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McGraw Hill Math Grade 7 Lesson 15.7 Answer Key Percent Markups and Markdowns

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McGraw-Hill Math Grade 7 Answer Key Lesson 15.7 Percent Markups and Markdowns

Exercises

SOLVE

Question 1.
Valerie buys a book that costs $22.00, plus 8.25% sales tax. What does she pay for the book?
Answer:
Cost of the book = $22.00
Sales tax = 8.25%
Calculate the tax:
(8.25/100) x $22.00 = $1.82
Add the tax to the cost of the book.
$22.00 + $1.82 = $23.82
She pay $23.82 for the book.

Question 2.
Chris always tips his barber 30% for a haircut. If the haircut costs $25.00, how much will Chris leave for a trip?
Answer:
The cost of haircut is $25.00.
Chris always tips his barber 30% for a haircut.
(30/100) x $25.00 = $7.50
Chris leaves $7.50 for a tip.

Question 3.
There is a 4% line fee added to cell phone bills in Bellville. If Erlene’s bill before the fee is $56.80, what is her bill total after the fee is added?
Answer:
There is a 4% line fee added to cell phone bills in Bellville.
Erlene’s before the fee is $56.80.
(4/100) x $56.80 = $2.27
The line fee added to cell phone bills in Bellville is $2.27.
Add the line fee to Erlene’s bill before the fee.
$56.80 + $2.27 = $59.07
Erlene’s total bill is $59.07 after the fee is added.

Question 4.
Bob earns a base salary of $500 per week, plus 6% commission on all his sales. If he sold $3,240 this week, what will his salary be for this week?
Answer:
Bob earns a base salary of $500 per week, plus 6% commission on all his sales.
He sold $3,240 this week.
$3,240 x (6/100) = $194.40
Bob commission on all his sales is $194.40.
Add commission with base salary.
$500 + $194.40 = $694.40
Bob salary for this week is $694.40.

Question 5.
Last year, 32,500 people attended the county fair. This year, 45,800 people attended. What is the percent increase in attendance?
Answer:
Last year, 32,500 people attended the county fair.
This year, 45,800 people attended.
Find the difference between the two amounts.
45,800 – 32,500 = 13,300 people
Percentage increase in attendance = (Difference between the amounts)/(original amounts) x 100
= (13,300/32,500) x 100
= 40.92%
= 41%
The percentage increase in attendance is equal to 41%.

Question 6.
Elba missed 7 out of 60 questions on a test. What percent did she get correct?
Answer:
Elba missed 7 out of 60 questions on a test.
Find the difference between the two amounts.
60 – 7 = 53 questions
Percentage = (Difference between the amounts)/(original amounts) x 100
= (53/60) x 100
= 88.33%
= 88%
88% percentage did she get correct.

Question 7.
A store is having a 15% off sale. What is the new price of a table that originally cost $200?
Answer:
A store is having a 15% off sale.
The original cost is $200.
Multiply the percentage off by the price.
$200 x (15/100) = $30
Subtract the sale off price from original price.
$200 – $30 = $170
The new price of a table is $170.

Question 8.
A dress that was originally $89 is marked down to $75. By what percent was the price decreased?
Answer:
A dress that was originally $89 is marked down to $75.
The difference between the two amounts.
$89 – $75 = $14
Percentage = (Difference between the amounts)/(original amounts) x 100
= ($14/$89) x 100
= 15.73%
= 16%
The price was decreased by16% percentage.

Question 9.
Only 12 people can ride a trolley at one time. This is 20% of the people waiting to ride. How many people are waiting to ride?
Answer:
Only 12 people can ride a trolley at one time.
20% of the people waiting to ride.
20% x r = 12
r = 12 x (100/20)
r = 60 people
60 people are waiting to ride a trolley.

Question 10.
Jack received $40 from his aunt for his birthday. He wants to buy a video game for $27.99, a hat for $7.99, and a candy bar for $.50. Sales tax is 8.5%. What would the total be for his purchases? Will he have enough money?
Answer:
First find the total before the tax.
$27.99 + $7.99 + $0.50 = $36.48
Second calculate the tax.
(8.5/100) x $36.48 = $3.1
Third add the tax to the total.
$36.48 + $3.1 = $39.58
The total for Jack purchases is $39.58.
Yes, Jack have enough money.

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McGraw Hill Math Grade 7 Lesson 15.6 Answer Key Simple Interest for More or Less than One Year

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McGraw-Hill Math Grade 7 Answer Key Lesson 15.6 Simple Interest for More or Less than One Year

Exercises

SOLVE

Round all answers to the nearest cent.

Question 1.
How much simple interest would you earn if you had $10,000 and you were being paid 5% for 15 months?
Answer:
Principal = $10,000
Rate of interest = 5% = 5/100
15 months = 12 months + 3 months = 1 1/4
Total number of years = 5/4
Simple interest = Principal x Rate of interest x Years
= $10,000 x (5/100) x (5/4)
= $625
I will earn simple interest $625.

Question 2.
If you invest $5,600 for 18 months at a simple interest rate of 7%, how much would you earn?
Answer:
Principal = $5,600
Rate of interest = 7% = 7/100
18 months = 12 months + 6 months = 1 1/2
Total number of years = 3/2
Simple interest = Principal x Rate of interest x Years
= $5,600 x (7/100) x (3/2)
= $588
I will earn simple interest $588.

Question 3.
What would be the total amount that you would have after 7 months if you started with $2,700 and were paid simple interest of 5.5%?
Answer:
Principal = $2,700
Rate of interest = 5.5% = 5.5/100
7 months = 7/12
Total number of years = 7/12
Simple interest = Principal x Rate of interest x Years
= $2,700 x (5.5/100) x (7/12)
= $86.625
Simple interest is equal to $86.625.
Principal + simple interest = $2,700 + $86.625 = $2,786.625
After 7 months the total amount that I would have is $2,786.625.

Question 4.
If you start with $6,275 and earn simple interest of 14.75% for 37 months, what would be your total earnings for the period?
Answer:
Principal = $6,275
Rate of interest = 14.75% = 14.75/100
37 months = 37/12
Total number of years = 37/12
Simple interest = Principal x Rate of interest x Years
= $6,275 x (14.75/100) x (37/12)
= $2853.82
The total earning for the period is equal to $2,853.82.

Question 5.
You have a principal of $45,200 and will receive simple interest of 19.5% for 4 years. How much interest will you earn?
Answer:
Principal = $45,200
Rate of interest = 19.5% = 19.5/100
Total number of years = 4
Simple interest = Principal x Rate of interest x Years
= $45,200 x (19.5/100) x 4
= $35256
I will earn simple interest $35,256.

Question 6.
What would be the simple interest earned on $2,350 at 9.27% for 23 months?
Answer:
Principal = $2,350
Rate of interest = 9.27% = 9.27/100
23 months = 23/12
Total number of years = 23/12
Simple interest = Principal x Rate of interest x Years
= $2,350 x (9.27/100) x (23/12)
= $417.54
Simple interest is equal to $417.54.

