McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Unit Test Lessons 1–6 to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key

Solve.

Question 1.
Edie’s local newspaper has 4,476 pages of advertising each year. If the magazine is published once a week, about how many pages of advertising are in each issue? (Calculate using 52 weeks in a year.) How many pages exactly?
Answer:
90,86
Explanation:
4,476 pages of advertising each year
the magazine is published once a week and there are 52 weeks in a year
\(\frac{4476}{52}\)
= 86.0769
86 to 90 pages for each issue

Add or subtract.

Question 2.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 1
Answer:
41606
Explanation:
Start by lining up the number, to add by place value.
Add up each place value, starting in the ones place.
If the total of a place value has 2 digits,
write the second digit and carry the first digit to the next column.

Question 3.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 2
Answer:
236137
Explanation:
Start by lining up the number, to add by place value.
Add up each place value, starting in the ones place.
If the total of a place value has 2 digits,
write the second digit and carry the first digit to the next column.

Question 4.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 3
Answer:
1511691
Explanation:
Start by lining up the number, to add by place value.
Add up each place value, starting in the ones place.
If the total of a place value has 2 digits,
write the second digit and carry the first digit to the next column.

Question 5.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 4
Answer:
193
Explanation:
Line up the numbers according to their place values.
Subtract each value, starting from ones place.
Regroup the numbers and borrow one ten from the next place value.

Question 6.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 5
Answer:
1389
Explanation:
Line up the numbers according to their place values.
Subtract each value, starting from ones place.
Regroup the numbers and borrow one ten from the next place value.

Question 7.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 6
Answer:
120109
Explanation:
Line up the numbers according to their place values.
Subtract each value, starting from ones place.
Regroup the numbers and borrow one ten from the next place value.

Question 8.
McGraw Hill Math Grade 8 Unit Test Lessons 1–6 Answer Key 7
Answer:
91785
Explanation:
Line up the numbers according to their place values.
Subtract each value, starting from ones place.
Regroup the numbers and borrow one ten from the next place value.

Question 9.
\(\frac{31}{4}\) + \(\frac{3}{4}\)
Answer:
8\(\frac{1}{2}\)
Explanation:
\(\frac{31}{4}\) + \(\frac{3}{4}\)
As both the denominators are same,
numerators can be added directly.
\(\frac{31 + 3}{4}\)
= \(\frac{34}{4}\)
= 8\(\frac{1}{2}\)

Question 10.
\(\frac{19}{43}\) – \(\frac{13}{43}\)
Answer:
\(\frac{6}{43}\)
Explanation:
\(\frac{19}{43}\) – \(\frac{13}{43}\)
As both the denominators are same,
numerators can be added directly.
\(\frac{19 – 13}{4}\)
= \(\frac{6}{43}\)

Question 11.
4\(\frac{5}{11}\) + 5\(\frac{6}{11}\)
Answer:
10
Explanation:
4\(\frac{5}{11}\) + 5\(\frac{6}{11}\)
Convert the mixed fraction in to improper fraction.
\(\frac{49}{11}\) + \(\frac{61}{11}\)
As both the denominators are same,
numerators can be added directly.
\(\frac{49 + 61}{11}\)
= \(\frac{110}{11}\)
= 10

Question 12.
2\(\frac{23}{39}\) + \(\frac{24}{39}\)
Answer:
3\(\frac{8}{39}\)
Explanation:
2\(\frac{23}{39}\) + \(\frac{24}{39}\)
Convert the mixed fraction in to improper fraction.
\(\frac{101}{39}\) + \(\frac{24}{39}\)
As both the denominators are same,
numerators can be added directly.
\(\frac{101 + 24}{39}\)
= \(\frac{125}{39}\)
= 3\(\frac{8}{39}\)

Question 13.
\(\frac{12}{61}\) – \(\frac{3}{61}\)
Answer:
\(\frac{9}{61}\)
Explanation:
\(\frac{12}{61}\) – \(\frac{3}{61}\)
As both the denominators are same,
numerators can be subtracted directly.
\(\frac{12 – 3{61}\)
= \(\frac{9}{61}\)

Change each to a mixed number.

