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McGraw Hill Math Grade 7 Lesson 10.3 Answer Key Adding and Subtracting Money

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 10.3 Adding and Subtracting Money existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 10.3 Adding and Subtracting Money

Exercises Calculate

Question 1.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 1
Answer:
$56 + $32 = $88.

Explanation:
The addition of $56 and $32 is $88.
MCGRAW~1

Question 2.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 2
Answer:
$22.71 + $5.20 = $17.51.

Explanation:
The addition of $22.71 and $5.20 is $17.51.
MCGRAW~2

Question 3.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 3
Answer:
$15-$12.40 = $2.6.

Explanation:
The subtraction of $15-$12.40 is $2.6.
MCGRAW~3

Question 4.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 4
Answer:
$11.06 + $0.32 = $11.38.

Explanation:
The addition of $11.06 and $.32 is $11.38.
MCGRAW~4

Question 5.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 5
Answer:
$10-$7.21 = $2.79.

Explanation:
The subtraction of $10-$7.21 is $2.79.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-5-1

Question 6.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 6
Answer:
$315.32-$297.61 = $17.71.

Explanation:
The subtraction of $315.32-$297.61 is $17.71.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-6-1

Question 7.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 7
Answer:
$89.45-$3.50 = $85.95.

Explanation:
The subtraction of $89.45-$3.50 is $85.95.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-7-1

Question 8.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 8
Answer:
$34-$4.77 = $29.23.

Explanation:
The subtraction of $34-$4.77 is $29.23.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-8-1

Question 9.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 9
Answer:
$1000.03-$88.4 = $911.61.

Explanation:
The subtraction of $1000.03-$88.4 is $911.61.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-9-1

Question 10.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 10
Answer:
$45 and $2.30 = $47.3.

Explanation:
The addition of $45 and $2.30 is $47.3.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-10-1

Question 11.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 11
Answer:
$89-$56.81 = $32.19.

Explanation:
The subtraction of $89-$56.81 is $32.19.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-11-1

Question 12.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 12
Answer:
$813-$7.71 = $805.29.

Explanation:
The subtraction of $813-$7.71 is $805.29.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-12-1

Question 13.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 13
Answer:
$5-$2.93 = $2.07.

Explanation:
The subtraction of $5-$2.93 is $2.07.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-13-1

Question 14.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 14
Answer:
$71.45-$3.56 = $67.89.

Explanation:
The subtraction of $71.45-$3.56 is $67.89.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-14-1

Question 15.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 15
Answer:
$8.55-$2.61 = $5.94.

Explanation:
The subtraction of $8.55-$2.61 is $5.94.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-15-1

Question 16.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 16
Answer:
$3.21-$2 = $1.21.

Explanation:
The subtraction of $3.21-$2 is $1.21.

McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-16-1

Question 17.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 17
Answer:
$1561-$87.87 = $1473.13.

Explanation:
The subtraction of $1561-$87.87 is $1473.13.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-17-1

Question 18.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 18
Answer:
$1987.23-$476.30 = $1,510.93.

Explanation:
The subtraction of $1987.23-$476.30 is $1,510.93.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-18-1

Question 19.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 19
Answer:
$81-$22.57 = $58.43.

Explanation:
The subtraction of $81-$22.57 is $58.43.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-19-1

Question 20.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.3 Answer Key Adding and Subtracting Money 20
Answer:
$45.60-$7 = $38.6.

Explanation:
The subtraction of $45.60-$7 is $38.6.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.3-Answer-Key-Adding-and-Subtracting-Money-20-1

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McGraw Hill Math Grade 7 Lesson 10.2 Answer Key Subtracting Decimals

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 10.2 Subtracting Decimals existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 10.2 Subtracting Decimals

Exercises Subtract

Question 1.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 1
Answer: The subtraction of decimals 15.45 – 7.82 is 7.63.

Explanation:
The subtraction of decimals 15.45 – 7.82 is 7.63.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-1-1

Question 2.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 2
Answer:
48.001 – 5.62 = 42.381.

Explanation:
The subtraction of decimals 48.001 – 5.62 is 42.381.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-2-1

Question 3.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 3
Answer:
88.88 – 2.97 = 5.9758.

Explanation:
The subtraction of decimals 88.88 – 2.97 is 5.9758.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 20-1

Question 4.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 4
Answer:
50.202 – 2.5005 = 47.7015.

Explanation:
The subtraction of decimals 50.202 – 2.5005 is 47.7015.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-4-1

Question 5.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 5
Answer:
10.3 – 4.777 = 5.523.

Explanation:
The subtraction of decimals 10.3 – 4.777 is 5.523.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-5-1

Question 6.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 6
Answer:
100.111 – 5.374 = 94.737.

Explanation:
The subtraction of decimals 100.111 – 5.374 is 94.737.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-6-1

Question 7.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 7
Answer:
565.002 – 12.345 = 552.657.

Explanation:
The subtraction of decimals 565.002 – 12.345 is 552.657.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-7-1

Question 8.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 8
Answer:
7.701 – 6.994 = 0.707.

Explanation:
The subtraction of decimals 7.701 – 6.994 is 0.707.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-8-1

Question 9.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 9
Answer:
5.5514 – 4.61 = 0.9414.

Explanation:
The subtraction of decimals 5.5514 – 4.61 is 0.9414.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-9-1

Question 10.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 10
Answer:
12.157 – 5.2 = 6.957.

Explanation:
The subtraction of decimals 12.157 – 5.2 is 6.957.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-10-1

Question 11.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 11
Answer:
89.7 – 63.63 = 26.07.

Explanation:
The subtraction of decimals 89.7 – 63.63 is 26.07.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-11-1

Question 12.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 12
Answer:
3.561 – 2.9872 = 0.5738.

Explanation:
The subtraction of decimals 3.561 – 2.9872 is 0.5738.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-12-1

Question 13.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 13
Answer:
4789.32 – 555.55 = 4233.77.

Explanation:
The subtraction of decimals 4789.32 – 555.55 is 4233.77.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-13-1

Question 14.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 14
Answer:
8.651 – 6.98 = 1.671.

Explanation:
The subtraction of decimals 8.651 – 6.98 is 1.671.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-14-1

Question 15.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 15
Answer:
45.87 – 33.999 = 11.871.

Explanation:
The subtraction of decimals 45.87 – 33.999 is 11.871.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-15-1

Question 16.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 16
Answer:
963.751 – 8.8 = 954.951.

Explanation:
The subtraction of decimals 963.751 – 8.8 is 954.951.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-16-1

Question 17.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 17
Answer:
8.789 – 1.79 = 6.999.

Explanation:
The subtraction of decimals 8.789 – 1.79 is 6.999.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-17-1

Question 18.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 18
Answer:
5.2 – 3.571= 1.629.

Explanation:
The subtraction of decimals 5.2 – 3.571 is 1.629.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-18-1

Question 19.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 19
Answer:
6.91 – 2.84 = 4.07.

Explanation:
The subtraction of decimals 6.91 – 2.84 is 4.07.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-19-1

Question 20.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.2 Answer Key Subtracting Decimals 20
Answer:
8.888 – 2.913 = 5.975.

Explanation:
The subtraction of decimals 8.888 – 2.913 is 5.975.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.2-Answer-Key-Subtracting-Decimals-21-1

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McGraw Hill Math Grade 7 Lesson 10.1 Answer Key Adding Decimals

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 10.1 Adding Decimals existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 10.1 Adding Decimals

Exercises Add

Question 1.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 1
Answer:
45.45 + 2.1 = 47.55.