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McGraw Hill Math Grade 7 Lesson 15.5 Answer Key Simple Interest

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McGraw-Hill Math Grade 7 Answer Key Lesson 15.5 Simple Interest

Exercises

SOLVE

Question 1.
If the simple interest earned on $200 is $50, how much would you be earning on $700?
Answer:
The simple interest earned on $200 is $50.
We have to calculate how much interest is earned on $700.
$200 = $50
$700 = $?
($700 x $50)/$200 = $175
The simple interest earned on $700 is $175.

Question 2.
A principal of $3000 will earn how much simple interest at 7.2%?
Answer:
Principal = $3000
Rate of interest = 7.2%
Simple interest = Principal x Rate of interest
= $3000 x 7.2%
= $3000 x (7.2/100)
= $216
Simple interest is equal to $216.

Question 3.
Your uncle gives you $100 and deposits it into a savings account that pays simple interest of 6% per year. How much will you earn in interest for the year?
Answer:
Principal amount = $100
Simple interest per year = ?
Rate of interest for the year = 6%
Simple interest = Principal x Rate of interest
= $100 x (6/100)
= $6
I will earn $6 in interest for the year.

Question 4.
At the beginning of the year you have $450 in your savings account and you are earning simple interest of 3.5% for the year. How much will you have at the end of the year?
Answer:
Principal = $450
Rate of interest = 3.5%
Simple interest = Principal x Rate of interest
= $450 x (3.5/100)
= $15.75
Simple interest for the year is equal to $15.75.
Principal + simple interest = $450 + $15.75 = $465.75
I will have $465.75 at the end of the year.

Question 5.
Simple interest at 7% on $5,000 would be how much?
Answer:
Principal = $5,000
Rate of interest = 7%
Simple interest = Principal x Rate of interest
= $5,000 x (7/100)
= $350
Simple interest at 7% is $350 for a principal of $5,000

Question 6.
Simple interest at 1% is how much for a principal of $10,000?
Answer:
Principal = $10,000
Rate of interest = 1%
Simple interest = Principal x Rate of interest
= $10,000 x (1/100)
= $100
Simple interest at 1% is $100 for a principal of $10,000.

Question 7.
If you have a principal of $4,000 and earn simple interest of 5% for one year, how much will you have at the end of the year?
Answer:
Principal = $4,000
Rate of interest = 5%
Simple interest = Principal x Rate of interest
= $4,000 x (5/100)
= $200
Simple interest for the year is equal to $200.
Principal + simple interest = $4,000 + $200 = $4,200
I will have $4,200 at the end of the year.

Question 8.
How much will you earn in a year on $150 if the simple interest is paid at a rate of 11%?
Answer:
Principal = $150
Rate of interest = 11%
Simple interest = Principal x Rate of interest
= $150 x (11/100)
= $16.50
I will earn $16.50 in a year on $150 if the simple interest is paid at a rate of 11%.

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McGraw Hill Math Grade 7 Lesson 15.4 Answer Key Multiplying Percents and Fractions

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McGraw-Hill Math Grade 7 Answer Key Lesson 15.4 Multiplying Percents and Fractions

Exercises

MULTIPLY

Question 1.
\(\frac{1}{2}\) of 40% = _________________
Answer:
40% = \(\frac{40}{100}\)
\(\frac{1}{2}\) x \(\frac{40}{100}\)
= \(\frac{40}{200}\)
= \(\frac{20}{100}\)
= 20%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{1}{2}\) of 40% is equal to 20%.

Question 2.
\(\frac{2}{3}\) of 60% = _________________
Answer:
60% = \(\frac{60}{100}\)
\(\frac{2}{3}\) x \(\frac{60}{100}\)
= \(\frac{120}{300}\)
= \(\frac{40}{100}\)
= 40%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{2}{3}\) of 60% is equal to 40%.

Question 3.
50% of 18 = _______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
50% = \(\frac{50}{100}\) = \(\frac{1}{2}\)
Multiply \(\frac{1}{2}\) with 18 the product is equal to 9.
\(\frac{1}{2}\) x 18 = 9
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 50% of 18 is equal to 9.

Question 4.
12% of 400 = _______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
12% = \(\frac{12}{100}\) = \(\frac{3}{25}\)
Multiply \(\frac{3}{25}\) with 400 the product is equal to 48.
\(\frac{3}{25}\) x 400 = 48
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 12% of 400 is equal to 48.

Question 5.
\(\frac{1}{4}\) of 8% = _________________
Answer:
8% = \(\frac{8}{100}\)
\(\frac{1}{4}\) x \(\frac{8}{100}\)
= \(\frac{8}{400}\)
= \(\frac{2}{100}\)
= 2%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{1}{4}\) of 8% is equal to 2%.

Question 6.
20% of 75 = ______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
20% = \(\frac{20}{100}\) = \(\frac{1}{5}\)
Multiply \(\frac{1}{5}\) with 75 the product is equal to 15.
\(\frac{1}{5}\) x 75 = 15
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 20% of 75 is equal to 15.

Question 7.
39% of 300 = ______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
39% = \(\frac{39}{100}\)
Multiply \(\frac{39}{100}\) with 300 the product is equal to 117.
\(\frac{39}{100}\) x 300 = 117
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 39% of 300 is equal to 117.

Question 8.
\(\frac{1}{9}\) of 45% = _________________
Answer:
45% = \(\frac{45}{100}\)
\(\frac{1}{9}\) x \(\frac{45}{100}\)
= \(\frac{45}{900}\)
= \(\frac{5}{100}\)
= 5%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{1}{9}\) of 45% is equal to 5%.

Question 9.
\(\frac{1}{3}\) of 90% = _________________
Answer:
90% = \(\frac{90}{100}\)
\(\frac{1}{3}\) x \(\frac{90}{100}\)
= \(\frac{90}{300}\)
= \(\frac{30}{100}\)
= 30%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{1}{3}\) of 90% is equal to 30%.

Question 10.
25% of 60 = _______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
25% = \(\frac{25}{100}\) = \(\frac{1}{4}\)
Multiply \(\frac{1}{4}\) with 60 the product is equal to 15.
\(\frac{1}{4}\) x 60 = 15
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 25% of 60 is equal to 15.

Question 11.
\(\frac{1}{3}\) of 27% = _________________
Answer:
27% = \(\frac{27}{100}\)
\(\frac{1}{3}\) x \(\frac{27}{100}\)
= \(\frac{27}{300}\)
= \(\frac{9}{100}\)
= 9%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{1}{3}\) of 27% is equal to 9%.

Question 12.
18% of 50 = ______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
18% = \(\frac{18}{100}\) = \(\frac{9}{50}\)
Multiply \(\frac{9}{50}\) with 50 the product is equal to 9.
\(\frac{9}{50}\) x 50= 9
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 18% of 50 is equal to 9.

Question 13.
120% of 35 = ______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
120% = \(\frac{120}{100}\) = \(\frac{6}{5}\)
Multiply \(\frac{6}{5}\) with 35 the product is equal to 42.
\(\frac{6}{5}\) x 35 = 42
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 120% of 35 is equal to 42.

Question 14.
100% of 37 = _______________
Answer:
A percentage is displayed as a fraction with a denominator of 100.
100% = \(\frac{100}{100}\) = 1
Multiply 1 with 37 the product is equal to 37.
1 x 37 = 37
Here we are finding a percentage of a fraction. So, the product will be in fraction form. So, 100% of 37 is equal to 37.

