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Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 24.6 Calculating Probabilities to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 24.6 Calculating Probabilities

Exercises
INTERPRET
Question 1.
If you place 14 marbles in a bag with 7 red, 4 orange, and 3 black, what is the probability of blindly pulling a red marble from the bag?
Answer:
Probability of blindly pulling a red marble from the bag = 0.5.

Explanation:
Total number of marbles in a bag = 14.
Number of red marbles = 7.
Number of orange marbles = 4.
Number of black marbles = 3.
Probability of blindly pulling a red marble from the bag = Number of red marbles ÷ Total number of marbles in a bag
= 7 ÷ 14
= 1 ÷ 2
= 0.5.

Question 2.
If there are 20 males and 15 females in your class, and the teacher wants to appoint one person to be in charge of attendance, what is the probability that this person will be a female?
Answer:
Probability that this person will be a female = 0.42.

Explanation:
Number of males in the class = 20.
Number of females in the class = 15.
Total number of students in the class = Number of males in the class + Number of females in the class
= 20 + 15
= 35.
Probability that this person will be a female = Number of females in the class ÷ Total number of students in the class
= 15 ÷ 35
= 3 ÷ 7
= 0.42.

Question 3.
A survey was taken at school and all 525 students were asked if they belonged to a club. 212 people responded that they did belong to a club. What is the probability that if you randomly chose a person walking down the hall, that this person would belong to a club?
Answer:
Probability that randomly chosen a person walking down the hall, that this person would belong to a club = 2.47.

Explanation:
Total number of students were asked if they belonged to a club in the school = 525.
Number of students responded that they did belong to a club = 212.
Probability that randomly chosen a person walking down the hall, that this person would belong to a club = Number of students responded that they did belong to a club ÷ Total number of students were asked if they belonged to a club in the school
= 525 ÷ 212
= 2.47.

Question 4.
Someone mistakenly put three boxes of hardboiled eggs in with the regular farm eggs that totaled 156 boxes. What is the probability that someone buying a box of eggs will get a box of hardboiled eggs?
Answer:
Probability that someone buying a box of eggs will get a box of hardboiled eggs = 52.

Explanation:
Total number of boxes of eggs = 156.
Number of boxes of hardboiled eggs mixed mistakenly with boxes of regular farm eggs = 3.
Probability that someone buying a box of eggs will get a box of hardboiled eggs = Number of boxes of hardboiled eggs mixed mistakenly with boxes of regular farm eggs  ÷ Total number of boxes of eggs
= 3 ÷ 156
= 52.

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 24.5 Venn Diagrams to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 24.5 Venn Diagrams

Exercises
DIAGRAM
Question 1.
Ramon surveyed a group of 50 people at the town meeting about the expansion of the town zoo and the construction of a bike path. He found that of the 50 people he surveyed, 32 people supported expanding the zoo and 30 people supported constructing a bike path. Twelve people supported both projects. Fill in the Venn Diagram to represent the results of the survey.

How many people supported the town zoo only? ____________
How many supported the bike path only? _____________
Answer:
Number of people supported the town zoo only = 20.
Number of people supported the bike only = 18.

Explanation:
Total number of people he surveyed = 50.
Number of people supported expanding the zoo = 32.
Number of people supported constructing a bike path = 30.
Number of people supported both projects = 12.
Total number of people surveyed = Number of people supported expanding the zoo + Number of people supported constructing a bike path
= 32 + 30
= 62.
Number of people supported the town zoo only = Number of people supported expanding the zoo – Number of people supported expanding the zoo
= 32 – 12
= 20.
Number of people supported the bike only = Number of people supported constructing a bike path – Number of people supported both projects
= 30 – 12
= 18.

Question 2.
The manager of the local clothing store wants to know which jeans to stock for the upcoming back-to-school sale. He reviews the numbers from last year’s sale and finds that the store sold 120 pairs of jeans. 80 were boot- cut, and 60 were stone-washed. Assuming the store only stocked those two styles of jeans, how many of the jeans sold were both stone-washed and boot-cut?

How many of the jeans were just stone-washed and not boot-cut? _____________
How many were just boot-cut and not stone-washed? _____________
Complete the Venn Diagram to show the data.
Answer:
Number of people of the jeans were just stone-washed and not boot-cut = 60.
Number of people were just boot-cut and not stone-washed = 40.

Explanation:
Number of pairs of jeans the store sold = 120.
Number of pairs of jeans were boot- cut = 80.
Number of pairs of jeans were stone-washed = 60.
Total number of pairs of jeans were boot- cut and stone-washed = Number of pairs of jeans were boot- cut + Number of pairs of jeans were stone-washed
= 80 + 60
= 140.
Total number of pairs of jeans were both boot- cut and stone-washed = Total number of pairs of jeans were boot- cut and stone-washed – Number of pairs of jeans the store sold
= 140 – 120
= 20.
Number of people of the jeans were just stone-washed and not boot-cut = Number of pairs of jeans were boot- cut – Total number of pairs of jeans were both boot- cut and stone-washed
= 80 – 20
= 60.
Number of people were just boot-cut and not stone-washed = Number of pairs of jeans were stone-washed  – Total number of pairs of jeans were both boot- cut and stone-washed
= 60 – 20
= 40.

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 24.4 Tree Diagrams to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 24.4 Tree Diagrams

Exercises
DIAGRAM
Question 1.
Phil first rolls a 6-sided number cube then flips a coin. Draw a tree diagram that shows all the possible outcomes. How many different outcomes are there? How many outcomes exist where Phil rolls an even number and he flips a coin “heads”?
Answer:
Total different outcomes = 12.

