Go Math Answer Key

McGraw Hill Math Grade 7 Lesson 22.6 Answer Key Sampling

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.6 Sampling existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.6 Sampling

Exercises

EVALUATE

Question 1.
To predict who will become the next president of the United States, a news organization asked people leaving voting sites around the country who they had just voted for. Who is the population in this situation? What is the sample group in this situation?
Answer:
All the voters in the United States;
People who voted at certain voting sites.
Explanation:
A sample is a group with in the larger population surveys or poll are done on just a sample of the population, and the results are projected on to the larger population.
As whole for the conclusions drawn to be valid the sample must be representative of the population.
To predict who will become the next president of the United States,
a news organization asked people leaving voting sites around the country who they had just voted.
The population in this situation is voters in the United States;
People who voted at certain voting sites are the sample group in this situation.

Question 2.
The high school principle wants to find out which elective class the 200 students at her school prefer. Which sampling method should she use?
(a) ask all the students in the chess club
(b) ask all the seniors
(c) ask the first 25 students in an alphabetical list of all the students
Answer:
Option(C)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
The high school principle wants to find out which elective class the 200 students at her school prefer,
ask the first 25 students in an alphabetical list of all the students.

Question 3.
Kai has a giant bag of red, yellow, and blue marbles. He wants to find out approximately what percent are blue, but doesn’t want to count every marble in the bag. Which sampling method should he use?
(a) Shake up the bag, pull out 30 marbles, and see how many are blue.
(b) Reach into the bag and grab the biggest marbles he can feel.
(c) Pull out three marbles from the top of the bag and see how many are blue.
Answer:
Option(A)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
To find out approximately what percent are blue,
but doesn’t want to count every marble in the bag,
Shake up the bag, pull out 30 marbles, and see how many are blue.

Question 4.
Mrs. Webster is the coordinator for the school field trip and is trying to decide between a trip to the museum or a trip to the zoo. She decides to do a survey of some of the students about their preference. Who should she survey?
(a) 30 students chosen at random by the office computer
(b) all the girls in the school
(c) the first 30 students to arrive at school
Answer:
Option(A)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
Mrs. Webster is the coordinator for the school field trip and is trying to decide between a trip to the museum or a trip to the zoo.
She decides to do a survey of some of the students about their preference 30 students chosen at random by the office computer.

Question 5.
In a random sampling of 100 fish caught in a fishing net in a river, there were 39 trout, 19 flounder, and 42 perch. Which of the following is the most valid conclusion?
(a) Perch is the most common fish in the river.
(b) The river has about twice as many perch and trout as it does flounder.
(c) There are only three kinds of fish in the river.
Answer:
Option(B)
Explanation:
There are two types of sampling methods:
Probability sampling method :
Involves random selection, allowing you to make strong statistical inferences about the whole group.
Non-probability sampling method :
Involves non-random selection based on convenience or other criteria, allowing you to easily collect data.
In a random sampling of 100 fish caught in a fishing net in a river,
there were 39 trout, 19 flounder, and 42 perch,
the river has about twice as many perch and trout as it does flounder.

McGraw Hill Math Grade 7 Lesson 22.6 Answer Key Sampling Read More »

McGraw Hill Math Grade 7 Lesson 22.5 Answer Key Venn Diagrams

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.5 Venn Diagrams existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.5 Venn Diagrams

Exercises

DIAGRAM

Question 1.
This Venn Diagram represents numbers that are even and numbers that are divisible by the variable b. What does their intersection represent?
McGraw Hill Math Grade 7 Lesson 22.5 Answer Key Venn Diagrams 1
Answer:
Numbers that are even and divisible by b.
Explanation:
The above Venn Diagram represents the numbers of even and odd numbers,
pink circle represents even numbers and blue circle is divisible by b numbers.
The intersecting point in mid is even numbers of divisible by b.