Explanation:
The addition of decimals 45.45 and 2.1 is 47.55.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-1

Question 2.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 2
Answer:
33.7 + 41.22 = 74.92.

Explanation:
The addition of decimals 33.7 and 41.22 is 74.92.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-2-1

Question 3.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 3
Answer:
5.4 + 8.54 = 13.94.

Explanation:
The addition of decimals 5.4 and 8.54 is 13.94.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-3-1

Question 4.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 4
Answer:
2.22 + 3.001 = 5.221.

Explanation:
The addition of decimals 2.22 and 3.001 is 5.221.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-4-1

Question 5.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 5
Answer:
33.045 + 0.011 = 33.056.

Explanation:
The addition of decimals 33.045 and 0.011 is 33.056.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-5-1

Question 6.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 6
Answer:
9.0901 + 13.245 = 22.3351.

Explanation:
The addition of decimals 9.0901 and 13.245 is 22.3351.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-6-1

Question 7.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 7
Answer:
0.782 + 5.6 = 6.382.

Explanation:
The addition of decimals 0.782 and 5.6 is 6.382.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-7-1

Question 8.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 8
Answer:
454.32 + 2.111 = 456.431.

Explanation:
The addition of decimals 454.32 and 2.111 is 456.431.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-8-1

Question 9.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 9
Answer:
4.5 + 9.5001 = 14.0001

Explanation:
The addition of decimals 4.5 and 9.5001 is 14.0001.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-9-1

Question 10.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 10
Answer:
63.1 + 5.46 = 68.56.

Explanation:
The addition of decimals 63.1 and 5.46 is 68.56.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-10-1

Question 11.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 11
Answer:
2.22201 + 7.38 = 9.60201.

Explanation:
The addition of decimals 2.22201 and 7.38 is 9.60201.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-11-1

Question 12.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 12
Answer:
8.704 + 18.0001 = 23.7041.

Explanation:
The addition of decimals 8.704 and 18.0001 is 26.7041.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-12-1

Question 13.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 13
Answer:
4.147 + 5.963 = 10.11.

Explanation:
The addition of decimals 4.147 and 5.963 is 10.11.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-13

Question 14.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 14
Answer:
9.46 + 55.7222 = 65.1822.

Explanation:
The addition of decimals 9.46 and 55.7222 is 65.1822.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-14-1

Question 15.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 15
Answer:
0.00152 + 152.1522 = 152.15372.

Explanation:
The addition of decimals 0.00152 and 152.1522 is 152.15372.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-15-1

Question 16.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 16
Answer:
3.202 + 2.3031 = 5.5051.

Explanation:
The addition of decimals 3.202 and 2.3031 is 5.5051.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-16-1

Question 17.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 17
Answer:
9.781 + 1.832 = 11.613.

Explanation:
The addition of decimals 9.781 and 1.832 is 11.613.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-17-1

Question 18.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 18
Answer:
2.2222 + 8.888 = 11.1102.

Explanation:
The addition of decimals 2.2222 and 8.888 is 11.1102.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-18-1

Question 19.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 19
Answer:
478.654 + 3.9702 = 482.6242.

Explanation:
The addition of decimals 478.654 and 3.9702 is 482.6242.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-19-1

Question 20.
McGraw Hill Math Grade 7 Chapter 10 Lesson 10.1 Answer Key Adding Decimals 20
Answer:
3.303 + 19.0771 = 22.3801.

Explanation:
The addition of decimals 3.303 and 19.0771 is 22.3801.
McGraw-Hill-Math-Grade-7-Chapter-10-Lesson-10.1-Answer-Key-Adding-Decimals-20-1

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McGraw Hill Math Grade 7 Lesson 7.1 Answer Key Multiply Fractions and Whole Numbers

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 7.1 Multiply Fractions and Whole Numbers existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 7.1 Multiply Fractions and Whole Numbers

Exercises Multiply

Question 1.
3 × \(\frac{1}{4}\)
Answer:
\(\frac{3}{4}\)
Explanation:
3 × \(\frac{1}{4}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{3}{1}\) × \(\frac{1}{4}\)
= \(\frac{3}{4}\)

Question 2.
15 × \(\frac{2}{7}\)
Answer:
4\(\frac{2}{7}\)
Explanation:
15 × \(\frac{2}{7}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{15}{1}\) × \(\frac{2}{7}\)
= \(\frac{30}{7}\)
= 4\(\frac{2}{7}\)

Question 3.
12 × –\(\frac{3}{8}\)
Answer:
-4\(\frac{1}{2}\)
Explanation:
12 × –\(\frac{3}{8}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{12}{1}\) × –\(\frac{3}{8}\)
= –\(\frac{12 X 3}{8}\)
= \(\frac{36}{8}\)
= -4\(\frac{1}{2}\)

Question 4.
22 × \(\frac{3}{11}\)
Answer:
6
Explanation:
22 × \(\frac{3}{11}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{22}{1}\) × –\(\frac{3}{11}\)
= \(\frac{22 X 3}{11}\)
= \(\frac{66}{11}\)
= 6

Question 5.
15 × –\(\frac{3}{20}\)
Answer:
-2\(\frac{1}{4}\)
Explanation:
15 × –\(\frac{3}{20}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{15}{1}\) × –\(\frac{3}{20}\)
=-\(\frac{15 X 3}{20}\)
= –\(\frac{45}{20}\)
= –\(\frac{9}{4}\)
= -2\(\frac{1}{4}\)

Question 6.
31 × \(\frac{2}{17}\)
Answer:
3\(\frac{11}{17}\)
Explanation:
31 × \(\frac{2}{17}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{31}{1}\) × \(\frac{2}{17}\)
= \(\frac{31 X 2}{17}\)
= \(\frac{62}{17}\)
= 3\(\frac{11}{17}\)

Question 7.
6 × \(\frac{7}{24}\)
Answer:
1\(\frac{3}{4}\)
Explanation:
6 × \(\frac{7}{24}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{6}{1}\) × \(\frac{7}{24}\)
= \(\frac{6 X 7}{24}\)
= \(\frac{42}{24}\)
= \(\frac{7}{4}\)
= 1\(\frac{3}{4}\)

Question 8.
14 × \(\frac{10}{11}\)
Answer:
12\(\frac{8}{11}\)
Explanation:
14 × \(\frac{10}{11}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{14}{1}\) × \(\frac{10}{11}\)
= \(\frac{14 X 10}{11}\)
= \(\frac{140}{11}\)
= 12\(\frac{8}{11}\)

Question 9.
16 × \(\frac{5}{36}\)
Answer:
2\(\frac{2}{9}\)
Explanation:
\(\frac{16}{1}\) × \(\frac{5}{36}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{16 X 5}{36}\)
= \(\frac{80}{36}\)
= 2\(\frac{2}{9}\)

Question 10.
7 × \(\frac{2}{3}\)
Answer:
4\(\frac{2}{3}\)
Explanation:
7 × \(\frac{2}{3}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{7}{1}\) × \(\frac{2}{3}\)
= \(\frac{7 X 2}{3}\)
= \(\frac{14}{3}\)
= 4\(\frac{2}{3}\)