The coin is fair, the probabilities of getting a head and a tail are equal = 12 .
The probability of getting an even number on a die is 36 = 12 (because among 6 results there are 3 even numbers)

Explanation:
Phil first rolls a 6-sided number cube then flips a coin.
Number of outcomes of a cube Phil first rolls = 6.
Number of outcomes of a coin Phil second rolls = 2.
Total different outcomes = Number of outcomes of a cube Phil first rolls × Number of outcomes of a coin Phil second rolls
= 6 × 2
= 12.
The coin is fair, the probabilities of getting a head and a tail are equal = 12 .
The probability of getting an even number on a die is 36 = 12 (because among 6 results there are 3 even numbers)

.Question 2.
Felicia is laying out her wardrobe for an upcoming vacation. She will be gone 4 days. She lays out 4 shirts (blue, black, red, yellow), 3 pairs of pants (black, tan, white), and 3 pairs of shoes (black, brown, red). Draw a tree diagram to show all of the different combinations of outfits that Felicia could wear on the trip. How many combinations are there? ______________
If Felicia brings only two pairs of shoes but adds another shirt, how many possible combinations will she have? ________________
Answer:
Total outcomes of combinations she have = 40.

Explanation:
Number of days she will be gone = 4 .
Number of shirts she lays out = 4 (blue, black, red, yellow)
Number of pairs of pants = 3 (black, tan, white)
Number of pairs of shoes = 3 (black, brown, red).
Outcomes of wearing shirts = 4 × 4 = 16.
Outcomes of wearing pants = 4 × 3 = 12.
Outcomes of wearing shoes = 4 × 3 = 12.
Total outcomes of combinations she have = Outcomes of wearing shirts + Outcomes of wearing pants + Outcomes of wearing shoes
= 16 + 12 + 12
= 28 + 12
= 40.
If Felicia brings only two pairs of shoes but adds another shirt, how many possible combinations will she have?
Number of shoes she has = 2.
Number of shirts she has = 5.
Outcomes of wearing shirts = 4 × 5 = 20.
Outcomes of wearing pants = 4 × 3 = 12.
Outcomes of wearing shoes = 4 × 2 = 8.
Total outcomes of combinations she have = Outcomes of wearing shirts + Outcomes of wearing pants + Outcomes of wearing shoes
= 20 + 12 + 8
= 32 + 8
= 40.

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 24.3 Box-and-Whisker Plots to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 24.3 Box-and-Whisker Plots

Exercises
INTERPRET
Question 1.
Give the lower quartile for the box-and whisker plot.

Answer:
Weight 70 is the lower quartile for the box-and whisker plot.

Explanation:
The lower quartile, or first quartile (Q1), is the value under which 25% of data points are found when they are arranged in increasing order.
Weight line data = 60, 70, 78, 82, 98.
=> The lower quartile for the box-and whisker plot = Weight 70.

Question 2.
What is the range for this box-and-whisker plot?

Answer:
The range for this box-and-whisker plot = 38.

Explanation:
The range of a box plot is the difference between the maximum and minimum value.
=> Highest value = 60.
Lowest value = 22.
Range of this box-and-whisker plot = Highest value – Lowest value
= 60 – 22
= 38.

Question 3.
Create a box-and whisker plot from this information.

Answer:
A box-and whisker plot from this information:

Explanation:
Median = 12.
Lower Quartile = 8.5.
Upper Quartile = 14.
Lower Extreme = 5.
Upper Extreme = 20.

Question 4.
What is the range and median of this box-and-whisker plot?

Range _____________
Median ____________
Answer:
Range = 40.
Median = 75.

Explanation:
Highest value = 90.
Lowest value = 50.
Range of this box-and-whisker plot = Highest value – Lowest value
= 90 – 50
= 40.
The median is the middle number in the data set.
Median of this box-and-whisker plot = 75.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 11.1 Multiplying Decimals existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 11.1 Multiplying Decimals

Exercises Multiply

Question 1.

Answer:
32.5 × 0.5 = 16.25.

Explanation:
The product of 32.5 × 0.5 is 16.25.

Question 2.

Answer:
45.6×0.33 = 15.048.

Explanation:
The product of 45.6×0.33 is 15.048.

Question 3.

Answer:
-4.52×6.31 = -28.5212.

Explanation:
The product of -4.52×6.31 is -28.5212.

Question 4.

Answer:
789.3×6.8 = 5367.24.

Explanation:
The product of 789.3×6.8 is 5367.24.

Question 5.

Answer:
1.731×0.52 = 0.90012.

Explanation:
The product of 1.731×0.52 is 0.90012.

Question 6.

Answer:
10.01×1.01 = 10.1101.

Explanation:
The product of 10.01×1.01 is 10.1101.

Question 7.

Answer:
-89.89×23.23 = -2088.1447.

Explanation:
The product of -89.89×23.23 is -2088.1447.

Question 8.

Answer:
4.82×88.3 = 425.606.

Explanation:
The product of 4.82×88.3 is 425.606.

Question 9.

Answer:
-.333×.444 = -0.147852.

Explanation:
The product of -.333×.444 is -0.147852.

Question 10.

Answer:
5.5×77.76 = 427.680.

Explanation:
The product of 5.5×77.76 is 427.680.

Question 11.

Answer:
842.1×2.64 = 2223.144.

Explanation:
The product of 842.1×2.64 is 2223.144.

Question 12.

Answer:
63.4×36.5 = 2314.10.

Explanation:
The product of 63.4×36.5 is 2314.10.

Question 13.

Answer:
1.111×55.67 is 61.84937.

Explanation:
The product of 1.111×55.67 is 61.84937

Question 14.