Question 2.
Make a Venn Diagram of people who are kickball fans, and people who are baseball fans. The only person that is a fan of both is your friend Kelsey.
McGraw Hill Math Grade 7 Lesson 22.5 Answer Key Venn Diagrams 2
Answer:

Explanation:
The above Venn Diagram represents people who are kickball fans and baseball fans.
The intersecting point between these two circles is fans who likes both the kickball and baseball,
a fan of both is your friend Kelsey.

McGraw Hill Math Grade 7 Lesson 22.5 Answer Key Venn Diagrams Read More »

McGraw Hill Math Grade 7 Lesson 22.4 Answer Key Tree Diagrams

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.4 Tree Diagrams existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.4 Tree Diagrams

Exercises

INTERPRET AND CREATE

Question 1.
The tree diagram at the right illustrates the outcomes when you choose two balls from a bag that contains a large number of red, white, and green balls. How many of these outcomes result in you not choosing at least 1 white ball? How many of these outcomes result in you choosing both a red ball and a green ball?
McGraw Hill Math Grade 7 Lesson 22.4 Answer Key Tree Diagrams 1
Answer:
4-Red and 2-Green,
Explanation:
Number of outcomes result in not choosing at least 1 white ball,
total there are 9 out comes.
Out of 9 out comes 4 out comes are with out white ball.

Number of outcomes result in choosing both a red ball and a green ball.
Green Red balls and Red and Green balls as shown below.

Question 2.
Draw a tree diagram to describe the following situation: You go to the ice cream store and you have a choice of vanilla, chocolate, or strawberry ice cream. On your ice cream, you can get either nuts or sprinkles.
Answer:

Explanation:
A tree diagram is a tool in the fields of general mathematics, probability, and statistics,
that helps calculate the number of possible outcomes of an event or problem.
The ice cream store have a choice of
vanilla (V) ice cream, chocolate (C) ice cream, or strawberry (S) ice cream.

McGraw Hill Math Grade 7 Lesson 22.4 Answer Key Tree Diagrams Read More »

McGraw Hill Math Grade 7 Lesson 22.3 Answer Key Box-and-Whisker Plots

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.3 Box-and-Whisker Plots existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.3 Box-and-Whisker Plots

Exercises

INTERPRET

Question 1.
Which of the three classes has the widest range of scores? The smallest range?
McGraw Hill Math Grade 7 Lesson 22.3 Answer Key Box-and-Whisker Plots 1
Widest Range ______________
Smallest Range _______________
Answer:
Widest Range is Botany.
Smallest Range is Zoology.
Explanation:
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
The lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.
Widest Range is Botany.
Smallest Range is Zoology.

Question 2.
Which class has the highest median score?
Answer:
Zoology
Explanation:
McGraw Hill Math Grade 7 Lesson 22.3 Answer Key Box-and-Whisker Plots 1
The highest median score is zoology.
Box – and – Whisker plot
which allows us to quickly look at data to tell where most of the numbers lie.
The lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.

Make a box-and-whisker plot with the following data:
Minimum – 15
Q1 – 25
Q2 – 35
Q3 – 45
Maximum – 55
Explanation:

Lower extreme(Minimum) – 15
Q1 – 25
Q2 – 35
Q3 – 45
Upper extreme(Maximum) – 55
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
the lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.
Question 3.
What is the range of this plot? The median?
Range _______________
Median _______________
Answer:
Range = 40;
median = 35.
Explanation:
Lower extreme(Minimum) – 15
Q1 – 25
Q2 – 35
Q3 – 45
Upper extreme(Maximum) – 55
Range =Upper extreme(Maximum) – Lower extreme(Minimum) = 55 -15 = 40
median = (Q3 + Q1)/2
= (45 + 25)/2 = 35
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
the lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.