Question 15.
\(\frac{1}{4}\) of 36% = _________________
Answer:
36% = \(\frac{36}{100}\)
\(\frac{1}{4}\) x \(\frac{36}{100}\)
= \(\frac{36}{400}\)
= \(\frac{9}{100}\)
= 9%
Here we are multiplying a fraction by a percentage. So, the product will be a percentage form.  So, \(\frac{1}{4}\) of 36% is equal to 9%.

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McGraw Hill Math Grade 7 Lesson 15.3 Answer Key Percents and Decimals

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McGraw-Hill Math Grade 7 Answer Key Lesson 15.3 Percents and Decimals

Exercises

CONVERT

Convert the decimals to a percentage. If the number is already a percentage, convert it to a decimal.

Question 1.
7% = _______________
Answer:
7% = 7/100 = 0.07
Explanation:
A percentage is displayed as decimal with a denominator of 100. Here 7% in decimal form as 0.07.

Question 2.
18.5% = _______________
Answer:
18.5% = 18.5/100 = 0.185
Explanation:
A percentage is displayed as decimal with a denominator of 100. Here 18.5% in decimal form as 0.185.

Question 3.
.33 = _______________
Answer:
0.33 = 33%
Explanation:
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 0.33 in percentage form as 33%.

Question 4.
.675 = _______________
Answer:
0.675 = 67.5%
Explanation:
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 0.675 in percentage form as 67.5%.

Question 5.
.3356 = _______________
Answer:
0.3356 = 33.56%
Explanation:
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 0.3356 in percentage form as 33.56%.

Question 6.
.01 % = _______________
Answer:
0.01% = 0.01/100 = 0.0001
Explanation:
A percentage is displayed as decimal with a denominator of 100. Here 0.01% in decimal form as 0.0001.

Question 7.
2.34% = _______________
Answer:
2.34% = 2.34/100 = 0.0234
Explanation:
A percentage is displayed as decimal with a denominator of 100. Here 2.34% in decimal form as 0.0234.

Question 8.
3.45 = _______________
Answer:
3.45 = 345%
Explanation:
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 3.45 in percentage form as 345%.

Question 9.
2.145 = _______________
Answer:
2.145 = 214.5%
Explanation:
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 2.145 in percentage form as 214.5%.

Question 10.
.3% = _______________
Answer:
0.3% = 0.3/100 = 0.003
Explanation:
A percentage is displayed as decimal with a denominator of 100. Here 0.3% in decimal form as 0.003.

Question 11.
33.29% = _______________
Answer:
33.29% = 0.3329
Explanation:
A percentage is displayed as decimal with a denominator of 100. Here 33.29% in decimal form as 0.3329.

Question 12.
2456 = _______________
Answer:
2456.00 = 245600%
Explanation:
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 2456.00 in percentage form as 245600%.

Question 13.
Taylor divided 6 shares of XYZ Corporation among 7 of her cousins. Each cousin received .8571 shares of XYZ stock. What percentage of a whole share did each cousin receive?
Answer:
Taylor divided 6 shares of XYZ Corporation among 7 of her cousins.
Each cousin received .8571 shares of XYZ stock.
0.8571 = 85.71%
To convert decimals into percentages we need to move the decimal two places to the right. Then add a percent sign. The decimal 0.8571 in percentage form as 85.71%.
Each cousin received 85.71% of a whole share.

Question 14.
Bill wants to take 15.43% of his earnings this year and put his money in his savings account. If Bill earned $100 this year, how much money will he put into his savings account?
Answer:
Bill wants to take 15.43% of his earnings this year and put his money in his savings account.
Bill earned $100 in this year.
15.43% x $100 = 0.1543 x $100 = $15.43
Bill will put $15.43 into his savings account.

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McGraw Hill Math Grade 7 Lesson 15.2 Answer Key Percents and Fractions

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McGraw-Hill Math Grade 7 Answer Key Lesson 15.2 Percents and Fractions

Exercises

CONVERT

Convert the fractions to a simple percentage, or state that the fraction cannot be converted to a simple percentage.

Question 1.
\(\frac{1}{2}\) = ________________
Answer:
\(\frac{1}{2}\) = ?%
\(\frac{100}{2}\) = 50
1 x 50 = 50
\(\frac{1}{2}\) = 50%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 2 is evenly divided into 100. Divide 100 by 2 the quotient is equal to 50. Multiply the numerator 1 with the quotient 50 the product is equal to 50. Now add the percent sign. So\(\frac{1}{2}\) is equal to 50%.

Question 2.
\(\frac{3}{20}\) = ________________
Answer:
\(\frac{3}{20}\) = ?%
\(\frac{100}{20}\) = 5
3 x 5 = 15
\(\frac{3}{20}\) = 15%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 20 is evenly divided into 100. Divide 100 by 20 the quotient is equal to 5. Multiply the numerator 3 with the quotient 5 the product is equal to 15. Now add the percent sign. So\(\frac{3}{20}\) is equal to 15%.

Question 3.
\(\frac{7}{15}\) = ________________
Answer:
\(\frac{7}{15}\) = ?%
\(\frac{100}{15}\) = 6.66
7 x 6.66 = 46.7
\(\frac{7}{15}\) = 46.7%
Explanation:
The given fraction cannot be converted into simple percentage. Here the denominator of the given fraction 15 is not evenly divided into 100. Divide 100 by 15 the quotient is equal to 6.66. Multiply the numerator 7 with the quotient 6.66 the product is equal to 46.7. Now add the percent sign. So\(\frac{7}{15}\) is equal to 46.7%.

Question 4.
\(\frac{3}{10}\) = ________________
Answer:
\(\frac{3}{10}\) = ?%
\(\frac{100}{10}\) = 10
3 x 10= 30
\(\frac{3}{10}\) = 30%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 10 is evenly divided into 100. Divide 100 by 10 the quotient is equal to 10. Multiply the numerator 3 with the quotient 10 the product is equal to 30. Now add the percent sign. So\(\frac{3}{10}\) is equal to 30%.

Question 5.
\(\frac{2}{3}\) = ________________
Answer:
\(\frac{2}{3}\) = ?%
\(\frac{100}{3}\) = 33.3
2 x 33.3 = 66.6
\(\frac{2}{3}\) = 66.6%
Explanation:
The given fraction cannot be converted into simple percentage. Here the denominator of the given fraction 3 is not evenly divided into 100. Divide 100 by 3 the quotient is equal to 33.3. Multiply the numerator 2 with the quotient 33.3. the product is equal to 66.6. Now add the percent sign. So\(\frac{2}{3}\) is equal to 66.6%.

Question 6.
\(\frac{3}{4}\) = ________________
Answer:
\(\frac{3}{4}\) = ?%
\(\frac{100}{4}\) = 25
3 x 25 = 75
\(\frac{3}{4}\) = 75%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 4 is evenly divided into 100. Divide 100 by 4 the quotient is equal to 25. Multiply the numerator 3 with the quotient 25 the product is equal to 75. Now add the percent sign. So\(\frac{3}{4}\) is equal to 75%.