Answer:
51.02×3.91 = 199.4882.

Explanation:
The product of 51.02×3.91 is 199.4882.

Question 15.

Answer:
0.0098 × 0.0013 = 0.00001274.

Explanation:
The product of 0.0098 × 0.0013 is 0.00001274.

Question 16.

Answer:
-8.5 × 2.3 = -19.55.

Explanation:
The product of -8.5 × 2.3 is -19.55.

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 24.2 Stem-and-Leaf Plots to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 24.2 Stem-and-Leaf Plots

Exercises
INTERPRET
Question 1.
Make a list all of the points scored in the basketball games.

Answer:
Points scored in the basketball games = 39, 40, 41, 45, 47, 47, 47, 47, 49, 52, 56, 56, 56.

Explanation:
Stem 3 leaves 9 = 39 points.
Stem 4 leaves 0,1,5,7,7,7,9 = 40,41,45,47,47,47,47,49 points.
Stem 5 leaves 2,6,6,6 = 52,56,56,56 points.

Question 2.
Make a list of the data shown below.

Answer:
Points scored in the basketball games = 120, 125, 128, 128, 130,131, 132, 134, 136, 137, 139, 141, 142, 143, 145, 145, 149, 161, 165.

Explanation:
Stem 12 leaves 0,5,8,8 = 120, 125, 128, 128 points.
Stem 13 leaves 0,1,2,4,6,7,9 = 130,131, 132, 134, 136, 137, 139 points.
Stem 14 leaves 1,2,3,5,5,9 = 141, 142, 143, 145, 145, 149 points.
Stem 15 leaves no points.
Stem 16 leaves 1,5 = 161, 165 points.

Question 3.
Using the stem-and-leaf plot, determine the median age of people at the family reunion, the range, and the mode of the ages.

Median ______________
Range _____________
Mode _____________
Answer:
Median = 35.5.
Range = 80.
Mode = no number repeating.

Explanation:
Stem 0 leaves 1, 8, 9 = 01, 08, 09.
Stem 3 leaves 2, 4, 7 = 32, 34, 37.
Stem 4 leaves 5 = 45.
Stem 5 leaves 1, 5 = 51, 55.
Stem 8 leaves 1 = 81.
Ages of people at Family Reunion = 1, 8, 9, 32, 34, 37, 45, 51, 55, 81.
Median = (34 + 37) ÷ 2
= 71 ÷ 2
= 35.5.
Range = 81 – 1 = 80.
Mode = no number repeating.

Question 4.
In a biology class, eight students collected shrubs for a study. The number of shrubs collected by the students was 4, 8,12,16, 21, 21, and 23. Make a stem-and-leaf plot of these numbers.

Answer:

Explanation:
Number of students = 8.
Number of shrubs collected by the students was 4, 8,12,16, 21, 21, and 23.
Stem     Leaves
0            4  8
1            2  6
2            1  1  3

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 24.1 Measures of Central Tendency to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 24.1 Measures of Central Tendency

Exercises
CALCULATE
Round all answers to the hundredths place.
Question 1.
1, 2, 3, 4, 9, 8, 7, 6, 5.
Mean ________
Median ____________
Range  __________
Mode __________
Answer:
Mean = 0.05.
Median = 0.05.
Range = 0.08.
Mode = All values appeared just once.

Explanation:
1, 2, 3, 4, 9, 8, 7, 6, 5.
Sum of all numbers given = 1 + 2 + 3 + 4 + 9 + 8 + 7 + 6 + 5  = 45.
Numbers of numbers given= 9.
Mean = Sum of all numbers given ÷ Numbers of numbers given
= 45 ÷ 9
= 5.
To find the median, list the values of the data set in numerical order and identify which value appears in the middle of the list.
Arrange the digits from least to great:
1,2,3,4,5,6,7,8,9.
Median = 5.
Range = 9 – 1 = 8.
To find the mode, identify which value in the data set occurs most often.
1,2,3,4,5,6,7,8,9.
Mode: There is no mean as no number is repeating.

Hundredth value:
Mean – 6 = 6 ÷ 100 = 0.06.
Median – 5 = 5 ÷ 100 = 0.05.
Mode – 0 = 0÷ 100 = 0.
Range – 1 = 1 ÷ 100 = 0.01.

Question 2.
10, 15, 20, 60, 110, 10, 10, 45
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.35.
Median = 0.175.
Range = 1.
Mode = 0.10.

Explanation:
10, 15, 20, 60, 110, 10, 10, 45
Arranging numbers in numerical order:
10,10,10,15,20,45,60,110.
Sum of all numbers given= 10 + 10 + 10 + 15 + 20 + 45 + 60 + 110 = 280.
Numbers of numbers given = 8.
Mean = Sum of all numbers given÷ Numbers of numbers given
Mean = 280 ÷ 8 = 35.
10,10,10,15,20,45,60,110.
Median = (15 + 20) ÷ 2
= 35 ÷ 2
= 17.5.
10,10,10,15,20,45,60,110.
Mode = 10.(because its repeating thrice)
Range = 110 – 10 = 100.

Hundredth value :
Mean – 35 = 35 ÷ 100 = 0.35.
Median – 17.5 =  0.175
Mode – 10 = 10 ÷ 100 = 0.10.
Range – 100 = 100 ÷ 100 = 1.

Question 3.
23, 23, 24, 25, 48, 56, 32, 1, 2
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean  = 0.26.
Median  = 0.24.
Mode = 0.23.
Range  = 0.55.