Question 4.
What is the lower quartile? The upper quartile?
Lower Quartile _______________
Upper Quartile _______________
Answer:
Lower Quartile 15-25
Upper Quartile 45-55
Explanation:
Box – and – Whisker plot,
which allows us to quickly look at data to tell where most of the numbers lie.
the lowest number in set of data is called the lower extreme and the greatest number is called upper extreme.
The median of the numbers from the lower extreme to the median is called the lower quartile.
The median of the numbers from the upper extreme to the median is called the upper quartile.
Lower Quartile 15-25
Upper Quartile 45-55

McGraw Hill Math Grade 7 Lesson 22.3 Answer Key Box-and-Whisker Plots Read More »

McGraw Hill Math Grade 7 Lesson 22.2 Answer Key Stem-and-Leaf Plots

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.2 Stem-and-Leaf Plots existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.2 Stem-and-Leaf Plots

Exercises

INTERPRET

Question 1.
What is the range of the numbers represented in the stem-and-leaf plot below?
McGraw Hill Math Grade 7 Lesson 22.2 Answer Key Stem-and-Leaf Plots 1
Answer:
Range = 80
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
Range is the difference between,
First row Stem 9 Leaf 6,
Last row Stem 1 leaf 1.
So, the range of the numbers represented in the stem-and-leaf plot above,
96 – 16 = 80

Question 2.
Generate the number set represented by the stem-and-leaf plot below.
McGraw Hill Math Grade 7 Lesson 22.2 Answer Key Stem-and-Leaf Plots 2
Answer:
10, 17, 19
21, 21, 23, 24,26, 27, 28
30, 31, 33, 35,36, 37, 37,
40, 41, 41, 41, 42
69
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
numbers written as,
Frist row stem and leaf as written below up to last stem and last leaf.
10, 17, 19
21, 21, 23, 24,26, 27, 28
30, 31, 33, 35,36, 37, 37,
40, 41, 41, 41, 42
69

Question 3.
Generate the number set represented by the stem-and-leaf plot below.
McGraw Hill Math Grade 7 Lesson 22.2 Answer Key Stem-and-Leaf Plots 3
Answer:
80, 85
71, 75, 76,
51, 56, 58,
40, 46
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
numbers written as,
Frist row stem and leaf as written below up to last stem and last leaf
80, 85
71, 75, 76,
51, 56, 58,
40, 46.

Question 4.
What is the range of the numbers represented by the stem-and-leaf plot below?
McGraw Hill Math Grade 7 Lesson 22.2 Answer Key Stem-and-Leaf Plots 4
Answer:
Range = 45
Explanation:
A stem and leaf plot organizes data by the place value of digits.
It is named because it remained some people of a plant with stems,
each of which had a different number of leaves.
Range is the difference between,
First row Stem 2 Leaf 2,
Last row Stem 6 leaf 7.
So, the range of the numbers represented in the stem-and-leaf plot above,
67 – 22 = 45.

McGraw Hill Math Grade 7 Lesson 22.2 Answer Key Stem-and-Leaf Plots Read More »

McGraw Hill Math Grade 7 Lesson 22.1 Answer Key Measures of Central Tendency

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 22.1 Measures of Central Tendency existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 22.1 Measures of Central Tendency

Exercises

CALCULATE

Question 1.
Calculate the mean of [3.2, 2.5, 2.1, 3.7, 2.8, 2.0]
Answer:
Mean = 2.7
Explanation:
Find the sum of the values by adding them all up.
Divide the sum by the number of values in the data set.
Mean = \(\frac{3.2 + 2.5 + 2.1 + 3.7 + 2.8 + 2.0}{6}\)
= \(\frac{16.3}{6}\) = 2.7

Question 2.
Find the median of [7, 4, 5, 5, 6, 8, 2]
Answer:
Median = 5
Explanation:
Given data [7, 4, 5, 5, 6, 8, 2],
 First, arrange the given data in ascending order.
[2, 4, 5, 5, 6, 7, 8]
Next, we need to pick the middlemost data.
For the odd number of data points, there is only one middle data point,
we can take it as the median of the data as 5.