Question 14.
\(\frac{45}{7}\)
Answer:
6\(\frac{3}{7}\)
Explanation:

6\(\frac{3}{7}\)

Question 15.
\(\frac{66}{8}\)
Answer:
8\(\frac{1}{4}\)
Explanation:

= 8\(\frac{1}{4}\)

Question 16.
\(\frac{1}{2}\) × 44
Answer:
22
Explanation:
\(\frac{1}{2}\) × 44
\(\frac{44}{2}\)

Question 17.
\(\frac{1}{4}\) × 22
Answer:
5\(\frac{1}{2}\)
Explanation:
\(\frac{1}{4}\) × 22
\(\frac{22}{4}\)

= 5\(\frac{1}{2}\)

Question 18.
\(\frac{11}{18}\) × \(\frac{11}{22}\)
Answer:
\(\frac{11}{36}\)
Explanation:
\(\frac{11}{18}\) × \(\frac{11}{22}\)
= \(\frac{11 x 11}{18 x 22}\)
= \(\frac{11}{18 x 2}\)
= \(\frac{11}{36}\)

Question 19.
\(\frac{2}{3}\) × 4\(\frac{3}{5}\)
Answer:
3\(\frac{1}{15}\)
Explanation:
\(\frac{2}{3}\) × 4\(\frac{3}{5}\)
Convert the mixed fraction in to improper fraction.
= \(\frac{2}{3}\) × \(\frac{23}{5}\)
= \(\frac{2 x 23}{3 x 5}\)
= \(\frac{46}{15}\)
= 3\(\frac{1}{15}\)

Question 20.
18 × \(\frac{7}{9}\)
Answer:
14
Explanation:
18 × \(\frac{7}{9}\)
= \(\frac{18 x 7}{9}\)
= \(\frac{2 x 7}{1}\)
= 14

Question 21.
\(\frac{15}{29}\) ÷ 45
Answer:
\(\frac{1}{87}\)
Explanation:
\(\frac{15}{29}\) ÷ 45
= \(\frac{15}{45 x 29}\)
= \(\frac{1}{3 x 29}\)
= \(\frac{1}{87}\)

Question 22.
\(\frac{54}{47}\) ÷ 18
Answer:
\(\frac{3}{47}\)
Explanation:
= \(\frac{54}{47}\) ÷ 18
= \(\frac{54}{18 x 47}\)
= \(\frac{3}{47}\)

Question 23.
42 ÷ \(\frac{7}{3}\)
Answer:
18
Explanation:
42 ÷ \(\frac{7}{3}\)
= \(\frac{42 x 3}{7}\)
= 18

Question 24.
\(\frac{4}{27}\) ÷ 3
Answer:
\(\frac{4}{81}\)
Explanation:
\(\frac{4}{27}\) ÷ 3
= \(\frac{4}{3 x 27}\)
= \(\frac{4}{81}\)

Question 25.
\(\frac{75}{83}\) ÷ 15
Answer:
\(\frac{5}{83}\)
Explanation:
\(\frac{75}{83}\) ÷ 15
= \(\frac{75}{15 x 83}\)
= \(\frac{5}{83}\)

Determine if the following proportions are equal. (Write Yes or No.)

Question 26.
\(\frac{5}{4}\) = \(\frac{24}{26}\)
Answer:
No
Explanation:
\(\frac{5}{4}\) = \(\frac{24}{26}\)

Question 27.
\(\frac{21}{12}\) = \(\frac{7}{36}\)
Answer:
No
Explanation:
\(\frac{21 x 3}{12 x 3}\) = \(\frac{21}{36}\)
\(\frac{21}{12}\) is not equal to \(\frac{7}{36}\)

Question 28.
\(\frac{12}{19}\) = \(\frac{38}{48}\)
Answer:
No
Explanation:
\(\frac{12 x 3}{19 x 3} \) = \(\frac{36}{57}\)
\(\frac{12}{19}\) is not equal to \(\frac{38}{48}\)

Question 29.
\(\frac{1}{4}\) = \(\frac{6}{24}\)
Answer:
Yes
Explanation:
\(\frac{1}{4}\) = \(\frac{6}{24}\)
\(\frac{1 x 6}{4 x 6}\) = \(\frac{6}{24}\)
\(\frac{1}{4}\) = \(\frac{6}{24}\)
So, both the proportions equal.