Explanation:
23, 23, 24, 25, 48, 56, 32, 1, 2
Arranging the numbers in numerical order:
1,2,23,23,24,25,32,48,56.
Sum of numbers given = 1 + 2 + 23 + 23 + 24 + 25 + 32 + 48 + 56 = 234
Numbers of numbers given = 9.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 234 ÷ 9
= 26.
1,2,23,23,24,25,32,48,56.
Median = 24.
Mode = 23. (because its repeating twice)
Range = 56 – 1 = 55.

Hundredth value:
Mean – 26 = 26 ÷ 100 = 0.26.
Median – 24 = 24 ÷ 100 = 0.24.
Mode – 23 = 23 ÷ 100 = 0.23.
Range – 55 = 55 ÷ 100 = 0.55.

Question 4.
11, 22, 33, 44, 66, 77, 11, 21
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.35625.
Median = 0.275.
Mode = 0.11.
Range = 0.66.

Explanation:
11, 22, 33, 44, 66, 77, 11, 21
Arranging the numbers in numerical order:
11,11,21,22,33,44,66,77.
Sum of numbers given = 11 + 11 + 21 + 22 + 33 + 44 + 66 + 77 = 285
Numbers of numbers given = 8.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 285 ÷ 8
= 35.625.
11,11,21,22,33,44,66,77.
Median = (22 + 33) ÷ 2
= 55 ÷ 2
= 27.5.
Mode = 11. (because its repeating twice)
Range = 77 – 11 = 66.

Hundredth value:
Mean – 35.625 = 35.625 ÷ 100 = 0.35625.
Median – 27.5 = 27.5 ÷ 100 = 0.275.
Mode – 11 = 11 ÷ 100 = 0.11.
Range – 66 = 66 ÷ 100 = 0.66.

Question 5.
3, 3, 3, 3, 3, 4, 6, 7, 8
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.44.
Median = 0.03.
Mode = 0.03.
Range = 0.05.

Explanation:
3, 3, 3, 3, 3, 4, 6, 7, 8
Arranging the numbers in numerical order:
3, 3, 3, 3, 3, 4, 6, 7, 8.
Sum of numbers given = 3 + 3 + 3 + 3 + 3 + 4 + 6 + 7 + 8 = 40.
Numbers of numbers given = 9.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 40 ÷ 9
= 4.44.
Median = 3.
Mode = 3.(because its repeating 5 times)
Range = 8 – 3 = 5.

Hundredth value :
Mean – 4.44 = 4.44 ÷ 100 = 0.44.
Median – 3 = 3 ÷ 100 = 0.03.
Mode – 3 = 3 ÷ 100 = 0.03.
Range – 5 = 5 ÷ 100 = 0.05.

Question 6.
4, 5, 6, 8, 9, 21, 22, 23, 24, 21, 5, 27
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.145833.
Median = 0.15.
Mode = 0.05, 0.21.
Range = 0.23.

Explanation:
4, 5, 6, 8, 9, 21, 22, 23, 24, 21, 5, 27
Arranging the numbers in numerical order:
4, 5, 5, 6, 8, 9, 21, 21, 22, 23, 24, 27
Sum of numbers given = 4 + 5 + 5 + 6 + 8 + 9 + 21 + 21 + 22 + 23 + 24 + 27 = 175.
Numbers of numbers given = 12.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 154 ÷ 12
= 14.5833.
Median = (9 + 21) ÷ 2
= 30 ÷ 2
= 15.
Mode = 5, 21 (both are repeating twice)
Range = 27 – 4 = 23.

Hundredth value :
Mean – 14.5833 = 14.5833 ÷ 100 = 0.145833.
Median – 15 = 15 ÷ 100 = 0.15.
Mode – 5,21 = 5 ÷ 100 = 0.05, 21 ÷ 100 = 0.21.
Range – 23 = 23 ÷ 100 = 0.23.

Question 7.
9, 13, 56, 12, 13, 9, 9, 18, 45
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.20444.
Median = 0.13.
Mode = 0.09.
Range = 0.47.

Explanation:
9, 13, 56, 12, 13, 9, 9, 18, 45
Arranging the numbers in numerical order:
9,9,9,12,13,13,18,45,56.
Sum of numbers given = 9 + 9 + 9 + 12+ 13+ 13+ 18 + 45 + 56 = 184.
Numbers of numbers given = 9.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 184 ÷ 9
= 20.444.
Median = 13.
Mode = 9 (because its repeating thrice)
Range = 56 – 9 = 47.

Hundredth value :
Mean – 20.444 = 20.444÷ 100 = 0.20444.
Median – 13 = 13 ÷ 100 = 0.13.
Mode – 9 = 9 ÷ 100 = 0.09.
Range – 47= 47÷ 100 = 0.47.

Question 8.
-3, -10, -10, 14, 16, 22, 21, 30
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.10.
Median = 0.15.
Mode  = – 0.10.
Range = 0.40.

Explanation:
-3, -10, -10, 14, 16, 22, 21, 30
Arranging the numbers in numerical order:
-10, -10, -3, 14, 16, 21, 22, 30
Sum of numbers given = -3 – 10 – 10 + 14 + 16 + 21 + 22 + 30 = – 23 + 103 = 80.
Numbers of numbers given = 8.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 80 ÷ 8
= 10.
Median = (14 + 16) ÷ 2
= 30 ÷ 2
= 15.
Mode = – 10. (because its repeating twice)
Range = 30 – (-10) = 30 + 10 = 40.

Hundredth value :
Mean – 10= 10÷ 100 = 0.10.
Median – 15 = 15 ÷ 100 = 0.15.
Mode – (-10) = (-10) ÷ 100 = – 0.10.
Range – 40 = 40÷ 100 = 0.40.