Question 11.
16 × –\(\frac{3}{5}\)
Answer:
-9\(\frac{3}{5}\)
Explanation:
16 × \(\frac{3}{5}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{16}{1}\) × \(\frac{3}{5}\)
= \(\frac{16 X 3}{5}\)
= \(\frac{93}{5}\)
= -9\(\frac{3}{5}\)

Question 12.
11 × \(\frac{11}{12}\)
Answer:
10\(\frac{1}{2}\)
Explanation:
10 × \(\frac{1}{2}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{10}{1}\) × \(\frac{1}{2}\)
= \(\frac{10}{2}\)
= 10\(\frac{1}{2}\)

Question 13.
42 × \(\frac{5}{7}\)
Answer:
30
Explanation:
42 × \(\frac{5}{7}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{42}{1}\) × \(\frac{5}{7}\)
= \(\frac{42 X 5}{7}\)
= \(\frac{210}{7}\)
= 30

Question 14.
20 × \(\frac{3}{40}\)
Answer:
1\(\frac{1}{2}\)
Explanation:
20 × \(\frac{3}{40}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{20}{1}\) × \(\frac{3}{40}\)
= \(\frac{20 X 3}{40}\)
= \(\frac{60}{40}\)
= \(\frac{3}{2}\)
= 1\(\frac{1}{2}\)

Question 15.
32 × \(\frac{5}{8}\)
Answer:
20
Explanation:
32 × \(\frac{5}{8}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{32}{1}\) × \(\frac{5}{8}\)
= \(\frac{32 X 5}{8}\)
= \(\frac{160}{8}\)
= 20

Question 16.
15 × –\(\frac{1}{15}\)
Answer:
-1
Explanation:
15 × –\(\frac{1}{15}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{15}{1}\) × –\(\frac{1}{15}\)
= \(\frac{-15}{15}\)
= -1

Question 17.
16 × –\(\frac{3}{16}\)
Answer:
-3
Explanation:
16 × –\(\frac{3}{16}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{16}{1}\) × –\(\frac{3}{16}\)
= \(\frac{16 X -3}{16}\)
= \(\frac{-48}{16}\)
= -3

Question 18.
3 × \(\frac{1}{3}\)
Answer:
1
Explanation:
3 × \(\frac{1}{3}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{3}{1}\) ×\(\frac{1}{3}\)
= \(\frac{3}{3}\)
= 1

Question 19.
45 × \(\frac{13}{15}\)
Answer:
39
Explanation:
45 × \(\frac{13}{15}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{45}{1}\) ×\(\frac{13}{15}\)
= \(\frac{45 X 13}{15}\)
= \(\frac{585}{15}\)
= 39

Question 20.
7 × \(\frac{4}{7}\)
Answer:
4
Explanation:
7 × \(\frac{4}{7}\)
Multiply whole number by the numerator and then place over denominator.
= \(\frac{7}{1}\) × \(\frac{4}{7}\)
= \(\frac{7 X 4}{7}\)
= \(\frac{28}{7}\)
= 4

McGraw Hill Math Grade 7 Lesson 7.1 Answer Key Multiply Fractions and Whole Numbers Read More »

McGraw Hill Math Grade 7 Lesson 19.5 Answer Key Temperature

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McGraw-Hill Math Grade 7 Answer Key Lesson 19.5 Temperature

Exercises
CONVERT
° F = ° C × \(\frac{9}{5}\) + 32
° C = (° F – 32) × \(\frac{9}{5}\)

Question 1.
200° C = _______________ F
Answer:
200° C is equal to 392° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 200 × \(\frac{9}{5}\) + 32
° F = 40 × \(\frac{9}{1}\) + 32
° F = 360 + 32
° F = 392.

Question 2.
132° F = _______________ C
Answer:
132° F is equal to 180° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (132 – 32) × \(\frac{9}{5}\)
° C = 100 × \(\frac{9}{5}\)
° C = 20 × \(\frac{9}{1}\)
° C = 180.

Question 3.
81° F = _______________ C
Answer:
81° F is equal to 88.2° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (81 – 32) × \(\frac{9}{5}\)
° C = 49 × \(\frac{9}{5}\)
° C = \(\frac{441}{5}\)
° C = 88.2.

Question 4.
32° C = _______________ F
Answer:
32° C is equal to 89.6° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 32 × \(\frac{9}{5}\) + 32
° F = \(\frac{288}{5}\) + 32
° F = 57.6 + 32
° F = 89.6.

Question 5.
214° F = _______________ C
Answer:
214° F is equal to 327.6° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (214 – 32) × \(\frac{9}{5}\)
° C = 182 × \(\frac{9}{5}\)
° C = \(\frac{1638}{5}\)
° C = 327.6.

Question 6.
320° F = _______________ C
Answer:
320° F is equal to 518.4° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (320 – 32) × \(\frac{9}{5}\)
° C = 288 × \(\frac{9}{5}\)
° C = \(\frac{2592}{5}\)
° C = 518.4.

Question 7.
10°F = _______________ C
Answer:
10°F is equal to -39.6° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (10 – 32) × \(\frac{9}{5}\)
° C = -22 × \(\frac{9}{5}\)
° C = – \(\frac{198}{5}\)
° C = -39.6.

Question 8.
45° C = _______________ F
Answer:
45° C is equal to 113° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 45 × \(\frac{9}{5}\) + 32
° F = 9 × \(\frac{9}{1}\) + 32
° F = 81 + 32
° F = 113.

Question 9.
75° F = _______________ C
Answer:
75° F is equal to 77.4° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (75 – 32) × \(\frac{9}{5}\)
° C = 43 × \(\frac{9}{5}\)
° C = \(\frac{387}{5}\)
° C = 77.4.

Question 10.
90° C = _______________ F
Answer:
90° C is equal to 64.4° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 90 × \(\frac{9}{5}\) + 32
° F = 18 × \(\frac{9}{1}\) + 32
° F = \(\frac{162}{5}\) + 32
° F = 32.4 + 32
° F = 64.4.

Question 11.
-15° F = _______________ C
Answer:
-15° F is equal to – 84.6° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (-15 – 32) × \(\frac{9}{5}\)
° C = – 47 × \(\frac{9}{5}\)
° C = \(\frac{- 423}{5}\)
° C = – 84.6.

Question 12.
130° F = _______________ C
Answer:
130° F is equal to 176.4° C.

Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (130 – 32) × \(\frac{9}{5}\)
° C = 98 × \(\frac{9}{5}\)
° C = \(\frac{882}{5}\)
° C =176.4.

Question 13.
37° C = _______________ F
Answer:
37° C is equal to 69° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 37 × \(\frac{9}{5}\) + 32
° F =  \(\frac{185}{5}\) + 32
° F = 37 + 32
° F = 69.

Question 14.
2000° C = _______________ F
Answer:
2000° C is equal to 3632° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 2000 × \(\frac{9}{5}\) + 32
° F = 400 × \(\frac{9}{1}\) + 32
° F = 3,600 + 32
° F = 3632.

Question 15.
244° C = _______________ F
Answer:
244° C is equal to 471.2° F.

Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 244 × \(\frac{9}{5}\) + 32
° F =  \(\frac{2196 }{5}\) + 32
° F = 439.2 + 32
° F = 471.2.

Question 16.
Sarah has a fever and is running a temperature of 39° C. What is her temperature in Fahrenheit?
Answer:
102.2 is her temperature in Fahrenheit.