Solve for x.

Question 30.
\(\frac{x}{10}\) = \(\frac{30}{20}\)
Answer:
x = 15
Explanation:
\(\frac{x}{10}\) = \(\frac{30}{20}\)
x = \(\frac{30 x 10}{20}\)
x = 15

Question 31.
\(\frac{20}{x}\) = \(\frac{40}{100}\)
Answer:
x = 50
Explanation:
\(\frac{20}{x}\) = \(\frac{40}{100}\)
x = \(\frac{20 x 100}{40}\)
x = 50

Question 32.
\(\frac{36}{90}\) = \(\frac{12}{x}\)
Answer:
x = 30
Explanation:
\(\frac{36}{90}\) = \(\frac{12}{x}\)
x = \(\frac{12 x 90}{36}\)
x = 30

Solve.

Question 33.
Walter looked at the list of nutrients in the fruit juice he bought. He noticed that there were a total of 4 grams of carbohydrates and 3 grams of sugar in every bottle of juice. Compare the amount of sugar to carbohydrates in the fruit juice.
Answer:
\(\frac{3}{4}\) grams
Explanation:
Walter noticed that there were a total of 4 grams of carbohydrates and 3 grams of sugar in every bottle of juice. Compare the amount of sugar to carbohydrates in the fruit juice,
= \(\frac{3}{4}\) grams.

Question 34.
Will rides his unicycle at an average speed of 8 miles per hour. How far will he travel in 2\(\frac{1}{2}\) hours?
Answer:
20 miles.
Explanation:
Will rides his unicycle at an average speed of 8 miles per hour.
Total distance he travel in 2\(\frac{1}{2}\) hours,
= 2\(\frac{1}{2}\) x 8
= \(\frac{5}{2}\) x 8
= 2 x 8 + \(\frac{8}{2}\)
= 16 + 4
= 20 miles

Question 35.
Jack makes 22 muffins for every 3 batches he bakes. How many batches of muffins will he need to bake in order to sell 242 muffins?
Answer:
33 batches.
Explanation:
22 muffins for 3 batches
242 muffins  —- x batches
x X 22 = 3 x 242
x = \(\frac{3 x 242}{22}\)
x = 3 x 11
x = 33 batches

Question 36.
Priscilla drinks an average of \(\frac{2}{3}\) quart of water for each mile she walks. How many quarts of water will she drink if she walks \(\frac{2}{3}\) miles?
Answer:
\(\frac{4}{9}\) qts.
Explanation:
Priscilla drinks an average of \(\frac{2}{3}\) quart of water for each mile she walks.
Total quarts of water she drink if she walks \(\frac{2}{3}\) miles,
= \(\frac{2}{3}\) x \(\frac{2}{3}\)
= \(\frac{2 x 2}{3 x 3}\)
= \(\frac{4}{9}\) qts

Question 37.
Jenny changes the oil in her car every 2,250 miles. How many times will she need to change the oil in her car if she takes a trip that is 9,000 miles in length?
Answer:
4 times.
Explanation:
Jenny changes the oil in her car every 2,250 miles.
Number of times she need to change the oil in her car if she takes a trip that is 9,000 miles in length,
= \(\frac{9000}{2250}\)
= 2250 x 4 = 9000
= \(\frac{9000}{2250}\) = 4

Question 38.
30% of 1\(\frac{2}{5}\)
Answer:
\(\frac{21}{50}\)
Explanation:
30% of 1\(\frac{2}{5}\)
= \(\frac{30}{100}\) x \(\frac{7}{5}\)
= \(\frac{3}{10}\) x \(\frac{7}{5}\)
= \(\frac{3 x 7}{10 x 5}\)
= \(\frac{21}{50}\)