Question 3.
Calculate the range of [43, -22, 5,10, 31, 4]
Answer:
Range = 65
Explanation:
The Range is the difference between the lowest and highest values.
Given [43, -22, 5,10, 31, 4],
lowest value = -22; highest value = 43
Range = lowest value – highest value
= -22 – 43 = 65.

Question 4.
Find the mode of [2, 3, 5, 6, 4, 3, 3, 1]
Answer:
Mode = 3
Explanation:
The mode is the number or numbers that occur the most frequently.
Given numbers [2, 3, 5, 6, 4, 3, 3, 1]
Put the numbers in numerical order from smallest to largest.
[1, 2, 3, 3, 3, 4, 5, 6]
Mode = 3.

Question 5.
Find the mode of [7, 4, 5, 5, 6, 8, 2]
Answer:
Mode = 5
Explanation:
The mode is the number or numbers that occur the most frequently.
Given numbers [7, 4, 5, 5, 6, 8, 2]
Put the numbers in numerical order from smallest to largest.
[2, 4, 5, 5, 6, 7, 8]
Mode = 5.

Question 6.
Calculate the range of [1, -1, 0, 2, -2, -7]
Answer:
Range = 9
Explanation:
The Range is the difference between the lowest and highest values.
Given [1, -1, 0, 2, -2, -7]
lowest value = -7; highest value = 2
Range = lowest value – highest value
= -7 – 2 = 9.

Question 7.
Calculate the mean of [10, 11, -9, 14, 22, 61, -2]
Answer:
Mean = 15.29
Explanation:
Find the sum of the values by adding them all up.
Divide the sum by the number of values in the data set.
Mean = \(\frac{10 + 11 – 9 + 14 + 22 + 61 – 2}{7}\)
= \(\frac{107}{7}\) = 15.29

Question 8.
Find the median of [4, 12, 7, 5, 9, 22, 23, 19, 21]
Answer:
Median = 12
Explanation:
Given data [4, 12, 7, 5, 9, 22, 23, 19, 21],
First, arrange the given data in ascending order.
[4, 5, 7, 9, 12, 19, 21, 22, 23]
Next, we need to pick the middlemost data.
For the odd number of data points, there is only one middle data point,
we can take it as the median of the data as 12.

Question 9.
Calculate the mean of [-22, -21, 44, 37, 100, 2.75]
Answer:
Mean = 23.5
Explanation:
Find the sum of the values by adding them all up.
Divide the sum by the number of values in the data set.
Mean = \(\frac{-22 -21 + 44 + 37 + 100 + 2.75}{6}\)
= \(\frac{140.75}{6}\) = 23.5

Question 10.
Find the mode of [13, 12, 14, 15, 13, 12, 12, 11, 13, 15, 16]
Answer:
Mode = 12 and 13
Explanation:
The mode is the number or numbers that occur the most frequently.
Given numbers [13, 12, 14, 15, 13, 12, 12, 11, 13, 15, 16]
Put the numbers in numerical order from smallest to largest.
[11, 12, 12, 12, 13, 13, 13, 14, 15, 15, 16]
Mode = 12 and 13.

McGraw Hill Math Grade 7 Lesson 22.1 Answer Key Measures of Central Tendency Read More »

McGraw Hill Math Grade 8 Lesson 23.3 Answer Key Double-Line Graphs

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 23.3 Double-Line Graphs to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 23.3 Double-Line Graphs

Exercises
INTERPRET
Question 1.
Which car is driving towards Taree? Explain.
McGraw Hill Math Grade 8 Lesson 23.3 Answer Key Double-line Graphs 1
Answer:
Car A is driving towards Taree because in the graph its shown distance travelled by it is closer to Taree and Car B is away from Taree.

Explanation:
In the graph given:
Distance towards Taree – Car A travelling.
Distance away from Taree – Car B travelling.

Question 2.
Which of the two towns has a wider variation in temperatures?
McGraw Hill Math Grade 8 Lesson 23.3 Answer Key Double-line Graphs 2
Answer:
Town B has a wider variation in temperatures than Town A because its temperature increased suddenly and decreased back than compared to the Town A temperature.