Explanation:
Sarah has a fever and is running a temperature of 39° C.
Temperature of Sarah  = 39 ° C.
° F = ° C × \(\frac{9}{5}\) + 32
° F = 39 × \(\frac{9}{5}\) + 32
° F = \(\frac{351}{5}\) + 32
° F = 70.2 + 32
° F = 102.2.

Question 17.
Jared is baking cookies for a bake sale. His recipe calls for him to set the oven to a temperature of 350° F. If his oven only displays temperature in Celsius, then to what temperature should Jared set his oven?
Answer:
572.4 is the temperature should Jared set his oven.

Explanation:
Temperature of his recipe calls for him to set the oven = 350° F.
If his oven only displays temperature in Celsius,
Temperature should Jared set his oven =
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (350 – 32) × \(\frac{9}{5}\)
° C = 318 × \(\frac{9}{5}\)
° C =  \(\frac{2862}{5}\)
° C = 572.4.

McGraw Hill Math Grade 7 Lesson 19.5 Answer Key Temperature Read More »

McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid

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McGraw-Hill Math Grade 7 Answer Key Lesson 19.4 Metric Perimeter, Area, and Volume of a Solid

Exercises
CALCULATE
Question 1.
What is the perimeter of a square with sides of 7 cm?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 1
What is the area?
Answer:
Perimeter of the square = 28 cm.
Area of the square = 49 square cm.

Explanation:
Side of the square = 7 cm.
Perimeter of the square = 4 × Side of the square
= 4 × 7
= 28 cm.
Area of the square = Side of the square × Side of the square
= 7 × 7
= 49 square cm.

Question 2.
The perimeter of this figure with 6 equal sides is 48 millimeters. What is the length of each side?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 2
Answer:
Length of the each side = 8 mm.

Explanation:
Number of sides of the figure = 6.
Perimeter of this figure = 48 millimeters.
Length of the each side = Perimeter of this figure ÷ Number of sides of the figure
= 48 ÷ 6
= 8 mm.

Question 3.
A cube has sides of 6 cm. What is the volume of the cube?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 3
What is the surface area of the whole figure?
Answer:
Volume of the cube = 216 cubic cm.
Surface area of the cube = 36 square cm.

Explanation:
Side of the cube = 6 cm.
Volume of the cube = Side of the cube × Side of the cube × Side of the cube
= 6 × 6 × 6
= 36 × 6
= 216 cubic cm.
Surface area of the cube = 6 × Side of the cube
= 6 × 6
= 36 square cm.

Question 4.
A rectangle has sides of 2.4 cm and 8 cm. What is the perimeter of the rectangle?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 4
What is the area of the rectangle?
Answer:
Perimeter of the rectangle = 20.8 cm.
Area of the rectangle = 19.2 square cm.

Explanation:
Length of the rectangle = 8 cm.
Width of the rectangle = 2.4 cm.
Perimeter of the rectangle = 2(Length of the rectangle + Width of the rectangle)
= 2(8 + 2.4)
= 2 × 10.4
= 20.8 cm.
Area of the rectangle = Length of the rectangle × Width of the rectangle
= 8 × 2.4
= 19.2 square cm.

Question 5.
What is the perimeter of this rectangle with sides of 14 meters and 6 meters?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 5
What is the area?
Answer:
Perimeter of the rectangle = 40 m.
Area of the rectangle = 84 square m.

Explanation:
Length of the rectangle = 14 m.
Width of the rectangle = 6 m.
Perimeter of the rectangle = 2(Length of the rectangle + Width of the rectangle0
= 2(14 + 6)
= 2 × 20
= 40 m.
Area of the rectangle = Length of the rectangle × Width of the rectangle
= 14 × 6
= 84 square m.

Question 6.
Damian designed a course around his neighborhood to race his bicycle with friends. His neighborhood is in the shape of a regular pentagon with 5 equal sides measuring 500 meters each. If Damian can ride his bicycle at a speed of 20 km per hour, how many times around the course will he go in an hour?
Answer:
Number of times around the course will he go in an hour = 125.

Explanation:
Number of sides His neighborhood is in the shape of a regular pentagon = 5.
Length of the each side = 500 m.
Perimeter of the pentagon = Number of sides His neighborhood is in the shape of a regular pentagon × Length of the each side
= 5 × 500
= 2,500 m.
Speed of Damian can ride his bicycle = 20 km per hour.
Number of times around the course will he go in an hour = Perimeter of the pentagon ÷ Speed of Damian can ride his bicycle
= 2,500 ÷ 20
= 125.

Question 7.
Anabelle is buying a new rug for her living room. The rug store prices the rug by the square meter. If Anabelle needs a rug with dimensions of 3.7 meters long and 2 meters wide, and the rug store charges $12.00 per square meter, how much will she pay for a new rug? ______________
What is the perimeter of the rug? ______________
Answer:
Amount of money she needs to pay for new rug = $88.8.
Perimeter of the rug = 11.4 m.

Explanation:
Length of the rug = 3.7 m.
Width of the rug = 2 m.
Area of the rug = Length of the rug × Width of the rug
= 3.7 × 2
= 7.4 square m.
Amount of money rug store chargers for the rug = $12.00 per square meter.
Amount of money she needs to pay for new rug = Area of the rug × Amount of money rug store chargers for the rug
= 7.4 × 12
= $88.8.
Perimeter of the rug = 2(Length of the rug + Width of the rug)
= 2(3.7 + 2)
= 2 × 5.7
= 11.4 m.

Question 8.
What is the volume of the rectangular solid?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 6
Answer:
Volume of the rectangular solid = 900 cubic cm.

Explanation:
Length of the rectangular solid = 18 cm.
Width of the rectangular solid = 10 cm.
Height of the rectangular solid = 5 cm.
Volume of the rectangular solid = Length of the rectangular solid × Width of the rectangular solid × Height of the rectangular solid
= 18 × 10 × 5
= 180 × 5
= 900 cubic cm.

Question 9.
What is the area of the triangle?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 7
Answer:
Area of the triangle = 35 square m.

Explanation:
Base of the triangle = 14 m.
Height of the triangle = 5 m.
Area of the triangle = \(\frac{1}{2}\) × Base of the triangle × Height of the triangle
= \(\frac{1}{2}\) × 14 × 5
= \(\frac{1}{1}\) × 7 × 5
= 35 square m.

Question 10.
How much water can a swimming pool with a flat bottom hold? It is 12 meters long, 8 meters wide, and 2.5 meters deep.
Answer:
Number of liters of water can a swimming pool with a flat bottom hold = 2,40,000 liters.

Explanation:
Length of the swimming pool = 12 m.
Width of the swimming pool = 8 m.
Height of the swimming pool = 2.5 m.
Volume of the swimming pool = Length of the swimming pool × Width of the swimming pool × Height of the swimming pool
= 12 × 8 × 2.5
= 96 × 2.5
= 240 cubic m.
Number of liters of water can a swimming pool with a flat bottom hold =
Conversion:
1 cubic m= 1,000 liters.
240 cubic m = ?? liters
=> 1 × ?? = 1,000 × 240
=> ?? = 2,40,000 liters.

Question 11.
What is the area of the triangle?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 8
Answer:
Area of the triangle = 96 square m.

Explanation:
Base of the triangle = 12 m.
Height of the triangle = 16 m.
Area of the triangle = \(\frac{1}{2}\) × Base of the triangle × Height of the triangle
= \(\frac{1}{2}\) × 12 × 16
= \(\frac{1}{1}\) × 6 × 16
= 96 square m.