Question 7.
\(\frac{6}{11}\) = ________________
Answer:
\(\frac{6}{11}\) = ?%
\(\frac{100}{11}\) = 9.09
6 x 9.09 = 54.5
\(\frac{6}{11}\) = 54.5%
Explanation:
The given fraction cannot be converted into simple percentage. Here the denominator of the given fraction 11 is not evenly divided into 100. Divide 100 by 11 the quotient is equal to 9.09. Multiply the numerator 6 with the quotient 9.09 the product is equal to 54.5. Now add the percent sign. So\(\frac{6}{11}\) is equal to 54.5%.

Question 8.
1 = ________________
Answer:
\(\frac{1}{1}\) = ?%
\(\frac{100}{1}\) = 100
1 x 100 = 100
\(\frac{1}{1}\) = 100%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 1 is evenly divided into 100. Divide 100 by 1 the quotient is equal to 100. Multiply the numerator 1 with the quotient 100 the product is equal to 100. Now add the percent sign. So\(\frac{1}{1}\) is equal to 100%.

Question 9.
\(\frac{1}{32}\) = ________________
Answer:
\(\frac{1}{32}\) = ?%
\(\frac{100}{32}\) = 3.1
1 x 3.1 = 3.1
\(\frac{1}{32}\) = 3.1%
Explanation:
The given fraction cannot be converted into simple percentage. Here the denominator of the given fraction 32 is not evenly divided into 100. Divide 100 by 32 the quotient is equal to 3.1. Multiply the numerator 1 with the quotient 3.1 the product is equal to 3.1. Now add the percent sign. So\(\frac{1}{32}\) is equal to 3.1%.

Question 10.
\(\frac{4}{25}\) = ________________
Answer:
\(\frac{4}{25}\) = ?%
\(\frac{100}{25}\) = 4
4 x 4 = 16
\(\frac{4}{25}\) = 16%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 25 is evenly divided into 100. Divide 100 by 25 the quotient is equal to 4. Multiply the numerator 4 with the quotient 4 the product is equal to 16. Now add the percent sign. So\(\frac{4}{25}\) is equal to 16%.

Question 11.
\(\frac{19}{50}\) = ________________
Answer:
\(\frac{19}{50}\) = ?%
\(\frac{100}{50}\) = 2
19 x 2 = 38
\(\frac{19}{50}\) = 38%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 50 is evenly divided into 100. Divide 100 by 50 the quotient is equal to 2. Multiply the numerator 19 with the quotient 2 the product is equal to 38. Now add the percent sign. So\(\frac{19}{50}\) is equal to 38%.

Question 12.
\(\frac{3}{50}\) = ________________
Answer:
\(\frac{3}{50}\) = ?%
\(\frac{100}{50}\) = 2
3 x 2 = 6
\(\frac{3}{50}\) = 6%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 50 is evenly divided into 100. Divide 100 by 50 the quotient is equal to 2. Multiply the numerator 3 with the quotient 2 the product is equal to 6. Now add the percent sign. So\(\frac{3}{50}\) is equal to 6%.

Question 13.
\(\frac{14}{10}\) = ________________
Answer:
\(\frac{14}{10}\) = ?%
\(\frac{100}{10}\) = 10
14 x 10 = 140
\(\frac{14}{10}\) = 140%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 10 is evenly divided into 100. Divide 100 by 10 the quotient is equal to 10. Multiply the numerator 14 with the quotient 10 the product is equal to 140. Now add the percent sign. So\(\frac{14}{10}\) is equal to 140%.

Question 14.
\(\frac{11}{20}\) = ________________
Answer:
\(\frac{11}{20}\) = ?%
\(\frac{100}{20}\) = 5
11 x 5 = 55
\(\frac{11}{20}\) = 55%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 20 is evenly divided into 100. Divide 100 by 20 the quotient is equal to 5. Multiply the numerator 11 with the quotient 5 the product is equal to 55. Now add the percent sign. So\(\frac{11}{20}\) is equal to 55%.

Question 15.
\(\frac{3}{25}\) = ________________
Answer:
\(\frac{3}{25}\) = ?%
\(\frac{100}{25}\) = 4
3 x 4 = 12
\(\frac{3}{25}\) = 12%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 25 is evenly divided into 100. Divide 100 by 25 the quotient is equal to 4. Multiply the numerator 3 with the quotient 4 the product is equal to 12. Now add the percent sign. So\(\frac{3}{25}\) is equal to 12%.

Question 16.
\(\frac{4}{9}\) = ________________
Answer:
\(\frac{4}{9}\) = ?%
\(\frac{100}{9}\) = 11.11
4 x 11.11 = 44.4
\(\frac{4}{9}\) = 44.4%
Explanation:
The given fraction cannot be converted into simple percentage. Here the denominator of the given fraction 9 is not evenly divided into 100. Divide 100 by 9 the quotient is equal to 11.11. Multiply the numerator 4 with the quotient 11.11 the product is equal to 44.4. Now add the percent sign. So\(\frac{4}{9}\) is equal to 44.4%.

Question 17.
\(\frac{7}{20}\) = ________________
Answer:
\(\frac{7}{20}\) = ?%
\(\frac{100}{20}\) = 5
7 x 5 = 35
\(\frac{7}{20}\) = 35%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 20 is evenly divided into 100. Divide 100 by 20 the quotient is equal to 5. Multiply the numerator 7 with the quotient 5 the product is equal to 35. Now add the percent sign. So\(\frac{7}{20}\) is equal to 35%.

Question 18.
200 = ______________
Answer:
\(\frac{200}{1}\) = ?%
\(\frac{100}{1}\) = 100
200 x 100 = 20000
\(\frac{200}{1}\) = 20000%
Explanation:
The given fraction can be converted into simple percentage. Here the denominator of the given fraction 1 is evenly divided into 100. Divide 100 by 1 the quotient is equal to 100. Multiply the numerator 200 with the quotient 100 the product is equal to 20000. Now add the percent sign. So\(\frac{200}{1}\) is equal to 20000%.

McGraw Hill Math Grade 7 Lesson 15.2 Answer Key Percents and Fractions Read More »

McGraw Hill Math Grade 7 Lesson 12.4 Answer Key Dividing Money

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 12.4 Dividing Money existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money

Exercises Divide

Round to the nearest cent.

Question 1.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 1
Answer:
$15÷$3 = $5.

Explanation:
The quotient of $15÷$3 is $5 and the nearest cent is $5.0.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 1-1

Question 2.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 2
Answer:
$56÷$5 is $11.20.

Explanation:
The quotient of $56÷$5 is $11.2 and the nearest cent is $11.20.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 2-1

Question 3.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 3
Answer:
$89÷$3.25 = $27.38.

Explanation:
The quotient of $89÷$3.25 is $27.384 and the nearest cent is $27.38.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 3-1

Question 4.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 4
Answer:
$10÷2.3 = $4.347.

Explanation:
The quotient of $10÷2.3 is $4.347 and the nearest cent is $4.35.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 4-1

Question 5.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 5
Answer:
$4.25÷5.5 = $0.772.

Explanation:
The quotient of $4.25÷5.5 is $0.772 and the nearest cent is $0.77.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 5-1

Question 6.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 6
Answer:
$25.25÷$4.50 is $5.611.