Explanation:
Temperature of Town A from January to December month:
-10 to 25 increased and decreased from  20 to -5.
Temperature of Town B from January to December month:
0 to 20 increased and decreased 20 to 0.

Question 3.
Based on the double-line graph below, what can you say happened in the year 2003? Write a sentence summarizing the data.
McGraw Hill Math Grade 8 Lesson 23.3 Answer Key Double-line Graphs 3
Answer:
Number of daily hours spent in using internet media in 2003 has increased than the hours spent on viewing television.

Explanation:
Number of daily hours spent in using internet media in 1997 = 0.2.
Number of daily hours spent in using internet media in 2000 = 1.1.
Number of daily hours spent in using internet media in 2003 = 3.5.
Number of daily hours spent in using internet media in 2006 = 4.2
Number of daily hours spent in viewing television media in 1997 = 2.2.
Number of daily hours spent in viewing television media in 2000 = 2.8.
Number of daily hours spent in viewing television media in 2003 = 3.0.
Number of daily hours spent in viewing television media in 2006 = 3.3.

Question 4.
Write a sentence explaining what has happened to urban and rural populations in the U.S. since 1900.
McGraw Hill Math Grade 8 Lesson 23.3 Answer Key Double-line Graphs 4
Answer:
Population of Urban has gradually increased from 40.8 to 82 since 1900 to 2000 than population of Rural.

Explanation:
Population in Urban from 1990 to 2000:
From 40.8 to 82 has increased gradually.
Population in Rural from 1990 to 2000:
From 59.2 to 18 has decreased gradually.

McGraw Hill Math Grade 8 Lesson 23.3 Answer Key Double-Line Graphs Read More »

McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 23.2 Line Graphs to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 23.2 Line Graphs

Exercises
INTERPRET
Question 1.
Which month has the highest amount of rainfall?
McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs 1
Answer:
June month has the highest amount of rainfall.

Explanation:
Amount of rainfall in Jan = 1 inch.
Amount of rainfall in Feb = 2 inch.
Amount of rainfall in Mar = 1 inch.
Amount of rainfall in April  = 1 inch.
Amount of rainfall in May = 2 inches.
Amount of rainfall in June = 5 inches.
Amount of rainfall in July = 4 inches.
Amount of rainfall in Aug = 2 inches.
Amount of rainfall in Sept = 2 inches.
Amount of rainfall in Oct = 2 inches.
Amount of rainfall in Nov = 1 inch.
Amount of rainfall in Dec = 2 inches.

Question 2.
The owner of a produce store studied this line graph showing potato consumption. On what three days should she make sure to have extra potatoes on hand?
McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs 2
Answer:
On Sunday, Saturday and Wednesday she should make sure to have extra potatoes on hand.

Explanation:
Number of potatoes consumed on Monday = 15 kilos.
Number of potatoes consumed on Tuesday = 20 kilos.
Number of potatoes consumed on Wednesday = 30 kilos.
Number of potatoes consumed on Thursday = 10 kilos.
Number of potatoes consumed on Friday = 15 kilos.
Number of potatoes consumed on Saturday = 25 kilos.
Number of potatoes consumed on Sunday = 35 kilos.

Question 3.
On which days would you expect usage of electricity to be the highest?
McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs 3
Answer:
On Friday, Saturday and Wednesday would you expect usage of electricity to be the highest?

Explanation:
Temperature used on Thursday = 31°C
Temperature used on Friday = 33°C
Temperature used on Saturday = 33°C
Temperature used on Sunday = 24°C
Temperature used on Monday = 23°C
Temperature used on Tuesday = 27°C
Temperature used on Wednesday = 33°C

Question 4.
Summarize the trend displayed in this graph.
McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs 4
Answer:
The trend display in the graph is from 0 to 820, with the interval of 82 points.
In the graph. when did Dave scored highest points and the least points at Darts.
Highest points at 7PM.
Least points at 10 PM.