Question 12.
What is the area of this rectangle?
McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid 9
Answer:
Area of the rectangle = 192 square mm.

Explanation:
Length of the rectangle = 16mm.
Width of the rectangle =  12mm.
Area of the rectangle = Length of the rectangle × Width of the rectangle
= 16 × 12
= 192 square mm.

McGraw Hill Math Grade 7 Lesson 19.4 Answer Key Metric Perimeter, Area, and Volume of a Solid Read More »

McGraw Hill Math Grade 7 Lesson 19.3 Answer Key Metric Units of Mass

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 19.3 Metric Units of Mass existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 19.3 Metric Units of Mass

Exercises
CALCULATE
Question 1.
200 g = ____________ kg
Answer:
200 g is equal to 0.2 kg.

Explanation:
Conversion:
1 kg = 1,000 g.
?? kg = 200 g
=> 1 × 200 = 1,000 × ??
=> 200 ÷ 1,000 = ??
=> 0.2 kg.

Question 2.
125 kg = ____________ mg
Answer:
125 kg is equal to 12,50,00,000 mg.

Explanation:
Conversion:
1 kg = 10,00,000 mg.
125 kg = ?? mg.
=> 1 × ?? = 10,00,000 × 125
=> ?? = 12,50,00,000 mg.

Question 3.
660 g = ____________ kg
Answer:
600 g is equal to 0.6 kg.

Explanation:
Conversion:
1 kg = 1,000 g.
?? kg = 600 g.
=> 1 × 600 = 1,000 × ??
=> 600 ÷ 1,000 = ??
=> 0.6 kg = ??

Question 4.
4500 mg = ____________ g
Answer:
450 mg is equal to 0.45 g.

Explanation:
Conversion:
1 g = 1,000 mg.
?? g = 450 mg.
=> 1 × 450 = 1,000 × ??
=> 450 ÷ 1,000 = ??
=> 0.45 g = ??

Question 5.
11.3 kg = ____________ mg
Answer:
11.3 kg is equal to 1,13,00,000 mg.

Explanation:
Conversion:
1 kg = 10,00,000 mg.
11.3 kg = ?? mg
=> 1 × ?? = 10,00,000 × 11.3
=> ?? = 1,13,00,000 mg.

Question 6.
300 mg = ____________ g
Answer:
300 mg is equal to 0.3g.

Explanation:
Conversion:
1 g = 1,000 mg.
?? g = 300 mg
=> 1 × 300 = 1,000 × ??
=> 300 ÷ 1,000 = ??
=> 0.3 g = ??

Question 7.
500 g + 600 mg = ____________ g
Answer:
Sum of 500 g and 600 mg is equal to 500.6 g.

Explanation:
Conversion:
1 g = 1,000 mg.
?? g = 600 mg.
=> 1 × 600 = 1,000 × ??
=> 600 ÷ 1,000 = ??
=> 0.6 g = ??
500 g + 0.6 g = 500.6 g.

Question 8.
7 kg + 190 g = ____________ cg
Answer:
Sum of 7kg and 190 g, we get 7,19,000 cg.

Explanation:
Conversion:
1 g = 100 cg.
190 g = ?? cg
=> 1 × ?? = 100 × 190
=> ?? = 19000 cg.
1 kg = 1,00,000 cg.
7 kg = ?? cg
=> 1 × ?? = 1,00,000 × 7
=> ?? = 7,00,000 cg.
19,000 cg + 7,00,000 cg = 7,19,000 cg.

Question 9.
438 g + 1.62kg = ____________ g
Answer:
Sum of 438 g and 1.62kg, we get 2,058 g.

Explanation:
Conversion:
1 kg = 1,000 g.
1.62 kg = ?? g
=> 1 × ?? = 1,000 × 1.62
=> ?? = 1,620 g.
438 g + 1,620 g = 2,058 g.

Question 10.
267 kg – 33g = ____________ kg
Answer:
Difference between 267 kg and 33g, we get 266.967 kg.

Explanation:
Conversion:
1 kg = 1,000 g.
?? kg = 33 g
=> 1 × 33 = 1,000 × ??
=> 33 ÷ 1,000 = ??
=> 0.033 kg = ??
Difference between 267 kg and 33g:
267 kg – 0.033 kg = 266.967 kg.

Question 11.
354 g – 346 mg = ____________ g
Answer:
Difference between 354 g and 346 mg, we get 353.654 g.

Explanation:
Conversion:
1 g = 1,000 mg.
?? g = 346 mg
=> 1 × 346 = 1,000 × ??
=> 346 ÷ 1,000 = ??
=> 0.346 g = ??
Difference between 354 g and 346 mg:
354 g – 0.346 g = 353.654 g.

Question 12.
4300 g + 3300 mg = ____________ kg
Answer:
Sum of 4300 g and 3300 mg, we get 4.3033 kg.

Explanation:
Conversion:
1 kg = 1,000 g.
?? kg = 4,300 g.
=> 1 × 4,300 = 1,000 × ??
=> 4,300 ÷ 1,000 = ??
=> 4.3 kg = ??
1 kg = 10,00,000 mg.
?? kg = 3300 mg
=> 1 × 3300 = 10,00,000 × ??
=> 3300 ÷ 10,00,000 = ??
=> 0.0033 kg = ??
4.3 kg + 0.0033 kg = 4.3033 kg.

Question 13.
5300 g – 2430 mg = ____________ g
Answer:
Difference between 5300 g and 2430 mg, we get 5297.57 g.

Explanation:
Conversion:
1 g = 1,000 mg.
?? g = 2,430 mg
=> 1 × 2,430 = 1,000 × ??
=> 2,430 ÷ 1,000 = ??
=> 2.430 g = ??
Difference between 5300 g and 2430 mg:
5300 g – 2.430 g = 5297.57 g.

Question 14.
12.34 kg + 1.66 kg = ____________ g
Answer:
Sum of 12.34 kg and 1.66 kg, we get 14,000 g.

Explanation:
Conversion:
1 kg = 1,000 g.
12.34 kg = ?? g
=> 1 × ?? = 1000 × 12.34
=> ?? = 12,340 g.
1 kg = 1,000 g.
1.66 kg = ?? g
=> 1 × ?? = 1000 ×  1.66
=> ?? = 1,660 g.
12,340 g + 1,660 g = 14,000 g.

Question 15.
2 mg + 4 g + 5 kg = ____________ kg
Answer:
Sum of 2 mg, 4 g and 5 kg, we get 5.004002 kg.

Explanation:
Conversion:
1 kg = 10,00,000 mg.
?? kg = 2 mg
=> 1 × 2 = 10,00,000 × ??
=> 2 ÷ 10,00,000 = ??
=> 0.000002 kg = ??
1 kg = 1,000 g.
?? kg  = 4 g
=> 1 × 4 = 1,000 × ??
=> 4 ÷ 1,000 = ??
=> 0.004 kg = ??
0.000002 kg + 0.004 kg + 5 kg = 5.004002 kg.

Question 16.
300 kg + 300 g + 300 cg = ____________ mg
Answer:
Sum of 300 kg, 300 g and 300 cg , we get 30,03,03,000 mg.