Question 39.
40% of 440
Answer:
176
Explanation:
40% of 440
= \(\frac{40}{100}\) x 440
= \(\frac{4}{10}\) x \(\frac{440}{1}\)
= \(\frac{4 x 440}{10}\)
= 4 x 44
= 176

Question 40.
\(\frac{1}{4}\) of 48%
Answer:
12%
Explanation:
\(\frac{1}{4}\) of 48%
= \(\frac{1}{4}\) x \(\frac{48}{100}\)
= \(\frac{1 x 48}{4 x 100}\)
= \(\frac{12}{100}\)
= 12%

Question 41.
\(\frac{2}{5}\) of 70%
Answer:
28%
Explanation:
\(\frac{2}{5}\) of 70%
= \(\frac{2}{5}\) x \(\frac{70}{100}\)
= \(\frac{2 x 70}{100}\)
= \(\frac{2 x 14 }{100}\)
= 28%

Question 42.
\(\frac{3}{8}\) of 340%
Answer:
127.5%
Explanation:
\(\frac{3}{8}\) of 340%
= \(\frac{3}{8}\) x \(\frac{340}{100}\)
= \(\frac{3 x 340}{8 x 100}\)
= \(\frac{127.5 }{4 x 100}\)
= 127.5%

Question 43.
43% of .705
Answer:
0.3032
Explanation:
43% of .705
\(\frac{43}{100}\) x 0.705
= 0.43 x 0.705
= 0.3032

Question 44.
84% of 1.906
Answer:
1.601
Explanation:
84% of 1.906
\(\frac{84}{100}\)
= 0.84 x 1.906
= 1.601

Question 45.
\(\frac{3}{4}\) of 160%
Answer:
120%
Explanation:
\(\frac{3}{4}\) of 160%
= \(\frac{3}{4}\) x \(\frac{160}{100}\)
= \(\frac{3 x 160}{4 x 100}\)
= \(\frac{3 x 40}{100}\)
= 120%

Question 46.
Pete’s Pet Emporium is having a sale on birdcages. Pete is selling his $50 cages at a 20% discount, his $75 cages at \(\frac{1}{3}\) off, and his $100 cages at 60% off the original price. What are the new sale prices for the 3 cages?
$50 cage ________ $75 cage _________ $100 cage
Answer:
$40, $50, $40
Explanation:
Pete is selling his $50 cages at a 20% discount,
$50 cages at a 20% discount,
50 x 20 / 100 = 10
$50 – $10 = $40
his $75 cages at \(\frac{1}{3}\) off,
his $75 cages at \(\frac{1}{3}\) off,
$75 x \(\frac{1}{3}\) = $25
$75 – $25 = $50
and his $100 cages at 60% off the original price,
$100 x 60/100 = 60
$100 – $60 = $40
the new sale prices for the 3 cages,
$50 cage __$40
$75 cage __$50
$100 cage __$40

Question 47.
Tom is selling wristbands for $4.50. He has to charge sales tax of 6% on each wristband. What is the cost to the customer, including sales tax, for one wristband?
Answer:
$4.77
Explanation:
Tom is selling wristbands for $4.50.
He has to charge sales tax of 6% on each wristband.
$4.50x 6%
4.50 x 0.06 = 0.27
the cost to the customer, including sales tax, for one wristband,
4.50 + 0.27 = $4.77

Question 48.
Ursula put $200 into a money market account that pays 3% simple interest. How much will she have in her account at the end of 1 year if she does not deposit any more money in the account? How much will she have at the end of 2 years?
Answer:
$206.00, $212.00

Question 49.
Pam put $400 into a savings account that pays 2.5% in compound interest. How much will she have in the account at the end of 2 years, if she does not deposit any more money in the account? How much will she have at the end of 5 years?
Answer:
$420.25; $452.56

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