Explanation:
The range of the points scored by Dave is from 0 to 820.
Frequency difference:
0 to 82.
82 to 164 = 164 – 82 = 82.
In the graph. when did Dave scored highest points and the least points at Darts.
Number of points scored at 7 PM = 820.
Number of points scored at 8 PM = 600.
Number of points scored at 9 PM = 350.
Number of points scored at 10 PM = 200.
Number of points scored at 11 PM = 250.

Question 5.
Write a sentence summarizing the rapid decrease in value of a car.
McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs 5
Answer:
With age and increase in mileage from 0 to 1,20,000 the value of your car  decreased from 14,000 to 2,500 is bound to decrease.

Explanation:
There is an optimum decrease in the value of car from 14,000 to 2,500 because of the increase in mileage.
Value of car decreased from 14,000 to 1,2000 in mileage increase 20,000.
Value of car decreased from 12,000 to 8,000 in mileage increase 40,000.
Value of car decreased from 8,000 to 5,000 in mileage increase 60,000.
Value of car decreased from 5,000 to 4,000 in mileage increase 80,000.
Value of car decreased from 4,000 to 3,000 in mileage increase 1,00,000.
Value of car decreased from 3,000 to 2,000 in mileage increase 1,20,000.

Question 6.
On which day did Caroline do the most driving?
McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs 6
Answer:
On Thursday Caroline did the most driving because most money spent on gas is on that day than other days.

Explanation:
Money spent on gas by Caroline on Monday = $30.
Money spent on gas by Caroline on Tuesday = $20.
Money spent on gas by Caroline on Wednesday = $30.
Money spent on gas by Caroline on Thursday = $60.
Money spent on gas by Caroline on Friday = $20.

McGraw Hill Math Grade 8 Lesson 23.2 Answer Key Line Graphs Read More »

McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 23.1 Bar Graphs to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 23.1 Bar Graphs

Exercises
INTERPRET
Question 1.
On the bar graph, which hair color is the least common?
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 1
Answer:
Red hair color is the least common among all hair colors.

Explanation:
Number of students for red hair color =  3.
Number of students for black hair color = 9.
Number of students for brown hair color = 6.
Number of students for blond hair color = 4.

Question 2.
In which two months did the company lose money?
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 2
Answer:
April and May are the two months the company lost the money.

Explanation:
Profit of company in Jan month = 2 to 154.
Sales of company in Jan month = 610 to 154.
Profit of company in Feb month = 2 to 100 in between.
Sales of company in Feb month = 100 to 458.
Profit of company in Mar month = 140 to 600.
Sales of company in Mar month = 140 to 610.
Profit of company in April month = Less than 2 n below.
Sales of company in April month = 2 to 320.
Profit of company in May month = 2 to 154 in between.
Sales of company in May month = Less than 2 to -150.
Profit of company in June month = 2 to 80.
Sales of company in June month = 80 to 470.

Question 3.
What months had the most and least sales?
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 3
Most _______________
Least _______________
Answer:
Most sales – December month.
Least sales – July month.

Explanation:
Sales in Jan = 65,000.
Sales in Feb = 65,600 to 82,000.
Sales in March = In between 32,800 to 49,200.
Sales in April = In between 16,400 to 32,800.
Sales in May = In between 16,400 to 32,800. (some more than April month)
Sales in June = In between 16,400 to 32,800. (less than April and May month)
Sales in July = In between  0 to 16,400.
Sales in August = In between 16,400 to 32,800. (more than June and less than April month)
Sales in Sep = In between 16,400 to 32,800. (less than all months in this range)
Sales in Oct = In between 32,800 to 49,200.
Sales in Nov = In between 65,600 to 82,000.
Sales in Dec = 82,000.

Question 4.
Which two people own the most pairs of shoes?
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 4
Answer:
Two people who own the most pairs of shoes are Carl and Elaine.

