Go Math Grade 3 Answer Key Chapter 5 Use Multiplication Facts Extra Practice with a detailed explanation are given here. So the students who are interested to solve the additional practice questions can go through the HMH Go Math Grade 3 Answer Key Chapter 5 Use Multiplication Facts Extra Practice pdf.

## Go Math Grade 3 Answer Key Chapter 5 Use Multiplication Facts Extra Practice

Learn the fundamentals of multiplications from our Go Math Answer Key Chapter 5. This chapter includes the basics of multiplication using the line plot, number line, and graphs. Students can learn simple tricks to solve the problems which help to score good marks in the exams.

### Common Core – Page No. 101000

**Lesson 5.1**

**Describe a pattern for the table. Then complete the table.**

Question 1.

Teams | 2 | 3 | 4 | 5 | 6 |

Players | 12 | 18 | 24 | _________ | _________ |

Answer:

Teams | 2 | 3 | 4 | 5 | 6 |

Players | 12 | 18 | 24 | 30 |
36 |

Explanation:

Multiply 6 with a number of tables.

Multiply 6 with 5 teams = 6 Ã— 5 = 30

Multiply 6 with 6 teams = 6 Ã— 6 = 36

Question 2.

Tables | 4 | 5 | 6 | 7 | 8 |

Chairs | 16 | 20 | _________ | 28 | _________ |

Answer:

Tables | 4 | 5 | 6 | 7 | 8 |

Chairs | 16 | 20 | 24 |
28 | 32 |

Explanation:

Multiply 4 with number of tables.

Number of chairs for 6 tables = x

Number of chairs for 8 tables = y

Now multiply number of tables with 4 = 6 Ã— 4 = 24

And then multiply 8 tables with 4 = 8 Ã— 4 = 32

Therefore the missing numbers in the table are 24 and 32

**Lesson 5.2**

**Find the unknown factor.**

Question 3.

72 = 9 Ã— t

t = _______

Answer: 8

Explanation:

t Ã— 9 = 72

t = 72/9 = 8

The unknown factor t is 8.

Question 4.

4 Ã— â˜… = 28

â˜… = _______

Answer: 7

Explanation:

4 Ã— â˜… = 28

â˜… = 28/4 = 7

â˜… = 7

Question 5.

b Ã— 5 = 30

b = _______

Answer: 6

Explanation:

b Ã— 5 = 30

b = 30/5 = 6

Thus the unknown factor b is 6.

Question 6.

d Ã— 3 = 24

d = _______

Answer: 8

Explanation:

d Ã— 3 = 24

d = 24/3 = 8

Therefore the unknown factor d is 8.

Question 7.

48 = 8 Ã— p

p = _______

Answer: 6

Explanation:

8 Ã— p = 48

p = 48/8

p = 6

Thus the unknown factor p is 6.

Question 8.

6 Ã— â–² = 24

â–²= _______

Answer: 4

6 Ã— â–²= 24

â–²= 24/6

â–²= 4

So the unknown factorâ–²is 4.

Question 9.

56 = 7 Ã— â–

â– = _______

Answer: 8

Explanation:

7 Ã— â– = 56

â– = 56/7

7 divides 56 eight times.

So the unknown factor â– is 8.

Question 10.

2 Ã— g = 20

g = _______

Answer: 10

Explanation:

2 Ã— g = 20

g = 20/2 = 10

Therefore the unknown factor g is 10.

Question 11.

h Ã— 7 = 35

h = _______

Answer: 5

Explanation:

h Ã— 7 = 35

h = 35/7

h = 5

Thus the unknown factor h is 5.

Question 12.

9 = 9 Ã— a

a = _______

Answer: 1

Explanation:

9 Ã— a = 9

a = 9/9

a = 1

So the unknown factor a is 1.

Question 13.

c Ã— 4 = 36

c = _______

Answer: 9

Explanation:

c Ã— 4 = 36

c = 36/4

4 divides 36 nine times.

c = 9

Therefore the unknown factor is 9.

Question 14.

5 Ã— y = 40

y = _______

Answer: 8

Explanation:

5 Ã— y = 40

y = 40/5

y = 8

Thus the unknown factor is 8.