Question 9.
-1, -1, -5, -6, -7, 10, 1, 14, 27
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.03555.
Median = – 0.01.
Mode = – 0.01.
Range = 0.34.

Explanation:
-1, -1, -5, -6, -7, 10, 1, 14, 27
Arranging the numbers in numerical order:
-7, -6, -5, -1, -1, 1, 10, 14, 27
Sum of numbers given = – 1 – 1 – 5 – 6 – 7 + 10 + 1 + 14 + 27 = – 20 + 52 = 32.
Numbers of numbers given = 9.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 32 ÷ 9
= 3.555.
Median = -1.
Mode = – 1. (because its repeating twice)
Range = 27 – (7) = 27 + 7 = 34.

Hundredth value :
Mean – 3.555 = 3.555 ÷ 100 = 0.03555.
Median – (-1) = – 1÷ 100 = – 0.01.
Mode – (-1) = -1 ÷ 100 = – 0.01.
Range – 34= 34 ÷ 100 = 0.34.

Question 10.
-10, -20, -20, 0, 10, 20, 20
Mean ___________
Median ___________
Range ___________
Mode ___________
Answer:
Mean = 0.00.
Median = 0.00.
Mode = – 0.20 and 0.20.
Range = 0.40.

Explanation:
-10, -20, -20, 0, 10, 20, 20
Arranging the numbers in numerical order:
-20, -20, -10, 0, 10, 20, 20.
Sum of numbers given = – 20 – 20 – 10 + 0 + 10 + 20 + 20 = – 50 + 50 = 0.
Numbers of numbers given = 7.
Mean = Sum of numbers given ÷ Numbers of numbers given
= 0 ÷ 7
= 0.
Median = 0.
Mode = – 20, 20. (because both are repeating twice)
Range = 20 – (-20) = 20 + 20 = 40.

Hundredth value :
Mean – 0 = 0 ÷ 100 = 0.00.
Median – 0 = 0 ÷ 100 = 0.00.
Mode – (-20, 20) = -20 ÷ 100 = – 0.20 and 20 ÷ 100 = 0.20.
Range – 40 = 40 ÷ 100 = 0.40.

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 7.3 Multiplying Mixed Numbers: Reducing existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 7.3 Multiplying Mixed Numbers: Reducing

Exercises Multiply

Question 1.
5\(\frac{1}{4}\) × \(\frac{1}{2}\)
Answer:
2\(\frac{5}{8}\)
Explanation:
5\(\frac{1}{4}\) × \(\frac{1}{2}\)
Convert mixed fraction into simplest fraction.
= \(\frac{21}{4}\) × \(\frac{1}{2}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{21 X 1}{4 X 2}\)
= \(\frac{21}{8}\)
= 5\(\frac{5}{8}\)

Question 2.
\(\frac{1}{3}\) × 5\(\frac{1}{3}\)
Answer:
1\(\frac{7}{9}\)
Explanation:
\(\frac{1}{3}\) × 5\(\frac{1}{3}\)
Convert mixed fraction into simplest fraction.
= \(\frac{1}{3}\) × \(\frac{16}{3}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{1 X 16}{3 X 3}\)
= \(\frac{16}{9}\)
= 1\(\frac{7}{9}\)

Question 3.
-12\(\frac{1}{4}\) × \(\frac{3}{2}\)
Answer:
-18\(\frac{3}{8}\)
Explanation:
-12\(\frac{1}{4}\) × \(\frac{3}{2}\)
Convert mixed fraction into simplest fraction.
= –\(\frac{49}{4}\) × \(\frac{3}{2}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= –\(\frac{49 X 3}{4 X 2}\)
= –\(\frac{147}{8}\)
= -12\(\frac{3}{8}\)

Question 4.
3\(\frac{1}{7}\) × \(\frac{14}{3}\)
Answer:
14\(\frac{2}{3}\)
Explanation:
3\(\frac{1}{7}\) × \(\frac{14}{3}\)
Convert mixed fraction into simplest fraction.
= \(\frac{22}{7}\) × \(\frac{14}{3}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{22 X 14}{7 X 3}\)
= \(\frac{308}{21}\)
= \(\frac{44}{3}\)
= 14\(\frac{2}{3}\)

Question 5.
–\(\frac{1}{5}\) × 1\(\frac{3}{4}\)
Answer:
–\(\frac{7}{20}\)
Explanation:
–\(\frac{1}{5}\) × 1\(\frac{3}{4}\)
Convert mixed fraction into simplest fraction.
= –\(\frac{1}{5}\) × \(\frac{7}{4}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= –\(\frac{1 X 7}{5 X 4}\)
= –\(\frac{7}{20}\)

Question 6.
6\(\frac{5}{7}\) × \(\frac{2}{3}\)
Answer:
4\(\frac{10}{21}\)
Explanation:
6\(\frac{5}{7}\) × \(\frac{2}{3}\)
Convert mixed fraction into simplest fraction.
= \(\frac{47}{7}\) × \(\frac{2}{3}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{47 X 2}{7 X 3}\)
= \(\frac{94}{21}\)
= 4\(\frac{10}{21}\)

Question 7.
4\(\frac{2}{5}\) × \(\frac{3}{8}\)
Answer:
1\(\frac{13}{20}\)
Explanation:
4\(\frac{2}{5}\) × \(\frac{3}{8}\)
Convert mixed fraction into simplest fraction.
= \(\frac{22}{5}\) × \(\frac{3}{8}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{22 X 3}{5 X 8}\)
= \(\frac{66}{40}\)
= \(\frac{33}{20}\)
= 1\(\frac{13}{20}\)