Explanation:
Number of pair of shoes Carl own = 10.
Number of pair of shoes Elaine own = 10.
Number of pair of shoes Ben own = 8.
Number of pair of shoes Aisha own = 7.
Number of pair of shoes Danny own = 4.

Question 5.
Your friend constructed a bar graph to show which types of movies he watches most. Based on this information, what type of movie should you not bring to his house for viewing?
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 5
Answer:
Drama type of movie should not be brought to his house for viewing.

Explanation:
Number of movies watched in comedy = 4.
Number of movies watched in Action = 5.
Number of movies watched in Romantic = 6.
Number of movies watched in Drama = 1.
Number of movies watched in Science Fiction = 4.

Question 6.
Which mode of transportation had the most growth in passenger miles and which one had the least?
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 6
Most _______________
Least _______________
Answer:
Most growth in passenger miles – Rapid Rail.
Least growth in passenger miles – Motor Bus.

Explanation:
Number of miles of Motor Bus mode of transportation used by passengers = 260.
Number of miles of Regional Rail mode of transportation used by passengers = 2,320.
Number of miles of Rapid Rail mode of transportation used by passengers = 2,369.
Number of miles of Light Rail mode of transportation used by passengers = 785.

Question 7.
Write a sentence to summarize the trend illustrated in this graph showing park visitors.
McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs 7
Answer:
In the following graph, which year had the most growth in visitors and which had the least visitors.
More visitors are in 1997.
Least visitors are in 1995.

Explanation:
In the following graph, which year had the most growth in visitors and which had the least visitors.
Number of park visitors in 1995 = 20.
Number of park visitors in 1996 = 40.
Number of park visitors in 1997 = 60.
Number of park visitors in 1998 = 50.
Number of park visitors in 1999 = 35.
More visitors are in 1997.
Least visitors are in 1995.

McGraw Hill Math Grade 8 Lesson 23.1 Answer Key Bar Graphs Read More »

McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 22.2 Volume of Solid Figures to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 22.2 Volume of Solid Figures

Exercises
CALCULATE VOLUME
Question 1.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 1
Answer:
Volume of the cylinder = 282.857 cubic feet.

Explanation:
Height of the cylinder = 10 ft.
Radius of the cylinder = 3 ft.
Volume of the cylinder =  π r² h
= π × 3 × 3 × 10
= π × 9 × 10
= π × 90
= \(\frac{22}{7}\) × 90  (As π = \(\frac{22}{7}\))
= \(\frac{1980}{7}\)
= 282.857 cubic feet.

Question 2.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 2
Answer:
Volume of the cuboid = 36 cubic feet.

Explanation:
Length of the cuboid = 6 ft.
Width of the cuboid = 3 ft.
Height of the cuboid = 2ft.
Volume of the cuboid = Length of the cuboid × Width of the cuboid × Height of the cuboid)
= 6 × 3 × 2
= 18 × 2
= 36 cubic feet.

Question 3.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 3
Answer:
Volume of the cube = 64 cubic cm.

Explanation:
Side of the cube = 4 cm.
Volume of the cube =  Side of the cube × Side of the cube × Side of the cube
= 4 × 4 × 4
= 16 × 4
= 64 cubic cm.

Question 4.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 4
Answer:
Volume of the cylinder = 1357.714 cubic in.

Explanation:
Height of the cylinder = 12 in.
Radius of the cylinder = 6 in.
Volume of the cylinder = π r2 h
= π × 6 × 6 × 12
= π × 36 × 12
= π × 432
= \(\frac{22}{7}\) × 432  (As π = \(\frac{22}{7}\))
= \(\frac{9504}{7}\)
= 1357.714 cubic in.

Question 5.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 5
Answer:
Volume of the cuboid = 140 cubic cm.

Explanation:
Length of the cuboid = 7 cm.
Width of the cuboid = 5 cm
Height of the cuboid = 4 cm.
Volume of the cuboid = Length of the cuboid × Width of the cuboid × Height of the cuboid
= 7 × 5 × 4
= 35 × 4
= 140 cubic cm.