Explanation:
The quotient of $25.25÷$4.50 is $5.611 and the nearest cent is $5.61.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 6-1

Question 7.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 7
Answer:
$78.89÷2.1 is $37.566.

Explanation:
The quotient of $78.89÷2.1 is $37.566 and the nearest cent is $37.57.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 7-1

Question 8.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 8
Answer:
$42.50÷$8.25 = $5.151.

Explanation:
The quotient of $42.50÷$8.25 is $5.151 and the nearest cent is $5.15.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 8-1

Question 9.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 9
Answer:
$45.45÷5.5 is $8.263.

Explanation:
The quotient of $45.45÷5.5 is $8.263 and the nearest cent is $8.26.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 9-1

Question 10.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 10
Answer:
$5.01÷$2.33 is $2.150.

Explanation:
The quotient of $5.01÷$2.33 is $2.150 and the nearest cent is $2.15.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 10-1

Question 11.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 11
Answer:

Explanation:
The quotient of $15÷$3 is $5 and the nearest cent is
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 11-1

Question 12.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 12
Answer:
$9800.12÷10.2 = $960.796.

Explanation:
The quotient of $9800.12÷10.2 is $960.796 and the nearest cent is $960.80.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 12-1

Question 13.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 13
Answer:
$96.65÷$5.55 = $17.414.

Explanation:
The quotient of $96.65÷$5.55 is $17.414 and the nearest cent is $17.41.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 13-1

Question 14.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 14
Answer:
$45.12÷$6.51 is $6.930.

Explanation:
The quotient of $45.12÷$6.51 is $6.930 and the nearest cent is $6.93.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 14-1

Question 15.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 15
Answer:
$99.50÷$7.55 = $13.178.

Explanation:
The quotient of $99.50÷$7.55 is $13.178 and the nearest cent is $13.18.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 15-1

Question 16.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.4 Answer Key Dividing Money 16
Answer:
$8.88÷4.1 is $2.165.

Explanation:
The quotient of $8.88÷4.1 is $2.165 and the nearest cent is $2.17.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.4 Dividing Money 16-1

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McGraw Hill Math Grade 7 Lesson 12.3 Answer Key Dividing Decimals by Decimals

Excel in your academics by accessing McGraw Hill Math Grade 7 Answer Key PDF Lesson 12.3 Dividing Decimals by Decimals existing for free of cost.

McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals

Exercises Divide

Round to the nearest ten-thousandth.

Question 1.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 1
Answer:
11.2÷-4.5 = -002.488.

Explanation:
The quotient of 11.2÷-4.5 is -002.488, so the nearest ten thousand will be -2.4889.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 1-1

Question 2.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 2
Answer:
5.7÷2.5 is 2.28000.

Explanation:
The quotient of 5.7÷2.5 is 2.28000, so the nearest ten thousand will be 2.2800.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 2-1

Question 3.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 3
Answer:
88.3÷8.1 = 10.90123.

Explanation:
The quotient of 88.3÷8.1 is 10.90123, so the nearest ten thousand will be 10.9012.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 3-1

Question 4.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 4
Answer:
4.5÷2.1 = 02.14285.

Explanation:
The quotient of 4.5÷2.1 is 02.14285, so the nearest ten thousand will be 2.1429.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 4-1

Question 5.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 5
Answer:
5.98÷7.88 is 0.75888.

Explanation:
The quotient of 5.98÷7.88 is 0.75888, so the nearest ten thousand will be 0.7589.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 5-1

Question 6.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 6
Answer:
17.1÷2.33 is 7.33905.

Explanation:
The quotient of 17.1÷2.33 is 7.33905, so the nearest ten thousand will be 7.3390.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 6-1

Question 7.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 7
Answer:
8.56÷-2.3 = -3.72173.

Explanation:
The quotient of 8.56÷-2.3 is -3.72173, so the nearest ten thousand will be -3.7217.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 7-1

Question 8.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 8
Answer:
5.12÷2.222 = 02.30423.

Explanation:
The quotient of 5.12÷2.222 is 02.30423, so the nearest ten thousand will be 02.3042.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 8-1

Question 9.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 9
Answer:
4.6÷3.41 = 01.34897.

Explanation:
The quotient of 4.6÷3.41 is 01.34897, so the nearest ten thousand will be 1.3490.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 9-1

Question 10.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 10
Answer:
6.54÷-2.11 is -3.09952.

Explanation:
The quotient of 6.54÷-2.11 is -3.09952, so the nearest ten thousand will be -3.0995.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 10-1

Question 11.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 11
Answer:
6.01÷2.37 = 02.53586.

Explanation:
The quotient of 6.01÷2.37 is 02.53586, so the nearest ten thousand will be 02.5359.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 11-1

Question 12.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 12
Answer:
6.44÷5.55 = 1.16036.

Explanation:
The quotient of 6.44÷5.55 is 1.16036, so the nearest ten thousand will be 1.1603.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 12-1

Question 13.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 13
Answer:
9.1÷3.03 is 3.00330.

Explanation:
The quotient of 9.1÷3.03 is 3.00330, so the nearest ten thousand will be 3.0033.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 13-1

Question 14.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 14
Answer:
987.1÷2.1 is 470.04761.

Explanation:
The quotient of 987.1÷2.1 is 470.04761, so the nearest ten thousand will be 470.0476.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 14-1

Question 15.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 15
Answer:
8.89÷3.71 = 2.39622.

Explanation:
The quotient of 8.89÷3.71 is 2.39622, so the nearest ten thousand will be 2.3962.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 15-1

Question 16.
McGraw Hill Math Grade 7 Chapter 12 Lesson 12.3 Answer Key Dividing Decimals by Decimals 16
Answer:
56.98÷-2.45 = -23.25714.

Explanation:
The quotient of 56.98÷-2.45 is -23.25714, so the nearest ten thousand will be -23.2571.
McGraw-Hill Math Grade 7 Answer Key Lesson 12.3 Dividing Decimals by Decimals 16-1

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McGraw Hill Math Grade 8 Lesson 4.4 Answer Key Multiplying Mixed Numbers

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 4.4 Multiplying Mixed Numbers to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 4.4 Multiplying Mixed Numbers

Exercises Multiply

Question 1.
5\(\frac{1}{2}\) × 3\(\frac{3}{4}\)
Answer:
20\(\frac{5}{8}\),

Explanation:
We have 5\(\frac{1}{2}\) X 3\(\frac{3}{4}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{5 X 2  +  1}{2}\) = \(\frac{11}{2}\) and
3\(\frac{3}{4}\) = \(\frac{3 X 4 + 3}{4}\) = \(\frac{15}{4}\),
Step 2:
Multiplying the fractions as \(\frac{11}{2}\) X \(\frac{15}{4}\) = \(\frac{11 X 15}{2 X 4}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{165}{8}\) = \(\frac{20 X 8 + 5}{8}\) = 20\(\frac{5}{8}\).

