}{□}\)

Answer:
\(\frac{3}{500}\)

Explanation:
In the Chang family’s budget, 0.6% of the expenses are for internet service
That is 0.6% = 0.6/100 = 6/1000 = 3/500
So, 3/500 part of the family’s expenses is used for internet service

Question 5.
How many meters are equivalent to 357 centimeters?
_____ meters

Answer:
3.57 meters

Explanation:
357 ntimeters
100centimeters = 1 meter
Then, 357 centimeters = 357/100 = 3.57 meters
3.57 meters is equivalent to 357 centimeters

Question 6.
What is the product of the two quantities shown below?
\(\frac{60 \mathrm{mi}}{1 \mathrm{hr}}\) × 12 hr
_____ miles

Answer:
720 miles

Explanation:
60 mi/1hr x 12 hr
That is, 60 milesx12 = 720 miles
So, the equivalent quantity of 60mi/1hr x 12hr is 720 miles

Chapter 6 Review/Test – Page No. 347

Question 1.
A construction crew needs to remove 2.5 tons of river rock during the construction of new office buildings
The weight of the rocks is ____________ pounds

Answer:
The weight of the rocks is 5,000 pounds

Explanation:
A construction crew needs to remove 2.5 tons of river rock during the construction of new office buildings
1 Ton = 2000 pounds
Then, 2.5 Tons = 2.5×2000
= 25×200 = 5000 pounds
So, the weight of the rocks is 5000 pounds

Question 2.
Select the conversions that are equivalent to 10 yards. Mark all that apply
Options:
a. 20 feet
b. 240 inches
c. 30 feet
d. 360 inches

Answer:
c. 30 feet
d. 360 inches

Explanation:
a. 20 feet
3feet = 1 yard
Then, 20 feet = 20/3 yard
b. 240 inches
36 inches = 1 yard
Then, 240 inches = 240/36 = 6 yards
c. 30 feet
3feet = 1 yard
Then, 30 feet =30/3 = 10 yards
d. 360inches
36 inches = 1 yard
Then, 360 inches = 360/36 = 10 yards
So, 30 feet and 360 inches are equivalent to 10 yards

Question 3.
Meredith runs at a rate of 190 meters per minute. Use the formula d=r×t to find how far she runs in 6 minutes.
_____ meters

Answer:
1,140 meters

Explanation:
Meredith runs at a rate of 190 meters per minute
Formula d = r x t
Here, d= 190 meters, t = 1 minute
Then, r = 190/1 = 190 meters per minute
Now, t = 6 minutes and r = 190 meters per minute
Then d = 190 x 6 = 1,140 meters

Question 4.
The table shows data for 4 cyclists during one day of training. Complete the table by finding the speed for each cyclist. Use the formula r = d ÷ t.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 7
Type below:
____________

Answer:
D = RxT
Alisha
36 = Rx3
Then, Rate of Alisha =36/3 =12 miles per hour
Jose
39 = Rx3
Then, Rate of Jose = 39/3 = 13 miles per hour
Raul
40 = Rx4
Then, Rate of Raul = 40/4 = 10 miles per hour
Ruthie
22= Rx2
Then, Rate of Ruthie = 22/2 = 11 miles per hour

Page No. 348

Question 5.
For numbers 5a–5c, choose <, >, or =.
5a. 5 kilometers Ο 5,000 meters
5b. 254 centiliters Ο 25.4 liters
5c. 6 kilogram Ο 600 gram
5 kilometers _____ 5,000 meters
254 centiliters _____ 25.4 liters
6 kilogram _____ 600 gram

Answer:
5a. 5 kilometers Ο 5,000 meters
5b. 254 centiliters Ο 25.4 liters
5c. 6 kilogram Ο 600 gram
5 kilometers = 5,000 meters
254 centiliters < 25.4 liters
6 kilogram > 600 gram

Explanation:
a. 5 kilometers —— 5000 meters
1 kilometer = 1000 meters
then,5 kilometers 5×1000 = 5000 meters
So, 5 kilometers = 5000 meters
b. 254 centiliters ——25.4 liters
100centiliters = 1 liter
Then, 254 centiliters = 254/100 = 2.54 liters
So, 254 centiliters < 25.4 liters
c. 6 kilograms —– 600 grams
1kilogram = 1000 grams
Then, 6 kilograms = 6000 grams
So, 6 kilograms > 600 grams

Question 6.
A recipe calls for 16 fluid ounces of light whipping cream. If Anthony has 1 pint of whipping cream in his refrigerator, does he have enough for the recipe? Explain your answer using numbers and words.
____________

Answer:
A recipe calls for 16 fluid ounces of light whipping cream
8 fluid ounces = 1 cup
So, 16 fluid ounces = 2 cups = 1 pint
If Anthony has 1 pint of whipping cream in his refrigerator, then it is enough for the recipe

Question 7.
For numbers 7a–7d, choose <, >, or =.
7a. 43 feet Ο 15 yards
7b. 10 pints Ο 5 quarts
7c. 5 tons Ο 5,000 pounds
7d. 6 miles Ο 600 yards
43 feet _____ 15 yards
10 pints _____ 5 quarts
5 tons _____ 5,000 pounds
6 miles _____ 600 yards

Answer:
43 feet < 15 yards
10 pints = 5 quarts
5 tons > 5,000 pounds
6 miles > 600 yards

Explanation:
a. 43 feet —- 15 yards
3feet = 1 yard
Then, 43 feet = 43/3 = 14.3 yards
So, 43 feet < 15 yards
b. 10 pints —- 5 quarts
1 pints = 1 quart
then, 10 pints = 10/2 = 5 quarts
So, 10 pints = 5 quarts
c. 5 tons —– 5000 pounds
1 ton = 2000 pounds
then, 5 tons = 5×2000 = 10,000 pounds
So, 5 tons > 5000 pounds
d. 6 miles —- 600 yards
1 mile =1760 yards
then, 6 miles = 6×1760 = 10,560yards
So, 6 miles > 600 yards

Question 8.
The distance from Caleb’s house to the school is 1.5 miles, and the distance from Ashlee’s house to the school is 3,520 feet. Who lives closer to the school, Caleb or Ashlee? Use numbers and words to support your answer.
____________

Answer:
There are 5280 feet in one mile.
So, you need to change the miles to feet.
1.5 x 5280 = 7920.
7920 > 3520
So, Ashley lives closer.

Page No. 349

Question 9.
Write the mass measurements in order from least to greatest.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 8
Type below:
____________

Answer:
7.4 kilograms, 7.4 centigrams, 7.4 decigrams

Question 10.
An elephant’s heart beats 28 times per minute. Complete the product to find how many times its heart beats in 30 minutes
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 9
Type below:
____________

Answer:
840 beats

Explanation:
An elephant’s heart beats 28 times per minute
Then, elephant’s heart beats in 30 minutes = 28 x 30 = 840
So, an elephant’s heartbeat is 840 times in 30 minutes

Question 11.
The length of a rectangular football field, including both end zones, is 120 yards. The area of the field is 57,600 square feet. For numbers 11a–11d, select True or False for each statement.
11a. The width of the field is 480 yards.
11b. The length of the field is 360 feet.
11c. The width of the field is 160 feet.
11d. The area of the field is 6,400 square yards.
11a. ____________
11b. ____________
11c. ____________
11d. ____________

Answer:
11a. True
11b. True
11c. False
11d. False

Explanation:
The length of a rectangular football field, including both end zones, is 120 yards
The area of the field is 57,600 square feet
That is length x width = 57,600 square feet
Here, length = 120 yards
Then, width = 57,600/120 = 480 yards
11a. True
11b. 1 yard = 3 feet
Then, 120 yards = 120×3 = 360 feet
True
11c. 480 yards = 480×3 = 1440
False
11d. 6400 square yards
3 feet = 1 yard
then, 57,600 square feet = 57,600/3 = 19,200 square yards
False

Question 12.
Harry received a package for his birthday. The package weighed 357,000 centigrams. Select the conversions that are equivalent to 357,000 centigrams. Mark all that apply.
Options:
a. 3.57 kilograms
b. 357 dekagrams
c. 3,570 grams
d. 3,570,000 decigrams

Answer:
a. 3.57 kilograms
b. 357 dekagrams
c. 3,570 grams

Explanation:
Harry received a package for his birthday
The package weighed 357,000 centigrams
100centigrams = 1 gram
Then, 357,000 centigrams = 357,000/100 = 3570 grams
1000 grams = 1 kilogram
Then, 3570 grams = 3570/1000 = 3.57 kilograms
10grams = 1 dekagram
Then, 3570 grams = 3570/10 = 357 dekagrams
1gram = 10 decigrams
Then, 3570 grams = 35700 decigrams
Options a, b and c are true

Page No. 350

Question 13.
Mr. Martin wrote the following problem on the board.
Juanita’s car has a gas mileage of 21 miles per gallon. How many miles can Juanita travel on 7 gallons of gas?
Alex used the expression \(\frac{21 \text { miles }}{\text { 1 gallon }} \times \frac{1}{7 \text { gallons }}\) to find the answer. Explain Alex’s mistake.
Type below:
____________

Answer:
Juanita’s car has a gas mileage of 21 miles per gallon
Juanita traveled miles on 7 gallons of gas = 21×7 = 147 miles
But, Alex used the expression 21 miles 1 gallon ×17 gallons
In the place of 7 gallons, Alex used 17 gallons

Question 14.
Mr. Chen filled his son’s wading pool with 20 gallons of water.
20 gallons is equivalent to ____________ quarts.

Answer:
80 quarts

Explanation:
Mr. Chen filled his son’s wading pool with 20 gallons of water
1gallon = 4 quarts
Then, 20 gallons = 20×4 = 80 quarts
So, 20 gallons is equivalent to 80 quarts

Question 15.
Nadia has a can of vegetables with a mass of 411 grams. Write equivalent conversions in the correct boxes.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 10
Type below:
____________

Answer:
0.411, 41.1, 4.11

Explanation:
Nadia has a can of vegetables with a mass of 411 grams
1000 grams = 1 kilogram
Then, 411 grams = 411/1000 = 0.411 kilograms
100grams = 1 hectogram
Then, 411 grams = 411/100 = 4.11 hectograms
10grams = 1 dekagram
Then, 411 grams = 411/10 = 41.1 dekagram

Question 16.
Steve is driving 440 miles to visit the Grand Canyon. He drives at an average rate of 55 miles per hour. Explain how you can find the amount of time it will take Steve to get to the Grand Canyon.
Type below:
____________

Answer:
Steve is driving 440 miles to visit the Grand Canyon
He drives at an average rate of 55 miles per hour
Then, 440 miles = 440/55 = 8 hours
So, Steve can take 8 hours of time to visit the Grand Canyon

Page No. 351

Question 17.
Lucy walks one time around the lake. She walks for 1.5 hours at an average rate of 3 miles per hour. What is the distance, in miles, around the lake?
_____ miles

Answer:
4.5 miles

Explanation:
Lucy walks one time around the lake
She walks for 1.5 hours at an average rate of 3 miles per hour
1 hour = 3 miles
Then, 1.5 hours = 1.5×3 = 4.5 miles
So, Luke walks 4.5 miles around the lake

Question 18.
The parking lot at a store has a width of 20 yards 2 feet and a length of 30 yards.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 11
Part A
Derrick says that the width could also be written as 22 feet. Explain whether you agree or disagree with Derrick.
Type below:
____________

Answer:
Derrick says that the width could also be written as 22 feet
1yard = 3 feet
20 yards = 60 feet
So, we cannot write 20 yards 2 feet as 22 feet

Question 19.
Part B
The cost to repave the parking lot is $2 per square foot. Explain how much it would cost to repave the parking lot.
Type below:
____________

Answer:
The cost to repave the parking lot is $2 per square foot
Parking lot area =20 yards 2 feet x 30 yards
1yard = 3 feet
Then, 20 yards = 20×3 = 60 feet
30 yards = 30×3 = 90 feet
so, Parking lot area = 62 feet x 90 feet = 5580 feet
1 square foot cost = $2
then, 5580 feet cost = 2×5580 = $11,160

Page No. 352

Question 19.
Jake is using a horse trailer to take his horses to his new ranch.
Part A
Complete the table by finding the weight, in pounds, of Jake’s horse trailer and each horse.
Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length img 12
Type below:
____________

Answer:
Horse weight in Tons = 0.5 T
Trailer weight in Tons = 1.25 T
1 ton = 2000 pounds
then, 0.5 T = 0.5×2000 = 1000 pounds
then, 1.25 T = 1.25×2000 = 2,500 pounds

Question 19.
Part B
Jake’s truck can tow a maximum weight of 5,000 pounds. What is the maximum number of horses he can take in his trailer at one time without going over the maximum weight his truck can tow? Use numbers and words to support your answer.
Type below:
____________

Answer:
Max. No of Horses = (Max weight truck can tow)/(Average weight of one horse)
The weight of a horse is not given in the question .Thus, we assume the average weight of one horse, to be equal to 1000 pounds,
Max. No of Horses = 5000 pounds/ 1000 pounds
Max. No of Horses = 5

Question 20.
A rectangular room measures 13 feet by 132 inches. Tonya said the area of the room is 1,716 square feet. Explain her mistake, then find the area in square feet.
Type below:
____________

Answer:
A rectangular room measures 13 feet by 132 inches =13 feetx132 inches
Tonya said the area of the room is 1,716 square feet
Area of the rectangular room = 13 feet x 132 inches
12inches = 1 foot
Then, 132 inches = 132/12 = 11 feet
So, the area of the rectangular room = 13 feet x 12 feet = 156 feet
So, Tonya’s answer is wrong

Conclusion:

Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length is free online. Get your Go Math Grade 6 Solution Key and start practice. To get the best way of learning and to score high marks in the exam, the only way to learn maths is by using Go Math Grade 6 Chapter 6 Convert Units of Length Answer Key.

Go Math Grade 6 Answer Key Chapter 6 Convert Units of Length Read More »

go-math-grade-6-answer-key-chapter-2-fractions-and-decimals

Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals

Do you want the best learning material for your students? Then, you are at the correct place. Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals PDF is included here for free. All the solutions and explanations will let you understand the easy way of learning and practice the maths in an easy way. Get the support by referring Go Math Grade 6 Chapter 2 Fractions and Decimals Solution Key. Every individual’s first preference to reach their target is HMH Go Math Grade 6 Answer Key.

Improve your student’s maths-solving skills with the help of Go Math 6th Standard Answer Key. Unlimited practice access with all the maths questions and answers along with the practice questions. Use Go Math Grade 6 Answer Key handy solutions to learn the deep maths online. You can also download Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals for free.

Go Math Grade 6 Chapter 2 Fractions and Decimals Answer Key

Go Math Grade 6 Chapter 2 Fractions and Decimals Solution Key helps you to assess your preparation level. You can easily know which concepts are difficult for preparation and find a simple way to solve the problems using Grade 6 Go Math Answer Key. Learn the concepts easily and apply them to real-life to have a smooth life.

Lesson 1: Fractions and Decimals

Lesson 2: Compare and Order Fractions and Decimals

Lesson 3: Multiply Fractions

Lesson 4: Simplify Factors

Mid-Chapter Checkpoint

Lesson 5: Investigate • Model Fraction Division

Lesson 6: Estimate Quotients

Lesson 7: Divide Fractions

Lesson 8: Investigate • Model Mixed Number Division

Lesson 9: Divide Mixed Numbers

Lesson 10: Problem Solving • Fraction Operations

Chapter 2 Review/Test

Share and Show – Page No. 71

Write as a fraction or as a mixed number in simplest form.

Question 1.
95.5
_____ \(\frac{□}{□}\)

Answer:
\(\frac{1}{2}\)

Explanation:
95.5
95.5 is 95 ones and 5 tenths.
5 tenths = \(\frac{5}{10}\)
Simplify using the GCF.
The GCF of 5 and 10 is 10.
Divide the numerator and the denominator by 10
\(\frac{5 ÷ 10}{10 ÷ 10}\) = \(\frac{1}{2}\)

Question 2.
0.6
\(\frac{□}{□}\)

Answer:
\(\frac{3}{5}\)

Explanation:
0.6
6 tenths = \(\frac{6}{10}\)
Simplify using the GCF.
The GCF of 6 and 10 is 2.
Divide the numerator and the denominator by 10
\(\frac{6 ÷ 2}{10 ÷ 2}\) = \(\frac{3}{5}\)

Compare Fractions and Decimals Lesson 1 Question 3.
5.75
_____ \(\frac{□}{□}\)

Answer:
5\(\frac{3}{4}\)

Explanation:
5.75 is 5 ones and 75 hundredths.
75 hundredths = \(\frac{75}{100}\)
Simplify using the GCF.
The GCF of 75 and 100 is 25.
Divide the numerator and the denominator by 25
5\(\frac{75 ÷ 25}{100 ÷ 25}\) = 5\(\frac{3}{4}\)

Write as a decimal.

Question 4.
\(\frac{7}{8}\)
_____

Answer:
0.875

Explanation:
Use division to rename the fraction part as a decimal.
7/8 = 0.875
The quotient has 3 decimal places.
Add the whole number to the decimal.
0 + 0.875 = 0.875.
So, \(\frac{7}{8}\) = 0.875

Question 5.
\(\frac{13}{20}\)
_____

Answer:
0.65

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{13}{20}\) = 0.65
The quotient has 2 decimal places.
Add the whole number to the decimal.
0 + 0.65 = 0.65.
So, \(\frac{13}{20}\) = 0.65

Question 6.
\(\frac{3}{25}\)
_____

Answer:
0.12

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{3}{25}\) = 0.12
The quotient has 2 decimal places.
Add the whole number to the decimal.
0 + 0.12 = 0.12.
So, \(\frac{3}{25}\)= 0.12

On Your Own

Write as a fraction or as a mixed number in simplest form.

Question 7.
0.27
\(\frac{□}{□}\)

Answer:
\(\frac{27}{100}\)

Explanation:
0.27 is 0 ones and 27 hundredths.
27 hundredths = \(\frac{27}{100}\)
Simplify using the GCF.
The GCF of 27 and 100 is 1.
Divide the numerator and the denominator by 1
\(\frac{27 ÷ 1}{100 ÷ 1}\) = \(\frac{27}{100}\)

Question 8.
0.055
\(\frac{□}{□}\)

Answer:
\(\frac{11}{200}\)

Explanation:
0.055 is 0 ones and 55 thousandths.
55 thousandths = \(\frac{55}{1000}\)
Simplify using the GCF.
The GCF of 55 and 1000 is 5.
Divide the numerator and the denominator by 5
\(\frac{55 ÷ 5}{1000 ÷ 5}\) = \(\frac{11}{200}\)

Question 9.
2.45
_____ \(\frac{□}{□}\)

Answer:
\(\frac{9}{20}\)

Explanation:
2.45 is 2 ones and 45 hundredths.
45 hundredths = \(\frac{45}{100}\)
Simplify using the GCF.
The GCF of 45 and 100 is 5.
Divide the numerator and the denominator by 1
\(\frac{45 ÷ 5}{100 ÷ 5}\) = \(\frac{9}{20}\)

Write as a decimal.

Question 10.
\(\frac{3}{8}\)
_____

Answer:
0.375

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{3}{8}\) = 0.375
The quotient has 3 decimal places.
Add the whole number to the decimal.
0 + 0.375 = 0.375.
So, \(\frac{3}{8}\) = 0.375

Decimal Questions and Answers for Grade 6 Question 11.
3 \(\frac{1}{5}\)
_____

Answer:
3.2

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{1}{5}\) = 0.2
The quotient has 1 decimal place.
Add the whole number to the decimal.
3 + 0.2 = 3.2.
So, 3 \(\frac{1}{5}\) = 3.2

Question 12.
2 \(\frac{11}{20}\)
_____

Answer:
2.55

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{11}{20}\) = 0.55
The quotient has 2 decimal places.
Add the whole number to the decimal.
2 + 0.55 = 2.55.
So, 2 \(\frac{11}{20}\) = 2.55

Identify a decimal and a fraction in simplest form for the point.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 1

Question 13.
Point A
Type below:
__________

Answer:
0.2

Question 14.
Point B
Type below:
__________

Answer:
0.9

Explanation:
Point B is between 0.8 and 1.0. Every point is separated by 0.1. So, Point B is at 0.9

Question 15.
Point C
Type below:
__________

Answer:
0.5

Explanation:
Point C is between 0.4 and 0.6. Every point is separated by 0.1. So, Point C is at 0.5

Question 16.
Point D
Type below:
__________

Answer:
0.1

Explanation:
Point D is between 0 and 0.2. Every point is separated by 0.1. So, Point D is at 0.1

Problem Solving + Applications – Page No. 72

Use the table for 17 and 18.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 2

Question 17.
Members of the Ozark Trail Hiking Club hiked a steep section of the trail in June and July. The table shows the distances club members hiked in miles. Write Maria’s July distance as a decimal.
_____ miles

Answer:
2.625 miles

Explanation:
Maria’s July distance = 2 \(\frac{5}{8}\)
Use division to rename the fraction part as a decimal.
\(\frac{5}{8}\) = 0.625
The quotient has 3 decimal places.
Add the whole number to the decimal.
2 + 0.625 = 2.625.
2 \(\frac{5}{8}\) = 2.625

Question 18.
How much farther did Zoey hike in June and July than Maria hiked in June and July? Explain how you found your answer.
_____ miles

Answer:
0.7 miles

Explanation:
Maria: June = 2.95, July = 2 \(\frac{5}{8}\) = 2.58
Zoey: June = 2.85, July = 3 \(\frac{3}{8}\) = 3.38
[2.85 + 3.38] – [2.95 + 2.58] = 0.7 miles

Question 19.
What’s the Error? Tabitha’s hiking distance in July was 2 \(\frac{1}{5}\) miles. She wrote the distance as 2.02 miles. What error did she make?
Type below:
__________

Answer:
Tabitha’s hiking distance in July was 2 \(\frac{1}{5}\) miles.
2 \(\frac{1}{5}\)
Use division to rename the fraction part as a decimal.
\(\frac{1}{5}\)  = 0.2
The quotient has 1 decimal place.
Add the whole number to the decimal.
2 + 0.2 = 2.2.
2 \(\frac{1}{5}\) = 2.2
She wrote the distance as 2.02 miles in mistake.

Question 20.
Use Patterns Write \(\frac{3}{8}, \frac{4}{8}, \text { and } \frac{5}{8}\) as decimals. What pattern do you see? Use the pattern to predict the decimal form of \(\frac{6}{8}\) and \(\frac{7}{8}\).
Type below:
__________

Answer:
\(\frac{3}{8}, \frac{4}{8}, \text { and } \frac{5}{8}\) as decimals.
0.375, 0.5, 0.625
Each decimal is separated by 0.125.
So, 6/8 = 0.625 + 0.125 = 0.75
7/8 = 0.75 + 0.125 = 0.875

Question 21.
Identify a decimal and a fraction in simplest form for the point.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 3
Type below:
__________

Answer:
Point A: 0.5
Point B: 0.7
Point C: 0.3
Point D: 0.8

Explanation:
Every point is differentiated by 0.1 distance.
The A is between 0.4 and 0.6 which is 0.5
The B is between 0.6 and 0.8 which is 0.7
The C is between 0.1 and 0.6 which is 0.53

Fractions and Decimals – Page No. 73

Write as a fraction or as a mixed number in simplest form.

Question 1.
0.52
\(\frac{□}{□}\)

Answer:
\(\frac{13}{25}\)

Explanation:
0.52
0.52 is 52 hundredths.
52 hundredths = \(\frac{52}{100}\)
Simplify using the GCF.
The GCF of 52 and 100 is 4.
Divide the numerator and the denominator by 4
\(\frac{52 ÷ 4}{100 ÷ 4}\) = \(\frac{13}{25}\)

Question 2.
0.02
\(\frac{□}{□}\)

Answer:
\(\frac{1}{50}\)

Explanation:
0.02
0.02 is 2 hundredths.
2 hundredths = \(\frac{2}{100}\)
Simplify using the GCF.
The GCF of 2 and 100 is 2.
Divide the numerator and the denominator by 2
\(\frac{2 ÷ 2}{100 ÷ 2}\) = \(\frac{1}{50}\)

Question 3.
4.8
______ \(\frac{□}{□}\)

Answer:
\(\frac{4}{5}\)

Explanation:
4.8
4.8 is 4 ones and 8 tenths.
8 tenths = \(\frac{8}{10}\)
Simplify using the GCF.
The GCF of 8 and 10 is 2.
Divide the numerator and the denominator by 2
\(\frac{8 ÷ 2}{10 ÷ 2}\) = \(\frac{4}{5}\)

Question 4.
6.025
______ \(\frac{□}{□}\)

Answer:
\(\frac{1}{40}\)

Explanation:
6.025 is 6 ones and 25 thousandths.
25 thousandths = \(\frac{25}{1000}\)
Simplify using the GCF.
The GCF of 25 and 1000 is 25.
Divide the numerator and the denominator by 25
\(\frac{25 ÷ 25}{1000 ÷ 25}\) = \(\frac{1}{40}\)

Write as a decimal.

Question 5.
\(\frac{17}{25}\)
______

Answer:
0.68

Explanation:
Use division to rename the fraction part as a decimal.
17/25 = 0.68
The quotient has 2 decimal places.
Add the whole number to the decimal.
0 + 0.68 = 0.68.
So, \(\frac{17}{25}\) = 0.68

Question 6.
\(\frac{11}{20}\)
______

Answer:
0.55

Explanation:
Use division to rename the fraction part as a decimal.
11/20 = 0.55
The quotient has 2 decimal places.
Add the whole number to the decimal.
0 + 0.55 = 0.55.
So, \(\frac{11}{20}\) = 0.55

Question 7.
4 \(\frac{13}{20}\)
______

Answer:
4.65

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{13}{20}\) = 0.65
The quotient has 2 decimal places.
Add the whole number to the decimal.
4 + 0.65 = 4.65.
So, 4 \(\frac{13}{20}\) = 4.65

Question 8.
7 \(\frac{3}{8}\)
______

Answer:
7.375

Explanation:
Use division to rename the fraction part as a decimal.
\(\frac{3}{8}\) = 0.375
The quotient has 3 decimal places.
Add the whole number to the decimal.
7 + 0.375 = 7.375.
So, 7 \(\frac{3}{8}\) = 7.375

Identify a decimal and a fraction or mixed number in simplest form for each point.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 4

Question 9.
Point A
Type below:
__________

Answer:
0.4

Explanation:

Point A is between 0 and 0.5. Every point is separated by 0.1. So, Point A is at 0.4

Question 10.
Point D
Type below:
__________

Answer:
1.9

Explanation:
Point D is between 1.5 and 2. Every point is separated by 0.1. So, Point D is at 1.9

Question 11.
Point C
Type below:
__________

Answer:
1.2

Explanation:
Point C is between 1 and 1.5. Every point is separated by 0.1. So, Point C is at 1.2

Question 12.
Point B
Type below:
__________

Answer:
0.6

Explanation:
Point C is between 0.5 and 1. Every point is separated by 0.1. So, Point C is at 0.6

Problem Solving

Question 13.
Grace sold \(\frac{5}{8}\) of her stamp collection. What is this amount as a decimal?
______

Answer:
0.625

Explanation:
Grace sold \(\frac{5}{8}\) of her stamp collection.
Use division to rename the fraction part as a decimal.
\(\frac{5}{8}\)  = 0.625
The quotient has 3 decimal places.
Add the whole number to the decimal.
0 + 0.625 = 0.625.
So, \(\frac{5}{8}\) = 0.625

Question 14.
What if you scored an 0.80 on a test? What fraction of the test, in simplest form, did you answer correctly?
\(\frac{□}{□}\)

Answer:
\(\frac{4}{5}\)

Explanation:
0.80 is 0 ones and 8 tenths.
8 tenths = \(\frac{8}{10}\)
Simplify using the GCF.
The GCF of 8 and 10 is 2.
Divide the numerator and the denominator by 2
\(\frac{8 ÷ 2}{10 ÷ 2}\) = \(\frac{4}{5}\)

Chapter 2 Fractions Decimals and Percents Question 15.
What fraction in simplest form is equivalent to 0.45? What decimal is equivalent to \(\frac{17}{20}\)? Explain how you found your answers.
Type below:
__________

Answer:
0.45 is 0 ones and 45 hundredths.
45 hundredths = \(\frac{45}{100}\)
Simplify using the GCF.
The GCF of 45 and 100 is 5.
Divide the numerator and the denominator by 5
\(\frac{45 ÷ 5}{100 ÷ 5}\) = \(\frac{9}{20}\)
\(\frac{17}{20}\)
Use division to rename the fraction part as a decimal.
\(\frac{17}{20}\) = 0.85
The quotient has 2 decimal places.
Add the whole number to the decimal.
0 + 0.85 = 0.85.
So, \(\frac{17}{20}\) = 0.85

Lesson Check – Page No. 74

Question 1.
After a storm, Michael measured 6 \(\frac{7}{8}\) inches of snow. What is this amount as a decimal?
______ inches

Answer:
6.875 inches

Explanation:
Michael measured 6 \(\frac{7}{8}\) inches of snow.
Use division to rename the fraction part as a decimal.
\(\frac{7}{8}\) = 0.875
The quotient has 3 decimal places.
Add the whole number to the decimal.
6 + 0.875 = 6.875.
So, 6 \(\frac{7}{8}\) = 6.875.

Question 2.
A recipe calls for 3.75 cups of flour. What is this amount as a mixed number in simplest form?
______ \(\frac{□}{□}\) cups

Answer:
3 \(\frac{3}{4}\) cups

Explanation:
A recipe calls for 3.75 cups of flour.
3 + 0.75
0.75 is 0 ones and 75 hundredths.
75 hundredths = \(\frac{75}{100}\)
Simplify using the GCF.
The GCF of 75 and 100 is 25.
Divide the numerator and the denominator by 25
\(\frac{75 ÷ 25}{100 ÷ 25}\) = \(\frac{3}{4}\)
3 \(\frac{3}{4}\)

Spiral Review

Question 3.
Gina bought 2.3 pounds of red apples and 2.42 pounds of green apples. They were on sale for $0.75 a pound. How much did the apples cost altogether?
$ ______

Answer:
$3.54

Explanation:
Gina bought 2.3 pounds of red apples and 2.42 pounds of green apples. They were on sale for $0.75 a pound.
$0.75 x 2.3 = 1.725
$0.75 x 2.42 = 1.815
1.725 + 1.815 = 3.54
So the apples cost $3.54

Question 4.
Ken has 4.66 pounds of walnuts, 2.1 pounds of cashews, and 8 pounds of peanuts. He mixes them together and divides them equally among 18 bags. How many pounds of nuts are in each bag?
______ pounds

Answer:
0.82 pounds

Explanation:
Ken has 4.66 pounds of walnuts, 2.1 pounds of cashews, and 8 pounds of peanuts.
4.66 + 2.1 + 8 = 14.76
He mixes them together and divides them equally among 18 bags.
14.76/18 = 0.82

Question 5.
Mia needs to separate 270 blue pens and 180 red pens into packs. Each pack will have the same number of blue pens and the same number of red pens. What is the greatest number of packs she can make? How many red pens and how many blue pens will be in each pack?
Type below:
__________

Answer:
There are 2 red pens and 3 blue pens in each pack.

Explanation:
Mia needs to separate 270 blue pens and 180 red pens into packs.
The GCF of 270 and 180 is 90
The greatest number of packs she can make is 90.
Divide the total number of red pens by the total number of packs.
180/90 = 2
Divide the total number of blue pens by the total number of packs.
270/90 = 3
There are 2 red pens and 3 blue pens in each pack.

Question 6.
Evan buys 19 tubes of watercolor paint for $50.35. What is the cost of each tube of paint?
$ ______

Answer:
$2.65

Explanation:
Evan buys 19 tubes of watercolor paint for $50.35.
$50.35/19 = $2.65

Share and Show – Page No. 77

Order from least to greatest.

Question 1.
\(3 \frac{3}{6}, 3 \frac{5}{8}, 2 \frac{9}{10}\)
Type below:
__________

Answer:
2 \(\frac{9}{10}\) < 3 \(\frac{3}{6}\) < 3 \(\frac{5}{8}\)

Explanation:
\(3 \frac{3}{6}, 3 \frac{5}{8}, 2 \frac{9}{10}\)
Compare the whole numbers first.
2 < 3
If the whole numbers are the same, compare the fractions.
3 \(\frac{3}{6}\), 3 \(\frac{5}{8}\)
6 and 8 are multiples of 48.
So, 48 is a common denominator.
3 \(\frac{3 x 8}{6 x 8}\) = 3 \(\frac{24}{48}\), 3 \(\frac{5 x 6}{8 x 6}\) = 3 \(\frac{30}{48}\)
3 \(\frac{24}{48}\) < 3 \(\frac{30}{48}\)
So, 3 \(\frac{3}{6}\) < 3 \(\frac{5}{8}\)
Order the fractions from least to greatest.
2 \(\frac{9}{10}\) < 3 \(\frac{3}{6}\) < 3 \(\frac{5}{8}\)

Write <, >, or =.

Question 2.
0.8 _____ \(\frac{4}{12}\)

Answer:
0.8 < latex]\frac{4}{12}[/latex]

Explanation:
Write the decimal form of \(\frac{4}{12}\) = 0.3333
0.8 > 0.333
So, 0.8 < latex]\frac{4}{12}[/latex]

Question 3.
0.22 _____ \(\frac{1}{4}\)

Answer:
0.22 < \(\frac{1}{4}\)

Explanation:
Write the decimal form of \(\frac{1}{4}\) = 0.25
0.22 < 0.25
So, 0.22 < \(\frac{1}{4}\)

Question 4.
\(\frac{1}{20}\) _____ 0.06

Answer:
\(\frac{1}{20}\) < 0.06

Explanation:
Write the decimal form of \(\frac{1}{20}\) = 0.05
0.05 < 0.06
So, \(\frac{1}{20}\) < 0.06

Use a number line to order from least to greatest.

Question 5.
\(1 \frac{4}{5}, 1.25, 1 \frac{1}{10}\)
Type below:
__________

Answer:
1\(\frac{1}{10}\), 1.25, 1\(\frac{4}{5}\)

Explanation:
Write the decimal form of 1\(\frac{4}{5}\) = 1.8
Write the decimal form of 1\(\frac{1}{10}\) = 1.1
1.8, 1.25, 1.1
Locate each decimal on a number line.
So, from least to greatest, the order is 1.1, 1.25, 1.8
1\(\frac{1}{10}\), 1.25, 1\(\frac{4}{5}\)

On Your Own

Order from least to greatest.

Question 6.
0.6, \(\frac{4}{5}\), 0.75
Type below:
__________

Answer:
0.6, 0.75, \(\frac{4}{5}\)

Explanation:
Write the decimal form of \(\frac{4}{5}\) = 0.8
0.6, 0.8, 0.75
Compare decimals.
All ones are equal.
Compare tenths: 6 < 7 < 8
So, from least to greatest, the order is 0.6, 0.75, 0.8
So, 0.6, 0.75, \(\frac{4}{5}\)

Practice and Homework Lesson 2.2 Answer Key Question 7.
\(\frac{1}{2}\), \(\frac{2}{5}\), \(\frac{7}{15}\)
Type below:
__________

Answer:
\(\frac{2}{5}\), \(\frac{7}{15}\), \(\frac{1}{2}\)

Explanation:
Write the decimal form of \(\frac{1}{2}\) = 0.5
Write the decimal form of \(\frac{2}{5}\) = 0.4
Write the decimal form of \(\frac{7}{15}\) = 0.466
0.5, 0.4, 0.466
Compare decimals.
All ones are equal.
Compare tenths: 4 < 5
Compare hundredths of 0.4 and 0.466; 0 < 6
So, from least to greatest, the order is 0.4 < 0.466 < 0.5
So, \(\frac{2}{5}\), \(\frac{7}{15}\), \(\frac{1}{2}\)

Question 8.
5 \(\frac{1}{2}\), 5.05, 5 \(\frac{5}{9}\)
Type below:
__________

Answer:
5.05, 5 \(\frac{1}{2}\), 5 \(\frac{5}{9}\)

Explanation:
Write the decimal form of 5 \(\frac{1}{2}\) = 5.5
Write the decimal form of 5 \(\frac{5}{9}\) = 5.555
5.5, 5.05, 5.5555
Compare decimals.
All ones are equal.
Compare tenths: 0 < 5
Compare hundredths of 5.5 and 5.55; 0 < 5
So, from least to greatest, the order is 5.05 < 5.5 < 5.55
So, 5.05, 5 \(\frac{1}{2}\), 5 \(\frac{5}{9}\)

Question 9.
\(\frac{5}{7}\), \(\frac{5}{6}\), \(\frac{5}{12}\)
Type below:
__________

Answer:
\(\frac{5}{12}\), \(\frac{5}{7}\), \(\frac{5}{6}\)

Explanation:
\(\frac{5}{7}\), \(\frac{5}{6}\), \(\frac{5}{12}\)
To compare fractions with the same numerators, compare the denominators.
So, from least to greatest, the order is \(\frac{5}{12}\), \(\frac{5}{7}\), \(\frac{5}{6}\)

Question 10.
\(\frac{7}{15}\) _____ \(\frac{7}{10}\)

Answer:
\(\frac{7}{15}\) < \(\frac{7}{10}\)

Explanation:
\(\frac{7}{15}\) and \(\frac{7}{10}\)
To compare fractions with the same numerators, compare the denominators.
So, \(\frac{7}{15}\) < \(\frac{7}{10}\)

Question 11.
\(\frac{1}{8}\) _____ 0.125

Answer:
\(\frac{1}{8}\) = 0.125

Explanation:
Write the decimal form of \(\frac{1}{8}\) = 0.125
0.125 = 0.125

Question 12.
7 \(\frac{1}{3}\) _____ 6 \(\frac{2}{3}\)

Answer:
7 \(\frac{1}{3}\) > 6 \(\frac{2}{3}\)

Explanation:
Compare the whole numbers first.
7 > 6.
So, 7 \(\frac{1}{3}\) > 6 \(\frac{2}{3}\)

Question 13.
1 \(\frac{2}{5}\) _____ 1 \(\frac{7}{15}\)

Answer:
1 \(\frac{2}{5}\) < 1 \(\frac{7}{15}\)

Explanation:
1 \(\frac{2}{5}\) _____ 1 \(\frac{7}{15}\)
If the whole numbers are the same, compare the fractions.
Compare \(\frac{2}{5}\) and \(\frac{7}{15}\)
5 and 15 are multiples of 15.
So, \(\frac{2 x 3}{5 x 3}\) = \(\frac{6}{15}\)
\(\frac{6}{15}\) < \(\frac{7}{15}\)
Use common denominators to write equivalent fractions.
1 \(\frac{2}{5}\) < 1 \(\frac{7}{15}\)

Question 14.
Darrell spent 3 \(\frac{2}{5}\) hours on a project for school. Jan spent 3 \(\frac{1}{4}\) hours and Maeve spent 3.7 hours on the project. Who spent the least amount of time? Show how you found your answer. Then describe another possible method.
Type below:
__________

Answer:
Jan spent the least amount of time.

Explanation:
Darrell spent 3 \(\frac{2}{5}\) hours on a project for school. Jan spent 3 \(\frac{1}{4}\) hours and Maeve spent 3.7 hours on the project.
Write the decimal form of 3 \(\frac{2}{5}\) = 3.4
Write the decimal form of 3 \(\frac{1}{4}\) = 3.25
3.4, 3.25, 3.7
3.25 is the least one.
So, Jan spent the least amount of time.

Problem Solving + Applications – Page No. 78

Use the table for 15–18.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 5

Question 15.
In one week, Altoona, PA, and Bethlehem, PA, received snowfall every day, Monday through Friday. On which days did Altoona receive over 0.1 inch more snow than Bethlehem?
Type below:
__________

Answer:
Altoona received over 1 inch more snow than Bethlehem on Friday

Explanation:
Altoona (converted to decimal form): 2.25, 3.25, 2.625, 4.6, 4.75
Bethlehem: 2.6, 3.2, 2.5, 4.8, 2.7
Altoona received over 1 inch more snow than Bethlehem on Friday

Question 16.
What if Altoona received an additional 0.3 inch of snow on Thursday? How would the total amount of snow in Altoona compare to the amount received in Bethlehem that day?
Type below:
__________

Answer:
Altoona received 0.1 inches more snow than Bethlehem on Thursday

Explanation:
Altoona received an additional 0.3 inch of snow on Thursday = 4.6 + 0.3 = 4.9
Bethlehem received on Thursday = 4.8
Altoona received 0.1 inches more snow than Bethlehem on Thursday

Question 17.
Explain two ways you could compare the snowfall amounts in Altoona and Bethlehem on Monday.
Type below:
__________

Answer:

Explanation:
Altoona received on Monday = 2.25
Bethlehem received on Monday = 2.6
Bethlehem received 0.35 inches more snow than Altoona on Monday.
As the whole numbers are equal compare 1/4 and 0.6.
0.25 < 0.6
So, Altoona received less snow compared to Bethlehem on Monday.

Question 18.
Explain how you could compare the snowfall amounts in Altoona on Thursday and Friday.
Type below:
__________

Answer:
Altoona received on Thursday = 4.6
Altoona received on Friday = 4.75
4.6 < 4.75
Altoona received less snow on Thursday compared to Friday.

Question 19.
Write the values in order from least to greatest.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 6
Type below:
__________

Answer:
1/3, 0.39, 2/5, 0.45

Explanation:
1/3 = 0.333
0.45
0.39
2/5 = 0.4
Compare tenths: 3 < 4
Compare hundredths:
0.33 < 0.39
0.4 < 0.45
So, 1/3, 0.39, 2/5, 0.45

Compare and Order Fractions and Decimals – Page No. 79

Write <, >, =.

Question 1.
0.64 _____ \(\frac{7}{10}\)

Answer:
0.64 < \(\frac{7}{10}\)

Explanation:
Write the decimal form of \(\frac{7}{10}\) = 0.7
Compare tenths: 6 < 7
So, 0.64 < 0.7
0.64 < \(\frac{7}{10}\)

Question 2.
0.48 _____ \(\frac{6}{15}\)

Answer:
0.48 > \(\frac{6}{15}\)

Explanation:
Write the decimal form of \(\frac{6}{15}\) = 0.4
Compare hundredths:
0.48 > 0.4
0.48 > \(\frac{6}{15}\)

Question 3.
0.75 _____ \(\frac{7}{8}\)

Answer:
0.75 < \(\frac{7}{8}\)

Explanation:
Write the decimal form of \(\frac{7}{8}\) = 0.875
Compare tenths:
7 < 8
0.75 < \(\frac{7}{8}\)

Practice and Homework Lesson 2.2 Question 4.
7 \(\frac{1}{8}\) _____ 7.025

Answer:
7 \(\frac{1}{8}\) > 7.025

Explanation:
Write the decimal form of 7 \(\frac{1}{8}\) = 7.125
Compare tenths:
1 > 0
7 \(\frac{1}{8}\) > 7.025

Order from least to greatest.

Question 5.
\(\frac{7}{15}\), 0.75, \(\frac{5}{6}\)
Type below:
__________

Answer:
\(\frac{7}{15}\), 0.75, \(\frac{5}{6}\)

Explanation:
Write the decimal form of \(\frac{7}{15}\) = 0.466
0.75
Write the decimal form of \(\frac{5}{6}\) = 0.833
Order from least to greatest: \(\frac{7}{15}\), 0.75, \(\frac{5}{6}\)

Question 6.
0.5, 0.41, \(\frac{3}{5}\)
Type below:
__________

Answer:
0.41, 0.5, \(\frac{3}{5}\)

Explanation:
Write the decimal form of \(\frac{3}{5}\) = 0.6
Compare tenths:
0.41, 0.5, 0.6
Order from least to greatest: 0.41, 0.5, \(\frac{3}{5}\)

Question 7.
3.25, 3 \(\frac{2}{5}\), 3 \(\frac{3}{8}\)
Type below:
__________

Answer:
3.25, 3 \(\frac{2}{5}\), 3 \(\frac{3}{8}\)

Explanation:
Write the decimal form of 3 \(\frac{2}{5}\) = 3.4
Write the decimal form of 3 \(\frac{3}{8}\) = 3.375
Compare tenths:
Order from least to greatest: 3.25, 3 \(\frac{2}{5}\), 3 \(\frac{3}{8}\)

Question 8.
0.9, \(\frac{8}{9}\), 0.86
Type below:
__________

Answer:
0.86, \(\frac{8}{9}\), 0.9

Explanation:
Write the decimal form of \(\frac{8}{9}\) = 0.88
Compare tenths:
0.86, 0.88, 0.9
Order from least to greatest: 0.86, \(\frac{8}{9}\), 0.9

Order from greatest to least.

Question 9.
0.7, \(\frac{7}{9}\), \(\frac{7}{8}\)
Type below:
__________

Answer:
\(\frac{7}{8}\), \(\frac{7}{9}\), 0.7

Explanation:
0.7 = 7/10
To compare fractions with the same numerators, compare the denominators.
7/10, 7/9, 7/8
Order from greatest to least: 7/8, 7/9, 7/10

Question 10.
0.2, 0.19, \(\frac{3}{5}\)
Type below:
__________

Answer:
\(\frac{3}{5}\), 0.2, 0.19

Explanation:
Write the decimal form of \(\frac{3}{5}\) = 0.6
Compare tenths:
0.6, 0.2, 0.19
Order from greatest to least: \(\frac{3}{5}\), 0.2, 0.19

Question 11.
6\(\frac{1}{20}\), 6.1, 6.07
Type below:
__________

Answer:

Explanation:
Write the decimal form of 6\(\frac{1}{20}\) = 121/20 = 6.05
Compare tenths:
6.1, 6.07, 6.05
Order from greatest to least: 6.1, 6.07, 6\(\frac{1}{20}\)

Question 12.
2 \(\frac{1}{2}\), 2.4, 2.35, 2 \(\frac{1}{8}\)
Type below:
__________

Answer:
2 \(\frac{1}{2}\), 2.4, 2.35, 2 \(\frac{1}{8}\)

Explanation:
Write the decimal form of 2 \(\frac{1}{2}\) = 2.5
Write the decimal form of 2 \(\frac{1}{8}\) = 2.125
Compare tenths: 2.5, 2.4, 2.35, 2.125
Order from greatest to least: 2 \(\frac{1}{2}\), 2.4, 2.35, 2 \(\frac{1}{8}\)

Question 13.
One day it snowed 3 \(\frac{3}{8}\) inches in Altoona and 3.45 inches in Bethlehem. Which city received less snow that day?
__________

Answer:
Altoona

Explanation:
One day it snowed 3 \(\frac{3}{8}\) inches in Altoona and 3.45 inches in Bethlehem.
Write the decimal form of 3 \(\frac{3}{8}\) = 27/8 = 3.375
3.375 < 3.45.
Altoona received less snow that day

Question 14.
Malia and John each bought 2 pounds of sunflower seeds. Each ate some seeds. Malia has 1 \(\frac{1}{3}\) pounds left, and John has 1 \(\frac{2}{5}\) pounds left. Who ate more sunflower seeds?
__________

Answer:
Malia

Explanation:
Malia and John each bought 2 pounds of sunflower seeds. Each ate some seeds. Malia has 1 \(\frac{1}{3}\) pounds left, and John has 1 \(\frac{2}{5}\) pounds left.
2 – 1 \(\frac{1}{3}\) = 0.667
2 – 1 \(\frac{2}{5}\) = 0.6
0.667 > 0.6
So, Malia ate more sunflower seeds

Question 15.
Explain how you would compare the numbers 0.4 and \(\frac{3}{8}\).
Type below:
__________

Answer:
Write the decimal form of \(\frac{3}{8}\) = 0.375
Compare tenths:
0.4 > 0.375

Lesson Check – Page No. 80

Question 1.
Andrea has 3 \(\frac{7}{8}\) yards of purple ribbon, 3.7 yards of pink ribbon, and 3 \(\frac{4}{5}\) yards of blue ribbon. List the numbers in order from least to greatest.
Type below:
__________

Answer:
Andrea has 3 \(\frac{7}{8}\) yards of purple ribbon, 3.7 yards of pink ribbon, and 3 \(\frac{4}{5}\) yards of blue ribbon.
Write the decimal form of 3 \(\frac{7}{8}\) = 3.875
3.7
Write the decimal form of 3 \(\frac{4}{5}\) = 3.8
Least to greatest : 3.7, 3 \(\frac{4}{5}\), 3 \(\frac{7}{8}\)

Question 2.
Nassim completed \(\frac{18}{25}\) of the math homework. Kara completed 0.7 of it. Debbie completed \(\frac{5}{8}\) of it. List the numbers in order from greatest to least.
Type below:
__________

Answer:
$1.39, $0.70, $0.63

Explanation:
Nassim completed \(\frac{18}{25}\) of the math homework. Kara completed 0.7 of it. Debbie completed \(\frac{5}{8}\) of it.
Write the decimal form of 18/25 = 1.39
0.7
Write the decimal form of 5/8 = 0.63
They are now in order from greatest to least.
Think of the amounts as money:
$1.39, $0.70, $0.63

Spiral Review

Question 3.
Tyler bought 3 \(\frac{2}{5}\) pounds of oranges. Graph 3 \(\frac{2}{5}\) on a number line and write this amount using a decimal.
Type below:
__________

Answer:
grade 6 chapter 2 image 1
Tyler bought 3 \(\frac{2}{5}\) pounds of oranges.
Decimal Form: 17/5 = 3.4

Question 4.
At the factory, a baseball card is placed in every 9th package of cereal. A football card is placed in every 25th package of the cereal. What is the first package that gets both a baseball card and a football card?
Type below:
__________

Answer:
225th package

Explanation:
Look for the first number where both 25 and 9 are a factor of.
25 x 1 = 25 which isn’t a factor of 9, so it won’t be 25.
25 x 2 = 50, which isn’t a factor of 9.
75 is not a factor of 9. (you know because you don’t get a whole number when you divide 75 into 9.)
100 is not a factor of 9, nor is 125, 150, 175, or 200.
However, 225 is a factor of both 25 and 9. This makes sense because 25 x 9 is 225.
This means that the first package with both will be the 225th package.

Question 5.
$15.30 is divided among 15 students. How much does each student receive?
$ _____

Answer:
$1.02

Explanation:
$15.30 is divided among 15 students.
$15.30/15 = $1.02
Each student receives $1.02

Question 6.
Carrie buys 4.16 pounds of apples for $5.20. How much does 1 pound cost?
$ _____

Answer:
$1.25

Explanation:
Carrie buys 4.16 pounds of apples for $5.20.
$5.20/4.16 = $1.25
1 pound cost = $1.25

Share and Show – Page No. 83

Find the product. Write it in simplest form.

Question 1.
6 × \(\frac{3}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{9}{4}\)

Explanation:
\(\frac{6 × 3}{1 × 8}\)
\(\frac{18}{8}\)
Simplify using the GCF.
The GCF of 18 and 8 is 2.
Divide the numerator and the denominator by 2.
\(\frac{18 ÷ 2}{8 ÷ 2}\) = \(\frac{9}{4}\)

Question 2.
\(\frac{3}{8}\) × \(\frac{8}{9}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{3}\)

Explanation:
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 8}{8 × 9}\) = \(\frac{24}{72}\)
Simplify using the GCF.
The GCF of 24 and 72 is 24.
Divide the numerator and the denominator by 24.
\(\frac{24 ÷ 24}{72 ÷ 24}\) = \(\frac{1}{3}\)

Practice and Homework Lesson 2.3 Answer Key Question 3.
Sam and his friends ate 3 \(\frac{3}{4}\) bags of fruit snacks. If each bag contained 2 \(\frac{1}{2}\) ounces, how many ounces of fruit snacks did Sam and his friends eat?
\(\frac{□}{□}\)

Answer:
\(\frac{75}{8}\) ounces

Explanation:
Sam and his friends ate 3 \(\frac{3}{4}\) bags of fruit snacks. If each bag contained 2 \(\frac{1}{2}\) ounces
3 \(\frac{3}{4}\) x 2 \(\frac{1}{2}\)
\(\frac{15}{4}\) x \(\frac{5}{2}\)
\(\frac{15 x 5}{4 x 2}\) = \(\frac{75}{8}\)

Attend to Precision Algebra Evaluate using the order of operations.

Write the answer in the simplest form.

Question 4.
\(\left(\frac{3}{4}-\frac{1}{2}\right) \times \frac{3}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{20}\)

Explanation:
\(\left(\frac{3}{4}-\frac{1}{2}\right) \times \frac{3}{5}\)
Perform operations in parentheses.
\(\frac{3}{4}\) – \(\frac{1}{2}\) = \(\frac{1}{4}\)
\(\frac{1}{4}\) x \(\frac{3}{5}\) = \(\frac{1 x 3}{4 x 5}\) = \(\frac{3}{20}\)

Question 5.
\(\frac{1}{3}+\frac{4}{9} \times 12\)
\(\frac{□}{□}\)

Answer:
\(\frac{28}{3}\)

Explanation:
\(\frac{1}{3}\) + \(\frac{4}{9}\) = \(\frac{7}{9}\)
\(\frac{7 x 12}{9 x 1}\) = \(\frac{84}{9}\)
Simplify using the GCF.
The GCF of 84 and 9 is 3.
Divide the numerator and the denominator by 3.
\(\frac{84 ÷ 3}{9 ÷ 3}\) = \(\frac{28}{3}\)

Question 6.
\(\frac{5}{8} \times \frac{7}{10}-\frac{1}{4}\)
\(\frac{□}{□}\)

Answer:
\(\frac{11}{16}\)

Explanation:
\(\frac{5 x 7}{8 x 10}\) = \(\frac{35}{80}\)
\(\frac{35}{80}\) – \(\frac{1}{4}\) = \(\frac{11}{16}\)

Question 7.
3 × (\(\frac{5}{18}\) + \(\frac{1}{6}\)) + \(\frac{2}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{38}{15}\)

Explanation:
3 x \(\frac{4}{9}\) + \(\frac{2}{5}\)
3 x \(\frac{38}{45}\) = \(\frac{38}{15}\)

On Your Own

Practice: Copy and Solve Find the product. Write it in simplest form.

Question 8.
\(1 \frac{2}{3} \times 2 \frac{5}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{35}{8}\)

Explanation:
1 \(\frac{2}{3}\) = \(\frac{5}{3}\)
2 \(\frac{5}{8}\) = \(\frac{21}{8}\)
\(\frac{5 × 21}{3 × 8}\) = \(\frac{105}{24}\)
Simplify using the GCF
The GCF of 105 and 24 is 3.
Divide the numerator and the denominator by 3.
\(\frac{105 ÷ 3}{24 ÷ 3}\) = \(\frac{35}{8}\)

Question 9.
\(\frac{4}{9} \times \frac{4}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{16}{45}\)

Explanation:
\(\frac{4 × 4}{9 × 5}\) = \(\frac{16}{45}\)

Question 10.
\(\frac{1}{6} \times \frac{2}{3}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{9}\)

Explanation:
\(\frac{1 × 2}{6 × 3}\) = \(\frac{2}{18}\)
Simplify using the GCF
The GCF of 2 and 18 is 2.
Divide the numerator and the denominator by 2.
\(\frac{2 ÷ 2}{18 ÷ 2}\) = \(\frac{1}{9}\)

Question 11.
\(4 \frac{1}{7} \times 3 \frac{1}{9}\)
\(\frac{□}{□}\)

Answer:
\(\frac{116}{7}\)

Explanation:
4\(\frac{1}{7}\) = \(\frac{29}{7}\)
3\(\frac{1}{9}\) = \(\frac{28}{9}\)
\(\frac{29 × 28}{7 × 9}\) = \(\frac{812}{63}\)
Simplify using the GCF
The GCF of 812 and 63 is 7.
Divide the numerator and the denominator by 7.
\(\frac{812 ÷ 7}{63 ÷ 7}\) = \(\frac{116}{7}\)

Question 12.
\(\frac{5}{6}\) of the 90 pets in the pet show are cats. \(\frac{4}{5}\) of the cats are calico cats. What fraction of the pets are calico cats? How many of the pets are calico cats?
Type below:
__________

Answer:
60 calico cats

Explanation:
5/6 x 90 = 450/6 = 150/2
150/2 x 4/5 = 60

Question 13.
Five cats each ate \(\frac{1}{4}\) cup of cat food. Four other cats each ate \(\frac{1}{3}\) cup of cat food. How much food did the nine cats eat?
Type below:
__________

Answer:
\(\frac{31}{12}\)

Explanation:
5 x 1/4 = 5/4
4 x 1/3 = 4/3
5/4 + 4/3 = 31/12

Attend to Precision Algebra Evaluate using the order of operations.

Write the answer in the simplest form.

Question 14.
\(\frac{1}{4} \times\left(\frac{3}{9}+5\right)\)
\(\frac{□}{□}\)

Answer:
\(\frac{4}{3}\)

Explanation:
3/9 + 5 = 16/3
1/4 x 16/3
1 x 16 = 16
4 x 3 = 12
16/12
Simplify using the GCF
The GCF of 16 and 12 is 4.
Divide the numerator and the denominator by 4.
\(\frac{16 ÷ 4}{12÷ 4}\) = \(\frac{4}{3}\)

Question 15.
\(\frac{9}{10}-\frac{3}{5} \times \frac{1}{2}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{5}\)

Explanation:
3/5 x 1/2 = 3/10
9/10 – 3/10 = 6/10
Simplify using the GCF
The GCF of 6 and 10 is 2.
Divide the numerator and the denominator by 2.
\(\frac{6 ÷ 2}{10 ÷ 2}\) = \(\frac{3}{5}\)

Question 16.
\(\frac{4}{5}+\left(\frac{1}{2}-\frac{3}{7}\right) \times 2\)
\(\frac{□}{□}\)

Answer:
\(\frac{33}{35}\)

Explanation:
1/2 – 3/7 = 1/14
1/14 x 2 = 1/7
4/5 + 1/7 = 33/35

Question 17.
\(15 \times \frac{3}{10}+\frac{7}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{141}{8}\)

Explanation:
3/10 + 7/8 = 47/40
15 x 47/40 = 141/8
\(\frac{141}{8}\)

Page No. 84

Question 18.
Write and solve a word problem for the expression \(\frac{1}{4} \times \frac{2}{3}\). Show your work.
Type below:
__________

Answer:
\(\frac{1}{6}\)

Explanation:
\(\frac{1}{4} \times \frac{2}{3}\) = \(\frac{1 X 2}{4 X 3}\) = \(\frac{2}{12}\)
Simplify using the GCF
The GCF of 2 and 12 is 2.
Divide the numerator and the denominator by 2.
\(\frac{2 ÷ 2}{12 ÷ 2}\) = \(\frac{1}{6}\)

Question 19.
Michelle has a recipe that asks for 2 \(\frac{1}{2}\) cups of vegetable oil. She wants to use \(\frac{2}{3}\) that amount of oil and use applesauce to replace the rest. How much applesauce will she use?
Type below:
__________

Answer:
\(\frac{10}{6}\)

Explanation:
2 1/2 * 2/3 = 5/2 * 2/3 = 10/6 She will use 10/6 or 1 2/3 cups of vegetable oil

Question 20.
Cara’s muffin recipe asks for 1 \(\frac{1}{2}\) cups of flour for the muffins and \(\frac{1}{4}\) cup of flour for the topping. If she makes \(\frac{1}{2}\) of the original recipe, how much flour will she use for the muffins and topping?
Type below:
__________

Answer:
Cara will use 1\(\frac{1}{8}\) cups of flour.

Explanation:
For first we will find how many cups of flours need to makes the original recipe. Cara uses 1 1/2 cups of flour for the muffins and 1/4 cup off flour for the topping.
So, 1 1/2 + 1/4 cups of flour to make the original recipe.
1 1/2 = 3/2
3/2 + 1/4 = 7/4
To make the original recipe Cara needs 7/4 cups of flour.
If she makes \(\frac{1}{2}\) of the original recipe, then
7/4 x 1/2 = 7/8 = 1 1/8
Cara will use 1 1/8 cups of flour.

Multiply Fractions – Page No. 85

Find the product. Write it in simplest form.

Question 1.
\(\frac{4}{5} \times \frac{7}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{7}{10}\)

Explanation:
Multiply the numerators and Multiply the denominators.
\(\frac{4 × 7}{5 × 8}\) = \(\frac{28}{40}\)
Simplify using the GCF.
The GCF of 28 and 40 is 4.
Divide the numerator and the denominator by 4.
\(\frac{28 ÷ 4}{40 ÷ 4}\) = \(\frac{7}{10}\)

Question 2.
\(\frac{1}{8} \times 20\)
\(\frac{□}{□}\)

Answer:
\(\frac{5}{2}\)

Explanation:
\(\frac{1 × 20}{1 × 8}\)
\(\frac{20}{8}\)
Simplify using the GCF.
The GCF of 20 and 8 is 4.
Divide the numerator and the denominator by 4.
\(\frac{20 ÷ 4}{8 ÷ 4}\) = \(\frac{5}{2}\)

Question 3.
\(\frac{4}{5} \times \frac{3}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{10}\)

Explanation:
Multiply the numerators and Multiply the denominators.
\(\frac{4 × 3}{5 × 8}\) = \(\frac{12}{40}\)
Simplify using the GCF.
The GCF of 12 and 40 is 4.
Divide the numerator and the denominator by 4.
\(\frac{12 ÷ 4}{40 ÷ 4}\) = \(\frac{3}{10}\)

Question 4.
\(1 \frac{1}{8} \times \frac{1}{9}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{8}\)

Explanation:
1\(\frac{1}{8}\) = \(\frac{9}{8}\)
Multiply the numerators and Multiply the denominators.
\(\frac{9 × 1}{8 × 9}\) = \(\frac{9}{72}\)
Simplify using the GCF.
The GCF of 9 and 72 is 9.
Divide the numerator and the denominator by 9.
\(\frac{9 ÷ 9}{72 ÷ 9}\) = \(\frac{1}{8}\)

Question 5.
\(\frac{3}{4} \times \frac{1}{3} \times \frac{2}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{10}\)

Explanation:
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 1 × 2}{4 × 3 × 5}\) = \(\frac{6}{60}\)
Simplify using the GCF.
The GCF of 6 and 60 is 6.
Divide the numerator and the denominator by 6.
\(\frac{6 ÷ 6}{60 ÷ 6}\) = \(\frac{1}{10}\)

Question 6.
Karen raked \(\frac{3}{5}\) of the yard. Minni raked \(\frac{1}{3}\) of the amount Karen raked. How much of the yard did Minni rake?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{3}\)

Explanation:
Minni raked 1/5 of the yard.
So, minni raked 3/5 of 1/3 means 3/5 x 1/3
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 1}{5 × 3}\) = \(\frac{3}{15}\)
Simplify using the GCF.
The GCF of 3 and 15 is 3.
Divide the numerator and the denominator by 3.
\(\frac{3 ÷ 3}{15 ÷ 3}\) = \(\frac{1}{3}\)

Question 7.
\(\frac{3}{8}\) of the pets in the pet show are dogs. \(\frac{2}{3}\) of the dogs have long hair. What fraction of the pets are dogs with long hair?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\) are dogs with long hair

Explanation:
\(\frac{3}{8}\) of the pets in the pet show are dogs. \(\frac{2}{3}\) of the dogs have long hair.
\(\frac{3}{8}\) of \(\frac{2}{3}\) = \(\frac{3 × 2}{8 × 3}\) = \(\frac{6}{24}\)
The GCF of 6 and 24 is 6.
Divide the numerator and the denominator by 6.
\(\frac{6 ÷ 6}{24 ÷ 6}\) = \(\frac{1}{4}\)
\(\frac{1}{4}\) are dogs with long hair

Evaluate using the order of operations.

Question 8.
\(\left(\frac{1}{2}+\frac{3}{8}\right) \times 8\)
______

Answer:
7

Explanation:
1/2 + 3/8 = 7/8
7/8 × 8 = 7

Question 9.
\(\frac{3}{4} \times\left(1-\frac{1}{9}\right)\)
\(\frac{□}{□}\)

Answer:
\(\frac{2}{3}\)

Explanation:
1 – 1/9 = 8/9
3/4 × 8/9 = 24/36
The GCF of 24 and 36 is 12.
Divide the numerator and the denominator by 12.
\(\frac{24 ÷ 12}{36 ÷ 12}\) = \(\frac{2}{3}\)

Question 10.
\(4 \times \frac{1}{8} \times \frac{3}{10}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{20}\)

Explanation:
Multiply the numerators and Multiply the denominators.
\(\frac{4 × 1 × 3}{1 × 8 × 10}\) = \(\frac{12}{80}\)
Simplify using the GCF.
The GCF of 12 and 80 is 4.
Divide the numerator and the denominator by 4.
\(\frac{12 ÷ 4}{80 ÷ 4}\) = \(\frac{3}{20}\)

Question 11.
\(6 \times\left(\frac{4}{5}+\frac{2}{10}\right) \times \frac{2}{3}\)
______

Answer:
4

Explanation:
4/5 + 2/10 = 1
6 × 1 × 2/3 = 12/3
The GCF of 12 and 3 is 4.
Divide the numerator and the denominator by 3.
\(\frac{12 ÷ 3}{3 ÷ 3}\) = \(\frac{4}{1}\) = 4

Problem Solving

Question 12.
Jason ran \(\frac{5}{7}\) of the distance around the school track. Sara ran \(\frac{4}{5}\) of Jason’s distance. What fraction of the total distance around the track did Sara run?
\(\frac{□}{□}\)

Answer:
\(\frac{4}{7}\)

Explanation:
Jason ran \(\frac{5}{7}\) of the distance around the school track. Sara ran \(\frac{4}{5}\) of Jason’s distance.
\(\frac{5}{7}\) × \(\frac{4}{5}\) = 20/35
The GCF of 20 and 35 is 5.
Divide the numerator and the denominator by 5.
\(\frac{20 ÷ 5}{35 ÷ 5}\) = \(\frac{4}{7}\)

Question 13.
A group of students attend a math club. Half of the students are boys and \(\frac{4}{9}\) of the boys have brown eyes. What fraction of the group are boys with brown eyes?
\(\frac{□}{□}\)

Answer:
\(\frac{2}{9}\) group are boys with brown eyes

Explanation:
A group of students attend a math club. Half of the students are boys and \(\frac{4}{9}\) of the boys have brown eyes.
\(\frac{4}{9}\) × \(\frac{1}{2}\) = 4/18 = 2/9
2/9 group are boys with brown eyes

Question 14.
Write and solve a word problem that involves multiplying by a fraction.
Type below:
__________

Answer:
A group of students attends a math club. Half of the students are boys and \(\frac{6}{9}\) of the boys have brown eyes. What fraction of the group are boys with brown eyes?
\(\frac{□}{□}\)
Answer:
A group of students attends a math club. Half of the students are boys and \(\frac{6}{9}\) of the boys have brown eyes.
\(\frac{6}{9}\) × \(\frac{1}{2}\) = 6/18 = 1/3
1/3 group are boys with brown eyes.