Question 8.
3\(\frac{1}{4}\) × \(\frac{5}{8}\)
Answer:
2\(\frac{1}{32}\)
Explanation:
3\(\frac{1}{4}\) × \(\frac{5}{8}\)
Convert mixed fraction into simplest fraction.
= \(\frac{13}{4}\) × \(\frac{5}{8}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{13 X 5}{4 X 8}\)
= \(\frac{65}{32}\)
= 2\(\frac{1}{32}\)

Question 9.
3\(\frac{2}{5}\) × \(\frac{5}{9}\)
Answer:
1\(\frac{8}{9}\)
Explanation:
3\(\frac{2}{5}\) × \(\frac{5}{9}\)
Convert mixed fraction into simplest fraction.
= \(\frac{17}{5}\) × \(\frac{5}{9}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{17 X 5}{5 X 9}\)
= \(\frac{85}{45}\)
= \(\frac{17}{9}\)
= 1\(\frac{8}{9}\)

Question 10.
\(\frac{1}{4}\) × 4\(\frac{1}{3}\)
Answer:
1\(\frac{1}{12}\)
Explanation:
\(\frac{1}{4}\) × 4\(\frac{1}{3}\)
Convert mixed fraction into simplest fraction.
= \(\frac{1}{4}\) × \(\frac{13}{3}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{1 X 13}{4 X 3}\)
= \(\frac{13}{12}\)
= 1\(\frac{1}{12}\)

Question 11.
3\(\frac{2}{3}\) × 1\(\frac{2}{7}\)
Answer:
4\(\frac{5}{7}\)
Explanation:
3\(\frac{2}{3}\) × 1\(\frac{2}{7}\)
Convert mixed fraction into simplest fraction.
= \(\frac{11}{3}\) × \(\frac{9}{7}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{11 X 9}{3 X 7}\)
= \(\frac{99}{21}\)
= \(\frac{33}{7}\)
= 4\(\frac{5}{7}\)

Question 12.
-4\(\frac{1}{5}\) × -2\(\frac{3}{14}\)
Answer:
9\(\frac{3}{10}\)
Explanation:
-4\(\frac{1}{5}\) × -2\(\frac{3}{14}\)
Convert mixed fraction into simplest fraction.
= –\(\frac{21}{5}\) × –\(\frac{31}{14}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{21 X 31}{5 X 14}\)
= \(\frac{651}{70}\)
= \(\frac{93}{10}\)
= 9\(\frac{3}{10}\)

Question 13.
5\(\frac{1}{4}\) × 3\(\frac{1}{3}\)
Answer:
17\(\frac{1}{2}\)
Explanation:
5\(\frac{1}{4}\) × 3\(\frac{1}{3}\)
Convert mixed fraction into simplest fraction.
= \(\frac{21}{4}\) × \(\frac{10}{3}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{21 X 10}{4 X 3}\)
= \(\frac{210}{12}\)
= \(\frac{35}{2}\)
= 17\(\frac{1}{2}\)

Question 14.
-2\(\frac{4}{5}\) × -4\(\frac{2}{7}\)
Answer:
12
Explanation:
-2\(\frac{4}{5}\) × -4\(\frac{2}{7}\)
Convert mixed fraction into simplest fraction.
= –\(\frac{14}{5}\) × –\(\frac{30}{7}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{14 X 30}{5 X 7}\)
= \(\frac{520}{35}\)
= 12

Question 15.
3\(\frac{3}{4}\) × 3\(\frac{3}{10}\)
Answer:
12\(\frac{3}{8}\)
Explanation:
3\(\frac{3}{4}\) × 3\(\frac{3}{10}\)
Convert mixed fraction into simplest fraction.
= \(\frac{15}{4}\) × \(\frac{33}{10}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{15 X 33}{4 X 10}\)
= \(\frac{495}{40}\)
= \(\frac{99}{8}\)
= 12\(\frac{3}{8}\)

Question 16.
3\(\frac{1}{3}\) × 3\(\frac{3}{5}\)
Answer:
12
Explanation:
3\(\frac{1}{3}\) × 3\(\frac{3}{5}\)
Convert mixed fraction into simplest fraction.
= \(\frac{10}{3}\) × \(\frac{18}{5}\)
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
= \(\frac{10 X 18}{3 X 5}\)
= \(\frac{180}{15}\)
= 12

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 7.2 Multiply Fractions: Reciprocals existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 7.2 Multiply Fractions: Reciprocals

Exercises Multiply

Question 1.
\(\frac{1}{2}\) × \(\frac{2}{3}\)
Answer:
\(\frac{1}{3}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{1}{2}\) × \(\frac{2}{3}\)
= \(\frac{1 X 2}{2 X 3}\)
= \(\frac{2}{6}\)
= \(\frac{1}{3}\)

Question 2.
\(\frac{5}{7}\) × \(\frac{3}{8}\)
Answer:
\(\frac{15}{56}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{5}{7}\) × \(\frac{3}{8}\)
= \(\frac{5 X 3}{7 X 8}\)
= \(\frac{15}{56}\)

Question 3.
\(\frac{20}{21}\) × \(\frac{2}{5}\)
Answer:
\(\frac{8}{21}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{20}{21}\) × \(\frac{2}{5}\)
= \(\frac{20 X 2}{21 X 5}\)
= \(\frac{40}{105}\)
= \(\frac{8}{21}\)

Question 4.
–\(\frac{3}{2}\) × \(\frac{3}{2}\)
Answer:
–\(\frac{9}{4}\) or -2\(\frac{1}{4}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{3}{2}\) × \(\frac{3}{2}\)
= –\(\frac{3 X 3}{2 X 2}\)
= –\(\frac{9}{4}\)
= -2\(\frac{1}{4}\)