Explanation:
Conversion:
1 kg = 10,00,000 mg.
300 kg = ?? mg
=> 1 × ?? = 10,00,000 × 300
=> ?? = 30,00,00,000 mg.
1 g = 1,000 mg.
300 g = ?? mg
=> 1 × ?? = 1,000 × 300
=> ?? = 3,00,000 mg.
1 cg = 10 mg.
300 cg = ?? mg
=> 1 × ?? = 10 × 300
=> ?? = 3,000 mg.
30,00,00,000 mg + 3,00,000 mg + 3,000 mg = 30,03,03,000 mg.

Question 17.
142 g + 258 mg = ____________ cg
Answer:
Sum of 142 g + 258 mg, we get 14,225.8 cg.

Explanation:
Conversion:
1 g = 100 cg.
142 g = ?? cg
=> 1 × ?? = 100 × 142
=> ?? = 14,200 cg.
1 cg = 10 mg.
?? cg = 258 mg
=> 1 × 258 = 10 × ??
=> 258 ÷ 10 = ??
=> 25.8 cg = ??
14,200 cg + 25.8 cg = 14,225.8 cg.

Question 18.
65 g + 6500 g = ____________ kg
Answer:
Sum of 65 g and 6500 g, we get 6.565 kg.

Explanation:
Conversion:
1 kg = 1,000 g.
?? kg = 65 g
=> 1 × 65 = 1,000 × ??
=> 65 ÷ 1,000 = ??
=> 0.065 kg = ??
1 kg = 1,000 g.
?? kg = 6,500 g
=> 1 × 6,500 = 1,000 × ??
=> 6500 ÷ 1000 = ??
=> 6.5 kg.
0.065 kg + 6.5 kg = 6.565 kg.

McGraw Hill Math Grade 7 Lesson 19.3 Answer Key Metric Units of Mass Read More »

McGraw Hill Math Grade 7 Lesson 19.2 Answer Key Metric Units of Liquid Volume

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McGraw-Hill Math Grade 7 Answer Key Lesson 19.2 Metric Units of Liquid Volume

Exercises
CALCULATE

Question 1.
2.1 L = __________ mL
Answer:
2.1 L is equal to 2100 mL .

Explanation:
Conversion:
1 L = 1,000 mL
2.1 L = ?? mL
=> 1 × ?? = 1,000 × 2.1
=> ?? = 2100 mL .

Question 2.
1700 L = _________ kL
Answer:
1,700 L is equal to 1.7 kL.

Explanation:
Conversion:
1 kL = 1,000 L.
?? kL = 1,700 L
=> 1 × 1,700 = 1,000 × ??
=> 1,700 ÷ 1,000 = ??
=> 1.7 kL = ??

Question 3.
3.456 L = ____________ mL
Answer:
3.456 L is equal to 3,456 mL.

Explanation:
Conversion:
1 L = 1,000 mL.
3.456 L = ?? mL
=> 1 × ?? = 1,000 × 3.456
=> ?? = 3,456 mL.

Question 4.
350 L = ___________ mL
Answer:
350 L is equal to 3,50,000 mL.

Explanation:
Conversion:
1 L = 1,000 mL.
350 L = ?? mL.
=> 1 × ?? = 1,000 × 350
=> ?? = 3,50,000 mL.

Question 5.
3.901 kL = ____________ mL
Answer:
3.901 kL is equal to 39,01,000 mL.

Explanation:
Conversion:
1 kL = 10,00,000 mL.
3.901 kL = ?? mL
=> 1 × ?? = 10,00,000 × 3.901
=> ?? = 39,01,000 mL.

Question 6.
161.34 mL = ____________ L
Answer:
161.34 mL is equal to 0.16134 L.

Explanation:
Conversion:
1 L = 1,000 mL.
?? L= 161.34 mL
=> 1 × 161.34 = 1,000 × ??
=> 161.34 ÷ 1,000 = ??
=> 0.16134 L = ??

Question 7.
767 mL = ____________ kL
Answer:
767 mL is equal to 0.000767 kL.

Explanation:
Conversion:
1 kL = 10,00,000 ml
?? kL = 767 mL
=> 1 × 767 = 10,00,000 × ??
=> 767 ÷ 10,00,000 = ??
=> 0.000767 kL = ??

Question 8.
1276 mL + 487 L = _____________ L
Answer:
Sum of 1276 mL and 487 L , we get 488.276 L.

Explanation:
Conversion:
1 L = 1,000 mL.
?? L= 1,276 mL
=> 1 × 1,276 = 1,000 × ??
=> 1,276 ÷ 1,000 = ??
=> 1.276 L = ??
1.276 l + 487 L = 488.276 L.

Question 9.
2 kL + 135 L = ___________ L
Answer:
Sum of 2 kL and 135 L, we get 2,135 L.

Explanation:
Conversion:
1 kL = 1,000 L.
2 kL = ?? L
=> 1 × ?? = 1,000 × 2
=> ?? = 2,000 L.
2,000 L + 135 L = 2,135 L.

Question 10.
71 mL + 141 L = ___________ kL
Answer:
Sum of 71 mL and 141 L, we get 1,41,000.000071 kL.

Explanation:
Conversion:
1 kL = 10,00,000 mL.
?? kL = 71 mL.
=> 1 × 71 = 10,00,000 × ??
=> 71 ÷ 10,00,000 = ??
=> 0.000071 kL.
1 kL = 1,000 L.
141 L = ?? L
=> 1 × ?? = 1,000 × 141
=> ?? = 1,41,000 L.
0.000071 kL + 1,41,000 L = 1,41,000.000071 kL.

Question 11.
835 kL + 4500 L = ___________ kL
Answer:
Sum of 835 kL and 4500 L, we get 839.5 kL.

Explanation:
Conversion:
1 kL = 1,000 L.
?? kL = 4,500 L
=> 1 × 4,500 = 1,000 × ??
=> 4,500 ÷ 1,000 = ??
=> 4.5 kL.
835 kL + 4.5 kL = 839.5 kL.

Question 12.
562 kL + 5213 L = _____________ kL
Answer:
Sum of 562 kL and 5213 L, we get 567.213 kL.

Explanation:
Conversion:
1 kL = 1,000 L.
?? kL = 5,213 L
=> 1 × 5,213 = 1,000 × ??
=> 5,213 ÷ 1,000 = ??
=> 5.213 kL = ??
562 kL + 5.213 kL = 567.213 kL.

Question 13.
423.98 L + 875.23 mL = ____________ L
Answer:
Sum of 423.98 L and 0.87523 L = 424.85523 L.

Explanation:
Conversion:
1 L = 1,000 mL.
?? L = 875.23 ml
=> 1 × 875.23 = 1,000 × ??
=> 875.23 ÷ 1,000 = ??
=> 0.87523 L = ??
423.98 L + 0.87523 L = 424.85523 L.

Question 14.
141.3 L + 43.2 mL = ____________ mL
Answer:
Sum of 141.3 L and 43.2 mL, we get 1,41,343.2 mL.

Explanation:
Conversion:
1 L = 1,000 mL.
141.3 L = ?? mL
=> 1 × ?? = 1,000 × 141.3
=> ?? = 1,41,300 mL.
1,41,300 mL + 43.2 mL = 1,41,343.2 mL.

Question 15.
A \(\frac{4}{3}\) liter bottle of water is a common size. How many of these bottles of water would it take to fill a 20-liter container?
Answer:
Number of bottles of water would it take to fill a 20-liter container = 15.

Explanation:
Number of liter bottle of water is a common size = \(\frac{4}{3}\)
Number of liters of container = 20.
Number of bottles of water would it take to fill a 20-liter container = Number of liters of container ÷ Number of liter bottle of water is a common size
= 20 ÷ \(\frac{4}{3}\)
= 20 × \(\frac{3}{4}\)
= 5 × \(\frac{3}{1}\)
= 15.