Lesson Check – Page No. 86

Question 1.
Veronica’s mom left \(\frac{3}{4}\) of a cake on the table. Her brothers ate \(\frac{1}{2}\) of it. What fraction of the cake did they eat?
\(\frac{□}{□}\)

Answer:
\(\frac{2}{4}\)

Explanation:
Veronica’s mom left \(\frac{3}{4}\) of a cake on the table. Her brothers ate \(\frac{1}{2}\) of it.
Since the fraction of the eaten cake is 1/2, you can multiply the numerator and denominator by and get an equivalent fraction, which is 2/4.

Question 2.
One lap around the school track is \(\frac{5}{8}\) mile. Carin ran 3 \(\frac{1}{2}\) laps. How far did she run?
_____ \(\frac{□}{□}\)

Answer:
2\(\frac{3}{16}\)

Explanation:
One lap around the school track is \(\frac{5}{8}\) mile. Carin ran 3 \(\frac{1}{2}\) laps.
3 \(\frac{1}{2}\) = \(\frac{7}{2}\)
Therefore, the total distance covered = 7/2 × 5/8 = 35/16 = 2 3/16

Spiral Review

Question 3.
Tom bought 2 \(\frac{5}{16}\) pounds of peanuts and 2.45 pounds of cashews. Which did he buy more of? Explain.
Type below:
__________

Answer:

Explanation:
Tom bought 2 \(\frac{5}{16}\) pounds of peanuts and 2.45 pounds of cashews.
2 \(\frac{5}{16}\) = 2.3125
2.3125 < 2.45
He buys more cashews.

Question 4.
Eve has 24 stamps each valued at $24.75. What is the total value of her stamps?
$ _____

Answer:
$594

Explanation:
Eve has 24 stamps each valued at $24.75.
24 x $24.75 = $594

Question 5.
Naomi went on a 6.5-mile hike. In the morning, she hiked 1.75 miles, rested, and then hiked 2.4 more miles. She completed the hike in the afternoon. How much farther did she hike in the morning than in the afternoon?
_____ miles

Answer:
Naomi went on a 6.5-mile hike. In the morning, she hiked 1.75 miles, rested, and then hiked 2.4 more miles. She completed the hike in the afternoon.
To find how many miles she walked in the afternoon you just subtract the morning miles 4.15 from the total miles 6.5.
6.5 – 4.15  = 2.35
To find how many more miles she walked in the morning you just subtract the morning from the afternoon 4.15 – 2.35=1.8 miles.
She hiked 1.8 more miles in the morning

Question 6.
A bookstore owner has 48 science fiction books and 30 mysteries he wants to sell quickly. He will make discount packages with one type of book in each. He wants the most books possible in each package, but all packages must contain the same number of books. How many packages can he make? How many packages of each type of book does he have?
Type below:
__________

Answer:
18 packages

Explanation:
The bookstore owner can make 18 possible packages
48 – 30 = 18 packages

Share and Show – Page No. 89

Find the product. Simplify before multiplying.

Question 1.
\(\frac{5}{6} \times \frac{3}{10}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
\(\frac{5}{6} \times \frac{3}{10}\)
Multiply the numerators and Multiply the denominators.
\(\frac{5 × 3}{6 × 10}\) = \(\frac{15}{60}\)
Simplify using the GCF.
The GCF of 15 and 60 is 15.
Divide the numerator and the denominator by 15.
\(\frac{15 ÷ 15}{60 ÷ 15}\) = \(\frac{1}{4}\)

Question 2.
\(\frac{3}{4} \times \frac{5}{9}\)
\(\frac{□}{□}\)

Answer:
\(\frac{5}{12}\)

Explanation:
\(\frac{3}{4} \times \frac{5}{9}\)
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 5}{4 × 9}\) = \(\frac{15}{36}\)
Simplify using the GCF.
The GCF of 15 and 36 is 3.
Divide the numerator and the denominator by 3.
\(\frac{15 ÷ 3}{36 ÷ 3}\) = \(\frac{5}{12}\)

Question 3.
\(\frac{2}{3} \times \frac{9}{10}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{5}\)

Explanation:
\(\frac{2}{3} \times \frac{9}{10}\)
Multiply the numerators and Multiply the denominators.
\(\frac{2 × 9}{3 × 10}\) = \(\frac{18}{30}\)
Simplify using the GCF.
The GCF of 18 and 30 is 6.
Divide the numerator and the denominator by 6.
\(\frac{18 ÷ 6}{30 ÷ 6}\) = \(\frac{3}{5}\)

Question 4.
After a picnic, \(\frac{5}{12}\) of the cornbread is left over. Val eats \(\frac{3}{5}\) of the leftover cornbread. What fraction of the cornbread does Val eat?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
After a picnic, \(\frac{5}{12}\) of the cornbread is left over. Val eats \(\frac{3}{5}\) of the leftover cornbread.
\(\frac{5}{12} \times \frac{3}{5}\)
Multiply the numerators and Multiply the denominators.
\(\frac{5 × 3}{12 × 5}\) = \(\frac{15}{60}\)
Simplify using the GCF.
The GCF of 15 and 60 is 15.
Divide the numerator and the denominator by 15.
\(\frac{15 ÷ 15}{60 ÷ 15}\) = \(\frac{1}{4}\)

Question 5.
The reptile house at the zoo has an iguana that is \(\frac{5}{6}\) yd long. It has a Gila monster that is \(\frac{4}{5}\) of the length of the iguana. How long is the Gila monster?
\(\frac{□}{□}\)

Answer:
\(\frac{2}{3}\)

Explanation:
The reptile house at the zoo has an iguana that is \(\frac{5}{6}\) yd long. It has a Gila monster that is \(\frac{4}{5}\) of the length of the iguana.
\(\frac{5}{6} \times \frac{4}{5}\)
Multiply the numerators and Multiply the denominators.
\(\frac{5 × 4}{6× 5}\) = \(\frac{20}{30}\)
Simplify using the GCF.
The GCF of 20 and 30 is 10.
Divide the numerator and the denominator by 10.
\(\frac{20 ÷ 10}{30 ÷ 10}\) = \(\frac{2}{3}\)

On Your Own

Find the product. Simplify before multiplying.

Question 6.
\(\frac{3}{4} \times \frac{1}{6}\)
\(\frac{□}{□}\)

Answer:

Explanation:
\(\frac{3}{4} \times \frac{1}{6}\)
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 1}{4 × 6}\) = \(\frac{3}{24}\)
Simplify using the GCF.
The GCF of 3 and 24 is 3.
Divide the numerator and the denominator by 3.
\(\frac{3 ÷ 3}{24 ÷ 3}\) = \(\frac{1}{8}\)

Question 7.
\(\frac{7}{10} \times \frac{2}{3}\)
\(\frac{□}{□}\)

Answer:
\(\frac{7}{15}\)

Explanation:
\(\frac{7}{10} \times \frac{2}{3}\)
Multiply the numerators and Multiply the denominators.
\(\frac{7 × 2}{10 × 3}\) = \(\frac{14}{30}\)
Simplify using the GCF.
The GCF of 14 and 30 is 2.
Divide the numerator and the denominator by 2.
\(\frac{14 ÷ 2}{30 ÷ 2}\) = \(\frac{7}{15}\)

Question 8.
\(\frac{5}{8} \times \frac{2}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
\(\frac{5}{8} \times \frac{2}{5}\)
Multiply the numerators and Multiply the denominators.
\(\frac{5 × 2}{8 × 5}\) = \(\frac{10}{40}\)
Simplify using the GCF.
The GCF of 10 and 40 is 10.
Divide the numerator and the denominator by 10.
\(\frac{10 ÷ 10}{40 ÷ 10}\) = \(\frac{1}{4}\)

Question 9.
\(\frac{9}{10} \times \frac{5}{6}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{4}\)

Explanation:
\(\frac{9}{10} \times \frac{5}{6}\)
Multiply the numerators and Multiply the denominators.
\(\frac{9 × 5}{10 × 6}\) = \(\frac{45}{60}\)
Simplify using the GCF.
The GCF of 45 and 60 is 15.
Divide the numerator and the denominator by 15.
\(\frac{45 ÷ 15}{60 ÷ 15}\) = \(\frac{3}{4}\)

Question 10.
\(\frac{11}{12} \times \frac{3}{7}\)
\(\frac{□}{□}\)

Answer:
\(\frac{11}{28}\)

Explanation:
\(\frac{11}{12} \times \frac{3}{7}\)
Multiply the numerators and Multiply the denominators.
\(\frac{11 × 3}{12 × 7}\) = \(\frac{33}{84}\)
Simplify using the GCF.
The GCF of 33 and 84 is 3.
Divide the numerator and the denominator by 3.
\(\frac{33 ÷ 3}{84 ÷ 3}\) = \(\frac{11}{28}\)

Question 11.
Shelley’s basketball team won \(\frac{3}{4}\) of their games last season. In \(\frac{1}{6}\) of the games they won, they outscored their opponents by more than 10 points. What fraction of their games did Shelley’s team win by more than 10 points?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{8}\)

Explanation:
Let the total number of games be x.
Number of games Shelley’s team won = 3/4x
The number of games they outscored their opponents by more than 10 points = 1/6 X 3/4x = 1/8x
Hence, in 1/8 of the total games, Shelley’s team won by 10 points.

Question 12.
Mr. Ortiz has \(\frac{3}{4}\) pound of oatmeal. He uses \(\frac{2}{3}\) of the oatmeal to bake muffins. How much oatmeal does Mr. Ortiz have left?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{2}\)

Explanation:
Mr. Ortiz has \(\frac{3}{4}\) pound of oatmeal. He uses \(\frac{2}{3}\) of the oatmeal to bake muffins.
\(\frac{3}{4} \times \frac{2}{3}\)
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 2}{4 × 3}\) = \(\frac{6}{12}\)
Simplify using the GCF.
The GCF of 6 and 12 is 6.
Divide the numerator and the denominator by 6.
\(\frac{6 ÷ 6}{12 ÷ 6}\) = \(\frac{1}{2}\)

Question 13.
Compare Strategies To find \(\frac{16}{27}\) × \(\frac{3}{4}\), you can multiply the fractions and then simplify the product or you can simplify the fractions and then multiply. Which method do you prefer? Explain.
Type below:
__________

Answer:
\(\frac{16}{27}\) × \(\frac{3}{4}\)
\(\frac{16 × 3}{27 × 4}\) = \(\frac{16 × 3}{4 × 27}\)
\(\frac{48}{96}\)
Simplify using the GCF.
The GCF of 48 and 96 is 48.
Divide the numerator and the denominator by 48.
\(\frac{48 ÷ 48}{96 ÷ 48}\) = \(\frac{1}{2}\)

Problem Solving + Applications – Page No. 90

Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 7

Question 14.
Three students each popped \(\frac{3}{4}\) cup of popcorn kernels. The table shows the fraction of each student’s kernels that did not pop. Which student had \(\frac{1}{16}\) cup unpopped kernels?
__________

Answer:
Mirza

Explanation:
Three students each popped \(\frac{3}{4}\) cup of popcorn kernels. The table shows the fraction of each student’s kernels that did not pop.
Katie = 3/4 x 1/10 = 3/40
Mirza = 3/4 x 1/12 = 1/16

Question 15.
The jogging track at Francine’s school is \(\frac{3}{4}\) mile long. Yesterday Francine completed two laps on the track. If she ran \(\frac{1}{3}\) of the distance and walked the remainder of the way, how far did she walk?
____ mile

Answer:
1 mile

Explanation:
Length of jogging track at Francine’s school = 3/4 mile
Let the distance covered by running be = x
Let the distance covered by walking be = y
Total number of laps completed by Francine = 2
Total distance covered by Francine = number of laps X distance covered in one lap
2 x 3/4 = 3/25 mile
Now,
distance covered by running = 1/3 of the total distance
x = 1/3 x 3/2
distance covered by walking y = total distance – distance covered by running
3/2 – x = 3/2 – 1/2 = 1 mile
Hence, Francine walked for 1 mile.

Question 16.
At a snack store, \(\frac{7}{12}\) of the customers bought pretzels and \(\frac{3}{10}\) of those customers bought low-salt pretzels. Bill states that \(\frac{7}{30}\) of the customers bought low-salt pretzels. Does Bill’s statement make sense? Explain.
Type below:
__________

Answer:
Bill’s statement does not make sense because it is incorrect:
7/12 customers bought pretzels.
3/10 Of those customers bought low-salt pretzels (x)
3/10 of 7/12 = x
21/120 = x
Simplify: 7/40
To be correct, Bill would have to say that 7/40 of the customers bought low-salt pretzels, but instead, he had said 7/30.

Question 17.
The table shows Tonya’s homework assignment. Tonya’s teacher instructed the class to simplify each expression by dividing the numerator and denominator by the GCF. Complete the table by simplifying each expression and then finding the value.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 8
Type below:
__________

Answer:
Garde 6 chapter 2 image 1

Simplify Factors – Page No. 91

Find the product. Simplify before multiplying.

Question 1.
\(\frac{8}{9} \times \frac{5}{12}\)
\(\frac{□}{□}\)

Answer:
\(\frac{10}{27}\)

Explanation:
\(\frac{8}{9} \times \frac{5}{12}\)
Multiply the numerators and Multiply the denominators.
\(\frac{8 × 5}{9 × 12}\) = \(\frac{40}{108}\)
Simplify using the GCF.
The GCF of 40 and 108 is 4.
Divide the numerator and the denominator by 4.
\(\frac{40 ÷ 4}{108 ÷ 4}\) = \(\frac{10}{27}\)

Question 2.
\(\frac{3}{4} \times \frac{16}{21}\)
\(\frac{□}{□}\)

Answer:
\(\frac{4}{7}\)

Explanation:
\(\frac{3}{4} \times \frac{16}{21}\)
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 16}{4 × 21}\) = \(\frac{48}{84}\)
Simplify using the GCF.
The GCF of 48 and 84 is 12.
Divide the numerator and the denominator by 12.
\(\frac{48 ÷ 12}{84 ÷ 12}\) = \(\frac{4}{7}\)

Question 3.
\(\frac{15}{20} \times \frac{2}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{3}{10}\)

Explanation:
\(\frac{15}{20} \times \frac{2}{5}\)
Multiply the numerators and Multiply the denominators.
\(\frac{15 × 2}{20 × 5}\) = \(\frac{30}{100}\)
Simplify using the GCF.
The GCF of 30 and 100 is 10.
Divide the numerator and the denominator by 10.
\(\frac{30 ÷ 10}{100 ÷ 10}\) = \(\frac{3}{10}\)

Question 4.
\(\frac{9}{18} \times \frac{2}{3}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{3}\)

Explanation:
\(\frac{9}{18} \times \frac{2}{3}\)
Multiply the numerators and Multiply the denominators.
\(\frac{9 × 2}{18 × 3}\) = \(\frac{18}{54}\)
Simplify using the GCF.
The GCF of 18 and 54 is 18.
Divide the numerator and the denominator by 18.
\(\frac{18 ÷ 18}{54 ÷ 18}\) = \(\frac{1}{3}\)

Question 5.
\(\frac{3}{4} \times \frac{7}{30}\)
\(\frac{□}{□}\)

Answer:
\(\frac{7}{40}\)

Explanation:
\(\frac{3}{4} \times \frac{7}{30}\)
Multiply the numerators and Multiply the denominators.
\(\frac{3 × 7}{4 × 30}\) = \(\frac{21}{120}\)
Simplify using the GCF.
The GCF of 21 and 120 is 3.
Divide the numerator and the denominator by 3.
\(\frac{21 ÷ 3}{120 ÷ 3}\) = \(\frac{7}{40}\)

Question 6.
\(\frac{8}{15} \times \frac{15}{32}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
\(\frac{8}{15} \times \frac{15}{32}\)
Multiply the numerators and Multiply the denominators.
\(\frac{8 × 15}{15 × 32}\) = \(\frac{120}{480}\)
Simplify using the GCF.
The GCF of 120 and 480 is 120.
Divide the numerator and the denominator by 120.
\(\frac{120 ÷ 120}{480 ÷ 120}\) = \(\frac{1}{4}\)

Question 7.
\(\frac{12}{21} \times \frac{7}{9}\)
\(\frac{□}{□}\)

Answer:
\(\frac{4}{9}\)

Explanation:
\(\frac{12}{21} \times \frac{7}{9}\)
Multiply the numerators and Multiply the denominators.
\(\frac{12 × 7}{21 × 9}\) = \(\frac{84}{189}\)
Simplify using the GCF.
The GCF of 84 and 189 is 21.
Divide the numerator and the denominator by 21.
\(\frac{84 ÷ 21}{189 ÷ 21}\) = \(\frac{4}{9}\)

Question 8.
\(\frac{18}{22} \times \frac{8}{9}\)
\(\frac{□}{□}\)

Answer:
\(\frac{8}{11}\)

Explanation:
\(\frac{18}{22} \times \frac{8}{9}\)
Multiply the numerators and Multiply the denominators.
\(\frac{18 × 8}{22 × 9}\) = \(\frac{144}{198}\)
Simplify using the GCF.
The GCF of 144 and 198 is 18.
Divide the numerator and the denominator by 18.
\(\frac{144 ÷ 18}{198 ÷ 18}\) = \(\frac{8}{11}\)

Problem Solving

Question 9.
Amber has a \(\frac{4}{5}\)-pound bag of colored sand. She uses \(\frac{1}{2}\) of the bag for an art project. How much sand does she use for the project?
\(\frac{□}{□}\) pounds

Answer:
\(\frac{2}{5}\) pounds

Explanation:
Amber has a \(\frac{4}{5}\)-pound bag of colored sand. She uses \(\frac{1}{2}\) of the bag for an art project.
4/5 X 1/2 = 2/5

Question 10.
Tyler has \(\frac{3}{4}\) month to write a book report. He finished the report in \(\frac{2}{3}\) at that time. How much time did it take Tyler to write the report?
\(\frac{□}{□}\) month

Answer:
\(\frac{1}{2}\) month

Explanation:
Tyler has \(\frac{3}{4}\) month to write a book report. He finished the report in \(\frac{2}{3}\) at that time.
3/4 X 2/3 = 1/2

Question 11.
Show two ways to multiply \(\frac{2}{15} \times \frac{3}{20}\). Then tell which way is easier and justify your choice.
Type below:
__________

Answer:
\(\frac{2}{15} \times \frac{3}{20}\)
2/15 X 3/20 = 2/20 X 3/15 = 1/10 X 1/5 = 1/50

Lesson Check – Page No. 92

Find each product. Simplify before multiplying.

Question 1.
At Susie’s school, \(\frac{5}{8}\) of all students play sports. Of the students who play sports, \(\frac{2}{5}\) play soccer. What fraction of the students in Susie’s school play soccer?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
At Susie’s school, \(\frac{5}{8}\) of all students play sports. Of the students who play sports, \(\frac{2}{5}\) play soccer.
Multiply 5/8 X 2/5, and the answer is 0.25, which converts to 25/100 or 1/4

Question 2.
A box of popcorn weighs \(\frac{15}{16}\) pounds. The box contains \(\frac{1}{3}\) buttered popcorn and \(\frac{2}{3}\) cheesy popcorn. How much does the cheesy popcorn weigh?
\(\frac{□}{□}\)

Answer:
\(\frac{5}{8}\)

Explanation:
Total weight of a box of popcorn = 15/16 pounds.
We are given two types of popcorn are there, butter popcorn and cheesy popcorn.
Butter popcorn is one-third of the total weight = 1/3 of the Total weight
Plugging the value of the total weight, we get
= 1/3 * 15/16 = 5/16 pounds.
Cheesy popcorn = 2/3 of Total weight
Plugging the value of the total weight, we get
= 2/3 * 15/16 = 10/16 or 5/8 pounds.
Therefore, cheesy popcorn weighs is 5/8 pounds.

Spiral Review

Question 3.
Ramòn bought a dozen ears of corn for $1.80. What was the cost of each ear of corn?
$ ______

Answer:
$0.15

Explanation:
Ramòn bought a dozen ears of corn for $1.80.
So, for the cost of each ear of corn, $1.80/12 = $0.15

Question 4.
A 1.8-ounce jar of cinnamon costs $4.05. What is the cost per ounce?
$ ______

Answer:
$2.25 per ounce

Explanation:
If a 1.8-ounce jar costs $4.05, do $4.05 divided by 1.8.
$4.05 / 1.8 = $2.25 per ounce.

Question 5.
Rose bought \(\frac{7}{20}\) kilogram of ginger candy and 0.4 kilogram of cinnamon candy. Which did she buy more of? Explain how you know.
Type below:
__________

Answer:
Rose bought ginger candy = 7/20 kilogram = 0.35 Kilogram
She bought cinnamon candy = 0.4 kilogram
0.4 > 0.35
Therefore, She bought cinnamon candy.

Question 6.
Don walked 3 \(\frac{3}{5}\) miles on Friday, 3.7 miles on Saturday, and 3 \(\frac{5}{8}\) miles on Sunday. List the distances from least to greatest.
Type below:
__________

Answer:
3 \(\frac{3}{5}\), 3 \(\frac{5}{8}\), 3.7

Explanation:
3 \(\frac{3}{5}\) = 18/5 = 3.6
3 \(\frac{5}{8}\) = 29/8 = 3.625
3.6 < 3.625 < 3.7
3 \(\frac{3}{5}\), 3 \(\frac{5}{8}\), 3.7

Mid-Chapter Checkpoint – Vocabulary – Page No. 93

Choose the best term from the box to complete the sentence.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 9

Question 1.
The fractions \(\frac{1}{2}\) and \(\frac{5}{10}\) are _____.
Type below:
__________

Answer:
Equivalent fractions

Question 2.
A _____ is a denominator that is the same in two or more fractions.
Type below:
__________

Answer:
Common Denominator

Concepts and Skills

Write as a decimal. Tell whether you used division, a number line, or some other method.

Question 3.
\(\frac{7}{20}\)
_____

Answer:
0.35

Explanation:
By using Division,
\(\frac{7}{20}\) = 0.35

Question 4.
8 \(\frac{39}{40}\)
_____

Answer:
8.975

Explanation:
By using Division,
8 \(\frac{39}{40}\) = 359/40 = 8.975

Question 5.
1 \(\frac{5}{8}\)
_____

Answer:
1.625

Explanation:
By using Division,
1 \(\frac{5}{8}\) = 13/8 = 1.625

Question 6.
\(\frac{19}{25}\)
_____

Answer:
0.76

Explanation:
By using Division,
\(\frac{19}{25}\) = 0.76

Order from least to greatest.

Question 7.
\(\frac{4}{5}, \frac{3}{4}, 0.88\)
Type below:
__________

Answer:
\(\frac{3}{4}\), \(\frac{4}{5}\),0.88

Explanation:
Write the decimal form of 4/5 = 0.8
Write the decimal form of 3/4 = 0.75
0.88
0.75 < 0.8 < 0.88

Question 8.
0.65, 0.59, \(\frac{3}{5}\)
Type below:
__________

Answer:
0.59, \(\frac{3}{5}\), 0.65

Explanation:
Write the decimal form of 3/5 = 0.6
0.59 < 0.6 < 0.65

Question 9.
\(1 \frac{1}{4}, 1 \frac{2}{3}, \frac{11}{12}\)
Type below:
__________

Answer:
\(\frac{11}{12}\), 1\(\frac{1}{4}\), 1\(\frac{2}{3}\)

Explanation:
Write the decimal form of 1 1/4 = 5/4 = 1.25
Write the decimal form of 1 2/3 = 5/3 = 1.66
Write the decimal form of 11/12 = 0.916
0.916 < 1.25 < 1.66

Question 10.
0.9, \(\frac{7}{8}\), 0.86
Type below:
__________

Answer:
0.86, \(\frac{7}{8}\), 0.9

Explanation:
Write the decimal form of \(\frac{7}{8}\) = 0.875
0.86 < 0.875 < 0.9

Find the product. Write it in simplest form.

Question 11.
\(\frac{2}{3} \times \frac{1}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{12}\)

Explanation:
\(\frac{2}{3} \times \frac{1}{8}\)
Multiply the numerators and Multiply the denominators.
\(\frac{2 × 1}{3 × 8}\) = \(\frac{2}{24}\)
Simplify using the GCF.
The GCF of 2 and 24 is 2.
Divide the numerator and the denominator by 2.
\(\frac{2 ÷ 2}{24 ÷ 2}\) = \(\frac{1}{12}\)

Question 12.
\(\frac{4}{5} \times \frac{2}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{8}{25}\)

Explanation:
\(\frac{4}{5} \times \frac{2}{5}\)
Multiply the numerators and Multiply the denominators.
\(\frac{4 × 2}{5 × 5}\) = \(\frac{8}{25}\)

Question 13.
12 × \(\frac{3}{4}\)
_____

Answer:
9

Explanation:
12 × \(\frac{3}{4}\)
Multiply the numerators and Multiply the denominators.
\(\frac{12 × 3}{1 × 4}\) = \(\frac{36}{4}\) = 9

Question 14.
Mia climbs \(\frac{5}{8}\) of the height of the rock wall. Lee climbs \(\frac{4}{5}\) of Mia’s distance. What fraction of the wall does Lee climb?
\(\frac{□}{□}\)

Answer:
\(\frac{7}{40}\)

Explanation:
find the LCM (least common denominator) for 5/8 and 4/5.
5/8= 25/40 and 4/5= 32/40.
Subtract and you get 7/40.

Page No. 94

Question 15.
In Zoe’s class, \(\frac{4}{5}\) of the students have pets. Of the students who have pets, \(\frac{1}{8}\) have rodents. What fraction of the students in Zoe’s class have pets that are rodents? What fraction of the students in Zoe’s class have pets that are not rodents?
Type below:
__________

Answer:
\(\frac{1}{10}\) of the students in Zoe’s class have pets that are rodents
\(\frac{7}{10}\) of the students in Zoe’s class have pets that are not rodents

Explanation:
In Zoe’s class, \(\frac{4}{5}\) of the students have pets. Of the students who have pets, \(\frac{1}{8}\) have rodents.
4/5 X 1/8 = 1/10
4/5 – 1/10 = 7/10

Question 16.
A recipe calls for 2 \(\frac{2}{3}\) cups of flour. Terell wants to make \(\frac{3}{4}\) of the recipe. How much flour should he use?
_____ cups

Answer:
2 cups

Explanation:
2 \(\frac{2}{3}\) = 8/3
8/3 * 3/4 = 2

Question 17.
Following the Baltimore Running Festival in 2009, volunteers collected and recycled 3.75 tons of trash. Graph 3.75 on a number line and write the weight as a mixed number.
Type below:
__________

Answer:
Volunteers collected and recycled 3.75 tons of trash.
We need to convert 3.75 as a mixed number.
The mixed number consists of a whole number and a proper fraction.
In the given number 3.75, 3 as the whole number and convert 0.75 to a fraction.
3.75 = 3 + 0.75 = 3 + 75/100
We can reduce the fraction 75/ 100 = 3+ 3/4 = 3 3/4

Question 18.
Four students took an exam. The fraction of the total possible points that each received is given. Which student had the highest score? If students receive a whole number of points on every exam item, can the exam be worth a total of 80 points? Explain.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 10
Type below:
__________

Answer:
22/25 = 0.88
17/20 = 0.85
4/5 = 0.8
3/4 = 0.75
Monica had the highest score
Let x be the total number of points:
(22/25 + 17/20 + 4/5 + 3/4)x = 80
x = 24.39
That is not a whole number of points.

Share and Show – Page No. 97

Use the model to find the quotient.

Question 1.
\(\frac{1}{2}\) ÷ 3
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 11
\(\frac{□}{□}\)

Answer:
\(\frac{1}{6}\)

Explanation:
1/2 groups of 3
\(\frac{1}{2}\) ÷ 3
1/2 × 1/3 = 1/6

Question 2.
\(\frac{3}{4} \div \frac{3}{8}\)
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 12
______

Answer:
2

Explanation:
3/4 groups of 3/8
3/4 × 8/3 = 2

Use fraction strips to find the quotient. Then draw the model.

Question 3.
\(\frac{1}{3}\) ÷ 4
\(\frac{□}{□}\)

Answer:
\(\frac{1}{12}\)
Garde 6 chapter 2 image 2

Explanation:
\(\frac{1}{3}\) ÷ 4
\(\frac{1}{3}\) × \(\frac{1}{4}\)
\(\frac{1}{12}\)

Question 4.
\(\frac{3}{5} \div \frac{3}{10}\)
______

Answer:
2

Explanation:
\(\frac{3}{5} \div \frac{3}{10}\)
\(\frac{3}{5}\) × \(\frac{10}{3}\)
2

Draw a model to solve. Then write an equation for the model. Interpret the result.

Question 5.
How many \(\frac{1}{4}\) cup servings of raisins are in \(\frac{3}{8}\) cup of raisins?
Type below:
__________

Answer:
1.5

Explanation:
3/8 × 1/4 = 1.5

Question 6.
How many \(\frac{1}{3}\) lb bags of trail mix can Josh make from \(\frac{5}{6}\) lb of trail mix?
Type below:
__________

Answer:
2

Explanation:
Multiply 1/3 with 2
1/3 × 2 = 2/6. 2/6 can go into 5/6 twice so the answer is two bags.

Additional Practice 2.5 Compare Decimals Question 7.
Pose a Problem Write and solve a problem for \(\frac{3}{4}\) ÷ 3 that represents how much in each of 3 groups.
Type below:
__________

Answer:
\(\frac{1}{4}\)

Explanation:
\(\frac{3}{4}\) ÷ 3
\(\frac{3}{4}\) × \(\frac{1}{3}\) = 1/4

Problem Solving + Applications – Page No. 98

The table shows the amount of each material that students in a sewing class need for one purse.

Use the table for 8–10. Use models to solve.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 13

Question 8.
Mrs. Brown has \(\frac{1}{3}\) yd of blue denim and \(\frac{1}{2}\) yd of black denim. How many purses can be made using denim as the main fabric?
_____ purses

Answer:
5 purses

Explanation:
Mrs. Brown has \(\frac{1}{3}\) yd of blue denim and \(\frac{1}{2}\) yd of black denim.
3 + 2 = 5

Question 9.
One student brings \(\frac{1}{2}\) yd of ribbon. If 3 students receive an equal length of the ribbon, how much ribbon will each student receive? Will each of them have enough ribbon for a purse? Explain.
Type below:
__________

Answer:
One student brings \(\frac{1}{2}\) yd of ribbon. If 3 students receive an equal length of the ribbon,
\(\frac{1}{2}\) ÷ 3
1/2 × 1/3 = 1/6
They don’t have enough ribbon for a purse

Question 10.
Make Arguments There was \(\frac{1}{2}\) yd of purple and pink striped fabric. Jessie said she could only make \(\frac{1}{24}\) of a purse using that fabric as the trim. Is she correct? Use what you know about the meanings of multiplication and division to defend your answer.
Type below:
__________

Answer:
There was \(\frac{1}{2}\) yd of purple and pink striped fabric. Jessie said she could only make \(\frac{1}{24}\) of a purse using that fabric as the trim.
1/2 × 12 = 1/24
So, 12 is the answer

Question 11.
Draw a model to find the quotient.
\(\frac{1}{2}\) ÷ 4 =
Type below:
__________

Answer:
Garde 6 chapter 2 image 3

Explanation:
1/2 × 1/4 = 1/8

Model Fraction Division – Page No. 99

Use the model to find the quotient

Question 1.
\(\frac{1}{4}\) ÷ 3 =
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 14
\(\frac{□}{□}\)

Answer:
\(\frac{1}{12}\)

Explanation:
\(\frac{1}{4}\) ÷ 3
\(\frac{1}{4}\) × \(\frac{1}{3}\) = \(\frac{1}{12}\)

Question 2.
\(\frac{1}{2} \div \frac{2}{12}=\)
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 15
______

Answer:
3

Explanation:
\(\frac{1}{2} \div \frac{2}{12}=\)
\(\frac{1}{2}\) × \(\frac{12}{2}\) = \(\frac{12}{4}\) = 3

Use fraction strips to find the quotient.

Question 3.
\(\frac{5}{6} \div \frac{1}{2}=\)
______ \(\frac{□}{□}\)

Answer:
\(\frac{5}{3}\)

Explanation:
\(\frac{5}{6} \div \frac{1}{2}=\)
\(\frac{5}{6}\) × \(\frac{2}{1}\) = \(\frac{5}{3}\)

Question 4.
\(\frac{2}{3}\) ÷ 4 =
\(\frac{□}{□}\)

Answer:
\(\frac{1}{6}\)

Explanation:
\(\frac{2}{3}\) ÷ 4
\(\frac{2}{3}\) × \(\frac{1}{4}\) = \(\frac{2}{12}\) = 1/6

Question 5.
\(\frac{1}{2}\) ÷ 6 =
\(\frac{□}{□}\)

Answer:
\(\frac{1}{12}\)

Explanation:
\(\frac{1}{2}\) ÷ 6
\(\frac{1}{2}\) × \(\frac{1}{6}\) = \(\frac{1}{12}\)

Question 6.
\(\frac{1}{3} \div \frac{1}{12}\)
______

Answer:
4

Explanation:
\(\frac{1}{3} \div \frac{1}{12}\)
\(\frac{1}{3}\) × \(\frac{12}{1}\) = \(\frac{12}{3}\) = 4

Draw a model to solve. Then write an equation for the model. Interpret the result.

Question 7.
If Jerry runs \(\frac{1}{10}\) mile each day, how many days will it take for him to run \(\frac{4}{5}\) mile?
______ days

Answer:
8 days

Explanation:
If Jerry runs \(\frac{1}{10}\) mile each day,
\(\frac{4}{5}\) ÷ \(\frac{1}{10}\)
\(\frac{4}{5}\) × \(\frac{10}{1}\) = \(\frac{40}{5}\) = 8

Problem Solving

Question 8.
Mrs. Jennings has \(\frac{3}{4}\) gallon of paint for an art project. She plans to divide the paint equally into jars. If she puts \(\frac{1}{8}\) gallon of paint into each jar, how many jars will she use?
______ jars

Answer:
6 jars

Explanation:
Mrs. Jennings has 3/4 Gallons of paint for an art project.
In 1 jar she puts 1/8 gallon of paint.
The number of jars in which she plans to divide the paint equally is given by,
n= 3/4 ÷ 1/8
n = \(\frac{3}{4}\) × \(\frac{8}{1}\) = \(\frac{24}{4}\) = 6

Question 9.
If one jar of glue weighs \(\frac{1}{12}\) pound, how many jars can Rickie get from \(\frac{2}{3}\) pound of glue?
______ jars

Answer:
8 jars

Explanation:
The weight of glue in one jar = 1/12 pound
To get 2/3 pound of glue Rickie can get the number of jars
2/3 ÷ 1/12
2/3 × 12/1 = 24/3 = 8

Question 10.
Explain how to use a model to show \(\frac{2}{6} \div \frac{1}{12}\) and \(\frac{2}{6}\) ÷ 4.
Type below:
__________

Answer:
Garde 6 chapter 2 image 4
Garde 6 chapter 2 image 2

Explanation:
\(\frac{2}{6} \div \frac{1}{12}\)
2/6 = 1/3
1/3 x 12/1 = 4
\(\frac{2}{6}\) ÷ 4
1/3 x 1/4 = 1/12

Lesson Check – Page No. 100

Question 1.
Darcy needs \(\frac{1}{4}\) yard of fabric to make a banner. She has 2 yards of fabric. How many banners can she make?
______ banners

Answer:
8 banners

Explanation:
Darcy needs \(\frac{1}{4}\) yard of fabric to make a banner. She has 2 yards of fabric.
2 ÷ \(\frac{1}{4}\) = 2 x 4 = 8

Question 2.
Lorenzo bought \(\frac{15}{16}\) pounds of ground beef. He wants to make hamburgers that weigh \(\frac{3}{16}\) pound each. How many hamburgers can he make?
______ hamburgers

Answer:
5 hamburgers

Explanation:
Lorenzo bought \(\frac{15}{16}\) pounds of ground beef. He wants to make hamburgers that weigh \(\frac{3}{16}\) pound each.
\(\frac{15}{16}\) ÷ \(\frac{3}{16}\)
15/3 = 5

Spiral Review

Question 3.
Letisha wants to read 22 pages a night. At that rate, how long will it take her to read a book with 300 pages?
______ nights

Answer:
14 nights

Explanation:
Letisha wants to read 22 pages a night. It takes her to read a book with 300 pages
300/22 = 13.6
13.6 is near to 14
So, it is for 2 weeks.

Question 4.
A principal wants to order enough notebooks for 624 students. The notebooks come in boxes of 28. How many boxes should he order?
______ boxes

Answer:
22 boxes

Explanation:
A principal wants to order enough notebooks for 624 students. The notebooks come in boxes of 28.
624/28 = 22.2857
22.2857 is closer to 22
22 boxes.

Question 5.
Each block in Ton’s neighborhood is \(\frac{2}{3}\) mile long. If he walks 4 \(\frac{1}{2}\) blocks, how far does he walk?
______ miles

Answer:
3 miles

Explanation:
If each block is 2/3 miles long, and he walks 4 1/2 blocks, we can simply multiply to two. It looks like this:
(2/3)(4 1/2)
to multiply, make 4 1/2 into an improper fraction and multiply normally
(2/3)(9/4)
Ton walks 3 miles total.

Question 6.
In Cathy’s garden, \(\frac{5}{6}\) of the area is planted with flowers. Of the flowers, \(\frac{3}{10}\) of them are red. What fraction of Cathy’s garden is planted with red flowers?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
In Cathy’s garden, \(\frac{5}{6}\) of the area is planted with flowers. Of the flowers, \(\frac{3}{10}\) of them are red.
5/6 x 3/10 = 1/4

Share and Show – Page No. 103

Estimate using compatible numbers.

Question 1.
\(22 \frac{4}{5} \div 6 \frac{1}{4}\)
_______

Answer:
4

Explanation:
22 \(\frac{4}{5}\) = 114/5 = 22.8
6 \(\frac{1}{4}\) = 25/4 = 6.25
22.8 is closer to 24
6.25 is closer to 6
24/6 = 4

Question 2.
\(12 \div 3 \frac{3}{4}\)
_______

Answer:
3

Explanation:
3 \(\frac{3}{4}\) = 15/4 = 3.75
3.75 is closer to 4
12/4 = 3

Question 3.
\(33 \frac{7}{8} \div 5 \frac{1}{3}\)
_______

Answer:
7

Explanation:
33 \(\frac{7}{8}\) = 271/8 = 33.875
5 \(\frac{1}{3}\) = 16/3 = 5.333
33.875 is closer to 35
5.333 is closer to 5
35/5 = 7

Question 4.
\(3 \frac{7}{8} \div \frac{5}{9}\)
_______

Answer:
4

Explanation:
3 \(\frac{7}{8}\) = 31/8 = 3.875
\(\frac{5}{9}\) = 0.555
3.875 is closer to 4
0.555 is closer to 1
4/1 = 4

Additional Practice 2.6 Round Decimals Answer Key Question 5.
\(34 \frac{7}{12} \div 7 \frac{3}{8}\)
_______

Answer:
5

Explanation:
34 \(\frac{7}{12}\) = 415/12 = 34.583
7 \(\frac{3}{8}\) = 59/8 = 7.375
34.583 is closer to 35
7.375 is closer to 7
35/7 = 5

Question 6.
\(1 \frac{2}{9} \div \frac{1}{6}\)
_______

Answer:
5

Explanation:
1 \(\frac{2}{9}\) = 11/9 = 1.222
\(\frac{1}{6}\) = 0.1666
1.222 is closer to 1
0.1666 is closer to 0.2
1/0.2 = 5

On Your Own

Estimate using compatible numbers.

Question 7.
\(44 \frac{1}{4} \div 11 \frac{7}{9}\)
_______

Answer:
4

Explanation:
44 \(\frac{1}{4}\) = 177/4 = 44.25
11 \(\frac{7}{9}\) = 106/9 = 11.77
44.25 is closer to 44
11.77 is closer to 11
44/11 = 4

Question 8.
\(71 \frac{11}{12} \div 8 \frac{3}{4}\)
_______

Answer:
8

Explanation:
71 \(\frac{11}{12}\) = 863/12 = 71.916
8 \(\frac{3}{4}\) = 35/4 = 8.75
71.916 is closer to 72
8.75 is closer to 9
72/9 = 8

Question 9.
\(1 \frac{1}{6} \div \frac{1}{8}\)
_______

Answer:
12

Explanation:
1 \(\frac{1}{6}\) = 7/6 = 1.166
\(\frac{1}{8}\) = 0.125
1.166 is closer to 1.2
0.125 is closer to 0.1
1.2/0.1 = 12

Estimate to compare. Write <, >, or =.

Question 10.
\(21 \frac{3}{10} \div 2 \frac{5}{6}\) _______ \(35 \frac{7}{9} \div 3 \frac{2}{3}\)

Answer:
\(21 \frac{3}{10} \div 2 \frac{5}{6}\) < \(35 \frac{7}{9} \div 3 \frac{2}{3}\)

Explanation:
21 \(\frac{3}{10}\) = 213/10 = 21.3
2 \(\frac{5}{6}\) = 17/6 = 2.833
21.3 is closer to 21
2.833 is closer to 3
21/3 = 7
35 \(\frac{7}{9}\) = 322/9 = 35.777
3 \(\frac{2}{3}\) = 11/3 = 3.666
35.777 is closer to 36
3.666 is closer to 4
36/4 = 9
7 < 9
So, \(21 \frac{3}{10} \div 2 \frac{5}{6}\) < \(35 \frac{7}{9} \div 3 \frac{2}{3}\)

Question 11.
\(29 \frac{4}{5} \div 5 \frac{1}{6}\) _______ \(27 \frac{8}{9} \div 6 \frac{5}{8}\)

Answer:
\(29 \frac{4}{5} \div 5 \frac{1}{6}\) > \(27 \frac{8}{9} \div 6 \frac{5}{8}\)

Explanation:
29 \(\frac{4}{5}\) = 149/5 = 29.8
5 \(\frac{1}{6}\) = 31/6 = 5.1666
29.8 is closer to 30
5.1666 is closer to 5
30/5 = 6
27 \(\frac{8}{9}\) = 251/9 = 27.888
6 \(\frac{5}{8}\) = 53/8 = 6.625
27.888 is closer to 30
6.625 is closer 7
30/7 = 5
6 > 5
\(29 \frac{4}{5} \div 5 \frac{1}{6}\) > \(27 \frac{8}{9} \div 6 \frac{5}{8}\)

Question 12.
\(55 \frac{5}{6} \div 6 \frac{7}{10}\) _______ \(11 \frac{5}{7} \div \frac{5}{8}\)

Answer:
\(55 \frac{5}{6} \div 6 \frac{7}{10}\) < \(11 \frac{5}{7} \div \frac{5}{8}\)

Explanation:
55 \(\frac{5}{6}\) = 335/6 = 55.833
6 \(\frac{7}{10}\) = 67/10 = 6.7
55.833 is closer to 56
6.7 is closer to 7
56/7 = 8
11 \(\frac{5}{7}\) = 82/7 = 11.714
\(\frac{5}{8}\) = 0.625
11.714 is closer to 12
0.625 is closer to 1
12/1 = 12
8 < 12

Question 13.
Marion is making school flags. Each flag uses 2 \(\frac{3}{4}\) yards of felt. Marion has 24 \(\frac{1}{8}\) yards of felt. About how many flags can he make?
About _______ flags

Answer:
About 8 flags

Explanation:
Marion is making school flags. Each flag uses 2 \(\frac{3}{4}\) yards of felt. Marion has 24 \(\frac{1}{8}\) yards of felt.
2 \(\frac{3}{4}\) = 11/4
24 \(\frac{1}{8}\) = 193/8
193/8 ÷ 11/4
193/8 x 4/11 = 8.77
About 8 flags

Question 14.
A garden snail travels about 2 \(\frac{3}{5}\) feet in 1 minute. At that speed, about how many hours would it take the snail to travel 350 feet?
About _______ hours

Answer:
About 2 hours

Explanation:
2 \(\frac{3}{5}\) = 2.6
That’s how long he travels in one minute. There are 60 minutes in an hour so multiply it by 60 and see if that gets you close to 350.
60 x 2.6 = 156
Now let’s add one more hour.
156 + 156 = 312
14 x 2.6 = 36.4
312 + 36.4 = 348.4
348.4 + 2.6 = 351
So two hours and fourteen minutes

Problem Solving + Applications – Page No. 104

What’s the Error?

Question 15.
Megan is making pennants from a piece of butcher paper that is 10 \(\frac{3}{8}\) yards long. Each pennant requires \(\frac{3}{8}\) yard of paper. To estimate the number of pennants she could make, Megan estimated the quotient 10 \(\frac{3}{8}\) ÷ \(\frac{3}{8}\).
Look at how Megan solved the problem. Find her error
Estimate:
10 \(\frac{3}{8}\) ÷ \(\frac{3}{8}\)
10 ÷ \(\frac{1}{2}\) = 5
Correct the error. Estimate the quotient.
So, Megan can make about _____ pennants.
Describe the error that Megan made
Explain Tell which compatible numbers you used to estimate 10 \(\frac{3}{8}\) ÷ \(\frac{3}{8}\). Explain why you chose those numbers.
Type below:
__________

Answer:
10 \(\frac{3}{8}\) ÷ \(\frac{3}{8}\)
10 \(\frac{3}{8}\) = 83/8 = 10.375
\(\frac{3}{8}\) = 0.375
She had written 10 ÷ \(\frac{1}{2}\) = 5
10.375 is closer to 10
0.375 is closer to 0.5
10/0.5 = 20
But she has written 5 instead of 20.
Megan can make about 20 pennants.

For numbers 16a–16c, estimate to compare. Choose <, >, or =.

Question 16.
16a. 18 \(\frac{3}{10} \div 2 \frac{5}{6}\) ? \(30 \frac{7}{9} \div 3 \frac{1}{3}\)
_____

Answer:
16a. 18 \(\frac{3}{10} \div 2 \frac{5}{6}\) < \(30 \frac{7}{9} \div 3 \frac{1}{3}\)

Explanation:
18 \(\frac{3}{10}\) = 183/10 = 18.3
2 \(\frac{5}{6}\) = 17/6 = 2.833
18.3 is closer to 18
2.833 is closer to 3
18/3 = 6
30 \(\frac{7}{9}\) = 277/9 = 30.777
3 \(\frac{1}{3}\) = 10/3 = 3.333
30.777 is closer to 30
3.333 is closer to 3
30/3 = 10
6 < 10

Question 16.
16b. 17 \(\frac{4}{5} \div 6 \frac{1}{6}\) ? \(19 \frac{8}{9} \div 4 \frac{5}{8}\)
_____

Answer:
17 \(\frac{4}{5} \div 6 \frac{1}{6}\) < \(19 \frac{8}{9} \div 4 \frac{5}{8}\)

Explanation:
17 \(\frac{4}{5}\) = 89/5 = 17.8
6 \(\frac{1}{6}\) = 37/6 = 6.1666
17.8 is closer to 18
6.1666 is closer to 6
18/6 = 3
19 \(\frac{8}{9}\) = 179/9 = 19.888
4 \(\frac{5}{8}\) = 37/8 = 4.625
19.888 is closer to 20
4.625 is closer to 5
20/5 = 4
3 < 4
17 \(\frac{4}{5} \div 6 \frac{1}{6}\) < \(19 \frac{8}{9} \div 4 \frac{5}{8}\)

Question 16.
16c. 17 \(\frac{5}{6} \div 6 \frac{1}{4}\) ? \(11 \frac{5}{7} \div 2 \frac{3}{4}\)
_____

Answer:
17 \(\frac{5}{6} \div 6 \frac{1}{4}\) < \(11 \frac{5}{7} \div 2 \frac{3}{4}\)

Explanation:
17 \(\frac{5}{6}\) = 107/6 = 17.833
6 \(\frac{1}{4}\) = 25/4 = 6.25
17.833 is closer to 18
6.25 is closer to 6
18/6 = 3
11 \(\frac{5}{7}\) = 82/7 = 11.714
2 \(\frac{3}{4}\) = 11/4 = 2.75
11.714 is closer to 12
2.75 is closer to 3
12/3 = 4
3 < 4
17 \(\frac{5}{6} \div 6 \frac{1}{4}\) < \(11 \frac{5}{7} \div 2 \frac{3}{4}\)

Estimate Quotients – Page No. 105

Estimate using compatible numbers.

Question 1.
\(12 \frac{3}{16} \div 3 \frac{9}{10}\)
______

Answer:
3

Explanation:
12 \(\frac{3}{16}\) = 195/16 = 12.1875
3 \(\frac{9}{10}\) = 39/10 = 3.9
12.1875 is closer to 12
3.9 is closer to 4
12/4 = 3

Question 2.
\(15 \frac{3}{8} \div \frac{1}{2}\)
______

Answer:
30

Explanation:
15 \(\frac{3}{8}\) = 123/8 = 15.375
\(\frac{1}{2}\) = 0.5
15.375 is closer to 15
0.5 is closer to 0.5
15/0.5 = 30

Question 3.
\(22 \frac{1}{5} \div 1 \frac{5}{6}\)
______

Answer:
11

Explanation:
22 \(\frac{1}{5}\) = 111/5 = 22.2
1 \(\frac{5}{6}\) = 11/6 = 1.8333
22.2 is closer to 22
1.8333 is closer to 2
22/2 = 11

Question 4.
\(7 \frac{7}{9} \div \frac{4}{7}\)
______

Answer:
16

Explanation:
7 \(\frac{7}{9}\) = 70/9 = 7.777
\(\frac{4}{7}\) = 0.571
7.777 is closer to 8
0.571 is closer to 0.5
8/0.5 = 16

Question 5.
\(18 \frac{1}{4} \div 2 \frac{4}{5}\)
______

Answer:
6

Explanation:
18 \(\frac{1}{4}\) = 73/4 = 18.25
2 \(\frac{4}{5}\) = 14/5 = 2.8
18.25 is closer to 18
2.8 is closer to 3
18/3 = 6

Question 6.
\(\frac{15}{16} \div \frac{1}{7}\)
______

Answer:
10

Explanation:
\(\frac{15}{16}\) = 0.9375
\(\frac{1}{7}\) = 0.1428
0.9375 is closer to 1
0.1428 is closer to 0.1
1/0.1 = 10

Question 7.
\(14 \frac{7}{8} \div \frac{5}{11}\)
______

Answer:
30

Explanation:
14 \(\frac{7}{8}\) = 119/8 = 14.875
\(\frac{5}{11}\) = 0.4545
14.875 is closer to 15
0.4545 is closer to 0.5
15/0.5 = 30

Question 8.
\(53 \frac{7}{12} \div 8 \frac{11}{12}\)
______

Answer:
6

Explanation:
53 \(\frac{7}{12}\) = 643/12 = 53.58
8 \(\frac{11}{12}\) = 107/12 = 8.916
53.58 is closer to 54
8.916 is closer to 9
54/9 = 6

Question 9.
\(1 \frac{1}{6} \div \frac{1}{9}\)
______

Answer:
10

Explanation:
1 \(\frac{1}{6}\) = 7/6 = 1.166
\(\frac{1}{9}\) = 0.111
1.166 is closer to 1
0.111 is closer to 0.1
1/0.1 = 10

Problem Solving

Question 10.
Estimate the number of pieces Sharon will have if she divides 15 \(\frac{1}{3}\) yards of fabric into 4 \(\frac{4}{5}\) yard lengths.
About ______ pieces

Answer:
About 3 pieces

Explanation:
Sharon will have if she divides 15 \(\frac{1}{3}\) yards of fabric into 4 \(\frac{4}{5}\) yard lengths.
3 7/36 is the answer.
So, about 3 pieces

Question 11.
Estimate the number of \(\frac{1}{2}\) quart containers Ethan can fill from a container with 8 \(\frac{7}{8}\) quarts of water.
About ______ containers

Answer:
About 18 containers

Question 12.
How is estimating quotients different from estimating products?
Type below:
__________

Answer:
To estimate products and quotients, you need to first round the numbers. To round to the nearest whole number, look at the digit in the tenths place. If it is less than 5, round down. If it is 5 or greater, round up. Remember that an estimate is an answer that is not exact, but is approximate and reasonable.
Let’s look at an example of estimating a product.
Estimate the product: 11.256×6.81
First, round the first number. Since there is a 2 in the tenths place, 11.256 rounds down to 11.
Next, round the second number. Since there is an 8 in the tenths place, 6.81 rounds up to 7.
Then, multiply the rounded numbers. 11×7=77
The answer is 77.
Let’s look at an example of estimating a quotient.
Estimate the quotient: 91.93÷4.39
First, round the first number. Since there is a 9 in the tenths place, 91.93 rounds up to 92.
Next, round the second number. Since there is a 3 in the tenths place, 4.39 rounds down to 4.
Then, divide the rounded numbers.
92÷4=23
The answer is 23.

Lesson Check – Page No. 106

Question 1.
Each loaf of pumpkin bread calls for 1 \(\frac{3}{4}\) cups of raisins. About how many loaves can be made from 10 cups of raisins?
About ______ loaves

Answer:
About 5 loaves

Explanation:
Divide 10 by 1 3/4.
The answer is 5.714285
So you can make about 5 loaves of bread with 10 cups of raisins if each loaf needs 1 3/4 cups of raisins.

Question 2.
Perry’s goal is to run 2 \(\frac{1}{4}\) miles each day. One lap around the school track is \(\frac{1}{3}\) mile. About how many laps must he run to reach his goal?
About ______ laps

Answer:
About 9 laps

Explanation:
Perry’s goal is to run 2 \(\frac{1}{4}\) miles each day. One lap around the school track is \(\frac{1}{3}\) mile.
2 \(\frac{1}{4}\) = 9/4 = 2.25
\(\frac{1}{3}\) = 0.333
Perry will have to run 9 laps to reach his goal.

Spiral Review

Question 3.
A recipe calls for \(\frac{3}{4}\) teaspoon of red pepper. Uri wants to use \(\frac{1}{3}\) of that amount. How much red pepper should he use?
\(\frac{□}{□}\) teaspoon

Answer:
\(\frac{1}{4}\) teaspoon

Explanation:
A recipe calls for \(\frac{3}{4}\) teaspoon of red pepper. Uri wants to use \(\frac{1}{3}\) of that amount.
\(\frac{1}{3}\) of \(\frac{3}{4}\) = \(\frac{1}{4}\)

Question 4.
A recipe calls for 2 \(\frac{2}{3}\) cups of apple slices. Zoe wants to use 1 \(\frac{1}{2}\) times this amount. How many cups of apples should Zoe use?
______ cups

Answer:
4 cups

Explanation:
A recipe calls for 2 2/3 cups of apple slices.
Zoe wants to use 1 1/2 times this amount.
We will multiply the number of apple slices to 1 1/2
2 2/3 X 1 1/2
8/3 X3/2 = 24/6 = 4 cups
Zoe will use 4 cups of apple slices.

Question 5.
Edgar has 2.8 meters of rope. If he cuts it into 7 equal parts, how long will each piece be?
______ meters

Answer:
0.4 meters

Explanation:
2.8/7 = 0.4 meters

Question 6.
Kami has 7 liters of water to fill water bottles that each hold 2.8 liters. How many bottles can she fill?
______ bottles

Answer:
2 bottles

Explanation:
7/2.8 = 2.5
she can only fill 2 because anything over that would be 8.4 liters of water

Share and Show – Page No. 109

Estimate. Then find the quotient.

Question 1.
\(\frac{5}{6}\) ÷ 3
\(\frac{□}{□}\)

Answer:
\(\frac{3}{10}\)

Explanation:
5/6 = 0.8333 is closer to 0.9
0.9/3 = 0.3 = 3/10

Use a number line to find the quotient.

Question 2.
\(\frac{3}{4} \div \frac{1}{8}\)
_______

Answer:
grade 6 chapter 2 image 7

Explanation:
3/4 x 8 = 3 x 2 = 6

Question 3.
\(\frac{3}{5} \div \frac{3}{10}\)
_______

Answer:

Explanation:
3/5 x 10/3 = 2

Estimate. Then write the quotient in simplest form.

Question 4.
\(\frac{3}{4} \div \frac{5}{6}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{1}\)

Explanation:
3/4 = 0.75 is closer to 0.8
5/6 = 0.8333 is closer to 0.8
0.8/0.8 = 1

Practice and Homework Lesson 2.7 Question 5.
\(3 \div \frac{3}{4}\)
_______

Answer:
4

Explanation:
3/4 = 0.75
3/0.75 = 4

Question 6.
\(\frac{1}{2} \div \frac{3}{4}\)
\(\frac{□}{□}\)

Answer:
\(\frac{625}{1000}\)

Explanation:
1/2 = 0.5
3/4 = 0.75 is closer to 0.8
0.5/0.8 = 0.625 = 625/1000

Question 7.
\(\frac{5}{12} \div 3\)
\(\frac{□}{□}\)

Answer:
\(\frac{2}{10}\)

Explanation:
5/12 = 0.4166 is closer to 0.6
0.6/3 = 0.2 = 2/10

On Your Own

Practice: Copy and Solve Estimate. Then write the quotient in simplest form

Question 8.
\(2 \div \frac{1}{8}\)
_______

Answer:
20

Explanation:
1/8 = 0.125 is closer to 0.1
2/0.1 = 20

Question 9.
\(\frac{3}{4} \div \frac{3}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{1}\)

Explanation:
3/4 = 0.75 is closer to 0.8
3/5 = is 0.6 closer to 0.8
0.8/0.8 = 1

Question 10.
\(\frac{2}{5} \div 5\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{10}\)

Explanation:
2/5 = 0.4 is closer to 0.5
0.5/5 = 0.1 = 1/10

Question 11.
\(4 \div \frac{1}{7}\)
_______

Answer:
40

Explanation:
1/7 = 0.1428 is closer to 0.1
4/0.1 = 40

Practice: Copy and Solve Evaluate using the order of operations.

Write the answer in simplest form.

Question 12.
\(\left(\frac{3}{5}+\frac{1}{10}\right) \div 2\)
\(\frac{□}{□}\)

Answer:
\(\frac{7}{20}\)

Explanation:
3/5 + 1/10 = 7/10 = 0.7
0.7/2 = 7/20

Question 13.
\(\frac{3}{5}+\frac{1}{10} \div 2\)
\(\frac{□}{□}\)

Answer:
\(\frac{13}{20}\)

Explanation:
\(\frac{3}{5}+\frac{1}{10} \div 2\)
(1/10)/2 = 1/20
3/5 + 1/20 = 0.65 = 13/20

Question 14.
\(\frac{3}{5}+2 \div \frac{1}{10}\)
_______ \(\frac{□}{□}\)

Answer:

Explanation:
2/(1/10) = 1/5
3/5 + 1/5 = 4/5

Question 15.
Generalize Suppose the divisor and the dividend of a division problem are both fractions between 0 and 1, and the divisor is greater than the dividend. Is the quotient less than, equal to, or greater than 1?
Type below:
__________

Answer:
Divisor and Dividend are fractions lying between 0 and 1
Also, Divisor > Dividend
A smaller number is being divided by a larger number
Whenever a smaller number is divided by a larger number, the quotient is less than 1
Example:
0,5/0,6 Here, they are both numbers between 0 and 1, and the divisor is greater than the dividend.
The result is 0,8333, LESS THAN 1
Hence, the answer is that the quotient will be less than 1

Problem Solving + Applications – Page No. 110

Use the table for 16–19.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 16

Question 16.
Kristen wants to cut ladder rungs from a 6 ft board. How many ladder rungs can she cut?
_______ ladder rungs

Answer:
8 ladder rungs

Explanation:
Kristen wants to cut ladder rungs from a 6 ft board.
ladder rungs = 3/4 ft
6/(3/4) = 8 rungs

Question 17.
Pose a Problem Look back at Problem 16. Write and solve a new problem by changing the length of the board Kristen is cutting for ladder rungs.
Type below:
__________

Answer:
Kristen wants to cut ladder rungs from a 9 ft board. How many ladder rungs can she cut?
Kristen wants to cut ladder rungs from a 9 ft board.
ladder rungs = 3/4 ft
9/(3/4) = 12 rungs

Question 18.
Dan paints a design that has 8 equal parts along the entire length of the windowsill. How long is each part of the design?
\(\frac{□}{□}\) yards

Answer:
\(\frac{1}{16}\) yards

Explanation:
Dan paints a design that has 8 equal parts along the entire length of the windowsill.
(1/2)/8 = 1/2 x 1/8 = 1/16 yards

Question 19.
Dan has a board that is \(\frac{15}{16}\) yd. How many “Keep Out” signs can he make if the length of the sign is changed to half of the original length?
_______ signs

Answer:
3 signs

Explanation:
Dan has a board that is \(\frac{15}{16}\) yd.
If the length of the sign is changed to half of the original length, (5/8)/2 = 5/16
(15/16) ÷ 5/16 = 15/16 x 16/5 = 3

Question 20.
Lauren has \(\frac{3}{4}\) cup of dried fruit. She puts the dried fruit into bags, each holding \(\frac{1}{8}\) cup. How many bags will Lauren use? Explain your answer using words and numbers.
Type below:
__________

Answer:
6

Explanation:
Lauren has \(\frac{3}{4}\) cup of dried fruit. She puts the dried fruit into bags, each holding \(\frac{1}{8}\) cup.
3/4 ÷ 1/8 = 3/4 x 8 = 6
Lauren has 3/4 and in 1/4 there are 2 1/8s. That 3 fourths times two = 6 so 6 one eights

Divide Fractions – Page No. 111

Estimate. Then write the quotient in simplest form.

Question 1.
\(5 \div \frac{1}{6}\)
_____

Answer:
25

Explanation:
1/6 = 0.166 is closer to 0.2
5/0.2 = 25

Question 2.
\(\frac{1}{2} \div \frac{1}{4}\)
_____

Answer:
5

Explanation:
1/2 = 0.5 is closer to 1
1/4 = 0.25 is closer to 0.2
1/0.2 = 5

Question 3.
\(\frac{4}{5} \div \frac{2}{3}\)
_____ \(\frac{□}{□}\)

Answer:
1 \(\frac{1}{5}\)

Explanation:
4/5 = 0.8 is closer to 0.8
2/3 = 0.66 is closer to 0.6
0.8/0.6 = 1 1/5

Question 4.
\(\frac{14}{15} \div 7\)
\(\frac{□}{□}\)

Answer:
\(\frac{2}{15}\)

Explanation:
14/15 = 0.9333
0.9/7 = 2/15

Question 5.
\(8 \div \frac{1}{3}\)
_____

Answer:
20

Explanation:
1/3 = 0.33 is closer to 0.4
8/0.4 = 20

Question 6.
\(\frac{12}{21} \div \frac{2}{3}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{1}\)

Explanation:
12/21 = 0.571 is closer to 0.6
2/3 = 0.666 is closer to 0.6
0.6/0.6 = 1

Question 7.
\(\frac{5}{6} \div \frac{5}{12}\)
_____

Answer:
2

Explanation:
5/6 = 0.833 is closer to 0.8
5/12 = 0.416 is closer to 0.4
0.8/0.4 = 2

Question 8.
\(\frac{5}{8} \div \frac{1}{2}\)
_____ \(\frac{□}{□}\)

Answer:
1 \(\frac{2}{10}\)

Explanation:
5/8 = 0.625 is closer to 0.6
1/2 = 0.5 is closer to 0.5
0.6/0.5 = 1.2 = 1 2/10

Question 9.
Joy ate \(\frac{1}{4}\) of a pizza. If she divides the rest of the pizza into pieces equal to \(\frac{1}{8}\) pizza for her family, how many pieces will her family get?
_____ pieces

Answer:
6 pieces

Explanation:
The pizza is divided into 4 pieces, Joy ate 1/4.
So, the left pieces are 1 – 1/4 = 3/4
Now, 3/4 of a pizza and Joy will divide the rest of the pizza in pieces equal to 1/8, so we need to make a division
(3/4) ÷ (1/8) = 24/4 = 6 pieces.