### Common Core – Page No. 102000

**Lesson 5.3**

**Solve.**

Question 1.

Hailey plants 6 rows of marigolds. Each row has 20 marigolds. How many marigolds does Hailey plant in all?

_______ marigolds

Answer: 120

Explanation:

Given that, Hailey plants 6 rows of marigolds.

Each row contains 20 marigolds.

Total number of marigolds that Hailey planted in all = x

x = 20 Ã— 6 = 120

Therefore Hailey planted 120 marigolds.

Question 2.

A meeting room has 8 rows of chairs. Each row has 10 chairs. The first people to arrive fill 2 rows. How many chairs are not filled?

_______ chairs

Answer: 60

Explanation:

Given, A meeting room has 8 rows of chairs.

Each row has 10 chairs.

Total number of chairs = 8 Ã— 10 = 80 chairs

The first people to arrive fill 2 rows.

That means 2 Ã— 10 = 20 chairs

Number of chairs that are not filled = total number of chairs – number of filled chairs

= 80 – 20 = 60 chairs.

**Lesson 5.4**

Question 3.

1. Use a number line to find the product.

4 Ã— 30 = _______

Answer: 120

Step 1:

Starts at 0.

Step 2:

Make a jump of 30s until you reach 120.

Step 3:

Count the number of jumps till you reach 120.

Number of jumps = 4

4 Ã— 30 = 120

**Use place value to find the product.**

Question 4.

40 Ã— 8 = _______ tens Ã— 8

= _______ tens = _______

Answer:

i. 4

ii. 32

iii. 320

Explanation:

4 Ã— tens = 4 tens = 40

4 tens Ã— 8 = 32 tens

32 tens = 32 Ã— 10 = 320

Question 5.

5 Ã— 60 = 5 Ã— _______ tens

= _______ tens = _______

Answer:

i. 6

ii. 30 tens

iii. 300

Explanation:

60 = 6 Ã— tens = 6 tens

5 Ã— 6 tens = 30 tens

30 tens = 30 Ã— 10 = 300

**Lesson 5.5**

**Find the product.**

Question 6.

9 0

Ã— 3

——

_______

Answer: 270

Explanation:

First multiply 3 with ones = 3 Ã— 0 = 0

Next multiply 3 with tens = 3 Ã— 90 = 270

So the product of 90 and 3 is 270.

Question 7.

5 0

Ã— 8

——

_______

Answer: 400

Explanation:

First multiply 8 with ones = 8 Ã— 0 = 0

Now multiply 8 with tens = 8 Ã— 50 = 400

The product of 50 and 8 is 400.

Question 8.

7 0

Ã— 9

——

_______

Answer: 630

Explanation:

Multiply 9 with ones = 9 Ã— 0 = 0

Multiply 9 with tens = 9 Ã— 70 = 630

The product of 9 and 70 is 630.

Question 9.

8 0

Ã— 7

——

_______

Answer: 560

Explanation:

Multiply 7 with ones = 7 Ã— 0 = 0

And then multiply 7 with tens = 7 Ã— 80 = 560

Thus the product of 80 and 7 is 560.

**Solve.**

Question 10.

During the summer, Jayden volunteers at the library for 20 hours each week for 7 weeks. How many hours does Jayden volunteer in all?

_______ hours

Answer: 140 hours

Explanation:

During the summer, Jayden volunteers at the library for 20 hours each week for 7 weeks.

For each week he worked 20 hours

Number of hours he worked for 7 weeks = y

y = 7 Ã— 20 = 140 hours

Therefore Jayden volunteers at the library for 20 hours.

Question 11.

Trisha teaches 8 different cooking classes. There are 20 students in each class. How many students in all are in Trishaâ€™s cooking classes?

_______ students

Answer: 160 students

Explanation:

Given,

Trisha teaches 8 different cooking classes.

There are 20 students in each class.

Total number of students = number of classes Ã— number of students in each class

= 8 Ã— 20 = 160 students.

Therefore the total number of students in all the cooking classes area 120.

Additional practice with a brief explanation will help the students to become masters in the subject. So make use of the links attached here to improve the math skills. If you have any queries go through the Go Math Grade 3 Answer Key Chapter 5 Use Multiplication Facts. All the Best!!!