Question 16.
If the reservoir has 200,000,000,000 centiliters of water in it, how many kiloliters does it contain?
Answer:
Number of kiloliters does it contain =

Explanation:
Number of centiliters of water reservoir has = 200,000,000,000.
Number of kiloliters does it contain = 20,00,000.
Conversion:
1 kiloliters = 1,00,000 centiliters.
?? kiloliters = 200,000,000,000 centiliters.
=> 1 × 200,000,000,000 = 1,00,000 × ??
=> 200,000,000,000 ÷ 1,00,000 = ??
=> 20,00,000 kiloliters = ??

Question 17.
If you are providing beverages for 25 students and family members at the school outing and each person expects to drink 1,500 centiliters, how many liters of beverages will you need?
Answer:
Number of liters of beverages will you need = 37.5.

Explanation:
Number of beverages are provided to students and family members at the school outing = 25.
Number of centiliters each person expects to drink = 1,500.
Number of centiliters of beverages will you need = Number of beverages are provided to students and family members at the school outing × Number of centiliters each person expects to drink
= 25 × 1,500
= 37,500.
Number of liters of beverages will you need =
Conversion:
1 L = 1,000 centiliters.
?? L = 37,500 centiliters
=> 1 × 37,500 = 1,000 × ??
=> 37,500 ÷ 1,000 = ??
=> 37.5 L = ??

Question 18.
If an aquarium holds 600 liters of water, and each cup of water holds 25 milliliters, how many cups of water does the aquarium hold?
Answer:
Number of cups of water does the aquarium hold = 24.

Explanation:
Number of liters of water an aquarium holds = 600.
Number of milliliters each cup of water holds = 25.
Number of cups of water does the aquarium hold = Number of liters of water an aquarium holds ÷ Number of milliliters each cup of water holds
= 600 ÷ 25
= 24.

McGraw Hill Math Grade 7 Lesson 19.2 Answer Key Metric Units of Liquid Volume Read More »

McGraw Hill Math Grade 7 Lesson 19.1 Answer Key Metric Units of Length

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 19.1 Metric Units of Length existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 19.1 Metric Units of Length

Exercises
CALCULATE
Question 1.
335 cm = ___________ m
Answer:
335 cm is equal to 3.35 m.

Explanation:
Conversion:
1 m = 100 cm.
?? m = 335 cm
=> 1 × 335 = 100 × ??
=> 335 ÷ 100 = ??
=> 3.35 m = ??

Question 2.
6235 mm = ___________ m
Answer:
6,235 mm is equal to 6.235 m.

Explanation:
Conversion:
1 m = 1,000 mm.
?? m = 6,235 mm
=> 1 × 6,235 = 1,000 × ??
=> 6235 ÷ 1000 = ??
=> 6.235 m = ??

Question 3.
5.761 km = ___________ cm
Answer:
5.761 km is equal to 5,76,100 cm.

Explanation:
Conversion:
1 km = 1,00,000 cm
5.761 km = ?? cm
=> 1 × ?? = 1,00,000 × 5.761
=> ?? = 5,76,100 cm.

Question 4.
725.02 km = ____________ mm
Answer:
725.02 km is equal to 72,50,20,000 mm.

Explanation:
Conversion:
1 km = 10,00,000 mm.
725.02 km = ?? mm.
=> 1 × ?? = 10,00,000 × 725.02
=> ?? = 72,50,20,000 mm.

Question 5.
335 cm + 550 mm = ____________ m
Answer:
Sum of 335 cm and 550 mm, we get 3.9 m.

Explanation:
Conversion:
1m = 100 cm
?? m = 335 cm
=> 1 × 335 = 100 × ??
=> 335 ÷ 100 = ??
=> 3.35 m = ??
1 m = 1000 mm.
?? m = 550 mm
=> 1 × 550 = 1,000 × ??
=> 550 ÷ 1,000 = ??
=> 0.55 m = ??
-> 3.35m + 0.55m = 3.9m.

Question 6.
2.611 km = ____________ cm
Answer:
2.611 km is equal to 2,61,100 cm.

Explanation:
Conversion:
1 km = 1,00,000 cm.
2.611 km = ?? cm
=> 1 × ?? = 1,00,000 × 2.611
=> ?? = 2,61,100 cm.

Question 7.
12 cm +12 mm = ____________ m
Answer:
Sum of 12 cm and 12 mm, we get .0132 m.

Explanation:
Conversion:
1 m = 100 cm.
?? m = 12 cm
=> 1 × 12 = 100 × ??
=> 12 ÷ 100 = ??
=> 0.12 m.
1 m = 1,000 mm.
?? m = 12 mm.
=> 1 × 12 = 1,000 × ??
=> 12 ÷ 1,000 = ??
=> 0.012 m = ??
-> 0.12m + 0.012 m =  .0132 m.

Question 8.
6.872 m = __________ mm
Answer:
6.872 m is equal to 6,872 mm.

Explanation:
Conversion:
1 m = 1,000 mm.
6.872 m = ?? mm
=> 1 × ?? = 1,000 × 6.872
=> ?? = 6,872 mm.

Question 9.
8 km + 65 m = ____________ m
Answer:
Sum of 8 km and 65 m, we get 8,065 m.

Explanation:
Conversion:
1 km = 1,000 m.
8 km = ?? m
=> 1 × ?? = 1,000 × 8
=> ?? = 8,000 m.
8,000m + 65m = 8,065 m.

Question 10.
320 km + 415 m = ______________ cm
Answer:
Sum of 320 km and 415 m, we get 3,20,41,500 cm.

Explanation:
Conversion:
1 km = 1,00,000 cm.
320 km = ?? cm
=> 1 × ?? = 1,00,000 × 320
=> ?? = 3,20,00,000 cm.
1 m = 100 cm.
415 m = ?? cm
=> 1 × ?? = 100 × 415
=> ?? = 41,500 cm.
-> 3,20,00,000 cm + 41,500 cm = 3,20,41,500 cm.

Question 11.
478.98 cm + 760.34 cm = ____________ m
Answer:
Sum of 478.98 cm and 760.34 cm, we get 12.3932 m.

Explanation:
Conversion:
1m = 100 cm.
?? m = 478.98 cm
=> 1 × 478.98 = 100 × ??
=> 478.98 ÷ 100 = ??
=> 4.7898 m = ??
1m = 100 cm.
?? m = 760.34 cm
=> 1 × 760.34 = 100 × ??
=> 760.34 ÷ 100 = ??
=> 7.6034 m = ??
-> 4.7898 m + 7.6034 m = 12.3932 m.

Question 12.
540 cm = _____________ km
Answer:
540 cm is equal to 0.0054 km.

Explanation:
Conversion:
1 km = 1,00,000 cm
?? km = 540 cm
=> 1 × 540 = 1,00,000 × ??
=> 540 ÷ 1,00,000 = ??
=> 0.0054 km = ??

Question 13.
45 m + 35 cm = ___________ cm
Answer:
Sum of 45 m and 35 cm, we get 4,535 cm.

Explanation:
Conversion:
1 m = 100 cm.
45 m = ?? cm
=> 1 × ?? = 100 × 45
=> ?? = 4,500 cm.
4,500 cm + 35 cm = 4,535 cm.