Question 10.
Hideko has \(\frac{3}{5}\) yard of ribbon to tie on balloons for the festival. Each balloon will need \(\frac{3}{10}\) yard of ribbon. How many balloons can Hideko tie with ribbon?
_____ balloons

Answer:
2 balloons

Explanation:
3/10 yard of ribbon required to tie = 1 balloon
3/5 yard of ribber can tie = (3/5) ÷ (3/10) = 2 ballons
With 3/5 yard, Hideko can tie 2 balloons

Problem Solving

Question 11.
Rick knows that 1 cup of glue weighs \(\frac{1}{18}\) pound. He has \(\frac{2}{3}\) pound of glue. How many cups of glue does he have?
_____ cups

Answer:
12 cups

Explanation:
For 1/18lb, 1 cup
For 2/3lb, x cups.
1/8x = 1 x 2/3
1/8x = 2/3
x = 2/3 x 18
x = 2 x 6 = 12 cups

Question 12.
Mrs. Jennings had \(\frac{5}{7}\) gallon of paint. She gave \(\frac{1}{7}\) gallon each to some students. How many students received paint if Mrs. Jennings gave away all the paint?
_____ students

Answer:
4 students

Explanation:
Mrs. Jennings had \(\frac{5}{7}\) gallon of paint. She gave \(\frac{1}{7}\) gallon each to some students.
\(\frac{5}{7}\) ÷ \(\frac{1}{7}\) = 25/7 = 3.571 is closer to 4

Question 13.
Write a word problem that involves two fractions. Include the solution.
Type below:
__________

Answer:
Mrs. Jennings had \(\frac{5}{7}\) gallon of paint. She gave \(\frac{1}{7}\) gallon each to some students. How many students received paint if Mrs. Jennings gave away all the paint?
Answer:
Mrs. Jennings had \(\frac{5}{7}\) gallon of paint. She gave \(\frac{1}{7}\) gallon each to some students.
\(\frac{5}{7}\) ÷ \(\frac{1}{7}\) = 25/7 = 3.571 is closer to 4

Lesson Check – Page No. 112

Question 1.
There was \(\frac{2}{3}\) of a pizza for 6 friends to share equally. What fraction of the pizza did each person get?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{9}\)

Explanation:
There was \(\frac{2}{3}\) of a pizza for 6 friends to share equally.
\(\frac{2}{3}\) ÷ 6 = 2/3 x 1/6 = 2/18 = 1/9

Question 2.
Rashad needs \(\frac{2}{3}\) pound of wax to make a candle. How many candles can he make with 6 pounds of wax?
_____ candles

Answer:
9 candles

Explanation:
Rashad needs 2/3 pound a wax to make candles.
1 Candle = 2/3 pounds.
So, for 2 pounds,
3 x 2/3 = 3 candles
2 pounds = 3 candles
1 pound = 3/2 candles
So, for 6 pounds,
6 x 3/2 = 9 candles

Spiral Review

Question 3.
Jeremy had \(\frac{3}{4}\) of a submarine sandwich and gave his friend \(\frac{1}{3}\) of it. What fraction of the sandwich did the friend receive?
\(\frac{□}{□}\)

Answer:
\(\frac{1}{4}\)

Explanation:
Jeremy had \(\frac{3}{4}\) of a submarine sandwich and gave his friend \(\frac{1}{3}\) of it.
1/3 x 3/4 = 1/4

Question 4.
Ebony walked at a rate of 3 \(\frac{1}{2}\) miles per hour for 1 \(\frac{1}{3}\) hours. How far did she walk?
_____ \(\frac{□}{□}\)

Answer:
4 \(\frac{2}{3}\)

Explanation:
Ebony walked at a rate of 3 \(\frac{1}{2}\) miles per hour for 1 \(\frac{1}{3}\) hours.
3 1/2 miles = 7/2 miles … 1 hour
x miles = ? … 1 1/3 hours = 4/3 hours
7/2 x 4/3 = 1 x x
x = 7/2 x 4/3
x = 14/3 = 4 2/3 miles
The correct result would be 4 2/3 miles.

Question 5.
Penny uses \(\frac{3}{4}\) yard of fabric for each pillow she makes. How many pillows can she make using 6 yards of fabric?
_____ pillows

Answer:
8 pillows

Explanation:
Penny uses \(\frac{3}{4}\) yard of fabric for each pillow she makes.
Using 6 yards of fabric 6/(3/4) = 24/3 = 8

Question 6.
During track practice, Chris ran 2.5 laps in 81 seconds. What was his average time per lap?
_____ seconds

Answer:
32.4 seconds

Explanation:
During track practice, Chris ran 2.5 laps in 81 seconds.
81/2.5 = 32.4 seconds

Share and Show – Page No. 115

Use the model to find the quotient.

Question 1.
\(3 \frac{1}{3} \div \frac{1}{3}\)
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 17
_____

Answer:
21

Explanation:
Model 3 with 3 hexagonal blocks.
Model 1/2 with 1 trapezoid block.
For 1/6,
6 triangle blocks are equal to 1 hexagon.
So, a triangle block shows 1/6.
Count the triangles.
There are 21 triangle blocks.
So, 3 1/2 ÷ 1/6 = 21.

Question 2.
\(2 \frac{1}{2} \div \frac{1}{6}\)
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 18
_____

Answer:
15

Explanation:
Model 2 with 2 hexagonal blocks.
Model 1/2 with 1 trapezoid block.
For 1/6,
6 triangle blocks are equal to 1 hexagon.
So, a triangle block shows 1/6.
Count the triangles.
There are 15 triangle blocks.
So, \(2 \frac{1}{2} \div \frac{1}{6}\) = 15.

Use pattern blocks to find the quotient. Then draw the model.

Question 3.
\(2 \frac{2}{3} \div \frac{1}{6}\)
_____

Answer:
grade 6 chapter 2 image 1

Explanation:
2 2/3 = 8/3
8/3 ÷ 1/6 = 16

Question 4.
\(3 \frac{1}{2} \div \frac{1}{2}\)
_____

Answer:
grade 6 chapter 2 image 2

Explanation:
3 1/2 = 7/2
7/2 ÷ 1/2 = 7

Draw a model to find the quotient.

Question 5.
\(3 \frac{1}{2} \div 3\)
_____ \(\frac{□}{□}\)

Answer:
grade 6 chapter 2 image 3

Explanation:
3 1/2 = 7/2
7/2 ÷ 3 = 21/2

Question 6.
\(1 \frac{1}{4} \div 2\)
\(\frac{□}{□}\)

Answer:
grade 6 chapter 2 image 4

Explanation:
1/4 ÷ 2 = 1/2

Question 7.
Use Appropriate Tools Explain how models can be used to divide mixed numbers by fractions or whole numbers
Type below:
__________

Answer:
Multiply the whole number part by the fraction’s denominator. Add that to the numerator. Then write the result on top of the denominator.

Problem Solving + Applications – Page No. 116

Use a model to solve. Then write an equation for the model.

Question 8.
Use Models Eliza opens a box of bead kits. The box weighs 2 \(\frac{2}{3}\) lb. Each bead kit weighs \(\frac{1}{6}\) lb. How many kits are in the box? What does the answer mean?
Type below:
__________

Answer:
grade 6 chapter 2 image 6
16 kits are in the box

Explanation:
Eliza opens a box of bead kits. The box weighs 2 \(\frac{2}{3}\) lb. Each bead kit weighs \(\frac{1}{6}\) lb, 2 \(\frac{2}{3}\) ÷ \(\frac{1}{6}\) = 8/3 ÷ 1/6 = 16.
16 kits are in the box

Question 9.
Hassan has two boxes of trail mix. Each box holds 1 \(\frac{2}{3}\) lb of trail mix. He eats \(\frac{1}{3}\) lb of trail mix each day. How many days can Hassan eat trail mix before he runs out?
_____ days

Answer:
10 days

Explanation:
Hassan has two boxes of trail mix. Each box holds 1 \(\frac{2}{3}\) lb of trail mix.
1 \(\frac{2}{3}\) = 5/3
2 x (5/3) = 10/3
He eats \(\frac{1}{3}\) lb of trail mix each day.
10/3 ÷ 1/3 = 10
Hassan eats trail mix for 10 days before he runs out.

Question 10.
Sense or Nonsense? Steve made this model to show \(2 \frac{1}{3} \div \frac{1}{6}\). He says that the quotient is 7. Is his answer sense or nonsense? Explain your reasoning
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 19
Type below:
__________

Answer:
\(2 \frac{1}{3} \div \frac{1}{6}\) = 7/3 ÷ 1/6 = 14.
He said the quotient is 7.
His answer is Nonsense.

Question 11.
Eva is making muffins to sell at a fundraiser. She has 2 \(\frac{1}{4}\) cups of flour, and the recipe calls for \(\frac{3}{4}\) cup of flour for each batch of muffins. Explain how to use a model to find the number of batches of muffins Eva can make.
Type below:
__________

Answer:
3

Explanation:
Eva is making muffins to sell at a fundraiser. She has 2 \(\frac{1}{4}\) cups of flour, and the recipe calls for \(\frac{3}{4}\) cup of flour for each batch of muffins.
2 \(\frac{1}{4}\) ÷ \(\frac{3}{4}\) = 9/4 ÷ 3/4 = 3

Model Mixed Number Division – Page No. 117

Use the model to find the quotient.

Question 1.
\(4 \frac{1}{2} \div \frac{1}{2}\)
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 20
_____

Answer:
9

Explanation:
Count the number of trapezoids to find the answer.

Question 2.
\(3 \frac{1}{3} \div \frac{1}{6}\)
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 21
_____

Answer:
20

Use pattern blocks or another model to find the quotient. Then draw the model.

Question 3.
\(2 \frac{1}{2} \div \frac{1}{6}\)
_____

Answer:
grade 6 chapter 2 image 5

Explanation:
Model 2 with 2 hexagonal blocks.
Model 1/2 with 1 trapezoid block.
For 1/6,
6 triangle blocks are equal to 1 hexagon.
So, a triangle block shows 1/6.
Count the triangles.
There are 15 triangle blocks.
So, 212÷16 = 15.

Question 4.
\(2 \frac{3}{4} \div 2\)
_____

Answer:
grade 6 chapter 2 image 6

Explanation:
2 3/4 ÷ 2 = 11/2

Problem Solving

Question 5.
Marty has 2 \(\frac{4}{5}\) quarts of juice. He pours the same amount of juice into 2 bottles. How much does he pour into each bottle?
_____ \(\frac{□}{□}\) quarts

Answer:
1\(\frac{2}{5}\) quarts

Explanation:
Marty has 2 \(\frac{4}{5}\) quarts of juice. He pours the same amount of juice into 2 bottles.
2 \(\frac{4}{5}\) = 14/5 = 2.8
2.8/2 = 1.4 = 1 2/5

Question 6.
How many \(\frac{1}{3}\) pound servings are in 4 \(\frac{2}{3}\) pounds of cheese?
_____ pounds

Answer:
14 pounds

Explanation:
4 2/3 = 14/3
(14/3)/(1/3) = 14

Question 7.
Write a word problem that involves dividing a mixed number by a whole number. Solve the problem and describe how you found the answer.
Type below:
__________

Answer:
How many \(\frac{1}{3}\) pound servings are in 4 \(\frac{2}{3}\) pounds of cheese?
Explanation:
4 2/3 = 14/3
(14/3)/(1/3) = 14

Lesson Check – Page No. 118

Sketch a model to find the quotient.

Question 1.
Emma has 4 \(\frac{1}{2}\) pounds of birdseed. She wants to divide it evenly among 3 bird feeders. How much birdseed should she put in each?
_____ \(\frac{□}{□}\) pounds

Answer:
1\(\frac{1}{2}\) pounds

Explanation:
Emma has 4 1/2 pounds of birdseed.
Convert this to an improper fraction.
4 1/2 = 9/2
Emma wants to divide it evenly among 3 bird feeders.
So, she should put (9/2)/3 = 3/2 = 1 1/2

Question 2.
A box of crackers weighs 11 \(\frac{1}{4}\) ounces. Kaden estimates that one serving is \(\frac{3}{4}\) ounce. How many servings are in the box?
_____ servings

Answer:
15 servings

Explanation:
11 1/4 by 3/4
11 1/4 = 45/4
45/4 / 3/4 = 45/4 × 4/3 = 180/12 = 15
there are 15 servings

Spiral Review

Question 3.
The Ecology Club has volunteered to clean up 4.8 kilometers of highway. The members are organized into 16 teams. Each team will clean the same amount of highway. How much highway will each team clean?
_____ kilometers

Answer:
0.3 kilometers

Explanation:
The Ecology Club has volunteered to clean up 4.8 kilometers of highway. The members are organized into 16 teams.
The total length of the highway is given to clean = 4.8 kilometers
If the members are organized into 16 teams.
4.8/16 = 0.3
Hence, each team will clean 0.3 kilometers of the highway.

Question 4.
Tyrone has $8.06. How many bagels can he buy if each bagel costs $0.65?
_____ bagels

Answer:
12 bagels

Explanation:
$8.06/$0.65 = 12.4
12 bagels

Question 5.
A nail is 0.1875 inches thick. What is its thickness as a fraction? Is 0.1875 inch closer to \(\frac{1}{8}\) inch or \(\frac{1}{4}\) inch on a number line?
Type below:
__________

Answer:
0.1875 = 3/16 which is at the same distance to 1/4 and 1/8
It is the same distance apart.

Question 6.
Maria wants to find the product of 5 \(\frac{3}{20}\) × 3 \(\frac{4}{25}\) using decimals instead of fractions. How can she rewrite the problem using decimals?
Type below:
__________

Answer:
16.274

Explanation:
The decimal for 5 3/20 is 5.15
The decimal for 3 4/25 is 3.16
5.15 × 3.16 = 16.274

Share and Show – Page No. 121

Estimate. Then write the quotient in simplest form.

Question 1.
\(4 \frac{1}{3} \div \frac{3}{4}\)
______ \(\frac{□}{□}\)

Answer:
5\(\frac{375}{1000}\)

Explanation:
4 1/3 = 13/3 = 4.333 is closer to 4.3
3/4 = 0.75 is closer to 0.8
4.3/0.8 = 5.375 = 5 375/1000

Question 2.
Six hikers shared 4 \(\frac{1}{2}\) lb of trail mix. How much trail mix did each hiker receive?
\(\frac{□}{□}\)

Answer:
\(\frac{75}{100}\)

Explanation:
6 hikers = 4.5 lbs of trail mix
4.5/6= .75 lbs each hiker.

Question 3.
\(5 \frac{2}{3} \div 3\)
______ \(\frac{□}{□}\)

Answer:
2\(\frac{947}{1000}\)

Explanation:
5 2/3 = 17/3 = 5.666 is closer to 5.6
5.6/3 = 1.866 is closer to 1.9
5.6/1.9 = 2.947 = 2 947/1000

Question 4.
\(7 \frac{1}{2} \div 2 \frac{1}{2}\)
______

Answer:
3

Explanation:
7 1/2 = 15/2 = 7.5
2 1/2 = 5/2 = 2.5
7.5/2.5 = 3

On Your Own

Estimate. Then write the quotient in simplest form.

Question 5.
\(5 \frac{3}{4} \div 4 \frac{1}{2}\)
______ \(\frac{□}{□}\)

Answer:
1\(\frac{27}{100}\)

Explanation:
5 3/4 = 23/4 = 5.75
4 1/2 = 9/2 = 4.5
5.75/4.5 = 1.27 = 1 27/100

Question 6.
\(5 \div 1 \frac{1}{3}\)
______ \(\frac{□}{□}\)

Answer:
3\(\frac{84}{100}\)

Explanation:
1 1/3 = 4/3 = 1.33 is closer to 1.3
5/1.3 = 3.84 = 3 84/100

Divide Mixed Numbers Lesson 2.9 Question 7.
\(6 \frac{3}{4} \div 2\)
______ \(\frac{□}{□}\)

Answer:
3\(\frac{2}{5}\)

Explanation:
6 3/4 = 27/4 = 6.75 is closer to 6.8
6.8/2 = 3.4 = 3 2/5

Question 8.
\(2 \frac{2}{9} \div 1 \frac{3}{7}\)
______ \(\frac{□}{□}\)

Answer:
1\(\frac{571}{1000}\)

Explanation:
2 2/9 = 20/9 = 2.22 is closer to 2.2
1 3/7 = 10/7 = 1.428 is closer to 1.4
2.2/1.4 = 1.571 = 1 571/1000

Question 9.
How many 3 \(\frac{1}{3}\) yd pieces can Amanda get from a 3 \(\frac{1}{3}\) yd ribbon?
______

Answer:
1

Explanation:
(3 1/3) ÷ (3 1/3) = 1

Question 10.
Samantha cut 6 \(\frac{3}{4}\) yd of yarn into 3 equal pieces. Explain how she could use mental math to find the length of each piece
Type below:
__________

Answer:
27/12

Explanation:
Samantha cut 6 \(\frac{3}{4}\) yd of yarn into 3 equal pieces.
6 3/4 = 27/4
(27/4)/3
(27/4)(1/3) = 27/12

Evaluate Algebra Evaluate using the order of operations. Write the answer in simplest form.

Question 11.
\(1 \frac{1}{2} \times 2 \div 1 \frac{1}{3}\)
_____ \(\frac{□}{□}\)

Answer:
2\(\frac{1}{4}\)

Explanation:
(1 1/2) × 2 = 3/2 × 2 = 3
1 1/3 = 4/3
3/(4/3) = 9/4 = 2.25 = 2 1/4

Question 12.
\(1 \frac{2}{5} \div 1 \frac{13}{15}+\frac{5}{8}\)
_____ \(\frac{□}{□}\)

Answer:
1\(\frac{3}{8}\)

Explanation:
(1 2/5)/(1 13/15) = (7/5)/(28/15) = 3/4 = 0.75
0.75 + 0.625 = 1.375 = 1 3/8

Question 13.
\(3 \frac{1}{2}-1 \frac{5}{6} \div 1 \frac{2}{9}\)
_____

Answer:
2

Explanation:
(1 5/6)/(1 2/9) = (11/6)/11/9 = 3/2 = 1 1/2 = 1.5
3 1/2 = 7/2 = 3.5
3.5 – 1.5 = 2

Question 14.
Look for a Pattern Find these quotients: \(20 \div 4 \frac{4}{5}\), \(10 \div 4 \frac{4}{5}\), \(5 \div 4 \frac{4}{5}\). Describe a pattern you see.
Type below:
__________

Answer:
20 ÷ 4 4/5 = 20 ÷ 24/5 = 20/4.8 = 4.1666
10 ÷ 4 4/5 = 10 ÷ 24/5 = 10/4.8 = 2.08333
5 ÷ 4 4/5 = 5 ÷ 24/5 = 5/4.8 = 1.04166
The pattern is multiplied by 2 every time.

Page No. 122

Question 15.
Dina hikes \(\frac{1}{2}\) of the easy trail and stops for a break every 3 \(\frac{1}{4}\) miles. How many breaks will she take?
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 22
a. What problem are you asked to solve?
Type below:
__________

Answer:
How many breaks Dina will take when hikes \(\frac{1}{2}\) of the easy trail and stops for a break every 3 \(\frac{1}{4}\) mile.

Question 15.
b. How will you use the information in the table to solve the problem?
Type below:
__________

Answer:
Dina easy trail length, break time

Question 15.
c. How can you find the distance Dina hikes? How far does she hike?
______ \(\frac{□}{□}\) miles

Answer:
9\(\frac{3}{4}\) miles

Explanation:
19 1/2 × 1/2 = 39/2 × 1/2 = 39/4 = 9 3/4

Question 15.
d. What operation will you use to find how many breaks Dina takes?
Type below:
__________

Answer:
Division

Question 15.
e. How many breaks will Dina take?
______ breaks

Answer:
3 breaks

Explanation:
39/4 ÷ 13/4 = 3

Question 16.
Carlo packs 15 \(\frac{3}{4}\) lb of books in 2 boxes. Each book weighs 1 \(\frac{1}{8}\) lb. There are 4 more books in Box A than in Box B. How many books are in Box A? Explain your work.
______ books

Answer:
Carlo packs 15 \(\frac{3}{4}\) lb of books in 2 boxes. Each book weighs 1 \(\frac{1}{8}\) lb.
15 \(\frac{3}{4}\) ÷ 1 \(\frac{1}{8}\) = 63/4 ÷ 9/8 = 14
14 books available in 2 boxes.
There are 4 more books in Box A than in Box B.
Box A contains 5 + 4 = 9 books
Box B contains 5 books

Question 17.
Rex’s goal is to run 13 \(\frac{3}{4}\) miles over 5 days. He wants to run the same distance each day. Jordan said that Rex would have to run 3 \(\frac{3}{4}\) miles each day to reach his goal. Do you agree with Jordan? Explain your answer using words and numbers.
Type below:
__________

Answer:
Rex’s goal is to run 13 \(\frac{3}{4}\) miles over 5 days. He wants to run the same distance each day.
13 \(\frac{3}{4}\) ÷ 5 = 55/4 ÷ 5 = 11/4 or 2 3/4.
Jordan answer is wrong

Divide Mixed Numbers – Page No. 123

Estimate. Then write the quotient in simplest form.

Question 1.
\(2 \frac{1}{2} \div 2 \frac{1}{3}\)
______ \(\frac{□}{□}\)

Answer:
1\(\frac{1}{2}\)

Explanation:
2 1/2 = 5/2 = 2.5 is closer to 3
2 1/3 = 7/3 = 2.333 is closer to 2
3/2 = 1.5 = 1 1/2

Question 2.
\(2 \frac{2}{3} \div 1 \frac{1}{3}\)
______

Answer:
2

Explanation:
2 2/3 = 8/3 = 2.666 is closer to 2.6
1 1/3 = 4/3 = 1.333 is closer to 1.3
2.6/1.3 = 2

Question 3.
\(2 \div 3 \frac{5}{8}\)
\(\frac{□}{□}\)

Answer:
\(\frac{1}{2}\)

Explanation:
3 5/8 = 29/8 = 3.625 is closer to 3.6
2/3.6 = 0.5 = 1/2

Question 4.
\(1 \frac{13}{15} \div 1 \frac{2}{5}\)
\(\frac{□}{□}\)

Answer:
\(\frac{126}{100}\)

Explanation:
1 13/15 = 28/15 = 1.8666 is closer to 1.9
1 2/5 = 7/5 = 1.4 is closer to 1.5
1.9/1.5 = 1.266
126/100

Question 5.
\(10 \div 6 \frac{2}{3}\)
______ \(\frac{□}{□}\)

Answer:
1\(\frac{1}{2}\)

Explanation:
6 2/3 = 20/3 = 6.666 is closer to 6.7
10/6.7 = 3/2 = 1 1/2

Question 6.
\(2 \frac{3}{5} \div 1 \frac{1}{25}\)
______ \(\frac{□}{□}\)

Answer:
2\(\frac{3}{5}\)

Explanation:
2 3/5 = 13/5 = 2.6
1 1/25 = 26/25 = 1.04 is closer to 1
2.6/1 = 13/5 or 2 3/5

Question 7.
\(2 \frac{1}{5} \div 2\)
______ \(\frac{□}{□}\)

Answer:
1\(\frac{1}{10}\)

Explanation:
2 1/5 = 11/5 = 2.2 is closer to 2.2
2.2/2 = 1.1 = 11/10 = 1 1/10

Lesson 2.9 Divide Mixed Numbers Question 8.
Sid and Jill hiked 4 \(\frac{1}{8}\) miles in the morning and 1 \(\frac{7}{8}\) miles in the afternoon. How many times as far did they hike in the morning as in the afternoon?
______ \(\frac{□}{□}\) times

Answer:
2\(\frac{1}{5}\) times

Explanation:
Sid and Jill hiked 4 \(\frac{1}{8}\) miles in the morning and 1 \(\frac{7}{8}\) miles in the afternoon.
4 \(\frac{1}{8}\) = 33/8
1 \(\frac{7}{8}\) = 15/8
(33/8) ÷ (15/8) = 33/15 = 11/5 or 2 1/5

Problem Solving

Question 9.
It takes Nim 2 \(\frac{2}{3}\) hours to weave a basket. He worked Monday through Friday, 8 hours a day. How many baskets did he make?
______ baskets

Answer:
15 baskets

Explanation:
he worked (Mon – Fri) 5 days at 8 hrs per day = 5 × 8= 40 hrs
40/ (2 2/3) = 40 / (8/3) = 40 × 3/8 = 120/8 = 15 baskets

Question 10.
A tree grows 1 \(\frac{3}{4}\) feet per year. How long will it take the tree to grow from a height of 21 \(\frac{1}{4}\) feet to a height of 37 feet?
______ years

Answer:
9 years

Explanation:
A tree grows 1 3/4 = 7/4 feet per year.
If you would like to know how long will it take the tree to grow from a height of 21 1/4 = 85/4 feet to a height of 37 feet,
37 – 21 1/4 = 37 – 85/4 = 148/4 – 85/4 = 63/4 = 15 3/4
15 3/4 / 1 3/4 = 63/4 / 7/4 = 63/4 × 4/7 = 9 years

Question 11.
Explain how you would find how many 1 \(\frac{1}{2}\) cup servings there are in a pot that contains 22 \(\frac{1}{2}\) cups of soup.
Type below:
__________

Answer:
Given that, Total number of cups = 22 1/2
The number of cups required for each serving = 1 1/2
The number of servings = 22 1/2 ÷ 1 1/2
= 45/2 ÷ 3/2 = 45/3 = 15

Lesson Check – Page No. 124

Question 1.
Tom has a can of paint that covers 37 \(\frac{1}{2}\) square meters. Each board on the fence has an area of \(\frac{3}{16}\) square meters. How many boards can he paint?
______ boards

Answer:
200 boards

Explanation:
Tom has a can of paint that covers 37 \(\frac{1}{2}\) square meters. Each board on the fence has an area of \(\frac{3}{16}\) square meters.
37 \(\frac{1}{2}\) ÷ \(\frac{3}{16}\) = 200 square meters

Question 2.
A baker wants to put 3 \(\frac{3}{4}\) pounds of apples in each pie she makes. She purchased 52 \(\frac{1}{2}\) pounds of apples. How many pies can she make?
______ pies

Answer:
14 pies

Explanation:
A baker wants to put 3 \(\frac{3}{4}\) pounds of apples in each pie she makes. She purchased 52 \(\frac{1}{2}\) pounds of apples.
52 \(\frac{1}{2}\) ÷ 3 \(\frac{3}{4}\) = 14 pies

Spiral Review

Question 3.
The three sides of a triangle measure 9.97 meters, 10.1 meters, and 0.53 meters. What is the distance around the triangle?
______ meters

Answer:
20.6 meters

Explanation:
The distance around the triangle is called the perimeter, to get it we must add the 3 sides.
So, 9.97 + 10.1 + 0.53 = 20.6 meters

Question 4.
Selena bought 3.75 pounds of meat for $4.64 per pound. What was the total cost of the meat?
$ ______

Answer:
$17.40

Explanation:
Selena bought 3.75 pounds of meat.
The cost of meat of one pound = $4.64
The total cost of the meat = 4.64 × 3.75 = $17.40
The total cost of 3.75 lb of meat was $17.40.

Question 5.
Melanie prepared 7 \(\frac{1}{2}\) tablespoons of a spice mixture. She uses \(\frac{1}{4}\) tablespoon to make a batch of barbecue sauce. Estimate the number of batches of barbecue sauce she can make using the spice mixture.
Type below:
__________

Answer:
30 batches of sauce

Explanation:
Melanie prepared 7 \(\frac{1}{2}\) tablespoons of a spice mixture. She uses \(\frac{1}{4}\) tablespoon to make a batch of barbecue sauce.
4 X 1/4 tbsp = 1 tbsp.
4 X 7 1/2 = 30.
She can make 30 batches of sauce

Question 6.
Arturo mixed together 1.24 pounds of pretzels, 0.78 pounds of nuts, 0.3 pounds of candy, and 2 pounds of popcorn. He then packaged it in bags that each contained 0.27 pounds. How many bags could he fill?
______ bags

Answer:
16 bags

Explanation:
Arturo mixed together 1.24 pounds of pretzels, 0.78 pounds of nuts, 0.3 pounds of candy, and 2 pounds of popcorn.
1.24 + 0.78 + 0.3 + 2 = 4.32
4.32/0.27 = 16

Page No. 127

Question 1.
There is \(\frac{4}{5}\) lb of sand in the class science supplies. If one scoop of sand weighs \(\frac{1}{20}\) lb, how many scoops of sand can Maria get from the class supplies and still leave \(\frac{1}{2}\) lb in the supplies?
Type below:
__________

Answer:
16 scoops

Explanation:
There is \(\frac{4}{5}\) lb of sand in the class science supplies. If one scoop of sand weighs \(\frac{1}{20}\) lb,
\(\frac{4}{5}\) ÷ \(\frac{1}{20}\) = 4/5 × 1/20 = 16 scoops

Question 2.
What if Maria leaves \(\frac{2}{5}\) lb of sand in the supplies? How many scoops of sand can she get?
______ scoops

Answer:
8 scoops

Explanation:
There is \(\frac{2}{5}\) lb of sand in the class science supplies. If one scoop of sand weighs \(\frac{1}{20}\) lb,
\(\frac{2}{5}\) ÷ \(\frac{1}{20}\) = 2/5 × 20 = 8

Question 3.
There are 6 gallons of distilled water in the science supplies. If 10 students each use an equal amount of distilled water and there is 1 gal left in the supplies, how much will each student get?
\(\frac{□}{□}\) gallon

Answer:
\(\frac{1}{2}\) gallon

Explanation:
There are 6 gallons of distilled water in the science supplies.
There is 1 gal left in the supplies, 6 – 1 = 5
10 students each use an equal amount of the distilled water = 5/10 = 1/2
.5 gal for each student

On Your Own – Page No. 128

Question 4.
The total weight of the fish in a tank of tropical fish at Fish ‘n’ Fur was \(\frac{7}{8}\) lb. Each fish weighed \(\frac{1}{64}\) lb. After Eric bought some fish, the total weight of the fish remaining in the tank was \(\frac{1}{2}\) lb. How many fish did Eric buy?
______ fish

Answer:
386 fish

Explanation:
The total weight of the fish in a tank of tropical fish at Fish ‘n’ Fur was \(\frac{7}{8}\) lb. Each fish weighed \(\frac{1}{64}\) lb. After Eric bought some fish, the total weight of the fish remaining in the tank was \(\frac{1}{2}\) lb.
386 is the answer

Question 5.
Fish ‘n’ Fur had a bin containing 2 \(\frac{1}{2}\) lb of gerbil food. After selling bags of gerbil food that each held \(\frac{3}{4}\) lb, \(\frac{1}{4}\) lb of food was left in the bin. If each bag of gerbil food sold for $3.25, how much did the store earn?
$ ______

Answer:
$9.75

Explanation:
The store would earn 9.75$ because 3 bags of gerbil food is sold. Then you would multiply 3 by 3.25.

Question 6.
Describe Niko bought 2 lb of dog treats. He gave his dog \(\frac{3}{5}\) lb of treats one week and \(\frac{7}{10}\) lb of treats the next week. Describe how Niko can find how much is left.
Type below:
__________

Answer:
Niko bought 2 lb of dog treats. He gave his dog \(\frac{3}{5}\) lb of treats one week and \(\frac{7}{10}\) lb of treats the next week.
Let us find the amount of dog food eaten by dogs in two months.
3/5 + 7/10 = 13/10
Now we will subtract the amount of food eaten by the dog from the amount of food initially to find the remaining amount of dog food.
2 – 13/10 = 7/10
Therefore, 7/10 pounds of food was remaining in the bag at the end of the two months.

Question 7.
There were 14 \(\frac{1}{4}\) cups of apple juice in a container. Each day, Elise drank 1 \(\frac{1}{2}\) cups of apple juice. Today, there is \(\frac{3}{4}\) cup of apple juice left. Derek said that Elise drank apple juice on nine days. Do you agree with Derek? Use words and numbers to explain your answer.
Type below:
__________

Answer:
Derek is correct.

Explanation:
An apple juice the container had 14 1/2 =14.25
She drank per day 1 1/2= 1.5
The left part in the container 3/4= .75
14.25 cups – .75 cup = 13.5 cups
13.5 cups ÷ 1.5 cups per day= 9 days

Problem Solving Fraction Operations – Page No. 129

Read each problem and solve.

Question 1.
\(\frac{2}{3}\) of a pizza was left over. A group of friends divided the leftover pizza into pieces each equal to \(\frac{1}{18}\) of the original pizza. After each friend took one piece, \(\frac{1}{6}\) of the original pizza remained. How many friends were in the group?
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 23
______ friends

Answer:
9 friends

Explanation:
Let us say that there are x friends.
Each one gets 1/18 of the original pizza: but this in turn leaves 1/6 of the 2/3 leftover.
1x/18 = 2/3 – 1/6
x = 12 – 3 = 9

Question 2.
Sarah’s craft project uses pieces of yarn that are \(\frac{1}{8}\) yard long. She has a piece of yarn that is 3 yards long. How many \(\frac{1}{8}\) -yard pieces can she cut and still have 1 \(\frac{1}{4}\) yards left?
______ pieces

Answer:
14 pieces

Explanation:
Sarah’s craft project uses pieces of yarn that are \(\frac{1}{8}\) yard long. She has a piece of yarn that is 3 yards long.
If she left 1 \(\frac{1}{4}\) yards left, 3 – 1 \(\frac{1}{4}\) = 7/4
7/4 ÷ \(\frac{1}{8}\) = 14

Question 3.
Alex opens a 1-pint container of orange butter. He spreads \(\frac{1}{16}\) of the butter on his bread. Then he divides the rest of the butter into \(\frac{3}{4}\) -pint containers. How many \(\frac{3}{4}\) -pint containers is he able to fill?
______ \(\frac{□}{□}\) containers

Answer:
1\(\frac{1}{4}\) containers

Explanation:
Alex opens a 1-pint container of orange butter. He spreads \(\frac{1}{16}\) of the butter on his bread.
1 – 1/16 = 15/16
Then he divides the rest of the butter into \(\frac{3}{4}\) -pint containers.
(15/16) ÷ (3/4) = 5/4 = 1 1/4

Question 4.
Kaitlin buys \(\frac{9}{10}\) a pound of orange slices. She eats \(\frac{1}{3}\) of them and divides the rest equally into 3 bags. How much is in each bag?
______ lb

Answer:
17/90 lb

Explanation:
Kaitlin buys \(\frac{9}{10}\) a pound of orange slices. She eats \(\frac{1}{3}\) of them and divides the rest equally into 3 bags.
If she starts with 9/10 pounds and has eaten 1/3 of them, 9/10 – 1/3 = 17/30
This is the amount she has left. Let’s divide this value by 3 to see how many pounds are in one bag.
(17/30)/3 = 17/90
There are 17/90 pounds in one bag.

Question 5.
Explain how to draw a model that represents \(\left(1 \frac{1}{4}-\frac{1}{2}\right) \div \frac{1}{8}\).
Type below:
__________

Answer:
Divide 2 bars into 8 quarters.
Below that draw 1 1/4 or 5 quarters.
Remove 1/2 or 2 quarters
Divide each of the 3 quarters left into 2 eighths

Explanation:
\(\left(1 \frac{1}{4}-\frac{1}{2}\right) \div \frac{1}{8}\)
1 1/4 -1/2 = 5/4 – 1/2 = 3/4
3/4 ÷ 1/8 = 6

Lesson Check – Page No. 130

Question 1.
Eva wanted to fill bags with \(\frac{3}{4}\) pounds of trail mix. She started with 11 \(\frac{3}{8}\) pounds but ate \(\frac{1}{8}\) pound before she started filling the bags. How many bags could she fill?
______ bags

Answer:
15 bags

Explanation:
11 and 3/8-1/8=11 and 2/8=11 and 1/4
3/4 times x bags=11 and 1/4
convert 11 and 1/4 to improper fraction
11 and 1/4 = 11 + 1/4 = 44/4 + 1/4 = 45/4
3/4 times x bags=45/4
x bags = 45/4 × 4/3 = 15 bags
she could fill 15 bags

Question 2.
John has a roll containing 24 \(\frac{2}{3}\) feet of wrapping paper. He wants to divide it into 11 pieces. First, though, he must cut off \(\frac{5}{6}\) foot because it was torn. How long will each piece be?
______ \(\frac{□}{□}\) feet

Answer:
2\(\frac{4}{25}\) feet

Explanation:
John had a roll containing wrapping paper = 24 2/3 = 74/3
First, he must cut off 5/6 feet because it was torn.
He wants to divide it into 11 pieces.
74/3 – 5/6
Taking the L.C.M of 3 and 6 is 6
(148-5)/6 = 143/6 = 23.83 feet
He wants to divide it into 11 pieces. length of the each piece = 23.83/11 = 2.16 feet

Spiral Review

Question 3.
Alexis has 32 \(\frac{2}{5}\) ounces of beads. How many necklaces can she make if each uses 2 \(\frac{7}{10}\) ounces of beads?
______ necklaces

Answer:
12 necklaces

Explanation:
Alexis has 32 \(\frac{2}{5}\) ounces of beads.
If each uses 2 \(\frac{7}{10}\) ounces of beads, 32 \(\frac{2}{5}\) × 2 \(\frac{7}{10}\)
32 \(\frac{2}{5}\) = 162/5
2 \(\frac{7}{10}\) = 27/10
162/5 × 27/10 = 12 necklaces

Question 4.
Joseph has $32.40. He wants to buy several comic books that each cost $2.70. How many comic books can he buy?
______ comic books

Answer:
12 comic books

Explanation:
Joseph has $32.40. He wants to buy several comic books that each cost $2.70.
$32.40/$2.70 = 12 comic books

Question 5.
A rectangle is 2 \(\frac{4}{5}\) meters wide and 3 \(\frac{1}{2}\) meters long. What is its area?
______ \(\frac{□}{□}\) m2

Answer:
9\(\frac{4}{5}\) m2

Explanation:
2 \(\frac{4}{5}\) = 14/5
3 \(\frac{1}{2}\) = 7/2
14/5 × 7/2 = 9 4/5

Question 6.
A rectangle is 2.8 meters wide and 3.5 meters long. What is its area?
______ m2

Answer:
9.8 m2

Explanation:
A rectangle is 2.8 meters wide and 3.5 meters long.
2.8 × 3.5 = 9.8

Chapter 2 Review/Test – Page No. 131

Question 1.
Write the values in order from least to greatest.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 24
Type below:
__________

Answer:
0.45, 0.5, 5/8, 3/4

Explanation:
3/4 = 0.75
5/8 = 0.625
0.45, 0.5
0.45 < 0.5 < 0.625 < 0.75

Question 2.
For numbers 2a–2d, compare. Choose <, >, or =.
2a. 0.75 _____ \(\frac{3}{4}\)
2b. \(\frac{4}{5}\) _____ 0.325
2c. 1 \(\frac{3}{5}\) _____ 1.9
2d. 7.4 _____ 7 \(\frac{2}{5}\)

Answer:
2a. 0.75 = \(\frac{3}{4}\)
2b. \(\frac{4}{5}\) > 0.325
2c. 1 \(\frac{3}{5}\) < 1.9
2d. 7.4 = 7 \(\frac{2}{5}\)

Explanation:
2a. 3/4 = 0.75
0.75 = 0.75
2b. \(\frac{4}{5}\) = 0.8
0.8 > 0.325
2c. 1 \(\frac{3}{5}\) = 8/5 = 1.6
1.6 < 1.9
2d. 7 \(\frac{2}{5}\) = 37/5 = 7.4
7.4 = 7.4

Question 3.
The table lists the heights of 4 trees.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 25
For numbers 3a–3d, select True or False for each statement.
3a. The oak tree is the shortest. True False
3b. The birch tree is the tallest. True False
3c. Two of the trees are the same height. True False
3d. The sycamore tree is taller than the maple tree. True False
Type below:
__________

Answer:
3a. The oak tree is the shortest. True
3b. The birch tree is the tallest. False
3c. Two of the trees are the same height. False
3d. The sycamore tree is taller than the maple tree. False

Explanation:
Sycamore = 15 2/3 = 47/3 = 15.666
Oak = 14 3/4 = 59/4 = 14.75
Maple = 15 3/4 = 63/4 = 15.75
Birch = 15.72

Page No. 132

Question 4.
For numbers 4a–4d, choose Yes or No to indicate whether the statement is correct.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 26
4a. Point A represents 1.0. Yes No
4b. Point B represents \(\frac{3}{10}\). Yes No
4c. Point C represents 6.5. Yes No
4d. Point D represents \(\frac{4}{5}\). Yes No
Type below:
__________

Answer:
4a. Point A represents 1.0. Yes
4b. Point B represents \(\frac{3}{10}\). Yes
4c. Point C represents 6.5. No
4d. Point D represents \(\frac{4}{5}\). Yes

Question 5.
Select the values that are equivalent to one twenty-fifth. Mark all that apply.
Options:
a. 125
b. 25
c. 0.04
d. 0.025

Answer:
c. 0.04

Explanation:
one twenty-fifth = 1/25 = 0.04

Question 6.
The table shows Lily’s homework assignment. Lily’s teacher instructed the class to simplify each expression by dividing the numerator and denominator by the GCF. Complete the table by simplifying each expression and then finding the product.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 27
Type below:
___________

Answer:
a. Simplified Expression: 1/10
Product: 0.1
b. Simplified Expression: 1/2
Product: 0.5
c. Simplified Expression: 15/56
Product: 0.267
d. Simplified Expression: 1/12
Product: 0.083

Explanation:
a. 2/5 × 1/4 = 2/20
Simplify using the GCF.
The GCF of 2 and 20 is 2.
Divide the numerator and the denominator by 2.
So, 1/10 is the answer.
Product: 0.1
b. 4/5 × 5/8 = 1/2
Product: 0.5
c. 3/7 × 5/8 = 15/ 56
Product: 0.267
d. 4/9 × 3/16 = 1/12
Product: 0.083

Page No. 133

Question 7.
Two-fifths of the fish in Gary’s fish tank are guppies. One-fourth of the guppies are red. What fraction of the fish in Gary’s tank are red guppies? What fraction of the fish in Gary’s tank are not red guppies? Show your work.
Type below:
___________

Answer:
1/10 of the fish are red guppies.
and 9/10 of the fish are not red guppies.

Explanation:
two-fifths of the fish in Gary’s fish tank are guppies.
One-fourth of the guppies are red.
Let the total number of fish in Gary’s fish tank be x.
It is given that two-fifths of the fish in Gary’s fish tank are guppies.
So, the number of guppies in Gary’s fish tank is 2/5 × x
Given that One-fourth of the guppies are red.
number of red guppies = 1/4 × 2x/5 = x/10
So, 1/10 of the fish are red guppies.
1 – 1/10 = 9/10 of the fish are not red guppies.

Question 8.
One-third of the students at Finley High School play sports. Two-fifths of the students who play sports are girls. What fraction of all students are girls who play sports? Use numbers and words to explain your answer.
Type below:
___________

Answer:
One-third of the students at Finley High School play sports. Two-fifths of the students who play sports are girls.
1/3 × 2/5 = 2/15 of the girls in the school play sports.

Question 9.
Draw a model to find the quotient.
\(\frac{3}{4}\) ÷ 2 =
\(\frac{3}{4}\) ÷ \(\frac{3}{8}\) =
How are your models alike? How are they different?
Type below:
___________

Answer:
grade 6 chapter 2 image 5

Explanation:
\(\frac{3}{4}\) ÷ 2 = 3/4 × 1/2 = 3/8
\(\frac{3}{4}\) ÷ \(\frac{3}{8}\) = 3/4 × 8/3 = 2
Both models are multiplying with the 3/4.
The number line model shows how many groups of 3/8 are in 3/4.

Question 10.
Explain how to use a model to find the quotient.
2 \(\frac{1}{2}\) ÷ 2 =
Type below:
___________

Answer:
5/4

Explanation:
2 1/2 = 5/2
5/2 groups of 2
5/2 ÷ 2 = 5/2 × 1/2 = 5/4

Page No. 134

Divide. Show your work.

Question 11.
\(\frac{7}{8}\) ÷ \(\frac{3}{5}\) =
_______ \(\frac{□}{□}\)

Answer:
1 \(\frac{11}{24}\)

Explanation:
\(\frac{7}{8}\) ÷ \(\frac{3}{5}\)
\(\frac{7}{8}\) × \(\frac{5}{3}\) = 35/24 = 1 \(\frac{11}{24}\)

Question 12.
\(2 \frac{1}{10} \div 1 \frac{1}{5}=\) =
_______ \(\frac{□}{□}\)

Answer:
1 \(\frac{3}{4}\)

Explanation:
2 \(\frac{1}{10}\) = 21/10
1 \(\frac{1}{5}\) = 6/5
(21/10) ÷ (6/5) = 7/4 or 1 3/4

Question 13.
Sophie has \(\frac{3}{4}\) quart of lemonade. If she divides the lemonade into glasses that hold \(\frac{1}{16}\) quart, how many glasses can Sophie fill? Show your work
_______ glasses

Answer:
12 glasses

Explanation:
Let x be the number of glasses
1/16x = 3/4
x = 3/4 × 16 = 3 × 4 = 12 glasses

Question 14.
Ink cartridges weigh \(\frac{1}{8}\) pound. The total weight of the cartridges in a box is 4 \(\frac{1}{2}\) pounds. How many cartridges does the box contain? Show your work and explain why you chose the operation you did.
_______ cartridges

Answer:
36 cartridges

Explanation:
Weight of ink cartridges = 1/8 pounds
Total weight of the cartridges in a box = 4 1/2 = 9/2 pounds
So, the number of cartridges that box contains is given by
9/2 ÷ 1/8 = 36
Hence, there are 36 cartridges that the box contains.

Question 15.
Beth had 1 yard of ribbon. She used \(\frac{1}{3}\) yard for a project. She wants to divide the rest of the ribbon into pieces \(\frac{1}{6}\) yard long. How many \(\frac{1}{6}\) yard pieces of ribbon can she make? Explain your solution.
_______ pieces

Answer:
4 pieces

Explanation:
Beth had 1 yard of ribbon. She used \(\frac{1}{3}\) yard for a project.
1 – \(\frac{1}{3}\) = 2/3 yard left
She wants to divide the rest of the ribbon into pieces \(\frac{1}{6}\) yard long.
2/3 ÷ 1/6 = 4

Page No. 135

Question 16.
Complete the table by finding the products. Then answer the questions in Part A and Part B.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 28
Part A
Explain how each pair of division and multiplication problems are the same, and how they are different.
Type below:
___________

Answer:
1/5 ÷ 3/4 = 4/15; 1/5 × 4/3 = 4/15
2/13 ÷ 1/5 = 10/13; 2/13 × 5/1 = 10/13
4/5 ÷ 3/5 = 4/3; 4/5 × 5/3 = 4/3
the product of the each pair of division and multiplication problems is the same.
They are different from the operation performed.

Question 16.
Part B
Explain how to use the pattern in the table to rewrite a division problem involving fractions as a multiplication problem.
Type below:
___________

Answer:
First, since it’s the division you have to change the second fraction which is called the reciprocal. That means the second fraction has to be flipped before you can multiply the fractions.

Page No. 136

Question 17.
Margie hiked a 17 \(\frac{7}{8}\) mile trail. She stopped every 3 \(\frac{2}{5}\) miles to take a picture. Martin and Tina estimated how many times Margie stopped.
Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals 29
Who made the better estimate? Use numbers and words to explain your answer.
Type below:
___________

Answer:
Margie hiked a 17 7/8 mile trail.
Distance hiked by Margie = 17 7/8 = 143/8 mile.
She stopped every 3 2/5 miles to take a picture = 17/5 mile
Number of pictures = (143/8) ÷ (17/5) = 715/136 = 5.28
So she can take a maximum of 6 pictures and a minimum of 5 pictures.
B is the correct answer.

Question 18.
Brad and Wes are building a tree house. They cut a 12 \(\frac{1}{2}\) foot piece of wood into 5 of the same length pieces. How long is each piece of wood? Show your work.
_______ \(\frac{□}{□}\) foot

Answer:
2 \(\frac{1}{2}\) foot

Explanation:
Brad and Wes cut a 12 1/2 foot piece of wood into 5 of the same length.
Let the length of 1 piece be x
So, Length of 5 pieces = 5x
The total length of wood = 25/2
5x = 25/2
x = 5/2 = 2 1/2

Free Grade 6 HMH Go Math Answer Key PDF Download

You can get Go Math 6th Grade Answer Key PDF for free from our page. Access all the questions and explanations for free on our website. Get All the questions, answers along with explanations. Download free pdf of Go Math Grade 6 Answer Key.

Go Math Grade 6 Answer Key Chapter 2 Fractions and Decimals Read More »

go-math-grade-6-answer-key-chapter-4-model-ratios

Go Math Grade 6 Answer Key Chapter 4 Model Ratios

Check out Go Math Grade 6 Answer Key Chapter 4 Model Ratios here. The best way of learning is in your hands now. Simple tricks and techniques on our Go Math Grade 6 Chapter 4 Model Ratios Answer Key will help the students to love the maths. The easy way of solving can quickly habituate to students with Go Math Grade 6 Answer Key. Freely Download Go Math Grade 6 Chapter 4 Model Ratios Solution Key PDF. Every concept is deeply explained in an understandable way. So, the students can refer to the HMH Go math Grade 6 answer key and get the best results.

Go Math Grade 6 Chapter 4 Model Ratios Answer Key

Are you searching for the easy way of maths learning? Then, you must follow Go Math Grade 6 Chapter 4 Model Ratios Answer Key. All questions are explained with step by step explanation and also with diagrams. So, students can learn visual learning in an easy manner. If you want to learn maths seriously, then Go Math Grade 6 Answer Key is the only solution for you.

Lesson 1: Investigate • Model Ratios

Lesson 2: Ratios and Rates

Lesson 3: Equivalent Ratios and Multiplication Tables

Lesson 4: Problem Solving • Use Tables to Compare Ratios

Lesson 5: Algebra • Use Equivalent Ratios

Mid-Chapter Checkpoint

Lesson 6: Find Unit Rates

Lesson 7: Algebra • Use Unit Rates

Lesson 8: Algebra • Equivalent Ratios and Graphs

Chapter 4 Review/Test

Share and Show – Page No. 213

Write the ratio of yellow counters to red counters.

Question 1.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 1
Type below:
___________

Answer:
1: 2

Explanation:
There is one yellow counter and two red counters.
So, the ratio is 1:2

Question 2.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 2
Type below:
___________

Answer:
5: 3

Explanation:
There are 5 yellow counters and 3 red counters.
So, the ratio is 5:3

Draw a model of the ratio.

Question 3.
3 : 2
Type below:
___________

Answer:
Grade 6 Chapter 4 image 1

Explanation:
As the ratio is 3:2, we can draw three yellow counters and 2 red counters.

Question 4.
1 : 5
Type below:
___________

Answer:
Grade 6 Chapter 4 image 2

Explanation:
As the ratio is 1:5, we can draw 1 yellow counter and 5 red counters.

Use the ratio to complete the table.

Question 5.
Wen is arranging flowers in vases. For every 1 rose she uses, she uses 6 tulips. Complete the table to show the ratio of roses to tulips.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 3
Type below:
___________

Answer:
Grade 6 Chapter 4 image 3

Explanation:
There is 1 box for every 6 Tulips.
The ratio is 1 : 6.
Each time the number of boxes increases by 1, the number of Tulips increases by 6
So, for 2 boxes, 6 + 6 = 12 Tulips
For 3 boxes, 12 + 6 = 18 Tulips
For 4 boxes, 18 + 6 = 24 Tulips

Lesson 1 Ratios Answer Key Question 6.
On the sixth-grade field trip, there are 8 students for every 1 adult. Complete the table to show the ratio of students to adults.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 4
Type below:
___________

Answer:
Grade 6 Chapter 4 image 4

Explanation:
There is 1 adult out of 8 Students.
The ratio is 8:1.
Each time the number of students increases, the number of adults becomes double.
So, for 8 + 8 = 16 students, 2 Adults available
For 16 + 8 = 24 students, 2 + 1 = 3 Adults available
For 24 + 8 = 32 students, 3 + 1 = 4 Adults available

Question 7.
Zena adds 4 cups of flour for every 3 cups of sugar in her recipe. Draw a model that compares cups of flour to cups of sugar.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 5

Explanation:
Zena adds 4 cups of flour for every 3 cups of sugar in her recipe.
For every 3 cups of sugar, she adds 4 cups of flour.
For 6 cups of sugar, she adds 8 cups of flour
For 9 cups of sugar, she adds 12 cups of flour
For 12 cups of sugar, she adds 16 cups of flour

Draw Conclusions – Page No. 214

The reading skill of drawing conclusions can help you analyze and make sense of information.

Hikers take trail mix as a snack on long hikes because it is tasty, nutritious, and easy to carry. There are many different recipes for trail mix, but it is usually made from different combinations of dried fruit, raisins, seeds, and nuts. Tanner and his dad make trail mix that has 1 cup of raisins for every 3 cups of sunflower seeds.

Question 8.
Model Mathematics Explain how you could model the ratio that compares cups of raisins to cups of sunflower seeds when Tanner uses 2 cups of raisins.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 6

Explanation:
Hikers take trail mix as a snack on long hikes because it is tasty, nutritious, and easy to carry. There are many different recipes for trail mix, but it is usually made from different combinations of dried fruit, raisins, seeds, and nuts. Tanner and his dad make trail mix that has 1 cup of raisins for every 3 cups of sunflower seeds.
For 2 cups of raisins, he needs 3 + 3 = 6 cups of sunflower seeds

The table shows the ratio of cups of raisins to cups of sunflower seeds for different amounts of trail mix. Model each ratio as you complete the table.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 5
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 6

Question 9.
Describe the pattern you see in the table.
Type below:
___________

Answer:
Multiply Raisins by 3 to get a number of Sunflower Seeds.

Question 10.
Draw Conclusions What conclusion can Tanner draw from this pattern?
Type below:
___________

Answer:
He needs 3 times as many seeds as raisins

Lesson 1 Ratios Answer Key 6th Grade Question 11.
What is the ratio of cups of sunflower seeds to cups of trail mix when Tanner uses 4 cups of raisins?
Type below:
___________

Answer:
4:12

Explanation:
If Tanner uses 4 cups of raisins, he needs 12 cups of sunflower seeds.

Model Ratios – Page No. 215

Write the ratio of gray counters to white counters.

Question 1.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 7
Type below:
___________

Answer:
3:4

Explanation:
There are 3 gray counters and 4 white counters.
So, the ratio is 3:4

Question 2.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 8
Type below:
___________

Answer:
4:1

Explanation:
There are 4 gray counter and 1 white counter.
So, the ratio is 4:1

Question 3.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 9
Type below:
___________

Answer:
2:3

Explanation:
There are 2 gray counter and 3 white counters.
So, the ratio is 2:3

Draw a model of the ratio.

Question 4.
5 : 1
Type below:
___________

Answer:
Grade 6 Chapter 4 image 7

Explanation:
As the ratio is 5:1, we can draw 5 yellow counters and 1 red counter.

Question 5.
6 : 3
Type below:
___________

Answer:
Grade 6 Chapter 4 image 8

Explanation:
As the ratio is 6:3, we can draw 6 yellow counters and 3 red counters.

Use the ratio to complete the table.

Question 6.
Marc is assembling gift bags. For every 2 pencils he places in the bag, he uses 3 stickers. Complete the table to show the ratio of pencils to stickers.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 10
Type below:
___________

Answer:
Grade 6 Chapter 4 image 9

Explanation:
Marc is assembling gift bags. For every 2 pencils he places in the bag, he uses 3 stickers.
For 4 pencils, he uses 3 + 3 = 6 stickers
For 6 pencils, he uses 6 + 3 = 9 stickers
For 8 pencils, he uses 9 + 3 = 12 stickers

Question 7.
Singh is making a bracelet. She uses 5 blue beads for every 1 silver bead. Complete the table to show the ratio of blue beads to silver beads
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 11
Type below:
___________

Answer:
Grade 6 Chapter 4 image 10

Explanation:
Singh is making a bracelet. She uses 5 blue beads for every 1 silver bead.
For 2 silver beads, she uses 5 + 5 = 10 blue beads.
For 3 silver beads, she uses 10 + 5 = 15 blue beads.
For 4 silver beads, she uses 15 + 5 = 20 blue beads.

Problem Solving

Question 8.
There are 4 quarts in 1 gallon. How many quarts are in 3 gallons?
______ quarts

Answer:
12 quarts

Explanation:
There are 4 quarts in 1 gallon. If there are 3 gallons, he uses 3 × 4 = 12 quarts

Chapter 1 Ratios and Rates Answer Key Question 9.
Martin mixes 1 cup of lemonade with 4 cups of cranberry juice to make his favorite drink. How much cranberry juice does he need if he uses 5 cups of lemonade?
______ cups

Answer:
20 cups

Explanation:
Martin mixes 1 cup of lemonade with 4 cups of cranberry juice to make his favorite drink. If he uses 5 cups of lemonade, 5 × 4 = 20 cups

Question 10.
Suppose there was 1 centerpiece for every 5 tables. Use counters to show the ratio of centerpieces to tables. Then make a table to find the number of tables if there are 3 centerpieces.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 7

Grade 6 Chapter 4 image 11

Explanation:
Suppose there was 1 centerpiece for every 5 tables.
If there are 3 centerpieces, 5 × 3 = 15 tables

Lesson Check – Page No. 216

Question 1.
Francine is making a necklace that has 1 blue bead for every 6 white beads. How many white beads will she use if she uses 11 blue beads?
______ white beads

Answer:
66 white beads

Explanation:
Francine is making a necklace that has 1 blue bead for every 6 white beads.
11 × 6 = 66 white beads

Question 2.
A basketball league assigns 8 players to each team. How many players can sign up for the league if there are 24 teams?
______ players

Answer:
192 players

Explanation:
A basketball league assigns 8 players to each team.
If there are 24 teams, 24 × 8 = 192 players to each team

Spiral Review

Question 3.
Louis has 45 pencils and 75 pens to divide into gift bags at the fair. He does not want to mix the pens and pencils. He wants to place an equal amount in each bag. What is the greatest number of pens or pencils he can place in each bag?
______

Answer:
Louis can form at most 15 bags, each of which will contain 3 pencils and 5 pens.

Explanation:
Louis has 45 pencils and 75 pens to divide into gift bags at the fair. He does not want to mix the pens and pencils. He wants to place an equal amount in each bag.
Factor both these numbers:
45 = 3·3·5;
75 = 3·5·5.
The greatest common factor (write all common factors and multiply them) is 3·5=15. Then:
45=15·3;
75=15·5.
Louis can form at most 15 bags, each of which will contain 3 pencils and 5 pens.

Ratio Quiz Grade 6 Pdf Answer Key Question 4.
Of the 24 students in Greg’s class, \(\frac{3}{8}\) ride the bus to school. How many students ride the bus?
______ students

Answer:
9 students

Explanation:
Of the 24 students in Greg’s class, \(\frac{3}{8}\) ride the bus to school.
3/8 x 24 = 9

Question 5.
Elisa made 0.44 of the free throws she attempted. What is that amount written as a fraction in simplest form?
\(\frac{□}{□}\)

Answer:
\(\frac{11}{25}\)

Explanation:
Elisa made 0.44 of the free throws she attempted.
0.44 = 44/100
44/100 = 22/50 = 11/25
11/25

Question 6.
On a coordinate plane, the vertices of a rectangle are (–1, 1), (3, 1), (–1, –4), and (3, –4). What is the perimeter of the rectangle?
______ units

Answer:
18 units

Explanation:
On a coordinate plane, the vertices of a rectangle are (–1, 1), (3, 1), (–1, –4), and (3, –4).
|-1| = 1
The distance from (–1, 1), (3, 1) is 1 + 0 + 0 + 3 = 4
|-4| = 4
The distance from (3, 1), (3, –4) is 1 + 0 + 0 + 4 = 5
perimeter of the rectangle = 4 + 5 + 5 + 4 = 18

Share and Show – Page No. 219

Question 1.
Write the ratio of the number of red bars to blue stars.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 12
\(\frac{□}{□}\)

Answer:
\(\frac{8}{3}\)

Explanation:
There are 8 stars and 3 red boxes.
So, the ratio is 8:3

Write the ratio in two different ways.

Question 2.
8 to 16
Type below:
___________

Answer:
\(\frac{8}{16}\)
8:16

Explanation:
8 to 16 as a fraction 8/16
8 to 16 with a colon 8:16

Question 3.
\(\frac{4}{24}\)
Type below:
___________

Answer:
4 to 24
4:24

Explanation:
\(\frac{4}{24}\) using words 4 to 24
\(\frac{4}{24}\) with a colon 4:24

Question 4.
1 : 3
Type below:
___________

Answer:
1 to 3
\(\frac{1}{3}\)

Explanation:
1 : 3 using words 1 to 3
1 : 3 as a fraction 1/3

Question 5.
7 to 9
Type below:
___________

Answer:
\(\frac{7}{9}\)
7:9

Explanation:
7 to 9 as a fraction of 7/9
7 to 9 with a colon 7:9

Question 6.
Marilyn saves $15 per week. Complete the table to find the rate that gives the amount saved in 4 weeks. Write the rate in three different ways.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 13
Type below:
___________

Answer:
Grade 6 Chapter 4 image 15

Explanation:
Marilyn saves $15 per week.
for 4 weeks, $15 × 4 = $60

On Your Own

Write the ratio in two different ways.

Question 7.
\(\frac{16}{40}\)
Type below:
___________

Answer:
16 to 40
16:40

Explanation:
\(\frac{16}{40}\) using words 16 to 40
\(\frac{16}{40}\) with a colon 16:40

Question 8.
8 : 12
Type below:
___________

Answer:
8 to 12
\(\frac{8}{12}\)

Explanation:
8 : 12 using words 8 to 12
8 : 12 as a fraction \(\frac{8}{12}\)

Ratio Questions and Answers Grade 6 Question 9.
4 to 11
Type below:
___________

Answer:
\(\frac{4}{11}\)
4:11

Explanation:
4 to 11 as a fraction \(\frac{4}{11}\)
4 to 11 with a colon 4:11

Question 10.
2 : 13
Type below:
___________

Answer:
2 to 13
\(\frac{2}{13}\)

Explanation:
2 : 13 using words 2 to 13
2 : 13 as a fraction \(\frac{2}{13}\)

Question 11.
There are 24 baseball cards in 4 packs. Complete the table to find the rate that gives the number of cards in 2 packs. Write this rate in three different ways.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 14
Type below:
___________

Answer:
Grade 6 Chapter 4 image 16

Explanation:
There are 24 baseball cards in 4 packs.
For 2 packs, (2 × 24)/4 = 12
For 1 pack, (1× 24)/4 = 6

Question 12.
Make Connections Explain how the statement “There is \(\frac{3}{4}\) cup per serving” represents a rate.
Type below:
___________

Answer:
There is a 3/4 cup of whatever in one serving. If that serving amount changed to 2, then the 3/4 would be multiplied by 2. If there is half a serving, then it would be divided by 2. There is a constant change and not one that is always changing.

Problem Solving + Applications – Page No. 220

Use the diagram of a birdhouse for 13–15.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 15

Question 13.
Write the ratio of AB to BC in three different ways.
Type below:
___________

Answer:
28 : 12, 28 to 12, \(\frac{2}{13}\)

Explanation:
AB = 28 in
BC = 12 in
AB : BC = 28 : 12, 28 to 12, \(\frac{2}{13}\)

Question 14.
Write the ratio of the shortest side length of triangle ABC to the perimeter of the triangle in three different ways.
Type below:
___________

Answer:
12 : 64, 12 to 64, \(\frac{12}{64}\)

Explanation:
The shortest side length of triangle ABC = 12 in
the perimeter of the triangle 12 + 28 + 24 = 64
12 : 64, 12 to 64, \(\frac{12}{64}\)

Question 15.
Represent a Problem Write the ratio of the perimeter of triangle ABC to the longest side length of the triangle in three different ways.
Type below:
___________

Answer:
64 : 28, 64 to 28, \(\frac{64}{28}\)

Explanation:
the ratio of the perimeter of triangle ABC = 12 + 28 + 24 = 64
The longest side length of the triangle = 28 in
64 : 28, 64 to 28, \(\frac{64}{28}\)

Question 16.
Leandra places 6 photos on each page in a photo album. Find the rate that gives the number of photos on 2 pages. Write the rate in three different ways.
Type below:
___________

Answer:
6 : 12, 6 to 12, \(\frac{6}{12}\)

Explanation:
Leandra places 6 photos on each page in a photo album.
For 2 pages, 6 × 2 = 12 in
6 : 12, 6 to 12, \(\frac{6}{12}\)

Question 17.
What’s the Question? The ratio of total students in Ms. Murray’s class to students in the class who have an older brother is 3 to 1. The answer is 1:2. What is the question?
Type below:
___________

Answer:
What is the ratio of students in the class who don’t have an older brother to students in the class with an older brother.

Question 18.
What do all unit rates have in common?
Type below:
___________

Answer:
A rate is a ratio that is used to compare different kinds of quantities. A unit rate describes how many units of the first type of quantity corresponds to one unit of the second type of quantity.