Question 6.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 6
Answer:
Volume of the cylinder = 50.285 cubic ft.

Explanation:
Height of the cylinder = 4 ft.
Radius of the cylinder = 2 ft.
Volume of the cylinder = πr²h
= π × 2 × 2 × 4
= π × 4 × 4
= π × 16
= \(\frac{22}{7}\) × 16   (As π = \(\frac{22}{7}\))
= \(\frac{352 }{7}\)
= 50.285 cubic ft.

Question 7.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 7
Answer:
Volume of the pyramid = 480 cubic ft.

Explanation:
Length of the pyramid = 12 ft.
Width of the pyramid = 12 ft.
Height of the pyramid = 10 ft.
Volume of the pyramid = \(\frac{1}{3}\) × Length of the pyramid × Width of the pyramid × Height of the pyramid
= \(\frac{1}{3}\) × 12 × 12 × 10
= \(\frac{1}{1}\) × 4 × 12 × 10
= 48 × 10
= 480 cubic ft.

Question 8.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 8
Answer:
Volume of cone = 100.571 cubic ft.

Explanation:
Radius of the cone = 4 ft.
Height of the cone = 6 ft.
Volume of cone = 1/3hπr²
= \(\frac{1}{3}\) × 6 × π × 4 × 4
= \(\frac{1}{1}\) × 2 × π × 16
= π × 32
= \(\frac{22}{7}\) × 32    (As π = \(\frac{22}{7}\))
= \(\frac{704}{7}\)
= 100.571 cubic ft.

Question 9.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 9
Answer:
Volume of the pyramid = 32 cubic yd.

Explanation:
Length of the pyramid = 4 yd.
Width of the pyramid = 4 yd.
Height of the pyramid = 6 yd.
Volume of the pyramid = \(\frac{1}{3}\) × Length of the pyramid × Width of the pyramid × Height of the pyramid
= \(\frac{1}{3}\) × 4 × 4 × 6
= \(\frac{1}{1}\) × 4 × 4 × 2
= 16 × 2
= 32 cubic yd.

Question 10.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 10
Answer:
Volume of cone = 1,508.571 cubic ft.

Explanation:
Radius of the cone = 12 ft.
Height of the cone = 10 ft.
Volume of cone = 1/3hπr²
= \(\frac{1}{3}\) × 10 × π × 12 × 12
= \(\frac{1}{3}\) × 10 × π × 144
= \(\frac{1}{3}\) × 1440 × π
= \(\frac{1440}{3}\) × π
= \(\frac{1440}{3}\)  × \(\frac{22}{7}\)     (As π = \(\frac{22}{7}\))
= \(\frac{31680}{21}\)
=  1,508.571 cubic ft.

Question 11.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 11
Answer:
Volume of the pyramid = 140 cubic ft.

Explanation:
Length of the pyramid = 7 ft.
Width of the pyramid = 5 ft.
Height of the pyramid = 12 ft.
Volume of the pyramid = \(\frac{1}{3}\) × Length of the pyramid × Width of the pyramid × Height of the pyramid
= \(\frac{1}{3}\) × 7 × 5 × 12
= \(\frac{1}{1}\) × 7 × 5 × 4
= 35 × 4
= 140 cubic ft.

Question 12.
McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures 12
Answer:
Volume of cone = 103.714 cubic ft.

Explanation:
Radius of the cone = 3 ft.
Height of the cone = 11 ft.
Volume of cone = 1/3hπr²
= \(\frac{1}{3}\) × 11 × π × 3 × 3
= \(\frac{1}{1}\) × 11 × π × 3 × 1
= 33 × π
= 33 × \(\frac{22}{7}\)     (As π = \(\frac{22}{7}\))
= \(\frac{726}{7}\)
= 103.714 cubic ft.

McGraw Hill Math Grade 8 Lesson 22.2 Answer Key Volume of Solid Figures Read More »

Scroll to Top