Question 2.
2\(\frac{1}{3}\) × 2\(\frac{4}{5}\)
Answer:
6\(\frac{8}{15}\),

Explanation:
We have 2\(\frac{1}{3}\) X 2\(\frac{4}{5}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{6 X 3  +  1}{3}\) = \(\frac{2 X 5 + 4}{5}\),
Step 2:
Multiplying the fractions as \(\frac{7}{3}\) X \(\frac{14}{5}\) =
\(\frac{7 X 14}{3  X  5}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{98}{15}\) = \(\frac{15 X 6 + 8}{15}\) = 6\(\frac{8}{15}\).

Question 3.
8\(\frac{1}{5}\) × 3\(\frac{1}{7}\)
Answer:
25\(\frac{27}{35}\),

Explanation:
We have 8\(\frac{1}{5}\) X 3\(\frac{1}{7}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{8 X 5  +  1}{5}\) = \(\frac{41}{5}\) and
3\(\frac{1}{7}\) = \(\frac{3 X 7 + 1}{7}\) = \(\frac{22}{7}\),
Step 2:
Multiplying the fractions as \(\frac{41}{5}\) X \(\frac{22}{7}\) =
\(\frac{41 X 22}{5  X  7}\) = \(\frac{902}{35}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{902}{35}\) = \(\frac{25 X 35 + 27}{35}\) = 25\(\frac{27}{35}\).

Question 4.
1\(\frac{3}{4}\) × 12\(\frac{1}{3}\)
Answer:
21\(\frac{7}{12}\),

Explanation:
We have 1\(\frac{3}{4}\) X 12\(\frac{1}{3}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{1 X 4 + 3}{4}\) = \(\frac{7}{4}\) and
12\(\frac{1}{3}\) = \(\frac{12 X 3 + 1}{3}\) = \(\frac{37}{3}\),
Step 2:
Multiplying the fractions as \(\frac{7}{4}\) X \(\frac{37}{3}\) =
\(\frac{7 X 37}{4  X  3}\) = \(\frac{259}{12}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{259}{12}\) = \(\frac{21 X 12 + 7}{12}\) = 21\(\frac{7}{12}\).

Question 5.
2\(\frac{1}{2}\) × 4\(\frac{2}{3}\)
Answer:
11\(\frac{2}{3}\),

Explanation:
We have 2\(\frac{1}{2}\) X 4\(\frac{2}{3}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{2 X 2 + 1}{2}\) = \(\frac{5}{2}\) and
4\(\frac{2}{3}\) = \(\frac{4 X 3 + 2}{3}\) = \(\frac{14}{3}\),
Step 2:
Multiplying the fractions as \(\frac{5}{2}\) X \(\frac{14}{3}\) =
\(\frac{5 X 14}{2 X 3}\) = \(\frac{70}{6}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{70}{6}\) = \(\frac{35}{3}\) = 11\(\frac{2}{3}\).

Question 6.
3\(\frac{1}{8}\) × 3\(\frac{1}{7}\)
Answer:
9\(\frac{23}{28}\),

Explanation:
We have 3\(\frac{1}{8}\) X 3\(\frac{1}{7}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 8 + 1}{8}\) = \(\frac{25}{8}\) and
3\(\frac{1}{7}\) = \(\frac{3 X 7 + 1}{7}\) = \(\frac{22}{7}\),
Step 2:
Multiplying the fractions as \(\frac{25}{2}\) X \(\frac{22}{7}\) =
\(\frac{25 X 22}{8 X 7}\) = \(\frac{550}{56}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{550}{56}\) = \(\frac{275}{28}\) =
9\(\frac{23}{28}\).

Question 7.
11\(\frac{1}{5}\) × 6\(\frac{2}{3}\)
Answer:
74\(\frac{2}{3}\),

Explanation:
We have 11\(\frac{1}{5}\) X 6\(\frac{2}{3}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{11 X 5 + 1}{5}\) = \(\frac{56}{5}\) and
6\(\frac{2}{3}\) = \(\frac{6 X 3 + 2}{3}\) = \(\frac{20}{3}\),
Step 2:
Multiplying the fractions as \(\frac{56}{5}\) X \(\frac{20}{3}\) =
\(\frac{56 X 20}{5 X 3}\) = \(\frac{1,120}{15}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{1,120}{15}\) = \(\frac{56 X 5 X 4}{5 X 3}\) = \(\frac{224}{3}\) = 74\(\frac{2}{3}\).

Question 8.
9\(\frac{1}{2}\) × 5\(\frac{1}{5}\)
Answer:
49\(\frac{2}{5}\),

Explanation:
We have 9\(\frac{1}{2}\) X 5\(\frac{1}{5}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{9 X 2 + 1}{2}\) = \(\frac{19}{2}\) and
5\(\frac{1}{5}\) = \(\frac{5 X 5 + 1}{5}\) = \(\frac{26}{5}\),
Step 2:
Multiplying the fractions as \(\frac{19}{2}\) X \(\frac{26}{5}\) =
\(\frac{19 X 26}{2 X 5}\) = \(\frac{494}{10}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{494}{10}\) = \(\frac{247 X 2}{5 X 2}\) = \(\frac{247}{5}\) = 49\(\frac{2}{5}\).

Question 9.
1\(\frac{2}{3}\) × 7\(\frac{1}{5}\)
Answer:
12,

Explanation:
We have 1\(\frac{2}{3}\) X 7\(\frac{1}{5}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{1 X 3 + 2}{3}\) = \(\frac{5}{3}\) and
7\(\frac{1}{5}\) = \(\frac{7 X 5 + 1}{5}\) = \(\frac{36}{5}\),
Step 2:
Multiplying the fractions as \(\frac{5}{3}\) X \(\frac{36}{5}\) =
\(\frac{5 X 36}{3 X 5}\) = \(\frac{180}{15}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{180}{15}\) = \(\frac{15 X 12 }{15}\)= 12.

Question 10.
8\(\frac{3}{4}\) × 3\(\frac{1}{2}\)
Answer:
23\(\frac{5}{8}\),

Explanation:
We have 8\(\frac{3}{4}\) X 3\(\frac{1}{2}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{8 X 4 + 3}{4}\) = \(\frac{27}{4}\) and
3\(\frac{1}{2}\) = \(\frac{3 X 2 + 1}{2}\) = \(\frac{7}{2}\),
Step 2:
Multiplying the fractions as \(\frac{27}{4}\) X \(\frac{7}{2}\) =
\(\frac{27 X 7}{4 X 2}\) = \(\frac{189}{8}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{189}{8}\) = \(\frac{23 X 8 + 5}{8}\) = 23\(\frac{5}{8}\).

Question 11.
3\(\frac{5}{8}\) × 5\(\frac{1}{4}\)
Answer:
19\(\frac{1}{32}\),

Explanation:
We have 3\(\frac{5}{8}\) X 5\(\frac{1}{4}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 8 + 5}{8}\) = \(\frac{29}{8}\) and
5\(\frac{1}{4}\) = \(\frac{5 X 4 + 1}{4}\) = \(\frac{21}{4}\),
Step 2:
Multiplying the fractions as \(\frac{29}{8}\) X \(\frac{21}{4}\) = \(\frac{29 X 21}{8 X 4}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{609}{32}\) = \(\frac{19 X 32 + 1}{32}\) = 19\(\frac{1}{32}\).