Question 19.
Julia has 2 green reusable shopping bags and 5 purple reusable shopping bags. Select the ratios that compare the number of purple reusable shopping bags to the total number of reusable shopping bags. Mark all that apply.

  • 5 to 7
  • 5 : 7
  • 5 : 2
  • \(\frac{2}{5}\)
  • 2 to 7
  • \(\frac{5}{7}\)

Type below:
___________

Answer:
5 to 7, 5 : 7, \(\frac{5}{7}\)

Explanation:
the number of purple reusable shopping bags = 5
the total number of reusable shopping bags = 5 + 2 = 7
5 to 7, 5 : 7, \(\frac{5}{7}\)

Ratios and Rates – Page No. 221

Write the ratio in two different ways.

Question 1.
\(\frac{4}{5}\)
Type below:
___________

Answer:
4 to 5
4 : 5

Explanation:
\(\frac{4}{5}\) using words 4 to 5
\(\frac{4}{5}\) with a colon 4 : 5

Question 2.
16 to 3
Type below:
___________

Answer:
\(\frac{16}{3}\)
16 : 3

Explanation:
16 to 3 as a fraction \(\frac{16}{3}\)
16 to 3 with a colon 16 : 3

Question 3.
9 : 13
Type below:
___________

Answer:
9 to 13
\(\frac{9}{13}\)

Explanation:
9 : 13 using words 9 to 13
9 : 13 as a fraction \(\frac{9}{13}\)

Question 4.
\(\frac{15}{8}\)
Type below:
___________

Answer:
15 to 8
15 : 8

Explanation:
\(\frac{15}{8}\) using words 15 to 8
\(\frac{15}{8}\) with a colon 15 : 8

Ratio Tables Worksheets with Answers Pdf Question 5.
There are 20 light bulbs in 5 packages. Complete the table to find the rate that gives the number of light bulbs in 3 packages. Write this rate in three different ways.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 16
Type below:
___________

Answer:
Grade 6 Chapter 4 image 12

Explanation:
There are 20 light bulbs in 5 packages.
For 1 package, 4 light bulbs are available
For 2 packages, 8 light bulbs are available
For 3 packages, 12 light bulbs are available
For 4 packages, 16 light bulbs are available

Problem Solving

Question 6.
Gemma spends 4 hours each week playing soccer and 3 hours each week practicing her clarinet. Write the ratio of hours spent practicing clarinet to hours spent playing soccer in three different ways.
Type below:
___________

Answer:
\(\frac{3}{4}\), 3 : 4, 3 to 4

Explanation:
Gemma spends 4 hours each week playing soccer and 3 hours each week practicing her clarinet.
3/4, 3 : 4, 3 to 4

Question 7.
Randall bought 2 game controllers at Electronics Plus for $36. What is the unit rate for a game controller at Electronics Plus?
Type below:
___________

Answer:
\(\frac{$18}{1}\)

Explanation:
Randall bought 2 game controllers at Electronics Plus for $36. $36/2 = $18/1 is the unit rate for a game controller at Electronics Plus

Question 8.
Explain how to determine if a given rate is also a unit rate.
Type below:
___________

Answer:
when rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates. If you have a multiple-unit rate such as 120 students for every 3 buses, and want to find the single-unit rate, write a ratio equal to the multiple-unit rate with 1 as the second term

Lesson Check – Page No. 222

Question 1.
At the grocery store, Luis bought 10 bananas and 4 apples. What are three different ways to write the ratio of apples to bananas?
Type below:
___________

Answer:
4 : 10, 4 to 10, \(\frac{4}{10}\)

Explanation:
At the grocery store, Luis bought 10 bananas and 4 apples. 4/10, 4 : 10, 4 to 10

Question 2.
Rita checked out 7 books from the library. She had 2 non-fiction books. The rest were fiction. What are three different ways to write the ratio of non-fiction to fiction?
Type below:
___________

Answer:
2 to 5, 2 : 5, \(\frac{2}{5}\)

Explanation:
Rita checked out 7 books from the library. She had 2 non-fiction books. The rest were fiction.
fiction = 5
2 to 5, 2 : 5, \(\frac{2}{5}\)

Spiral Review

Question 3.
McKenzie bought 1.2 pounds of coffee for $11.82. What was the cost per pound?
$ ______

Answer:
$9.85

Explanation:
McKenzie bought 1.2 pounds of coffee for $11.82. $11.82/1.2 = $9.85

Question 4.
Pedro has a bag of flour that weighs \(\frac{9}{10}\) pound. He uses \(\frac{2}{3}\) of the bag to make gravy. How many pounds of flour does Pedro use to make gravy?
\(\frac{□}{□}\) pound

Answer:
\(\frac{3}{5}\) pound

Explanation:
Pedro has a bag of flour that weighs \(\frac{9}{10}\) pound. He uses \(\frac{2}{3}\) of the bag to make gravy.
\(\frac{9}{10}\) × \(\frac{2}{3}\) = 3/5

6th Grade Equivalent Ratios Answers Question 5.
Gina draws a map of her town on a coordinate plane. The point that represents the town’s civic center is 1 unit to the right of the origin and 4 units above it. What are the coordinates of the point representing the civic center?
Type below:
___________

Answer:
(-1, 4)

Explanation:
Gina draws a map of her town on a coordinate plane. The point that represents the town’s civic center is 1 unit to the right of the origin and 4 units above it.
(-1, 4)

Question 6.
Stefan draws these shapes. What is the ratio of triangles to stars?
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 17
Type below:
___________

Answer:
2 to 5

Explanation:
There are 2 triangles and 5 stars. So, the ratio is 2 : 5

Share and Show – Page No. 225

Write two equivalent ratios.

Question 1.
Use a multiplication table to write two ratios that are equivalent to \(\frac{4}{7}\).
Type below:
___________

Answer:
\(\frac{4}{7}\) = \(\frac{8}{14}\), \(\frac{12}{21}\)

Explanation:
The original ratio is 4/7. Shade the row for 4 and the row for 7 on the multiplication table.
The column for 2 shows there are 2 ∙ 4, when there are 2 ∙ 7. So, 4/7 equal to 8/14
The column for 3 shows there are 3 ∙ 4, when there are 3 ∙ 7. So, 4/7 equal to 12/21

Question 2.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 18
Type below:
___________

Answer:
Grade 6 Chapter 4 image 18

Explanation:
The original ratio is 3/7. Shade the row for 3 and the row for 7 on the multiplication table.
The column for 2 shows there are 2 ∙ 3, when there are 2 ∙ 7. So, 3/7 equal to 6/14
The column for 3 shows there are 3 ∙ 3, when there are 3 ∙ 7. So, 3/7 equal to 9/21

Question 3.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 19
Type below:
___________

Answer:
Grade 6 Chapter 4 image 19

Explanation:
The original ratio is 5/2. Shade the row for 5 and the row for 2 on the multiplication table.
The column for 2 shows there are 2 ∙ 5 when there are 2 ∙ 2. So, 5/2 equal to 10/4
The column for 3 shows there are 3 ∙ 5 when there are 3 ∙ 2. So, 5/2 equal to 15/6

Question 4.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 20
Type below:
___________

Answer:
Grade 6 Chapter 4 image 20

Explanation:
The original ratio is 2/10. Shade the row for 2 and the row for 10 on the multiplication table.
The column for 1 shows there are 1 ∙ 2 when there are 5 ∙ 2. So, 2/10 equal to 1/5
The column for 3 shows there are 1 ∙ 3 when there are 5 ∙ 3. So, 2/10 equal to 3/15

Question 5.
\(\frac{4}{5}\)
Type below:
___________

Answer:
\(\frac{4}{5}\) = \(\frac{8}{10}\), \(\frac{12}{15}\)

Explanation:
The original ratio is 4/5. Shade the row for 4 and the row for 5 on the multiplication table.
The column for 2 shows there are 2 ∙ 4, when there are 2 ∙ 5. So, 4/5 equal to 8/10
The column for 3 shows there are 3 ∙ 4, when there are 3 ∙ 5. So, 4/5 equal to 12/15

Question 6.
\(\frac{12}{30}\)
Type below:
___________

Answer:
\(\frac{12}{30}\) = \(\frac{24}{60}\), \(\frac{36}{90}\)

Explanation:
The original ratio is 12/30. Shade the row for 12 and the row for 30 on the multiplication table.
The column for 2 shows there are 2 ∙ 12 when there are 2 ∙ 30. So, 12/30 equal to 24/60
The column for 3 shows there are 3 ∙ 12 when there are 3 ∙ 30. So, 12/30 equal to 36/90

Question 7.
\(\frac{2}{9}\)
Type below:
___________

Answer:
\(\frac{2}{9}\) = \(\frac{4}{18}\), \(\frac{6}{27}\)

Explanation:
The original ratio is 2/9. Shade the row for 2 and the row for 9 on the multiplication table.
The column for 2 shows there are 2 ∙ 2, when there are 2 ∙ 9. So, 2/9 equal to 4/18
The column for 3 shows there are 3 ∙ 2, when there are 3 ∙ 9. So, 2/9 equal to 6/27

On Your Own

Write two equivalent ratios.

Question 8.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 21
Type below:
___________

Answer:
Grade 6 Chapter 4 image 21

Explanation:
The original ratio is 9/8. Shade the row for 9 and the row for 8 on the multiplication table.
The column for 2 shows there are 2 ∙ 9 when there are 2 ∙ 8. So, 9/8 equal to 18/16
The column for 3 shows there are 3 ∙ 9 when there are 3 ∙ 8. So, 9/8 equal to 27/24

Question 9.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 22
Type below:
___________

Answer:
Grade 6 Chapter 4 image 22

Explanation:
The original ratio is 5/4. Shade the row for 5 and the row for 4 on the multiplication table.
The column for 2 shows there are 2 ∙ 5 when there are 2 ∙ 4. So, 5/4 equal to 10/8
The column for 3 shows there are 3 ∙ 5 when there are 3 ∙ 4. So, 5/4 equal to 15/20

Question 10.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 23
Type below:
___________

Answer:
Grade 6 Chapter 4 image 23

Explanation:
The original ratio is 6/9. Shade the row for 6 and the row for 9 on the multiplication table.
The column for 1 shows there are 1 ∙ 3 when there are 1. 4.5. So, 5/4 equal to 3/4.5
The column for 3 shows there are 3 ∙ 3 when there are 3 ∙ 4.5. So, 5/4 equal to 9/13.5

Question 11.
\(\frac{8}{7}\)
Type below:
___________

Answer:
\(\frac{8}{7}\) = \(\frac{16}{14}\), \(\frac{24}{21}\)

Explanation:
The original ratio is 8/7. Shade the row for 8 and the row for 7 on the multiplication table.
The column for 2 shows there are 2 ∙ 8 when there are 2 ∙ 7. So, 8/7 equal to 16/14
The column for 3 shows there are 3 ∙ 8 when there are 3 ∙ 7. So, 8/7 equal to 24/21

Question 12.
\(\frac{2}{6}\)
Type below:
___________

Answer:
\(\frac{2}{6}\) = \(\frac{4}{12}\), \(\frac{6}{18}\)

Explanation:
The original ratio is 2/6. Shade the row for 2 and the row for 6 on the multiplication table.
The column for 2 shows there are 2 ∙ 2, when there are 2 ∙ 6. So, 2/6 equal to 4/12
The column for 3 shows there are 3 ∙ 2, when there are 3 ∙ 6. So, 2/6 equal to 6/18

Question 13.
\(\frac{4}{11}\)
Type below:
___________

Answer:
\(\frac{4}{11}\) = \(\frac{8}{22}\), \(\frac{12}{33}\)

Explanation:
The original ratio is 4/11. Shade the row for 4 and the row for 11 on the multiplication table.
The column for 2 shows there are 2 ∙ 4, when there are 2 ∙ 11. So, 4/11 equal to 8/22
The column for 3 shows there are 3 ∙ 4, when there are 3 ∙ 11. So, 4/11 equal to 12/33

Determine whether the ratios are equivalent.

Question 14.
\(\frac{2}{3} \text { and } \frac{8}{12}\)
___________

Answer:
Yes

Explanation:
2/3 × 4/4 = 8/12
So, 2/3 is equal to 8/12

Question 15.
\(\frac{8}{10} \text { and } \frac{6}{10}\)
___________

Answer:
No

Explanation:
8/10 ÷ 2/2 = 4/5
8/10 is not equal to 6/10

Question 16.
\(\frac{16}{60} \text { and } \frac{4}{15}\)
___________

Answer:
yes

Explanation:
16/60 ÷ 4/4 = 4/15
16/60 is equal to 4/15

Question 17.
\(\frac{3}{14} \text { and } \frac{8}{28}\)
___________

Answer:
No

Explanation:
3/14 is not equal to 8/28

Problem Solving + Applications – Page No. 226

Use the multiplication table for 18 and 19.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 24

Question 18.
In Keith’s baseball games this year, the ratio of times he has gotten on base to the times he has been at bat is \(\frac{4}{14}\). Write two ratios that are equivalent to \(\frac{4}{14}\).
Type below:
___________

Answer:
\(\frac{4}{14}\) = \(\frac{8}{28}\), \(\frac{2}{7}\)

Explanation:
4/14
multiply both numbers by 2
8/28
divide both numbers by 2
2/7

Question 19.
Pose a Problem Use the multiplication table to write a new problem involving equivalent ratios. Then solve the problem.
Type below:
___________

Answer:
The ratio of times he has gotten on base to the times he has been at bat is \(\frac{6}{9}\). Write two ratios that are equivalent to \(\frac{6}{9}\)
.multiply both numbers by 2 = 12/18
multiply both numbers by 3 = 18/ 27

Ratios and Rates Worksheets Answers Key 6th Grade Question 20.
Describe how to write an equivalent ratio for \(\frac{9}{27}\) without using a multiplication table.
Type below:
___________

Answer:
\(\frac{9}{27}\) = \(\frac{18}{54}\), \(\frac{3}{9}\)

Explanation:
\(\frac{9}{27}\)
Multiply both numbers by 2, 18/54
Divide both numbers by 3
3/9

Question 21.
Write a ratio that is equivalent to \(\frac{6}{9} \text { and } \frac{16}{24}\).
\(\frac{□}{□}\)

Answer:
\(\frac{2}{3}\)

Explanation:
\(\frac{6}{9} \text { and } \frac{16}{24}\)
\(\frac{2}{3}\) is the equivalent ratio to \(\frac{6}{9} \text { and } \frac{16}{24}\)

Question 22.
Determine whether each ratio is equivalent to \(\frac{1}{3}, \frac{5}{10}, \text { or } \frac{3}{5}\). Write the ratio in the correct box.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 25
Type below:
___________

Answer:
3/9, 7/21, 18/30, 10/30

Explanation:
2/4 = 1/2
3/9 = 1/3
7/21 = 1/3
18/30 = 3/5
10/30 = 1/3
6/10 = 2/5
8/16 = 4/8 = 1/2

Equivalent Ratios and Multiplication Tables – Page No. 227

Write two equivalent ratios.

Question 1.
Use a multiplication table to write two ratios that are equivalent to \(\frac{5}{3}\).
Type below:
___________

Answer:
\(\frac{5}{3}\) = \(\frac{10}{6}\), \(\frac{15}{9}\)

Explanation:
The original ratio is 5/3. Shade the row for 5 and the row for 3 on the multiplication table.
The column for 2 shows there are 2 ∙ 5, when there are 2 ∙ 3. So, 5/3 equal to 10/6
The column for 3 shows there are 3 ∙ 5, when there are 3 ∙ 3. So, 5/3 equal to 15/9

Question 2.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 26
Type below:
___________

Answer:
Grade 6 Chapter 4 image 24

Explanation:
The original ratio is 6/7. Shade the row for 6 and the row for 7 on the multiplication table.
The column for 2 shows there are 2 ∙ 6 when there are 2 ∙ 7. So, 6/7 equal to 12/14
The column for 3 shows there are 3 ∙ 6 when there are 3 ∙ 7. So, 6/7 equal to 18/21

Question 2.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 27
Type below:
___________

Answer:
Grade 6 Chapter 4 image 25

Explanation:
The original ratio is 3/2. Shade the row for 3 and the row for 2 on the multiplication table.
The column for 2 shows there are 2 ∙ 3 when there are 2 ∙ 2. So, 3/2 equal to 6/4
Multiply 3/2 with 4/4 = 12/8

Question 4.
\(\frac{6}{8}\)
Type below:
___________

Answer:
\(\frac{6}{8}\) =\(\frac{12}{16}\), \(\frac{18}{24}\)

Explanation:
The original ratio is 6/8. Shade the row for 6 and the row for 8 on the multiplication table.
The column for 2 shows there are 2 ∙ 6, when there are 2 ∙ 8. So, 6/8 equal to 12/16
The column for 3 shows there are 3 ∙ 6, when there are 3 ∙ 8. So, 6/8 equal to 18/24

Question 5.
\(\frac{11}{1}\)
Type below:
___________

Answer:
\(\frac{11}{1}\) = \(\frac{22}{2}\), \(\frac{33}{3}\)

Explanation:
The original ratio is 11/1. Shade the row for 11 and the row for 1 on the multiplication table.
The column for 2 shows there are 2 ∙ 11 when there are 2 ∙ 1. So, 11/1 equal to 22/2
The column for 3 shows there are 3 ∙ 11 when there are 3 ∙ 1. So, 11/1 equal to 33/3

Determine whether the ratios are equivalent.

Question 6.
\(\frac{2}{3} \text { and } \frac{5}{6}\).
___________

Answer:
No

Explanation:
2/3 is not equal to 5/6

Question 7.
\(\frac{5}{10} \text { and } \frac{1}{6}\).
___________

Answer:
No

Explanation:
5/10 is not equal to 1/6

Question 8.
\(\frac{8}{3} \text { and } \frac{32}{12}\).
___________

Answer:
Yes

Explanation:
8/3 × 4/4 = 32/12
8/3 is equal to 32/12

Question 9.
\(\frac{9}{12} \text { and } \frac{3}{4}\).
___________

Answer:
Yes

Explanation:
9/12 ÷ 3/3 = 3/4
9/12 is equal to 3/4

Problem Solving

Question 10.
Tristan uses 7 stars and 9 diamonds to make a design. Write two ratios that are equivalent to \(\frac{7}{9}\).
Type below:
___________

Answer:
\(\frac{7}{9}\)  = \(\frac{14}{18}\) , \(\frac{21}{27}\)

Explanation:
Tristan uses 7 stars and 9 diamonds to make a design.
\(\frac{7}{9}\)
The original ratio is 7/9. Shade the row for 7 and the row for 9 on the multiplication table.
The column for 2 shows there are 2 ∙ 7, when there are 2 ∙ 9. So, 7/9 equal to 14/18
The column for 3 shows there are 3 ∙ 7, when there are 3 ∙ 9. So, 7/9 equal to 21/27

Question 11.
There are 12 girls and 16 boys in Javier’s math class. There are 26 girls and 14 boys in Javier’s choir class. Are the ratios of girls to boys in the two classes equivalent? Explain.
Type below:
___________

Answer:
No, the ratio 26/14 is not equal to the ratio 12/16

Question 12.
Explain how to determine whether two ratios are equivalent.
Type below:
___________

Answer:
If any ratio is multiplied or divided by the same number, then the ratios are equivalent.

Lesson Check – Page No. 228

Question 1.
A pancake recipe calls for 4 cups of flour and 3 cups of milk. Does a recipe calling for 2 cups flour and 1.5 cups milk use the same ratio of flour to milk?
___________

Answer:
A muffin recipe that calls for 2 cups flour and 1.5 cups milk

Explanation:
A pancake recipe calls for 4 cups of flour and 3 cups of milk. A muffin recipe that calls for 2 cups flour and 1.5 cups milk.

Question 2.
A bracelet is made of 14 red beads and 19 gold beads. A necklace is made of 84 red beads and 133 gold beads. Do the two pieces of jewelry have the same ratio of red beads to gold beads?
___________

Answer:
The bracelet has 14 red and 19 gold, so the ratio between red and gold is 14/19. We cannot simplify this ratio as there are not common factors between 14 and 19, because 19 is a prime number.
As there are 84 red and 133 gold the ratio will be 84/133. For this ratio to be equal to 14/19 it should be that 84 is multiple of 14 and 133 multiple of 19, and both multiples must the same,
84/133 is not equal to 14/19

Spiral Review

Question 3.
Scissors come in packages of 3. Glue sticks come in packages of 10. Martha wants to buy the same number of each. What is the fewest glue sticks Martha can buy?
_____ glue sticks

Answer:
30 glue sticks

Explanation:
Scissors come in packages of 3. Glue sticks come in packages of 10. Martha wants to buy the same number of each.
3 × 10 = 30 glue sticks

Question 4.
Cole had \(\frac{3}{4}\) hour of free time before dinner. He spent \(\frac{2}{3}\) of the time playing the guitar. How long did he play the guitar?
\(\frac{□}{□}\) hour

Answer:
\(\frac{1}{2}\) hour

Explanation:
Cole had \(\frac{3}{4}\) hour of free time before dinner. He spent \(\frac{2}{3}\) of the time playing the guitar.
\(\frac{2}{3}\) × \(\frac{3}{4}\) = 1/2 hour

Question 5.
Delia has 3 \(\frac{5}{8}\) yards of ribbon. About how many \(\frac{1}{4}\)-yard-long pieces can she cut?
About _____ pieces

Answer:
About 14 pieces

Explanation:
Length of yards of ribbon is 3 5/8 = 29/8
Length of yards of ribbon pieces need to be cut is 1/4
Number of yards = 29/8 ÷ 1/4 = 14.5 = 14

Question 6.
Which point is located at –1.1?
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 28
Type below:
___________

Answer:
B

Explanation:
-1.1 is in between -1 and -2
-1.1 is close to -1
So, the answer is point B

Share and Show – Page No. 231

Question 1.
In Jawan’s school, 4 out of 10 students chose basketball as a sport they like to watch, and 3 out of 5 students chose football. Is the ratio of students who chose basketball (4 to 10) equivalent to the ratio of students who chose football (3 to 5)?
Type below:
___________

Answer:
the ratio of students who chose basketball (4 to 10) is not equivalent to the ratio of students who chose football (3 to 5)

Explanation:
In Jawan’s school, 4 out of 10 students chose basketball as a sport they like to watch, and 3 out of 5 students chose football.
4/10 = 0.4
3/5 = 0.6
0.4 is not equal to 0.6
The ratio of students who chose basketball (4 to 10) is not equivalent to the ratio of students who chose football (3 to 5)

Question 2.
What if 20 out of 50 students chose baseball as a sport they like to watch? Is this ratio equivalent to the ratio for either basketball or football? Explain.
Type below:
___________

Answer:
The baseball ratio is equal to the basketball ratio

Explanation:
If 20 out of 50 students chose baseball, 20/50 = 2/5
2/5 × 2/2 = 4/10
The baseball ratio is equal to the basketball ratio.

Lesson 4 Skills Practice Ratio Tables Answer Key Question 3.
Look for Structure The table shows the results of the quizzes Hannah took in one week. Did Hannah get the same score on her math and science quizzes? Explain.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 29
Type below:
___________

Answer:
Hannah didn’t get the same score on her math and science quizzes

Explanation:
Social Studies = 4/5
Math = 8/10 = 0.8
Science = 3/4 = 0.75
English = 10/12
Math = 8/10
Divide the 8/10 with 2/2 = 8/10 ÷ 2/2 = 4/5
Hannah didn’t get the same score on her math and science quizzes

Question 4.
Did Hannah get the same score on the quizzes in any of her classes? Explain.
Type below:
___________

Answer:
The ratio of Social Studies is equal to the ratio of Math

Explanation:
Social Studies = 4/5 = 0.8
Math = 8/10 = 0.8
Science = 3/4 = 0.75
English = 10/12 = 0.8333
The ratio of Social Studies is equal to the ratio of Math

On Your Own – Page No. 232

Question 5.
For every $10 that Julie makes, she saves $3. For every $15 Liam makes, he saves $6. Is Julie’s ratio of money saved to money earned equivalent to Liam’s ratio of money saved to money earned?
Type below:
___________

Answer:
Julie’s ratio of money saved to money earned is not equivalent to Liam’s ratio of money saved to money earned.

Explanation:
No. Julie’s ratio is 3:10 or 30 percent towards her savings while Lion’s is 6:15 which is 40 percent towards savings.

Question 6.
A florist offers three different bouquets of tulips and irises. The list shows the ratios of tulips to irises in each bouquet. Determine the bouquets that have equivalent ratios.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 30
Type below:
___________

Answer:
The ratio of Spring Mix is equal to the ratio of Splash of Sun

Explanation:
Spring Mix = 4/6 = 0.66
Morning Melody = 9/12 = 0.75
Splash of Sun = 10/15 =0.66
The ratio of Spring Mix is equal to the ratio of Splash of Sun

Question 7.
The ratio of boys to girls in a school’s soccer club is 3 to 5. The ratio of boys to girls in the school’s chess club is 13 to 15. Is the ratio of boys to girls in the soccer club equivalent to the ratio of boys to girls in the chess club? Explain
Type below:
___________

Answer:
No

Explanation:
They are not equivalent because you can not reduce 13 any further because it is a prime number and if you multiply 3 by 3 and 5 by 3 you would get 9:15 as the equivalent ratio.

Question 8.
Analyze Thad, Joey, and Mia ran in a race. The finishing times were 4.56 minutes, 3.33 minutes, and 4.75 minutes. Thad did not finish last. Mia had the fastest time. What was each runner’s time?
Type below:
___________

Answer:
Mia = 3.33 minutes
Joey = 4.75 minutes
Thad = 4.56 minutes

Explanation:
Mia had the fastest time. 3.33 minutes
Thad did not finish last. So, Joey = 4.75 minutes
Thad = 4.56 minutes

Question 9.
Fernando donates $2 to a local charity organization for every $15 he earns. Cleo donates $4 for every $17 she earns. Is Fernando’s ratio of money donated to money earned equivalent to Cleo’s ratio of money donated to money earned? Explain.
Type below:
___________

Answer:
Fernando’s ratio of money donated to money earned is not equivalent to Cleo’s ratio of money donated to money earned

Explanation:
Fernando donates $2 to a local charity organization for every $15 he earns.
$2/$15 = 0.1333
Cleo donates $4 for every $17 she earns. $4/$17 = 0.2359
Fernando’s ratio of money donated to money earned is not equivalent to Cleo’s ratio of money donated to money earned

Problem Solving Use Tables to Compare Ratios – Page No. 233

Read each problem and solve it.

Question 1.
Sarah asked some friends about their favorite colors. She found that 4 out of 6 people prefer blue, and 8 out of 12 people prefer green. Is the ratio of friends who chose blue to the total asked equivalent to the ratio of friends who chose green to the total asked?
Type below:
___________

Answer:
Yes, 4/6 is equivalent to 8/12

Explanation:
Grade 6 Chapter 4 image 26
4/6 = 0.666
8/12 = 0.666

Question 2.
Lisa and Tim make necklaces. Lisa uses 5 red beads for every 3 yellow beads. Tim uses 9 red beads for every 6 yellow beads. Is the ratio of red beads to yellow beads in Lisa’s necklace equivalent to the ratio in Tim’s necklace?
Type below:
___________

Answer:
The ratio of red beads to yellow beads in Lisa’s necklace is not equivalent to the ratio in Tim’s necklace

Explanation:
Lisa and Tim make necklaces. Lisa uses 5 red beads for every 3 yellow beads.
5/3 = 1.666
Tim uses 9 red beads for every 6 yellow beads. 9/6 = 1.5
The ratio of red beads to yellow beads in Lisa’s necklace is not equivalent to the ratio in Tim’s necklace

Go Math Grade 6 Module 4 Answer Key Question 3.
Mitch scored 4 out of 5 on a quiz. Demetri scored 8 out of 10 on a quiz. Did Mitch and Demetri get equivalent scores?
Type below:
___________

Answer:
Mitch and Demetri get equivalent scores

Explanation:
Mitch scored 4 out of 5 on a quiz. 4/5 = 0.8
Demetri scored 8 out of 10 on a quiz. = 8/10 = 0.8
Mitch and Demetri get equivalent scores

Question 4.
Use tables to show which of these ratios are equivalent : \(\frac{4}{6}\), \(\frac{10}{25}, \text { and } \frac{6}{15}\).
Type below:
___________

Answer:
\(\frac{10}{25}, \text { and } \frac{6}{15}\) are equal

Explanation:
\(\frac{4}{6}\) = 0.6666
\(\frac{10}{25}\) = 0.4
\(\frac{6}{15}\) = 0.4
\(\frac{10}{25}, \text { and } \frac{6}{15}\) are equal

Page No. 234

Question 1.
Mrs. Sahd distributes pencils and paper to students in the ratio of 2 pencils to 10 sheets of paper. Three of these ratios are equivalent to \(\frac{2}{10}\). Which one is NOT equivalent?
\(\frac{1}{5} \frac{7}{15} \frac{4}{20} \frac{8}{40}\)
Type below:
___________

Answer:
\(\frac{7}{15}\) is not equal \(\frac{2}{10}\)

Explanation:
Mrs. Sahd distributes pencils and paper to students in the ratio of 2 pencils to 10 sheets of paper. Three of these ratios are equivalent to \(\frac{2}{10}\) = 0.2
\(\frac{1}{5}\) = 0.2
\(\frac{7}{15}\) = 0.4666
\(\frac{4}{20}\) = 0.2
\(\frac{8}{40}\) = 0.2
\(\frac{7}{15}\) is not equal \(\frac{2}{10}\)

Lesson 4 Solve Problems with Unit Rate Answer Key Question 2.
Keith uses 18 cherries and 3 peaches to make a pie filling. Lena uses an equivalent ratio of cherries to peaches when she makes pie filling. Can Lena use a ratio of 21 cherries to 6 peaches? Explain.
Type below:
___________

Answer:
No, she cannot use a ratio of 21 cherries to 6 peaches

Explanation:
Keith uses 18 cherries and 3 peaches to make a pie filling. 18/3 = 6
Lena uses a ratio of 21 cherries to 6 peaches, 21/6 = 3.5
No, she cannot use a ratio of 21 cherries to 6 peaches

Spiral Review

Question 3.
What is the quotient \(\frac{3}{20} \div \frac{7}{10}\)?
Type below:
___________

Answer:
\(\frac{3}{14}\)

Explanation:
\(\frac{3}{20} \div \frac{7}{10}\)
3/20 × 10/7 = 3/14

Question 4.
Which of these numbers is greater than – 2.25 but less than –1?
1 -1.5 0 -2.5
Type below:
___________

Answer:

Explanation:
1 lies between 0 to 1
-1.5 lies between -1 and -2. It is greater than -2.25 and also less than -1
0 lies between -1 to 1
-2.5 lies between -2 and -3. -2.5 is less than -2.25

Question 5.
Alicia plots a point at (0, 5) and (0, –2). What is the distance between the points?
Type below:
___________

Answer:
7 units

Explanation:
Alicia plots a point at (0, 5) and (0, –2).
The given points have the same x-coordinates.
|-2| = 2
5 + 0 = 5
0 + 2 = 2
5 + 2 = 7
The distance is 7 units

Question 6.
Morton sees these stickers at a craft store. What is the ratio of clouds to suns?
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 31
Type below:
___________

Answer:
3 : 2

Explanation:
there are 3 clouds and 2 suns. So, the ratio is 3 to 2.

Share and Show – Page No. 237

Use equivalent ratios to find the unknown value.

Question 1.
\(\frac{?}{10}=\frac{4}{5}\)
_____

Answer:
\(\frac{8}{10}\) = \(\frac{4}{5}\)

Explanation:
Use common denominators to write equivalent ratios.
10 is a multiple of 5, so 10 is a common denominator.
Multiply the 4 and denominator by 2 to write the ratios using a common denominator.
4/5 × 2/2 = 8/10
The denominators are the same, so the numerators are equal to each other.
So, the unknown value is 8/10 = 4/5
\(\frac{8}{10}\)

Question 2.
\(\frac{18}{24}=\frac{6}{?}\)
_____

Answer:
\(\frac{6}{8}\) = \(\frac{18}{24}\)

Explanation:
Write an equivalent ratio with 18 in the numerator.
Divide 18 by 6 to get 3
So, divide the denominator by 24 as well.
24/3 = 8
The numerators are the same, so the denominators are equal to each other.
So, the unknown value is 6/8 = 18/24
\(\frac{6}{8}\)

Question 3.
\(\frac{3}{6}=\frac{15}{?}\)
_____

Answer:
\(\frac{15}{30}\)

Explanation:
Write an equivalent ratio with 15 in the numerator.
Multiply 3 by 5 to get 15
So, Multiply 6 by 5 to get the denominator of the unknown number.
6 × 5 = 30
The numerators are the same, so the denominators are equal to each other.
So, the unknown value is 3/6 = 15/30
\(\frac{15}{30}\)

Question 4.
\(\frac{?}{5}=\frac{8}{10}\)
_____

Answer:
\(\frac{4}{5}\)

Explanation:
Write an equivalent ratio with 10 in the denominator.
Divide 10 by 2 to get 5
So, divide the numerator 8 as well.
8/2 = 4
The denominators are the same, so the numerators are equal to each other.
So, the unknown value is 8/10 = 4/5
\(\frac{4}{5}\)

Question 5.
\(\frac{7}{4}=\frac{?}{12}\)
_____

Answer:
\(\frac{21}{12}\)

Explanation:
Write an equivalent ratio with 12 in the denominator.
Multiply 4 with 3 to get 12
So, Multiply 7 with 3 to get the numerator of the unknown number.
7 × 3 = 21
The denominators are the same, so the numerators are equal to each other.
So, the unknown value is 21/12 = 7/4
\(\frac{21}{12}\)

Question 6.
\(\frac{10}{?}=\frac{40}{12}\)
_____

Answer:
\(\frac{10}{3}\)

Explanation:
Write an equivalent ratio with 40 in the numerator.
Divide 40 by 4 to get 10
So, divide the denominator 12 as well.
12/4 = 3
The numerators are the same, so the denominators are equal to each other.
So, the unknown value is 10/3 = 40/12
\(\frac{10}{3}\)

On Your Own

Use equivalent ratios to find the unknown value.

Question 7.
\(\frac{2}{6}=\frac{?}{30}\)
_____

Answer:
\(\frac{10}{30}\)

Explanation:
Use common denominators to write equivalent ratios.
30 is a multiple of 6, so 30 is a common denominator.
Multiply the 6 and denominator by 5 to write the ratios using a common denominator.
2/6 × 5/5 =10/30
The denominators are the same, so the numerators are equal to each other.
So, the unknown value is 10/30 = 2/6
\(\frac{10}{30}\)

Question 8.
\(\frac{5}{?}=\frac{55}{110}\)
_____

Answer:
\(\frac{5}{10}\)

Explanation:
Write an equivalent ratio with 55 in the numerator.
Divide 55 with 11 to get 5
So, Divide 110 by 11 to get the denominator of unknown number.
110/11 = 10
The numerators are the same, so the denominators are equal to each other.
So, the unknown value is 5/10 = 55/110
\(\frac{5}{10}\)

Question 9.
\(\frac{3}{9}=\frac{9}{?}\)
_____

Answer:
\(\frac{9}{27}\)

Explanation:
Write an equivalent ratio with 9 in the numerator.
Multiply 3 with 3 to get 9
So, Multiply 9 with 3 to get the denominator of unknown number.
9 × 3 = 27
The numerators are the same, so the denominators are equal to each other.
So, the unknown value is 9/27 = 3/9
\(\frac{9}{27}\)

Question 10.
\(\frac{?}{6}=\frac{16}{24}\)
_____

Answer:
\(\frac{4}{6}\)

Explanation:
Use common denominators to write equivalent ratios.
Divide 24 with 4 to get 6.
So, divide 16 with 4 to know the unknown number of numerator
16/4 = 4
The denominators are the same, so the numerators are equal to each other.
So, the unknown value is 4/6 = 16/24
\(\frac{4}{6}\)

Question 11.
Mavis walks 3 miles in 45 minutes. How many minutes will it take Mavis to walk 9 miles?
_____ minutes

Answer:
135 minutes

Explanation:
Mavis walks 3 miles in 45 minutes.
For 9 miles, (9 × 45)/3 = 135 minutes

Question 12.
The ratio of boys to girls in a choir is 3 to 8. There are 32 girls in the choir. How many members are in the choir?
_____ members

Answer:
12 members

Explanation:
The ratio of boys to girls in a choir is 3 to 8.
3/8 × 4/ 4 = 12/32
So, if there are 32 girls in the choir, there will be 12 boys present.

Question 13.
Use Reasoning Is the unknown value in \(\frac{2}{3}=\frac{?}{18}\) the same as the unknown value in \(\frac{3}{2}=\frac{18}{?}\)? Explain.
Type below:
___________

Answer:
12

Explanation:
\(\frac{2}{3}=\frac{?}{18}\)
2/3 × 6/6 = 12/18
The unknown value is 12
\(\frac{3}{2}=\frac{18}{?}\)
3/2 × 6/6 = 18/12
The unknown value is 12

Problem Solving + Applications – Page No. 238

Solve by finding an equivalent ratio.

Question 14.
It takes 8 minutes for Sue to make 2 laps around the go-kart track. How many laps can Sue complete in 24 minutes?
_____ laps

Answer:
6 laps

Explanation:
It takes 8 minutes for Sue to make 2 laps around the go-kart track.
For 24 minutes, (24 × 2)/8 = 48/8 =6

Question 15.
The width of Jay’s original photo is 8 inches. The length of the original photo is 10 inches. He prints a smaller version that has an equivalent ratio of width to length. The width of the smaller version is 4 inches less than the width of the original. What is the length of the smaller version?
_____ inches

Answer:
5 inches

Explanation:
The width of Jay’s original photo is 8 inches. The length of the original photo is 10 inches.
8/10
He prints a smaller version that has an equivalent ratio of width to length. The width of the smaller version is 4 inches less than the width of the original.
4/s
8/10 ÷ 2/2 = 4/5
5 inches

Question 16.
Ariel bought 3 raffle tickets for $5. How many tickets could Ariel buy for $15?
_____ tickets

Answer:
9 tickets

Explanation:
Ariel bought 3 raffle tickets for $5.
For $15, ($15 × 3)/ $5 = 45/5 = 9

6th Grade Lesson 5 Skills Practice Ratio Tables Answer Key Question 17.
What’s the Error? Greg used the steps shown to find the unknown value. Describe his error and give the correct solution.
\(\frac{2}{6}=\frac{?}{12}\)
\(\frac{2+6}{6+6}=\frac{?}{12}\)
\(\frac{8}{12}=\frac{?}{12}\)
The unknown value is 8.
Type below:
___________

Answer:
Greg added 6 to the numerator and denominator which is not correct to find the unknown value.
\(\frac{2}{6}=\frac{?}{12}\)
2/6 × 2/2 = 4/12
4 is the unknown value.

Question 18.
Courtney bought 3 maps for $10. Use the table of equivalent ratios to find how many maps she can buy for $30.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 32
Type below:
___________

Answer:
Grade 6 Chapter 4 image 28

Explanation:
3/10 × 3/3 = 9/30

Use Equivalent Ratios – Page No. 239

Use equivalent ratios to find the unknown value.

Question 1.
\(\frac{4}{10}=\frac{?}{40}\)
_____

Answer:
\(\frac{16}{40}\)

Explanation:
4/10 × 4/4 = 16/40

Question 2.
\(\frac{3}{24}=\frac{33}{?}\)
_____

Answer:
\(\frac{33}{264}\)

Explanation:
3/24 × 11/11 = 33/264

Question 3.
\(\frac{7}{?}=\frac{21}{27}\)
_____

Answer:
\(\frac{7}{9}\)

Explanation:
21/27 ÷ 3/3 = 7/9

Question 4.
\(\frac{?}{9}=\frac{12}{54}\)
_____

Answer:
\(\frac{2}{9}\)

Explanation:
12/54 ÷ 6/6 = 2/9

Question 5.
\(\frac{3}{2}=\frac{12}{?}\)
_____

Answer:
\(\frac{12}{8}\)

Explanation:
3/2 × 4/4 = 12/8

Question 6.
\(\frac{4}{5}=\frac{?}{40}\)
_____

Answer:
\(\frac{32}{40}\)

Explanation:
4/5 × 8/8 = 32/40

Question 7.
\(\frac{?}{2}=\frac{45}{30}\)
_____

Answer:
\(\frac{3}{2}\)

Explanation:
45/30 ÷ 15/15 = 3/2

Question 8.
\(\frac{45}{?}=\frac{5}{6}\)
_____

Answer:
\(\frac{45}{54}\)

Explanation:
5/6 × 9/9 = 45/54

Problem Solving

Question 9.
Honeybees produce 7 pounds of honey for every 1 pound of beeswax they produce. Use equivalent ratios to find how many pounds of honey are produced when 25 pounds of beeswax are produced.
_____ pounds

Answer:
175 pounds

Explanation:
Honeybees produce 7 pounds of honey for every 1 pound of beeswax they produce.
7/1
25 pounds of beeswax, 25 × 7 = 175 pounds

Practice and Homework Lesson 4.5 Answer Key Question 10.
A 3-ounce serving of tuna provides 21 grams of protein. Use equivalent ratios to find how many grams of protein are in 9 ounces of tuna.
_____ grams of protein

Answer:
63 grams of protein

Explanation:
A 3-ounce serving of tuna provides 21 grams of protein.
For 9 ounces of tuna, (21 × 9)/3 = 63

Question 11.
Explain how using equivalent ratios is like adding fractions with unlike denominators.
Type below:
___________

Answer:
Equivalent ratios have different numbers but represent the same relationship. In this tutorial, you’ll see how to find equivalent ratios by first writing the given ratio as a fraction. And it cannot be the same by adding two fractions with different ratios.

Lesson Check – Page No. 240

Question 1.
Jaron paid $2.70 for 6 juice boxes. How much should Jaron expect to pay for 18 juice boxes?
$ _____

Answer:
$8.1

Explanation:
Jaron paid $2.70 for 6 juice boxes. For 6 boxes he paid $2.70.
For 18 juice boxes, (18 × $2.70)/6 = $8.1

Question 2.
A certain shade of orange paint is made by mixing 3 quarts of red paint with 2 quarts of yellow paint. To make more paint of the same shade, how many quarts of yellow paint should be mixed with 6 quarts of red paint?
_____ quarts

Answer:
4 quarts

Explanation:
A certain shade of orange paint is made by mixing 3 quarts of red paint with 2 quarts of yellow paint.
3 quarts of red paint is mixed with 2 quarts of yellow paint
So, 6 quarts of red paint is mixed with 6/3 × 2 = 4 quarts of yellow paint

Spiral Review

Question 3.
What is the quotient \(2 \frac{4}{5} \div 1 \frac{1}{3}\)?
______ \(\frac{□}{□}\)

Answer:
2\(\frac{1}{10}\)

Explanation:
2 4/5 = 14/5 = 2.8
1 1/3 = 4/3 = 1.333
2.8/1.333 = 2 1/10

Question 4.
What is the quotient \(-2 \frac{2}{3}\)?
______ \(\frac{□}{□}\)

Answer:
1\(\frac{11}{16}\)

Explanation:
−4 1/2 ÷ -2 2/3
1 11/16

Practice and Homework Lesson 4.5 Answer Key Question 5.
On a map, a clothing store is located at (–2, –3). A seafood restaurant is located 6 units to the right of the clothing store. What are the coordinates of the restaurant?
Type below:
___________

.Answer:
(4, -3)

Explanation:
On a map, a clothing store is located at (–2, –3). A seafood restaurant is located 6 units to the right of the clothing store.
|-2| = 2
2 + 0 = 2
0+4 = 4
2 + 4 = 6 units

Question 6.
Marisol plans to make 9 mini-sandwiches for every 2 people attending her party. Write a ratio that is equivalent to Marisol’s ratio.
Type below:
___________

Answer:
27/6 and 45/10

Explanation:
Marisol plans to make 9 mini-sandwiches for every 2 people attending her party. 9/2 × 3/3 = 27/6
9/2 × 5/5 = 45/10

Mid-Chapter Checkpoint – Vocabulary – Page No. 241

Choose the best term from the box to complete the sentence.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 33

Question 1.
A _____ is a rate that makes a comparison to 1 unit.
Type below:
___________

Answer:
rate

Question 2.
Two ratios that name the same comparison are _____ .
Type below:
___________

Answer:
Equivalent Ratios

Concepts and Skills
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 34

Question 3.
Write the ratio of red circles to blue squares.
Type below:
___________

Answer:
3 : 5

Explanation:
There are 3 red counter and 5 square boxes.
So, the ratio is 3 : 5

Write the ratio in two different ways.

Question 4.
8 to 12
Type below:
___________

Answer:
\(\frac{8}{12}\)
8 : 12

Explanation:
8 to 12 as a fraction  \(\frac{8}{12}\)
8 to 12 with a colon 8 : 12

Question 5.
7 : 2
Type below:
___________

Answer:
\(\frac{7}{2}\)
7 to 2

Explanation:
7 : 2 as a fraction  \(\frac{7}{2}\)
7 : 2 using words 7 to 2

Question 6.
\(\frac{5}{9}\)
Type below:
___________

Answer:
5 to 9
5 : 9

Explanation:
\(\frac{5}{9}\) using words 5 to 9
\(\frac{5}{9}\) with a colon 5 : 9

Question 7.
11 to 3
Type below:
___________

Answer:
\(\frac{11}{3}\)
11 : 3

Explanation:
11 to 3 as a fraction \(\frac{11}{3}\)
11 to 3 with a colon 11 : 3

Write two equivalent ratios.

Question 8.
\(\frac{2}{7}\)
Type below:
___________

Answer:
\(\frac{2}{7}\) = \(\frac{4}{14}\), \(\frac{6}{21}\)

Explanation:
The original ratio is 2/7. Shade the row for 2 and the row for 7 on the multiplication table.
The column for 2 shows there are 2 ∙ 2, when there are 2 ∙ 7. So, 2/7 equal to 4/14
The column for 3 shows there are 3 ∙ 2, when there are 3 ∙ 7. So, 2/7 equal to 6/21

Question 9.
\(\frac{6}{5}\)
Type below:
___________

Answer:
\(\frac{6}{5}\) = \(\frac{12}{10}\), \(\frac{18}{15}\)

Explanation:
The original ratio is 6/5. Shade the row for 6 and the row for 5 on the multiplication table.
The column for 2 shows there are 2 ∙ 6, when there are 2 ∙ 5. So, 6/5 equal to 12/10
The column for 3 shows there are 3 ∙ 6, when there are 3 ∙ 5. So, 6/5 equal to 18/15

Question 10.
\(\frac{9}{12}\)
Type below:
___________

Answer:
\(\frac{9}{12}\) = \(\frac{18}{24}\), \(\frac{27}{36}\)

Explanation:
The original ratio is 9/12. Shade the row for 9 and the row for 12 on the multiplication table.
The column for 2 shows there are 2 ∙ 9, when there are 2 ∙ 12. So, 9/12 equal to 18/24
The column for 3 shows there are 3 ∙ 9, when there are 3 ∙ 12. So, 9/12 equal to 27/36

Question 11.
\(\frac{18}{6}\)
Type below:
___________

Answer:
\(\frac{18}{6}\) = \(\frac{36}{12}\), \(\frac{54}{18}\)

Explanation:
The original ratio is 18/6. Shade the row for 18 and the row for 6 on the multiplication table.
The column for 2 shows there are 2 ∙ 18, when there are 2 ∙ 6. So, 18/6 equal to 36/12
The column for 3 shows there are 3 ∙ 18, when there are 3 ∙ 6. So, 18/6 equal to 54/18

Find the unknown value.

Question 12.
\(\frac{15}{?}=\frac{5}{10}\)
Type below:
___________

Answer:
30

Explanation:
5/10 × 3/3 = 15/30
So, the unknown number is 30

Question 13.
\(\frac{?}{9}=\frac{12}{3}\)
Type below:
___________

Answer:
36

Explanation:
12/3 × 3/3 = 36/9
So, the unknown number is 36

Question 14.
\(\frac{48}{16}=\frac{?}{8}\)
Type below:
___________

Answer:
24

Explanation:
48/16 ÷ 2/2 = 24/8
So, the unknown number is 24

Question 15.
\(\frac{9}{36}=\frac{3}{?}\)
Type below:
___________

Answer:
12

Explanation:
9/36 ÷ 3/3 = 3/12
So, the unknown number is 12

Page No. 242

Question 16.
There are 36 students in the chess club, 40 students in the drama club, and 24 students in the film club. What is the ratio of students in the drama club to students in the film club?
Type below:
___________

Answer:
40 to 24

Explanation:
There are 36 students in the chess club, 40 students in the drama club, and 24 students in the film club.
The ratio of students in the drama club to students in the film club 40 to 24

Question 17.
A trail mix has 4 cups of raisins, 3 cups of dates, 6 cups of peanuts, and 2 cups of cashews. Which ingredients are in the same ratio as cashews to raisins?
Type below:
___________

Answer:
dates to peanuts

Explanation:
A trail mix has 4 cups of raisins, 3 cups of dates, 6 cups of peanuts, and 2 cups of cashews.
cashews to raisins = 2/4 = 1/2
dates to peanuts = 3/6 = 1/2

Question 18.
There are 32 adults and 20 children at a school play. What is the ratio of children to people at the school play?
Type below:
___________

Answer:
5 to 13

Explanation:
There are 32 adults and 20 children at a school play.
people = 32 + 20 = 52
the ratio of children to people at the school play = 20/52 = 5/13

Question 19.
Sonya got 8 out of 10 questions right on a quiz. She got the same score on a quiz that had 20 questions. How many questions did Sonya get right on the second quiz? How many questions did she get wrong on the second quiz?
Type below:
___________

Answer:
4 wrong

Explanation:
8/10 = x/20
So, 10 × 2 = 20, so 8 × 2=16
so she got 16 out of 20 right and 20 – 16 = 4
She got 4 wrong.

Share and Show – Page No. 245

Write the rate as a fraction. Then find the unit rate.

Question 1.
Sara drove 72 miles on 4 gallons of gas.
_____ miles/gallon

Answer:
18 miles/gallon

Explanation:
Sara drove 72 miles on 4 gallons of gas.
72/4
Divide 72/4 with 4/4
72/4 ÷ 4/4 = 18

Question 2.
Dean paid $27.00 for 4 movie tickets.
$ _____ per ticket

Answer:
$6.75 per ticket

Explanation:
Dean paid $27.00 for 4 movie tickets.
$27.00/4
Divide $27.00/4 with 4/4
$27.00/4 ÷ 4/4 = $6.75

Question 3.
Amy and Mai have to read Bud, Not Buddy for a class. Amy reads 20 pages in 2 days. Mai reads 35 pages in 3 days. Who reads at a faster rate?
___________

Answer:
Mai reads at a faster rate

Explanation:
Amy and Mai have to read Bud, Not Buddy for a class.
Amy reads 20 pages in 2 days. 20/2 = 10 pages for each day
Mai reads 35 pages in 3 days. 35/3 = 11.66 pages for each day
Mai reads at a faster rate

Question 4.
An online music store offers 5 downloads for $6.25. Another online music store offers 12 downloads for $17.40. Which store offers the better deal?
___________

Answer:
An online music store offers 5 downloads for $6.25 offers the better deal

Explanation:
An online music store offers 5 downloads for $6.25.
$6.25/5 = $1.25
Another online music store offers 12 downloads for $17.40.
$17.40/12 = $1.45
An online music store offers 5 downloads for $6.25 offers the better deal

On Your Own

Write the rate as a fraction. Then find the unit rate.

Question 5.
A company packed 108 items in 12 boxes.
Type below:
___________

Answer:
9

Explanation:
A company packed 108 items in 12 boxes.
108/12
Divide 108/12 with 12/12
108/12 ÷ 12/12 = 9

Question 6.
There are 112 students for 14 teachers.
Type below:
___________

Answer:
8

Explanation:
There are 112 students for 14 teachers.
112/14
Divide 112/14 with 14/14
112/14 ÷ 14/14 = 8

Lesson 6 Skills Practice Ratio Tables Answer Key Question 7.
Geoff charges $27 for 3 hours of swimming lessons. Anne charges $31 for 4 hours. How much more does Geoff charge per hour than Anne?
$ _____

Answer:
$1.25

Explanation:
Geoff charges $27 for 3 hours of swimming lessons.
$27/3 = $9 for an hour
Anne charges $31 for 4 hours.
$31/4 = $7.75
$9 – $7.75 = $1.25
Geoff charge $1.25 per hour more than Anne

Question 8.
Compare One florist made 16 bouquets in 5 hours. A second florist made 40 bouquets in 12 hours. Which florist makes bouquets at a faster rate?
Type below:
___________

Answer:
A second florist made 40 bouquets in 12 hours at a faster rate

Explanation:
Compare One florist made 16 bouquets in 5 hours.
16/5 = 3.2
A second florist made 40 bouquets in 12 hours.
40/12 = 3.333
A second florist made 40 bouquets in 12 hours at a faster rate

Tell which rate is faster by comparing unit rates.

Question 9.
\(\frac{160 \mathrm{mi}}{2 \mathrm{hr}} \text { and } \frac{210 \mathrm{mi}}{3 \mathrm{hr}}\)
Type below:
___________

Answer:
160mi/2hr

Explanation:
160mi/2hr ÷ 2/2 = 80mi/hr
210mi/3hr = 70mi/hr
80mi/hr > 70mi/hr

Question 10.
\(\frac{270 \mathrm{ft}}{9 \mathrm{min}} \text { and } \frac{180 \mathrm{ft}}{9 \mathrm{min}}\)
Type below:
___________

Answer:
270ft/9min

Explanation:
270ft/9min = 30ft/min
180ft/9min = 20ft/min
30ft/min > 20ft/min

Question 11.
\(\frac{250 \mathrm{m}}{10 \mathrm{s}} \text { and } \frac{120 \mathrm{m}}{4 \mathrm{s}}\)
Type below:
___________

Answer:
250m/10s

Explanation:
250m/10s = 25m/s
120m/4s = 20m/s
25m/s > 20m/s

Unlock the Problem – Page No. 246

Question 12.
Ryan wants to buy treats for his puppy. If Ryan wants to buy the treats that cost the least per pack, which treat should he buy? Explain.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 35
a. What do you need to find?
Type below:
___________

Answer:
We need to find that cost the least per pack

Question 12.
b. Find the price per pack for each treat.
Type below:
___________

Answer:
Pup bites = $5.76/4 ÷ 4/4 = $1.44
Doggie Treats = $7.38/6 ÷ 6/6 = $1.23
Pupster snacks = $7.86/6 ÷ 6/6 = $1.31
Nutri-Biscuits = $9.44/8 ÷ 8/8 = $1.18

Question 12.
c. Complete the sentences
The treat with the highest price per pack is _____.
The treat with the lowest price per pack is _____.
Ryan should buy _____ because _____.
Type below:
___________

Answer:
The treat with the highest price per pack is Pup bites.
The treat with the lowest price per pack is Nutri-Biscuits.
Ryan should buy Nutri-Biscuits because it has the least cost.

Question 13.
Reason Abstractly What information do you need to consider in order to decide whether one product is a better deal than another? When might the lower unit rate not be the best choice? Explain.
Type below:
___________

Answer:
We will consider the low cost in order to decide whether one product is a better deal than another.
The lower unit rate is not the best choice. Because it will show the highest cost.

Go Math Grade 6 Lesson 4.6 Answer Key Question 14.
Select the cars that get a higher mileage per gallon of gas than a car that gets 25 miles per gallon. Mark all that apply.
Options:
a. Car A 22 miles per 1 gallon
b. Car B 56 miles per 2 gallons
c. Car C 81 miles per 3 gallons
d. Car D 51 miles per 3 gallons

Answer:
b. Car B 56 miles per 2 gallons
c. Car C 81 miles per 3 gallons

Explanation:
22/1 = 22
56/2 = 28
81/3 = 27
51/3 = 17

Find Unit Rates – Page No. 247

Write the rate as a fraction. Then find the unit rate.

Question 1.
A wheel rotates through 1,800º in 5 revolutions.
Type below:
___________

Answer:

Explanation:
A wheel rotates through 1,800º in 5 revolutions.
1,800º/5 revolutions
1,800º/5 revolutions ÷ 5/5 = 360º/1revolution

Question 2.
There are 312 cards in 6 decks of playing cards.
Type below:
___________

Answer:
52 cards/1 deck of playing cards

Explanation:
There are 312 cards in 6 decks of playing cards.
312/6 ÷ 6/6 = 52 cards/1 deck of playing cards

Question 3.
Bana ran 18.6 miles of a marathon in 3 hours.
Type below:
___________

Answer:
6.2 miles/hour

Explanation:
Bana ran 18.6 miles of a marathon in 3 hours.
18.6 miles/ 3 hours ÷ 3/3 = 6.2 miles/hour

Question 4.
Cameron paid $30.16 for 8 pounds of almonds.
Type below:
___________

Answer:
$3.77/1 pound

Explanation:
Cameron paid $30.16 for 8 pounds of almonds.
$30.16/8 pounds ÷ 8/8 = $3.77/1 pound

Compare unit rates.

Question 5.
An online game company offers a package that includes 2 games for $11.98. They also offer a package that includes 5 games for $24.95. Which package is a better deal?
_____ package

Answer:
5 game package

Explanation:
An online game company offers a package that includes 2 games for $11.98.
$11.98/2 = $5.99
They also offer a package that includes 5 games for $24.95.
$24.95/5 = $4.99

Question 6.
At a track meet, Samma finished the 200-meter race in 25.98 seconds. Tom finished the 100-meter race in 12.54 seconds. Which runner ran at a faster average rate?
___________

Answer:
Tom

Explanation:
At a track meet, Samma finished the 200-meter race in 25.98 seconds.
200/25.98 seconds = 7.698 – meter/1 sec
Tom finished the 100-meter race in 12.54 seconds.
100 – meter/12.54 seconds = 7.974 – meter/1 sec

Problem Solving

Question 7.
Sylvio’s flight is scheduled to travel 1,792 miles in 3.5 hours. At what average rate will the plane have to travel to complete the trip on time?
Type below:
___________

Answer:
512 miles per hour

Explanation:
Sylvio’s flight is scheduled to travel 1,792 miles in 3.5 hours.
1,792 miles/3.5 hours ÷ 3.5/3.5 = 512 miles per hour

Question 8.
Rachel bought 2 pounds of apples and 3 pounds of peaches for a total of $10.45. The apples and peaches cost the same amount per pound. What was the unit rate?
Type below:
___________

Answer:
$2.09 per pound

Explanation:
Rachel bought 2 pounds of apples and 3 pounds of peaches for a total of $10.45.
The apples and peaches cost the same amount per pound.
2 + 3 = 5
$10.45/5 = $2.09 per pound

Question 9.
Write a word problem that involves comparing unit rates.
Type below:
___________

Answer:
At a track meet, Samma finished the 200-meter race in 25.98 seconds. Tom finished the 100-meter race in 12.54 seconds. Which runner ran at a faster average rate?
At a track meet, Samma finished the 200-meter race in 25.98 seconds.
200/25.98 seconds = 7.698 – meter/1 sec
Tom finished the 100-meter race in 12.54 seconds.
100 – meter/12.54 seconds = 7.974 – meter/1 sec
Tom

Lesson Check – Page No. 248

Question 1.
Cran–Soy trail mix costs $2.99 for 5 ounces, Raisin–Nuts mix costs $3.41 for 7 ounces, Lots of Cashews mix costs $7.04 for 8 ounces, and Nuts for You mix costs $2.40 for 6 ounces. List the trail mix brands in order from the least expensive to the most expensive.
Type below:
___________

Answer:
Nuts for You, Raisin–Nuts, Cran–Soy trail mix, Lots of Cashews mix

Explanation:
Cran–Soy trail mix costs $2.99 for 5 ounces,
$2.99/5 = $0.598
Raisin–Nuts mix costs $3.41 for 7 ounces,
$3.41/7 = $0.487
Lots of Cashews mix costs $7.04 for 8 ounces,
$7.04/8 = $0.88
and Nuts for You mix costs $2.40 for 6 ounces.
$2.40/6 = $0.4

Question 2.
Aaron’s heart beats 166 times in 120 seconds. Callie’s heart beats 88 times in 60 seconds. Emma’s heart beats 48 times in 30 seconds. Galen’s heart beats 22 times in 15 seconds. Which two students’ heart rates are equivalent?
Type below:
___________

Answer:
Callie and Galen

Explanation:
Aaron’s heart beats 166 times in 120 seconds.
166/120 = 1.3833
Callie’s heart beats 88 times in 60 seconds.
88/60 = 1.4666
Emma’s heart beats 48 times in 30 seconds.
48/30 = 1.6
Galen’s heart beats 22 times in 15 seconds.
22/15 = 1.4666

Spiral Review

Question 3.
Courtlynn combines \(\frac{7}{8}\) cup sour cream with \(\frac{1}{2}\) cup cream cheese. She then divides the mixture between 2 bowls. How much mixture does Courtlynn put in each bowl?
\(\frac{□}{□}\) cup

Answer:
\(\frac{11}{16}\) cup

Explanation:
Courtlynn combines \(\frac{7}{8}\) cup sour cream with \(\frac{1}{2}\) cup cream cheese.
7/8 + 1/2 = 11/8
11/8 ÷ 2 = 11/8 × 1/2 = 11/16 cup

Practice and Homework Lesson 4.6 Answer Key Question 4.
Write a comparison using < or > to show the relationship between |-\(\frac{2}{3}\)| and – \(\frac{5}{6}\).
Type below:
___________

Answer:
>

Explanation:
|-\(\frac{2}{3}\)| = 2/3 = 0.666
– \(\frac{5}{6}\) = -0.8333
|-\(\frac{2}{3}\)| > – \(\frac{5}{6}\)

Question 5.
There are 18 tires on one truck. How many tires are on 3 trucks of the same type?
_____ tires

Answer:
54 tires

Explanation:
There are 18 tires on one truck.
For 3 trucks, (3 × 18)/1 = 54 tires

Question 6.
Write two ratios that are equivalent to \(\frac{5}{6}\).
Type below:
___________

Answer:
\(\frac{5}{6}\) = \(\frac{10}{12}\), \(\frac{15}{18}\)

Explanation:
5/6 × 2/2 = 10/12
5/6 × 3/3 = 15/18

Share and Show – Page No. 251

Use a unit rate to find the unknown value.

Question 1.
\(\frac{10}{?}=\frac{6}{3}\)
_____

Answer:
5

Explanation:
6/3 ÷ 3/3 = 2/1
2/1 × 5/5 = 10/1
The unknown value is 5

Question 2.
\(\frac{6}{8}=\frac{?}{20}\)
_____

Answer:
15

Explanation:
6/8 ÷ 8/8 = 0.75/1
0.75/1 × 20/20 = 15/20
The unknown value is 15

On Your Own

Use a unit rate to find the unknown value.

Question 3.
\(\frac{40}{8}=\frac{45}{?}\)
_____

Answer:
9

Explanation:
40/8 ÷ 8/8 = 5/1
5/1 × 9/9 = 45/9
The unknown value is 9

Question 4.
\(\frac{42}{14}=\frac{?}{5}\)
_____

Answer:
15

Explanation:
42/14 ÷ 14/14 = 3/1
3/1 × 5/5 = 15/5
The unknown value is 15

Question 5.
\(\frac{?}{2}=\frac{56}{8}\)
_____

Answer:
14

Explanation:
56/8 ÷ 8/8 = 7/1
7/1 × 2/2 = 14/2
The unknown value is 14

Question 6.
\(\frac{?}{4}=\frac{26}{13}\)
_____

Answer:
8

Explanation:
26/13 ÷ 13/13 = 2/1
2/1 × 4/4 = 8/4
The unknown value is 8

Practice: Copy and Solve Draw a bar model to find the unknown value.

Question 7.
\(\frac{4}{32}=\frac{9}{?}\)
_____

Answer:
Grade 6 Chapter 4 image 29

Explanation:
4/32 ÷ 32/32 = 0.125/1
0.125/1 × 72/72 = 9/72
The unknown value is 72

Question 8.
\(\frac{9}{3}=\frac{?}{4}\)
_____

Answer:
Grade 6 Chapter 4 image 30
12

Explanation:
9/3 ÷ 3/3 = 3/1
3/1 × 4/4 = 12/4
The unknown value is 12

Question 9.
\(\frac{?}{14}=\frac{9}{7}\)
_____

Answer:
Grade 6 Chapter 4 image 31

Explanation:
9/7 ÷ 7/7 = 1.2857/1
1.2857/1 × 14/14 = 18/14
The unknown value is 18

Question 10.
\(\frac{3}{?}=\frac{2}{1.25}\)
_____

Answer:
1.875

Explanation:
2/1.25 ÷ 1.25/1.25 = 1.6/1
1.6/1 × 1.875/1.875 = 3/1.875
The unknown value is 1.875

Question 11.
Communicate Explain how to find an unknown value in a ratio by using a unit rate.
Type below:
___________

Answer:
Firstly, Identify the known ratio, where both values are known. Then, Identify the ratio with one known value and one unknown value. Next, Use the two ratios to create a proportion. Finally, Cross-multiply to solve the problem.