Question 14.
76 m + .355 m = ____________ mm
Answer:
Sum of 76 m and .355 m, we get 7,955 mm.

Explanation:
Conversion:
1 m = 1,000 mm.
76 m = ?? mm
=> 1 × ?? = 1,000 × 76
=> ?? = 7,600 mm.
1 m = 1,000 mm.
.355 m = ?? mm
=> 1 × ?? = 1,000 × .355
=> ?? = 355 mm.
7,600 mm + 355 mm = 7,955 mm.

Question 15.
1.1755 km = ______________ m
Answer:
1.1755 km is equal to 1,175.5 m.

Explanation:
Conversion:
1 km = 1,000 m.
1.1755 km= ?? m
=> 1 × ?? = 1,000 × 1.1755
=> ?? = 1,175.5 m.

Question 16.
66.66 cm + 666 cm + 66 m = _____________ m
Answer:
Sum of 66.66 cm, 666 cm and 66 m, we get 73.3266 m.

Explanation:
Conversion:
1 m = 100 cm.
?? m = 66.66 cm
=> 1 × 66.66 = 100 × ??
=> 66.66 ÷ 100 = ??
=> 0.6666 m = ??
1 m = 100 cm.
?? m = 666 cm.
=> 1 × 666 = 100 × ??
=> 666 ÷ 100 = ??
=> 6.66 m = ??
0.6666 m + 6.66 m + 66 m = 73.3266 m.

Question 17.
2104 m = ____________ km
Answer:
2104 m is equal to 2.104 km.

Explanation:
Conversion:
1 km = 1,000 m
?? km = 2104 m
=> 1 × 2,104 = 1,000 × ??
=> 2,104 ÷ 1,000 = ??
=> 2.104 km = ??

Question 18.
1545 cm = _____________ km
Answer:
1545 cm is equal to 0.01545 km.

Explanation:
Conversion:
1 km = 1,00,000 cm.
?? km = 1,545 cm
=> 1 × 1,545 = 1,00,000 × ??
=> 1,545 ÷ 1,00,000 = ??
=> 0.01545 km = ??

McGraw Hill Math Grade 7 Lesson 19.1 Answer Key Metric Units of Length Read More »

McGraw Hill Math Grade 7 Lesson 18.7 Answer Key Time

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 18.7 Time existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 18.7 Time

Exercises

CALCULATE
Question 1.
36 hours = __________ seconds
Answer:
36 hours is equal to 1,29,600 seconds

Explanation:
Conversion:
1 hour = 3,600 seconds.
36 hours = ?? seconds.
=> 1 × ?? = 3,600 × 36
=> ?? = 1,29,600 seconds.

Question 2.
25 days = __________ hours
Answer:
25 days is equal to 600 hours.

Explanation:
Conversion:
1 day = 24 hours.
25 days = ?? hours
=> 1 × ?? = 24 × 25
=> ?? = 600 hours.

Question 3.
35 days = ___________ minutes
Answer:
35 days is equal to 50,400 minutes.

Explanation:
Conversion:
1 day = 1,440 minutes.
35 days = ?? minutes.
=> 1 × ?? = 1,440 × 35
=> ?? = 50,400 minutes.

Question 4.
96 hours = ___________ days
Answer:
96 hours is equal to 4 days.

Explanation:
Conversion:
1 day = 24 hours.
?? days = 96 hours
=> 1 × 96 = 24 × ??
=> 96 ÷ 24 = ??
=> 4 days = ??

Question 5.
32 days = ___________ minutes
Answer:
32 days is equal to 46,080 minutes.

Explanation:
Conversion:
1 day = 1,440 minutes.
32 days = ?? minutes.
=> 1 × ?? = 1,440 × 32
=> ?? = 46,080 minutes.

Question 6.
125 minutes = ___________ hours
Answer:
125 minutes is equal to 2.08 hours.

Explanation:
Conversion:
1 hour = 60 minutes.
?? hours = 125 minutes.
=> 1 × 125 = 60 × ??
=> 125 ÷ 60 = ??
=> 2.08 hours = ??

Question 7.
91 days = ___________ weeks
Answer:
91 days is equal to 13 weeks.

Explanation:
Conversion:
1 week = 7 days.
?? weeks = 91 days.
=> 1 × 91 = 7 × ??
=> 91 ÷ 7 = ??
=> 13 weeks = ??

Question 8.
300 years = ___________ decades
Answer:
300 years is equal to 30 decades.

Explanation:
Conversion:
1 decade = 10 years.
?? decades = 300 years
=> 1 × 300 = 10 × ??
=> 300 ÷ 10 = ??
=> 30 decades = ??

Question 9.
2,500 years = ___________ centuries
Answer:
2,500 years is equal to 25 centuries.

Explanation:
Conversion:
1 century = 100 years.
?? centuries = 2,500 years
=> 1 × 2,500 = 100 × ??
=> 2,500 ÷ 100 = ??
=> 25 centuries = ??

Question 10.
6,000 seconds = __________ weeks
Answer:
6,000 seconds is equal to 0.009 weeks.

Explanation:
Conversion:
1 week = 6,04,800 seconds.
?? weeks = 6,000 seconds
=> 1 × 6,000 = 6,04,800 ÷ ??
=> 6,000 ÷ 6,04,800 = ??
=> 0.009 weeks = ??

Question 11.
If you get paid $700 and you worked 3.2 days, approximately how much did you make per hour (assume an 8-hour day of work)?
Answer:
Amount of money paid for per hour = $27.34.

Explanation:
Amount of money paid = $700.
Number of days of work = 3.2
Amount of money paid for 1 day = Amount of money paid ÷ Number of days of work
= $700 ÷ 3.2
= $218.75.
(assume an 8-hour day of work)
Conversion:
1 day – 8 hours.
Amount of money paid for per hour = Amount of money paid for 1 day ÷ 8
= $218.75 ÷ 8
= $27.34.

Question 12.
The production rate for widgets in the factory is 8 per second. How many widgets should you make in a 9-hour shift?
Answer:
Number of widgets should you make in a 9-hour shift = 32,400 seconds.

Explanation:
Production rate for widgets in the factory per second = 8.
Conversion:
1 hour = 3,600 seconds.
Number of widgets should you make in a 9-hour shift = ?? seconds.
=> 1 × ?? = 9 × 3,600
=> ?? = 32,400 seconds.

Question 13.
What is the maximum of different centuries that a person can live in if he lived to be 110 years?
Answer:
1.1 centuries is the maximum of different centuries that a person can live in if he lived to be 110 years.

Explanation:
Maximum of different centuries that a person can live in if he lived to be 110 years= ??
Conversion:
1 century = 100 years.
?? centuries = 110 years
=> 1 × 110 = 100 × ??
=> 110 ÷ 100 = ??
=> 1.1 centuries = ??

Question 14.
If you get paid $8.00 per hour and you work 5,400 minutes, how much will you earn?
Answer:
Amount of money earned = $720.

Explanation:
Amount of money paid per hour = $8.00.
Number of minutes you worked = 5,400.
Conversion:
1 hour = 60 minutes.
?? hours – 5,400 minutes
=> 1 × 5,400 = 60 × ??
=> 5,400 ÷ 60 = ??
=> 90 hours = ??
Amount of money earned = Amount of money paid per hour  × 90
= $8 × 90
= $720.

McGraw Hill Math Grade 7 Lesson 18.7 Answer Key Time Read More »

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