Question 12.
4\(\frac{2}{3}\) × 4\(\frac{1}{2}\)
Answer:
21,

Explanation:
We have 4\(\frac{2}{3}\) X 4\(\frac{1}{2}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{4 X 3 + 2}{3}\) = \(\frac{14}{3}\) and
4\(\frac{1}{2}\) = \(\frac{4 X 2 + 1}{2}\) = \(\frac{9}{2}\),
Step 2:
Multiplying the fractions as \(\frac{14}{3}\) X \(\frac{9}{2}\) = \(\frac{14 X 9}{3 X 2}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{126}{6}\) = 21.

Question 13.
3\(\frac{1}{5}\) × 2\(\frac{1}{10}\)
Answer:
6\(\frac{18}{25}\),

Explanation:
We have 3\(\frac{1}{5}\) X 2\(\frac{1}{10}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 5 + 1}{5}\) = \(\frac{16}{5}\) and
2\(\frac{1}{10}\) = \(\frac{2 X 10 + 1}{10}\) = \(\frac{21}{10}\),
Step 2:
Multiplying the fractions as \(\frac{16}{5}\) X \(\frac{21}{10}\) = \(\frac{16 X 21}{5 X 10}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{336}{50}\) = \(\frac{2 X 168}{2 X 25}\) = \(\frac{168}{25}\) = 6\(\frac{18}{25}\).

Question 14.
10\(\frac{4}{5}\) × 2\(\frac{1}{11}\)
Answer:
22\(\frac{32}{55}\),

Explanation:
We have 10\(\frac{4}{5}\) X 2\(\frac{1}{11}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{10 X 5 + 4}{5}\) = \(\frac{54}{5}\) and
2\(\frac{1}{11}\) = \(\frac{2 X 11 + 1}{11}\) = \(\frac{23}{11}\),
Step 2:
Multiplying the fractions as \(\frac{54}{5}\) X \(\frac{23}{11}\) = \(\frac{1,242}{55}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{1,242}{55}\) = \(\frac{22 X 55 + 32}{55}\) = 22\(\frac{32}{55}\).

Question 15.
22\(\frac{5}{9}\) × 1\(\frac{3}{5}\)
Answer:
36\(\frac{4}{45}\),

Explanation:
We have 22\(\frac{5}{9}\) X 1\(\frac{3}{5}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{22 X 9 + 5}{9}\) = \(\frac{203}{9}\) and
1\(\frac{3}{5}\) = \(\frac{1 X 5 + 3}{5}\) = \(\frac{8}{5}\),
Step 2:
Multiplying the fractions as \(\frac{203}{9}\) X \(\frac{8}{5}\) = \(\frac{203 X 8}{9 X 5}\) = \(\frac{1,624}{45}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{1,624}{45}\) = \(\frac{1,624}{45}\) = \(\frac{36 X 45 + 4}{45}\) = 36\(\frac{4}{45}\).

Question 16.
14\(\frac{3}{4}\) × 2\(\frac{5}{7}\)
Answer:
40\(\frac{1}{28}\),

Explanation:
We have 14\(\frac{3}{4}\) X 2\(\frac{5}{7}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{14 X 4 + 3}{4}\) = \(\frac{59}{4}\) and
2\(\frac{5}{7}\) = \(\frac{2 X 7 + 5}{7}\) = \(\frac{19}{7}\),
Step 2:
Multiplying the fractions as \(\frac{59}{4}\) X \(\frac{19}{7}\) = \(\frac{59 X 19}{4 X 7}\) = \(\frac{1,121}{28}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{1,121}{28}\) = \(\frac{40 X 28 + 1}{28}\) = 40\(\frac{1}{28}\).

McGraw Hill Math Grade 8 Lesson 4.4 Answer Key Multiplying Mixed Numbers Read More »

McGraw Hill Math Grade 8 Lesson 4.3 Answer Key Multiplying Fractions and Mixed Numbers

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 4.3 Multiplying Fractions and Mixed Numbers to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 4.3 Multiplying Fractions and Mixed Numbers

Exercises Multiply

Question 1.
6\(\frac{3}{4}\) × \(\frac{1}{9}\)
Answer:
\(\frac{3}{4}\),

Explanation:
We have 6\(\frac{3}{4}\) X \(\frac{1}{9}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{6 X 4  +  3}{4}\) = \(\frac{27}{4}\),
Step 2:
Multiplying the fractions as \(\frac{27}{4}\) X \(\frac{1}{9}\) = \(\frac{27 X 1}{4  X  9}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{27}{36}\) = \(\frac{9 X 3}{9 X 4}\) = \(\frac{3}{4}\).

Question 2.
\(\frac{1}{10}\) × 4\(\frac{1}{6}\)
Answer:
\(\frac{5}{12}\),

Explanation:
We have \(\frac{1}{10}\) X 4\(\frac{1}{6}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{4 X 6  +  1}{6}\) = \(\frac{25}{6}\),
Step 2:
Multiplying the fractions as \(\frac{1}{10}\) X \(\frac{25}{6}\) = \(\frac{1 X 25}{10 X  6}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{25}{60}\) = \(\frac{5 X 5}{5 X 2 X 6}\) = \(\frac{5}{12}\).

Question 3.
12\(\frac{1}{4}\) × \(\frac{2}{7}\)
Answer:
14,

Explanation:
We have 12\(\frac{1}{4}\) X \(\frac{2}{7}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{12 X 4  +  1}{4}\) = \(\frac{49}{4}\),
Step 2:
Multiplying the fractions as \(\frac{49}{4}\) X \(\frac{2}{7}\) = \(\frac{49 X 4}{2 X 7}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{7 X 7 X 2 X 2}{2 X 7}\) = 7 X 2 = 14.

Question 4.
3\(\frac{1}{7}\) × \(\frac{14}{11}\)
Answer:
4,

Explanation:
We have 3\(\frac{1}{7}\) X \(\frac{14}{11}\),
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 7  +  1}{7}\) = \(\frac{22}{7}\),
Step 2:
Multiplying the fractions as \(\frac{22}{7}\) X \(\frac{14}{11}\) = \(\frac{22 X 14}{7 X  11}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{308}{77}\) = \(\frac{4 X 11 X 7}{7 X 11}\) = 4.

Question 5.
\(\frac{2}{5}\) × 3\(\frac{3}{4}\)
Answer:
\(\frac{3}{2}\),

Explanation:
We have \(\frac{2}{5}\) X 3\(\frac{3}{4}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 4  +  3}{4}\) = \(\frac{15}{4}\),
Step 2:
Multiplying the fractions as \(\frac{2}{5}\) X \(\frac{15}{4}\) = \(\frac{2 X 15}{ X  11}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{308}{77}\) = \(\frac{4 X 11 X 7}{7 X 11}\) = 4.

Question 6.
4\(\frac{5}{7}\) × \(\frac{7}{11}\)
Answer:
3,

Explanation:
We have 4\(\frac{5}{7}\) X \(\frac{7}{11}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{4 X 7  +  5}{7}\) = \(\frac{33}{7}\),
Step 2:
Multiplying the fractions as \(\frac{33}{7}\) X \(\frac{7}{11}\) = \(\frac{221}{77}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{221}{77}\) = \(\frac{3 X 11 X 7}{7 X 11}\) = 3.

Question 7.
4\(\frac{2}{5}\) × \(\frac{3}{11}\)
Answer:
\(\frac{6}{5}\) = 1\(\frac{1}{5}\),

Explanation:
We have 4\(\frac{2}{5}\) X \(\frac{3}{11}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{4 X 5  + 2}{5}\) = \(\frac{22}{5}\),
Step 2:
Multiplying the fractions as \(\frac{22}{5}\) X \(\frac{3}{11}\) = \(\frac{66}{55}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{66}{55}\) = \(\frac{6 X 11}{5 X 11}\) = \(\frac{6}{5}\)
as numerator is greater than denominator \(\frac{1 X 5 + 1}{5}\) = 1\(\frac{1}{5}\).

Question 8.
3\(\frac{1}{4}\) × \(\frac{4}{13}\)
Answer:
1,

Explanation:
We have 3\(\frac{1}{4}\) X \(\frac{4}{13}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 4  +  1}{4}\) = \(\frac{13}{4}\),
Step 2:
Multiplying the fractions as \(\frac{13}{4}\) X \(\frac{4}{13}\) = 3.

Question 9.
3\(\frac{3}{5}\) × \(\frac{10}{9}\)
Answer:
4,

Explanation:
We have 3\(\frac{3}{5}\) X \(\frac{10}{9}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 5  +  3}{5}\) = \(\frac{18}{5}\),
Step 2:
Multiplying the fractions as \(\frac{18}{5}\) X \(\frac{10}{9}\) = \(\frac{180}{45}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{180}{45}\) = \(\frac{45 X 4}{45}\) = 4.

Question 10.
\(\frac{3}{13}\) × 4\(\frac{1}{3}\)
Answer:
1,

Explanation:
We have \(\frac{3}{13}\) X 4\(\frac{1}{3}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{4 X 3  +  1}{3}\) = \(\frac{13}{3}\),
Step 2:
Multiplying the fractions as \(\frac{3}{13}\) X \(\frac{13}{3}\) = 1.

Question 11.
3\(\frac{2}{3}\) × \(\frac{2}{11}\)
Answer:
\(\frac{2}{3}\),

Explanation:
We have 3\(\frac{2}{3}\) X \(\frac{2}{11}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 3  +  2}{3}\) = \(\frac{11}{3}\),
Step 2:
Multiplying the fractions as \(\frac{11}{3}\) X \(\frac{2}{11}\) = \(\frac{22}{33}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{22}{33}\) = \(\frac{2 X 11}{3 X 11}\) = \(\frac{2}{3}\).

Question 12.
5\(\frac{1}{5}\) × \(\frac{3}{13}\)
Answer:
\(\frac{6}{5}\),

Explanation:
We have 5\(\frac{1}{5}\) X \(\frac{3}{13}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{5 X 5 + 1}{5}\) = \(\frac{26}{5}\),
Step 2:
Multiplying the fractions as \(\frac{26}{5}\) X \(\frac{3}{13}\) = \(\frac{78}{65}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{78}{65}\) = \(\frac{6 X 13}{5 X 13}\) =\(\frac{6}{5}\).

Question 13.
5\(\frac{1}{4}\) × \(\frac{1}{3}\)
Answer:
\(\frac{7}{4}\),

Explanation:
We have 5\(\frac{1}{4}\) X \(\frac{1}{3}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{5 X 4  +  1}{4}\) = \(\frac{21}{4}\),
Step 2:
Multiplying the fractions as \(\frac{26}{5}\) X \(\frac{3}{13}\) = \(\frac{78}{65}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{78}{65}\) = \(\frac{6 X 13}{5 X 13}\) =\(\frac{6}{5}\).

Question 14.
2\(\frac{4}{5}\) × \(\frac{2}{7}\)
Answer:
\(\frac{4}{5}\),

Explanation:
We have 2\(\frac{4}{5}\) X \(\frac{2}{7}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{2 X 5  + 4}{5}\) = \(\frac{14}{5}\),
Step 2:
Multiplying the fractions as \(\frac{14}{5}\) X \(\frac{2}{7}\) = \(\frac{28}{35}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{28}{35}\) = \(\frac{7 X 4}{7 X 5}\) =\(\frac{4}{5}\).

Question 15.
2\(\frac{1}{4}\) × \(\frac{3}{10}\)
Answer:
\(\frac{27}{40}\),

Explanation:
We have 2\(\frac{1}{4}\) X \(\frac{3}{10}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{2 X 4  +  1}{4}\) = \(\frac{9}{4}\),
Step 2:
Multiplying the fractions as \(\frac{9}{4}\) X \(\frac{3}{10}\) = \(\frac{27}{40}\) as numerator is smaller we cannot reduce further.

Question 16.
3\(\frac{1}{3}\) × \(\frac{3}{5}\)
Answer:
2,

Explanation:
We have 3\(\frac{1}{3}\) X \(\frac{3}{5}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{3 X 3 + 1}{3}\) = \(\frac{10}{3}\),
Step 2:
Multiplying the fractions as \(\frac{10}{3}\) X \(\frac{3}{5}\) = 2.

Question 17.
Thomas can walk on his hands 20\(\frac{2}{5}\) yards in a minute. How far can he go in \(\frac{3}{4}\) minutes?
Answer:
Thomas can walk 15\(\frac{3}{10}\) minutes,

Explanation:
As Thomas can walk on his hands 20\(\frac{2}{5}\) yards in a minute.
Far can he go in \(\frac{3}{4}\) minutes is 20\(\frac{2}{5}\) X \(\frac{3}{5}\)
Step 1:
Change the mixed number into improper fraction as
\(\frac{20 X 5  + 2}{5}\) = \(\frac{102}{15}\),
Step 2:
Multiplying the fractions as \(\frac{102}{15}\) X \(\frac{3}{5}\) = \(\frac{306}{75}\),
Step 3:
Convert the improper fraction to a mixed number and reduce
\(\frac{306}{75}\) = \(\frac{153}{10}\) = 15\(\frac{3}{10}\).
Therefore, Thomas can walk 15\(\frac{3}{10}\) minutes,

Question 18.
Peyton plays a round of golf in 3\(\frac{3}{8}\) hours. How long would it take him to play \(\frac{2}{3}\) rounds of golf?
Answer:
Peyton took 2\(\frac{1}{4}\) rounds of golf’s,

Explanation:
Given Peyton plays a round of golf in 3\(\frac{3}{8}\) hours. Long would it take him to play \(\frac{2}{3}\) rounds of golf is 3\(\frac{3}{8}\) X \(\frac{2}{3}\), So \(\frac{3 X 8 + 3}{8}\) X \(\frac{2}{3}\) = \(\frac{27}{8}\) X \(\frac{2}{3}\) = \(\frac{27 X 2}{8 X 3}\) = \(\frac{54}{24}\) both goes by 6 we get \(\frac{6 X 9}{6 X 4}\) = \(\frac{9}{4}\) =
as numerator is more than denominator \(\frac{2 X 4 + 1}{4}\) = 2\(\frac{1}{4}\). Peyton took 2\(\frac{1}{4}\) rounds of golf’s.

McGraw Hill Math Grade 8 Lesson 4.3 Answer Key Multiplying Fractions and Mixed Numbers Read More »

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