Question 12.
Savannah is tiling her kitchen floor. She bought 8 cases of tile for $192. She realizes she bought too much tile and returns 2 unopened cases to the store. What was her final cost for tile?
$ _____

Answer:
$144

Explanation:
Savannah is tiling her kitchen floor. She bought 8 cases of tile for $192.
$192/8 ÷ 8/8 = $24 per each case of tile
She realizes she bought too much tile and returns 2 unopened cases to the store.
So, she bought 8 – 2 = 6 cases of tiles.
6 × $24 = $144

Problem Solving + Applications – Page No. 251

Pose a Problem

Question 13.
Josie runs a T-shirt printing company. The table shows the length and width of four sizes of T-shirts. The measurements of each size T-shirt form equivalent ratios.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 36
What is the length of an extra-large T-shirt?
Write two equivalent ratios and find the unknown value:
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 37
The length of an extra-large T-shirt is 36 inches.
Write a problem that can be solved by using the information in the table and could be solved by using equivalent ratios
Type below:
___________

Answer:
Small = 27/18 ÷ 18/18 = 1.5
Medium = 30/20 = 3/2 = 1.5
Large = 1.5/1 × 22/22 = 33/22
the length of an extra-large T-shirt = 1.5/1 × 24/24 = 36/24
What is the length of an large T-shirt?
Write two equivalent ratios and find the unknown value?
Large = 1.5/1 × 22/22 = 33/22
33/22 × 2/2 = 66/44
33/22 × 3/3 = 99/66

Question 14.
Peri earned $27 for walking her neighbor’s dog 3 times. If Peri earned $36, how many times did she walk her neighbor’s dog? Use a unit rate to find the unknown value.
_____ times

Answer:
4 times

Explanation:
Peri earned $27 for walking her neighbor’s dog 3 times.
If Peri earned $36, ($36 × 3)/$27 = 4

Use Unit Rates – Page No. 253

Use a unit rate to find the unknown value.

Question 1.
\(\frac{34}{7}=\frac{?}{7}\)
_____

Answer:
34

Explanation:
34/7 ÷ 7/7 = 4.8571/1
4.8571/1 × 7/7 = 34
The unknown value is 34

Question 2.
\(\frac{16}{32}=\frac{?}{14}\)
_____

Answer:
7

Explanation:
16/32 ÷ 32/32 = 0.5/1
0.5/1 × 14/14 = 7/1
The unknown value is 7

Question 3.
\(\frac{18}{?}=\frac{21}{7}\)
_____

Answer:
6

Explanation:
21/7 ÷ 7/7 = 3/1
3/1 × 6/6 = 18/6
The unknown value is 6

Question 4.
\(\frac{?}{16}=\frac{3}{12}\)
_____

Answer:
4

Explanation:
3/12 ÷ 12/12 = 0.25/1
0.25/1 × 16/16 = 4
The unknown value is 4

Draw a bar model to find the unknown value.

Question 5.
\(\frac{15}{45}=\frac{6}{?}\)
_____

Answer:
Grade 6 Chapter 4 image 32
18

Explanation:
15/45 ÷ 45/45 = 1/3
1/3 × 6/6 = 6/18
The unknown value is 18

Question 6.
\(\frac{3}{6}=\frac{?}{7}\)
_____

Answer:
Grade 6 Chapter 4 image 33
3.5

Explanation:
3/6 ÷ 6/6 = 1/2
1/2 × 3.5/3.5 = 3.5/7
The unknown value is 3.5

Problem Solving

Question 7.
To stay properly hydrated, a person should drink 32 fluid ounces of water for every 60 minutes of exercise. How much water should Damon drink if he rides his bike for 135 minutes?
_____ fluid ounces

Answer:
72 fluid ounces

Explanation:
To stay properly hydrated, a person should drink 32 fluid ounces of water for every 60 minutes of exercise.
If he rides his bike for 135 minutes, (135 × 32)/60 = 72

Question 8.
Lillianne made 6 out of every 10 baskets she attempted during basketball practice. If she attempted to make 25 baskets, how many did she make?
_____ baskets

Answer:
15 baskets

Explanation:
Lillianne made 6 out of every 10 baskets she attempted during basketball practice. If she attempted to make 25 baskets,
(25 × 6)/10 = 15 baskets

Question 9.
Give some examples of real-life situations in which you could use unit rates to solve an equivalent ratio problem.
Type below:
___________

Answer:
1) If a 10-ounce box of cereal costs $3 and a 20-ounce box of cereal costs $5, the 20 ounce box is the better value because each ounce of cereal is cheaper.
2) Yoda Soda is the intergalactic party drink that will have all your friends saying, “Mmmmmm, good this is!”
You are throwing a party, and you need 555 liters of Yoda Soda for every 121212 guests.
If you have 363636 guests, how many liters of Yoda Soda do you need?

Lesson Check – Page No. 254

Question 1.
Randi’s school requires that there are 2 adult chaperones for every 18 students when the students go on a field trip to the museum. If there are 99 students going to the museum, how many adult chaperones are needed?
_____ chaperones

Answer:
11 chaperones

Explanation:
Randi’s school requires that there are 2 adult chaperones for every 18 students when the students go on a field trip to the museum.
If there are 99 students going to the museum, (99 × 2)/18 = 11 chaperones

Question 2.
Landry’s neighbor pledged $5.00 for every 2 miles he swims in a charity swim-a-thon. If Landry swims 3 miles, how much money will his neighbor donate?
$ _____

Answer:
$7.5

Explanation:
Landry’s neighbor pledged $5.00 for every 2 miles he swims in a charity swim-a-thon. If Landry swims 3 miles, 15/2 = $7.5

Spiral Review

Question 3.
Describe a situation that could be represented by –8.
Type below:
___________

Answer:
In Alaska the normal temperature in December was 3 degrees. Scientist predicted that by February the temperature would drop 11 degrees. What is the predicted temperature for February? The answer is -8.

Question 4.
What are the coordinates of point G?
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 38
Type below:
___________

Answer:
(-2, 0.5)

Explanation:
The x-coordinate is -2
The y-coordinate is 0.5

Question 5.
Gina bought 6 containers of yogurt for $4. How many containers of yogurt could Gina buy for $12?
_____ containers

Answer:
18 containers

Explanation:
Gina bought 6 containers of yogurt for $4.
For $12, ($12 × 6)/$4 = 18

Question 6.
A bottle containing 64 fluid ounces of juice costs $3.84. What is the unit rate?
$ _____

Answer:
$0.06

Explanation:
A bottle containing 64 fluid ounces of juice costs $3.84.
$3.84/64 = $0.06

Share and Show – Page No. 257

A redwood tree grew at a rate of 4 feet per year. Use this information for 1–3.

Question 1.
Complete the table of equivalent ratios for the first 5 years.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 39
Type below:
___________

Answer:
Grade 6 Chapter 4 image 34

Explanation:
A redwood tree grew at a rate of 4 feet per year.
For 2 years, 2 × 4 = 8ft
For 3 years, 3 × 4 = 12ft
For 4 years, 4 × 4 = 16ft
For 5 years, 5 × 4 = 20ft

Question 2.
Write ordered pairs, letting the x-coordinate represent time in years and the y-coordinate represent height in feet.
Type below:
___________

Answer:
(1, 4), (2, 8), (3, 12), (4, 16), (5, 20)

Question 3.
Use the ordered pairs to graph the tree’s growth over time.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 35

On Your Own

The graph shows the rate at which Luis’s car uses gas, in miles per gallon. Use the graph for 4–8.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 40

Question 4.
Complete the table of equivalent ratios.
Type below:
___________

Answer:
30/1, 60/2, 90/3, 120/4, 150/5

Question 5.
Find the car’s unit rate of gas usage.
Type below:
___________

Answer:
30mi/gal

Question 6.
How far can the car go on 5 gallons of gas?
_____ miles

Answer:
150 miles

Explanation:
the car go on 5 gallons of gas, 150/5

Question 7.
Estimate the amount of gas needed to travel 50 miles.
Type below:
___________

Answer:
5/3

Explanation:
30/1,
50/30 = 5/3

Practice and Homework Lesson 4.8 Answer Key Question 8.
Ellen’s car averages 35 miles per gallon of gas. If you used equivalent ratios to graph her car’s gas usage, how would the graph differ from the graph of Luis’s car’s gas usage?
Type below:
___________

Answer:
Grade 6 Chapter 4 image 36
The distance is high for Ellen’s car’s gas usage compared to Luis’s car’s gas usage per one gal

Explanation:
35/1 × 2/2 = 70/2
35/1 × 3/3 = 105/3
35/1 × 4/4 = 140/4
35/1 × 5/5 = 175/5

Problem Solving + Applications – Page No. 258

Question 9.
Look for Structure The graph shows the depth of a submarine over time. Use equivalent ratios to find the number of minutes it will take the submarine to descend 1,600 feet.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 41
_____ minutes

Answer:
8 minutes

Explanation:
200/1 × 8/8 = 1600/8

Question 10.
The graph shows the distance that a plane flying at a steady rate travels over time. Use equivalent ratios to find how far the plane travels in 13 minutes.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 42
_____ miles

Answer:
91 miles

Explanation:
7/1 × 13/13 = 91/13

Question 11.
Sense or Nonsense? Emilio types at a rate of 84 words per minute. He claims that he can type a 500-word essay in 5 minutes. Is Emilio’s claim sense or nonsense? Use a graph to help explain your answer.
Type below:
___________

Answer:
He said that he can write 84 in 60sec ,500 words will be written in 500×60/84=357 it’s a nonsense

Question 12.
The Tuckers drive at a rate of 20 miles per hour through the mountains. Use the ordered pairs to graph the distance traveled over time.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 43
Type below:
___________

Answer:
Grade 6 Chapter 4 image 37

Equivalent Ratios and Graphs – Page No. 259

Christie makes bracelets. She uses 8 charms for each bracelet. Use this information for 1–3.

Question 1.
Complete the table of equivalent ratios for the first 5 bracelets.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 38

Explanation:

Question 2.
Write ordered pairs, letting the x-coordinate represent the number of bracelets and the y-coordinate represent the number of charms.
Type below:
___________

Answer:
(1, 8), (2, 16), (3, 24), (4, 32), (5, 40)

Question 3.
Use the ordered pairs to graph the charms and bracelets.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 39

The graph shows the number of granola bars that are in various numbers of boxes of Crunch N Go. Use the graph for 4–5.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 44

Question 4.
Complete the table of equivalent ratios.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 45
Type below:
___________

Answer:
Grade 6 Chapter 4 image 40

Question 5.
Find the unit rate of granola bars per box.
Type below:
___________

Answer:
10 bars/1 box

Problem Solving

Question 6.
Look at the graph for Christie’s Bracelets. How many charms are needed for 7 bracelets?
_____ charms

Answer:
56 charms

Question 7.
Look at the graph for Crunch N Go Granola Bars. Stefan needs to buy 90 granola bars. How many boxes must he buy?
_____ boxes

Answer:
9 boxes

Question 8.
Choose a real-life example of a unit rate. Draw a graph of the unit rate. Then explain how another person could use the graph to find the unit rate.
Type below:
___________

Answer:
Sam prepares 4 bracelets per month. How many bracelets does she prepare in a span of 6 months?
For 1 month, 1 × 4 = 4 bracelets
For 2 months, 2 × 4 = 8 bracelets
For 3 months, 3 × 4 = 12 bracelets
For 4 months, 4 × 4 = 16 bracelets
For 5 months, 5 × 4 = 20 bracelets

Lesson Check – Page No. 260

Question 1.
A graph shows the distance a car traveled over time. The x-axis represents time in hours, and the y-axis represents distance in miles. The graph contains the point (3, 165). What does this point represent?
Type below:
___________

Answer:

Explanation:
In 3 hours the car traveled 165 miles.
(3,165) is (x,y) so 3 = x and 165 = y, and
3=x=time in hours
165=y= miles…. soooo
In 3 hours the car traveled 165 miles

Question 2.
Maura charges $11 per hour to babysit. She makes a graph comparing the amount she charges (the y-coordinate) to the time she babysits (the x-coordinate). Which ordered pair shown is NOT on the graph?
(4, 44) (11, 1) (1, 11) (11, 12)
Type below:
___________

Answer:
(11, 1)

Explanation:
It is not 11,1 because she charges 11 hours per hour (y coordinate) and x would be time to babysit. so it can’t be 11,1

Spiral Review

Question 3.
List 0, –4, and 3 from least to greatest.
Type below:
___________

Answer:
-4, 0, 3

Question 4.
What two numbers can be used in place of the ? to make the statement true?
|?| = \(\frac{8}{9}\)
Type below:
___________

Answer:
–\(\frac{8}{9}\), \(\frac{8}{9}\)

Explanation:
|-\(\frac{8}{9}\)| = \(\frac{8}{9}\)
|\(\frac{8}{9}\)| = \(\frac{8}{9}\)

Question 5.
Morgan plots the point (4, –7) on a coordinate plane. If she reflects the point across the y-axis, what are the coordinates of the reflected point?
Type below:
___________

Answer:
(-4, -7)

Explanation:
Morgan plots the point (4, –7) on a coordinate plane. If she reflects the point across the y-axis, it will be (-4, -7)

Question 6.
Jonathan drove 220 miles in 4 hours. Assuming he drives at the same rate, how far will he travel in 7 hours?
_____ miles

Answer:
385 miles

Explanation:
Jonathan drove 220 miles in 4 hours.
If he travel in 7 hours, (7 × 220)/4 = 385 miles

Chapter 4 Review/Test – Page No. 261

Question 1.
Kendra has 4 necklaces, 7 bracelets, and 5 rings. Draw a model to show the ratio that compares rings to bracelets
Type below:___________

Answer:
Grade 6 Chapter 4 image 41

Question 2.
There are 3 girls and 2 boys taking swimming lessons. Write the ratio that compares the girls taking swimming lessons to the total number of students taking swimming lessons.
Type below:
___________

Answer:
3 : 5

Explanation:
There are 3 girls and 2 boys taking swimming lessons.
the total number of students taking swimming lessons = 5
3 : 5

Question 3.
Luis adds 3 strawberries for every 2 blueberries in his fruit smoothie. Draw a model to show the ratio that compares strawberries to blueberries.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 42

Question 4.
Write the ratio 3 to 10 in two different ways.
Type below:
___________

Answer:
3/10, 3 : 10

Question 5.
Alex takes 3 steps every 5 feet he walks. As Alex continues walking, he takes more steps and walks a longer distance. Complete the table by writing two equivalent ratios.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 46
Type below:
___________

Answer:
Grade 6 Chapter 4 image 43

Explanation:
Alex takes 3 steps every 5 feet he walks. As Alex continues walking, he takes more steps and walks a longer distance.
3/5 × 2/2 = 6/10
3/5 × 3/3 = 9/15

Page No. 262

Question 6.
Sam has 3 green apples and 4 red apples. Select the ratios that compare the number of red apples to the total number of apples. Mark all that apply.
Options:
a. 4 to 7
b. 3 to 7
c. 4 : 7
d. 4 : 3
e. \(\frac{3}{7}\)
f. \(\frac{4}{7}\)

Answer:
a. 4 to 7
c. 4 : 7
f. \(\frac{4}{7}\)

Explanation:
Sam has 3 green apples and 4 red apples.
the total number of apples = 3 + 4 = 7
4 : 7

Question 7.
Jeff ran 2 miles in 12 minutes. Ju Chan ran 3 miles in 18 minutes. Did Jeff and Ju Chan run the same number of miles per minute? Complete the tables of equivalent ratios to support your answer.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 47
Type below:
___________

Answer:
Grade 6 Chapter 4 image 44

Explanation:
2/12 × 2/2 = 4/24
2/12 × 3/3 = 6/39
2/12 × 4/4 = 8/48
3/18 × 2/2 = 6/36
3/18 × 3/3 = 9/24
3/18 × 4/4 = 12/72

Question 8.
Jen bought 2 notebooks for $10. Write the rate as a fraction. Then find the unit rate.
Type below:
___________

Answer:
$10/2
unit rate = $5

Explanation:
Jen bought 2 notebooks for $10.
$10/2 ÷ 2/2 = $5

Page No. 263

Question 9.
Determine whether each ratio is equivalent to \(\frac{1}{2}, \frac{2}{3}, \text { or } \frac{4}{7}\). Write the ratio in the correct box.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 48
Type below:
___________

Answer:
Grade 6 Chapter 4 image 45

Explanation:
1/2 × 2/2 = 4/8
7/14 ÷ 2/2 = 1/2
20/35 ÷ 5/5 = 4/7
40/80 ÷ 40/40 = 1/2
8/14 ÷ 2/2 = 4/7
4/6 ÷ 2/2 = 2/3
8/12 ÷ 4/4 = 2/3

Question 10.
Amos bought 5 cantaloupes for $8. How many cantaloupes can he buy for $24? Show your work.
_____ cantaloupes

Answer:
15 cantaloupes

Explanation:
Amos bought 5 cantaloupes for $8.
For $24, ($24 × 5)/$8 = 15

Question 11.
Camille said \(\frac{4}{5}\) is equivalent to \(\frac{24}{30}\). Check her work by making a table of equivalent ratios.
Type below:
___________

Answer:
Grade 6 Chapter 4 image 46

Question 12.
A box of oat cereal costs $3.90 for 15 ounces. A box of rice cereal costs $3.30 for 11 ounces. Which box of cereal costs less per ounce? Use numbers and words to explain your answer.
Type below:
___________

Answer:
A box of oat cereal costs $3.90 for 15 ounces.
$3.90/15 = $0.26
A box of rice cereal costs $3.30 for 11 ounces.
$3.30/11 = $0.3
$0.26 < $0.3

Page No. 264

Question 13.
Scotty earns $35 for babysitting for 5 hours. If Scotty charges the same rate, how many hours will it take him to earn $42?
_____ hours

Answer:
6 hours

Explanation:
Scotty earns $35 for babysitting for 5 hours
For $42, (42 × 5)/35 = 6

Question 14.
Use a unit rate to find the unknown value.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 49
Type below:
___________

Answer:
Grade 6 Chapter 4 image 47

Explanation:
(9 × 42)/14 = 3

Question 15.
Jenna saves $3 for every $13 she earns. Vanessa saves $6 for every $16 she earns. Is Jenna’s ratio of money saved to money earned equivalent to Vanessa’s ratio of money saved to money earned?
Type below:
___________

Answer:
No, 3/13 = 6/26. Vanessa ratio is 6/16

Question 16.
The Hendersons are on their way to a national park. They are traveling at a rate of 40 miles per hour. Use the ordered pairs to graph the distance traveled over time
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 50
Type below:
___________

Answer:
Grade 6 Chapter 4 image 48

Page No. 265

Question 17.
Abby goes to the pool to swim laps. The graph shows how far Abby swam over time. Use equivalent ratios to find how far Abby swam in 7 minutes
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 51
_____ meters

Answer:
350 meters

Explanation:
50/1 × 7/7 = 350/7

Question 18.
Caleb bought 6 packs of pencils for $12.
Part A
How much will he pay for 9 packs of pencils? Use numbers and words to explain your answer
$ _____

Answer:
$18

Explanation:
Caleb bought 6 packs of pencils for $12.
6/12 = 1/2 × 9/9 = 9/18
So, $18 is the answer

Question 18.
Part B
Describe how to use a bar model to solve the problem.
Type below:
___________

Answer:
Take the known ratio and identify the unknown value using known ratio.

Page No. 266

Question 19.
A rabbit runs 35 miles per hour. Select the animals who run at a faster unit rate per hour than the rabbit. Mark all that apply.
Options:
a. Reindeer: 100 miles in 2 hours
b. Ostrich: 80 miles in 2 hours
c. Zebra: 90 miles in 3 hours
d. Squirrel: 36 miles in 3 hours

Answer:
a. Reindeer: 100 miles in 2 hours
b. Ostrich: 80 miles in 2 hours

Explanation:
A rabbit runs 35 miles per hour.
35/1
100/2 = 50/1
80/2 = 40/1
90/3 = 30/1
36/3 = 12/1

Question 20.
Water is filling a bathtub at a rate of 3 gallons per minute.
Part A
Complete the table of equivalent ratios for the first five minutes of the bathtub filling up.
Go Math Grade 6 Answer Key Chapter 4 Model Ratios 52
Type below:
___________

Answer:
Grade 6 Chapter 4 image 50

Question 20.
Part B
Emily said there will be 36 gallons of water in the bathtub after 12 minutes. Explain how Emily could have found her answer
Type below:
___________

Answer:
Emily said there will be 36 gallons of water in the bathtub after 12 minutes.
36/12 ÷ 12/12 = 3/1
She can find the answer using the unit rate.

Conclusion:

Go Math Grade 6 Answer Key Chapter 4 Model Ratios questions, answers, and explanations, all together comes with a single package here. You don’t need to pay anything for any question. Just follow and refer Go Math Grade 6 Chapter 4 Model Ratios Solution Key and begin your practice now. The best practice will come with the Go Math Grade 6 Answer Key.

Go Math Grade 6 Answer Key Chapter 4 Model Ratios Read More »

go-math-grade-8-answer-key-chapter-14-scatter-plots

Go Math Grade 8 Answer Key Chapter 14 Scatter Plots

A great selection will give you a happy ending. Such best selection to learn maths is Go Math Grade 8 Answer Key Chapter 14 Scatter Plots. Yes. Go Math Grade 8 Chapter 14 Scatter Plots Answer Key is the only choice for students who wants the easy and best learning of maths. To help every student to practice maths, we provided questions and answers along with the explanation in an easy way. Therefore, start practicing the maths with the help of Go Math Grade 8 Answer Key.

Go Math Grade 8 Answer Key Chapter 14 Scatter Plots

It is an open place to learn maths. You need not pay anything to anyone to learn maths. We are offering a free PDF of Go Math Grade 8 Answer Key Chapter 14 Scatter Plots. So, students can learn offline with the help of Go Math Grade 8 Chapter 14 Scatter Plots Answer Key if they want. Or else, it is also easy to learn maths with the HMH Go Math guide. What are you waiting for? Immediately start practicing maths now using GO Math Grade 8 Answer Key.

Lesson 1: Scatter Plots and Association

Lesson 2: Trend Lines and Predictions

Model Quiz

Mixed Review

Guided Practice – Scatter Plots and Association – Page No. 436

Bob recorded his height at different ages. The table below shows his data.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 1: Scatter Plots and Association img 1

Question 1.
Make a scatter plot of Bob’s data.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 1: Scatter Plots and Association img 2
Type below:
_____________

Answer:
grade 8 chapter 14 image 1

Explanation:
As Bob gets older, his height increases along with the straight line on the
graph. So, the association is positive and linear.

Scatter Plots and Data Analysis Answer Key Question 2.
Describe the association between Bob’s age and his height. Explain the association.
Type below:
_____________

Answer:
The association is positive and linear. Bob’s height increases as he gets older. We would see that Bob’s height eventually stops increasing if the data continues.

Question 3.
The scatter plot shows the basketball shooting results for 14 players. Describe any clusters you see in the scatter plot. Identify any outliers.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 1: Scatter Plots and Association img 3
Type below:
_____________

Answer:
There is an outlier at (35,18)

Explanation:
There is a cluster in the “20 – 25” shots attempted range and a smaller cluster in the “5 – 14” shots attempted range.
There is an outlier at (35,18)

ESSENTIAL QUESTION CHECK-IN

Question 4.
Explain how you can make a scatter plot from a set of bivariate data.
Type below:
_____________

Answer:
Bivariate data – data that has two variables per observation,
An x variable and y variable.
Scatterplot – The graph displaying categorical data, with an x and y-axis.
Response Variable – the variable that is explained by the other.
Explanatory Variable – the variable which explains the other.

14.1 Independent Practice – Scatter Plots and Association – Page No. 437

Sports Use the scatter plot for 5–8.

Olympic Men’s Long Jump Winning Distances
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 1: Scatter Plots and Association img 4

Question 5.
Describe the association between the year and the distance jumped for the years 1960 to 1988.
Type below:
_____________

Answer:
The data shows a positive linear association. If the year increases, the winning distance increases.

Question 6.
Describe the association between the year and the distance jumped for the years after 1988.
Type below:
_____________

Answer:
Between 1996 and 2004, there was a slight increase in distance over time. The data from 1988 to 2012 will show a negative association.

Question 7.
For the entire scatter plot, is the association between the year and the distance jumped linear or nonlinear?
_____________

Answer:
The data show a rise between 1960 and 1988. The data also show a fall between 1988 and 2012. Therefore, overall, there is no linear pattern.

Scatter Plots and Data Unit Test Answer Key Question 8.
Identify the outlier and interpret its meaning.
Type below:
_____________

Answer:
The outlier is at (1968, 8.9). It represents a long jump of 8.9 meters in 1968 that exceeds the other jumps made in the surrounding years.

Question 9.
Communicate Mathematical Ideas Compare a scatter plot that shows no association to one that shows a negative association.
Type below:
_____________

Answer:
Randomly scattered data points with no apparent pattern define a scatter plot with no association. Data points that fall from left to right and has data set values that increase as the other decreases define a scatter plot with a negative association.

Scatter Plots and Association – Page No. 438

For 10–11, describe a set of real-world bivariate data that the given scatter plot could represent. Define the variable represented on each axis.

Question 10.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 1: Scatter Plots and Association img 5
_____________

Answer:
The x-axis represents the number of containers. The y-&is represents the price per container.

Unit Scatter Plots and Data Homework 4 Problem Solving with Trend Lines Question 11.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 1: Scatter Plots and Association img 6
_____________

Answer:
The x-axis represents the number of hours spent watching tv. The y-axis represents the number of TVs owned.

FOCUS ON HIGHER ORDER THINKING

Question 12.
Multiple Representations Describe what you might see in a table of bivariate data that would lead you to conclude that the scatter plot of the data would show a cluster.
Type below:
_____________

Answer:
A cluster in a scatter plot is when there are a lot of points all grouped around the same location.
Look for points that have the same input and output values. If there are a lot of points together, you must have a cluster in your scatter plot.

Question 13.
Justify Reasoning Is it possible for a scatter plot to have a positive or negative association that is not linear? Explain.
Type below:
_____________

Answer:
Yes

Explanation:
Yes; it is possible for a scatter plot to have a positive or negative association that is not linear. The data points may have a falling or rising curve that will exhibit a nonlinear association.

Question 14.
Critical Thinking To try to increase profits, a theater owner increases the price of a ticket by $25 every month. Describe what a scatter plot might look like if x represents the number of months and y represents the profits. Explain your reasoning.
Type below:
_____________

Answer:
Initially, the number of tickets sold might decline a little, but the price increase would offset the loss in sales. That means that profits would increase, showing a positive association. When the price would get too high, ticket sales would decline rapidly, so profits would fall giving a negative association.

Guided Practice – Trend Lines and Predictions – Page No. 442

Angela recorded the price of different weights of several bulk grains. She made a scatter plot of her data. Use the scatter plot for 1–4.

Question 1.
Draw a trend line for the scatter plot.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 2: Trend Lines and Predictions img 7
Type below:
_____________

Answer:
grade 8 chapter 14 image 2

Question 2.
How do you know whether your trend line is a good fit for the data?
Type below:
_____________

Answer:
Most of the data points are close to the trend line. The trend line has about the same number of points above and below it.

Scatter Plots and Trend Lines Quiz 1 Answer Key Question 3.
Write an equation for your trend line.
Type below:
_____________

Answer:
y = 0.09x

Explanation:
The trend line passes through (0, 0) and (19, 1.80).
Find the slope by using the slope formula.
slope = m = (y2 – y1)/(x2 – x1) = 1.80/19 = 0.09
The line passes through the origin. So, the y-intercept is 0.
From an equation for the trend line substituting the slope value for m and the value of the y-intercept b in the slope-intercept formula.
y = mx + b
y = 0.09x + 0
y = 0.09x

Question 4.
Use the equation for your trend line to interpolate the price of 7 ounces and extrapolate the price of 50 ounces.
Type below:
_____________

Answer:
The price for 7 and 50 ounces is $0.63 and $4.50

Explanation:
Use the equation for the trend line (y = 0.09x) to interpolate the price of 7 ounces by substituting 7 for x (y= 0.09 • 7) and solving for y.
Use the equation for the trend line (y = 0.09x) to interpolate the price of 50 ounces by substituting 50 for x (y= 0.09 • 50) and solving for y.

ESSENTIAL QUESTION CHECK-IN

Question 5.
A trend line passes through two points on a scatter plot. How can you use the trend line to make a prediction between or outside the given data points?
Type below:
_____________

Answer:
Use two points on the line. rind the slope and y-intercept. Substitute the values of the slope (m) and y-intercept (b) to form an equation using y = mx + b. Substitute the value of x for which you want to make a prediction and solve for y OR substitute your prediction for y and solve to find its value.

14.2 Independent Practice – Trend Lines and Predictions – Page No. 443

Use the data in the table for Exercises 6–10.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 2: Trend Lines and Predictions img 8

Question 6.
Make a scatter plot of the data and draw a trend line.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 2: Trend Lines and Predictions img 9
Type below:
_____________

Answer:
grade 8 chapter 14 image 3

Question 7.
What type of association does the trend line show?
Type below:
_____________

Answer:
Negative Association

Explanation:
One data set increases – Wind Speed and the other – Wind Chill decreases. So, the trend line shows a Negative Association.

Scatter Plots and Trend Lines Answer Key Question 8.
Write an equation for your trend line.
Type below:
_____________

Answer:
y = -0.25x + 2.5

Explanation:
Find the slope using the Slope Formula
m = (y2 – y1)/(x2 – x1) = ((-10) – 5)/(50 – 30) = -5/20 = -0.25
Find the y-intercept using the Slope-Intercept Formula
y = mx + b
-5 = -0.25(30) + b
-5 = -7.5 + b
2.5 = b
Substitute the value of m and b into the Slope-Intercept Formula to form an equation for the trend line.
y = -0.25x + 2.5

Question 9.
Make a Prediction Use the trend line to predict the wind chill at these wind speeds.
a. 36 mi/h
_________ °F

Answer:
-6.5°F

Explanation:
Use the trend line to predict the wind chill at 36mi/h
y = -0.25x + 2.5
y = -0.25(36) + 2.5
y = -9 + 2.5
y = -6.5
The wind chill at 36mi/h is -6.5ºF

Question 9.
b. 100 mi/h
_________ °F

Answer:
-22.5°F

Explanation:
Use the trend line to predict the wind chill at 100mi/h
y = -0.25x + 2.5
y = -0.25(100) + 2.5
y = -25 + 2.5
y = -22.5
The wind chill at 100mi/h is -22.5ºF

Question 10.
What is the meaning of the slope of the line?
Type below:
_____________

Answer:
The slope means that the wind chill falls about 1°F for every 4 mph increase in wind speed.

Use the data in the table for Exercises 11–14.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 2: Trend Lines and Predictions img 10

Question 11.
Make a scatter plot of the data and draw a trend line.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Lesson 2: Trend Lines and Predictions img 11
Type below:
_____________

Answer:
grade 8 chapter 14 image 4

Problem Solving with Trend Lines Worksheet Answers Question 12.
Write an equation for your trend line.
Type below:
_____________

Answer:
y = -(2/15)x + 64

Explanation:
Find the slope using the Slope Formula
m = (y2 – y1)/(x2 – x1) = (72 – 64)/(60 – 0) = 8/60 = -2/15
Find the y-intercept using the Slope-Intercept Formula at (0, 64)
y = mx + b
b = 64
Substitute the value of m and b into the Slope-Intercept Formula to form an equation for the trend line.
y = -2/15x + 64

Question 13.
Make a Prediction Use the trend line to predict the apparent temperature at 70% humidity.
Type below:
_____________

Answer:
73.3º F

Explanation:
Use the equation of the trend line. Substitute 70(for 70%) into the equation for x.
y = -(2/15)x + 64
y = -(2/15)(70) + 64
y = -140/15 + 64
y = -9.3 + 64
y = 73.3
The apparent temperature is 73.3º F

Question 14.
What is the meaning of the y-intercept of the line?
Type below:
_____________

Answer:
The y-intercept explains that at 0% humidity, the apparent temperature is 64ºF

FOCUS ON HIGHER ORDER THINKING – Trend Lines and Predictions – Page No. 444

Question 15.
Communicate Mathematical Ideas Is it possible to draw a trend line on a scatter plot that shows no association? Explain.
_____________

Answer:
No

Explanation:
It is not possible to draw a trend line on a scatter plot that shows no association. If the scatter plot shows no association, the data points have no relationships with one another. You can draw a trend line if a linear association is available.

Question 16.
Critique Reasoning Sam drew a trend line that had about the same number of data points above it as below it, but did not pass through any data points. He then picked two data points to write the equation for the line. Is this a correct way to write the equation? Explain.
_____________

Answer:
No

Explanation:
Sam did not use the correct way to write an equation.
Sam may have drawn a correct trend line but using the data points that are not on the trend line may have an incorrect equation for the line. He should use two points on that trend line to write the equation.

Problem Solving with Trend Lines Homework 4 Answer Key Question 17.
Marlene wanted to find a relationship between the areas and populations of counties in Texas. She plotted x (area in square miles) and y (population) for two counties on a scatter plot:
Kent County (903, 808)                                Edwards County (2118, 2002)
She concluded that the population of Texas counties is approximately equal to their area in square miles and drew a trend line through her points.
a. Critique Reasoning Do you agree with Marlene’s method of creating a scatter plot and a trend line? Explain why or why not.
_____________

Answer:
I do not agree with Marlene’s method of creating a scatter plot and a trend line. She did not have enough data. Marlene should have collected and plotted data for many more counties.

Question 17.
b. Counterexamples Harris County has an area of 1778 square miles and a population of about 4.3 million people. Dallas County has an area of 908 square miles and a population of about 2.5 million people. What does this data show about Marlene’s conjecture that the population of Texas counties is approximately equal to their area?
Type below:
_____________

Answer:
The data collected are only of two counties whose populations are nearly equal to their area. The fact that the populations of Harris and Dallas counties are in the millions, Marlene’s conjecture about the population of Texas counties being equivalent to their area is invalid.

Ready to Go On? – Model Quiz – Page No. 445

14.1 Scatter Plots and Association

An auto store is having a sale on motor oil. The chart shows the price per quart as the number of quarts purchased increases. Use the data for Exs. 1–2.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Model Quiz img 12

Question 1.
Use the given data to make a scatter plot.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Model Quiz img 13
Type below:
_____________

Answer:
grade 8 chapter 14 image 5

Unit Scatter Plots and Data Homework 1 Answer Key Question 2.
Describe the association you see between the number of quarts purchased and the price per quart. Explain.
Type below:
_____________

Answer:
Negative nonlinear association

Explanation:
The association seen between the number of quarts purchased and the price per quart is negative and nonlinear. As the number of quarts rises, the price per quart decreases but you can see a data curve.

14.2 Trend Lines and Predictions

The scatter plot below shows data comparing wind speed and wind chill for an air temperature of 20 °F. Use the scatter plot for Exs. 3–5.

Question 3.
Draw a trend line for the scatter plot.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Model Quiz img 14
Type below:
_____________

Answer:
grade 8 chapter 14 image 6

Question 4.
Write an equation for your trend line.
Type below:
_____________

Answer:
y = -0.35x + 12.25

Explanation:
The line passes through (10, 8.75) and (35, 0) so we can use these points to find the slope.
The slope of the line is :
Slope = m = (y2 – y1)/(x2 – x1) = (0 – 8.75)/(35 – 10) = -8.75/25 = -0.35
Find the y-intercept using the slope-intercept formula :
y = mx + b
0 = -0.35 . 35 + b
0 = -12.25 + b
b = 12.25
Substitute the slope m and the y-intercept b in the slope-intercept formula.
The equation for the trend line is :
y = mx + b
y = -0.35x + 12.25

Problem-Solving with Trend Lines Homework 4 Answers Question 5.
Use your equation to predict the wind chill to the nearest degree for a wind speed of 60 mi/h.
________ °F

Answer:
9°F

Explanation:
y = −0.35x + 12.25
y = -0.35(60) + 12.25
y = -21 + 12.25
y = -8.75
The wind chill to the nearest degree for a wind speed of 60 mi/h is 9°F.

ESSENTIAL QUESTION

Question 6.
How can you use scatter plots to solve real-world problems?
Type below:
_____________

Answer:
Using a scatter plot, you can see positive and negative trends such as prices over time. You can also make predictions such as height at a certain age.

Selected Response – Mixed Review – Page No. 446

Question 1.
Which scatter plot could have a trend line whose equation is y = 3x + 10?
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Mixed Review img 15
Options:
a. A
b. B
c. C
d. D

Answer:
b. B

Question 2.
What type of association would you expect between a person’s age and hair length?
Options:
a. linear
b. negative
c. none
d. positive

Answer:
c. none

Explanation:
The length of their hair reduces. This is because the length of hair changes with the growth phase of the hair follicles. When one is young, the cells of the papilla divide more rapidly, and hence the length of the hair is long before reaching the transitional phase and then shedding off in the telogen phase. The older one gets, the papilla cells do not divide as rapidly and the length of the hair shortens with age.

Question 3.
Which is not shown on the scatter plot?
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Mixed Review img 16
Options:
a. cluster
b. negative association
c. outlier
d. positive association

Answer:
d. positive association

Explanation:
The scatter plot shows a cluster, some outliers, and a negative association.
It does not show a positive association.

Unit Scatter Plots and Data Homework 3 Answer Key Question 4.
A restaurant claims to have served 352,000,000 hamburgers. What is this number in scientific notation?
Options:
a. 3.52 × 106
b. 3.52 × 108
c. 35.2 × 107
d. 352 × 106

Answer:
b. 3.52 × 108

Explanation:
100,000,000
So, 3.52 × 108

Question 5.
Which equation describes the relationship between x and y in the table?
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Mixed Review img 17
Options:
a. y = −4x
b. y = −\(\frac{1}{4}\)x
c. y = 4x
d. y = \(\frac{1}{4}\)x

Answer:
b. y = −\(\frac{1}{4}\)x

Explanation:
In order to find out the relationship between x and y, we have to use the values in the question and substitute them into the solution options.
So, y = -1/4x

Mini-Task

Question 6.
Use the data in the table.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Mixed Review img 18
a. Make a scatterplot of the data.
Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Mixed Review img 19
Type below:
______________

Answer:
grade 8 chapter 14 image 7

Question 6.
b. Which data point is an outlier?
Type below:
______________

Answer:
The outlier is the point (92, 135).

Question 6.
c. Predict the number of visitors on a day when the high temperature is 102 °F.
Type below:
______________

Answer:
Based on the cluster around 100°F, I would expect that on a day with a temperature of 102 °F, the pool would have between 350 and 400 visitors.

Conclusion:

Go Math Grade 8 Answer Key Chapter 14 Scatter Plots for free. Get your copy and start practicing now. Become a member of learning maths in the best and easy way with the help of the Go Math Grade 8 Chapter 14 Scatter Plots Answer Key. Enjoy learning maths with the help of the HMH Go Maths Grade 8 Solution Key.

Go Math Grade 8 Answer Key Chapter 14 Scatter Plots Read More »

go-math-grade-8-answer-key-chapter-10-transformations-and-similarity

Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity

Be the first person to grab Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity to score good marks in the exam. Many students have loved the way of explanation given on Go Math Grade 8 Answer Key on our website. If you want to learn the best way of solving maths, students can immediately start their practice with the help of the Go Math Grade 8 Chapter 10 Transformations and Similarity Answer Key.

Go Math Grade 8 Chapter 10 Transformations and Similarity Answer Key

The best learning comes with the best learning guide. So, to have the best online maths practice, follow the questions, answers, and explanations available on Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity. Download Go Math Grade 8 Chapter 10 Transformations and Similarity Answer Key PDF and begin your practice. The students can easily learn maths with the Go Math Grade 8 Solution Key.

Lesson 1: Properties of Dilations

Lesson 2: Algebraic Representations of Dilations

Lesson 3: Similar Figures

Model Quiz

Mixed Review

Guided Practice – Properties of Dilations – Page No. 318

Use triangles ABC and A′B′C ′ for 1–5.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 1: Properties of Dilations img 1

Question 1.
For each pair of corresponding vertices, find the ratio of the x-coordinates and the ratio of the y-coordinates.
ratio of x-coordinates = _______
ratio of y-coordinates = _______
ratio of x-coordinates = ____________
ratio of y-coordinates = ____________

Answer:
ratio of x-coordinates = 2
ratio of y-coordinates = 2

Explanation:
A’ = (-4, 4), A = (-2, 2);
ratio of x-coordinates = -4/-2 = 2
ratio of y-coordinates = 4/2 = 2
B’ = (4, 2), B = (2, 1);
ratio of x-coordinates = 4/2 = 2
ratio of y-coordinates = 2/1 = 2
C’ = (-2, -4), C = (-1, -2);
ratio of x-coordinates = -2/-1 = 2
ratio of y-coordinates = -4/-2 = 2

Question 2.
I know that triangle A′B′C ′ is a dilation of triangle ABC because the ratios of the corresponding x-coordinates are _______ and the ratios of the corresponding y-coordinates are _______.
Type below:
_____________

Answer:
I know that triangle A′B′C ′ is a dilation of triangle ABC because the ratios of the corresponding x-coordinates are equal and the ratios of the corresponding y-coordinates are equal.

Question 3.
The ratio of the lengths of the corresponding sides of triangle A′B′C ′ and triangle ABC equals _______.
________

Answer:
The ratio of the lengths of the corresponding sides of triangle A′B′C ′ and triangle ABC equals 2.

Properties of Dilations Answer Key Question 4.
The corresponding angles of triangle ABC and triangle A′B′C ′ are _______.
Type below:
_____________

Answer:
The corresponding angles of triangle ABC and triangle A′B′C ′ are congruent.

Question 5.
The scale factor of the dilation is _______.
________

Answer:
The scale factor of the dilation is 2.

ESSENTIAL QUESTION CHECK-IN

Question 6.
How can you find the scale factor of a dilation?
Type below:
_____________

Answer:
Divide a side length of the dilated figure by the corresponding side length of the original figure.

10.1 Independent Practice – Properties of Dilations – Page No. 319

For 7–11, tell whether one figure is a dilation of the other or not. Explain your reasoning.

Question 7.
Quadrilateral MNPQ has side lengths of 15 mm, 24 mm, 21 mm, and 18 mm. Quadrilateral M′N′P′Q′ has side lengths of 5 mm, 8 mm, 7 mm, and 4 mm.
_____________

Answer:
MNPQ is not a dilation of M′N′P′Q′

Explanation:
15/5 = 3 mm
24/8 = 3 mm
21/7 = 3 mm
18/4 = 4.5 mm
The ratios of the lengths of the corresponding sides are not equal.
Therefore, MNPQ is not a dilation of M′N′P′Q′

Question 8.
Triangle RST has angles measuring 38° and 75°. Triangle R′S′T ′ has angles measuring 67° and 38°. The sides are proportional.
_____________

Answer:
Yes

Explanation:
Both Triangle S have Angle S of measures 38°, 67° and 75°. So, the corresponding ∠S are congruent.

Question 9.
Two triangles, Triangle 1 and Triangle 2, are similar.
_____________

Answer:
Yes

Explanation:
a dilation produces an image similar to the original figure

Question 10.
Quadrilateral MNPQ is the same shape but a different size than quadrilateral M′N′P′Q.
_____________

Answer:
Yes

Explanation:
The figures are similar is they are the same shape but different size SO one is a dilation of the other

Question 11.
On a coordinate plane, triangle UVW has coordinates U(20, −12), V(8, 6), and W(−24, -4). Triangle U′V′W′ has coordinates U′(15, −9), V′(6, 4.5), and W′(−18, -3).
_____________

Answer:
Yes

Explanation:
Each coordinate of Triangle U′V′W′ is 3/4 times the corresponding coordinate of Triangle UVW.
So, the scale factor of the dilation is 3/4.

Complete the table by writing “same” or “changed” to compare the image with the original figure in the given transformation.

Question 12.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 1: Properties of Dilations img 2
Type below:
_____________

Answer:
grade 8 chapter 10 image 1

Question 16.
Describe the image of a dilation with a scale factor of 1.
_____________

Answer:
The image is congruent to the original figure

Properties of Dilations – Page No. 320

Identify the scale factor used in each dilation.

Question 17.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 1: Properties of Dilations img 3
________

Answer:
3

Explanation:
A’B’/AB = 6/2 = 3
B’D’/BD = 6/2 = 3
scale factor = 3

Question 18.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 1: Properties of Dilations img 4
\(\frac{□}{□}\)

Answer:
\(\frac{1}{2}\)

Explanation:
A’B’/AB = 2/4 = 1/2
scale factor = 1/2

FOCUS ON HIGHER ORDER THINKING

Question 19.
Critical Thinking Explain how you can find the center of dilation of a triangle and its dilation.
Type below:
_____________

Answer:
If you draw a line connecting each pair of corresponding vertices, the lines will intersect at the center of dilation

Dilations and Similarity Answer Key Question 20.
Make a Conjecture
a. A square on the coordinate plane has vertices at (−2, 2), (2, 2), (2, −2), and (−2, −2). A dilation of the square has vertices at (−4, 4), (4, 4), (4, −4), and (−4, −4). Find the scale factor and the perimeter of each square.
Scale factor: _________
Original perimeter: _________
Image perimeter: _________

Answer:
Scale factor: 2
Original perimeter: 16
Image perimeter: 32

Explanation:
-4/-2 =2; 4/2 = 2
Scale factor = 2
perimeter of the original square = 4 + 4 + 4 + 4 = 16
perimeter of the image = 8 + 8 + 8 + 8 = 32

Question 20.
b. A square on the coordinate plane has vertices at (−3, 3), (3, 3), (3, −3), and (−3, −3). A dilation of the square has vertices at (−6, 6), (6, 6), (6, −6), and (−6, −6). Find the scale factor and the perimeter of each square.
Scale factor: _________
Original perimeter: _________
Image perimeter: _________

Answer:
Scale factor: 2
Original perimeter: 24
Image perimeter: 48

Explanation:
-6/-3 =2; 6/3 = 2
Scale factor = 2
perimeter of the original square = 6 + 6 + 6 + 6 = 24
perimeter of the image = 12 + 12 + 12 + 12 = 48

Question 20.
c. Make a conjecture about the relationship of the scale factor to the perimeter of a square and its image.
Type below:
_____________

Answer:
The perimeter of the image is the perimeter of the original figure times the scale factor

Guided Practice – Algebraic Representations of Dilations – Page No. 324

Question 1.
The grid shows a diamond-shaped preimage. Write the coordinates of the vertices of the preimage in the first column of the table. Then apply the dilation (x, y) → (\(\frac{3}{2}\)x, \(\frac{3}{2}\)y) and write the coordinates of the vertices of the image in the second column. Sketch the image of the figure after the dilation.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 2: Algebraic Representations of Dilations img 5
Type below:
_____________

Answer:
grade 8 chapter 10 image 2

Graph the image of each figure after a dilation with the origin as its center and the given scale factor. Then write an algebraic rule to describe the dilation.

Question 2.
scale factor of 1.5
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 2: Algebraic Representations of Dilations img 6
Type below:
_____________

Answer:
(x, y) -> (1.5x, 1.5y)

Explanation:
After dilation
F’ (3, 3)
G’ (7.5, 3)
H’ (7.5, 6)
I’ (3, 6)
algebraic rule: (x, y) -> (1.5x, 1.5y)

Algebraic Representations of Dilations Lesson 10.2 Answers Question 3.
scale factor of \(\frac{1}{3}\)
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 2: Algebraic Representations of Dilations img 7
Type below:
_____________

Answer:
(x, y) -> (1/3x, 1/3y)

Explanation:
After dilation
A’ (3, 3)
B’ (7.5, 3)
C’ (7.5, 6)
algebraic rule: (x, y) -> (1/3x, 1/3y)

ESSENTIAL QUESTION CHECK-IN

Question 4.
A dilation of (x, y) → (kx, ky) when 0 < k < 1 has what effect on the figure? What is the effect on the figure when k > 1?
Type below:
_____________

Answer:
When k is between 0 and 1, the dilation is a reduction by the scale factor k.
When k is greater than 1, the dilation is an enlargement by the scale factor k.

10.2 Independent Practice – Algebraic Representations of Dilations – Page No. 325

Question 5.
The blue square is the preimage. Write two algebraic representations, one for the dilation to the green square and one for the dilation to the purple square.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 2: Algebraic Representations of Dilations img 8
Type below:
_____________

Answer:
Green square -> (x, y) -> (2x, 2y)
Purple square -> (x, y) -> (1/2x, 1/2y)

Question 6.
Critical Thinking A triangle has vertices A(-5, -4), B(2, 6), and C(4, -3). The center of dilation is the origin and (x, y) → (3x, 3y). What are the vertices of the dilated image?
Type below:
_____________

Answer:
A'(-15, -12)
B'(6, 18)
C'(12, -9)

Explanation:
A'((3.-15), (3.-12)) -> A'(-15, -12)
B'((3. 2), (3.6)) -> B'(6, 18)
C'((3. 4), (3.-3)) -> C'(12, -9)

Dilations Worksheet Answer Key 8th Grade Question 7.
Critical Thinking M′N′O′P′ has vertices at M′(3, 4), N′(6, 4), O′(6, 7), and P′(3, 7). The center of dilation is the origin. MNOP has vertices at M(4.5, 6), N(9, 6), O′(9, 10.5), and P′(4.5, 10.5). What is the algebraic representation of this dilation?
Type below:
_____________

Answer:
(x, y) -> (2/3x, 2/3y)

Explanation:
M’N’/MN = 3/4.5 = 2/3
algebraic rule: (x, y) -> (2/3x, 2/3y)

Question 8.
Critical Thinking A dilation with center (0,0) and scale factor k is applied to a polygon. What dilation can you apply to the image to return it to the original preimage?
Type below:
_____________

Answer:
A dilation with scale factor 1/k

Question 9.
Represent Real-World Problems The blueprints for a new house are scaled so that \(\frac{1}{4}\) inch equals 1 foot. The blueprint is the preimage and the house is the dilated image. The blueprints are plotted on a coordinate plane.
a. What is the scale factor in terms of inches to inches?
Scale factor: ________

Answer:
Scale factor: 48

Explanation:
scale factor = 48

Question 9.
b. One inch on the blueprint represents how many inches in the actual house? How many feet?
________ inches
________ feet

Answer:
48 inches
4 feet

Explanation:
48 inches or 4 feet

Question 9.
c. Write the algebraic representation of the dilation from the blueprint to the house.
Type below:
_____________

Answer:
(x, y) -> (48x, 48y)

Question 9.
d. A rectangular room has coordinates Q(2, 2), R(7, 2), S(7, 5), and T(2, 5) on the blueprint. The homeowner wants this room to be 25% larger. What are the coordinates of the new room?
Type below:
_____________

Answer:
Q'(2.5, 2.5),
R'(8.75, 2.5),
S'(8.75, 6.25),
T'(2.5, 6.25)

Question 9.
e. What are the dimensions of the new room, in inches, on the blueprint? What will the dimensions of the new room be, in feet, in the new house?
Type below:
_____________

Answer:
Blueprint dimensions: 6.25 in. by 3.75 in.
House dimensions: 25ft by 15ft

Algebraic Representations of Dilations – Page No. 326

Question 10.
Write the algebraic representation of the dilation shown.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 2: Algebraic Representations of Dilations img 9
Type below:
_____________

Answer:
(x, y) -> (1/4x, 1/4y)

Explanation:
algebraic rule of the dilation: (x, y) -> (1/4x, 1/4y)

FOCUS ON HIGHER ORDER THINKING

Question 11.
Critique Reasoning The set for a school play needs a replica of a historic building painted on a backdrop that is 20 feet long and 16 feet high. The actual building measures 400 feet long and 320 feet high. A stage crewmember writes (x, y) → (\(\frac{1}{12}\)x, \(\frac{1}{12}\)y) to represent the dilation. Is the crewmember’s calculation correct if the painted replica is to cover the entire backdrop? Explain.
_____________

Answer:
The stage crewmember’s calculation is incorrect.
The backdrop scale factor is 1/20, not 1/12

10.2 Independent Practice Answer Key Question 12.
Communicate Mathematical Ideas Explain what each of these algebraic transformations does to a figure.
a. (x, y) → (y, -x)
Type below:
_____________

Answer:
(x, y) → (y, -x)
90º clockwise rotation

Question 12.
b. (x, y) → (-x, -y)
Type below:
_____________

Answer:
(x, y) → (-x, -y)
180º rotation

Question 12.
c. (x, y) → (x, 2y)
Type below:
_____________

Answer:
(x, y) → (x, 2y)
vertically stretches by a factor of 2

Question 12.
d. (x, y) → (\(\frac{2}{3}\)x, y)
Type below:
_____________

Answer:
(x, y) → (\(\frac{2}{3}\)x, y)
horizontally shrinks by a factor of 2/3

Question 12.
e. (x, y) → (0.5x, 1.5y)
Type below:
_____________

Answer:
(x, y) → (0.5x, 1.5y)
horizontally shrinks by a factor of 0.5 and vertically stretches by a factor of 1.5

Question 13.
Communicate Mathematical Ideas Triangle ABC has coordinates A(1, 5), B(-2, 1), and C(-2, 4). Sketch triangle ABC and A′B′C′ for the dilation (x, y) → (-2x, -2y). What is the effect of a negative scale factor?
Type below:
_____________

Answer:
The figure is dilated by a factor of 2, but the orientation of the figure in the coordinate plane is rotated 180°

Guided Practice – Similar Figures – Page No. 330

Question 1.
Apply the indicated sequence of transformations to the square. Apply each transformation to the image of the previous transformation. Label each image with the
letter of the transformation applied.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 3: Similar Figures img 10
A: (x, y) → (-x, y)
B: Rotate the square 180° around the origin.
C: (x, y) → (x – 5, y – 6)
D: (x, y) → (\(\frac{1}{2}\)x, \(\frac{1}{2}\)y)
Type below:
_____________

Answer:

Explanation:
A: (x, y) → (-x, y)
coordinates for A
(-7, -8)
(-7, -4)
(-3, -4)
(-3, -8)
B: Rotate the square 180° around the origin.
coordinates for B
(3, 4)
(3, 8)
(7, 8)
(7, 4)
C: (x, y) → (x – 5, y – 6)
coordinates for C
(-2, -2)
(-2, 2)
(2, 2)
(2, -2)
D: (x, y) → (\(\frac{1}{2}\)x, \(\frac{1}{2}\)y)
coordinates for D
(-1, -1)
(-1, 1)
(1, 1)
(1, -1)

Identify a sequence of two transformations that will transform Figure A into the given figure.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 3: Similar Figures img 11

Question 2.
figure B
Type below:
_____________

Answer:
(x, y) -> (x, -y)
(x, y) -> (x +5, y-6)

Question 3.
figure C
Type below:
_____________

Answer:
(x, y) -> (x, y+6)
rotate 90º counterclockwise

Question 4.
figure D
Type below:
_____________

Answer:
(x, y) -> (1.5x, 1.5y)
(x, y) -> (x+3, y+5)

ESSENTIAL QUESTION CHECK-IN

Question 5.
If two figures are similar but not congruent, what do you know about the sequence of transformations used to create one from the other?
Type below:
_____________

Answer:
At least one transformation must be a dilation with a scale factor other than 1

10.3 Independent Practice – Similar Figures – Page No. 331

Question 6.
A designer creates a drawing of a triangular sign on centimeter grid paper for a new business. The drawing has sides measuring 6 cm, 8 cm, and 10 cm, and angles measuring 37°, 53°, and 90°. To create the actual sign shown, the drawing must be dilated using a scale factor of 40.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 3: Similar Figures img 12
a. Find the lengths of the sides of the actual sign.
Type below:
_____________

Answer:
240 cm, 320 cm, and 400 cm

Explanation:
6cm × 40 = 240cm
8cm × 40 = 320cm
10cm × 40 = 400cm
The lengths are 240 cm, 320 cm, and 400 cm

Question 6.
b. Find the angle measures of the actual sign.
Type below:
_____________

Answer:
The angle measures are the same
37º, 53º, and 90º

Question 6.
c. The drawing has the hypotenuse on the bottom. The business owner would like it on the top. Describe two transformations that will do this.
Type below:
_____________

Answer:
Reflect the drawing over the x-axis
Rotate the drawing 180º around the origin.

Question 6.
d. The shorter leg of the drawing is currently on the left. The business owner wants it to remain on the left after the hypotenuse goes to the top. Which transformation in part c will accomplish this?
Type below:
_____________

Answer:
Reflecting over the x-axis

In Exercises 7–10, the transformation of a figure into its image is described. Describe the transformations that will transform the image back into the original figure. Then write them algebraically.

Question 7.
The figure is reflected across the x-axis and dilated by a scale factor of 3.
Type below:
_____________

Answer:
Dilate the image by a scale factor of 1/3 and reflect it back across the x-axis.
(x, y) -> (1/3x, 1/3y)

Lesson 10 Practice Problems Answer Key Grade 8 Question 8.
The figure is dilated by a scale factor of 0.5 and translated 6 units left and 3 units up.
Type below:
_____________

Answer:
Translate the image 3 units down and 6 units right and dilate it by a factor of 2
(x, y) -> (x+6, y-3)
(x, y) -> (2x, 2y)

Question 9.
The figure is dilated by a scale factor of 5 and rotated 90° clockwise.
Type below:
_____________

Answer:
Rotate the image 90 counterclockwise and dilate it by a factor of 1/5.
(x, y) -> (-y, x)
(x, y) -> (1/5x, 1/5y)

Similar Figures – Page No. 332

Question 10.
The figure is reflected across the y-axis and dilated by a scale factor of 4.
Type below:
_____________

Answer:
Dilate the image by a factor of 1/4 and reflect it back across the y-axis.
(x, y) -> (1/4x, 1/4y)
(x, y) -> (-x, y)

FOCUS ON HIGHER ORDER THINKING

Question 11.
Draw Conclusions A figure undergoes a sequence of transformations that include dilations. The figure and its final image are congruent. Explain how this can happen.
Type below:
_____________

Answer:
There must be an even number of dilations and for each dilation applied to the figure, a dilation that has the opposite effect must be applied as well.

Question 12.
Multistep As with geometric figures, graphs can be transformed through translations, reflections, rotations, and dilations. Describe how the graph of y = x shown at the right is changed through each of the following transformations.
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Lesson 3: Similar Figures img 13
a. a dilation by a scale factor of 4
Type below:
_____________

Answer:
original coordinates
(0, -6)
(0, -4)
(4, 0)
(0, 4)
(-4, 4)
(-4, 2)
(-2, 0)
(-4, -2)

Question 12.
b. a translation down 3 units
Type below:
_____________

Answer:
coordinates for A
(0, -4)
(0, -3)
(2, -1)
(0, 1)
(-2, 1)
(-2, 0)
(-1, -1)
(-2, -2)

Question 12.
c. a reflection across the y-axis
Type below:
_____________

Answer:
coordinates for B
(-4, 3)
(-4, 2)
(-2, 0)
(-4, -2)
(-6, -2)
(-6, -1)
(-5, 0)
(-6, 1)

Question 13.
Justify Reasoning The graph of the line y = x is dilated by a scale factor of 3 and then translated up 5 units. Is this the same as translating the graph up 5 units and then dilating by a scale factor of 3? Explain.
Type below:
_____________

Answer:
No; the dilation is not the same reversed

Explanation:
The position of the sketch from 12A will be 1/2 unit above the sketch obtained when the translation occurs first

Ready to Go On? – Model Quiz – Page No. 333

10.1 Properties of Dilations

Determine whether one figure is a dilation of the other. Justify your answer.

Question 1.
Triangle XYZ has angles measuring 54° and 29°. Triangle X′Y′Z′ has angles measuring 29° and 92°.
_____________

Answer:
No; one figure is not a dilation of the other

Explanation:
The triangles have only one pair of congruent angles

Dilations Answer Key Question 2.
Quadrilateral DEFG has sides measuring 16 m, 28 m, 24 m, and 20 m. Quadrilateral D′E′F′G′ has sides measuring 20 m, 35 m, 30 m, and 25 m.
_____________

Answer:
Yes; Quadrilateral D’E’F’G’ is a dilation of quadrilateral DEFG

Explanation:
each side of the second figure is 1.25 times the corresponding side of the original figure.

10.2 Algebraic Representations of Dilations

Dilate each figure with the origin as the center of dilation.

Question 3.
(x, y) → (0.8x, 0.8y)
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Model Quiz img 14
Type below:
_____________

Answer:
Coordinates after dilation
(0, -4)
(4, 0)
(0, 4)
(-4, 0)

Question 4.
(x, y) → (2.5x, 2.5y)
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Model Quiz img 15
Type below:
_____________

Answer:
Coordinates after dilation
(-2.5, 2.5)
(5, 5)
(5, -3)

10.3 Similar Figures

Question 5.
Describe what happens to a figure when the given sequence of transformations is applied to it: (x, y) → (-x, y); (x, y) → (0.5x, 0.5y); (x, y) → (x – 2, y + 2)
Type below:
_____________

Answer:
After the sequencing of transformations, reflection over the y-axis.
dilation with a scale factor of 0.5
translation 2 units left and 2 units up

ESSENTIAL QUESTION

Question 6.
How can you use dilations to solve real-world problems?
Type below:
_____________

Answer:
You can use dilations when drawing or designing

Selected Response – Mixed Review – Page No. 334

Question 1.
A rectangle has vertices (6, 4), (2, 4), (6, –2), and (2, –2). What are the coordinates of the vertices of the image after a dilation with the origin as its center and a scale factor of 1.5?
Options:
a. (9, 6), (3, 6), (9, –3), (3, –3)
b. (3, 2), (1, 2), (3, –1), (1, –1)
c. (12, 8), (4, 8), (12, –4), (4, –4)
d. (15, 10), (5, 10), (15, –5), (5, –5)

Answer:
a. (9, 6), (3, 6), (9, –3), (3, –3)

Explanation:
(9 -3)/(6 -2) = 6/4 = 1.5

Question 2.
Which represents the dilation shown where the black figure is the preimage?
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Mixed Review img 16
Options:
a. (x, y) -> (1.5x, 1.5y)
b. (x, y) -> (2.5x, 2.5y)
c. (x, y) -> (3x, 3y)
d. (x, y) -> (6x, 6y)

Answer:
b. (x, y) -> (2.5x, 2.5y)

Explanation:
5/2 = 2.5
10/4 = 2.5
(x, y) -> (2.5x, 2.5y)

Question 3.
Identify the sequence of transformations that will reflect a figure over the x-axis and then dilate it by a scale factor of 3.
Options:
a. (x, y) -> (-x, y); (x, y) -> (3x, 3y)
b. (x, y) -> (-x, y); (x, y) -> (x, 3y)
c. (x, y) -> (x, -y); (x, y) -> (3x, y)
d. (x, y) -> (x, -y); (x, y) -> (3x, 3y)

Answer:
d. (x, y) -> (x, -y); (x, y) -> (3x, 3y)

Explanation:
Reflection over x-axis (x, y) -> (x, -y)
dilation by scale factor of 3 (x, y) -> (3x, 3y)
(x, y) -> (x, -y); (x, y) -> (3x, 3y)

Question 4.
Solve −a + 7 = 2a − 8.
Options:
a. a = -3
b. a = −\(\frac{1}{3}\)
c. a = 5
d. a = 15

Answer:
c. a = 5

Explanation:
-a + 7 = 2a – 8
2a + a = 8 + 7
3a = 15
a = 15/3
a = 5

8th Grade Transformations Worksheet Answers Question 5.
Which equation does not represent a line with an x-intercept of 3?
Options:
a. y = −2x + 6
b. y = −\(\frac{1}{3}\)x + 1
c. y = \(\frac{2}{3}\)x − 2
d. y = 3x − 1

Answer:
d. y = 3x − 1

Explanation:
y = -2x + 6
0 = -2x + 6
2x = 6
x = 3
y = -1/3 . x + 1
0 = -1/3 . x + 1
1/3x = 1
x = 3
y = 2/3 . x – 2
0 = 2/3 . x – 2
2/3x = 2
x = 2 . 3/2
x = 3
y = 3x – 1
0 = 3x – 1
3x = 1
x = 1/3

Mini-Task

Dilation and Similarity Iready Answers Question 6.
The square is dilated under the dilation (x, y) → (0.25x, 0.25y).
Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Mixed Review img 17
a. Graph the image. What are the coordinates?
Type below:
_____________

Answer:
After dilation:
(-1, 1)
(1, 1)
(1, -1)
(-1, -1)

Question 6.
b. What is the length of a side of the image?
______ units

Answer:
2 units

Explanation:
The length is 2 units

Question 6.
c. What are the perimeter and area of the preimage?
Perimeter = ________ units
Area = ________ square units

Answer:
Perimeter = 32 units
Area = 64 square units

Explanation:
Perimeter = 2l + 2w = 2(8) + 2(8) = 32
area = l.w = 8 .8 = 64

Question 6.
d. What are the perimeter and area of the image?
Perimeter = ________ units
Area = ________ square units

Answer:
Perimeter = 8 units
Area = 4 square units

Explanation:
Perimeter = 2l + 2w = 2(2) + 2(2) = 8
area = l.w = 2 . 2 = 4

Conclusion:

Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Online PDF to help the students to practice maths. All the explanations are given by the best online maths experts. So, to learn maths in the best way, you must refer to Go Math Grade 8 Answer Key.