Question 5.
\(\frac{2}{3}\) × \(\frac{3}{2}\)
Answer:
1
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{2}{3}\) × \(\frac{3}{2}\)
= \(\frac{2 X 3}{3 X 2}\)
= \(\frac{6}{6}\)
= 1

Question 6.
–\(\frac{7}{4}\) × \(\frac{16}{3}\)
Answer:
–\(\frac{28}{3}\) or -9\(\frac{1}{3}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{7}{4}\) × \(\frac{16}{3}\)
= –\(\frac{7 X 16}{2 X 3}\)
= –\(\frac{112}{6}\)
= –\(\frac{28}{3}\)
= -9\(\frac{1}{3}\)

Question 7.
\(\frac{5}{9}\) × \(\frac{90}{10}\)
Answer:
5
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{5}{9}\) × \(\frac{90}{10}\)
= \(\frac{5 X 90}{9 X 10}\)
= \(\frac{450}{90}\)
= 5

Question 8.
\(\frac{4}{7}\) × \(\frac{3}{28}\)
Answer:
\(\frac{3}{49}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{4}{7}\) × \(\frac{3}{28}\)
= \(\frac{4 X 3}{7 X 28}\)
= \(\frac{12}{196}\)
= \(\frac{3}{49}\)

Question 9.
\(\frac{3}{11}\) × \(\frac{11}{3}\)
Answer:
1
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{3}{11}\) × \(\frac{11}{3}\)
= \(\frac{3 X 11}{11 X 3}\)
= \(\frac{33}{33}\)
= 1

Question 10.
\(\frac{12}{13}\) × \(\frac{39}{2}\)
Answer:
18
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{12}{13}\) × \(\frac{39}{2}\)
= \(\frac{12 X 39}{13 X 2}\)
= \(\frac{468}{26}\)
=18

Question 11.
–\(\frac{3}{8}\) × –\(\frac{2}{13}\)
Answer:
\(\frac{3}{52}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{3}{8}\) × –\(\frac{2}{13}\)
= \(\frac{3 X 2}{8 X 13}\)
= \(\frac{6}{104}\)
= \(\frac{3}{52}\)

Question 12.
\(\frac{7}{8}\) × \(\frac{16}{3}\)
Answer:
\(\frac{14}{3}\) or 4\(\frac{2}{3}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{7}{8}\) × \(\frac{16}{3}\)
= \(\frac{7 X 16}{8 X 3}\)
= \(\frac{112}{24}\)
= \(\frac{14}{3}\)
= 4\(\frac{2}{3}\)

Question 13.
–\(\frac{81}{7}\) × –\(\frac{1}{9}\)
Answer:
\(\frac{9}{7}\) or 1\(\frac{2}{7}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
–\(\frac{81}{7}\) × –\(\frac{1}{9}\)
= \(\frac{81 X 1}{7 X 9}\)
= \(\frac{81}{63}\)
= \(\frac{9}{7}\)
= 1\(\frac{2}{7}\)

Question 14.
\(\frac{7}{3}\) × \(\frac{3}{14}\)
Answer:
\(\frac{1}{2}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{7}{3}\) × \(\frac{3}{14}\)
= \(\frac{7 X 3}{3 X 14}\)
= \(\frac{21}{42}\)
= \(\frac{1}{2}\)

Question 15.
\(\frac{15}{16}\) × \(\frac{3}{5}\)
Answer:
\(\frac{9}{16}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{15}{16}\) × \(\frac{3}{5}\)
= \(\frac{15 X 3}{16 X 5}\)
= \(\frac{45}{80}\)
= \(\frac{9}{16}\)

Question 16.
\(\frac{10}{13}\) × \(\frac{52}{7}\)
Answer:
\(\frac{40}{7}\)or 5\(\frac{5}{7}\)
Explanation:
Multiply the numerators to get the numerator of the product,
then multiply the denominators to get the denominators of the product.
\(\frac{10}{13}\) × \(\frac{52}{7}\)
= \(\frac{10 X 52}{7 X 7}\)
= \(\frac{520}{49}\)
= \(\frac{40}{49}\)
= 5\(\frac{5}{7}\)

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 6.7 Subtracting Mixed Numbers with Unlike Denominators existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 6.7 Subtracting Mixed Numbers with Unlike Denominators

Add Mixed Numbers

Question 1.
5\(\frac{1}{2}\) – 2\(\frac{1}{4}\)
Answer:
First subtract the whole numbers.
5 – 2 = 3
Second find a common denominator for the fractions.
\(\frac{1}{2}\) = \(\frac{2}{4}\) 
Third subtract the fractions.
\(\frac{2}{4}\) – \(\frac{1}{4}\) = \(\frac{1}{4}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
3 + \(\frac{1}{4}\) = 3\(\frac{1}{4}\) 

Question 2.
10\(\frac{3}{7}\) – 4\(\frac{2}{11}\)
Answer:
First subtract the whole numbers.
10 – 4 = 6
Second find a common denominator for the fractions.
\(\frac{3}{7}\) = \(\frac{33}{77}\)
\(\frac{2}{11}\) = \(\frac{14}{77}\) 
Third subtract the fractions.
\(\frac{33}{77}\) – \(\frac{14}{77}\) = \(\frac{19}{77}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
6 + \(\frac{19}{77}\) = 6\(\frac{19}{77}\) 

