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McGraw-Hill Math Grade 7 Answer Key Lesson 19.5 Temperature
Exercises
CONVERT
° F = ° C × \(\frac{9}{5}\) + 32
° C = (° F – 32) × \(\frac{9}{5}\)
Question 1.
200° C = _______________ F
Answer:
200° C is equal to 392° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 200 × \(\frac{9}{5}\) + 32
° F = 40 × \(\frac{9}{1}\) + 32
° F = 360 + 32
° F = 392.
Question 2.
132° F = _______________ C
Answer:
132° F is equal to 180° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (132 – 32) × \(\frac{9}{5}\)
° C = 100 × \(\frac{9}{5}\)
° C = 20 × \(\frac{9}{1}\)
° C = 180.
Question 3.
81° F = _______________ C
Answer:
81° F is equal to 88.2° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (81 – 32) × \(\frac{9}{5}\)
° C = 49 × \(\frac{9}{5}\)
° C = \(\frac{441}{5}\)
° C = 88.2.
Question 4.
32° C = _______________ F
Answer:
32° C is equal to 89.6° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 32 × \(\frac{9}{5}\) + 32
° F = \(\frac{288}{5}\) + 32
° F = 57.6 + 32
° F = 89.6.
Question 5.
214° F = _______________ C
Answer:
214° F is equal to 327.6° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (214 – 32) × \(\frac{9}{5}\)
° C = 182 × \(\frac{9}{5}\)
° C = \(\frac{1638}{5}\)
° C = 327.6.
Question 6.
320° F = _______________ C
Answer:
320° F is equal to 518.4° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (320 – 32) × \(\frac{9}{5}\)
° C = 288 × \(\frac{9}{5}\)
° C = \(\frac{2592}{5}\)
° C = 518.4.
Question 7.
10°F = _______________ C
Answer:
10°F is equal to -39.6° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (10 – 32) × \(\frac{9}{5}\)
° C = -22 × \(\frac{9}{5}\)
° C = – \(\frac{198}{5}\)
° C = -39.6.
Question 8.
45° C = _______________ F
Answer:
45° C is equal to 113° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 45 × \(\frac{9}{5}\) + 32
° F = 9 × \(\frac{9}{1}\) + 32
° F = 81 + 32
° F = 113.
Question 9.
75° F = _______________ C
Answer:
75° F is equal to 77.4° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (75 – 32) × \(\frac{9}{5}\)
° C = 43 × \(\frac{9}{5}\)
° C = \(\frac{387}{5}\)
° C = 77.4.
Question 10.
90° C = _______________ F
Answer:
90° C is equal to 64.4° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 90 × \(\frac{9}{5}\) + 32
° F = 18 × \(\frac{9}{1}\) + 32
° F = \(\frac{162}{5}\) + 32
° F = 32.4 + 32
° F = 64.4.
Question 11.
-15° F = _______________ C
Answer:
-15° F is equal to – 84.6° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (-15 – 32) × \(\frac{9}{5}\)
° C = – 47 × \(\frac{9}{5}\)
° C = \(\frac{- 423}{5}\)
° C = – 84.6.
Question 12.
130° F = _______________ C
Answer:
130° F is equal to 176.4° C.
Explanation:
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (130 – 32) × \(\frac{9}{5}\)
° C = 98 × \(\frac{9}{5}\)
° C = \(\frac{882}{5}\)
° C =176.4.
Question 13.
37° C = _______________ F
Answer:
37° C is equal to 69° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 37 × \(\frac{9}{5}\) + 32
° F =  \(\frac{185}{5}\) + 32
° F = 37 + 32
° F = 69.
Question 14.
2000° C = _______________ F
Answer:
2000° C is equal to 3632° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 2000 × \(\frac{9}{5}\) + 32
° F = 400 × \(\frac{9}{1}\) + 32
° F = 3,600 + 32
° F = 3632.
Question 15.
244° C = _______________ F
Answer:
244° C is equal to 471.2° F.
Explanation:
° F = ° C × \(\frac{9}{5}\) + 32
° F = 244 × \(\frac{9}{5}\) + 32
° F =  \(\frac{2196 }{5}\) + 32
° F = 439.2 + 32
° F = 471.2.
Question 16.
Sarah has a fever and is running a temperature of 39° C. What is her temperature in Fahrenheit?
Answer:
102.2 is her temperature in Fahrenheit.
Explanation:
Sarah has a fever and is running a temperature of 39° C.
Temperature of Sarah = 39 ° C.
° F = ° C × \(\frac{9}{5}\) + 32
° F = 39 × \(\frac{9}{5}\) + 32
° F = \(\frac{351}{5}\) + 32
° F = 70.2 + 32
° F = 102.2.
Question 17.
Jared is baking cookies for a bake sale. His recipe calls for him to set the oven to a temperature of 350° F. If his oven only displays temperature in Celsius, then to what temperature should Jared set his oven?
Answer:
572.4 is the temperature should Jared set his oven.
Explanation:
Temperature of his recipe calls for him to set the oven = 350° F.
If his oven only displays temperature in Celsius,
Temperature should Jared set his oven =
° C = (° F – 32) × \(\frac{9}{5}\)
° C = (350 – 32) × \(\frac{9}{5}\)
° C = 318 × \(\frac{9}{5}\)
° C =  \(\frac{2862}{5}\)
° C = 572.4.