Go Math Grade 8 Answer Key Chapter 10 Transformations and Similarity Read More »

go-math-grade-8-answer-key-chapter-8-solving-systems-of-linear-equations

Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations

Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations for the best practice of maths. All the answers and explanations are explained by the best maths experts. All the students can quickly open our website and start practicing now. If you don’t have an internet connection, then download the free pdf of Go Math Grade 8 Chapter 8 Solving Systems of Linear Equations Answer Key and start practicing offline. There is no payment required to get Go Math Grade 8 Answer Key.

Go Math Grade 8 Chapter 8 Solving Systems of Linear Equations Answer Key

Sometimes it’s really a difficult task to choose the best maths to answer key to know the correct answers. A trustable guide will help you to learn perfectly and to improve your math skills. One of such best online guide is Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations. Refer to Go Math Grade 8 Solution Key to learning the easy way of maths practice.

Lesson 1: Solving Systems of Linear Equations by Graphing

Lesson 2: Solving Systems by Substitution

Lesson 3: Solving Systems by Elimination

Lesson 4: Solving Systems by Elimination with Multiplication

Lesson 5: Solving Solving Special Systems

Model Quiz

Review

Guided Practice – Solving Systems of Linear Equations by Graphing – Page No. 232

Solve each system by graphing.

Question 1.
\(\left\{\begin{array}{l}y=3 x-4 \\y=x+2\end{array}\right.\)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 1
Type below:
______________

Answer:
grade 8 chapter 8 image 1

Explanation:
y = 3x – 4
y = x + 2
The solution of thr linear system of equations is the intersection point of the two equations.
(3, 5) is the solution of the system of equations.
If x = 3, y = 3(3) – 4 = 9 – 4 = 5; y = 3 + 2 = 5
5 = 5; True

Question 2.
\(\left\{\begin{array}{l}x-3 y=2 \\-3x+9y=-6\end{array}\right.\)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 2
Type below:
______________

Answer:
grade 8 chapter 8 image 2
Infinitely many solutions

Explanation:
x – 3y = 2
-3x + 9y = -6
x – 3y – x = -x + 2
-3y = -x + 2
y = 1/3 . x – 2/3
-3x + 9y + 3x = 3x – 6
9y = 3x – 6
y = 3/9 . x – 6/9
y = 1/3 . x – 2/3
The solution of the linear system of equations is the intersection of the two equations.
Infinitely many solutions

Lesson 8.1 Solve Systems of Equations Algebraically Answer Key Question 3.
Mrs. Morales wrote a test with 15 questions covering spelling and vocabulary. Spelling questions (x) are worth 5 points and vocabulary questions (y) are worth 10 points. The maximum number of points possible on the test is 100.
a. Write an equation in slope-intercept form to represent the number of questions on the test.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 3
Type below:
______________

Answer:
y = -x + 15

Explanation:
Mrs. Morales wrote a test with 15 questions covering spelling and vocabulary. Spelling questions (x) are worth 5 points and vocabulary questions (y) are worth 10 points.
x + y = 15
x + y – x = -x + 15
y = -x + 15

Question 3.
b. Write an equation in slope-intercept form to represent the total number of points on the test.
Type below:
______________

Answer:
y = -1/2 . x + 10

Explanation:
The total number of points on the test is 100
5x + 10y = 100
5x + 10y – 5x = -5x + 100
10y = -5x + 100
y = -5/10 . x + 100/10
y = -1/2 . x + 10

Question 3.
c. Graph the solutions of both equations.
Type below:
______________

Answer:
grade 8 chapter 8 image 3

Question 3.
d. Use your graph to tell how many of each question type are on the test.
_________ spelling questions
_________ vocabulary questions

Answer:
10 spelling questions
5 vocabulary questions

ESSENTIAL QUESTION CHECK-IN

Question 4.
When you graph a system of linear equations, why does the intersection of the two lines represent the solution of the system?
Type below:
______________

Answer:
Solving a system of linear equations means finding the solutions that satisfy all the equations of that system. When we graph a system of linear equations, the intersection point lies on the line of each equation, which means that satisfies all the equations. Therefore, it is considered to be the solution to that system.

Solving Systems of Linear Equations by Graphing – Page No. 233

Question 5.
Vocabulary
A_________________ is a set of equations that have the same variables.
______________

Answer:
system of equations

Explanation:
A system of equations is a set of equations that have the same variables.

Lesson 8.1 Solving Systems of Linear Equations by Graphing Question 6.
Eight friends started a business. They will wear either a baseball cap or a shirt imprinted with their logo while working. They want to spend exactly $36 on the shirts and caps. The shirts cost $6 each and the caps cost $3 each.
a. Write a system of equations to describe the situation. Let x represent the number of shirts and let y represent the number of caps.
______________

Answer:
6x + 3y = 36

Explanation:
The sum of caps and shirts is 8. The total cost of caps and shirts is $36.
x + y = 8
6x + 3y = 36

Question 6.
b. Graph the system. What is the solution and what does it represent?
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 4
Type below:
______________

Answer:
The solution is (4, 4)
grade 8 chapter 8 image 4

Explanation:
x + y – x = -x + 8
y = -x + 8
6x + 3y – 6x = -6x + 36
3y = -6x + 36
y = -6/2 . x + 36/3
y = -2x + 12
(4, 4). They should order 4 shirts and 4 caps.

Question 7.
Multistep The table shows the cost of bowling at two bowling alleys.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 5
a. Write a system of equations, with one equation describing the cost to bowl at Bowl-o-Rama and the other describing the cost to bowl at Bowling Pinz. For each equation, let x represent the number of games played and let y represent the total cost.
Type below:
______________

Answer:
y = 2.5x + 2
y = 2x + 4

Explanation:
Cost at Bowl-o-Rama => y = 2.5x + 2
Cost at Bowling Pinz => y = 2x + 4

Question 7.
b. Graph the system. What is the solution and what does it represent?
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 6
Type below:
______________

Answer:
grade 8 chapter 8 image 5

Explanation:
The solution of the linear system of equations is the intersection of the two equations.
(4, 12)
When 4 games are played, the total cost is $12.

Solving Systems of Linear Equations by Graphing – Page No. 234

Question 8.
Multi-Step Jeremy runs 7 miles per week and increases his distance by 1 mile each week. Tony runs 3 miles per week and increases his distance by 2 miles each week. In how many weeks will Jeremy and Tony be running the same distance? What will that distance be?
Type below:
______________

Answer:
After 4 weeks Jeremy and Tony will be running the same distance and that distance would be 11 miles.

Explanation:
Multi-Step Jeremy runs 7 miles per week and increases his distance by 1 mile each week.
y = x + 7
Tony runs 3 miles per week and increases his distance by 2 miles each week.
y = 2x + 3
grade 8 chapter 8 image 6
The solution of the system of linear equation is (4, 11) which means that after 4 weeks Jeremy and Tony will be running the same distance and that distance would be 11 miles.

Lesson 1 Solve Systems of Equations Algebraically Answers Question 9.
Critical Thinking Write a real-world situation that could be represented by the system of equations shown below.
\(\left\{\begin{array}{l}y=4 x+10 \\y=3x+15\end{array}\right.\)
Type below:
______________

Answer:
The entry fee of the first gym is $10 and for every hour that you spend there, you pay an extra $4. If we denote with x the number of hours that somebody spends at the gym and with y the total cost is
y = 4x + 10
The entry fee of the second gym is $15 and for every hour that you spend there, you pay an extra $3. If we denote with x the number of hours that somebody spends at the gym and with y the total cost is
y = 3x + 15
y = 4x + 10
y = 3x + 15

FOCUS ON HIGHER ORDER THINKING

Question 10.
Multistep The table shows two options provided by a high-speed Internet provider.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson1: Solving Systems of Linear Equations by Graphing img 7
a. In how many months will the total cost of both options be the same? What will that cost be?
________ months
$ ________

Answer:
5 months
$ 200

Explanation:
Let y be the total cost after x month
y = 30x + 50
Let y be the total cost after x month
y = 40x
Substitute y = 40x in y = 30x + 50
40x = 30x + 50
40x – 30x = 50
10x = 50
x = 50/10
x = 5
The total cost of both options will be the same after 5 months. Total cost would be y = 40(5) = $200.

Question 10.
b. If you plan to cancel your Internet service after 9 months, which is the cheaper option? Explain.
______________

Answer:
When x = 9 months
y = 30(9) + 50 = $320
y = 40(9) = $360
$320 < $360
Option 1 is cheaper as the total cost is less for option 1

Lesson 1 Solve Systems of Equations by Graphing Question 11.
Draw Conclusions How many solutions does the system formed by x − y = 3 and ay − ax + 3a = 0 have for a nonzero number a? Explain.
Type below:
______________

Answer:
x – y = 3
ay – ax + 3a =0
ay – ax + 3a – 3a = 0 – 3a
ay – ax = – 3a
a(y – x) = -3a
y – x = -3
x – y = 3
Both equations are the same. The system of linear equations has infinitely many solutions.

Guided Practice – Solving Systems by Substitution – Page No. 240

Solve each system of linear equations by substitution.

Question 1.
\(\left\{\begin{array}{l}3x-2y=9 \\y=2x-7\end{array}\right.\)
x = ________
y = ________

Answer:
x = 5
y = 3

Explanation:
\(\left\{\begin{array}{l}3x-2y=9 \\y=2x-7\end{array}\right.\)
Substitute 2x – 7 in 3x – 2y = 9
3x – 2(2x – 7) = 9
3x – 4x + 14 = 9
-x + 14 = 9
-x + 14 – 14 = 9 – 14
-x = -5
x = -5/-1 = 5
y = 2(5) – 7 = 3
Solution is (5, 3)

Question 2.
\(\left\{\begin{array}{l}y=x-4 \\2x+y=5\end{array}\right.\)
x = ________
y = ________

Answer:
x = 3
y = -1

Explanation:
\(\left\{\begin{array}{l}y=x-4 \\2x+y=5\end{array}\right.\)
2x + x – 4 = 5
3x – 4 = 5
3x – 4 + 4 = 5 + 4
3x = 9
x = 9/3 = 3
y = 3 – 4 = -1
The solution is (3, -1)

8.2 Solving Systems by Substitution Answer Key Question 3.
\(\left\{\begin{array}{l}x+4y=6 \\y=-x+3\end{array}\right.\)
x = ________
y = ________

Answer:
x = 2
y = 1

Explanation:
\(\left\{\begin{array}{l}x+4y=6 \\y=-x+3\end{array}\right.\)
Substitute y = -x + 3 in x + 4y = 6
x + 4(-x + 3) = 6
x – 4x + 12 = 6
-3x + 12 = 6
-3x + 12 – 12 = 6 – 12
-3x = -6
x = -6/-3 = 2
y = -2 + 3 = 1
The solution is (2, 1)

Question 4.
\(\left\{\begin{array}{l}x+2y=6 \\x-y=3\end{array}\right.\)
x = ________
y = ________

Answer:
x = 4
y = 1

Explanation:
\(\left\{\begin{array}{l}x+2y=6 \\x-y=3\end{array}\right.\)
y = x – 3
Substitute y = x – 3 in x + 2y = 6
x + 2(x – 3) = 6
x + 2x – 6 = 6
3x = 12
x = 12/3
x = 4
4 – y = 3
-y = 3 – 4
-y = -1
y = 1
The solution is (4, 1)

Solve each system. Estimate the solution first.

Question 5.
\(\left\{\begin{array}{l}6x+y=4 \\x-4y=19\end{array}\right.\)
Estimate ______________
Solution ______________
Type below:
______________

Answer:
Estimate (2, -5)
Solution (1.4, -4.4)

Explanation:
\(\left\{\begin{array}{l}6x+y=4 \\x-4y=19\end{array}\right.\)
Let’s find the estimation by graphing the equations
Estimate: (2, -5)
grade 8 chapter 8 image 7
x = 4y + 19
6(4y + 19) + y = 4
24y + 114 + y = 4
25y + 114 = 4
25y = 4 – 114
25y = -110
y = -110/25
y = -4.4
x + 4(-4.4) = 19
x + 17.6 = 19
x = 19 – 17.6
x = 1.4
The solution is (1.4, -4.4)

8.2 Solving Systems by Substitution Question 6.
\(\left\{\begin{array}{l}x+2y=8 \\3x+2y=6\end{array}\right.\)
Estimate ______________
Solution ______________
Type below:
______________

Answer:
Estimate (-1, 5)
Solution (-1, 4.5)

Explanation:
\(\left\{\begin{array}{l}x+2y=8 \\3x+2y=6\end{array}\right.\)
Let’s find the estimation by graphing the equations
Estimate: (-1, 5)
grade 8 chapter 8 image 8
x = -2y + 8
Substitute the equation x = -2y + 8 in 3x + 2y = 6
3(-2y + 8) + 2y = 6
-6y + 24 + 2y = 6
-4y = 6 – 24
-4y = -18
y = -18/-4
y = 4.5
x + 2(4.5) = 8
x + 9 = 8
x = 8 – 9
x = -1
The solution is (-1, 4.5)

Question 7.
\(\left\{\begin{array}{l}3x+y=4 \\5x-y=22\end{array}\right.\)
Estimate ______________
Solution ______________
Type below:
______________

Answer:
Estimate (3, -6)
Solution (3.25, -5.75)

Explanation:
\(\left\{\begin{array}{l}3x+y=4 \\5x-y=22\end{array}\right.\)
Find the Estimation using graphing the equations.
Estimate: (3, -6)
grade 8 chapter 8 image 9
y = -3x + 4
Substitute y = -3x + 4 in 5x – y = 22
5x – (-3x + 4) = 22
5x + 3x -4 = 22
8x = 26
x = 26/8
x = 3.25
3(3.25) + y = 4
9.75 + y = 4
y = 4 – 9.75
y = -5.75
The solution is (3.25, -5.75)

Question 8.
\(\left\{\begin{array}{l}2x+7y=2 \\x+y=-1\end{array}\right.\)
Estimate ______________
Solution ______________
Type below:
______________

Answer:
Estimate (-2, 1)
Solution (-1.8, 0.8)

Explanation:
\(\left\{\begin{array}{l}2x+7y=2 \\x+y=-1\end{array}\right.\)
Find the Estimation using graphing the equations.
Estimate: (-2, 1)
grade 8 chapter 8 image 10
y = -x -1
Substitute y = -x – 1 in 2x + 7y = 2
2x + 7(-x – 1) = 2
2x – 7x -7 = 2
-5x = 2 + 7
-5x = 9
x = -9/5
x = -1.8
-1.8 + y = -1
y = -1 + 1.8
y = 0.8
The solution is (-1.8, 0.8)

Question 9.
Adult tickets to Space City amusement park cost x dollars. Children’s tickets cost y dollars. The Henson family bought 3 adult and 1 child tickets for $163. The Garcia family bought 2 adult and 3 child tickets for $174.
a. Write equations to represent the Hensons’ cost and the Garcias’ cost.
Hensons’ cost: ________________
Garcias’ cost:__________________
Type below:
______________

Answer:
Hensons’ cost: 3x + y = 163
Garcias’ cost: 2x + 3y = 174

Explanation:
Henson’s cost
3x + y = 163
Garcia’s cost
2x + 3y = 174

Question 9.
b. Solve the system.
adult ticket price: $ _________
Garcias’ cost: $ _________

Answer:
adult ticket price: $ 45
Garcias’ cost: $ 28

Explanation:
y = -3x + 163
Substitute y = -3x + 163 in 2x + 3y = 174
2x + 3(-3x + 163) = 174
2x -9x + 489 = 174
-7x = -315
x = -315/-7 = 45
3(45) + y = 163
135 + y = 163
y = 163 – 135
y = 28
Adult ticket price: $ 45
Garcias’ cost: $ 28

ESSENTIAL QUESTION CHECK-IN

Question 10.
How can you decide which variable to solve for first when you are solving a linear system by substitution?
Type below:
______________

Answer:
The variable with the unit coefficient should be solved first when solving a linear system by substitution.

8.2 Independent Practice – Solving Systems by Substitution – Page No. 241

Question 11.
Check for Reasonableness Zach solves the system
\(\left\{\begin{array}{l}x+y=-3 \\x-y=1\end{array}\right.\)
and finds the solution (1, -2). Use a graph to explain whether Zach’s solution is reasonable.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 2: Solving Systems by Substitution img 8
Type below:
______________

Answer:
grade 8 chapter 8 image 11

Explanation:
\(\left\{\begin{array}{l}x+y=-3 \\x-y=1\end{array}\right.\)
The x coordinate of the solution is negative, hence Zach’s solution is not reasonable.

Represent Real-World Problems Angelo bought apples and bananas at the fruit stand. He bought 20 pieces of fruit and spent $11.50. Apples cost $0.50 and bananas cost $0.75 each.
a. Write a system of equations to model the problem. (Hint: One equation will represent the number of pieces of fruit. A second equation will represent the money spent on the fruit.)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 2: Solving Systems by Substitution img 9
Type below:
______________

Answer:
x + y = 20
0.5x + 0.75y = 11.5

Explanation:
x + y = 20
0.5x + 0.75y = 11.5
where c is the number of Apples and y is the number of Bananas.

Question 12.
b. Solve the system algebraically. Tell how many apples and bananas Angelo bought.
________ apples
________ bananas

Answer:
14 apples
6 bananas

Explanation:
y = -x + 20
Substitute y = -x + 20 in 0.5x + 0.75y = 11.5
0.5x + 0.75(-x + 20) = 11.5
0.5x – 0.75x + 15 = 11.5
-0.25x + 15 = 11.5
-0.25x = 11.5 – 15
-0.25x = -3.5
x = -3.5/-0.25
x = 14
14 + y = 20
y = 6
Angelo bought 14 apples and 6 bananas.

Solving Systems by Substitution Lesson 8.2 Answer Key Question 13.
Represent Real-World Problems A jar contains n nickels and d dimes. There is a total of 200 coins in the jar. The value of the coins is $14.00. How many nickels and how many dimes are in the jar?
________ nickels
________ dimes

Answer:
120 nickels
80 dimes

Explanation:
A jar contains n nickels and d dimes. There is a total of 200 coins in the jar. The value of the coins is $14.00.
$14 = 1400 cents
n + d = 200
5n + 10d = 1400
d = -n + 200
5n + 10(-n + 200) = 1400
5n – 10n + 2000 = 1400
-5n = -600
n = -600/-5
n = 120
120 + d = 200
d = 200 – 120
d = 80
There are 120 nickles and 80 dimes in the jar.

Question 14.
Multistep The graph shows a triangle formed by the x-axis, the line 3x−2y=0, and the line x+2y=10. Follow these steps to find the area of the triangle.
a. Find the coordinates of point A by solving the system
\(\left\{\begin{array}{l}3x-2y=0 \\x-2y=10\end{array}\right.\)
Point A: ____________________
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 2: Solving Systems by Substitution img 10
Type below:
______________

Answer:
Point A: (2.5, 3.75)Coordinate of A is (2.5, 3.75)

Explanation:
\(\left\{\begin{array}{l}3x-2y=0 \\x-2y=10\end{array}\right.\)
x = -2y + 10
Substitute x = -2y + 10 in 3x – 2y = 0
3(-2y + 10) -2y = 0
-6y + 30 – 2y = 0
-8y = -30
y = -30/-8 = 3.75
x + 2(3.75) = 10
x + 7.5 = 10
x = 10 – 7.5
x = 2.5
Coordinate of A is (2.5, 3.75)

Question 14.
b. Use the coordinates of point A to find the height of the triangle.
height:__________________
height: \(\frac{□}{□}\) units

Answer:
height: 3.75
height: \(\frac{15}{4}\) units

Explanation:
The height of the triangle is the y coordinate of A
Height = 3.75

Question 14.
c. What is the length of the base of the triangle?
base:________________
base: ______ units

Answer:
base: 10 units

Explanation:
Length of the base = 10

Question 14.
d. What is the area of the triangle?
A = ______ \(\frac{□}{□}\) square units

Answer:
A = 18.75 square units
A = 18 \(\frac{3}{4}\) square units

Explanation:
Area of the triangle = 1/2 . Height . Base
Area = 1/2 . 3.75 . 10 = 18.75

Solving Systems by Substitution – Page No. 242

Question 15.
Jed is graphing the design for a kite on a coordinate grid. The four vertices of the kite are at A(−\(\frac{4}{3}\), \(\frac{2}{3}\)), B(\(\frac{14}{3}\), −\(\frac{4}{3}\)), C(\(\frac{14}{3}\), −\(\frac{16}{3}\)), and D(\(\frac{2}{3}\), −\(\frac{16}{3}\)). One kite strut will connect points A and C. The other will connect points B and D. Find the point where the struts cross.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 2: Solving Systems by Substitution img 11
Type below:
______________

Answer:
The struts cross as (8/3, 10/3)

Explanation:
1. From AC
Slope = (y2 – y1)/(x2 – x1) = [(-16/3)-(2/3)] ÷ [(14/3) – (-4/3)] = (-18/3) ÷ (18/3) = -1
y = mx + b
2/3 = -1(-4/3) + b
2/3 = 4/3 + b
1. From BD
Slope = (y2 – y1)/(x2 – x1) = [(-16/3)-(-4/3)] ÷ [(2/3) – (144/3)] = (-12/3) ÷ (-12/3) = 1
y = mx + b
-4/3 = 1(14/3) + b
-4/3 = 14/3 + b
-18/3 = b
-6 = b
y = mx + b
y = x -6
3. y = -x -2/3
y = x – 6
4. y = -x – 2/3
x – 6 = -x – 2/3
x = -x – 2/3 + 6
x = – x + 16/3
2x = 16/3
x = 16/6
x = 8/3
then y = x – 6
y = 8/3 – 18/3
y = -10/3
The struts cross as (8/3, 10/3)

FOCUS ON HIGHER ORDER THINKING

Question 16.
Analyze Relationships Consider the system
\(\left\{\begin{array}{l}6x-3y=15 \\x+3y=-8\end{array}\right.\)
Describe three different substitution methods that can be used to solve this system. Then solve the system.
Type below:
______________

Answer:
(1, -3) is the answer.

Explanation:
As there are three different substitution methods, we can write
Solve for y in the first equation, then substitute that value into the second equation.
Solve for x in the second equation, then substitute that value into the first equation.
Solve either equation for 3y, then substitute that value into the other equation.
From the Second method,
x + 3y = -8
x = -3y – 8
6x – 3y = 15
6 (-3y – 8) -3y = 15
-18y – 48 -3y = 15
-21y – 48 = 15
-21y = 63
y = -3
x + 3y = -8
x + 3(-3) = -8
x – 9 = -8
x = 1
(1, -3) is the answer.

Question 17.
Communicate Mathematical Ideas Explain the advantages, if any, that solving a system of linear equations by substitution has over solving the same system by graphing.
Type below:
______________

Answer:
The advantage of solving a system of linear equations by graphing is that it is relatively easy to do and requires very little algebra.

Question 18.
Persevere in Problem Solving Create a system of equations of the form
\(\left\{\begin{array}{l}Ax+By=C \\Dx+Ey=F\end{array}\right.\)
that has (7, −2) as its solution. Explain how you found the system.
Type below:
______________

Answer:
x + y = 5
x – y = 9
solves in :
x = (5+9)/2 = 7
y = 5-9)/2 = -2
A=1, B=2, C= 5
D=1, E= -1, F=9
x = 7
y = -2
IS a system (even if it is a trivial one) of equations so this answer would be acceptable.
The target for a system is to find it SOLUTION SET and not to conclude with x=a and y=b

Guided Practice – Solving Systems by Elimination – Page No. 248

Question 1.
Solve the system
\(\left\{\begin{array}{l}4x+3y=1 \\x-3y=-11\end{array}\right.\)
by adding.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 3: Solving Systems by Elimination img 12
Type below:
______________

Answer:
4x + 3y = 1
x – 3y = -11
Add the above two equations
4x + 3y = 1
+(x – 3y = -11)
Add to eliminate the variable y
5x + 0y = -10
Simplify and solve for x
5x = -10
Divide both sided by 5
x = -10/5 = -2
Substitute into one of the original equations and solve for y.
4(-2) + 3y = 1
-8 + 3y = 1
3y = 9
y = 9/3 = 3
So, (-2, 3) is the solution of the system.

Solve each system of equations by adding or subtracting.

Question 2.
\(\left\{\begin{array}{l}x+2y=-2 \\-3x+2y=-10\end{array}\right.\)
x = ________
y = ________

Answer:
x = 2
y = -2

Explanation:
\(\left\{\begin{array}{l}x+2y=-2 \\-3x+2y=-10\end{array}\right.\)
Subtract the equations
x + 2y = -2
-(-3x + 2y = -10)
y is eliminated as it has reversed coefficients. Solve for x
x + 2y + 3x – 2y = -2 + 10
4x = 8
x = 8/4 = 2
Substituting x in either of the equations to find y
2 + 2y = -2
2 + 2y -2 = -2 -2
2y = -4
y = -4/2 = -2
(2, -2) is the answer.

Lesson 3 Solve Systems of Equations Algebraically Answer Key Question 3.
\(\left\{\begin{array}{l}3x+y=23 \\3x-2y=8\end{array}\right.\)
(________ , ________)

Answer:
(6, 5)

Explanation:
\(\left\{\begin{array}{l}3x+y=23 \\3x-2y=8\end{array}\right.\)
Subtract the equations
3x + y = 23
-(3x – 2y = 8)
x is eliminated as it has reversed coefficients. Solve for y
3x + y – 3x + 2y = 23 – 8
3y = 15
y = 15/3 = 5
Substituting y in either of the equations to find x
3x + 5 = 23
3x + 5 – 5 = 23 – 5
3x = 18
x = 18/3 = 6
Solution is (6, 5)

Question 4.
\(\left\{\begin{array}{l}-4x-5y=7 \\3x+5y=-14\end{array}\right.\)
(________ , ________)

Answer:
(7, -7)

Explanation:
\(\left\{\begin{array}{l}-4x-5y=7 \\3x+5y=-14\end{array}\right.\)
Add the equations
-4x – 5y = 7
+(3x + 5y = -14)
y is eliminated as it has reversed coefficients. Solve for x
-4x -5y +3x + 5y = 7 -14
-x = -7
x = -7/-1 = 7
Substituting x in either of the equations to find y
3(7) + 5y = -14
21 + 5y -21 = -14 -21
5y = -35
y = -35/5 = -7
The answer is (7, -7)

Question 5.
\(\left\{\begin{array}{l}x-2y=-19 \\5x+2y=1\end{array}\right.\)
(________ , ________)

Answer:
(-3, 8)

Explanation:
\(\left\{\begin{array}{l}x-2y=-19 \\5x+2y=1\end{array}\right.\)
Add the equations
x – 2y = -19
+(5x + 2y = 1)
y is eliminated as it has reversed coefficients. Solve for x
x – 2y + 5x + 2y = -19 + 1
6x = -18
x = -18/6 = -3
Substituting x in either of the equations to find y
-3 -2y = -19
-3 -2y + 3 = -19 + 3
-2y = -16
y = -16/-2 = 8
The answer is (-3, 8)

Question 6.
\(\left\{\begin{array}{l}3x+4y=18 \\-2x+4y=8\end{array}\right.\)
(________ , ________)

Answer:
(2, 3)

Explanation:
\(\left\{\begin{array}{l}3x+4y=18 \\-2x+4y=8\end{array}\right.\)
Subtract the equations
3x + 4y = 18
-(-2x + 4y = 8)
y is eliminated as it has reversed coefficients. Solve for x
3x + 4y + 2x – 4y = 18 – 8
5x = 10
x = 10/5 = 2
Substituting x in either of the equations to find y
3(2) + 4y = 18
6 + 4y – 6 = 18 – 6
4y = 12
y = 12/4 =3
Solution is (2, 3)

Question 7.
\(\left\{\begin{array}{l}-5x+7y=11 \\-5x+3y=19\end{array}\right.\)
(________ , ________)

Answer:
(-5, -2)

Explanation:
\(\left\{\begin{array}{l}-5x+7y=11 \\-5x+3y=19\end{array}\right.\)
Subtract the equations
-5x + 7y = 11
-(-5x + 3y = 19)
x is eliminated as it has reversed coefficients. Solve for y
-5x + 7y + 5x – 3y = 11 – 19
4y = -8
y = -8/4 = -2
Substituting y in either of the equations to find x
-5x + 7(-2) = 11
-5x -14 + 14 = 11 + 14
-5x = 25
x = 25/-5 = -5
The solution is (-5, -2)

Question 8.
The Green River Freeway has a minimum and a maximum speed limit. Tony drove for 2 hours at the minimum speed limit and 3.5 hours at the maximum limit, a distance of 355 miles. Rae drove 2 hours at the minimum speed limit and 3 hours at the maximum limit, a distance of 320 miles. What are the two-speed limits?
a. Write equations to represent Tony’s distance and Rae’s distance.
Type below:
______________

Answer:
Tony’s distance: 2x + 3.5y = 355
Rae’s distance: 2x + 3y = 320
where x is the minimum speed and y is the maximum speed.

Question 8.
b. Solve the system.
minimum speed limit:______________
maximum speed limit______________
minimum speed limit: ________ mi/h
maximum speed limit: ________ mi/h

Answer:
minimum speed limit:55
maximum speed limit70
minimum speed limit: 55mi/h
Maximum speed limit: 70mi/h

Explanation:
Subtract the equations
2x + 3.5y = 355
-(2x + 3y = 320)
x is eliminated as it has reversed coefficients. Solve for y
2x + 3.5y – 2x – 3y = 355 – 320
0.5y = 35
y = 35/0.5 = 70
Substituting y in either of the equation to find x
2x + 3(70) = 320
2x + 210 – 210 = 320 – 210
2x = 110
x = 110/2 = 55
Minimum speed limit: 55 miles per hour
Maximum speed limit: 70 miles per hour

ESSENTIAL QUESTION CHECK-IN

Question 9.
Can you use addition or subtraction to solve any system? Explain.
________

Answer:
No. One of the variables should have the same coefficient in order to add or subtract the system.

8.3 Independent Practice – Solving Systems by Elimination – Page No. 249

Question 10.
Represent Real-World Problems Marta bought new fish for her home aquarium. She bought 3 guppies and 2 platies for a total of $13.95. Hank also bought guppies and platies for his aquarium. He bought 3 guppies and 4 platies for a total of $18.33. Find the price of a guppy and the price of a platy.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 3: Solving Systems by Elimination img 13
Guppy: $ ________
Platy: $ ________

Answer:
Guppy: $ 3.19
Platy: $ 2.19

Explanation:
3x + 2y = 13.95
3x + 4y = 18.33
where x is the unit price of guppy and y is the unit price of platy
Subtract the equations
3x + 2y = 13.95
-(3x + 4y = 18.33)
x is eliminated as it has reversed coefficients. Solve for y
3x + 2y – 3x – 4y = 13.95 – 18.33
-2y = -4.38
y = -4.38/-2 = 2.19
Substituting y in either of the equations to find x
3x + 2(2.19) = 13.95
3x + 4.38 – 4.38 = 13.95 – 4.38
3x = 9.57
x = 9.57/3 = 3.19
The price of a guppy is $3.19 and the price of platy is $2.19

Practice 8.3 Systems of Equations (Elimination) Answers Question 11.
Represent Real-World Problems The rule for the number of fish in a home aquarium is 1 gallon of water for each inch of fish length. Marta’s aquarium holds 13 gallons and Hank’s aquarium holds 17 gallons. Based on the number of fish they bought in Exercise 10, how long is a guppy and how long is a platy?
Length of a guppy = ________ inches
Length of a platy = ________ inches

Answer:
Length of a guppy = 3 inches
Length of a platy = 2 inches

Explanation:
3x + 2y = 13
3x + 4y = 17
where x is the length of guppy and y is the length of a platy
Subtract the equations
3x + 2y = 13
-(3x + 4y = 17)
x is eliminated as it has reversed coefficients. Solve for y
3x + 2y – 3x – 4y = 13 – 17
-2y = -4
y = -4/-2 = 2
Substituting y in either of the equation to find x
3x + 2(2) = 13
3x + 4 – 4 = 13 – 4
3x = 9
x = 9/3 = 3
The length of a guppy is 3 inches and price of a platy is 2 inches

Question 12.
Line m passes through the points (6, 1) and (2, -3). Line n passes through the points (2, 3) and (5, -6). Find the point of intersection of these lines.
Type below:
________________

Answer:
The intersection of these lines is (3.5, -1.5)

Explanation:
Find the slope of line m = (y2 – y1)/(x2 – x1) where (x2, y2) = (2, -3) and (x1, y1) = (6, 1)
Slope = (-3 -1)/(2 – 6) = -4/-4 = 1
Substitute the value of m and any of the given ordered pair (x, y) in the point-slope form of an equation: y – y1 = m(x – x1)
y – 1 = 1(x – 6)
y – 1 = x – 6
y = x – 6 + 1
x – y = 5
Find the slope of line n = (y2 – y1)/(x2 – x1) where (x2, y2) = (5, -6) and (x1, y1) = (2, 3)
Slope = (-6 -3)/(5 – 2) = -9/3 = -3
Substitute the value of m and any of the given ordered pair (x, y) in the point-slope form of an equation: y – y1 = m(x – x1)
y – 3 = -3(x – 2)
y – 3 = -3x + 6
y = -3x + 6 + 3
3x + y = 9
Add the equations
x – y = 5
+(3x + y = 9)
y is eliminated as it has reversed coefficients. Solve for x
x – y + 3x + y = 5 + 9
4x = 14
x = 14/4 = 3.5
Substituting x in either of the equations to find y
3.5 – y = 5
3.5 – y – 3.5 = 5 – 3.5
-y = 1.5
y = -1.5
The intersection of these lines is (3.5, -1.5)

Question 13.
Represent Real-World Problems Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. The oil change for one car required 5 quarts of oil and cost $22.45. The oil change for the other car required 7 quarts of oil and cost $25.45. How much is the labor fee and how much is each quart of oil?
Labor fee: $ ________
Quart of oil: $ ________

Answer:
Labor fee: $ 14.95
Quart of oil: $ 1.5

Explanation:
5x + y = 22.45
7x + y = 25.45
where x is the unit cost of quarts of oil and y is the flat fee for labor
Subtract the equations
5x + y = 22.45
-(7x + y = 25.45)
y is eliminated as it has reversed coefficients. Solve for x
5x + y – 7x – y = 22.45 – 25.45
-2x = -3
x = -3/-2 = 1.5
Substituting x in either of the equations to find y
5(1.5) + y = 22.45
7.5 + y – 7.5 = 22.45 – 7.5
y = 14.95
Labor fee is $14.95 and the unit cost of a quart of oil is $1.5

Solving System of Equations by Elimination Worksheet Answers Question 14.
Represent Real-World Problems A sales manager noticed that the number of units sold for two T-shirt styles, style A and style B, was the same during June and July. In June, total sales were $2779 for the two styles, with A selling for $15.95 per shirt and B selling for $22.95 per shirt. In July, total sales for the two styles were $2385.10, with A selling at the same price and B selling at a discount of 22% off the June price. How many T-shirts of each style were sold in June and July combined?
________ T-shirts of style A and style B were sold in June and July.

Answer:
15.95x + 22.95y = 2779
15.95x + 17.9y = 2385.10
where x is the number of style A shirts and y is the number of style B shirts
In July, the price of style B shirt is 22% of the price of style B shirt in June, hence 0.78(22.95) = 17.90
Subtract the equations
15.95x + 22.95y = 2779
-(15.95x + 17.9y = 2385.10)
x is eliminated as it has reversed coefficients. Solve for y
15.95x + 22.95 – 15.95x – 17.9y = 2779 – 2385.10
5.05y = 393.9
y = 393.9/5.05 = 78
Substituting y in either of the equations to find x
15.95x +22.95(78) = 2779
15.95x + 1790.1 – 1790.1 = 2779 – 1790.1
15.95x = 988.9
x = 988.9/15.95 = 62
The number of style A T-shirt sold in June is 62.
Since the number of T-shirts sold in both numbers is the same, the total number = 2. 62 = 124.
The number of style B T-shirts sold in June is 78.
Since the number of T-shirts sold in both numbers is the same, the total number = 2. 78 = 156.

Question 15.
Represent Real-World Problems Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,874 was collected on the sale of 1,246 tickets. How many of each type of ticket were sold?
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 3: Solving Systems by Elimination img 14img 14
________ adult tickets
________ student tickets

Answer:
407 adult tickets
839 student tickets

Explanation:
x + y = 1246
5x + y = 2874
where x is the number of adult tickets sold and y is the number of student tickets sold.
Subtract the equations
x + y = 1246
-(5x + y = 2874)
y is eliminated as it has reversed coefficients. Solve for x
x + y – 5x – y = 1246 – 2874
-4x = -1628
x = -1628/-4 = 407
Substituting x in either of the equations to find y
407 + y = 1246
407 + y – 407 = 1246 – 407
y = 839
The number of adult tickets sold is 407 and student tickets sold is 839.

FOCUS ON HIGHER ORDER THINKING – Solving Systems by Elimination – Page No. 250

Question 16.
Communicate Mathematical Ideas Is it possible to solve the system
\(\left\{\begin{array}{l}3x-2y=10 \\x+2y=6\end{array}\right.\)
by using substitution? If so, explain how. Which method, substitution or elimination, is more efficient? Why?
________

Answer:
The system can be solved by substitution as x in equation 2 can be isolated.
3x – 2y = 10
x + 2y = 6
Solve the equation for x in the equation.
x = -2y + 6
Substitute the expression for x in the other equation and solve.
3(-2y + 6) -2y = 10
-6y + 18 – 2y = 10
-8y + 18 = 10
-8y = -8
y = -8/-8 = 1
Substitute the values of y into one of the equations and solve for the other variable x.
x + 2(1) = 6
x = 4
The solution is (4, 1)
As the coefficient if variable y is opposite, it will be eliminated and solved for x in less number of steps.
Elimination would be more efficient.

Question 17.
Jenny used substitution to solve the system
\(\left\{\begin{array}{l}2x+y=8 \\x-y=1\end{array}\right.\). Her solution is shown below.
Step 1: y = -2x + 8               Solve the first equation for y.
Step 2: 2x + (-2x + 8) = 8     Substitute the value of y in an original equation.
Step 3: 2x – 2x + 8 = 8          Use the Distributive Property.
Step 4: 8 = 8                         Simplify.
a. Explain the Error Explain the error Jenny made. Describe how to correct it.
Type below:
______________

Answer:
2x + y = 8
x – y = 1
The rewritten equation should be substituted in the other original equation
Error is that Jenny solved for y in the first equation and substituted it in the original equation.
x – (-2x + 8) = 1
3x – 8 = 1
3x = 9
x = 9/3 = 3
x = 3

Question 17.
b. Communicate Mathematical Ideas Would adding the equations have been a better method for solving the system? If so, explain why.
________

Answer:
Yes

Explanation:
As the coefficient, if variable y is the opposite, it will be eliminated and solved for x in less number of steps.

Guided Practice – Solving Systems by Elimination with Multiplication – Page No. 256

Question 1.
Solve the system
\(\left\{\begin{array}{l}3x-y=8 \\-2x+4y=-12\end{array}\right.\)
by multiplying and adding.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 4: Solving Systems by Elimination with Multiplication img 15
Type below:
______________

Answer:
\(\left\{\begin{array}{l}3x-y=8 \\-2x+4y=-12\end{array}\right.\)
Multiply each term in the first equation by 4 to get opposite coefficients for the y-terms.
4(3x – y = 8)
12x – 4y = 32
Add the second equation to the new equation
12x – 4y = 32
+(-2x + 4y = -12)
Add to eliminate the variable y
10x = 20
Divide both sides by 10
x = 20/10 = 2
Substitute into one of the original equations and solve for y
y = 3(2) – 8 = -1
S0, (2, -2)is the solution of the system.

Solve each system of equations by multiplying first.

Question 2.
\(\left\{\begin{array}{l}x+4y=2 \\2x+5y=7\end{array}\right.\)
(________ , ________ )

Answer:
(6, -1)

Explanation:
x + 4y = 2
2x + 5y = 7
To eliminate x terms, multiply the 2nd equation by 2
2(x + 4y = 2)
2x + 8y = 4
Subtract the equations
2x + 8y = 4
-(2x + 5y = 7)
x is eliminated as it has reversed coefficients. Solve for y
2x + 8y – 2x – 5y = 4 – 7
3y = -3
y = -3/3 = -1
Substituting y in either of the equations to find x
x + 4(-1) = 2
x – 4 + 4 = 2 + 4
x = 6
Solution: (6, -1)

Question 3.
\(\left\{\begin{array}{l}3x+y=-1 \\2x+3y=18\end{array}\right.\)
(________ , ________ )

Answer:
(-3, 8)

Explanation:
\(\left\{\begin{array}{l}3x+y=-1 \\2x+3y=18\end{array}\right.\)
To eliminate y terms, multiply the 1st equation by 3
3(3x + y = -1)
9x + 3y = -3
Subtract the equations
9x + 3y = -3
-(2x + 3y = 18)
y is eliminated as it has reversed coefficients. Solve for x
9x + 3y – 2x – 3y = -3 -18
7x = -21
x = -21/7
x = -3
Substituting x in either of the equations to find y
3(-3) + y = -1
-9 + y + 9 = -1 + 9
y = 8
Solution: (-3, 8)

Question 4.
\(\left\{\begin{array}{l}2x+8y=21 \\6x-4y=14\end{array}\right.\)
Type below:
______________

Answer:
The solution is (3.5, 1.75)

Explanation:
\(\left\{\begin{array}{l}2x+8y=21 \\6x-4y=14\end{array}\right.\)
To eliminate y terms, multiply the 2nd equation by 2
2(6x – 4y = 14)
2x + 8y = 21
Add the equations
2x + 8y = 21
+(12x – 8y = 28)
y is eliminated it has reversed coefficients. Solve for x
2x + 8y + 12x – 8y = 21 + 28
14x = 49
x = 49/14 = 3.5
Substituting x in either of the equations to find y
6(3.5) – 4y = 14
21 – 4y – 21 = 14 – 21
-4y = -7
y = -7/-4 = 1.75
The solution is (3.5, 1.75)

Question 5.
\(\left\{\begin{array}{l}2x+y=3 \\-x+3y=-12\end{array}\right.\)
(________ , ________ )

Answer:

Explanation:
\(\left\{\begin{array}{l}2x+y=3 \\-x+3y=-12\end{array}\right.\)
To eliminate x terms, multiply the 2nd equation by 2
2(-x + 3y = -12)
-2x + 6y = -24
Add the equations
2x + y = 3
+(-2x + 6y = -24)
x is eliminated it has reversed coefficients. Solve for y
2x + y – 2x + 6y = 3 – 24
7y = -21
y = -21/7 = -3
Substituting y in either of the equations to find x
-x + 3(-3) = -12
-x -9 + 9 = -12 + 9
-x = -3
x = 3
The soultion is (3, -3)

Question 6.
\(\left\{\begin{array}{l}6x+5y=19 \\2x+3y=5\end{array}\right.\)
(________ , ________ )

Answer:
The solution is (4, -1)

Explanation:
\(\left\{\begin{array}{l}6x+5y=19 \\2x+3y=5\end{array}\right.\)
To eliminate x terms, multiply the 2nd equation by 3
3(2x + 3y = 5)
6x + 9y = 15
Subtract the equations
6x + 5y = 19
-(6x + 9y = 15)
x is eliminated it has reversed coefficients. Solve for y
6x + 5y – 6x – 9y = 19 – 15
-4y = 4
y = 4/-4 = -1
Substituting y in either of the equations to find x
2x + 3(-1) = 5
2x – 3 + 3 = 5 + 3
2x = 8
x = 8/2 = 4
The solution is (4, -1)

Question 7.
\(\left\{\begin{array}{l}2x+5y=16 \\-4x+3y=20\end{array}\right.\)
(________ , ________ )

Answer:
The solution is (-2, 4)

Explanation:
\(\left\{\begin{array}{l}2x+5y=16 \\-4x+3y=20\end{array}\right.\)
To eliminate x terms, multiply the 1st equation by 2
2(2x + 5y = 16)
4x + 10y = 32
Add the equations
4x + 10y = 32
+(-4x + 3y = 20)
x is eliminated it has reversed coefficients. Solve for y
10y + 3y = 32 + 20
13y = 52
y = 52/13 = 4
Substituting y in either of the equations to find x
2x + 5(4) = 16
2x + 20 – 20 = 16 – 20
2x = -4
x = -4/2 = -2
The solution is (-2, 4)

Question 8.
Bryce spent $5.26 on some apples priced at $0.64 each and some pears priced at $0.45 each. At another store he could have bought the same number of apples at $0.32 each and the same number of pears at $0.39 each, for a total cost of $3.62. How many apples and how many pears did Bryce buy?
a. Write equations to represent Bryce’s expenditures at each store
First store: _____________
Second store: _____________
Type below:
_____________

Answer:
First store: 0.64x + 0.45y = 5.26
Second store: 0.32x + 0.39y = 3.62

Explanation:
First store = 0.64x + 0.45y = 5.26
Second store = 0.32x + 0.39y = 3.62
where x is the number of apples and y is the number of pears.

Question 8.
b. Solve the system.
Number of apples: _______
Number of pears: _______

Answer:
Number of apples: 4
Number of pears: 6

Explanation:
First store = 0.64x + 0.45y = 5.26
Second store = 0.32x + 0.39y = 3.62
Multiply by 100
64x + 45y = 526
32x + 39y = 362
To eliminate x terms, multiply the 2nd equation by 2
2(32x + 39y = 362)
64x + 45y = 526
Subtract the equations
64x + 45y = 526
-(64x + 78y = 724)
x is eliminated it has reversed coefficients. Solve for y
64x + 45y – 64x – 78y = 526 – 724
-33y = -198
y = -198/-33 = 6
Substituting y in either of the equation to find x
32x + 39(6) = 362
32x + 234 – 234 = 362 – 234
32x = 128
x = 128/32 = 4
He bought 4 apples and 6 pears.

ESSENTIAL QUESTION CHECK-IN

Question 9.
When solving a system by multiplying and then adding or subtracting, how do you decide whether to add or subtract?
Type below:
_____________

Answer:
If the variable with the same coefficient but a reversed sign, we add and if they have the same sign, we subtract.

Solving Systems by Elimination with Multiplication – Page No. 257

Question 10.
Explain the Error Gwen used elimination with multiplication to solve the system
\(\left\{\begin{array}{l}2x+6y=3 \\x-3y=-1\end{array}\right.\)
Her work to find x is shown. Explain her error. Then solve the system.
2(x − 3y) = -1
2x − 6y = -1
+2x + 6y = 3
_____________
4x + 0y = 2
x = \(\frac{1}{2}\)
Type below:
____________

Answer:
2x + 6y = 3
x – 3y = -1
To eliminate x terms, multiply the 2nd equation by 2
2(x – 3y = -1)
2x – 6y = -2
Error is the Gnew did not multiply the entire expression with 2.
Add the equations
2x + 6y = 3
+(2x – 6y = -2)
y is eliminated it has reversed coefficients. Solve for x
2x + 6y + 2x – 6y = 3 – 2
4x = 1
x = 1/4
Substituting x in either of the equations to find y
x – 3y = -1
1/4 – 3y – 1/4 = -1 -1/4
-3y = -5/4
y = -5/4(-3) = 5/12

Question 11.
Represent Real-World Problems At Raging River Sports, polyester-fill sleeping bags sell for $79. Down-fill sleeping bags sell for $149. In one week the store sold 14 sleeping bags for $1,456.
a. Let x represent the number of polyester-fill bags sold and let y represent the number of down-fill bags sold. Write a system of equations you can solve to find the number of each type sold.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 4: Solving Systems by Elimination with Multiplication img 16
Type below:
____________

Answer:
x + y = 14
79x + 149y = 1456
where x is the polyester-fill bags and y is the number of down-fill bags

Question 11.
b. Explain how you can solve the system for y by multiplying and subtracting.
Type below:
____________

Answer:
x + y = 14
79x + 149y = 1456
Multiply the second equation by 79. Subtract the new equation from the first equation and solve the resulting equation for y.

Question 11.
c. Explain how you can solve the system for y using substitution.
Type below:
____________

Answer:
Solve the second equation for x. Substitute the expression for x , in the first equation and solve the resulting equation for y.

Question 11.
d. How many of each type of bag were sold?
_______ polyester-fill
_______ down-fill

Answer:
9 polyester-fill
5 down-fill

Explanation:
x + y = 14
79x + 149y = 1456
To eliminate x terms, multiply the 2nd equation by 2
79(x + y = 14)
79x + 149y = 1456
Subtract the equations
79x + 79y = 1106
-(79x + 149y = 1456)
x is eliminated it has reversed coefficients. Solve for y
79x + 79y – 79x – 149y = 1106 – 1456
-70y = -350
y = -350/-70 = 5
Substituting y in either of the equations to find x
x + 5 = 14
x = 14 – 5
x = 9
There were 9 polyester-fill bags and 5 down-fill bags sold.

Question 12.
Twice a number plus twice a second number is 310. The difference between the numbers is 55. Find the numbers by writing and solving a system of equations. Explain how you solved the system.
x = _______
y = _______

Answer:
x = 105
y = 50

Explanation:
2x + 2y = 310
x – y = 55
To eliminate y terms, multiply the 2nd equation by 2
2(x – y = 55)
2x – 2y = 110
Add the equations
2x + 2y = 310
+ (2x – 2y = 110)
y is eliminated it has reversed coefficients. Solve for x
2x + 2y + 2x – 2y = 310 + 110
4x = 420
x = 420/4 = 105
Substituting x in either of the equations to find y
105 – y = 55
y = 105 – 55
y = 50
The solution is (105, 50)

Solving Systems by Elimination with Multiplication – Page No. 258

Question 13.
Represent Real-World Problems A farm stand sells apple pies and jars of applesauce. The table shows the number of apples needed to make a pie and a jar of applesauce. Yesterday, the farm picked 169 Granny Smith apples and 95 Red Delicious apples. How many pies and jars of applesauce can the farm make if every apple is used?
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 4: Solving Systems by Elimination with Multiplication img 17
_______ pies
_______ jars of applesauce

Answer:
21 pies
16 jars of applesauce

Explanation:
5x + 4y = 169
3x + 2y = 95
where x is the number of apples needed for pie and y is the number of apples for jar of applesauce
To eliminate y terms, multiply the 2nd equation by 2
2(3x + 2y = 95)
6x + 4y = 190
Subtract the equations
5x + 4y = 169
– (6x + 4y = 190)
y is eliminated it has reversed coefficients. Solve for x
5x + 4y – 6x – 4y = 169 – 190
-x = -21
x = -21/-1 = 21
Substituting x in either of the equation to find y
5(21) + 4y = 169
105 + 4y – 105 = 169 – 105
4y = 64
y = 64/4 = 16
The number of apples needed for pie is 21 and the number of apples for jar of applesauce is 16.

FOCUS ON HIGHER ORDER THINKING

Question 14.
Make a Conjecture Lena tried to solve a system of linear equations algebraically and in the process found the equation 5 = 9. Lena thought something was wrong, so she graphed the equations and found that they were parallel lines. Explain what Lena’s graph and equation could mean.
Type below:
____________

Answer:
Lena’s graph is a parallel line which means the graph does not intersect each other, hence they have no solutions. Equation 5 = 9 means variables are eliminated and this statement is not true. This linear system has no solution.

Question 15.
Consider the system
\(\left\{\begin{array}{l}2x+3y=6 \\3x+7y=-1\end{array}\right.\)
a. Communicate Mathematical Ideas Describe how to solve the system by multiplying the first equation by a constant and subtracting. Why would this method be less than ideal?
Type below:
____________

Answer:
Multiplying the first equation by a constant and subtracting
2x + 3y = 6
3x + 7y = -1
Multiply the first equation by 1.5 and subtract. This would be less than ideal because you would introduce decimals into the solution process.

Question 15.
b. Draw Conclusions Is it possible to solve the system by multiplying both equations by integer constants? If so, explain how.
Type below:
____________

Answer:
Yes

Explanation:
Multiply the first equation by 3 and the second equation by 2. Both x-term coefficients would be 6. Solve by eliminating the x-terms using subtraction.

Question 15.
c. Use your answer from part b to solve the system.
(_______ , _______)

Answer:
(9, -4)

Explanation:
2x + 3y = 6
3x + 7y = -1
Multiply the first equation by 3 and the second equation by 2.
3(2x + 3y = 6)
2(3x + 7y = -1)
Subtract the equations
6x + 9y = 18
-(6x + 14y = -2)
x is eliminated it has reversed coefficients. Solve for y
6x + 9y – 6x – 14y = 18 + 2
-5y = 20
y = 20/-5 = -4
Substituting y in either of the equation to find x
2x + 3(-4) = 6
2x = 18
x = 18/2 = 9
The solution is (9, -4)

Guided Practice – Solving Solving Special Systems – Page No. 262

Use the graph to solve each system of linear equations

Question 1.
A. \(\left\{\begin{array}{l}4x-2y=-6 \\2x-y=4\end{array}\right.\)
B. \(\left\{\begin{array}{l}4x-2y=-6 \\x+y=6\end{array}\right.\)
C. \(\left\{\begin{array}{l}2x-y=4 \\6x-3y=-12\end{array}\right.\)
STEP 1 Decide if the graphs of the equations in each system intersect, are parallel, or are the same line.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 5: Solving Solving Special Systems img 18
System A: The graphs __________
System B: The graphs __________
System C: The graphs __________

Answer:
System A: The graphs are parallel
System B: The graphs are intersecting
System C: The graphs are  the same line

Explanation:
System A: 4x – 2y = -6
2x – y = 4
System B: 4x – 2y = -6
x + y = 6
System C: 2x – y = 4
6x – 3y = 12

Question 1.
STEP 2 Decide how many points the graphs have in common.
a. Intersecting lines have _______________ point(s) in common.
b. Parallel lines have _______________ point(s) in common.
c. The same lines have ___________ point(s) in common.
a. __________
b. __________
c. __________

Answer:
a. Intersecting lines have one point(s) in common.
b. Parallel lines have no point(s) in common.
c. The same lines have infinitely many points (s) in common.

Explanation:
From the graphs,
Intersecting lines have one point(s) in common
Parallel lines have no point(s) in common
The same lines have infinitely many points (s) in common

Question 1.
STEP 3 Solve each system.
System A has __________ points in common, so it has __________ solution.
System B has __________ point in common. That point is the solution, __________.
System C has __________ points in common. ________ ordered pairs on the line will make both equations true.
Type below:
___________

Answer:
System A has no points in common, so it has no solution. System B has one point in common. That point is the solution, (1,5). System C has an infinite number of points in common. All ordered pairs on the line will make both equations true.

Explanation:
Number of solutions for each system
System A has no points in common, so it has no solution. System B has one point in common. That point is the solution, (1,5). System C has an infinite number of points in common. All ordered pairs on the line will make both equations true.

Solve each system. Tell how many solutions each system has.

Question 2.
\(\left\{\begin{array}{l}x-3y=4 \\-5x+15y=-20\end{array}\right.\)
___________

Answer:
infinitely many solutions

Explanation:
x – 3y = 4
-5x + 15y = -20
To eliminate y terms, multiply the 1st equation by 5
5(x – 3y = 4)
5x – 15y = 20
Add the equations
5x – 15y = 20
+(-5x + 15y = -20)
x and y is eliminated as it has reversed coefficients.
5x – 15y – 5x + 15y = 20 – 20
0 = 0
The statement is true, hence the solution has infinitely many solutions.

Question 3.
\(\left\{\begin{array}{l}6x+2y=-4 \\3x+y=4\end{array}\right.\)
___________

Answer:
no solution

Explanation:
6x + 2y = -4
3x + y = 4
To eliminate y terms, multiply the 2nd equation by 5
2(3x + y = 4)
6x + 2y = 8
Subtract the equations
6x + 2y = -4
-(6x + 2y = 8)
x and y is eliminated as it has reversed coefficients.
6x + 2y – 6x – 2y = -4 -8
0 = -12
The statement is false, hence the solution has no solution.

Question 4.
\(\left\{\begin{array}{l}6x-2y=-10 \\3x+4y=-25\end{array}\right.\)
___________

Answer:
one solution

Explanation:
6x – 2y = -10
3x + 4y = -25
To eliminate y terms, multiply the 1st equation by 2
2(6x – 2y = -10)
12x – 4y = -20
Add the equations
12x – 4y = -20
+(3x + 4y = -25)
y is eliminated as it has reversed coefficients. Solve for x.
12x – 4y + 3x + 4y = -20 – 25
15x = -45
x = -45/15 = -3
Substitute x in any one of the original equations and solve for y
3(-3) + 4y = -25
-9 + 4y + 9 = -25 + 9
4y = -16
y = -16/4
y = -4
There is one solution, (-3, -4)

ESSENTIAL QUESTION CHECK-IN

Question 5.
When you solve a system of equations algebraically, how can you tell whether the system has zero, one, or an infinite number of solutions?
Type below:
___________

Answer:
When x and y are eliminated and the statement is true, the system has infinitely many solutions.
When x and y are eliminated and the statement is false, the system has no solutions.
When the system has one solution by solving, the system has one solution.

8.5 Independent Practice – Solving Solving Special Systems – Page No. 263

Solve each system by graphing. Check your answer algebraically.

Question 6.
\(\left\{\begin{array}{l}-2x+6y=12 \\x-3y=3\end{array}\right.\)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 5: Solving Solving Special Systems img 19
Solution: ______________
___________

Answer:
\(\left\{\begin{array}{l}-2x+6y=12 \\x-3y=3\end{array}\right.\)
Graph the equations on same coordinate plane
No solution as equations are parallel
grade 8 chapter 8 image 1
To eliminate y terms, multiply the 2nd equation by 2
2(x – 3y = 3)
2x – 6y = 6
Add the equations
-2x + 6y = 12
2x – 6y = 6
x and y is eliminated as it has reversed coefficients.
-2x + 6y + 2x – 6y = 12 + 6
0 = 18
The statement is false, hence the system has no solution.

Question 7.
\(\left\{\begin{array}{l}15x+5y=5 \\3x+y=1\end{array}\right.\)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 5: Solving Solving Special Systems img 20
Solution: ______________
___________

Answer:
\(\left\{\begin{array}{l}15x+5y=5 \\3x+y=1\end{array}\right.\)
Graph the equations on same coordinate plane
grade 8 chapter 8 image 2
Infinitely many solutions as equations are overlapping
To eliminate y terms, multiply the 2nd equation by 5
5(3x + y = 1)
15x + 5y = 5
Subtarct the equations
15x + 5y = 5
-(15x + 5y = 5)
x and y is eliminated as it has reversed coefficients.
15x + 5y -15x – 5y = 5 – 5
0 = 0
The statement is true, hence the system has infinitely many solutions.

For Exs. 8–14, state the number of solutions for each system of linear equations

Question 8.
a system whose graphs have the same slope but different y-intercepts
___________

Answer:
No solutions

Explanation:
Equations are parallel
No solutions

Question 9.
a system whose graphs have the same y-intercepts but different slopes
___________

Answer:
One solution

Explanation:
Equations are intersecting
One solution

Question 10.
a system whose graphs have the same y-intercepts and the same slopes
___________

Answer:
Infinitely many solutions

Explanation:
Equations are overlapping
Infinitely many solutions

Question 11.
a system whose graphs have different y-intercepts and different slopes
___________

Answer:
One solution

Explanation:
Equations are intersecting
One solution

Question 12.
the system
\(\left\{\begin{array}{l}y=2 \\y=-3\end{array}\right.\)
___________

Answer:
No solutions

Explanation:
Equations are parallel
No solutions

Question 13.
the system
\(\left\{\begin{array}{l}y=2 \\y=-3\end{array}\right.\)
___________

Answer:
One solution

Explanation:
Equations are intersecting
One solution

Question 14.
the system whose graphs were drawn using these tables of values:
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 5: Solving Solving Special Systems img 21
___________

Answer:
No solutions

Explanation:
Equations are parallel The slope is the same for both equations but the y-intercept is different.
No solutions

Question 15.
Draw Conclusions The graph of a linear system appears in a textbook. You can see that the lines do not intersect on the graph, but also they do not appear to be parallel. Can you conclude that the system has no solution? Explain.
___________

Answer:

No; although the lines do not intersect on the graph, they intersect at a point that is not on the graph. To prove that a system has no solution, you must do so algebraically

Solving Solving Special Systems – Page No. 264

Question 16.
Represent Real-World Problems Two school groups go to a roller skating rink. One group pays $243 for 36 admissions and 21 skate rentals. The other group pays $81 for 12 admissions and 7 skate rentals. Let x represent the cost of admission and let y represent the cost of a skate rental. Is there enough information to find values for x and y? Explain.
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Lesson 5: Solving Solving Special Systems img 22
___________

Answer:
36x + 21y = 243
12x + 7y = 81
where x is the cost of admission and y is the cost of stake rentals.
Although the information can be used to develop a system of linear equations, where each equation has two variables when the system is solved, the number of solutions is infinite, Mee the values of x and y cannot be determined.
No

System of Linear Equations Answer Key Question 17.
Represent Real-World Problems Juan and Tory are practicing for a track meet. They start their practice runs at the same point, but Tory starts 1 minute after Juan. Both run at a speed of 704 feet per minute. Does Tory catch up to Juan? Explain.
___________

Answer:
No; Both Juan and Tory run at the same rate, so the lines representing the distances each has run are parallel. There is no solution to the system

FOCUS ON HIGHER ORDER THINKING

Question 18.
Justify Reasoning A linear system with no solution consists of the equation y = 4x − 3 and a second equation of the form y = mx + b. What can you say about the values of m and b? Explain your reasoning.
Type below:
___________

Answer:
y = 4x – 3
y = mx + b
Since the system has no solutions, the two equations are parallel. The value of the slope, m would be the same i.e. 4.
The value of y-intercept, b can be any number except -3 as b is different for parallel lines.

Question 19.
Justify Reasoning A linear system with infinitely many solutions consists of the equation 3x + 5 = 8 and a second equation of the form Ax + By = C. What can you say about the values of A, B, and C? Explain your reasoning.
Type below:
___________

Answer:
3x + 5 = 8
Ax + By = C
Since the system has infinitely many solutions, the values of A, B, and C must all be the same multiple of 3, 5, and 8, respectively. The two equations represent a single line, so the coefficients and constants of one equation must be a multiple of the other.

Question 20.
Draw Conclusions Both points (2, -2) and (4, -4) are solutions of a system of linear equations. What conclusions can you make about the equations and their graphs?
Type below:
___________

Answer:
If a system has more than one solution, the equations represent the same line and have infinitely many solutions.

Ready to Go On? – Model Quiz – Page No. 265

8.1 Solving Systems of Linear Equations by Graphing

Solve each system by graphing.

Question 1.
\(\left\{\begin{array}{l}y=x-1 \\y=2x-3\end{array}\right.\)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Model Quiz img 23
(________ , ________)

Answer:
(2, 1)

Explanation:
y = x – 1
y = 2x – 3
Graph the equations on the same coordinate plane
grade 8 chapter 8 image 3
The solution of the system is the point of intersection
The solution is (2, 1)

Lesson 1 Solve Systems of Equations by Graphing Answers Question 2.
\(\left\{\begin{array}{l}x+2y=1 \\-x+y=2\end{array}\right.\)
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Model Quiz img 24
(________ , ________)

Answer:
(-1, 1)

Explanation:
x + 2y = 1
-x + y = 2
Graph the equations on same coordinate plane
grade 8 chapter 8 image 4
The solution of the system is the point of intersection
The solution is (-1, 1)

8.2 Solving Systems by Substitution

Solve each system of equations by substitution.

Question 3.
\(\left\{\begin{array}{l}y=2x \\x+y=-9\end{array}\right.\)
(________ , ________)

Answer:
(-3, -6)

Explanation:
y = 2x
x + y = -9
Substitute y from equation 1 in the other equation.
x + 2x = -9
3x = -9
x = -9/3
x = -3
Then, y = 2(-3) = -6
The Solution is (-3, -6)

Question 4.
\(\left\{\begin{array}{l}3x-2y=11 \\x+2y=9\end{array}\right.\)
(________ , ________)

Answer:
(5, 2)

Explanation:
3x – 2y = 11
x + 2y = 9
Solve for x in equation 2
x = – 2y + 9
Substitute x from equation 2 in the other equation
3(-2y + 9) – 2y = 11
-6y + 27 -2y = 11
-8y = -16
y = -16/-8 = 2
Substitute y in any of the equations to find x
x + 2(2) = 9
x + 4 – 4 = 9 – 4
x = 5
The solution is (5, 2)

8.3 Solving Systems by Elimination

Solve each system of equations by adding or subtracting.

Question 5.
\(\left\{\begin{array}{l}3x+y=9 \\2x+y=5\end{array}\right.\)
(________ , ________)

Answer:
(4, -3)

Explanation:
\(\left\{\begin{array}{l}3x+y=9 \\2x+y=5\end{array}\right.\)
Subtract the equations
3x + y = 9
-(2x + y = 5)
y is eliminated as it has reversed coefficients. Solve for x
3x + y – 2x – y = 9 – 5
x = 4
Substituting x in either of the equation to find y
2(4) + y = 5
8 + y – 8 = 5 – 8
y = -3
The solution is (4, -3)

Question 6.
\(\left\{\begin{array}{l}-x-2y=4 \\3x+2y=4\end{array}\right.\)
(________ , ________)

Answer:
(4, -4)

Explanation:
\(\left\{\begin{array}{l}-x-2y=4 \\3x+2y=4\end{array}\right.\)
Add the equations
-x – 2y = 4
+(3x + 2y = 4)
y is eliminated as it has reversed coefficients. Solve for x
-x – 2y + 3x + 2y = 4 + 4
2x = 8
x = 8/2 = 4
Substituting x in either of the equation to find y
3(4) + 2y = 4
12 + 2y – 12 = 4 – 12
2y = -8
y = -8/2 = -4
The solution is (4, -4)

8.4 Solving Systems by Elimination with Multiplication

Solve each system of equations by multiplying first.

Question 7.
\(\left\{\begin{array}{l}x+3y=-2 \\3x+4y=-1\end{array}\right.\)
(________ , ________)

Answer:
(1, -1)

Explanation:
\(\left\{\begin{array}{l}x+3y=-2 \\3x+4y=-1\end{array}\right.\)
Subtract the equations
3x + 9y = -6
-(3x + 4y = -1)
x is eliminated as it has reversed coefficients. Solve for y
3x + 9y – 3x – 4y = -6 + 1
5y = -5
y = -5/5
y = -1
Substituting y in either of the equation to find x
x + 3(-1) = -2
x – 3 = -2
x = -2 + 3
x = 1
The solution is (1, -1)

Solving Systems of Equations Algebraically Worksheet Question 8.
\(\left\{\begin{array}{l}2x+8y=22 \\3x-2y=5\end{array}\right.\)
(________ , ________)

Answer:
(3, 2)

Explanation:
\(\left\{\begin{array}{l}2x+8y=22 \\3x-2y=5\end{array}\right.\)
Multiply equation 2 by 4 so that y can be eliminated
4(3x – 2y = 5)
12x – 8y = 20
Add the equations
2x + 8y = 22
+(12x – 8y = 20)
y is eliminated as it has reversed coefficients. Solve for x
2x + 8y + 12x – 8y = 22 + 20
14x = 42
x = 42/14
x = 3
Substituting y in either of the equation to find x
2(3) + 8y = 22
6 + 8y = 22
8y = 22 – 6
8y = 16
y = 16/8
y = 2
The solution is (3, 2)

8.5 Solving Special Systems

Solve each system. Tell how many solutions each system has.

Question 9.
\(\left\{\begin{array}{l}-2x+8y=5 \\x-4y=-3\end{array}\right.\)
_____________

Answer:
no solution

Explanation:
\(\left\{\begin{array}{l}-2x+8y=5 \\x-4y=-3\end{array}\right.\)
Multiply equation 2 by 2 so that y can be eliminated
2(x – 4y = -3)
2x – 8y = -6
Add the equations
-2x + 8y = 5
+(2x – 8y = -6)
x and y is eliminated
-2x + 8y + 2x – 8y = 5 – 6
0 = -1
The statement is false. Hence, the system has no solution.

Question 10.
\(\left\{\begin{array}{l}6x+18y=-12 \\x+3y=-2\end{array}\right.\)
_____________

Answer:
infinitely many solutions

Explanation:
\(\left\{\begin{array}{l}6x+18y=-12 \\x+3y=-2\end{array}\right.\)
Multiply equation 2 by 6 so that x can be eliminated
6(x + 3y = -2)
6x + 18y = -12
Subtract the equations
6x + 18y = -12
-(6x + 18y = -12)
x and y is eliminated
6x + 18y -6x -18y = -12 + 12
0 = 0
The statement is true. Hence, the system has infinitely many solutions.

ESSENTIAL QUESTION

Question 11.
What are the possible solutions to a system of linear equations, and what do they represent graphically?
Type below:
___________

Answer:
A system of linear equations can have no solution, which is represented by parallel lines; one solution, which is represented by intersecting lines; and infinitely many solutions, which is represented by overlapping lines.

Selected Response – Mixed Review – Page No. 266

Question 1.
The graph of which equation is shown?
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Mixed Review img 25
Options:
A. y = −2x + 2
B. y = −x + 2
C. y = 2x + 2
D. y = 2x + 1

Answer:
C. y = 2x + 2

Explanation:
Options A and B are eliminated as the slope of the graph is 2.
Option D is eliminated as the y-intercept from the graph should be 2.
Option C is the equation of the graph

Question 2.
Which best describes the solutions to the system
\(\left\{\begin{array}{l}x+y=-4 \\-2x-2y=0\end{array}\right.\)
Options:
A. one solution
B. no solution
C. infinitely many
D. (0, 0)

Answer:
B. no solution

Explanation:
\(\left\{\begin{array}{l}x+y=-4 \\-2x-2y=0\end{array}\right.\)
Multiply equation 1 by 2 so that x can be eliminated
2(x + y = -4)
2x + 2y = -8
Add the equations
2x + 2y = -8
-2x – 2y = 0
x and y is eliminated
2x + 2y – 2x -2y = -8 + 0
0 = -8
The statement is false. Hence, the system has no solution.

Question 3.
Which of the following represents 0.000056023 written in scientific notation?
Options:
A. 5.6023 × 105
B. 5.6023 × 104
C. 5.6023 × 10-4
D. 5.6023 × 10-5

Answer:
D. 5.6023 × 10-5

Explanation:
Move the decimal 5 points right to get the equation.
D. 5.6023 × 10-5

Question 4.
What is the solution to
\(\left\{\begin{array}{l}2x-y=1 \\4x+y=11\end{array}\right.\)
Options:
A. (2, 3)
B. (3, 2)
C. (-2, 3)
D. (3, -2)

Answer:
A. (2, 3)

Explanation:
\(\left\{\begin{array}{l}2x-y=1 \\4x+y=11\end{array}\right.\)
Add the equations
2x – y = 1
4x + y = 11
y is eliminated as it has reversed coefficients. Solve for x.
2x – y + 4x + y = 1 + 11
6x = 12
x = 12/6 = 2
Substituting x in either of the equations to find y
4(2) + y = 11
8 + y = 11
y = 11 – 8
y = 3
The solution is (2, 3)

Question 5.
Which expression can you substitute in the indicated equation to solve
\(\left\{\begin{array}{l}3x-y=5 \\x+2y=4\end{array}\right.\)
Options:
A. 2y – 4 for x in 3x – y = 5
B. 4 – x for y in 3x – y = 5
C. 3x – 5 for y in 3x – y = 5
D. 3x – 5 for y in x + 2y = 4

Answer:
D. 3x – 5 for y in x + 2y = 4

Explanation:
\(\left\{\begin{array}{l}3x-y=5 \\x+2y=4\end{array}\right.\)
Solve for y in equation 1
y = 3x – 5
Substitute in other equation x + 2y = 4

Question 6.
What is the solution to the system of linear equations shown on the graph?
Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Mixed Review img 26
Options:
A. -1
B. -2
C. (-1, -2)
D. (-2, -1)

Answer:
C. (-1, -2)

Explanation:
The point of intersection is (-1, -2), which is the solution of the system

Question 7.
Which step could you use to start solving
\(\left\{\begin{array}{l}x-6y=8 \\2x-5y=3\end{array}\right.\)
Options:
A. Add 2x – 5y = 3 to x – 6y = 8.
B. Multiply x – 6y = 8 by 2 and add it to 2x – 5y = 3.
C. Multiply x – 6y = 8 by 2 and subtract it from 2x – 5y = 3.
D. Substitute x = 6y – 8 for x in 2x – 5y = 3.

Answer:
C. Multiply x – 6y = 8 by 2 and subtract it from 2x – 5y = 3.

Explanation:
x – 6y = 8
2x – 5y = 3
Multiply the 1st equation by 2 so that the coefficient of variable x is the same in both equations
Subtract the equations as x has the same sign.

Mini-Task

Question 8.
A hot-air balloon begins rising from the ground at 4 meters per second at the same time a parachutist’s chute opens at a height of 200 meters. The parachutist descends at 6 meters per second.
a. Define the variables and write a system that represents the situation.
Type below:
_____________

Answer:
y represents the distance from the ground and x represents the time in seconds
y = 4x
y = -6x + 200

Question 8.
b. Find the solution. What does it mean?
Type below:
_____________

Answer:
Substitute y from the equation 1 in the equation 2
4x = -6x + 200
4x + 6x = -6x + 200 + 6x
10x = 200
x = 200/10 = 20
Substitute x in any one of the equations and solve for x
y = 4(20) = 80
The solution is (20, 80)
The balloon and parachute meet after 20sec at 80m from the ground.

Conclusion:

Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations PDF for all the students who want to learn maths. See the Grade 8 Chapter 8 questions along with answers and explanations. Immediately start your practice now.

Go Math Grade 8 Answer Key Chapter 8 Solving Systems of Linear Equations Read More »

go-math-grade-8-answer-key-chapter-9-transformations-and-congruence

Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence

Fins multiple ways to solve Math problems. Choose the best and easy way to solve your math problems present on Go Math Text Book. Every student’s first preference to practice maths is Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence. Go Math Grade 8 Chapter 9 Transformations and Congruence Answer Key along with different explanations makes students’ math practice easy and simple. Refer to Go Math Grade 8 Answer Key to learn maths.

Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence

As many ways of problem-solving methods are available on Go Math Grade 8 Chapter 9 Transformations and Congruence Solution Key, student’s can select the easy solving method and learn the method of solving math problems. Also, images are included for a better understanding of the student. Therefore, students who want to score good marks in the exam must practice with Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence.

Lesson 1: Properties of Translations

Lesson 2: Properties of Reflections

Lesson 3: Algebraic Representations of Transformations

Lesson 4: Congruent Figures

Model Quiz

Mixed Review

Guided Practice – Properties of Translations – Page No. 282

Question 1.
Vocabulary A __________________is a change in the position, size, or shape of a figure.
____________

Answer:
transformation

Explanation:
A transformation is a change in the position, size, or shape of a figure.

Question 2.
Vocabulary When you perform a transformation of a figure on the coordinate plane, the input of the transformation is called the ________________, and the output of the transformation is called the_________________ .
Type below:
____________

Answer:
pre-image
image

Explanation:
When you perform a transformation of a figure on the coordinate plane, the input of the transformation is called the pre-image, and the output of the transformation is called the image.

Practice 9.1 Translations Answers Question 3.
Joni translates a right triangle 2 units down and 4 units to the right. How does the orientation of the image of the triangle compare with the orientation of the preimage?
Orientation is: _______

Answer:
Orientation is: Same

Explanation:
Since translation does not change the shape and size of a geometric figure, the two triangles are identical in shape and size, so they are congruent and the orientation is the same

Question 4.
Rashid drew a rectangle PQRS on a coordinate plane. He then translated the rectangle 3 units up and 3 units to the left and labeled the image P ‘Q ‘R ‘S ‘. How do rectangle PQRS and rectangle P ‘Q ‘R ‘S ‘ compare?
They are: _______

Answer:
congruent

Explanation:
Since translation does not change the shape and size of a geometric figure, the two rectangles are identical in shape and size, so they are congruent.

Question 5.
The figure shows trapezoid WXYZ. Graph the image of the trapezoid after a translation of 4 units up and 2 units to the left.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 1
Type below:
____________

Answer:
After translation:
W'(-4, 3)
X'(2, 3)
Y'(1, 1)
Z'(-3, 1)

ESSENTIAL QUESTION CHECK-IN

9.1 Reflections Homework Answer Key Question 6.
What are the properties of translations?
Type below:
____________

Answer:
A translation is a geometric transformation that moves every point of a figure or space by the same amount in a given direction. So the figures are identical and are congruent.

9.1 Independent Practice – Properties of Translations – Page No. 283

Question 7.
The figure shows triangle DEF.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 2
a. Graph the image of the triangle after the translation that maps point D to point D ‘.
Type below:
____________

Answer:
2 left, and 4 down

Question 7.
b. How would you describe the translation?
Type below:
____________

Answer:
It has the same size, shape. and orientation, but a different location

Question 7.
c. How does the image of triangle DEF compare with the preimage?
____________

Answer:
congruent

Quiz 9.1 Translations and Reflections Answers Question 8.
a. Graph quadrilateral KLMN with vertices K(-3, 2), L(2, 2), M(0, -3), and N(-4, 0) on the coordinate grid.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 3
Type below:
____________

Question 8.
b. On the same coordinate grid, graph the image of quadrilateral KLMN after a translation of 3 units to the right and 4 units up.
Type below:
____________

Answer:
grade 8 chapter 9 image 1

Question 8.
c. Which side of the image is congruent to side \(\overline { LM } \)?
___________
Name three other pairs of congruent sides.
___________
Type below:
____________

Answer:
Line LM is congruent to Line L!M!
Line KL is equal to K’L’
Line MN is equal to M’N’
Line KN is equal to K’N’

Draw the image of the figure after each translation.

Question 9.
4 units left and 2 units down
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 4
Type below:
____________

Answer:
After translation
P'(-3, 1)
Q'(0, 2)
R'(0, -1)
S'(-3, -3)

Question 10.
5 units right and 3 units up
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 5
Type below:
____________

Answer:
After translation
A'(0, 4)
B'(3, 5)
C'(3, 1)
D'(0, 0)

Properties of Translations – Page No. 284

Question 11.
The figure shows the ascent of a hot air balloon. How would you describe the translation?
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 6
Type below:
____________

Answer:
4 units along positive X and 5 units along positive Y

Explanation:
Initial coordinate of balloon = ( -2 , -4)
Final coordinates of the balloon = (2,1)
Translation along x-axis = 2 – (-2)
= 4 units along positive x direction
Translation along y-axis = 1-(-4)
= 5 units along the positive y direction

Properties of Translations Answer Key Question 12.
Critical Thinking Is it possible that the orientation of a figure could change after it is translated? Explain.
_________

Answer:
No, it is not possible to change the orientation just by translation. As translation means, a transformation in which a figure is moved to another location without any change in size or orientation.

FOCUS ON HIGHER ORDER THINKING

Question 13.
a. Multistep Graph triangle XYZ with vertices X(-2, -5), Y(2, -2), and Z(4, -4) on the coordinate grid.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 7

Question 13.
b. On the same coordinate grid, graph and label triangle X’Y’Z’, the image of triangle XYZ after a translation of 3 units to the left and 6 units up.

Question 13.
c. Now graph and label triangle X”Y”Z”, the image of triangle X’Y’Z’ after a translation of 1 unit to the left and 2 units down.
Type below:
____________

Answer:
grade 8 chapter 9 image 2

Question 13.
d. Analyze Relationships How would you describe the translation that maps triangle XYZ onto triangle X”Y”Z”?
Type below:
____________

Answer:
Triangle XYZ has translated 4 units up and 4 units to the left

Question 14.
Critical Thinking The figure shows rectangle P’Q’R’S’, the image of rectangle PQRS after a translation of 5 units to the right and 7 units up. Graph and label the preimage PQRS.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 1: Properties of Translations img 8
Type below:
____________

Answer:
grade 8 chapter 9 image 3

Question 15.
Communicate Mathematical Ideas Explain why the image of a figure after a translation is congruent to its preimage.
Type below:
____________

Answer:
A translation is a geometric transformation that moves every point of a figure or space by the same amount in a given direction. So the 2 figures are identical and the translated figure is congruent to its pre-image.

Guided Practice – Properties of Reflections – Page No. 288

Question 1.
Vocabulary A reflection is a transformation that flips a figure across a line called the __________ .
____________

Answer:
Reflection Axis

Explanation:
A reflection is a transformation that flips a figure across a line called the Reflection Axis.

Question 2.
The figure shows trapezoid ABCD.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 2: Properties of Reflections img 9
a. Graph the image of the trapezoid after a reflection across the x-axis. Label the vertices of the image.
Type below:
____________

Answer:
A'(-3, -4)
B'(1, -4)
C'(3, -1)
D'(-3, -1)

Question 2.
b. How do trapezoid ABCD and trapezoid A’B’C’D’ compare?
____________

Answer:
congruent

Explanation:
trapezoid ABCD and trapezoid A’B’C’D’ are congruent

Question 2.
c. What If? Suppose you reflected trapezoid ABCD across the y-axis. How would the orientation of the image of the trapezoid compare with the orientation of the preimage?
Type below:
____________

Answer:
The orientation would be reversed horizontally.

ESSENTIAL QUESTION CHECK-IN

Question 3.
What are the properties of reflections?
Type below:
____________

Answer:
properties of reflections

  • The size stays the same
  • The shape stays the same
  • The orientation does NOT stay the same

9.2 Independent Practice – Properties of Reflections – Page No. 289

The graph shows four right triangles. Use the graph for Exercises 4-7.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 2: Properties of Reflections img 10

Question 4.
Which two triangles are reflections of each other across the x-axis?
Type below:
____________

Answer:
Triangles A and C are the reflections of each other across the x-axis.

Question 5.
For which two triangles is the line of reflection the y-axis?
Type below:
____________

Answer:
For triangles C & D the line of reflection is the y-axis.

Question 6.
Which triangle is a translation of triangle C? How would you describe the translation?
Type below:
____________

Answer:
Triangle B is the translation of triangle C.
Lets take any one point of the triangle = (-2, -6)
Let’s take the corresponding side of triangle B = (4,2)
Translation across x-axis = 4 -(-2) = 6 units
Translation across y-axis = 2 -(-6) = 8 units

Question 7.
Which triangles are congruent? How do you know?
Type below:
____________

Answer:
All the 4 triangles A, B, C, D are congruent.
The length of the base and height of all four triangles are 3 units, and 4 units respectively.

Explanation:
All the 4 triangles A, B, C, D are congruent.
If base and height are equal then the hypotenuse should also be equal. Thus all three sides of the triangles A, B, C, and D are equal. Thus these triangles are congruent,
The length of the base and height of all four triangles are 3 units, and 4 units respectively.

Question 8.
a. Graph quadrilateral WXYZ with vertices W(-2, -2), X(3, 1), Y(5, -1), and Z(4, -6) on the coordinate grid.
Type below:
____________

Question 8.
b. On the same coordinate grid, graph quadrilateral W’X’Y’Z’, the image of quadrilateral WXYZ after a reflection across the x-axis.
Type below:
____________

Answer:
grade 8 chapter 9 image 4

Question 8.
c. Which side of the image is congruent to side \(\overline { YZ } \)?
_______________
Name three other pairs of congruent sides.
_______________
Type below:
____________

Answer:
Line YZ = Line Y’Z’
Line WX = Line W’X’
Line XY = Line X’Y’
Line WZ = Line W’Z’

Question 8.
d. Which angle of the image is congruent to ∠X?
_______________
Name three other pairs of congruent angles.
_______________
Type below:
____________

Answer:
Angle X’
Angle W and Angle W’
Angle Y and Angle Y’
Angle Z and Angle Z’

Properties of Reflections – Page No. 290

Question 9.
Critical Thinking Is it possible that the image of a point after a reflection could be the same point as the preimage? Explain.
________

Answer:
Yes

Explanation:
It is possible that the image of a point after a reflection could be the same point as the preimage

FOCUS ON HIGHER ORDER THINKING

Question 10.
a. Graph the image of the figure shown after a reflection across the y-axis.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 2: Properties of Reflections img 11
Type below:
____________

Answer:
grade 8 chapter 9 image 5

Question 10.
b. On the same coordinate grid, graph the image of the figure you drew in part a after a reflection across the x-axis.
Type below:
____________

Answer:
grade 8 chapter 9 image 6

Question 10.
c. Make a Conjecture What other sequence of transformations would produce the same final image from the original preimage? Check your answer by performing the transformations. Then make a conjecture that generalizes your findings.
Type below:
____________

Answer:
The same image can be obtained by reflecting first across the x-axis and then across the y-axis.
Reflecting a figure first across the y-axis and then across the x-axis has the same outcome,. reflecting first across the x-axis and then across the y-axis.

Reflections Worksheet 8th Grade Answers Question 11.
a. Graph triangle DEF with vertices D(2, 6), E(5, 6), and F(5, 1) on the coordinate grid.

Question 11.
b. Next graph triangle D ′E ′F ′, the image of triangle DEF after a reflection across the y-axis.
Type below:
____________

Question 11.
c. On the same coordinate grid, graph triangle D′′ E′′ F′′, the image of triangle D ′E ′F ′ after a translation of 7 units down and 2 units to the right.
Type below:
____________

Answer:
grade 8 chapter 9 image 7

Question 11.
d. Analyze Relationships Find a different sequence of transformations that will transform triangle DEF to triangle D ′′E ′′F ′′.
Type below:
____________

Answer:
Translate triangle DEF 7 units down and 2 units to the left. Then reflect the image across the y-axis.

Guided Practice – Properties of Reflections – Page No. 294

Question 1.
Vocabulary A rotation is a transformation that turns a figure around a given _____ called the center of rotation.
____________

Answer:
point

Explanation:
A rotation is a transformation that turns a figure around a given point called the center of rotation.

Siobhan rotates a right triangle 90° counterclockwise about the origin.

Question 2.
How does the orientation of the image of the triangle compare with the orientation of the preimage?
Type below:
____________

Answer:
Each leg in the preimage is perpendicular to its corresponding leg in the image.

Algebraic Representation of Reflections Question 3.
Is the image of the triangle congruent to the preimage?
______

Answer:
Yes

Explanation:
The image of the triangle is congruent to the preimage

Draw the image of the figure after the given rotation about the origin.

Question 4.
90° counterclockwise
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 12
Type below:
____________

Answer:
grade 8 chapter 9 image 8

Translations Reflections and Rotations Lesson 9.2 Question 5.
180°
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 13
Type below:
____________

Answer:
After 180° rotation
A'(-2, -3)
B'(-4, -1)
C'(-2, 0)
D'(0, -1)

ESSENTIAL QUESTION CHECK-IN

Question 6.
What are the properties of rotations?
Type below:
____________

Answer:
Rotations preserve size and shape but change orientation.

9.3 Independent Practice – Properties of Reflections – Page No. 295

Question 7.
The figure shows triangle ABC and a rotation of the triangle about the origin.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 14
a. How would you describe the rotation?
____________

Answer:
ABC was rotated 90º counterclockwise about the origin

Question 7.
b. What are the coordinates of the image?
Type below:
____________

Answer:
A'(3, 1)
B'(2, 3)
C'(-1, 4)

Question 8.
The graph shows a figure and its image after a transformation.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 15
a. How would you describe this as a rotation?
____________

Answer:
The figure was rotated 180º about the origin.

Question 8.
b. Can you describe this as a transformation other than a rotation? Explain.
____________

Answer:
Yes

Explanation:
This can also be described as a reflection across the y-axis.

Question 9.
What type of rotation will preserve the orientation of the H-shaped figure in the grid?
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 16
____________

Answer:
A 180º rotation about the origin will preserve the orientation of the H-shaped figure in the grid.

Question 10.
A point with coordinates (-2, -3) is rotated 90° clockwise about the origin. What are the coordinates of its image?
(_______ , _______)

Answer:
(-3, 2)

Explanation:
The new coordinates are (-3, 2)

Complete the table with rotations of 180° or 90°. Include the direction of rotation for rotations of 90°.

Question 11.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 17
Type below:
____________

Answer:
grade 8 chapter 9 image 10

Properties of Reflections – Page No. 296

Draw the image of the figure after the given rotation about the origin.

Question 14.
180°
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 18
Type below:
____________

Answer:
After 180°
A'(4, 0)
B'(2, -1)
C'(0, 0)
D'(2, 1)

Question 15.
270° counterclockwise
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 19
Type below:
____________

Answer:
After 270º counterclockwise rotation
A'(1, 2)
B'(2, -1)
C'(4, 2)

9.2 Practice A Geometry Answers Page 296 Question 16.
Is there a rotation for which the orientation of the image is always the same as that of the preimage? If so, what?
______

Answer:
Yes

Explanation:
A 360º rotation will always be the same as the original image

FOCUS ON HIGHER ORDER THINKING

Question 17.
Problem Solving Lucas is playing a game where he has to rotate a figure for it to fit in an open space. Every time he clicks a button, the figure rotates 90 degrees clockwise. How many times does he need to click the button so that each figure returns to its original orientation?
Figure A ____________
Figure B ____________
Figure C ____________
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 3: Properties of Rotation img 20
Figure A: _________ time(s)
Figure B: _________ time(s)
Figure C: _________ time(s)

Answer:
Figure A: 2 time(s)
Figure B: 1 time(s)
Figure C: 4 time(s)

Explanation:
2 times to return to original orientation
1 time to return to original orientation
4 times to return to the original orientation

Question 18.
Make a Conjecture Triangle ABC is reflected across the y-axis to form the image A′B′C′. Triangle A′B′C′ is then reflected across the x-axis to form the image A″B″C″. What type of rotation can be used to describe the relationship between triangle A″B″C″ and triangle ABC?
Type below:
____________

Answer:
Triangle A’B’C’ is a 90º rotation of triangle ABC
Triangle A”B”C” is a 90º rotation of triangle A’B’C’
Therefore, Triangle A”B”C” is a 180º rotation of triangle ABC

Question 19.
Communicate Mathematical Ideas Point A is on the y-axis. Describe all possible locations of image A′ for rotations of 90°, 180°, and 270°. Include the origin as a possible location for A.
Type below:
____________

Answer:
If Point A is on the y-axis, Point A’ will be on the x-axis for 190° and 270° rotations and on the y-axis for 180° rotation
If point A is at the origin,
A’ is at the origin for any rotation about the origin.

Guided Practice – Algebraic Representations of Transformations – Page No. 300

Question 1.
Triangle XYZ has vertices X(-3, -2), Y(-1, 0), and Z(1, -6). Find the vertices of triangle X′Y′Z′ after a translation of 6 units to the right. Then graph the triangle and its image.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 21
Type below:
____________

Answer:
After a translation of 6 units to the right:
X'(3, -2)
Y'(5, 0)
Z'(7, -6)

Question 2.
Describe what happens to the x- and y-coordinates after a point is reflected across the x-axis.
Type below:
____________

Answer:
The x-coordinate remains the same, while the sign of the y-coordinate changes

Lesson 9.3 Reflection Answer Key Question 3.
Use the rule (x, y) → (y, -x) to graph the image of the triangle at right. Then describe the transformation.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 22
Type below:
____________

Answer:
The triangle is rotated 90º clockwise about the origin

ESSENTIAL QUESTION CHECK-IN

Question 4.
How do the x- and y-coordinates change when a figure is translated right a units and down b units?
Type below:
____________

Answer:
The x-coordinates increase by a, and the y-coordinates decrease by b

9.4 Independent Practice – Algebraic Representations of Transformations – Page No. 301

Write an algebraic rule to describe each transformation.Then describe the transformation.

Question 5.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 23
Type below:
____________

Answer:
algebraic rule
(x, y) -> (x-2, y-5)
transformation
translation of 2 units to the left and 5 units down
new coordinates
M'(-4, -2)
N'(-2, -2)
O'(-1, -4)
P'(-4, -4)

Question 6.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 24
Type below:
____________

Answer:
algebraic rule
(x, y) -> (-x, -y)
transformation
rotation of 180º
new coordinates
A'(0, 0)
B'(0, -3)
C'(2, -3)
D'(2, 0)

Question 7.
Triangle XYZ has vertices X(6, -2.3), Y(7.5, 5), and Z(8, 4). When translated, X′ has coordinates (2.8, -1.3). Write a rule to describe this transformation. Then find the coordinates of Y′ and Z′.
Type below:
____________

Answer:
algebraic rule
(x, y) -> (x-3.2, y+1)
new coordinates
Y'(4.3, 6)
Z'(4.8, 5)

Question 8.
Point L has coordinates (3, -5). The coordinates of point L′ after a reflection are (-3, -5). Without graphing, tell which axis point L was reflected across. Explain your answer.
____________

Answer:
Point L was reflected on the y-axis.
When you reflect a point across the y-axis, the sign of the x-coordinate changes and the sign of the y-coordinate remains the same

Translations and Reflections Worksheet Answer Key Question 9.
Use the rule (x, y) → (x – 2, y – 4) to graph the image of the rectangle. Then describe the transformation.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 25
Type below:
____________

Answer:
The rectangle is translated 2 units to the left and 4 units down

Question 10.
Parallelogram ABCD has vertices A(−2, −5\(\frac{1}{2}\)), B(−4, −5\(\frac{1}{2}\)),C(-3, -2), and D(-1, -2). Find the vertices of parallelogram A′B′C′D′ after a translation of 2 \(\frac{1}{2}\) units down.
Type below:
__________

Answer:
after a translation of 2 \(\frac{1}{2}\) units
A'(-2, -8)
B'(-4, -8)
C'(-3, -4 \(\frac{1}{2}\))
D'(-1, -4 \(\frac{1}{2}\))

Algebraic Representations of Transformations – Page No. 302

Question 11.
Alexandra drew the logo shown on half-inch graph paper. Write a rule that describes the translation Alexandra used to create the shadow on the letter A.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 26
Type below:
__________

Answer:
(x,y) –> (x+1,y-0.5)
(x+1,y-0.5) –> (x+0.5,y-0.25)

Explanation:
translation in units
(x,y) –> (x+1,y-0.5)
This step converts translation rule in units to translation rule in inches. (Divide by 2 since graph paper is half inch paper.
(x+1,y-0.5) –> (x+0.5,y-0.25)

Question 12.
Kite KLMN has vertices at K(1, 3), L(2, 4), M(3, 3), and N(2, 0). After the kite is rotated, K′ has coordinates (-3, 1). Describe the rotation, and include a rule in your description. Then find the coordinates of L′, M′, and N′.
Type below:
__________

Answer:
rotation
90 counterclockwise
rule
(x, y) -> (-y, x)
new coordinates
L'(-4, 2)
M'(-3, 3)
N'(0, 2)

FOCUS ON HIGHER ORDER THINKING

Question 13.
Make a Conjecture Graph the triangle with vertices (-3, 4), (3, 4), and (-5, -5). Use the transformation (y, x) to graph its image.
a. Which vertex of the image has the same coordinates as a vertex of the original figure? Explain why this is true.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 4: Algebraic Representations of Transformations img 27
Type below:
__________

Answer:
(-5, 5) has the same coordinates

Question 13.
b. What is the equation of a line through the origin and this point?
Type below:
__________

Answer:
x and y are equal so switching x and y has no effect on the coordinates

Question 13.
c. Describe the transformation of the triangle.
Type below:
__________

Answer:
x and y are equal so switching x and y has no effect on the coordinates

Understand Properties of Transformations Answer Key Question 14.
Critical Thinking Mitchell says the point (0, 0) does not change when reflected across the x- or y-axis or when rotated about the origin. Do you agree with Mitchell? Explain why or why not.
_______

Answer:
Yes, I agree with Mitchell

Explanation:
Reflecting across the x-axis or y-axis changes the sign of the y or x coordinate 0 cannot change signs.
Rotating about the origin does not change the origin (0, 0)

Question 15.
Analyze Relationships Triangle ABC with vertices A(-2, -2), B(-3, 1), and C(1, 1) is translated by (x, y) → (x – 1, y + 3). Then the image, triangle A′B′C′, is translated by (x, y) → (x + 4, y – 1), resulting in A″B″C″.
a. Find the coordinates for the vertices of triangle A″B″C″.
Type below:
__________

Answer:
A”(-2-1+4, -2+3-1) = A”(1, 0)
B”(-3-1+4, 1+3-1) = B”(0, 3)
C”(1-1+4, 1+3-1) = C”(4, 3)

Question 15.
b. Write a rule for one translation that maps triangle ABC to triangle A″B″C″.
Type below:
__________

Answer:
(x, y) -> (x-1+4, y+3-1)
(x, y) -> (x+3, y+2)

Guided Practice – Congruent Figures – Page No. 306

Question 1.
Apply the indicated series of transformations to the rectangle. Each transformation is applied to the image of the previous transformation, not the original figure. Label each image with the letter of the transformation applied.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 28
A. Reflection across the y-axis
B. Rotation 90° clockwise around the origin
C. (x, y) → (x – 2, y)
D. Rotation 90° counterclockwise around the origin
E. (x, y) → (x – 7, y – 2)
Type below:
__________

Answer:
A. After transformation
(1, 3)
(1, 4)
(4, 4)
(4, 3)
B. After transformation
(3, -1)
(4, -1)
(4, -4)
(3, -4)
C. After transformation
(1, -1)
(2, -1)
(2, -4)
(1, -4)
D. After transformation
(1, 1)
(1, 2)
(4, 2)
(4, 1)
E. After transformation
(-6, -1)
(-6, 0)
(-3, 0)
(-3, -1)

Identify a sequence of transformations that will transform figure A into figure C.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 29

Question 2.
What transformation is used to transform figure A into figure B?
Type below:
__________

Answer:
Reflection across the y-axis

Explanation:
Reflection across the y-axis is used to transform figure A into figure B

Grade 8 Transformations Worksheets Pdf Answer Key Question 3.
What transformation is used to transform figure B into figure C?
Type below:
__________

Answer:
Translation 3 units right and 4 units down

Explanation:
Translation 3 units right and 4 units down is used to transform figure B into figure C

Question 4.
What sequence of transformations is used to transform figure A into figure C? Express the transformations algebraically.
Type below:
__________

Answer:
Reflection across the y-axis is used to transform figure A into figure B
Translation 3 units right and 4 units down is used to transform figure B into figure C
Algebraically:
(x, y) -> (-x, y)
(x, y) -> (x +3, y-4)

Question 5.
Vocabulary What does it mean for two figures to be congruent?
Type below:
__________

Answer:
Two figures are congruent when the figures have the same size and the same shape.

ESSENTIAL QUESTION CHECK-IN

Question 6.
After a sequence of translations, reflections, and rotations, what is true about the first figure and the final figure?
Type below:
__________

Answer:
After a sequence of translations, reflections, and rotations, the first and final figures have the same size and shape. (They are congruent)

9.5 Independent Practice – Congruent Figures – Page No. 307

For each given figure A, graph figures B and C using the given sequence of transformations. State whether figures A and C have the same or different orientation.

Question 7.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 30
Figure B: a translation of 1 unit to the right and 3 units up
Figure C: a 90° clockwise rotation around the origin
Type below:
__________

Answer:
Different orientation

Explanation:
grade 8 chapter 9 image 11
Different orientation

8th Grade Transformations Worksheet Answers Question 8.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 31
Figure B: a reflection across the y-axis
Figure C: a 180° rotation around the origin
Type below:
__________

Answer:
Different orientation

Explanation:
grade 8 chapter 9 image 12
Different orientation

Question 9.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 32
Figure B: a reflection across the y-axis
Figure C: a translation 2 units down
Type below:
__________

Answer:
Different orientation

Explanation:
grade 8 chapter 9 image 13
Different orientation

Question 10.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 33
Figure B: a translation 2 units up
Figure C: a rotation of 180° around the origin
Type below:
__________

Answer:
Different orientation

Explanation:
grade 8 chapter 9 image 14
Different orientation

Congruent Figures – Page No. 308

Question 11.
Represent Real-World Problems A city planner wanted to place the new town library at site A. The mayor thought that it would be better at site B. What transformations were applied to the building at site A to relocate the building to site B? Did the mayor change the size or orientation of the library?
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 34
Type below:
__________

Answer:
From Site A to Site B: Translation 2 units right and 4 units down
The size did NOT change
The orientation changed

Question 12.
Persevere in Problem-Solving Find a sequence of three transformations that can be used to obtain figure D from figure A. Graph the figures B and C that are created by the transformations.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Lesson 5: Congruent Figures img 35
Type below:
__________

Answer:
From figure A to D:
Reflection across the x-axis (-1, -5) (-1, -6) (2, -5) (4, -6)
90º clockwise rotation (4, -1) (5, -1) (5, -4) (4, -6)
translation 6 units left (4, -1) (5, -1) (5, -4) (4, -6)

FOCUS ON HIGHER ORDER THINKING

Question 13.
Counterexamples The Commutative Properties for Addition and Multiplication state that the order of two numbers being added or multiplied does not change the sum or product. Are translations and rotations commutative? If not, give a counterexample.
________

Answer:
No, Translation and rotations are not commutative

Explanation:
The point (2, 2) becomes (2, -4) when translated 2 units to the right then rotated 90 around the origin.
The point (2, 2) becomes (4, -2) when rotated 90 around the origin then translated 2 units to the right.
The above two points are not the same.

Lesson 9 Practice Problems Answer Key Grade 8 Question 14.
Multiple Representations For each representation, describe a possible sequence of transformations.
a. (x, y) → (-x – 2, y + 1)
Type below:
____________

Answer:
translation 2 units right and 1 unit up
reflection across y-axis

Question 14.
b. (x, y) → (y, -x – 3)
Type below:
____________

Answer:
rotation 90º clockwise around the origin
translation 3 units down

Ready to Go On? – Model Quiz – Page No. 309

9.1–9.3 Properties of Translations, Reflections, and Rotations

Question 1.
Graph the image of triangle ABC after a translation of 6 units to the right and 4 units down. Label the vertices of the image A’, B’, and C’.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Model Quiz img 36
Type below:
____________

Answer:
After translation:
A'(2, 1)
B'(2, -1)
C'(5, -1)

Question 2.
On the same coordinate grid, graph the image of triangle ABC after a reflection across the x-axis. Label the vertices of the image A”, B”, and C”.
Type below:
____________

Answer:
After reflection:
A”(-4, -5)
B”(-4, -3)
C”(-1, -3)

Question 3.
Graph the image of HIJK after it is rotated 180° about the origin. Label the vertices of the image H’I’J’K’.
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Model Quiz img 37
Type below:
____________

Answer:
After rotation:
H'(0, -4)
I'(0, -1)
J'(2, -2)
K'(2, -3)

9.4 Algebraic Representations of Transformations

Question 4.
A triangle has vertices at (2, 3), (−2, 2), and (−3, 5). What are the coordinates of the vertices of the image after the translation (x, y) → (x + 4, y − 3)?
Type below:
____________

Answer:
After translation:
(6, 0)
(2, -1)
(1, 2)

9.5 Congruent Figures

Question 5.
Vocabulary Translations, reflections, and rotations produce a figure that is _____ to the original figure.
Type below:
____________

Answer:
congruent

Explanation:
Vocabulary Translations, reflections, and rotations produce a figure that is congruent to the original figure.

Chapter 9 Properties and Equations Answer Key Question 6.
Use the coordinate grid for Exercise 3. Reflect H’I’J’K’ over the y-axis, then rotate it 180° about the origin. Label the new figure H″I″J″K″.
Type below:
____________

Answer:
after reflection
H'(0, -4)
I'(0, -1)
J'(-2, -2)
K'(-2, -3)
after rotation
H”(0, 4)
I”(0, 1)
J”(2, 2)
K”(2, 3)

ESSENTIAL QUESTION

Question 7.
How can you use transformations to solve real-world problems?
Type below:
____________

Answer:
Transformational properties allow the systematic movement of congruent figures while maintaining or adjusting their orientation.

Selected Response – Mixed Review – Page No. 310

Question 1.
What would be the orientation of the figure L after a translation of 8 units to the right and 3 units up?
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Mixed Review img 38
Options:
a. A
b. B
c. C
d. D

Answer:
c. C

Explanation:
After a translation of 8 units right and 3 units up, the orientation of figure L stays the same.

Question 2.
Figure A is reflected over the y-axis and then lowered 6 units. Which sequence describes these transformations?
Options:
a. (x, y) -> (x, -y) and (x, y) -> (x, y – 6)
b. (x, y) -> (-x, y) and (x, y) -> (x, y – 6)
c. (x, y) -> (x, -y) and (x, y) -> (x – 6, y)
d. (x, y) -> (-x, y) and (x, y) -> (x – 6, y)

Answer:
b. (x, y) -> (-x, y) and (x, y) -> (x, y – 6)

Explanation:
reflection over y-axis:
(x, y) -> (-x, y)
Translation 6 units down
(x, y) -> (x, y-6)

Question 3.
What quadrant would the triangle be in after a rotation of 90° counterclockwise about the origin?
Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Mixed Review img 39
Options:
a. I
b. II
c. III
d. IV

Answer:
d. IV

Explanation:
After a rotation of 90° counterclockwise about the origin, the triangle will be in QIV

Question 4.
Which rational number is greater than −3 \(\frac{1}{3}\) but less than −\(\frac{4}{5}\)?
Options:
a. −0.4
b. −\(\frac{9}{7}\)
c. −0.19
d. −\(\frac{22}{5}\)

Answer:
b. −\(\frac{9}{7}\)

Question 5.
Which of the following is not true of a trapezoid that has been reflected across the x-axis?
Options:
a. The new trapezoid is the same size as the original trapezoid.
b. The new trapezoid is the same shape as the original trapezoid.
c. The new trapezoid is in the same orientation as the original trapezoid.
d. The x-coordinates of the new trapezoid are the same as the x-coordinates of the original trapezoid.

Answer:
d. The x-coordinates of the new trapezoid are the same as the x-coordinates of the original trapezoid.

Explanation:
The x-coordinates of the new trapezoid are the same as the x-coordinates of the original trapezoid.

Question 6.
A triangle with coordinates (6, 4), (2, −1), and (−3, 5) is translated 4 units left and rotated 180° about the origin. What are the coordinates of its image?
Options:
a. (2, 4), (-2, -1), (-7, 5)
b. (4, 6), (-1, 2), (5, -3)
c. (4, -2), (-1, 2), (5, 7)
d. (-2, -4), (2, 1), (7, -5)

Answer:
d. (-2, -4), (2, 1), (7, -5)

Question 7.
A rectangle with vertices (3, -2), (3, -4), (7, -2), (7, -4) is reflected across the x-axis and then rotated 90° counterclockwise.
a. In what quadrant does the image lie?
____________

Answer:
After reflection and rotation, the image lies in QII

Question 7.
b. What are the vertices of the image?
Type below:
____________

Answer:
image vertices
(-2, 3)
(-4, 3)
(-2, 7)
(-4, 7)

Question 7.
c. What other transformations produce the same image?
Type below:
____________

Answer:
A reflection across the y-axis and 90º clockwise rotation will produce the same result.

Conclusion:

Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence available both online and offline. Students can refer to the Go Math Grade 8 Answer Key in their convenient way. Get your favorite Chapter math questions and answers and start practicing them.

Go Math Grade 8 Answer Key Chapter 9 Transformations and Congruence Read More »

go-math-grade-8-answer-key-chapter-15-two-way-tables

Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables

Who doesn’t love the best learning? Go, Math Grade, 8 Answer Key Chapter 15 Two-Way Tables is the perfect guide for every student to learn maths. The explanation also included along with the questions and answers where students can easily understand the method of solving math questions. Students can habituate practice maths if they start their practice with the Go Math Grade 8 Chapter 15 Two-Way Tables Solution Key. Don’t look anymore. Make your students learn the maths using Go Math Grade 8 Answer Key.

Go Math Grade 8 Chapter 15 Two-Way Tables Answer Key

Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables offering the best way to practice maths with easy tricks and tips. So, every student loves to learn maths in an easy way. You can download and practice Go Math Grade 8 Text Book questions for free. Free PDF of HMH Go Math Grade 8 Answer Key is provided for the students here.

Lesson 1: Two-Way Frequency Tables

 Lesson 2: Two-Way Relative Frequency Tables

Model Quiz

Mixed Review

Guided Practice – Two-Way Frequency Tables – Page No. 454

Question 1.
In a survey of 50 students, 60% said that they have a cat. Of the students who have a cat, 70% also have a dog. Of the students who do not have a cat, 75% have a dog. Complete the two-way table.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 1: Two-Way Frequency Tables img 1
a. Enter the total number of students surveyed in the bottom right cell of the table.
Type below:
_______________

Answer:
grade 8 chapter 15 image 1

Explanation:
In a survey of 50 students, 60% said that they have a cat.
In mathematical terms:
Cat = 0.6×50 = 30
If 60% have a cat, then 40% don’t have a cat
No Cat = (1 – 0.6) × 50 = 20
Because there are 2 options, Adding them will give the total amount of students
Total = Cat + No Cat = 50
Of the students who have a cat, 70% also have a dog. Of the students who do not have a cat, 75% have a dog. So, in mathematical terms:
Dog = Cat × 0.7 + No Cat ×0.75 = 30 × 0.7 + 20 × 0.75 = 36
Following the same logic as before, if 70% of students who have a cat also have a dog, then 30% of them don’t have a dog. The same analysis for the students who do not have a cat.
No Dog = Cat × (1-0.7) + No Cat × (1-0.75) = 30 × (1-0.7) + 20 × (1-0.75) = 14
Again, the addition of the 2 options has to give the total amount of students
Total = 50

Question 1.
b. Fill in right column.
Type below:
_______________

Answer:
Of the students who have a cat, 70% also have a dog. Of the students who do not have a cat, 75% have a dog. In mathematical terms:
Dog = Cat × 0.7 + No Cat ×0.75 = 30 × 0.7 + 20 × 0.75 = 36

Question 1.
c. Fill in top row.
Type below:
_______________

Answer:
In a survey of 50 students, 60% said that they have a cat. In mathematical terms:
Cat = 0.6×50 = 30

Question 1.
d. Fill in second row.
Type below:
_______________

Answer:
If 60% have a cat, then 40% don’t have a cat
No Cat = (1 – 0.6) × 50 = 20

Question 1.
e. Fill in last row.
Type below:
_______________

Answer:
Because there are 2 options, the addition of them has to give the total amount of students
Total = Cat + No Cat = 50

Two-Way Frequency Table Worksheet Answers Question 2.
The results of a survey at a school are shown. Is there an association between being a boy and being left-handed? Explain.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 1: Two-Way Frequency Tables img 2
_______________

Answer:
No, there isn’t any association between being a boy and being left-handed.
Boys are no more likely to be left-handed than right-handed.

ESSENTIAL QUESTION CHECK-IN

Question 3.
Voters were polled to see whether they supported Smith or Jones. Can you construct a two-way table of the results? Why or why not?
_______________

Answer:
You cannot construct a two-way table of the results. Because there is only one variable; voters. If there were two variables, such as men and women, a two-way table could be constructed.

15.1 Independent Practice – Two-Way Frequency Tables – Page No. 455

Question 4.
Represent Real-World Problems One hundred forty students were asked about their language classes. Out of 111 who take French, only 31 do not take Spanish. Twelve take neither French nor Spanish. Use this information to make a two-way table.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 1: Two-Way Frequency Tables img 3
Type below:
_______________

Answer:
grade 8 chapter 15 image 2

Question 5.
Represent Real-World Problems Seventh- and eighth-grade students were asked whether they preferred science or math.
a. Complete the two-way table.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 1: Two-Way Frequency Tables img 4
Type below:
_______________

Answer:
grade 8 chapter 15 image 3

Question 5.
b. Is there an association between being in eighth grade and preferring math? Explain.
_______________

Answer:
There is no association as such between being in eighth grade and preferring maths. But due the total no. of eighth-grade students choosing maths is greater than the total number of students in seventh-grade preferring science. So, the eighth-grade students preferred it.

Two-Way Frequency Table Worksheet Answer Key Question 6.
Persevere in Problem-Solving The table gives partial information on the number of men and women who play in the four sections of the Metro Orchestra.
a. Complete the table.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 1: Two-Way Frequency Tables img 5
Type below:
_______________

Answer:
grade 8 chapter 15 image 4

Question 6.
b. Is there an association between being a woman and playing strings? Explain.
_______________

Answer:
There is no association between being a woman and playing strings since the number of men playing strings is less than women.

Two-Way Frequency Tables – Page No. 456

FOCUS ON HIGHER ORDER THINKING

Question 7.
Multi-Step The two-way table below shows the results of a survey of Florida teenagers who were asked whether they preferred surfing or snorkeling.
a. To the right of the number in each cell, write the relative frequency of the number compared to the total for the row the number is in. Round to the nearest percent.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 1: Two-Way Frequency Tables img 6
Type below:
_______________

Answer:
grade 8 chapter 15 image 9

Two-Way Table Questions and Answers Question 7.
b. Explain the meaning of the relative frequency you wrote beside 28.
Type below:
_______________

Answer:
The relative frequency shows the percentage of people aged 16-18 who prefer snorkeling.

Question 7.
c. To the right of each number you wrote in part a, write the relative frequency of each number compared to the total for the column the number is in. Are the relative frequencies the same? Why or why not?
Type below:
_______________

Answer:
grade 8 chapter 15 image 10

Question 7.
d. Explain the meaning of the relative frequency you wrote beside 28.
Type below:
_______________

Answer:
The relative frequency represents the percentage of people that prefer snorkeling that is aged 16-18.

Guided Practice – Two-Way Relative Frequency Tables – Page No. 462

Question 1.
In a class survey, students were asked to choose their favorite vacation destination. The results are displayed by gender in the two-way frequency table.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 2: Two-Way Relative Frequency Tables img 7
a. Find the total for each gender by adding the frequencies in each row. Write the row totals in the Total column.
Type below:
_______________

Answer:
grade 8 chapter 15 image 5
Girl = 7 + 3 + 2 = 12
Boy = 5 + 2 + 6 = 13

Question 1.
b. Find the total for each preferred vacation spot by adding the frequencies in each column. Write the column totals in the Total row.
Type below:
_______________

Answer:
Seashore = 7 + 5 = 12
Mountains = 3 + 2 = 5
Other = 2 + 6 = 8

15.2 Relative Frequency Answer Key Question 1.
c. Write the grand total (the sum of the row totals and the column totals) in the lower-right corner of the table.
Type below:
_______________

Answer:
grand total = 25

Question 1.
d. Create a two-way relative frequency table by dividing each number in the above table by the grand total. Write the quotients as decimals.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 2: Two-Way Relative Frequency Tables img 8
Type below:
_______________

Answer:
grade 8 chapter 15 image 6

Explanation:
7/25 = 0.28, 3/25 = 0.12; 2/25 = 0.08; 12/25 = 0.48
5/25 = 0.2; 2/25 = 0.08; 6/25 = 0.24; 13/25 = 0.52
12/25 = 0.48; 5/25 = 0.2; 8/25= 0.32; 25/25 = 1

Question 1.
e. Use the table to find the joint relative frequency of students surveyed who are boys and who prefer vacationing in the mountains.
_________

Answer:
Joint relative frequency of boys = 2/25 = 0.08
These boys prefer vacationing in the mountains.

Question 1.
f. Use the table to find the marginal relative frequency of students surveyed who prefer vacationing at the seashore.
_________

Answer:
The marginal relative frequency of students = 12/25 = 0.48
These are the number of students who prefer vacationing in the seashore.

Question 1.
g. Find the conditional relative frequency that a student surveyed prefers vacationing in the mountains, given that the student is a girl. Interpret this result.
_________

Answer:
The condition relative frequency of girls of row = 3/12 = 0.25
And that of the column is 3/5 = 0.6
These are the number of girls who preferred vacationing in the mountains.

ESSENTIAL QUESTION CHECK-IN

Question 2.
How can you use a two-way frequency table to learn more about its data?
Type below:
_______________

Answer:
The two-way frequency table gives perfection and accuracy in calculating the data. It helps to calculate the total value two times while calculating the data of the row and to calculate the data of the column.

15.2 Independent Practice – Two-Way Relative Frequency Tables – Page No. 463

Stefan surveyed 75 of his classmates about their participation in school activities as well as whether they had a part-time job. The results are shown in the two-way frequency table. Use the table for Exercises 3–6.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 2: Two-Way Relative Frequency Tables img 9

Question 3.
a. Complete the table.
Type below:
_______________

Answer:
grade 8 chapter 15 image 7

Question 3.
b. Explain how you found the correct data to enter in the table.
Type below:
_______________

Answer:
1) In the first row of yes the values of sports only, Neither, and total were provided. Also, in the 1st column of cubes, only the values of No and Total were providers. So, these values were subtracted and the value of yes was known.
2) The values in the 1st row of yes were added and subtracted from the total column. Hence the value in both columns was known. So, Similarly, by adding and subtracting the values in the rows and columns the vacant values were known.

2 Way Relative Frequency Tables Question 4.
Create a two-way relative frequency table using decimals. Round to the nearest hundredth.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 2: Two-Way Relative Frequency Tables img 10
Type below:
_______________

Answer:
grade 8 chapter 15 image 8

Explanation:
Using the frequency table in problem 3, divide each number in each cell by 75, the grand total, and round to the nearest hundredth.
Job and clubs only: 10/75 = 0.13
Job and sports only: 12/75 = 0.16
Job and both clubs not sports: 20/75 = 0.27
Job and neither clubs nor sports: 9/75 = 0.12
Job total: 51/75 = 0.68
No jobs and clubs only: 5/75 = 0.07
No Job and sports only: 6/75 = 0.08
No job and both clubs and sports: 10/75 = 0.13
No Job and neither clubs nor sports: 3/75 = 0.04
No Job total: 24/75 = 0.32
Clubs only total: 15/75 = 0.2
Sports-only total: 18/75 = 0.24
Both clubs and sports total: 30/75 = 0.4
Neither clubs nor sports total: 12/75 = 0.16
Total: 75/75 = 1.00
Use the totals above to create a two-way frequency table.

Question 5.
Give each relative frequency as a percent.
a. the joint relative frequency of students surveyed who participate in school clubs only and have part-time jobs
_________ %

Answer:
13%

Explanation:
The joint relative frequency of students surveyed who participate in school clubs only and have part-time jobs 0.13 or 13%
(Job and clubs only: 10/75 = 0.13)

Question 5.
b. the marginal frequency of students surveyed who do not have a part-time job
_________ %

Answer:
32%

Explanation:
The marginal frequency of students surveyed who do not have a part-time job is 0.32 or 32%
(No job total: 24/75 = 0.32)

Question 5.
c. The conditional relative frequency that a student surveyed participates in both school clubs and sports, given that the student has a part-time job
_________ %

Answer:
39%

Explanation:
The conditional relative frequency that a student surveyed participates in both school clubs and sports, given that the student has a part-time job is 0.39 or 39%
(20/51 = 0.39)

Two-Way Relative Frequency Tables – Page No. 464

Question 6.
Discuss possible influences of having a part-time job on participation in school activities. Support your response with an analysis of the data.
Type below:
_______________

Answer:
The joint relative frequency of students surveyed who participate in school activities and have part-time jobs is 0.27 or 27%.
The joint relative frequency of students surveyed who participate in school activities and do not have part-time jobs is 0.13 or 13%.
This means that the students who have jobs are more likely to participate in school activities than the students who do not have jobs.

FOCUS ON HIGHER ORDER THINKING

Question 7.
The head of quality control for a chair manufacturer collected data on the quality of two types of wood that the company grows on its tree farm. The table shows the acceptance and rejection data.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Lesson 2: Two-Way Relative Frequency Tables img 11
a. Critique Reasoning To create a two-way relative frequency table for this data, the head of quality control divided each number in each row by the row total. Is this correct? Explain.
_______________

Answer:
No, it is not correct for the head of quality control to divide each number in each row by the row total to create a two-way relative frequency table. Each data value should have been divided by 600, the grand total, not by the row total.

Question 7.
b. Draw Conclusions Are any of the data the head of quality control entered into the two-way relative frequency table correctly? If so, which is and which isn’t? Explain.
Type below:
_______________

Answer:
Since the head of quality control is divided incorrectly, the top two rows are incorrect. However, the bottom row has correct data because each number in the bottom row was divided by the grand total.

Two-Way Table Questions and Answers Question 8.
Analyze Relationships What is the difference between relative frequency and conditional relative frequency?
Type below:
_______________

Answer:
Relative frequency is found by dividing a frequency by the grand total while conditional relative frequency is found by dividing a frequency that is not in the Total row or the Total column by the frequency’s row total or column total.

Ready to Go On? – Model Quiz – Page No. 465

15.1 Two-Way Frequency Tables

Martin collected data from students about whether they played a musical instrument. The table shows his results. Use the table for Exercises 1–4.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Model Quiz img 12

Question 1.
Of the students surveyed, how many played an instrument?
__________ students

Answer:
90 students

Explanation:
Of the students surveyed, 90 students played an instrument

Question 2.
How many girls surveyed did NOT play an instrument?
__________ girls

Answer:
40 girls

Explanation:
(No. of boys did not play a musical instrument) + (No.of girls who did not play a musical instrument) = (Total no. of students who did not play an instrument)
70 + x = 110
x = 40
So, the number of girls who did not play a musical instrument = 40.

Question 3.
What is the relative frequency of a student playing an instrument? Write the answer as a percent.
________ %

Answer:
45%

Explanation:
The relative frequency of a student playing an instrument in this case, 90 out of 200 students play a musical instrument
(90/200) . 100 = 45%

Two-Way Tables Worksheets with Answers Question 4.
What is the relative frequency of playing an instrument among boys? Write the answer as a decimal.
________ %

Answer:
38%

Explanation:
The relative frequency of playing an instrument among boys
(42/112) . 100 = 37.5% or 38%

15.2 Two-Way Relative Frequency Tables

Students were asked how they traveled to school. The two-way relative frequency table shows the results. Use the table for Exercises 5–7. Write answers as decimals rounded to the nearest hundredth.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Model Quiz img 13

Question 5.
What is the joint relative frequency of high school students who ride the bus?
________

Answer:
The joint relative frequency of high school students who ride the bus is 0.12

Question 6.
What is the marginal relative frequency of students surveyed who are in middle school?
________

Answer:
The marginal frequency of students surveyed in middle school is 0.42

Two-Way Table Worksheet With Answers Question 7.
What is the conditional relative frequency that a student rides the bus, given that the student is in middle school?
________

Answer:
0.62

Explanation:
The conditional relative frequency that a student rides the bus given that the student is in middle school.
Total no. of students going to bus = 0.26
Students who ride the bus (who are a middle school) = 0.42
Conditional relative frequency = 0.26/0.42 = 0.62

ESSENTIAL QUESTION

Question 8.
How can you use two-way tables to solve real-world problems?
Type below:
_______________

Answer:
Accuracy in the calculation of the data as it is maintained decently in a suitable format. It helps to measure each and every frequency easily as the values are placed individually. Also, helps to measure the total of each row and column separately. So, since the data represented is suitable it makes the person understand and solve the problem.

Selected Response – Mixed Review – Page No. 466

The table gives data on the length of time that teachers at Tenth Avenue School have taught. Use the table for Exercises 1–5.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Mixed Review img 14

Question 1.
How many female teachers have taught for fewer than 10 years?
Options:
a. 4
b. 9
c. 21
d. 30

Answer:
c. 21

Explanation:
(No. of male teachers who have taught fewer than 10 years) + (No. of female teachers who have taught fewer than 10 years) = 30
9 + x = 30
x = 21
The number of female teachers who have taught for fewer than 10 years is 21.

Lesson 15 Making A 2-Way Frequency Tables Answer Key Question 2.
What is the relative frequency of teachers who have taught for 10 or more years?
Options:
a. 10%
b. 25%
c. 30%
d. 60%

Answer:
b. 25%

Explanation:
The relative frequency of teachers who have taught more than 10 or more years.
Total no. of teachers = 40
No. of teachers who taught for more than 10 years = 10
Relative frequency = (10/40) . 100 = 25%

Question 3.
What is the relative frequency of having taught for fewer than 10 years among male teachers?
Options:
a. 0.09
b. 0.225
c. 0.6
d. 1.50

Answer:
c. 0.6

Explanation:
The relative frequency of male teachers who have taught fewer than 10 or more years.
Total no. of teachers = 15
No. of male teachers who taught for fewer than 10 years = 9
Relative frequency = (9/15) = 0.6

Question 4.
What is the joint relative frequency of female teachers who have taught for more than 10 years?
Options:
a. 4%
b. 10%
c. 16%
d. 25%

Answer:
b. 10%

Explanation:
The relative frequency of female teachers who taught for more than 10 years is 4/40 = 1/10 = 0.1 × 100 to calculate the data in percentage
10%

Question 5.
What is the marginal relative frequency of teachers who are female?
Options:
a. 0.16
b. 0.25
c. 0.4
d. 0.625

Answer:
d. 0.625

Explanation:
The total number of teachers who are female = 25
Total no. of teachers = 40
Marginal frequency = 25/40 = 0.625

Two-Way Frequency Tables Practice and Problem-Solving a/b Answers Question 6.
A triangle has an exterior angle of x°. Which of the following represents the measure of the interior angle next to it?
Options:
a. (180 − x)°
b. (x − 180)°
c. (90 − x)°
d. (x − 90)°

Answer:
a. (180 − x)°

Explanation:
The triangle has an exterior angle of x°. Let that angle be Angle ACD. So, the angle next to it is
Angle ACD + Angle ACB = 180º
Angle ACB = (180 − x)°

Question 7.
What is the volume of a cone that has a diameter of 12 cm and a height of 4 cm? Use 3.14 for π and round to the nearest tenth.
Options:
a. 25.12 cm3
b. 602.88 cm3
c. 150.72 cm3
d. 1,808.64 cm3

Answer:
c. 150.72 cm3

Explanation:
Diameter = 12cm
Radius r = 6cm
height h = 4cm
So, the volume of the cone = 1/3 . π . r². h
= 1/3 . 6 . 6 . 4 . 3.14 = 150.72 cm³

Mini-Task

Question 8.
The table gives data on books read by members of the Summer Reading Club.
Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Mixed Review img 15
a. Find the relative frequency of a club member reading fewer than 25 books.
________ %

Answer:
25%

Explanation:
The relative frequency of a club member reading fewer than 25 books is
Total of 16 members read fewer than 25 books
16/64 = 0.25 or 25%

Question 8.
b. Find the relative frequency of reading fewer than 25 books among girl club members.
________ %

Answer:
14%

Explanation:
The relative frequency of a girl club member reading fewer than 25 books is
9/64 = 0.14 or 14%

Question 8.
c. Is there an association between being a girl and reading fewer than 25 books? Explain.
____________

Answer:
No, there isn’t any association between being a girl and reading fewer than 25 books. It is a choice depending on an individual to read as many books as he/she can compare with the boys reading fewer than 25 books because the number of girls reading these books is comparatively greater.

Conclusion:

Practice all the questions available on Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables. Get your copy now to start your practice to be a part of the competition for maths exams. Go Math Grade 8 Answer Key is a great material that helps the students to learn in the best way.

Go Math Grade 8 Answer Key Chapter 15 Two-Way Tables Read More »

go-math-grade-8-answer-key-chapter-11-angle-relationships-in-parallel-lines-and-triangles

Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles

Tired of searching for the best online guide to practice maths? Don’t worry discover all the questions, answers, and explanations on Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles. Free Go Math Grade 8 Chapter 11 Angle Relationships in Parallel Lines and Triangles Solution Key PDF is provided to download and practice online. All the students who wish to practice Grade 8 math questions can begin their practice now by using Go Math Grade 8 Answer Key. Go Math Grade 8 Chapter 11 Answer key is the best guide to learn maths.

Go Math Grade 8 Chapter 11 Angle Relationships in Parallel Lines and Triangles Answer Key

Students can get trusted results with the practice of Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles. Get unlimited access to Go Math Grade 8 Chapter 11 Questions and Answers on our website. Choose the best and get the best. practice with perfection and get the best results by practicing with Go Math Grade 8 Chapter 11 Angle Relationships in Parallel Lines and Triangles Answer Key.

Lesson 1: Parallel Lines Cut by a Transversal

Lesson 2: Angle Theorems for Triangles

Lesson 3: Angle-Angle Similarity

Model Quiz

Review

Guided Practice – Parallel Lines Cut by a Transversal – Page No. 350

Use the figure for Exercises 1–4.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 1: Parallel Lines Cut by a Transversal img 1

Question 1.
∠UVY and ____ are a pair of corresponding angles.
∠ _________

Answer:
∠ VWZ

Explanation:
∠UVY and ∠ VWZ are a pair of corresponding angles.
When two lines are crossed by Transversal the angles in matching corners are called corresponding angles.

Question 2.
∠WVY and ∠VWT are _________ angles.
____________

Answer:
∠WVY and ∠VWT are alternate interior angles.
Alternate Interior Angles are a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal.

Explanation:
∠WVY and ∠VWT are alternate interior angles.
Alternate Interior Angles are a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal.

Parallel Lines cut by a Transversal Answer Key Question 3.
Find m∠SVW.
_________ °

Answer:
80º

Explanation:
∠SVW and ∠VWT are same sider interior angles. Therefore,
m∠SVW + m∠VWT = 180º
4xº +5xº = 180º
9x = 180º
x = 180/9
x = 20
m∠SVW = 4xº = (4.20)º = 80º

Question 4.
Find m∠VWT.
_________ °

Answer:
100º

Explanation:
∠SVW and ∠VWT are same sider interior angles. Therefore,
m∠SVW + m∠VWT = 180º
4xº +5xº = 180º
9x = 180º
x = 180/9
x = 20
m∠VWT = 5xº = (5.20)º = 100º

Question 5.
Vocabulary When two parallel lines are cut by a transversal, _______________ angles are supplementary.
____________

Answer:
If two parallel lines are cut by a transversal, then the pairs of alternate exterior angles are congruent. If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles are supplementary.

ESSENTIAL QUESTION CHECK-IN

Question 6.
What can you conclude about the interior angles formed when two parallel lines are cut by a transversal?
Type below:
____________

Answer:
Alternate interior angles are congruent; same-side interior angles are supplementary.

Explanation:
When two parallel lines are cut by a transversal, the interior angles will be the angles between the two parallel lines. Alternate interior angles will be on opposite sides of the transversal; the measures of these angles are the same.
Same-side interior angles will be on the same side of the transversal; the measures of these angles will be supplementary, adding up to 180 degrees.

11.1 Independent Practice – Parallel Lines Cut by a Transversal – Page No. 351

Vocabulary Use the figure for Exercises 7–10.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 1: Parallel Lines Cut by a Transversal img 2

Question 7.
Name all pairs of corresponding angles.
Type below:
____________

Answer:
∠1 and ∠5
∠3 and ∠7
∠2 and ∠6
∠4 and ∠8

Explanation:
Corresponding angles are
∠1 and ∠5
∠3 and ∠7
∠2 and ∠6
∠4 and ∠8

Parallel Lines cut by a Transversal Worksheet Answer Key Question 8.
Name both pairs of alternate exterior angles.
Type below:
____________

Answer:
∠1 and ∠8
∠2 and ∠7

Explanation:
Alternate exterior angles
∠1 and ∠8
∠2 and ∠7

Question 9.
Name the relationship between ∠ 3 and ∠6.
Type below:
____________

Answer:
alternate interior angles

Explanation:
∠3 and ∠6 are alternate interior angles.
Alternate Interior Angles are a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal.

Question 10.
Name the relationship between ∠4 and ∠6.
Type below:
____________

Answer:
same-side interior angles

Explanation:
∠4 and ∠6 are same-side interior angles.

Find each angle measure.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 1: Parallel Lines Cut by a Transversal img 3

Question 11.
m∠AGE when m∠FHD = 30°
_________ °

Answer:
m∠AGE = 30°

Explanation:
∠AGE and ∠FHD are alternate exterior angles.
Therefore, m∠AGE = m∠FHD = 30°
m∠AGE = 30°

Question 12.
m∠AGH when m∠CHF = 150°
_________ °

Answer:
150°

Explanation:
∠AGH and ∠CHF are corresponding angles.
Therefore, m∠AGH = m∠CHF = 150°
m∠AGH = 150°

Question 13.
m∠CHF when m∠BGE = 110°
_________ °

Answer:
110°

Explanation:
∠CHF and ∠BGE are alternate exterior angles.
Therefore, m∠CHF = m∠BGE = 110°
m∠CHF = 110°

Question 14.
m∠CHG when m∠HGA = 120°
_________ °

Answer:
m∠CHG = 60º

Explanation:
∠CHF and ∠HGA are same-side interior angles.
m∠CHG + m∠HGA = 180°
m∠CHG + 120° = 180°
m∠CHG = 180 – 120 = 60
m∠CHG = 60º

Question 15.
m∠BGH
_________ °

Answer:
78º

Explanation:
∠BGH and ∠GHD are same-side interior angles.
So, ∠BGH + ∠GHD = 180º
3x + (2x + 50)º = 180º
5x = 180º – 50º = 130º
x = 130/5 = 26º
∠BGH = 3xº = 3 × 26º = 78º
∠GHD = (2x + 50) += (2 × 26 + 50) = 102º

Question 16.
m∠GHD
_________ °

Answer:
102º

Explanation:
∠BGH and ∠GHD are same-side interior angles.
So, ∠BGH + ∠GHD = 180º
3x + (2x + 50)º = 180º
5x = 180º – 50º = 130º
x = 130/5 = 26º
∠BGH = 3xº = 3 × 26º = 78º
∠GHD = (2x + 50) += (2 × 26 + 50) = 102º

Parallel Lines cut by a Transversal Quiz Answer Key Question 17.
The Cross Country Bike Trail follows a straight line where it crosses 350th and 360th Streets. The two streets are parallel to each other. What is the measure of the larger angle formed at the intersection of the bike trail and 360th Street? Explain.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 1: Parallel Lines Cut by a Transversal img 4
_________ °

Answer:
The larger angle formed at the intersection of the bike trail and 360th Street is 132º

Explanation:
grade 8 chapter 11 image 1
The larger angle formed at the intersection of the bike trail and 360th Street is angle 5 in our schema. ∠5 and ∠3 are same-side interior angles. Therefore, m∠5 + m∠3 = 180º
m∠5 + 48º = 180º
m∠5 = 180º – 48º
m∠5 = 132º

Question 18.
Critical Thinking How many different angles would be formed by a transversal intersecting three parallel lines? How many different angle measures would there be?
_________ different angles
_________ different angle measures

Answer:
12 different angles
2 different angle measures

Explanation:
There are 12 different angles formed by a transversal intersecting three parallel lines.
There are 2 different angle measures:
m∠1 = m∠4 = m∠5 = m∠8 = m∠9 = m∠12
m∠2 = m∠3 = m∠6 = m∠7 = m∠10 = m∠11

Parallel Lines Cut by a Transversal – Page No. 352

Question 19.
Communicate Mathematical Ideas In the diagram at the right, suppose m∠6 = 125°. Explain how to find the measures of each of the other seven numbered angles.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 1: Parallel Lines Cut by a Transversal img 5
Type below:
____________

Answer:
m∠2 = m∠6 = 125º because ∠2 and ∠6 are corresponding angles.
m∠3 = m∠2 = 125º because ∠3 and ∠2 are vertical angles.
m∠7 = m∠3 = 125º because ∠7 and ∠3 are corresponding angles.
∠4 and ∠6 are same-side interior angles.
Therefore, m∠4 + m∠6 = 180º
m∠4 + 125º = 180º
m∠4 = 180º – 125º
m∠4 = 55º
m∠8 = m∠4 = 55º because ∠8 and ∠4 are corresponding angles.
m∠1 = m∠4 = 55º because ∠1 and ∠4 are vertical angles.
m∠5 = m∠1 = 55º because ∠5 and ∠1 are corresponding angles.

FOCUS ON HIGHER ORDER THINKING

Parallel Lines and Triangles Worksheet Answers Question 20.
Draw Conclusions In a diagram showing two parallel lines cut by a transversal, the measures of two same-side interior angles are both given as 3x°. Without writing and solving an equation, can you determine the measures of both angles? Explain. Then write and solve an equation to find the measures.

Answer:
m∠1 and m∠2 are same-side interior angles is 180º
Therefore, m∠1 + m∠2 = 180º
3x + 3x = 180º
6x = 180º
x = 180/6 = 30
m∠1 = m∠2 = 3x = 3(30) = 90º

Question 21.
Make a Conjecture Draw two parallel lines and a transversal. Choose one of the eight angles that are formed. How many of the other seven angles are congruent to the angle you selected? How many of the other seven angles are supplementary to your angle? Will your answer change if you select a different angle?
Type below:
____________

Answer:
grade 8 chapter 11 image 3
We have to select ∠a form of eight angles that are formed. There are two other angles that are congruent to the angle ∠a. Two other angles are ∠e and ∠g.
There are no supplementary to ∠a.
If we select a different angle then the answer will also change.

Question 22.
Critique Reasoning In the diagram at the right, ∠2, ∠3, ∠5, and∠8 are all congruent, and∠1, ∠4, ∠6, and ∠7 are all congruent. Aiden says that this is enough information to conclude that the diagram shows two parallel lines cut by a transversal. Is he correct? Justify your answer.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 1: Parallel Lines Cut by a Transversal img 6
____________

Answer:
This is not enough information to conclude that the diagram shows two parallel lines cut by a transversal. Because ∠2 and ∠3 are same-side interior angles. But ∠5 and ∠8 are not congruent with each other. And ∠6 and ∠7 are same-side interior angles. But ∠1 and ∠4 are not congruent with each other.

Guided Practice – Angle Theorems for Triangles – Page No. 358

Find each missing angle measure.

Question 1.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 7
m∠M = _________ °

Answer:
m∠M = 71º

Explanation:
From the Triangle Sum Theorem,
m∠L + m∠N + m∠M = 180º
78º + 31º + m∠M = 180º
109º + m∠M = 180º
m∠M = 180º – 109º
m∠M = 71º

Angle Relationships Study Guide Answer Key Pdf Question 2.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 8
m∠Q = _________ °

Answer:
m∠Q = 30º

Explanation:
From the Triangle Sum Theorem,
m∠Q + m∠S + m∠R = 180º
m∠Q + 24º + 126º = 180º
m∠Q + 150º = 180º
m∠Q = 180º – 150º
m∠Q = 30º

Use the Triangle Sum Theorem to find the measure of each angle in degrees.

Question 3.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 9
m∠T = _________ °
m∠V = _________ °
m∠U = _________ °

Answer:
m∠T = 88°
m∠V = 63°
m∠U = 29°

Explanation:
From the Triangle Sum Theorem,
m∠U + m∠T + m∠V = 180º
(2x + 5)º + (7x + 4)º + (5x + 3)º = 180º
2xº + 5º + 7xº + 4º + 5xº + 3º = 180º
14xº + 12º = 180º
14xº = 168º
x = 168/14 = 12
Substitute x value to find the angles
m∠U = (2x + 5)º = ((2 . 12) + 5)º = 29º
m∠U = 29º
m∠T = (7x + 4)º = ((7 . 12) + 4)º = 88º
m∠T = 88º
m∠V = (5x + 3)º = ((5 . 12) + 3)º = 63º
m∠V = 63º

Parallel Lines and Angle Relationships Worksheet Answers Question 4.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 10
m∠X = _________ °
m∠Y = _________ °
m∠Z = _________ °

Answer:
m∠X = 90°
m∠Y = 45 °
m∠Z = 45°

Explanation:
From the Triangle Sum Theorem,
m∠X + m∠Y + m∠Z = 180º
nº + (1/2 . n)º + (1/2 . n)º = 180º
2nº = 180º
n = 90
Substitute n values to find the angles
m∠X = nº = 90º
m∠X = 90º
m∠Y = (1/2 . n)º = (1/2 . 90)º = 45º
m∠Y = 45º
m∠Z = (1/2 . n)º = (1/2 . 90)º = 45º
m∠Z = 45º

Use the Exterior Angle Theorem to find the measure of each angle in degrees.

Question 5.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 11
m∠C = _________ °
m∠D = _________ °

Answer:
m∠C = 40°
m∠D = 76°

Explanation:
Given m∠C = 4y°, m∠D = (7y + 6)°, m∠E = 116°
By using the exterior angle theorem,
∠DEC + ∠DEF = 180°
grade 8 chapter 11 image 4
∠DEC + 116° = 180°
∠E = ∠DEC = 180° – 116° = 64°
The sum of the angles of a triangle = 180°
∠C +∠D + ∠E = 180°
4y° + (7y + 6)°+ 64° = 180°
11y° + 70° = 180°
11y° = 180° – 70° = 110°
y = 10
∠C = 4y° = 4. 10 = 40°
∠D = (7y + 6)° = ((7 . 10)  + 6)° = (70 + 6)° = 76°

Angle Relationships Worksheet Answer Key Pdf Question 6.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 12
m∠L = _________ °
m∠M = _________ °

Answer:
m∠L = 129°
m∠M = 32°

Explanation:
Given that m∠M = (5z – 3)°, m∠L = (18z + 3)°, m∠JKM = 161°
From the Exterior Angle Theorem,
m∠M + m∠L = m∠JKM
(5z – 3)° + (18z + 3)° = 161°
5z° – 3° + 18z° + 3° = 161°
23z° = 161°
z = 161/23 = 7
Substitute z values to find the angles
m∠M = (5z – 3)° = ((5 . 7) – 3)° = 32°
m∠L = (18z + 3)° = ((18 . 7) + 3)° = 129°
From the Triangle Sum Theorem,
m∠M + m∠L + m∠LKM = 180º
32º + 129º + m∠LKM = 180º
161º + m∠LKM = 180º
m∠LKM = 19º

ESSENTIAL QUESTION CHECK-IN

Question 7.
Describe the relationships among the measures of the angles of a triangle.
Type below:
______________

Answer:
The sum of all measures of the interior angles of a triangle is 180°. The measure of the exterior angle of a triangle is equal to the sum of its remote interior angles.

11.2 Independent Practice – Angle Theorems for Triangles – Page No. 359

Find the measure of each angle.

Question 8.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 13
m∠E = _________ °
m∠F = _________ °

Answer:
m∠E = 41°
m∠F = 41°

Explanation:
m∠E = x°, m∠F = x°,  m∠D = 98°
From the Triangle Sum Theorem, sum of the angles of the traingle is 180°
m∠E + m∠D + m∠F = 180°
x + 98 + x = 180°
2x + 98 = 180°
2x = 82°
x = 41°
So, m∠E = 41°
m∠F = 41°

Angle Relationships in Triangles Answer Key Question 9.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 14
m∠T = _________ °
m∠V = _________ °

Answer:
m∠T = 60°
m∠V = 30°

Explanation:
m∠W = 90°, m∠T = 2x°,  m∠V = x°
From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°
m∠T + m∠V + m∠W = 180°
2x + x + 90 = 180°
3x = 90°
x = 30°
So, m∠T = 2x° = 2 . 30° = 60°
m∠V = x° = 30°

Question 10.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 15
m∠G = _________ °
m∠H = _________ °
m∠J = _________ °

Answer:
m∠G = 75°
m∠H = 60°
m∠J = 45°

Explanation:
m∠G = 5x°, m∠H = 4x°,  m∠J = 3x°
From the Triangle Sum Theorem, the sum of the angles of the traingle is 180°
m∠G + m∠H + m∠J = 180°
5x + 4x + 3x = 180°
12x = 90°
x = 15°
So, m∠G = 5x° = 5 . 15° = 75°
m∠H = 4x° = 4. 15° = 60°
m∠J = 3x° = 3. 15° = 45°

Question 11.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 16
m∠Q = _________ °
m∠P = _________ °
m∠QRP = _________ °

Answer:
m∠Q = 98°
m∠P = 55°
m∠QRP = 27°

Explanation:
Given that m∠Q = (3y + 5)°, m∠P = (2y – 7)°, m∠QRS = 153°
From the exterior angle Theorem,
∠QRS + ∠QRP = 180°
153° + ∠QRP = 180°
grade 8 chapter 11 image 5
m∠R = m∠QRP = 180° – 153° = 27°
From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°
m∠P + m∠Q + m∠R = 180°
(3y + 5)° + (2y – 7)°+ 27° = 180°
5y° + 25 = 180°
5y° = 155°
y = 31°
m∠Q = (3y + 5)° = ((3 . 31°) + 5)° = 98°
m∠P = (2y – 7)° = ((2. 31° – 7)° = 55°
m∠QRP = 27°

Angle Relationships Math Lib Answer Key Question 12.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 17
m∠ACB = _________ °
m∠DCE = _________ °
m∠BCD = _________ °

Answer:
m∠ACB = 44°
m∠DCE = 35°
m∠BCD = 101°

Explanation:
In traingle ABC, m∠A = 78°, m∠B = 58°, m∠ACB = ?°
From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°
m∠A + m∠B + m∠ACB = 180°
78° + 58° + m∠ACB = 180°
m∠ACB = 180° – 136°
m∠ACB = 44°
In traingle CDE, m∠D = 85°, m∠E = 60°, m∠CDE = ?°
From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°
m∠D + m∠E + m∠CDE = 180°
85° + 60° + m∠CDE = 180°
m∠CDE = 180° – 145°
m∠CDE = 35°
From the Exterior Angle Theorem,
m∠ACB + m∠CDE + m∠BCD = 180°
44° + 35° + m∠BCD = 180°
m∠BCD = 180° – 79°
m∠BCD = 101°

Question 13.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 18
m∠K = _________ °
m∠L = _________ °
m∠KML = _________ °
m∠LMN = _________ °

Answer:

Explanation:
m∠K = 2x°, m∠L = 3x°, m∠KML = x°
So, From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°.
m∠K + m∠L + m∠KML = 180°
2x° + 3x° + x° = 180°
6x° = 180°
x= 30°
∠KML = x = 30°
∠L = 3x = 3 . 30° = 90°
∠K = 2x = 2 . 30° = 60°
From the Exterior Angle Theorem,
∠KML + ∠LMN = 180°
∠LMN = 180° – 30° = 150°

Question 14.
Multistep The second angle in a triangle is five times as large as the first. The third angle is two-thirds as large as the first. Find the angle measures.
The measure of the first angle: _________ °
The measure of the second angle: _________ °
The measure of the third angle: _________ °

Answer:
The measure of the first angle: 27°
The measure of the second angle: 135°
The measure of the third angle: 18°

Explanation:
Let us name the angles of a triangle as ∠1, ∠2, ∠3.
Consider ∠1 as x.
∠2 is 5 times as large as the first.
∠2 = 5x
Also, ∠3 = 2/3 . x
So, From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°.
x+ 5x + (2/3 . x) = 180°
20x = 540°
x = 27°
So, ∠1 = x = 27°
∠2 = 5x = 5 . 27° = 135°
∠3 = 2/3 . x = 2/3 . 27° = 18°
The measure of the first angle: 27°
The measure of the second angle: 135°
The measure of the third angle: 18°

Angle Theorems for Triangles – Page No. 360

Question 15.
Analyze Relationships Can a triangle have two obtuse angles? Explain.
___________

Answer:
No; a triangle can NOT have two obtuse angles

Explanation:
The measure of an obtuse angle is greater than 90°. Two obtuse angles and the third angle would have a sum greater than 180°

FOCUS ON HIGHER ORDER THINKING

Question 16.
Critical Thinking Explain how you can use the Triangle Sum Theorem to find the measures of the angles of an equilateral triangle.
Type below:
___________

Answer:
All angles have the same measure in an equilateral triangle

Explanation:
Using the Triangle Sum Theorem,
∠x + ∠x + ∠x = 180°
3∠x = 180°
∠x = 60°
All angles have the same measure in an equilateral triangle

Angle Relationships 8th Grade Math Question 17.
a. Draw Conclusions Find the sum of the measures of the angles in quadrilateral ABCD. (Hint: Draw diagonal \(\overline { AC } \). How can you use the figures you have formed to find the sum?)
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 2: Angle Theorems for Triangles img 19
Sum: _________ °

Answer:
Sum: 360°

Question 17.
b. Make a Conjecture Write a “Quadrilateral Sum Theorem.” Explain why you think it is true.
Type below:
___________

Answer:
The sum of the angle measures of a quadrilateral is 360°
Any quadrilateral can be divided into two triangles (180 + 180 = 360)

Angle in Triangles Math Lib Answer Key Question 18.
Communicate Mathematical Ideas Describe two ways that an exterior angle of a triangle is related to one or more of the interior angles.
Type below:
___________

Answer:
An exterior angle and it’s an adjacent interior angle equal 180°
An exterior angle equals the sum of the two remote interior angles.

Guided Practice – Angle-Angle Similarity – Page No. 366

Question 1.
Explain whether the triangles are similar. Label the angle measures in the figure.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 3: Angle-Angle Similarity img 20
Type below:
___________
△ABC has angle measures _______and △DEF has angle measures______. Because _______in one triangle are congruent to ______in the other triangle, the triangles are_____.

Answer:
△ABC has angle measures 40°, 30°, and 109° and △DEF has angle measures 41°, 109°, and 30°. Because 2∠s in one triangle are congruent to in the other triangle, the triangles similar.

Angle-Angle Similarity Worksheet Answers Question 2.
A flagpole casts a shadow 23.5 feet long. At the same time of day, Mrs. Gilbert, who is 5.5 feet tall, casts a shadow that is 7.5 feet long. How tall in feet is the flagpole? Round your answer to the nearest tenth.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 3: Angle-Angle Similarity img 21
_________ ft

Answer:
17.2 ft

Explanation:
In similar triangles, corresponding side lengths are proportional.
5.5/7.5 = h/23.5
h (7.5) = 129.25
h = 129.25/7.5
h = 17.23
Rounding to the nearest tenth
h = 17.2 feet

Question 3.
Two transversals intersect two parallel lines as shown. Explain whether △ABC and △DEC are similar.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 3: Angle-Angle Similarity img 22
∠BAC and∠EDC are ___________ since they are ___________.
∠ABC and∠DEC are ___________ since they are ___________.
By ________, △ABC and△DEC are ___________.
Type below:
___________

Answer:
∠BAC and∠EDC are congruent since they are alt. interior ∠s
∠ABC and∠DEC are congruent since they are alt. interior ∠s.
By AA similarity, △ABC and△DEC are similar.

ESSENTIAL QUESTION CHECK-IN

Question 4.
How can you determine when two triangles are similar?
Type below:
___________

Answer:
If 2 angles of one triangle are congruent to 2 angles of another triangle, the triangles are similar by the Angle-Angle Similarity Postulate

11.3 Independent Practice – Angle-Angle Similarity – Page No. 367

Use the diagrams for Exercises 5–7.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 3: Angle-Angle Similarity img 23

Question 5.
Find the missing angle measures in the triangles.
Type below:
___________

Answer:
m∠B = 42°
m∠F = 69°
m∠H = 64°
m∠K = 53°

Explanation:
Using the Triangle Sum Theorem,
m∠A + m∠B + m∠C = 180°
85° + m∠B + 53° = 180°
138° + m∠B = 180°
m∠B = 180° – 138°
m∠B = 42°
Using the Triangle Sum Theorem,
m∠D + m∠E + m∠F = 180°
We substitute the given angle measures and we solve for m∠F
64° + 47° + m∠F = 180°
111° + m∠F = 180°
m∠F = 180° – 111°
m∠F = 69°
Using the Triangle Sum Theorem,
m∠G + m∠H + m∠J = 180°
We substitute the given angle measures and we solve for m∠H
47° + m∠H + 69° = 180°
116° + m∠H = 180°
m∠H = 180° – 116°
m∠H = 64°
Using the Triangle Sum Theorem,
m∠J + m∠K + m∠L = 180°
We substitute the given angle measures and we solve for m∠K
85° + m∠K + 42° = 180°
127° + m∠K = 180°
m∠K = 180° – 127°
m∠K = 53°

11.3 Corresponding Parts of Similar Figures Answer Key Pdf Question 6.
Which triangles are similar?
Type below:
___________

Answer:
△ABC and △JKL are similar because their corresponding angles are congruent. Also, △DEF and △GHJ are similar because their corresponding is congruent.

Question 7.
Analyze Relationships Determine which angles are congruent to the angles in △ABC.
∠A ≅ ∠ ________
∠B ≅ ∠ ________
∠C ≅ ∠ ________

Answer:
△JKL ≅ △ABC

Explanation:
△JKL has angle measures that are the same as those is △ABC
∠A ≅ ∠ J
∠B ≅ ∠ L
∠C ≅ ∠ K
Therefore, they are congruent.

Question 8.
Multistep A tree casts a shadow that is 20 feet long. Frank is 6 feet tall,and while standing next to the tree he casts a shadow that is 4 feet long.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 3: Angle-Angle Similarity img 24
a. How tall is the tree?
h = ________ ft

Answer:
h = 30 ft

Explanation:
In similar triangles, corresponding side lengths are proportional.
20/4 = h/6
5 = h/6
h = 30
The tree is 30 feet tall.

Question 8.
b. How much taller is the tree than Frank?
________ ft

Answer:
24 ft

Explanation:
30 – 6 = 24
The tree is 24 feet taller than Frank.

Question 9.
Represent Real-World Problems Sheila is climbing on a ladder that is attached against the side of a jungle gym wall. She is 5 feet off the ground and 3 feet from the base of the ladder, which is 15 feet from the wall. Draw a diagram to help you solve the problem. How high up the wall is the top of the ladder?
________ ft

Answer:
25 ft

Explanation:
grade 8 chapter 11 image 6
3/15 = 5/h
15 ×3 = 3h
75 = 3h
h = 75/3 = 25

11.3 Practice Angle Relationships and Parallel Lines Answers Question 10.
Justify Reasoning Are two equilateral triangles always similar? Explain.
______________

Answer:
yes; two equilateral triangles are always similar.
Each angle of an equilateral triangle is 60°. Since both triangles are equilateral then they are similar.

Angle-Angle Similarity – Page No. 368

Question 11.
Critique Reasoning Ryan calculated the missing measure in the diagram shown. What was his mistake?
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Lesson 3: Angle-Angle Similarity img 25
\(\frac{3.4}{6.5}=\frac{h}{19.5}\)
19.5 × \(\frac{3.4}{6.5}=\frac{h}{19.5}\) × 19.5
\(\frac{66.3}{6.5}\) = h
10.2cm = h
Type below:
___________

Answer:
In the first line, Ryan did not take the sum of 6.5 and 19.5 to get the denominator on the right.
The denominator on the right should be 26 instead of 19.5
The correct value for h
3.4/6.5 = h/26
h = (3.4/6.5) × 26
h = 13.6cm

FOCUS ON HIGHER ORDER THINKING

Question 12.
Communicate Mathematical Ideas For a pair of triangular earrings, how can you tell if they are similar? How can you tell if they are congruent?
Type below:
___________

Answer:
The earrings are similar if two angle measures of one are equal to two angle measures of the other.
The earrings are congruent if they are similar and if the side lengths of one are equal to the side lengths of the other.

Question 13.
Critical Thinking When does it make sense to use similar triangles to measure the height and length of objects in real life?
Type below:
___________

Answer:
If the item is too tall or the distance is too long to measure directly, similar triangles can help with measuring.

Question 14.
Justify Reasoning Two right triangles on a coordinate plane are similar but not congruent. Each of the legs of both triangles are extended by 1 unit, creating two new right triangles. Are the resulting triangles similar? Explain using an example.
___________

Answer:
Two triangles are similar if their corresponding angles are congruent and the lengths of their corresponding sides are proportional. If each of the legs of both triangles is extended by 1 unit, the ratio between proportional sides does not change. Therefore, the resulting triangles are similar.

Ready to Go On? – Model Quiz – Page No. 369

11.1 Parallel Lines Cut by a Transversal

In the figure, line p || line q. Find the measure of each angle if m∠8 = 115°.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Model Quiz img 26

Question 1.
m∠7 = _________ °

Answer:
m∠7 = 65°

Explanation:
According to the exterior angle theorem,
m∠7 + m∠8 = 180°
m∠7 + 115° = 180°
m∠7 = 180° – 115°
m∠7 = 65°

How do Parallel Lines cut by a Transversal Question 2.
m∠6 = _________ °

Answer:
m∠6 = 115°

Explanation:
From the given figure, Line P is parallel to line Q. So, the angles given in line P is equal to the angles in line Q. They are corresponding angles.
So, m∠8 is parallel is m∠6 or m∠8 = m∠6 = 115°

Question 3.
m∠1 = _________ °

Answer:
m∠1 = 115°

Explanation:
∠1 and ∠6 are alternative exterior angles.
So, m∠1 = m∠6 = 115°

11.2 Angle Theorems for Triangles

Find the measure of each angle.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Model Quiz img 27

Question 4.
m∠A = _________ °

Answer:
m∠A = 48°

Explanation:
m∠A + m∠B + m∠C = 180°
4y° + (3y + 22)° + 74° = 180°
7y = 180 – 96 = 84
y = 12°
m∠A = 4y° = 4 (12°) = 48°
m∠B = (3y + 22)° = (3(12°) + 22)° = 58°

Question 5.
m∠B = _________ °

Answer:
m∠B = 58°

Explanation:
m∠A + m∠B + m∠C = 180°
4y° + (3y + 22)° + 74° = 180°
7y = 180 – 96 = 84
y = 12°
m∠A = 4y° = 4 (12°) = 48°
m∠B = (3y + 22)° = (3(12°) + 22)° = 58°

Transversal Angles Relationships Question 6.
m∠BCA = _________ °

Answer:
m∠BCA = 74°

Explanation:
m∠BCD + m∠BCA = 180°
106° + m∠BCA = 180°
m∠BCA = 180° – 106°
m∠BCA = 74°
So, m∠BCA = 74°

11.3 Angle-Angle Similarity

Triangle FEG is similar to triangle IHJ. Find the missing values.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Model Quiz img 28

Question 7.
x = _________

Answer:
x = 16

Explanation:
In similar triangles, corresponding side lengths are proportional.
HJ/EG = IJ/FG
(x + 12)/42 = 40/60
(x + 12)/42 = 4/6
6x = 96
x = 16

Question 8.
y = _________

Answer:
y = 9

Explanation:
In similar triangles, corresponding side lengths are congruent.
m∠HJI = m∠EGF
(5y + 7)° = 52°
5y° + 7° = 52°
5y° = 45°
y = 9

Question 9.
m∠H = _________°

Answer:
m∠H = 92°

Explanation:
Using the Triangle Sum Theorem,
m∠E + m∠F + m∠G = 180°
We substitute the given angle measures and we solve for m∠E
m∠E + 36° + 52° = 180°
m∠E + 88° = 180°
m∠E = 92°
In similar angles, corresponding side lengths are congruent
m∠H = m∠E
m∠H = 92°

ESSENTIAL QUESTION

Question 10.
How can you use similar triangles to solve real-world problems?
Type below:
____________

Answer:
we know that if two triangles are similar, then their corresponding angles are congruent and the lengths of their corresponding sides are proportional. We can use this to determine values that we cannot measure directly. For example, we can calculate the length of the tree if we measure its shadow and our shadow on a sunny day.

Selected Response – Mixed Review – Page No. 370

Use the figure for Exercises 1 and 2.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Mixed Review img 29

Question 1.
Which angle pair is a pair of alternate exterior angles?
Options:
A. ∠5 and ∠6
B. ∠6 and∠7
C. ∠5 and ∠4
D. ∠5 and ∠2

Answer:
C. ∠5 and ∠4

Explanation:
∠5 and ∠4 are alternate exterior angles

Question 2.
Which of the following angles is not congruent to ∠3?
Options:
A. ∠1
B. ∠2
C. ∠6
D. ∠8

Answer:
B. ∠2

Explanation:
∠2 and ∠3 are same-side interior angles. They are not congruent instead their sum is equal to 180°

Angle Sums and Exterior Angles of Triangles Independent Practice Worksheet Answers Question 3.
The measures, in degrees, of the three angles of a triangle are given by 2x + 1, 3x – 3, and 9x. What is the measure of the smallest angle?
Options:
A. 13°
B. 27°
C. 36°
D. 117°

Answer:
B. 27°

Explanation:
From the Triangle Sum Theorem, the sum of the angles of the triangle is 180°
m∠1 + m∠2 + m∠3 = 180°
(2x + 1)° + (3x – 3)° + (9x)° = 180°
2x° + 1° + 3x° – 3° + 9x° = 180°
14x° – 2° = 180°
14x° = 178°
x = 13
Substitute the value of x to find the m∠1, m∠2, and m∠3
m∠1 = (2x + 1)° = (2(13) + 1)° = 27°
m∠2 = (3x – 3)° = (3(13) – 3)° = 36°
m∠3 = (9x)° = (9(13))° = 117°
The smallest angle is 27°

Question 4.
Which is a possible measure of ∠DCA in the triangle below?
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Mixed Review img 30
Options:
A. 36°
B. 38°
C. 40°
D 70°

Answer:
D 70°

Explanation:
Using the Exterior Angle Theorem
m∠A + m∠B = m∠DCA
m∠A + 40° = m∠DCA
m∠DCA will be greater than 40°. The only suitable option is D, 70°.

Question 5.
Kaylee wrote in her dinosaur report that the Jurassic period was 1.75 × 108 years ago. What is this number written in standard form?
Options:
A. 1,750,000
B. 17,500,000
C. 175,000,000
D. 17,500,000,000

Answer:
C. 175,000,000

Explanation:
1.75 × 108 standard form
Move the decimal point to 8 right places.
175,000,000

Question 6.
Given that y is proportional to x, what linear equation can you write if y is 16 when x is 20?
Options:
A. y = 20x
B. y = \(\frac{5}{4}\) x
C. y = \(\frac{4}{5}\)x
D. y = 0.6x

Answer:
C. y = \(\frac{4}{5}\)x

Explanation:
Y=4/5x
16=4/5(20)
4/5×20/1=80/5
80/5=16

Mini-Task

Angles and Parallel Lines Answer Key Question 7.
Two transversals intersect two parallel lines as shown.
Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Mixed Review img 31
a. What is the value of x?
x = ________

Answer:
x = 4

Explanation:
mJKL = mLNM
6x + 1 = 25
6x = 24
x = 4

Question 7.
b. What is the measure of ∠LMN?
_________°

Answer:
23°

Explanation:
m∠LMN = 3x + 11 = 3(4) + 11 = 12 + 11 = 23

Question 7.
c. What is the measure of ∠KLM?
∠KLM = _________°

Answer:
∠KLM = 48°

Explanation:
∠KLM exterior angle of the triangle LMN
m∠KLM = m∠LNM + m∠LMN
= 25 + 23 = 48

Question 7.
d. Which two triangles are similar? How do you know?
Type below:
_____________

Answer:
triangle JKL = triangle LNM
triangle KJL = triangle LMN

Explanation:
triangle JLK and triangle LNM are similar.
triangle JKL = triangle LNM
triangle KJL = triangle LMN

Conclusion:

Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles PDF for the best practice. Practice all the math questions available on Grade 8 Text Book and learn how to solve Grade 8 math questions in a simple way.

Go Math Grade 8 Answer Key Chapter 11 Angle Relationships in Parallel Lines and Triangles Read More »

Go Math Grade 8 Answer Key Chapter 6 Functions

Go Math Grade 8 Answer Key Chapter 6 Functions PDF is provided here for download. The best-loved math experts are provided an easy way of solving maths questions along with the explanations. Every problem is simplified with a clear explanation with many tricks. Great problems with a high level of difficulty also solved in an easy way. Refer to Go Math Grade 8 Answer Key Chapter 6 Functions now to begin your practice.

Go Math Grade 8 Chapter 6 Functions Answer Key

Prefer learning using Go Math Grade 8 Chapter 6 Functions Solution Key. To get the good results in an exam you must prepare with the Go Math Grade 8 Chapter 6 Answer Key. Use HMH Go Math Grade 8 Answer Key for the best practice of maths. Step by step explanation is provided for every question below. Build your confidence in solving math problems by practicing with Go Math Grade 8 Answer Key Chapter 6 Functions.

Lesson 1: Identifying and Representing Functions 

Lesson 2: Describing Functions

Lesson 3: Comparing Functions 

Lesson 4: Analyzing Graphs

Model Quiz 

Mixed Review 

Guided Practice – Identifying and Representing Functions – Page No. 158

Complete each table. In the row with x as the input, write a rule as an algebraic expression for the output. Then complete the last row of the table using the rule.

Question 1.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 1
Type below:
_______________

Answer:
Grade 8 Chapter 6 image 1

Explanation:
Unit Cost of ticket = 40/2 = 20
Total cost = 20x where x is the number of tickets.
x = 20x
10 = 20(100) = 200

Question 2.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 2
Type below:
_______________

Answer:
Grade 8 Chapter 6 image 2

Explanation:
Number of pages per minute = 1/2 = 0.5
Total cost = 0.5x where x is the number of minutes.
x = 0.5x
30 = 0.5(30) = 15

Identifying and Representing Functions Question 3.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 3
Type below:
_______________

Answer:
Grade 8 Chapter 6 image 3

Explanation:
Units cost of Muffins = 2.25/1 = 2.25
Total cost = 2.25x where x is the number of muffins
x = 2.25x
12 = 2.25(12) = 27

Determine whether each relationship is a function.

Question 4.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 4
_______________

Answer:
Function

Explanation:
Each input is assigned to exactly one output.

Question 5.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 5
_______________

Answer:
Not a function

Explanation:
The input value is 4 is paired with two outputs 25 and 35

Lesson 6.1 Identifying and Representing Functions Reteach Answer Key Question 6.
The graph shows the relationship between the weights of 5 packages and the shipping charge for each package. Is the relationship represented by the graph a function? Explain.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 6
_______________

Answer:
Function

Explanation:
Each input is assigned to exactly one output.

Essential Question Check-In

Question 7.
What are four different ways of representing functions? How can you tell if a relationship is a function?
Type below:
_______________

Answer:
The function can be represented by an equation, table, graph, and Venn diagram.
If a relationship is a function, each input is paired with exactly one output.

Independent Practice – Identifying and Representing Functions – Page No. 159

Determine whether each relationship represented by the ordered pairs is a function. Explain.

Question 8.
(2, 2), (3, 1), (5, 7), (8, 0), (9, 1)
_______________

Answer:
Function

Explanation:
Each input value is paired with exactly one output value.

Question 9.
(0, 4), (5, 1), (2, 8), (6, 3), (5, 9)
_______________

Answer:
Not a function

Explanation:
The input value is 5 is paired with two outputs 1 and 9

Identifying and Representing Functions Worksheet Answers Question 10.
Draw Conclusions
Joaquin receives $0.40 per pound for 1 to 99 pounds of aluminum cans he recycles. He receives $0.50 per pound if he recycles more than 100 pounds. Is the amount of money Joaquin receives a function of the weight of the cans he recycles? Explain your reasoning.
_______________

Answer:
Yes

Explanation:
The amount of money increases with the weight of the cans. No weight will result in the same amount of money earned.

Question 11.
A biologist tracked the growth of a strain of bacteria, as shown in the graph.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 7
a. Explain why the relationship represented by the graph is a function.
Type below:
_______________

Answer:
The relationship is a function as each input has been assigned exactly one output. There is only one number of bacteria for each number of hours.

Question 11.
b. What If?
Suppose there was the same number of bacteria for two consecutive hours. Would the graph still represent a function? Explain.
Type below:
_______________

Answer:
Yes. If the number of bacteria for two consecutive hours is the same, one input will still be paired with one output, hence the relationship is still a function.

Question 12.
Multiple Representations
Give an example of a function in everyday life, and represent it as a graph, a table, and a set of ordered pairs. Describe how you know it is a function.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 8
Type below:
_______________

Answer:
The cost of a bouquet of flowers and the number of flowers in the bouquet is a function. The unit cost of flowers = $0.85 and x the number of flowers. Hence, C= 0.85x
Grade 8 Chapter 6 image 4
Grade 8 Chapter 6 image 5
(2, 1.7), (4, 3.4), (6, 5.1), (8, 6.8), (10, 8.5)
Each value of the input is paired with exactly one output.

Identifying and Representing Functions – Page No. 160

The graph shows the relationship between the weights of six wedges of cheese and the price of each wedge.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 1: Identifying and Representing Functions img 9

Question 13.
Is the relationship represented by the graph a function? Justify your reasoning. Use the words “input” and “output” in your explanation, and connect them to the context represented by the graph.
_______________

Answer:
Yes, the relationship represented by the graph is a function.
Each input (weight) in the graph is paired with exactly one output(price).

6.1 Identifying and Representing Functions Answer Key Question 14.
Analyze Relationships
Suppose the weights and prices of additional wedges of cheese were plotted on the graph. Might that change your answer to question 13? Explain your reasoning.
Type below:
_______________

Answer:
No. As the weight of the cheese will increase, the cost of wedges of cheese will increase as well. Hence, for each input (weight), there would be exactly one output (price).

H.O.T.

Focus on Higher Order Thinking

Question 15.
Justify Reasoning
A mapping diagram represents a relationship that contains three different input values and four different output values. Is the relationship a function? Explain your reasoning.
_______________

Answer:
No. Since there are three inputs and four outputs, one of the inputs will have more than one output, hence the relationship cannot be a function.

Question 16.
Communicate Mathematical Ideas
An onion farmer is hiring workers to help harvest the onions. He knows that the number of days it will take to harvest the onions is a function of the number of workers he hires. Explain the use of the word “function” in this context.
Type below:
_______________

Answer:
Number of days = f(number of workers)

Explanation:
We know that the more the number of workers will be involved in the harvesting of onion, the lesser days it will take to complete.
Thus the number of workers becomes the independent variable and the number of days becomes the dependent variable.
Here the word function is used to describe that the number of days is dependent on the number of workers.
Number of days = f(number of workers)

Guided Practice – Describing Functions – Page No. 164

Plot the ordered pairs from the table. Then graph the function represented by the ordered pairs and tell whether the function is linear or nonlinear.

Question 1.
y = 5 − 2x
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 2: Describing Functions img 10
_______________

Answer:
Grade 8 Chapter 6 image 6
Grade 8 Chapter 6 image 7
The graph of a linear function is a straight line
Linear relationship

Explanation:
Given y = 5 – 2x
y = 5 – 2(-1) = 5 + 2 = 7
y = 5 – 2(1) = 5 – 2 = 3
y = 5 – 2(3) = 5 – 6 = -1
y = 5 – 2(5) = 5 – 10 = -5

Analyzing Functions and Graphs Answer Key Question 2.
y = 2 − x2
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 2: Describing Functions img 11
_______________

Answer:
y = 2 − x2
Grade 8 Chapter 6 image 8
Graph the ordered pairs. Then draw a line through the points to represent the solution.
Grade 8 Chapter 6 image 9
Graph of a linear function is not a straight line
Non-linear relationship

Explanation:
y = 2 − x2
y = 2 – 4 = -2
y = 2 – 1 = 1
y = 2 – 0 = 2
y = 2 – 1 = 1
y = 2 – 4 = -2

Explain whether each equation is a linear equation.

Question 3.
y = x2 – 1
_______________

Answer:
The equation is not in the form of a linear equation, hence is not a linear equation.

Explanation:
Compare the equation with the general linear equation y = mx + b.
The equation is not in the form of a linear equation, hence is not a linear equation.

Question 4.
y = 1 – x
_______________

Answer:
The equation is in the form of a linear equation, hence is a linear equation.

Explanation:
Compare the equation with the general linear equation y = mx + b.
The equation is in the form of a linear equation, hence is a linear equation.

Essential Question Check-In

Question 5.
Explain how you can use a table of values, an equation, and a graph to determine whether a function represents a proportional relationship.
Type below:
_______________

Answer:
From a table, determine the ratio y/x. If it is constant the relationship is proportional.
From a graph, note if the graph passes through the origin. The graph of a proportional relationship must pass through the origin (0, 0).
From an equation, compare with the general linear form of the equation, y = mx + b. If b = 0, the relationship is proportional.

Independent Practice – Describing Functions – Page No. 165

Question 6.
State whether the relationship between x and y in y = 4x – 5 is proportional or nonproportional. Then graph the function.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 2: Describing Functions img 12
_______________

Answer:
Grade 8 Chapter 6 image 10

Explanation:
First, we compare the equation with the general linear equation y = mx + b. y = 4x – 5 is in the form of y = mx + b, with m = 4 and b = -5. Therefore, the equation is a linear equation. Since b is not equal to 0, the relationship is non-proportional.
Then, we choose several values for the input x. We substitute these values of x in the equation to find the output y.
y = 4x – 5
If x = 0; y = 4(0) – 5 = -5; (0, -5)
If x = 2; y = 4(2) – 5 = 3; (2, 3)
If x = 4; y = 4(4) – 5 = 11; (4, 11)
If x = 6; y = 4(6) – 5 = 19; (6, 19)
We graph the ordered pairs and we draw a line through the points to represent the solutions of the function.

Question 7.
The Fortaleza telescope in Brazil is a radio telescope. Its shape can be approximated with the equation y = 0.013x2. Is the relationship between x and y linear? Is it proportional? Explain.
____________
____________

Answer:
Compare the equation with the general linear equation y = mx + b.
The equation is not in the form of a linear equation, hence it is not a linear equation. Since x is squared, it is not proportional.

Question 8.
Kiley spent $20 on rides and snacks at the state fair. If x is the amount she spent on rides, and y is the amount she spent on snacks, the total amount she spent can be represented by the equation x + y = 20. Is the relationship between x and y linear? Is it proportional? Explain.
____________
____________

Answer:
x + y = 20
Rewriting the equation
y = 20 – x
Compare the equation with the general linear equation y = mx + b.
It is linear
Since b is not equal to 0, the relationship is not proportional.

Question 9.
Represent Real-World Problems
The drill team is buying new uniforms. The table shows y, the total cost in dollars, and x, the number of uniforms purchased.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 2: Describing Functions img 13
a. Use the data to draw a graph. Is the relationship between x and y linear? Explain.
____________

Answer:
Grade 8 Chapter 6 image 10
The graph of a linear relationship is a straight line.
x and y are linear.

Question 9.
b. Use your graph to predict the cost of purchasing 12 uniforms.
$ ________

Answer:
$720

Explanation:
Grade 8 Chapter 6 image 10
The cost of 12 uniforms is $720

Go Math Grade 8 Chapter 6 Answer Key Question 10.
Marta, a whale calf in an aquarium, is fed a special milk formula. Her handler uses a graph to track the number of gallons of formula y the calf drinks in x hours. Is the relationship between x and y linear? Is it proportional? Explain.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 2: Describing Functions img 14
____________
____________

Answer:
The relationship is linear
The relationship is proportional

Explanation:
As the data lies on a straight line, the relationship is linear
As the graph passes through the origin, the relationship is proportional

Describing Functions – Page No. 166

Question 11.
Critique Reasoning
A student claims that the equation y = 7 is not a linear equation because it does not have the form y=mx + b. Do you agree or disagree? Why?
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 2: Describing Functions img 15
____________

Answer:
Disagree; The equation can be written in the form y = mx + b Where m is 0. The graph of the solutions is a horizontal line.

Identifying and Representing Functions Worksheet Answer Key Question 12.
Make a Prediction
Let x represent the number of hours you read a book and y represent the total number of pages you have read. You have already read 70 pages and can read 30 pages per hour. Write an equation relating x hours and y pages you read. Then predict the total number of pages you will have read after another 3 hours.
_______ pages

Answer:
160 pages

Explanation:
Let x represent the number of hours you read a book and y represents the total number of pages you have read. You have already read 70 pages and can read 30 pages per hour.
m = 30; b = 70 pages
y = 30x + 70
x = 3 hrs
y = 30(3) + 70 = 160

H.O.T.

Focus on Higher Order Thinking

Question 13.
Draw Conclusions
Rebecca draws a graph of a real-world relationship that turns out to be a set of unconnected points. Can the relationship be linear? Can it be proportional? Explain your reasoning.
Type below:
______________

Answer:
The relationship is linear if all the points lie on the same line. If the relationship is linear and passes through the origin, it is proportional.

Question 14.
Communicate Mathematical Ideas
Write a real-world problem involving a proportional relationship. Explain how you know the relationship is proportional.
Type below:
______________

Answer:
The amount of money earned at a car wash is a proportional relationship. When there are 0 cars washed, $0 are earned. The amount of money earned increases by the unit cost of a car wash.

Question 15.
Justify Reasoning
Show that the equation y + 3 = 3(2x + 1) is linear and that it represents a proportional relationship between x and y.
Type below:
______________

Answer:
y + 3 = 3(2x + 1)
y +3 = 6x + 3
y = 6x
As b = 0, it is a Proportional Relationship.

Guided Practice – Comparing Functions – Page No. 170

Doctors have two methods of calculating maximum heart rate. With the first method, the maximum heart rate, y, in beats per minute is y = 220 − x, where x is the person’s age. Maximum heart rate with the second method is shown in the table.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 3: Comparing Functions img 16

Question 1.
Which method gives the greater maximum heart rate for a 70-year-old?
____________ method

Answer:
Second

Explanation:
y = 220 – x
y = 220 – 70 = 150
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (20, 194) and (x2, y2) = (30, 187)
Slope m = (y2 -y1)/(x2 – x1) = (187 – 194)/(30 – 20) = -7/10 = -0.7
197 = -0.7(20) + b
y-intercept b = 208
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = -0.7 and b = 208.
y = -0.7x +208
x = 70yrs
y = -0.7(70) + 208 = 159
150 < 159
The second method gives a greater maximum heart rate for a 70-year old.

Lesson 6.3 Comparing Functions Answer Key Question 2.
Are heart rate and age proportional or nonproportional for each method?
____________

Answer:
For method 1, the relationship is non-proportional.
For method 2, the relationship is non-proportional.

Explanation:
Compare the equation with the general linear equation y = mx + b.
It is linear
Since b is not equal to 0, the relationship is not proportional.

Aisha runs a tutoring business. With Plan 1, students may choose to pay $15 per hour. With Plan 2, they may follow the plan shown on the graph.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 3: Comparing Functions img 17

Question 3.
Describe the plan shown on the graph.
Type below:
______________

Answer:
Choose two points on the graph to find the slope.
Find the slope
m = (y2 -y1)/(x2 – x1)
m = (60 – 40)/(4 – 0) = 20/4 = 5
Read the y-intercept from the graph: b = 40
Use your slope and y-intercept values to write an equation in slope-intercept
form.
y = 5x + 40
Plan 2 has an initial cost of $40 and a rate of $5 per hour.

Question 4.
Sketch a graph showing the $15 per hour option.
Type below:
______________

Answer:
Grade 8 Chapter 6 image 11

Question 5.
What does the intersection of the two graphs mean?
Type below:
______________

Answer:
The intersection of the two graphs represents the number of hours for which both plans will cost the same,

Question 6.
Which plan is cheaper for 10 hours of tutoring?
______________

Answer:
Plan 1
y = 15x
x = 10 hrs
y = 15(10) = $150
Plan 2
y = 5x + 40
y = 5(10) + 40 = $90
$150 > $90
Plane 2 is cheaper

Question 7.
Are cost and time proportional or nonproportional for each plan?
Type below:
______________

Answer:
Comparing with the general linear form of equation y = mx + b. Since b = 0, the relationship is proportional
The cost and time are proportional for Plan 1
Comparing with the general linear form of equation y = mx + b. Since b is not equal to 0, the relationship is proportional
The cost and time are not proportional for Plan 2

Essential Question Check-In

Question 8.
When using tables, graphs, and equations to compare functions, why do you find the equations for tables and graphs?
Type below:
______________

Answer:
The tables and graphs represent a part of the solution of the function. By writing the equation, any value can be a substitute to evaluate the function and compare it with the equations.

Independent Practice – Comparing Functions – Page No. 171

The table and graph show the miles driven and gas used for two scooters.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 3: Comparing Functions img 18

Question 9.
Which scooter uses fewer gallons of gas when 1350 miles are driven?
______________

Answer:
Scooter B uses fewer gallons of gas when 1350 miles are driven

Explanation:
The equation for Scooter A Slope m = m = (y2 -y1)/(x2 – x1) where (x1, y1) = (150, 2) and (x2, y2) = (300, 4)
Slope m = (y2 -y1)/(x2 – x1) = (4 – 2)/(300 – 150) = 2/150 = 1/75
2 = 1/75(150) + b
y-intercept b = 0
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 1/75 and b = 0.
y = 1/75x
x = 1350 miles
y = 1/75(1,350)
y = 18gal
The equation for Scooter B Slope m = m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 0) and (x2, y2) = (90, 1)
Slope m = (y2 -y1)/(x2 – x1) = (1 – 0)/(90 – 0) = 1/90
2 = 1/90(90) + b
y-intercept b = 0
Substituting the value of the slope m and y-intercept in the slope-intercept form. y = mx + b where, m = 1/90 and b = 0.
y = 1/90x
x = 1350 miles
y = 1/90(1,350)
y = 15gal
Compare the gallons of gas to drive 1,350 miles
18 > 15
Scooter B uses fewer gallons of gas when 1,350 miles are driven.

Lesson 6.3 Comparing Functions Reteach Answer Key Question 10.
Are gas used and miles proportional or nonproportional for each scooter?
______________

Answer:
The gas used and miles are proportional to both scooters.

Explanation:
Compared with the general linear form of an equation, y = mx + b. If b = 0, the relationship is proportional.
The gas used and miles are proportional to both scooters.

A cell phone company offers two texting plans to its customers. The monthly cost, y dollars, of one plan, is y = 0.10x + 5, where x is the number of texts. The cost of the other plan is shown in the table.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 3: Comparing Functions img 19

Question 11.
Which plan is cheaper for under 200 texts?
______________

Answer:
Plane 1 is cheaper

Explanation:
Plan 1
y = 0.10x + 5
Substitute x = 199
y = 0.10(199) + 5 = $24.90
Find the slope using two points from the graph by m = (y2 -y1)/(x2 – x1) where (x1, y1) = (100, 20), (x2, y2) =(200, 25)
Substitute the value of m and (x1, y1) = (100, 20), (x2, y2) =(200, 25)
Slope m = (y2 -y1)/(x2 – x1) = (25 – 20)/(200 – 100) = 5/100 = 0.05
20 = 0.05(100) + b
y-intercept b = 15
Substituting the value of slope (m) and (x, y) in the slope-intercept form to find y-intercept (b):
y = 0.05x + 15
x = 199
y = 0.05(199) + 15 = $24.95
Compare the cost for two plans for text < 200
$24.90 < $24.95
Plane 1 is cheaper

Question 12.
The graph of the first plan does not pass through the origin. What does this indicate?
Type below:
______________

Answer:
Plan 1
y = 0.10x + 5
The graph that does not pass through the origin indicates that there is a base price of $5 for the plan.

Question 13.
Brianna wants to buy a digital camera for a photography class. One store offers the camera for $50 down and a payment plan of $20 per month. The payment plan for a second store is described by y = 15x + 80, where y is the total cost in dollars and x is the number of months. Which camera is cheaper when the camera is paid off in 12 months? Explain.
______________

Answer:
For the first store, the slope-intercept form y = mx + b where m = 20 dollars per month and b = 50 dollars.
y = 20x + 50
x = 12 months
y = 20(12) + 50 = $290
Second store
y = 15x + 80
x = 12 months
y = 15(12) + 80 = $260
Compare the cost of the camera if it paid off in 12 months $290 > $260
The camera is cheaper at the second store

Comparing Functions – Page No. 172

Question 14.
The French club and soccer team are washing cars to earn money. The amount earned, y dollars, for washing x cars is a linear function. Which group makes the most money per car? Explain.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 3: Comparing Functions img 20
______________

Answer:

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (2, 10) and (x2, y2) = (4, 20)
Slope m = (y2 -y1)/(x2 – x1) = (20 – 10)/(4 – 2) = 10/2 = 5
French Club makes $5 per car.
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (0, 0) and (x2, y2) = (2, 16)
Slope m = (y2 -y1)/(x2 – x1) = (16 – 0)/(2 – 0) = 16/2 = 8
Soccer Club makes $8 per car.
Compare the money earned for washing one car $5 < $8
Soccer club makes the most money per car

H.O.T.

Focus on Higher Order Thinking

Question 15.
Draw Conclusions
Gym A charges $60 a month plus $5 per visit. The monthly cost at Gym B is represented by y = 5x + 40, where x is the number of visits per month. What conclusion can you draw about the monthly costs of the gyms?
__________ is more expensive

Answer:
Gym A is more expensive

Explanation:
Since the rate per visit is the same, the monthly cost of Gyn A is always more than Gym B.

Question 16.
Justify Reasoning
Why will the value of y for the function y = 5x + 1 always be greater than that for the function y = 4x + 2 when x > 1?
Type below:
______________

Answer:
y1 = 5x + 1 and y2 = 4x + 2 Subtracting y2 from y1
y1 – y2 = 5x + 1 – (4x + 2)
y1 – y2 = x -1
For x>= 1 we get x – 1 >= 0
So y1 – y2 >= 0 or y1 >= y2

Question 17.
Analyze Relationships
The equations of two functions are y = −21x + 9 and y = −24x + 8. Which function is changing more quickly? Explain.
______________

Answer:
y = -21x + 9
y = -24x + 8
y = -24x + 8 is changing more quickly as the absolute value of -24 is greater than the absolute value of -21.

Guided Practice – Analyzing Graphs – Page No. 176

In a lab environment, colonies of bacteria follow a predictable pattern of growth. The graph shows this growth over time.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 21

Question 1.
What is happening to the population during Phase 2?
______________

Answer:
For Phase 2, the graph is increasing quickly. This shows a period of rapid growth.

Sketching Graphs and Comparing Functions Question 2.
What is happening to the population during Phase 4?
______________

Answer:
In Phase 4, the graph is decreasing, hence the number of bacteria is decreasing.

The graphs give the speeds of three people who are riding snowmobiles. Tell which graph corresponds to each situation.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 22

Question 3.
Chip begins his ride slowly but then stops to talk with some friends. After a few minutes, he continues his ride, gradually increasing his speed.
______________

Answer:
Graph 2

Explanation:
The slope of the graph is increasing, then it becomes constant and starts increasing again.
Graph 2

Question 4.
Linda steadily increases her speed through most of her ride. Then she slows down as she nears some trees.
______________

Answer:
Graph 3

Explanation:
The slope of the graph is increasing and then decreasing.
Graph 3

Question 5.
Paulo stood at the top of a diving board. He walked to the end of the board and then dove forward into the water. He plunged down below the surface, then swam straight forward while underwater. Finally, he swam forward and upward to the surface of the water. Draw a graph to represent Paulo’s elevation at different distances from the edge of the pool.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 23
Type below:
______________

Answer:
Grade 8 Chapter 6 image 12

Independent Practice – Analyzing Graphs – Page No. 177

Tell which graph corresponds to each situation below.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 24

Question 6.
Arnold started from home and walked to a friend’s house. He stayed with his friend for a while and then walked to another friend’s house farther from home.
______________

Answer:
Graph 3

Explanation:
The graph increases (as Arnold walks from home to their friend’s house), then becomes constant (when he stays with his friend), and then increases again (when he walk to another friend’s house farther away).
Graph 3

Question 7.
Francisco started from home and walked to the store. After shopping, he walked back home.
______________

Answer:
Graph 1

Explanation:
The graph increases (as Francisco walks from home to the store), becomes constant (when he shops), and then decreases (as he walked back home)
Graph 1

Question 8.
Celia walks to the library at a steady pace without stopping.
______________

Answer:
Graph 2

Explanation:
The graph increases at a constant rate (as Celia walks to the library without any stops)
Graph 2

Regina rented a motor scooter. The graph shows how far away she is from the rental site after each half-hour of riding.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 25

Question 9.
Represent Real-World Problems
Use the graph to describe Regina’s trip. You can start the description like this: “Regina left the rental shop and rode for an hour…”
Type below:
______________

Answer:
Regina left the rental shop and rode for an hour. She rested for half an hour and then started back. After half an hour, she changed her mind and rode for another half an hour. She rest for half an hour. Then she started back and ranched the rental site in 2 hours.

Question 10.
Analyze Relationships
Determine during which half-hour Regina covered the greatest distance.
Type below:
______________

Answer:
Regina covered the greatest distance between 0.5 to 1hr of the journey. She covered 12 miles.

Analyzing Graphs – Page No. 178

The data in the table shows the speed of a ride at an amusement park at different times one afternoon.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 26

Question 11.
Sketch a graph that shows the speed of the ride over time.
Type below:
______________

Answer:
Grade 8 Chapter 6 image 13

Question 12.
Between which times is the ride’s speed increasing the fastest?
Type below:
______________

Answer:
The speed is increasing the fastest during the 3: 21 and 3: 22

Question 13.
Between which times is the ride’s speed decreasing the fastest?
Type below:
______________

Answer:
The speed is decreasing the fastest during the 3: 23 and 3: 24

H.O.T.

Focus on Higher Order Thinking
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 27

Question 14.
Justify Reasoning
What is happening to the fox population before time t? Explain your reasoning.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 28
Type below:
______________

Answer:
The population decreases and then increases before time t

Question 15.
What If?
Suppose at time t, a conservation organization moves a large group of foxes to the island. Sketch a graph to show how this action might affect the population on the island after time t.
Go Math Grade 8 Answer Key Chapter 6 Functions Lesson 4: Analyzing Graphs img 29
Type below:
______________

Answer:
Grade 8 Chapter 6 image 14

Explanation:
Population is decreasing at first, then it is increasing rapidly.

Question 16.
Make a Prediction
At some point after time t, a forest fire destroys part of the woodland area on the island. Describe how your graph from problem 15 might change.
Type below:
______________

Answer:
The population would dramatically decrease if there was a fire due to lack of food supply and good land.

6.1 Identifying and Representing Functions – Model Quiz – Page No. 179

Determine whether each relationship is a function.

Question 1.
Go Math Grade 8 Answer Key Chapter 6 Functions Model Quiz img 30
__________

Answer:
Not a function

Explanation:
A relationship is a function when each input is paired with exactly one output. The input 5 has more than one output.
Not a function

Question 2.
Go Math Grade 8 Answer Key Chapter 6 Functions Model Quiz img 31
__________

Answer:
Function

Explanation:
A relationship is a function when each input is paired with exactly one output.
Each input is paired with only one output.
Function

Identifying and Representing Functions Homework Answer Key Question 3.
(2, 5), (7, 2), (−3, 4), (2, 9), (1, 1)
__________

Answer:
Not a function

Explanation:
A relationship is a function when each input is paired with exactly one output. Input 2 has more than one output.
Not a function

6.2 Describing Functions

Determine whether each situation is linear or nonlinear, and proportional or nonproportional.

Question 4.
Joanna is paid $14 per hour.
__________
__________

Answer:
Linear
Proportional

Explanation:
Writing the situation as an equation, where x is the number of hours.
y = 14x
Compare with general linear equation y = mx + b
Linear
Since b = 0, the relationship is proportional.
Proportional

Question 5.
Alberto started out bench pressing 50 pounds. He then added 5 pounds every week.
__________
__________

Answer:
Linear
Non-proportional

Explanation:
Writing the situation as an equation, where x is the number of hours.
y = 5x + 50
Compare with general linear equation y = mx + b
Linear
Since b is not equal to 0, the relationship is non-proportional.
Non-proportional

6.3 Comparing Functions

Question 6.
Which function is changing more quickly? Explain.
Go Math Grade 8 Answer Key Chapter 6 Functions Model Quiz img 32
__________

Answer:
Function 2 is changing more quickly.

Explanation:
Find the rate of change for function 1
Rate of Change = (20 – 0)/(0 – 5) = -4
Find the rate of change for function 1
Rate of Change = (6.5 – 11)/(3 – 2) = -4.5
Althogh -4.5 < -4, the absolute value of -4.5 s greater than -4.
Function 2 is changing more quickly.

6.4 Analyzing Graphs

Question 7.
Describe a graph that shows Sam running at a constant rate.
Type below:
______________

Answer:
The graph would be a straight line

Explanation:
Since Sam is running at a constant rate, distance covered per unit of time remains the same and the relationship is linear and proportional.
The graph would be a straight line

Essential Question

Question 8.
How can you use functions to solve real-world problems?
Type below:
______________

Answer:
If in the equation the power of x is 1 then it is linear otherwise nonlinear.
In a graph, if the points form a line it is linear if they form a curve it is a nonlinear function.

Selected Response – Mixed Review – Page No. 180

Question 1.
Which table shows a proportional function?
Go Math Grade 8 Answer Key Chapter 6 Functions Mixed Review img 33
Options:
a. A
b. B
c. C
d. D

Answer:
c. C

Explanation:
It contains the ordered pair of the origin (0, 0)
Option C represents a proportional relationship.

Question 2.
What is the slope and y-intercept of the function shown in the table?
Go Math Grade 8 Answer Key Chapter 6 Functions Mixed Review img 34
Options:
a. m = -2; b = -4
b. m = -2; b = 4
c. m = 2; b = 4
d. m = 4; b = 2

Answer:
c. m = 2; b = 4

Explanation:
Find the slope using two points from the grapgh by
Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (1, 6) and (x2, y2) = (4, 12)
Slope m = (y2 -y1)/(x2 – x1) = (12 – 6)/(4 – 1) = 6/3 = 2
Substituting the value of the slope m and (x, y) to find the slope-intercept form.
12 = 4(2) + b
y-intercept b = 4

Question 3.
The table below shows some input and output values of a function.
Go Math Grade 8 Answer Key Chapter 6 Functions Mixed Review img 35
What is the missing output value?
Options:
a. 20
b. 21
c. 22
d. 23

Answer:
b. 21

Explanation:
Find the rate of change = (17.5 – 14)/(5 – 4) = 3.5
Since the missing output is corresponding to x = 6 and 3.5 to 17.5 (for x = 5)
Output = 17.5 + 3.5 = 21

Lesson 6 Extra Practice Construct Functions Answer Key Question 4.
Tom walked to school at a steady pace, met his sister, and they walked home at a steady pace. Describe this graph.
Options:
a. V-shaped
b. upside down V-shaped
c. Straight line sloping up
d. Straight line sloping down

Answer:
b. upside-down V-shaped

Explanation:
The graph would increase at a constant rate and would decrease at a constant rate.
The graph would be the upside-down V-shaped

Mini-Task

Question 5.
Linear functions can be used to find the price of a building based on its floor area. Below are two of these functions.
y = 40x + 15,000
Go Math Grade 8 Answer Key Chapter 6 Functions Mixed Review img 36
a. Find and compare the slopes.
Type below:
____________

Answer:
Compare the slopes
The slope for the first function is less than the slope of the second function.
y = 40x + 15000
Compare with slope intercept form y = mx + b where m is the slope m = 40
Second function find the slope using given points by Slope m = (y2 -y1)/(x2 – x1) where (x1, y1) = (7, 3) and (x2, y2) = (6, 4)
Slope m = (y2 -y1)/(x2 – x1) = (56000 – 32000)/(700 – 400) = 24000/300 = 80
m = 80

Question 5.
b. Find and compare the y-intercepts.
Type below:
____________

Answer:
y = 40x + 15,000
Compare with slope-intercept form y = mx + b where m is the slope b = 15000
The second function finds the slope using given points by Slope m and (x, y) in the slope-intercept form to find y-intercept b
y = mx + b where (x, y) = (700, 56000) and m = 80
56000 = 80(700) + b
b = 0
Compare y-intercepts
The y-intercept of the first function is greater than the y-intercept of the second function

Question 5.
c. Describe each function as proportional or nonproportional.
Type below:
____________

Answer:
Comparable to slope intercept form y = mx + b
First function: y = 40x + 15000
Second function: y = 80x
Since b is not equal to 0
The first function is non-proportional
Since b = 0
The second function is proportional.

Conclusion:

Download Go Math Grade 8 Answer Key Chapter 6 Functions PDF for free. Famous and great math experts are working to provide the best way of solving math problems. Immediately, start your practice and learn maths easily.

Go Math Grade 8 Answer Key Chapter 6 Functions Read More »

Scroll to Top