Question 3.
21\(\frac{5}{9}\) – 4\(\frac{2}{5}\)
Answer:
First subtract the whole numbers.
21 – 4 = 17
Second find a common denominator for the fractions.
\(\frac{5}{9}\) = \(\frac{25}{45}\)
\(\frac{2}{5}\) = \(\frac{18}{45}\) 
Third subtract the fractions.
\(\frac{25}{45}\) – \(\frac{18}{45}\) = \(\frac{7}{45}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
17 + \(\frac{7}{45}\) = 17\(\frac{7}{45}\) 

Question 4.
13\(\frac{5}{6}\) – 10\(\frac{2}{9}\)
Answer:
First subtract the whole numbers.
13 – 10 = 3
Second find a common denominator for the fractions.
\(\frac{5}{6}\) = \(\frac{15}{18}\)
\(\frac{2}{9}\) = \(\frac{4}{18}\) 
Third subtract the fractions.
\(\frac{15}{18}\) – \(\frac{4}{18}\) = \(\frac{11}{18}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
3 + \(\frac{11}{18}\) = 3\(\frac{11}{18}\) 

Question 5.
14\(\frac{2}{3}\) – 5\(\frac{1}{6}\)
Answer:
First subtract the whole numbers.
14 – 5 = 9
Second find a common denominator for the fractions.
\(\frac{2}{3}\) = \(\frac{4}{6}\) 
Third subtract the fractions.
\(\frac{4}{6}\) – \(\frac{1}{6}\) = \(\frac{3}{6}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
9 + \(\frac{3}{6}\) = 9\(\frac{3}{6}\) or 9\(\frac{1}{2}\)

Question 6.
21\(\frac{3}{4}\) – 11\(\frac{5}{9}\)
Answer:
First subtract the whole numbers.
21 – 11 = 10
Second find a common denominator for the fractions.
\(\frac{3}{4}\) = \(\frac{27}{36}\)
\(\frac{5}{9}\) = \(\frac{20}{36}\) 
Third subtract the fractions.
\(\frac{27}{36}\) – \(\frac{20}{36}\) = \(\frac{7}{36}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
10 + \(\frac{7}{36}\) = 10\(\frac{7}{36}\) 

Question 7.
13\(\frac{5}{6}\) – 3\(\frac{1}{7}\)
Answer:
First subtract the whole numbers.
13 – 3 = 10
Second find a common denominator for the fractions.
\(\frac{5}{6}\) = \(\frac{35}{42}\)
\(\frac{1}{7}\) = \(\frac{6}{42}\) 
Third subtract the fractions.
\(\frac{35}{42}\) – \(\frac{6}{42}\) = \(\frac{29}{42}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
10 + \(\frac{29}{42}\) = 10\(\frac{29}{42}\) 

Question 8.
43\(\frac{4}{5}\) – 29\(\frac{3}{11}\)
Answer:
First subtract the whole numbers.
43 – 29 = 14
Second find a common denominator for the fractions.
\(\frac{4}{5}\) = \(\frac{44}{55}\)
\(\frac{3}{11}\) = \(\frac{15}{55}\) 
Third subtract the fractions.
\(\frac{44}{55}\) – \(\frac{15}{55}\) = \(\frac{29}{55}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
14 + \(\frac{29}{55}\) = 14\(\frac{29}{55}\) 

Question 9.

Answer:

Explanation:
First subtract the whole numbers.
10 – 4 = 6
Second find a common denominator for the fractions.
\(\frac{6}{11}\) = \(\frac{12}{22}\)
\(\frac{1}{2}\) = \(\frac{11}{22}\) 
Third subtract the fractions.
\(\frac{12}{22}\) – \(\frac{11}{22}\) = \(\frac{1}{22}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
6 + \(\frac{1}{22}\) = 6\(\frac{1}{22}\) 

Question 10.

Answer:

Explanation:
First subtract the whole numbers.
13 – 11 = 2
Second find a common denominator for the fractions.
\(\frac{2}{3}\) = \(\frac{6}{9}\) 
Third subtract the fractions.
\(\frac{6}{9}\) – \(\frac{5}{9}\) = \(\frac{1}{9}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
2 + \(\frac{1}{9}\) = 2\(\frac{1}{9}\) 

Question 11.

Answer:

Explanation:
First subtract the whole numbers.
77 – 41 = 36
Second find a common denominator for the fractions.
\(\frac{2}{3}\) = \(\frac{34}{51}\)
\(\frac{2}{17}\) =\(\frac{6}{51}\) 
Third subtract the fractions.
\(\frac{34}{51}\) – \(\frac{6}{51}\) = \(\frac{28}{51}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
36 + \(\frac{28}{51}\) = 36\(\frac{28}{51}\) 

Question 12.

Answer:

Explanation:
First subtract the whole numbers.
19 – 3 = 16
Second find a common denominator for the fractions.
\(\frac{5}{7}\) = \(\frac{10}{14}\)  
Third subtract the fractions.
\(\frac{10}{14}\) – \(\frac{1}{14}\) = \(\frac{9}{14}\) 
Fourth add the difference of the fractions to the difference of the whole numbers.
16 + \(\frac{9}{14}\) = 16\(\frac{9}{14}\)

Question 13.
Janelle practiced playing the piano 2\(\frac{1}{2}\) hours on Saturday. On Sunday, she practiced for 3\(\frac{1}{4}\) hours. How many more hours did Janelle practice on Sunday than on Saturday?
Answer:

Question 14.
Robby is helping his father make a casserole for dinner. They purchased 1\(\frac{1}{4}\) pounds of potatoes, and used \(\frac{2}{3}\) pounds of potatoes to make one casserole.
Do they have enough potatoes left over to make the casserole a second time?
Answer: